A bullet of mass 10g is fired from a gun. The bullet takes 0.003s to move through its barrel and leaves it with a velocity of 300m/s. Find the force exerted on the bullet by the gun? [ Ans: 1000N]​

The pressure in the tank is 618 kPa.

To determine the pressure in the tank, we can use the ideal gas law equation, which states that the pressure (P) times the volume (V) is equal to the number of moles (n) times the gas constant (R) times the temperature (T). However, in this case, we have water, which is a liquid, and the ideal gas law is not applicable to liquids. Instead, we can use the concept of saturation pressure.

At 160°C, water is in its vapor phase, and we need to find the saturation pressure at this temperature. The saturation pressure of water can be obtained from tables or by using equations specific to the substance. At 160°C, the saturation pressure of water is approximately 618 kPa.

Therefore, the pressure in the tank is 618 kPa.

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The vertical height attained by a basketball player who achieves a hang time of a full 1 s is about 1.22 m .

Option B is correct .

The player will be free falling because the basketball takes the same amount of time to ascend and descend. for 0.5 seconds. Time equals 0.5 seconds when he reaches his maximum height.

Distance is given by from the laws of motion equation :

                        s = ut + 1/2 at²

                        s = 0 × t + 1/2 × 9.81 × [ 0.5 ]²

                        s = 0 + 1/2 × 9.81 × 0.25

                         s = 1.22 m

According to the first law, a force acting on an object will not cause it to change its motion. According to the second law, an object's force is proportional to its acceleration divided by its mass.

According to the third law, when two objects interact, they exert forces of equal magnitude in opposite directions. The three conditions of movement are as per the following: v = u + at is the first equation of motion. s = ut + 1/2 at² is the solution to the second motion equation. The formula for the third motion equation is v² = u² + 2as.

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The 10 push-ups must Jaycie complete to do 200 J of work. If one push-up is applying a force of 10 N to raise her center of gravity 2 m.

As, we know that

W = F × S

where,

F is the force

W is the work done by the body

S is the distance travelled by the body

Given,

F = 10N

S = 2m

By substituting all the values, we get

W = 10 × 2

W = 20J

So, the 20J work is done by one push up.

Therefore,

200/20

= 10 push ups

Thus, we concluded that the 10 push-ups must Jaycie complete to do 200 J of work. If one push-up is applying a force of 10 N to raise her center of gravity 2 m.

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Answer:

\(2000\; {\rm cm^{3}}\).

Explanation:

When the ball is placed in this pool of water, part of the ball would be beneath the surface of the pool. The volume of the water that this ball displaced is equal to the volume of the ball that is beneath the water surface.

The buoyancy force on this ball would be equal in magnitude to the weight of water that this ball has displaced.

Let \(m(\text{ball})\) denote the mass of this ball. Let \(m(\text{water})\) denote the mass of water that this ball has displaced.

Let \(g\) denote the gravitational field strength. The weight of this ball would be \(m(\text{ball}) \, g\). Likewise, the weight of water displaced would be \(m(\text{water})\, g\).

For this ball to stay afloat, the buoyancy force on this ball should be greater than or equal to the weight of this ball. In other words:

\(\text{buoyancy} \ge m(\text{ball})\, g\).

At the same time, buoyancy is equal in magnitude the the weight of water displaced. Thus:

\(\text{buoyancy} = m(\text{water}) \, g\).

Therefore:

\(m(\text{water})\, g = \text{buoyancy} \ge m(\text{ball})\, g\).

\(m(\text{water}) \ge m(\text{ball})\).

In other words, the mass of water that this ball displaced should be greater than or equal to the mass of of the ball. Let \(\rho(\text{water})\) denote the density of water. The volume of water that this ball should displace would be:

\(\begin{aligned}V(\text{water}) &= \frac{m(\text{water})}{\rho(\text{water})} \\ &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \end{aligned}\).

Given that \(m(\text{ball}) = 2000\; {\rm g}\) while \(\rho = 1.00\; {\rm g\cdot cm^{-3}}\):

\(\begin{aligned}V(\text{water}) &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \\ &= \frac{2000\; {\rm g}}{1.00\; {\rm g\cdot cm^{-3}}} \\ &= 2000\; {\rm cm^{3}}\end{aligned}\).

In other words, for this ball to stay afloat, at least \(2000\; {\rm cm^{3}}\) of the volume of this ball should be under water. Therefore, the volume of this ball should be at least \(2000\; {\rm cm^{3}}\!\).

Answer:

Two 50 Ohm Resistors, One 20 Ohm Resistor.

Explanation:

For the given current and voltage specifications, the resistance can be calculated by Ohm's Law:

\(V = IR\\\\R = \frac{V}{I}\)

where,

R = Resistance = ?

V = Voltage = (1.5 V)(4) = 6 V

I = 0.05 A

Therefore,

\(R = \frac{6\ V}{0.05\ A}\\\\R = 120\ \Omega\\\)

Now, to minimize the cost we will buy the following set of resistors:

Two 50 Ohm Resistors, One 20 Ohm Resistor.

240 seconds

Explanation:

If he walked to A and took 80 Seconds it should be the same amount of distance to B and C

Answer:

The smaller net force :)

Explanation:

The second law shows that if you exert the same force on two objects of different mass, you will get different accelerations (changes in motion). The effect (acceleration) on the smaller mass will be greater (more noticeable).

If two different net forces are applied to the same object at different times, a smaller net force will cause the object to accelerate at a greater rate.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

Newton's second rule states that if you apply the same force to two objects with different masses, the accelerations will be different. The impact will be larger on the smaller mass.

If two different net forces are applied to the same object at different times, a smaller net force will cause the object to accelerate at a greater rate.

Hence smaller rate is the correct answer.

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Answer:

thank you very much for giving me points.

Explanation:

I really appreciate it so muchhhhh so muchhhh thanks again

Answer:

The answer is C because there is no friction there will be no friction force only applied and since its on ice you have to account for gravity

Explanation:

Answer:

c

Explanation:

c

The angle of the rotation of the wheel in 1.0 seconds is  164.7 radians.

Does a free-body diagram include centripetal force?

Because F = ma is the net force and the net force has the unique form when dealing with uniform circular motion, you should not include a centripetal force on a free-body diagram for the same reason that ma should not be included.

The given parameters;

radius of the wheel, r = 30 cm = 0.3 m

angular speed of the wheel, ω = 4.20 rev for 0.0510 s

The angle of the rotation in 1.0 seconds is calculated as;

Ф = ωt

Ф ={ 4.20 / 0.0510 ×  \(\frac{2}{1 rev}\)} × 1

Ф = 164.7 rad .

Hence, the angle at which the wheel rotates in 1 s is 164.7 rad.

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The maximum potential energy of the system is 0.5 J.

The given frequency, f = 5 Hz. The given amplitude, A = 20 cm = 0.2 m

The mass of the object, m = 0.250 kg

We can find the maximum potential energy of the system using the following formula: Umax = (1/2)kA²where k is the spring constant.

We know that the frequency of oscillation can be expressed as: f = (1/2π)√(k/m)

Rearranging the above formula, we get: k = (4π²m)/T² where T is the time period of oscillation.

We know that T = 1/f. Substituting this value in the above equation, we get:

k = (4π²m)/(1/f²)

k = 4π²mf².

Using this value of k, we can now find Umax.

Umax = (1/2)kA²

Substituting the given values, we get:

Umax = (1/2) x 4π² x 0.250 x (5)² x (0.2)²

Umax = 0.5 J

Therefore, the maximum potential energy of the system is 0.5 J.

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the drawdown at each distance from the well after 1 day of pumping.

calculate the drawdown at different distances from the well, we can use the Theis for equation confined aquifers:

s = (Q / (4πT)) × W(u)

where:

s is the drawdown at a certain distance from the well,

Q is the pumping rate (28 m³/day),

T is the transmissivity of the confined aquifer (3.8 m²/day),

W(u) is the well function that depends on the dimensionless distance u.

The well function W(u) can be calculated

W(u) =\((1 / u) × e^(u^2) × erfc(u)\)

where:

u = (r²S) / (4Tt)

r is the distance from the well,

S is the\(storativity\) of the confined aquifer (0.0035),

t is the time of pumping in days,

(u) is the complementary error function.

Now let's calculate the drawdown at the given distances of 1.5 m, 5.5 m, 10 m, 25 m, 75 m, and 150 m after 1 day of pumping.

Assuming the well is located at the origin (0,0) in a radial system:

For r = 1.5 m:

u = (1.5² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 5.5 m:

u = (5.5² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 10 m:

u = (10² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 25 m:

u = (25² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 75 m:

u = (75² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

For r = 150 m:

u = (150² × 0.0035) / (4 × 3.8 × 1)

Calculate W(u) and substitute the values into the Theis equation to find s.

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.

Answer:c

Explanation:

Answer:

C

Explanation:

The behavior of a wildfire is typically described by b) intensity and spread.

Wildfire behavior refers to the way the fire responds to the various factors that influence its spread and movement. The behavior of a wildfire is typically described by two main characteristics, which are intensity and spread. Intensity refers to the heat output of the fire and its potential for ignition and combustion. Spread, on the other hand, is the rate at which the fire is moving and how far it has spread. The intensity of a wildfire is influenced by several factors, including the type of fuel, weather conditions, and topography.

High-intensity wildfires tend to occur in areas with abundant and dry fuel, high temperatures, low humidity, and high winds, they can be dangerous and difficult to control, and they often result in significant damage to the environment and human communities. Spread is influenced by the same factors as intensity, as well as the presence of firebreaks, the availability of resources, and the tactics used by firefighting personnel. The speed and direction of the fire can vary greatly depending on the surrounding conditions, and it is important to monitor and assess these factors in order to manage the fire effectively. So therefore the behavior of a wildfire is typically described by b) intensity and spread.

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Answer:

Explanation: The density of gas differentiates all the varieties of gas present in the atmosphere.

HYDROGEN- it is a lighter gas having a lesser density.

For example, a hydrogen balloon displaces the air around it thus making it rise.

CARBON DIOXIDE: It is a denser gas as it makes the balloon heavier than the air pressure around it thus making it sink.

I hope the explanation was helpful. :)

Answer:

Cell phone signals are electromagnetic waves, which are reflected by the aluminum foil

Answer:

I think the best answer would be the first but am I the only one wondering why the mom didn't just turn off the phone but instead she had to be extra and wrap them up like a gift to give them after dinner.

The shape of the elastic curve for different values of x1 and x2, and thus, calculate the deflection and bending moment of the beam.

To determine the equation of the elastic curve for the beam shown in (Figure 1), we need to consider two cases: for x1 values between 0 and L/2 and for x2 values between L/2 and L.

For x1 values between 0 and L/2, the elastic curve can be expressed as:

y = (P/ (24 * E * I * L)) * (x1^2) * (6L - 3x1)

where P is the applied load, E is the modulus of elasticity, I is the moment of inertia of the beam, L is the length of the beam, and x1 is the distance along the beam.

For x2 values between L/2 and L, the elastic curve can be expressed as:

y = (P/ (24 * E * I * L)) * ((L-x2)^2) * (3x2 - 2L)

where P, E, I, L, and x2 have the same meaning as before.

By using these equations, we can determine the shape of the elastic curve for different values of x1 and x2, and thus, calculate the deflection and bending moment of the beam.

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✍ We can this formula:

\(\huge {\boxed {\sf v = g \cdot t }}\)

\(\huge {\text {$ \sf v = 9,8 \cdot 2,5 \Longrightarrow \boxed {\boxed {\bf v= 24,5 }} $ }}\)

The wavelength of an electromagnetic wave is inversely proportional to its frequency. This means that as the frequency of an electromagnetic wave increases, its wavelength decreases proportionally.

This relationship is described by the equation:

c = λν

where c is the speed of light, λ is the wavelength, and ν (nu) is the frequency. This equation shows that as the frequency increases, the wavelength must decrease to keep the speed of light constant.

This phenomenon can be observed in various electromagnetic waves. For example, visible light with a higher frequency appears more violet, while light with a lower frequency appears more red. Similarly, higher frequency radio waves have shorter wavelengths and can carry more data than lower frequency radio waves.

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Answer:

B

Explanation:

It becomes lighter so it rises

Answer:

Not all the pictures are popping up. So I can't answer them all. :(

Explanation:

The fist one is B. And the second is D. That's all I can see. I hope this helps a little bit :(

Answer:

the acceleration of the car is 1.167 m/s²

Explanation:

Given;

initial velocity of the race car, u = 5 m/s

final velocity of the race car, v = 12 m/s

time to finish the race, t = 6 s

The acceleration of the car is calculated as;

a = (v - u) / t

a = (12 - 5) / (6)

a = 1.167 m/s²

Therefore, the acceleration of the car is 1.167 m/s²

Answer:

1.167 m/s^2

Explanation:

Given that a race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of the race in 6 seconds what was the car's acceleration ?

From the question, the following parameters are given

Initial velocity U = 5 m/s

Final velocity V = 12 m/s

Time t = 6 s

According to the definition of acceleration:

Acceleration = change in velocity per time taken.

I.e

Acceleration =( V - U)/ t

Acceleration =( 12 - 5 )/6

Acceleration = 7/6

Acceleration = 1.167 m/s^2

Therefore, acceleration is 1.167 m/s^2

Answer:

B I'm Pretty Sure :DDD

Explanation:

Balanced Forces

In one of your situations in the last section, you pushed or pulled on an object from opposite directions but with the same force. You observed that the object did not move. When the forces on an object are equal and in opposite directions, the forces are balanced, and there is no change in motion.

Without additional information about the planets and their orbits, it is not possible to determine the day on which the next transit (t6) would occur or which planet would be transiting.

Transits occur when a planet passes directly in front of its star as seen from the observer's position, causing a small decrease in the star's apparent brightness. The frequency of transits depends on the orbital periods and alignments of the planets in the system.

In order to determine when the next transit will occur and which planet will be transiting, we need to know the orbital periods and relative positions of the planets.

If we have information about the orbital periods of the planets, we could use Kepler's laws of planetary motion to calculate when the planets will next align and a transit will occur. Alternatively, if we have data on the times and durations of previous transits, we could use that information to make predictions about future transits.

Without this additional information, we cannot determine when the next transit (t6) will occur or which planet will be transiting.

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The new electrostatic force would be 18.0 units.

The electrostatic force between two objects is given by Coulomb's Law, which states that the force is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

In this case, when the distance between Objects 1 and 2 is doubled, the new electrostatic force can be determined.

Let's assume the initial distance between Objects 1 and 2 is d. According to Coulomb's Law, the initial force is given by:

F1 = k(q1*q2) / d^2

where k is the electrostatic constant, q1 and q2 are the charges of Objects 1 and 2, respectively.

When the distance is doubled, the new distance becomes 2d. Applying Coulomb's Law to the new distance, the new electrostatic force (F2) is given by:

F2 = k(q1*q2) / (2d)^2

Simplifying this equation, we have:

F2 = k(q1*q2) / (4d^2)

Therefore, the new electrostatic force is 1/4th (or 25% of the initial force) because the distance is squared in the denominator. Hence, the new electrostatic force would be 18.0 units (72.0 units * 1/4 = 18.0 units).

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The Solar weather affects the Earth's magnetosphere which is a threat to our magnetic protection and generates auroras.

The effect of Earth's magnetosphere is like widening a hole - suddenly more energy and particles enter the magnetosphere. Auroras intensify, and geomagnetic storms become likely.

For this reason the scientists pay careful attention to not only the strength but also the orientation of incoming magnetic fields from the sun.

As the wind blows from the galaxy towards the earth it carries with it the Sun's magnetic field and moves very fast, then smacks right into the Earth's magnetic field. The blow causes a shock to our magnetic protection thus which can result in turbulence.

So we can conclude that The Solar weather affects the Earth's magnetosphere which is a threat to our magnetic protection and generates auroras.

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The car will travel a distance of 180 meters in 12 seconds.

To determine the distance traveled by the car, we can use the equation of motion:

Distance (d) = Initial velocity (v₀) × time (t) + 0.5 × acceleration (a) × time squared (t²)

Given:

Initial velocity (v₀) = 0 m/s (starting from rest)

Acceleration (a) = 2.5 m/s²

Time (t) = 12 seconds

Plugging in the values into the equation:

Distance (d) = 0 × 12 + 0.5 × 2.5 × 12²

Distance (d) = 0 + 0.5 × 2.5 × 144

Distance (d) = 0 + 0.5 × 2.5 × 144

Distance (d) = 180 meters

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A pendulum is a weight released from a starting point so that it can swing freely. When a pendulum is displaced sideways it restores a force due to gravity that will accelerate it back toward the equilibrium position from the resting position.

How to find initial potential energy, angular frequency, velocity and height of displacement of a pendulum?

We know, m= 0.40kg

L=0.5m

Angle = 12°

i) Main answer is : initial potential energy = PE = mgh (1-cos∅)

= 0.9×9.81×0.5×(1-cos12°)

= 0.0429 J

ii)Main answer is:  Angular frequency= W= √g/l

=4.43 rad/s

= 0.7 rev/s

iii) Main answer is : velocity of pendulum = V=√2gl(1-cos∅)

=0.46m/s

iv) Main answer is : height of displacement= h=L (1-cos∅)

=0.01m

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The pendulum's angular frequency is 4.42 rad/s, and its potential energy is 0.04 J. the pendulum's lowest in its swings has a speed of 0.44 m/s, a motion time of 0.010905 m, and a lateral distance of 0.1039 m.

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or strained, its energy increases. If a steel ball is lifted above the ground as contrasted to falling to the ground, it has higher potential energy.

Given data:

The associated mass is m=0.40kg.

The string measures L=0.5m in length.

Angle misplaced is equal to 12°.

(1). Calculate the potential energy of pendulum:

PE=mg[L−Lcosθ]

PE=0.40kg×9.8m/s[0.5m−0.5m×cos12°]

PE=0.04J

Consequently, the pendulum's potential energy is 0.04 J.

(2). Determine the pendulum's angular frequency:

\(\omega=\sqrt{\frac{g}{L}}\)

Changing every variable in the aforementioned equation:

\(\omega=\sqrt{\frac{9.8 \mathrm{~m} / \mathrm{s}^2}{0.5 \mathrm{~m}}}\)

ω = 4.42 rad/s

Consequently, the pendulum's angular frequency is 4.42 rad/s.

(4). Do the vertical displacement calculation:

\(x_V=L-L \cos \theta\)

\(\begin{aligned}& x_V=0.5 \mathrm{~m}-0.6 \mathrm{~m} \cos 12^{\circ} \\& x_V=0.010905 \mathrm{~m}\end{aligned}\)

Do the horizontal displacement calculation:

\(\begin{aligned}& x_H=L \sin \theta \\& x_H=L \sin 12^{\circ} \\& x_H=0.1039 \mathrm{~m}\end{aligned}\)

The height of the horizontal displacement is therefore 0.1039 m, while the height of the deformation is 0.010905 m.

(3).Calculate the pendulum's rock bottom in its swing by using energy balance to determine its velocity.

KE = PE

\(\frac{1}{2} 0.40 \mathrm{~kg} \times v^2=0.04 \mathrm{~J}\)

v = 0.44 m/s

Calculate the pendulum's velocity at its rock bottom in its swing, which is 0.44 m/s.

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O.A magnetic field is a region where a magnetic force is exerted on certain objects.

O. A magnetic field behaves like a force vector.

O.Magnetic field lines form closed loops that spread out of the north end of a magnet.

Explanation:

1,2, and 4

Answer:

a,b,d

Explanation:

i took the test