A bumper car with a mass of 240 kg is moving to the right with a velocity of 2.3
m/s. A second bumper car with a mass of 260 kg is moving to the left with a
velocity of 2.7 m/s. After the collision the first car's velocity is 2.9 m/s left, the
velocity of the second car is 2.1 m/s to the right. Prove conservation of momentum.
Assume the surface is frictionless.

The index of refraction of the transparent material where light has a wavelength of 600 nm and a frequency of 3 × 10¹⁴ Hz is 5/3. The correct option is 5/3.

To find the index of refraction (n) of a material, we can use the formula:

                          n = c / v

Where c is the speed of light in vacuum and v is the speed of light in the material.

Frequency of light, f = 3 × 10¹⁴ Hz

Wavelength of light in the material, λ = 600 nm = 600 × 10⁻⁹ m

The speed of light in vacuum is a constant, approximately 3 × 10⁸ m/s.

To find the speed of light in the material, we can use the formula:

                         v = f * λ

Substituting the given values:

v = (3 × 10¹⁴ Hz) * (600 × 10⁻⁹ m)

Calculating the value of v:

v = 1.8 × 10⁸ m/s

Now we can find the index of refraction:

n = c / v

n = (3 × 10⁸ m/s) / (1.8 × 10⁸ m/s)

Simplifying the expression:

n = 1.67

Among the given answer choices, the closest value to the calculated index of refraction is 5/3.

Therefore, the correct answer is 5/3.

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GREETINGS!

lightening usually strikes the metal pole and cables above the building because they provide a safe low resistance pathway to the lightening to move from building from the concrete steel to the ground below, thats how building doesnt get any damage and high electric charge passes through it

HOPE IT HELPS YOU!

Answer:

I would say all of the above.

Explanation:

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Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\(\Delta W\)), medido en joules, que reducida a:

\(\Delta W = m\cdot g\cdot \Delta z\) (1)

Donde:

\(m\) - Masa del montañero, medido en kilogramos.

\(g\) - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\(\Delta z\) - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que \(m = 65\,kg\), \(g = 9,807\,\frac{m}{s^{2}}\) y \(\Delta z = 500\,m\), entonces el trabajo realizado por el montañero para subir es:

\(\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)\)

\(\Delta W = 318727,5\,J\)

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Astronomers take advantage of chromatic aberration in the prism. Therefore, the correct answer is option (a) the prism.

A prism is a triangular piece of glass or plastic that can split white light into its constituent colors by refracting the light at different angles as it passes through the prism. This effect is due to the different refractive indices of the prism material for different wavelengths of light, which causes the colors to separate.

Chromatic aberration is actually a type of distortion that can occur in lenses and mirrors, where different wavelengths of light are focused at different distances from the lens or mirror, resulting in color fringing around objects. However, astronomers typically try to minimize chromatic aberration in the lenses and mirrors of telescopes in order to achieve sharper and more accurate images.

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Answer:

c. Intensity

Explanation:

Wavelength is a distance (meters).

Speed is distance per time (meters / second).

Intensity is power per area (Watts / square meter).

Pitch is frequency (cycles / second).

Answer:

cause why not.

the layers exist cause theoretically the deeper you go the hotter it gets and different atoms just do stuff

Answer:

Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory. The motion of falling objects, as covered in Problem-Solving Basics for One-Dimensional Kinematics, is a simple one-dimensional type of projectile motion in which there is no horizontal movement. In this section, we consider two-dimensional projectile motion, such as that of a football or other object for which air resistance is negligible.

Explanation:

B the dropped ball

Answer:

Explanation:

Given:

V₀ = 3.0 m/s

H = 5.2 m

__________

L - ?

Time for the ball to fall vertically:

H = g·t²/2;    ⇒    t = √ (2·H / g) = √ (2·5.2 / 9.8) ≈ 1.0 c

Move the ball horizontally:

L = V₀·t = 3.0·1.0 = 3.0 m

If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground , then the horizontal displacement of the ball is 3.09 meters.

There are three equations of motion given by Newton,

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

As given in the problem If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground

S = ut + 1/2 × a × t²

5.2 = 0 + 0.5 × 9.8 ×  t²

t² = 5.2 / 4.9

t = 1.03 seconds

The horizontal displacement of the ball = 1.03 × 3

                                                                  = 3.09 meters

Thus, the horizontal displacement of the ball is 3.09 meters.

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Explanation:

Graph 1 is linear motion because it has constant velocity for some time.

Graph 2 is , if we see path over path we can see positif uniformy accelerated motion when the graph sketch to upper right and uniformly deaccelerated motion when goes down right.

But for all, the2nd graph motion looks random motion

Answer:

A) a = 73.304 rad/s²

B) Δθ = 3665.2 rad

Explanation:

A) From Newton's first equation of motion, we can say that;

a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.

Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s

Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s

We are given; t = 10 s

Thus;

a = 733.04/10

a = 73.304 rad/s²

B) From Newton's third equation of motion, we can say that;

ω² = ω_o² + 2aΔθ

Where Δθ is angular displacement

Making Δθ the subject;

Δθ = (ω² - ω_o²)/2a

At this point, ω = 0 rad/s while ω_o = 733.04 rad/s

Thus;

Δθ = (0² - 733.04²)/(2 × 73.304)

Δθ = -537347.6416/146.608

Δθ = - 3665.2 rad

We will take the absolute value.

Thus, Δθ = 3665.2 rad

Answer:

Neither.

Explanation:

After 10 seconds the object will have travelled 490.5m, not 98.1. The vertical distance covered in freefall by an object in time t is given by Distance= 1/2 x 9.81 x t^2. Simply multiplying 9.81 by the time will NOT give the distance covered.

The acceleration of the object will not change, it will always be 9.81 m/s^2. Its speed will keep increasing by 9.81 m/s every second, thats what the ‘per second squared*’ means. The speed after 10 seconds will be 98.1 m/s

To summarise, after 10 seconds, the object will have covered 490.5 metres, and it will have a final speed of 98.1 m/s. It’s acceleration will remain 9.81 m/s^2 at all times

The average person's vertical jump on the Moon would be 0.65 m.

The gravitational acceleration near the surface of the Moon is 1.62 m/s2, which is about one sixth the gravitational acceleration on Earth.

As a result, an average person's vertical jump on the Moon would be less than on Earth.

To calculate the vertical jump on the Moon, we need to use the formula h = 1/2 x g x t2.

This equation is used to calculate the height h (in meters) that an object will reach when thrown into the air, given the gravitational acceleration g (in m/s2) and the time t (in seconds) it takes to reach the peak of the jump.

Since the gravitational acceleration on the Moon is 1.62 m/s2, and the time taken to reach the peak of the jump is the same (assume 0.5 s), then h = 0.5 x 1.62 x (0.5)2, which is 0.65 m.

Therefore, an average person's vertical jump on the Moon would be 0.65 m.

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Answer: a. 126.21secs

b. 12.621 meters.

Explanation:

Given data:

Speed of tortoise = 0.1m/s.

Speed of hare = 2m/s.

Solution:

a. Distance traveled = Speed* Time

Speed of tortoise = 0.1 m/s

Speed of hare = 20*0.1 m/s = 2 m/s

2 minutes = 2* 60 s = 120 s

Let the time taken for the race be t seconds.

• Distance moved by tortoise

= (0.1 /s)* (t s)

= 0.1*t meter

•Hare has run for a time of (t - 120)s.

distance moved by hare

= Speed * Time

= (2 m/s)*(t- 120)s

= (2t - 240) meter.

Since hare is 20 cm (0.2 m) behind the tortoise, therefore

(0.1*t - 0.2) meter

= (2t - 240) meter

0.1*t - 0.2 = 2t - 240

Collect like terms

239.8 = 1.9t

Divide both sides by 1.9

t = 126.21secs

The race lasted for 126.21secs

b. Length of race

= Distance moved by tortoise

= 0.1*126.21 meter

= 12.621 meter

The length of the race is 12.621 meters.

The given statement "swinging a tennis racket against a ball is an example of a third-class lever" is TRUE.

A third-class lever is a class of lever where the input force is located between the fulcrum and the load. The fulcrum is the pivot point of the lever. The load is the weight or resistance that is being moved, lifted, or carried.The following are some examples of third-class levers: Sweeping with a broom. Tennis racket. Field hockey stick. Butter knife, etc. Thus, we can say that swinging a tennis racket against a ball is an example of a third-class lever.

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The momentum of the rain that falls in one second is 1,000,000,000 kg·m/s.

To calculate the momentum of the rain that falls in one second, we need to determine the mass of the rain that falls in one second and then multiply it by the terminal velocity.

First, let's calculate the volume of rain that falls in one second. We know that the rainstorm drops 1 cm of rain over an area of 10 km². To convert the area from km² to m², we multiply by 1,000,000 (1 km² = 1,000,000 m²):

10 km² = 10,000,000 m²

The volume of rain that falls in one second is equal to the area multiplied by the height (thickness) of the rain. Since the height is given as 1 cm, we need to convert it to meters (1 cm = 0.01 m):

Volume = Area × Height

Volume = 10,000,000 m² × 0.01 m

Volume = 100,000 m³

Next, we can calculate the mass of the rain that falls in one second using the volume and the density of water. The density of water is approximately 1000 kg/m³:

Mass = Volume × Density

Mass = 100,000 m³ × 1000 kg/m³

Mass = 100,000,000 kg

Finally, we can calculate the momentum by multiplying the mass by the terminal velocity of the raindrops:

Momentum = Mass × Velocity

Momentum = 100,000,000 kg × 10 m/s

Momentum = 1,000,000,000 kg·m/s

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The momentum of the rain that falls in one second would be 5.236 x 10⁶ kg m/s. Given that the rainstorm drops 1 cm of rain over an area of 10 km² in the period of 1 hour, we can calculate the total volume of rain that falls using the formula: Volume = Area x Height.

Therefore, the volume of rain that falls in 1 hour is: Volume = 10 km² x (1 cm / 100) x (1000 m / 1 km)³= 1,000,000 m³To find the mass of the rain that falls, we need to know the density of water. The density of water is 1000 kg/m³. Therefore, the mass of the rain that falls in 1 hour is: Mass = Density x Volume= 1000 kg/m³ x 1,000,000 m³= 1,000,000,000 kg.

Now, we need to find the momentum of the rain that falls in one second. We can do this using the formula: Momentum = Mass x Velocity. The velocity of the rain is given as the terminal velocity, which is 10 m/s. Therefore, the momentum of the rain that falls in one second is: Momentum = 1,000,000,000 kg x 10 m/s= 10,000,000,000 kg m/s= 5.236 x 10⁶ kg m/s (rounded to three significant figures)Thus, the momentum of the rain that falls in one second is 5.236 x 10⁶ kg m/s.

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Answer:

length, width, thickness, mean diameter

mass, volume, density, sphericity, surface area, aspect ratio.Jan 7, 2019

Explanation:

Answer:

Since, In Chemical change the property of the substance is changed resulting in the formation of a new substance where as In Physical change the property of the substance remains unchanged resulting in the formation of no new substance. Therefore, Cutting of Carrot is a physical change.

Explanation:

hope this helps    :)

Mugabe gained power by using political strategies, forming alliances, and exploiting his status as a liberation hero within ZANU-PF.

Robert Mugabe, the former president of Zimbabwe, was able to build power through a combination of political strategies and alliances. One key factor was his involvement in the liberation struggle against white minority rule in Rhodesia (now Zimbabwe).

Mugabe emerged as a prominent figure within the Zimbabwe African National Union (ZANU) party, which later merged with the Zimbabwe African People's Union (ZAPU) to form the Zimbabwe African National Union - Patriotic Front (ZANU-PF). Mugabe's role as a liberation hero and his ability to mobilize support among the majority black population of Zimbabwe gave him a strong power base.

Within ZANU-PF, Mugabe strategically positioned himself and gained influence by forming alliances and outmaneuvering rivals. He rose to become the party's leader and played a key role in negotiating the Lancaster House Agreement in 1979, which paved the way for Zimbabwe's independence in 1980. Mugabe became the country's first prime minister and later transformed the position into an executive presidency, consolidating his authority.

Mugabe maintained power through various means, including controlling key institutions such as the military, intelligence agencies, and the ruling party. He also utilized patronage networks, distributing resources and positions to loyal supporters within the party and government. Mugabe's policies, such as the controversial land reform program, further solidified his power base by appealing to nationalist sentiments and redistributing land from white farmers to black Zimbabweans.

However, Mugabe's consolidation of power was also marked by authoritarianism, human rights abuses, and a declining economy. His grip on power faced challenges over the years, including opposition movements, internal party factions, and economic crises. Ultimately, his rule came to an end in 2017 when he was ousted from power following a military intervention.

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Answer:

so in 1 sec 2 times

so frequency = 2

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 18 × 1.62

We have the final answer as

Hope this helps you

This statement suggests that the ice undergoes a phase change from solid to liquid, indicating heat transfer.

All of the ice will melt, and the final temperature of the mixture will be 10°C.

If the surroundings were at a lower temperature than the ice, heat would flow from the ice to the surroundings, causing the ice to freeze instead of melt.

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When a 1.2 kg book is lying on a 0.77 mm -high table and place it on a bookshelf 2.0 mm  work done by gravity is 14.39 joule.

mass=1.2

h1=0.77mm

h2=2.0 mm

g=9.8m/s^2

work done= mgh2-h1

work done=1.2×9.8(2.0-0.77)

work done=14.39 joule

An external force must focus at least a portion of its energy in the direction of the displacement when moving an object over a distance. In physics, this is referred to as work. Work can be calculated if the force acting along the path is constant by multiplying the force's component by the length of the path. Mathematically, the work W is defined as the sum of the force f and the length h, or W = mgh. If the force is applied at an angle to the displacement, the work is W = mas.

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Answer:

1. 59 Ω

2. 3 Ω

3. 0.625 kΩ

Explanation:

1. The total resistance in a series circuit is equal to the sum of the resistance.

\(R_T=R_1+R_2+R_3...\\R_T=20+19+20\\R_T=59\)

Therefore, the total resistance in the first circuit is 59 Ω.

2. The total resistance in a parallel circuit is equal to the sum of the reciprocals of the resistance.

\(\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{6.0} +\frac{1}{12} +\frac{1}{36}+\frac{1}{18} \\\frac{1}{R_T} = \frac{1}{3} \\R_T=3\)

Therefore, the total resistance in the second circuit is 3 Ω.

3. This is another parallel circuit, so we use the same equation from above:

\(\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{10} +\frac{1}{2} +\frac{1}{1} ...\\\frac{1}{R_T} =1.6\\R_T=\frac{1}{1.6}\)

Therefore, the total resistance in the third circuit is \(\frac{1}{1.6}\) kΩ, or 0.625 kΩ.

I hope this helps!

Answer

3m/s²

Explanation

u=o

t=25s

v=75m/s

from Newton's first law of motion,

v=u+at

75=0+a(25)

75=25a

a= 75/25

a=3m/s²

The acceleration of the airplane is 3m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Initial velocity of the airplane: u=o.

Time taken: t=25s.

Final velocity of the airplane: v=75m/s.

We have to find acceleration of the plane: a = ?

We know that for accelerating motion of the air plane; final velocity can be expressed as:

    v=u+at

⇒ 75=0+a(25)

⇒ 75=25a

⇒ a= 75/25

⇒ a= 3m/s².

hence, acceleration of the airplane is 3m/s².

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Answer:

What’s your question

Explanation:

And where

Answer:

its upside down

Explanation:

The magnitude of the acceleration due to gravity on this distant planet is approximately 9.8 m/s².

To determine the acceleration due to gravity on the distant planet, we can follow these steps:

1. Find the time period (T) of one oscillation:
Since the pendulum completes 100 oscillations in 360 seconds, the time period for one oscillation is:
T = 360 s / 100 oscillations = 3.6 s

2. Use the formula for the period of a simple pendulum:
T = 2π√(L/g)
where L is the length of the pendulum (1.20 m) and g is the acceleration due to gravity.

3. Solve for g:
Square both sides of the equation:
T² = 4π²(L/g)
Now, isolate g:
g = 4π²L/T²

4. Substitute the known values:
g = (4 * π² * 1.20 m) / (3.6 s)²
g ≈ 9.8 m/s²

The magnitude of the acceleration due to gravity on this distant planet is approximately 9.8 m/s².

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How we could distinguish them is that the infrasonic sounds are the lower limit of human hearing while ultrasonic sound is above human hearing. The sound of frequency more than 20,000Hz are called ultrasonics while the frequency less than 20Hz are called infrasonics.

Explanation:

I hope it helps! Have a great day!

Anygays-

Answer:

\(125\:\mathrm{minutes\: or\: }2.08\bar{3}\: \mathrm{hours}\)

Explanation:

Speed is given by \(s=\frac{d}{t}\), where \(d\) is distance travelled and \(t\) is time. Rearranging this equation, we have \(t=\frac{d}{s}\).

Plugging in our given information:

\(t=\frac{d}{s}=\frac{1500\:\mathrm{km}}{720\:\mathrm{km/h}}=2.08\bar{3}\: \mathrm{hours}\)

Thus, our answer is:

\(2.08\bar{3}\: \mathrm{hours}\cdot \frac{60\:\mathrm{minutes}}{1\:\mathrm{hour}}=\fbox{$125\:\mathrm{minutes}$}\)