1) The base rate for the empty bus is $120.
2) The variable cost (slope) for each person on board the bus is $2.
3) An equation to show the cost, c, of a bus with x number of people on it is C = 120 + 2x.
How the base rate and slope for the equation are derived:The total charge for taking 30 people aboard = $180
The total charge for taking 50 people on board = $220
The differences in the number of people and charges are 20 and $40, respectively.
Let x = the number of people boarding the bus and n = the fixed rate per bus.
30x + n = 180 ... Equation 1
50x + n = $220 ... Equation 2
Subtract Equation 1 from Equation 2:
20x = $40
x = $2 ($40/20)
The variable cost per person = $2 ($40/20)
The base rate for the empty bus = 30(2) + n = $180, where n is the base rate or fixed cost per bus.
= 60 + n = $180
n = $120
OR:
50(2) + n = $220
100 + n = $220
n = $120
The equation for the cost, c, of a bus with x number of people:
C = 120 + 2x
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What is the value of 6/x+2x,when x=3
Answer:
8
Step-by-step explanation:
6/3 + 2 x 3
6/3 + 6
2 + 6=8
Answer:
\(2/3\)
Step-by-step explanation:
\(\frac{6}{3x}\)
\(\frac{6}{3(3)}\)
\(\frac{6}{9} =\frac{2}{3}\)
For a school project, Leah is investigating cell phone use in her hometown, Georgetown. So far, she has found that the residents of Georgetown used their cell phones for 463,090 minutes last year. This year, they used their cell phones for a total of 370,472 minutes. What is the percent of decrease in annual usage?
Answer:
19.99%
Step-by-step explanation:
hope this helps
here you go
2 points 5. What property is used to get from Step 1 to Step 2? * Step 1 : 28x + 10 = 66 Step 2: 28x = 56
Answer: subtraction property of equality
Step-by-step explanation:
Express 88 kilometers per hour in miles per hour.
mi/hr
(Round to the nearest hundredth as needed.)
88 kilometers per hour in miles per hour is 54.68 mi/hr
Converting kilometers per hour to miles per hourNote that:
1 km = 0.6214 miles
The measurement to convert is 88 kilometers per hour
Multiply 88 kilometers per hour by 0.6214 to convert to miles per hour
88 kilometers per hour = 88 x 0.6214 miles per hour
88 kilometers per hour = 54.6832 miles per hour
88 kilometers per hour = 54.68 mi/hr
Therefore, 88 kilometers per hour in miles per hour is 54.68 mi/hr
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why are the canal and roads important for a society
Step-by-step explanation:
The steam-powered locomotive revolutionized commercial transportation by providing a durable, faster, cheaper way to move goods. The Governor Stanford was the first train on the Central Pacific, which became the first transcontinental railroad line in 1869 when it was joined with the Union Pacific.
what is the length of the side of the square with an area of 64 square feet length of a side= ___ feet?
Answer: 8ft
Step-by-step explanation:
the are of a square is 64
A=l x l or A=l^2
64= l^2
l=sqrt64=8
Please look at the photo! Thank you.
The output value of (g/f)(x) is 9x/(7x + 28).
The domain of g/f is (-∞, -4) U (-4, ∞)..
How to determine the corresponding composite function?In this exercise, we would determine the corresponding composite function of f(x) and g(x) under the given mathematical operations in simplified form as follows;
(g/f)(x) = (9/(x + 4)) ÷ 7/x
By rearranging the mathematical expression using the multiplication operation, we have the following:
(g/f)(x) = (9/(x + 4)) × x/7
(g/f)(x) = 9x/(7x + 28)
For the restrictions on the domain, we would have to equate the denominator of the rational function to zero and then evaluate as follows;
7x + 28 ≠ 0
7x ≠ -28
x ≠ -4
Domain = (-∞, -4) U (-4, ∞).
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The angle measures of $\triangle ABC$ are $A=54\degree$ , $B=38\degree$ , and $C=88\degree$ . List the sides of the triangle in order from shortest to longest.
The sides of the triangle in order from shortest to longest are b < a < c
How to determine the sides of the triangle in order from shortest to longest.In triangle ABC, the side opposite angle A is denoted by a,
The side opposite angle B is denoted by bThe side opposite angle C is denoted by c.To determine the order of the sides from shortest to longest, we need to use the triangle inequality theorem which implies that
The side opposite the largest angle is the largest side and vice versa
So, we have
b from B = 38 degrees
a from A = 54 degrees
c from C = 88 degrees
Therefore, the order of the sides from shortest to longest is: b < a < c
In other words, the side opposite angle B is the shortest, followed by the side opposite angle A, and the side opposite angle C is the longest.
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Kubin Company’s relevant range of production is 12,000 to 16,000 units. When it produces and sells 14,000 units, its average costs per unit are as follows:
Average Cost per Unit
Direct materials $ 7.30
Direct labor $ 4.30
Variable manufacturing overhead $ 1.80
Fixed manufacturing overhead $ 5.30
Fixed selling expense $ 3.80
Fixed administrative expense $ 2.80
Sales commissions $ 1.30
Variable administrative expense $ 0.80
Required:
1. Assume the cost object is units of production:
a. What is the total direct manufacturing cost incurred to make 14,000 units?
b. What is the total indirect manufacturing cost incurred to make 14,000 units?
2. Assume the cost object is the Manufacturing Department and that its total output is 14,000 units.
a. How much total manufacturing cost is directly traceable to the Manufacturing Department?
b. How much total manufacturing cost is an indirect cost that cannot be easily traced to the Manufacturing Department?
3. Assume the cost object is the company’s various sales representatives. Furthermore, assume that the company spent $39,200 of its total fixed selling expense on advertising and the remainder of the total fixed selling expense comprised the fixed portion of the company's sales representatives’ compensation.
a. When the company sells 14,000 units, what is the total direct selling expense that can be readily traced to individual sales representatives?
b. When the company sells 14,000 units, what is the total indirect selling expense that cannot be readily traced to individual sales representatives?
2. Assume the cost object is the Manufacturing Department and that its total output is 14,000 units.
a. How much total manufacturing cost is directly traceable to the Manufacturing Department? (Round per unit values to 2 decimal places.)
b. How much total manufacturing cost is an indirect cost that cannot be easily traced to the Manufacturing Department?
Show less
2a. Direct material cost per unit
2a. Direct labor cost per unit
2a. Variable manufacturing overhead per unit
2a. Fixed manufacturing overhead per unit
2a. Total manufacturing cost per unit $0.00
2a. Number of units produced and sold
2a. Total direct costs $0
2b. Total indirect costs
1a) The total direct manufacturing cost incurred to make 14,000 units is $187,600.
1b) The total indirect manufacturing cost incurred to make 14,000 units is $74,200.
2a) The total manufacturing cost directly traceable to the Manufacturing Department is $187,600.
2b) The total manufacturing cost, which is an indirect cost, that cannot be easily traced to the Manufacturing Department is $74,200.
3a) When the company sells 14,000 units, the total direct selling expense, which can be readily traced to individual sales representatives, is $18,200.
3b) When the company sells 14,000 units, the total indirect selling expense, which cannot be readily traced to individual sales representatives, is $14,000.
4a) The total manufacturing cost directly traceable to the Manufacturing Department per unit is $13.40.
4b) The total manufacturing cost, which is an indirect cost, that cannot be easily traced to the Manufacturing Department per unit is $5.30.
2a. Direct material cost per unit is $7.30.
2a. Direct labor cost per unit is $4.30.
2a. The Variable manufacturing overhead per unit is $1.80.
2a. The Fixed manufacturing overhead per unit is $5.30.
2a. The total manufacturing cost per unit is $18.70 ($13.40 + $5.30)
2a. The number of units produced and sold is 14,000 units.
2a. Total direct costs are $217,000 (14,000 x $13.40 + 14,000 x $2.10).
2b. Total indirect costs are $166,600 (14,000 x $5.30 + 14,000 x $6.60).
Data and Calculations:Relevant production range = 12,000 to 16,000 units
Production and sales units = 14,000 units
Average Cost
per Unit
Direct materials $ 7.30
Direct labor $ 4.30
Variable manufacturing overhead $ 1.80
Direct cost per unit $13.40
Fixed manufacturing overhead $ 5.30
Total manufacturing cost per unit $18.70
Fixed selling expense $ 3.80 $53,200 ($3.80 x 14,000)
Fixed administrative expense $ 2.80 $39,200 ($2.80 x 14,000)
Total fixed costs per unit $6.60 $92,400 ($6.60 x 14,000)
Variable selling and admin:
Sales commissions $ 1.30
Variable administrative expense $ 0.80
Total variable selling and admin per unit = $2.10
1a) The total direct manufacturing cost incurred to make 14,000 units is $187,600 ($13.40 x 14,000).
1b) The total indirect manufacturing cost incurred to make 14,000 units is $74,200 ($5.30 x 14,000).
2a) The total manufacturing cost directly traceable to the Manufacturing Department is $187,600 ($13.40 x 14,000).
2b) The total manufacturing cost, which is an indirect cost, that cannot be easily traced to the Manufacturing Department is $74,200 ($5.30 x 14,000).
3) Fixed selling expenses = $53,200 ($3.80 x 14,000)
Advertising expenses = $39,200
Sales Compensation = $14,000 ($53,200 - $39,200)
Sales Commission = $18,200 ($1.30 x 14,000)
Total Salespersons' compensation = $32,200
a) When the company sells 14,000 units, the total direct selling expense, which can be readily traced to individual sales representatives, is $18,200.
b) When the company sells 14,000 units, the total indirect selling expense, which cannot be readily traced to individual sales representatives, is $14,000.
4a) The total manufacturing cost directly traceable to the Manufacturing Department per unit is $13.40.
4b) The total manufacturing cost, which is an indirect cost, that cannot be easily traced to the Manufacturing Department per unit is $5.30.
2a. Direct material cost per unit is $7.30.
2a. Direct labor cost per unit is $4.30.
2a. The Variable manufacturing overhead per unit is $1.80.
2a. The Fixed manufacturing overhead per unit is $5.30.
2a. The total manufacturing cost per unit is $18.70 ($13.40 + $5.30)
2a. The number of units produced and sold is 14,000 units.
2a. Total direct costs are $217,000 (14,000 x $13.40 + 14,000 x $2.10).
2b. Total indirect costs are $166,600 (14,000 x $5.30 + 14,000 x $6.60).
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PLEASE HELP ME
Jamie used a microscope to measure the diameter of a hair. She found that the diameter of the hair was 0.000072 meter. How is this number written in scientific notation?
A. 7.2 × 10−6
B. 7.2 × 105
C. 7.2 × 10−5
D. 7.2 × 106
I need help soo yah cna you help ne?
At one university, the mean distance commuted to campus by students is 19.0 miles, with a standard deviation of 5.1 miles. Suppose that the commute
distances are normally distributed. Complete the following statements.
(ə) Approximately 99.7% of the students have commute distances between__miles
and__miles
(b) Approximately ??
of the students have commute distances between 8.8 miles and 29.2 miles.
The approximately 99.7% of the students have commute distances between 13.9 miles and 24.1 miles, the area within two standard deviation is 95%
What is the standard deviation?It is defined as the measure of data disbursement, It gives an idea about how much is the data spread out.
a) We have:
mean u = 19.0 miles,
\(\rm \sigma = 5.1 \ miles\)
According to the empirical rule, the area between \(\mu - \sigma\) and \(\mu + \sigma\) is 99.7%
\(\mu - \sigma = 19- 5.1 = 13.9\)
\(\mu + \sigma = 19+5.1 = 24.1\)
b) = P(8.8 < X < 29.2)
\(\rm P(\dfrac{8.8-\mu}{\sigma } < \dfrac{X-\mu}\sigma < \dfrac{29.2-\mu}{\sigma})\)
\(\rm P(\dfrac{8.8-19}{5.1} < Z < \dfrac{29.2-19}{5.1})\)
P(-2 < Z < 2)
Thus, the approximately 99.7% of the students have commute distances between 13.9 miles and 24.1 miles, the area within two standard deviation is 95%
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I need help with this problem plz help
Answer:
Blue is 16.6667%
Green is 21.875%
Yellow is 28.5714%
Red is 10.7143%
Step-by-step explanation:
Set up a ratio for each amount to the total, make it a fraction, simplify or try to get to 100 with a common factor, and convert to a decimal.
Answer:
Part A) \(\frac{5}{25} or \frac{1}{5}\)
Part B) \(\frac{10}{25} or \frac{2}{5}\)
Part C) \(\frac{20}{25} or \frac{4}{5}\)
Step-by-step explanation:
First of all, the total number of tiles is 25.
For part A, all you need to do is make a fraction, like this:
# of blue tiles
# of total tiles
Now, make your fraction.
\(\frac{5}{25}\) = \(\frac{1}{5}\)
So, the probability is 5/25 or 1/5.
For part B, they are asking for both green and red. So, add the number of both green and red together, and put them as a fraction like this:
# of green and blue tiles
# of total tiles
Make your fraction.
\(\frac{3+7}{25} = \frac{10}{25} = \frac{2}{5}\)
So, the probability is 10/15 or 2/5.
For part C, they are asking for all the colors except blue. So, add all colors (red, green, yellow) together, and put them as a fraction like this:
# of red, green, yellow tiles
# of total tiles
Make your fraction.
\(\frac{7+10+3}{25} = \frac{20}{25} = \frac{4}{5}\)
So, the probability is 20/25 or 4/5.
Hope this helps!
Write the scale without units: 1 mm:92 cm
Answer:
1:92
Step-by-step explanation:
that's how you write scale
pls mark brainliest
Expanded form for 4082 × 1/10=
Answer:
4000+0+80+2×0.1
Step-by-step explanation:
after expanding, /means division so you diving
The time to assemble a certain type of a computer board from acertain assembly line, has a normal distribution. The assembly times for a random sample of 20 boards are measured. The sample mean and sample standard deviation of observed times are: X-35 minutes and s-5 minutes.
a. The manager of the assembly line claims the true average time, μ, for assembling a board is less than 38 minutes. Test the manager's claim at 1% level of significance and write your conclusion.
b. Test at 5% level of significance if the true variance of the assembly time, σ, is more than 22 and write your conclusion.
Answer:
Step-by-step explanation:
(a)
From the given information; we can compute the null and the alternative hypothesis as follows:
\(H_o : \mu = 38\)
\(H_1 : \mu < 38\)
Level of significance ∝ = 1% = 0.01
The critical values of t distribution since the sample size n = 20 is:
n - 1
= 20 - 1
= 19 degree of freedom
Assuming the population is normally distributed:
The t test can be computed by using the EXCEL FUNCTION
= TINV(0.01, 19 )
= 2.539483
\(t_{0.01,19} = 2.539483\)
However;
we were also given the sample mean X to be = 35 minutes
the standard deviation SD = 5 minutes
Thus; the test statistics can be computed as;
\(t = \dfrac{\bar X - \mu}{\dfrac{s}{\sqrt{n}}}\)
\(t = \dfrac{35- 38}{\dfrac{5}{\sqrt{20}}}\)
\(t = \dfrac{-3}{\dfrac{5}{4.472}}\)
\(t_o = -2.6833\)
The P-value P ( t < \(t_o\)) = P( t < - 2.633)
= 0.007355
P-value \(\approx\) 0.0074
Decision Rule: If P - value is less than the level of significance; we are to reject the null hypothesis.
Conclusion: P-value < level of significance ; i.e 0.0074 < 0.01; so we reject the null hypothesis and accept the alternative hypothesis.
Thus; we conclude that the average time for assembling the computer board is less than 38 minutes at 0.01 level of significance.
b).
Given that:
Sample size n = 20
level of significance = 0.05
The population variance σ² is more than 22
Thus null hypothesis and the alternative hypothesis can be computed as follows:
\(H_0 : \sigma^2 = 22\)
\(H_1 : \sigma^2 < 22\)
From above;
degree of freedom df = 19
The critical value of \(X^2\) at df = 19 and ∝ = 0.05 is = 30.14353 at the right tailed region.
\(X^2_{0.05,19} =\) 30.14353
The test statistics \(X^2\) for the sample variance is computed as:
\(X^2= \dfrac{(n-1 )s^2}{\sigma^2}\)
\(X^2= \dfrac{(20-1 )25}{22}\)
\(X^2= \dfrac{(19)25}{22}\)
\(X^2= \dfrac{475}{22}\)
\(X^2\) = 21.5909
The P-value for the test statistics is :
= 1 - P( \(X^2\) < 21.5909)
= 1 - 0.694914
= 0.305086
The P-value = 0.305086
Decision Rule: If P - value is less than the level of significance; we are to reject the null hypothesis.
Conclusion: SInce the P-value is greater than the level of significance ; i.e
0.305086 > 0.05 ; Therefore; we do not reject the null hypothesis.
Therefore the data does not have sufficient information to conclude that the population variance is more than 22 at 5% level of significance.
I hope that helps a lot.
If Daniela graphed the function describing Mondays storm she would find that it is
Daniela's graph of the function describing Monday's storm depicted the storm's temporal evolution, showcasing the changing intensity of rainfall, intermittent spikes, shifting wind direction, and overall duration. Analyzing the graph allowed Daniela to gain insights into the storm's behavior and better understand its impact on the area.
Daniela graphed the function describing Monday's storm and observed several key features. The graph displayed a rapid increase in precipitation during the early morning hours, with rain intensifying steadily until reaching its peak around midday. Afterward, the precipitation gradually subsided, leading to a decline in rainfall amounts throughout the afternoon and evening.
The graph exhibited a distinct pattern of fluctuation, reflecting the storm's dynamic nature. Intermittent spikes in rainfall were visible, indicating periodic bursts of heavy precipitation throughout the day. These spikes were followed by brief periods of relative calm, during which the rainfall decreased temporarily before resuming its intensity.
Furthermore, Daniela noticed a gradual shift in wind direction as the storm progressed. Initially, the wind blew from the east, but it gradually veered towards the south as the storm system moved across the region. The change in wind direction was evident on the graph, showing a gradual rotation of the wind vector over time.
The graph also revealed the storm's duration, spanning from the early morning hours until late evening. The rainfall accumulation steadily increased during the storm's initial phase and reached a maximum before gradually tapering off towards the end of the day.
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Determine whether each ordered pair is a solution of the equation y=2x+6
The equation does not hold true, the ordered pair (3, 10) is not a solution of the equation y = 2x + 6.In this way, we can determine whether an ordered pair is a solution of the given equation or not.
Given the equation y = 2x + 6To determine if an ordered pair is a solution of this equation or not, substitute the values of x and y in the equation. If the equation holds true, then the ordered pair is a solution.
If it is not true, then the ordered pair is not a solution.For example, let's consider the ordered pair (1, 8).
Here, x = 1 and y = 8.Substituting these values in the given equation,
we get: y = 2x + 6 => 8 = 2(1) + 6 => 8 = 8 Since the equation holds true,
the ordered pair (1, 8) is a solution of the equation y = 2x + 6.
Now, let's consider another ordered pair, say (3, 10). Here, x = 3 and y = 10.Substituting these values in the given equation, we get: y = 2x + 6 => 10 = 2(3) + 6 => 10 = 12
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The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with grams of a radioactive isotope, how much will be left after 4 half-lives?
After 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.
The amount of a radioactive isotope remaining after a certain number of half-lives can be calculated using the formula:
Amount remaining = Initial amount × (1/2)^(number of half-lives)
In this case, we are given the initial amount as "grams" and we want to find out the amount remaining after 4 half-lives.
So, the equation becomes:
Amount remaining = Initial amount × (1/2)^4
Since each half-life reduces the quantity to half, (1/2)^4 represents the fraction of the initial amount that will remain after 4 half-lives.
Simplifying the equation:
Amount remaining = Initial amount × (1/16)
Therefore, after 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.
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Matt has two very active dogs...
x = 4 and y = 5 is a solution to x + y = 10? agree or disagree
Answer:
Disagree
Step-by-step explanation:
X+y equals 9 if 4 replaces x and 5 replaces y not 10.
5x-6=29. What does x equal
Answer:
Solution given:
5x-6=29.
5x=29+6
x=35/5=7
x=7 is your answer
Answer:
x=7
Step-by-step explanation:
Is the relation shown in
the table a function?
Explain.
The inputs 4 and 8 have more than one out, the relation is not a function.
Is the relation shown in the table a function?A relation is said to be a function if one input is mapped to one output.
that is, each x-value can only have one y-value.
From the table;
Input, output
4 ----- 1
8 ----- 3
4 ------5
8 ----- 4
4 is an input, it has an output of 1.
4 appeared again as input but this time has an output of 5.
This means one input has more than one output.
Also, 8 is an input, it has an output of 3.
8 appeared again as input but this time has an output of 4.
Which also means one input has more than one output.
Therefore, the relation is not a function.
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The equation T^2= A^3 shows the relationship between a planets orbital period, T, and the planets mean distance from the sun, A, in astronomical units, AU. if the orbital period of planet Y is twice the orbital period of planet x, by what factor is the mean distance increased?
The mean distance increased by a factor of 2^(²/₃)
How to find the factor of increase?
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is;
T² = A³.
Let the orbital period of planet X = T(X).
Let the orbital period of planet Y = T(Y).
Let the mean distance of planet X from the sun = A(X).
Let the mean distance of planet Y = A(Y).
Thus;
A(Y) = 2A(X)
Therefore;
[T(Y)]² = [A(Y)]³ = [2A(X)]^3
However, [T(X)]² = [A(X)]³
Thus;
[T(Y)]² = 2³[T(X)]² * [T(Y)]²/[T(X)]² = 2³T(Y)/T(X) = 2^(³/₂)
That's for orbital period but the mean distance will increase by 2^(²/₃)
Thus we conclude that, the mean distance increased by a factor of 2^(²/₃)
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Answer:
2 Superscript three-halves
Step-by-step explanation:
Edge
According to the property , which choice is equivalent to the quotient below?3577 35 A.5B.C.D.-5E.25
Answer:
Option A is the right answer mate...
A report states that the mean household income last year for a certain rural county was $46,200 and the median was $37,800. If a histogram were constructed for the incomes of all households in the county, would you expect it to be skewed to the right, to the left, or approximately symmetric
Answer:
skewed to the right
Step-by-step explanation:
Given that
the mean household income for the last year was $46,200
And, the median was $37,800
In the case when the historgram is prepared so the income would be skewed to the right as the mean i..e $46,200 is more tha the median i.e. $37,800
So, the distribution would be right skewed
Hence, the same would be considered and relevant
Solve for x.
0≤3x-6≤18
A 0≤x≤8
B 2≤x≤8
C x≤0 orx≥8
D x≤2 or x ≥8
Answer:
B) 2≤x≤8.
Step-by-step explanation:
Add 6 to all sides of the inequality.
0+6≤3x-6+6≤18+6
6≤3x≤24
Divide all sides by 3.
2≤x≤8
The correct answer is B) 2≤x≤8.
PLEASE HURRY DUE TODAY WILL MARK BRAINLESTIS RIGHT
what is √29 Place a dot on the number line at the BEST approximation
Answer:
5.4
Step-by-step explanation:
square of 29 = 5.385164807
5.385164807 estimated is 5.4
4. Which of the following number of pairs have the same ratios?
8 and 3; 56 and 21; 104 and 36; 896 and 336.
Answer:
8 and 3; 56 and 21; 896 and 336 all have the same ratio i.e. 8:3
Use the following sets to answer the question.
A={1,2,3,4,5}
B={5,6,7,8}
Which answer shows the union of sets A
and B?
{5}
{1,2,3,4,6,7,8,9}
{1,2,3,4,5,6,7,8}
{2,4,8}
The union of sets A and B is {1, 2, 3, 4, 5, 6, 7, 8}.
The union of two sets A and B is the set of all elements that are in A, or B, or both. In this case, the elements in set A are {1, 2, 3, 4, 5} and the elements in set B are {5, 6, 7, 8}.
To find the union of these sets, we simply combine all the elements from both sets but remove any duplicates.
Therefore, the answer that shows the union of sets A and B is {1, 2, 3, 4, 5, 6, 7, 8}, since it contains all the elements from both sets without any duplicates.
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