a capacitor has a capacitive reactance of 50 when connected to a 60-hz line. what will be the capacitive reactance if the capacitor is connected to a 1000-hz line?

Answer:

√(0.7 * 9.81m/s^2 * r)

Explanation:

To determine the maximum speed at which the 800kg car can travel around the curve, the engineer needs to consider the forces acting on the car as it goes around the curve. Specifically, the engineer needs to consider the centrifugal force and the frictional force between the wheels and the road.

The centrifugal force is the force that acts on an object moving in a circular path and is directed away from the center of the circle. It is given by the equation Fc = mv^2 / r, where m is the mass of the object, v is the velocity of the object, and r is the radius of the curve.

The frictional force between the wheels and the road is given by the equation Ff = μFn, where Ff is the frictional force, μ is the coefficient of friction between the wheels and the road, and Fn is the normal force between the wheels and the road. The normal force is the force that acts perpendicular to the surface of the road and is equal in magnitude to the weight of the car (mg, where g is the acceleration due to gravity).

The maximum speed at which the car can travel around the curve occurs when the centrifugal force and the frictional force are in balance, meaning that they have the same magnitude. In this case, we can set Fc = Ff and solve for v.

Substituting the given values into the equations for Fc and Ff and setting them equal to each other, we get:

Fc = Ff

mv^2 / r = μmg

Solving for v, we find that the maximum speed at which the car can travel around the curve is:

v = √(μgr)

= √(0.7 * 9.81m/s^2 * r)

This is the maximum speed at which the car can travel around the curve without sliding or losing traction. The actual value of v will depend on the radius of the curve, which is not given in the problem.

Applying a net force of 10.0 N for 0.5 m/s will produce the greatest change of momentum for a 1.0-kilogram cart.

The situation that produces the greatest change of momentum for a 1.0-kilogram cart is (D) applying a net force of 10.0 N for 0.5 m/s. This option results in the greatest change in momentum as it involves the greatest impulse. Impulse is the product of force and time or the change in momentum of an object. The impulse can be calculated using the formulaImpulse (J) = force (F) x time (t)or J = FtWhen a force is applied to an object, it creates a change in momentum. The greater the force or the longer the time of application of the force, the greater the change in momentum. A net force of 10.0 N is applied for 0.5 s. Therefore, the impulse generated is given by J = (10.0 N) x (0.5 s) = 5.0 Ns.Due to the impulse, the velocity of the cart will change from its initial velocity. As momentum is conserved, the change in momentum of the cart will be equal to the impulse applied to it.

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Answer:

Dorsal side:B

Ventral side:D

Anterior end:A

Posterior end:C

Explanation:

The four regions of the earthworm are, A is the anterior end,B is the dorsal side, C is the posterior end, and D is the ventral side.

Earthworms are common soil dwellers who are both safe and useful. Earthworms help plants flourish by collapsing dead and decaying organic debris into rich humus soil.

They also aerate the soil and enhance flow by digging small canals and holes.

The four regions of the earthworm are;

A is the Anterior end

B is the Dorsal side

C is the Posterior end

D is the Ventral side

Hence all the regions are clearly defined with the help of digrame.

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Moment of inertia of thin cylindrical body = MR²/2 and Rotational kinetic energy= 1/2 × moment of inertia × (angular speed)²

a) As the angular acceleration If the style starts from rest.

Angular acceleration (in rad/s²) of the style if, starting from rest, it reaches a rotation speed of 12.0 rpm in 10.7s will be

angular acceleration= angular speed / time

angular acceleration= (12×2π)÷(10.7×60)

angular acceleration= 0.117 rad/s².

b) Angle (in rad) through which the style rotates to reach its final rotational speed after 10.7 seconds will be-

angle= 1/2 × angular acceleration × time²

angle = 1/2 × 0.117 × (10.7)²

angle = 6.697 rad.

c) The rotational kinetic energy (in j) of the 3.00 g style once it reaches its final rotational speed after 10.7 seconds will be-

Rotational kinetic energy= 1/2 × moment of inertia × (angular speed)²

and Moment of inertia of the cylindrical protrusion 5.00 mm in length and 0.800 mm in diameter style = (mass × radius²) ÷ 2

(Since moment of inertia of thin cylindrical shell = MR²/2)

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False. The center of gravity in most adult humans is not located in the spine.

The center of gravity refers to the point where the entire weight of an object or a person can be considered to act. In most adult humans, the center of gravity is located slightly anterior to the second sacral vertebra, which is in the pelvic region, rather than in the spine.

The human body is a complex structure with various anatomical components, including the head, trunk, and limbs. The distribution of mass within the body affects the location of the center of gravity. While the spine plays an important role in providing structural support and maintaining upright posture, the center of gravity is determined by the combined effect of the entire body's mass distribution.

Therefore, the statement that the center of gravity in most adult humans is located slightly in the spine is false.

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This process is called a quantization error. It is the difference between the analog signal and digital values.

Quantization error refers to the difference between analog signals and their closest digital values during the process of sampling.

This process (quantization error) involves an A/D converter, i.e., an analog to a digital converter (ADC).

The A/D converter is a type of converter that acts by capturing analog signals at given fixed time intervals.

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Answer:

D

Explanation:

The resultant displacement of  Matsushima is 330.72 miles.

The resultant displacement of an object is the change in the position of the object. It can also be described as the shortest path connecting the initial position and final position of an object.

The resultant displacement of  Matsushima is calculated by applying parallelogram law of vector addition as shown below.

d² = a² + b² - 2ab cos(θ)

where;

Substitute the given parameters and solve for the resultant displacement of  Matsushima as shown below.

d² = (250)² + (125)² - 2(250 x 125) cos(120)

d² = 109,375

d = √109,375

d = 330.72 mi

Thus, the resultant displacement of Matsushima depends on the initial position, final position and angle between the two position as shown in the parallelogram law of vector additions.

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The angular displacement of the car is 48.125 radians.

The angular displacement of the car can be calculated using the formula:

θ = ω_i t + (1/2) α\(t^2\)

where:

θ = angular displacement

ω_i = initial angular velocity

t = time

α = angular acceleration

At the initial velocity, ω_i = 45.0 rad/s. After the brakes are applied, the car slows down to a final angular velocity of 10.0 rad/s in 1.75 s, which gives an angular acceleration of:

α = (ω_f - ω_i) / t = (10.0 rad/s - 45.0 rad/s) / 1.75 s = -20.0 rad/\(s^2\)

Substituting the values in the formula, we get:

θ = (45.0 rad/s) (1.75 s) + (1/2) (-20.0 rad/s^2) (1.75 s)^2

θ = 78.75 rad - 30.625 rad

θ = 48.125 rad

Therefore, the angular displacement of the car is 48.125 radians.

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The particle with a larger acceleration at any one moment when a proton and an electron are held apart a distance of 1 m and then released is the electron.

This is because the force between the two particles is given by Coulomb's law which states that the force of attraction or repulsion between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.The equation is given as;F=kq1q2/r^2where F is the force, k is the constant of proportionality, q1 and q2 are the charges of the two particles, and r is the distance between them.The proton and electron have opposite charges, and so there is a force of attraction between them. However, since the electron has a much smaller mass than the proton, it will experience a larger acceleration due to this force.

This is because the force of attraction between the two particles is given by Coulomb's law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.F = kq1q2/r^2where F is the force, k is the constant of proportionality, q1 and q2 are the charges of the two particles, and r is the distance between them. Since the proton and electron have opposite charges, there is a force of attraction between them.However, since the electron has a much smaller mass than the proton, it will experience a larger acceleration due to this force. Therefore, the electron has a larger acceleration at any one moment.

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The particle with the larger acceleration is the proton, as the proton is heavier than the electron and they both will experience the same force as they are at the same distance from each other.

The force of attraction between two charged particles is given by Coulomb's law, which states that the force of attraction between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. This means that as the distance between the particles decreases, the force of attraction between them increases. Hence, as the distance between the proton and the electron decreases, the force of attraction between them increases, leading to an increase in acceleration. The acceleration of both the proton and the electron will continue to increase until they collide and cancel each other's charges.

The acceleration of an object is the rate at which its velocity changes over time. It is given by the formula

a = F/m,

where a is the acceleration, F is the force applied to the object, and m is the mass of the object.

Therefore, in the given scenario, both particles will experience the same force of attraction but the proton has a larger mass than the electron, so the proton will have a smaller acceleration than the electron. This means that the proton will move towards the electron at a slower speed compared to the electron, as acceleration is directly proportional to speed.

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Answer:

Hi... Potential energy is converted to kinetic energy and kinetic energy is converted to potential energy

Amy's distance and displacement if she runs 2 miles south, then turns around and runs 3 miles north is 1 mile.

This is referred to as the change in the position of an object and it is usually measured in meters by finding the difference in location between the two bodies involved.

We were told that she runs 2 miles south, then turns around and runs 3 miles north and they are at exact opposite sides on the map which means that the displacement will be:

3 miles - 2 miles

= 1 mile hence, it is the correct choice.

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Wanda can reply to her friend by saying that she is using a telephoto lens for their photography outing.

A telephoto lens is a type of camera lens that is designed to capture distant subjects by using a longer focal length than a standard lens. Telephoto lenses typically have a focal length of 60mm or longer, which allows them to see and record a very narrow view. This makes them ideal for capturing subjects that are far away, such as wildlife, sports events, and landscapes. Telephoto lenses are also popular for portrait photography because they can create a shallow depth of field, which helps to isolate the subject from the background.

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Answer:

All the options (a, b, c, and d) are correct situations for negative value of acceleration due to gravity.

Explanation:

Acceleration due to gravity is always acted towards the center of the earth. It's magnitude is \(9.8\rm{m/s^{2}}\).

As per the sign convention, downward direction is considered as negative.

Now, consider the cases:

1. When an object or ball is thrown upward: While moving upwards, gravity or gravitational acceleration opposes the motion of object. The object speed or displacement will be positive while gravity will be negative.

2. When an object is at the top or highest point of their path: When the object is at the top of its path, the gravity still acts downwards and the velocity becomes zero. So, gravity will be negative at this position.

3. When object is falling downward: While falling downwards, the acceleration and velocity will be negative as they both are directed downwards.

From the above points, the value of gravity will always be negative.

Therefore, in all the given options (a, b, c, and d), the acceleration will be \(-9.8\rm{m/s^{2}}\).

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Answer:

Explanation:

57.8 m/s

The direction of light wave changes when they are reflected or refracted. So, all the statements are true.

Light waves are defined as the electromagnetic waves made of smaller, energy carrying particles called photons.

Here,

Light is an electromagnetic radiation that can have the properties of both waves and particles.

Light waves can travel in straight lines in the transparent medium like air, glass, still water, etc.

Light waves can travel through any medium or substances.

Sources of light are of two types, natural source and artificial source.

Reflection and refraction are the two properties of light.

Reflection is the phenomenon exhibited by light through which a ray of light incident on a smooth, reflecting surface, gets bounced back. Thus, during reflection, the direction of the light ray changes.

Refraction is the phenomenon by which the the speed of the light decreases when light wave travels from a lighter medium to denser medium. The light wave will bend towards the normal line. Thus, during refraction, the direction of light wave changes.

Hence,

The direction of light wave changes when they are reflected or refracted. So, all the statements are true.

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Answer:

the answer to this question is A

Answer:

It is D. Almost no mass

Explanation:

The mass of an electron is 1/2000 times of proton/neutron

The most useful type of electromagnetic wave to investigate for keeping coffee warm would be infrared radiation. Infrared radiation is particularly suitable for this purpose because it can efficiently transfer heat energy without the need for direct contact between the heat source and the coffee.

Infrared radiation is a type of electromagnetic wave with longer wavelengths than visible light. It is commonly associated with heat energy and is capable of transferring thermal energy from one object to another. In the context of keeping coffee warm, infrared radiation can be used to transfer heat energy to the coffee.

The process works by utilizing the principle of thermal radiation. An infrared emitter, such as a heating element, emits infrared radiation that is absorbed by the coffee. As the coffee absorbs the infrared radiation, the energy is converted into heat, raising the temperature of the coffee and keeping it warm.

Furthermore, infrared radiation is relatively safe and widely used in various heating applications. It is also readily available and can be generated using different technologies, making it a practical choice for creating a device to keep coffee warm.

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The range of speeds the object can have before the string breaks is approximately 4.63 m/s to 9.77 m/s.

To determine the range of speeds, we need to consider the tension in the string. At maximum speed, the tension in the string is equal to the centripetal force required to keep the object moving in a circle. This can be calculated using the formula: T_max = m * v_max² / r, where T_max is the maximum tension, m is the mass of the object, v_max is the maximum speed, and r is the radius of the circle.

Since the tension in the string cannot exceed the breaking strength of 250 N (25.0 kg × 9.8 m/s²), we can set up the following inequality: m × v_max² / r ≤ 250 N. Simplifying the inequality, we have v_max² ≤ 250 N × r / m.

Taking the square root of both sides, we get v_max ≤ √(250 N × r / m). Plugging in the given values (r = 0.800 m, m = 3.00 kg), we can calculate the maximum speed: v_max ≤ √(250 N × 0.800 m / 3.00 kg) ≈ 9.77 m/s.

Similarly, we can calculate the minimum speed by considering the tension at minimum speed, which is zero. Using the same formula, we get v_min ≤ 0 m/s. Therefore, the range of speeds is approximately 0 m/s to 9.77 m/s.

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Complete question:

A light string can support a stationary hanging load of 25.0 kg before breaking. An object of mass m = 3.00 kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.800 m, and the other end of the string is held fixed. What range of speeds can the object have before the string breaks?

Answer:

4A*12Ω=48V

Explanation:

If the strong force was suddenly turned off throughout the universe, atoms would almost immediately disintegrate as the strong force is responsible for holding the nucleus of an atom together.

This would result in a release of energy as the protons and neutrons in the nucleus repel each other due to the electromagnetic force. The energy released would be so great that it would cause a massive explosion, similar to a nuclear explosion. Furthermore, the absence of the strong force would also affect the stability of neutron stars and supernovae, which rely on the strong force to maintain their structure. Overall, the absence of the strong force would result in a catastrophic and potentially apocalyptic scenario for the universe.

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The reason why the book does not slide off the teacher's hand when she tilts her hand forward is because of the force of friction between the surfaces of the book and the teacher's hand.

Friction is a force that resists the motion between two surfaces that are in contact. When the book is resting on the teacher's hand, the surfaces of the book and the hand are in contact with each other. When the teacher tilts her hand forward, the force of gravity tries to pull the book downward, but the force of friction between the book and the hand acts in the opposite direction, preventing the book from sliding off the hand.

The amount of friction between two surfaces depends on a few factors, such as the type of materials in contact, the roughness of the surfaces, and the force pressing the surfaces together. The force of friction increases as the force pressing the surfaces together increases. In this case, the weight of the book pressing down on the teacher's hand increases as the hand tilts forward, which increases the force of friction between the book and the hand, keeping the book in place.

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Answer:

B

Explanation:

-1 e so the atomic number should increase so,

B. Np

Answer:

Solution:

i) Heat supplied by heater = Heat gained by water = m * c*theta = 0.12Kg * 4200 * 10 = 5040Joules in 2 minutes.

ii) Power = Energy/time = 5040J/(2 * 60seconds) = 5040J/120seconds = 42Watts.

(iii) Heat supplied to the 70g of water = m * c * theta = 0.07Kg * 4200 * 9K = 2646J

(iv) Heat supplied by heater = Heat gained by 70g of water + Heat supplied to the metal vessel.

But,from our calculations above,

Heat supplied by heater = 5040J ......and

Heat supplied to the 70g of water = 2646J

.: substituting the values,we have that :

5040J = 2646J + Heat supplied to the metal vessel.

5040J - 2646J = Heat supplied to the metal vessel.

.: Heat supplied to the metal vessel = 2394J.

(v) Heat gained by metal vessel = Heat capacity of the vessel * theta.

2394J = Heat capacity of the vessel * 9K

.: Heat capacity of the vessel = 2394/9 = 266(Joule per Kelvin)

(vi) Using the formula:

Heat Capacity = mass * specific heat capacity

.: Specific heat capacity = Heat Capacity/mass = 266/0.55 = 484(Joules per Kilogram per Kelvin)

Explanation:

By Avogadro's number, the mass of Neon atom is 20 grams.

We need to know about Avogadro's number to solve this problem. Avogadro's number is the number that explains how many carbon atoms are in one mol. The Avogadro's number is

Na =  6,02 × 10²³ atoms / mol

From the question above, we know that

Mr = 20

N = 6,02 × 10²³ atoms

By using Avogadro's number, we can calculate how much Neon atoms

N = n . Na

6,02 × 10²³ = gr / Mr . 6,02 × 10²³

gr / 20 = 1

gr = 20 grams

Hence, the mass of Neon atom is 20 grams.

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No, it is not safe to plug the oscilloscope into the wall power source while using the EMG circuit. The EMG circuit is connected to the body through electrodes, and the amplified signal is being powered by a 6v battery. Since the entire circuit is battery powered, it was decided that an isolation amplifier was not needed.

However, when the oscilloscope is plugged into the wall power source, there is a risk of electrical shock or interference. The wall power source has a different ground potential than the battery powering the EMG circuit, which can cause ground loops and interfere with the EMG signal. This can be potentially dangerous and can also affect the accuracy of the EMG measurements.

In summary, it is not safe to plug the oscilloscope into the wall power source while using the EMG circuit. This is because it can cause ground loops and interfere with the EMG signal, which can be potentially dangerous and affect the accuracy of the measurements. It is recommended to use a battery-powered oscilloscope or to ensure that the oscilloscope and EMG circuit are properly grounded and isolated from each other.

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answer:

b. when objects attract they pull each other together and when they repel the push each other apart.

explanation:

Using Newtons law

\(\\ \sf\longmapsto Force=Mass\times Acceleration\)

\(\\ \sf\longmapsto Mass=\dfrac{Force}{Acceleration}\)

\(\\ \sf\longmapsto Mass=\dfrac{340}{3.8}\)

\(\\ \sf\longmapsto Mass=89.4kg\)

Answer:

a) the building of irrigation systems

Explanation:

Although b and c would also allow for farmers to grow more crops, I believe that the building of irrigation systems had the most impact. Irrigation systems allowed for farmers to have larger fields without having to spend a large amount of time watering the entire field.

Answer: I think it is a

Explanation:

answer:

click on the picture, hope it helps

The magnitude of the electric field at that location is is 40  N.C⁻¹.

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

Electric charge or magnetic fields with variable amplitudes can produce an electric field.

Given parameters:

Charge of the positive test charge, q =  5.0x10⁻⁶ C.

Electric force exerted by the electric field, F = 2.0x10⁻⁴ N.

Then, electric field at the position, E = F/q

= 2.0x10⁻⁴ / 5.0x10⁻⁶ N.C⁻¹.

= 40  N.C⁻¹.

Hence,  the magnitude of the electric field at the location of the test charge is 40  N.C⁻¹.

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