A car accelerates from rest for 8.0 s, and reaches a speed of 66 m/s. How far will the
car travel?
a) 8448 m
b) 2112 m
c) 264 m
d) 528 m

The specific heat of a metal is 54.89J/kg.K

What does "specific heat" mean?

Specific heat is the amount of energy needed to raise a substance's temperature by one degree Celsius per gram. Typically, the units of specific heat are calories or joules per gram per degree Celsius.

Given: The bottle weighs 3.6 kg and holds 13.5 kg of water.

The weight of the metal is 1.8 kg, and its initial temperature is 175 C.

From 16 to 18 degrees Celsius, the temperature rises.

The container and water both received the same amount of heat from the metal object.

Qp = Qw +Qc

​(mp)cΔT= (mw)(cw)ΔT + (mc)cΔT

where, respectively, p, w, and c stand for a metal object, a liquid, and a container.

c = [(mw)(cw)ΔT] / [(mp)cΔT -  (mc)cΔT]

  =[ 13.5*4187*(18-16) ] / [1.8*(175-16) - 3.6* (18-16)]

  =  54.89J/kg.K

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When the scientists draw conclusions the scientist find out whether the hypothesis was supported.

A hypothesis is a theory put up to explain a phenomenon. A hypothesis cannot be called a scientific hypothesis unless it can be tested using the scientific process.

Once your experiment is complete, you collect your measurements and analyze them to see if they support your hypothesis.

Scientists frequently discover that their hypotheses and predictions were not supported by the results of their experiments. In these circumstances, they will discuss the results of their experiment before reevaluating their initial theories and predictions in light of the fresh information. The scientific method is essentially restarted in this way. Even if they discover that their theory was correct, they could still wish to verify it once more using a different approach.

The correct option is (a).

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Answer:

The presence of water

Explanation:

Any evidence of water that might appear on the still photo would be a clear indication of life on the planet. This is because scientists believe that for life to thrive elsewhere as it has done here on Earth, it needs water. Water is necessary for fertilization of reproductive cells for some organism, and for others it is where their developing young starts life from. For most, all life biochemical system needs a certain level of moisture to function properly.

It's important to know that when poles have the same nature, the force is repulsive. But, when the poles have different nature, the force will be attractive.

Answer:

answer is 0.51

Explanation:

Force applied on the block is F = 20 N.

Mass of the block is m = 4 kg.

The weight of the block is

W=mg

\(4 \times 9.8 = 39.2\)

W = 39.2N

let the coefficient of static friction is μ

The force of friction acting on the block is given by

F = μ × N

where N is the normal reaction equal to the weight of the box

20 = μ × W

20 = μ × 39.2

μ = 20/39.2 = 0.51

Answer:

Explanation:

So the equation is ........

\(\huge\ \blue{F=UR} \)

and the weight of the block = 4 × 10

= 40 N

so , use the formula .....

Answer: W = \(1.04.10^{-20}\) J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

\(W=q.\Delta V\)

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = \(1.6.10^{-19}\) C

To determine work in joules, potential has to be in Volts, so:

\(\Delta V=65.10^{-3}V\)

Then, work is

\(W=1.6.10^{-19}.65.10^{-3}\)

\(W=1.04.10^{-20}\)

To move a potassium ion from the exterior to the interior of the cell, it is required \(W=1.04.10^{-20}\)J of energy.

Answer:

Mean distance = 1.61 x 10^8 km

Explanation:

Given the following data;

Orbital period for Icarus, T2 = 410 days

To find the mean distance of Icarus, we would use Kepler's third law of motion.

According to Kepler's third law of planetary motion, the square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.

Mathematically, it is given by the formula;

\( (\frac {T_{1}}{T_{2}})^2 = (\frac {r_{1}}{r_{2}})^3 \)

Where;

T1 & T2 is the orbital period of a planetary object.

r1 & r2 is the mean distance of a planetary object.

Also, we know that the orbital period for earth, T1 = 365 days

Mean distance of earth = 1.49x10^8 km

Substituting into the equation, we have;

\( (\frac {365}{410})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 \)

\( (\frac {365}{410}})^2 = (\frac {1.49x10^{8}}{r_{2}})^3 \)

\( (0.8902)^2 = (\frac {1.49x10^{8}}{r_{2}})^3 \)

\( (0.7925) = (\frac {1.49x10^{8}}{r_{2}})^3 \)

Cross-multiplying, we have;

\( (r_{2})^3 = \frac {1.49x10^{8}}{0.7925} \)

Taking the cube root of both sides;

\( r_{2} = 1.61 * 10^8 km\)

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

\(\qquad\qquad\huge\underline{{\sf Answer}}\)

The Correct choice is : D

Neutrons and Protons are collectively known as Neucleons because they are found in nucleus of the cell and they have almost equal mass, [ but neutron has slightly greater mass than proton ]. also, Neutrons are neutral particle with no charge on them, where as protons have positive charge on them. making nucleus positively charged altogether ~

Answer:

Option D

Explanation:

Answer:

Question 1 is "need them to survive"

Explanation:

vital means necessary or needed

The meaning of the word vital in this passage is "need them to survive". Therefore, option D is correct.

The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis. Chloroplasts, which house the chlorophyll in plants, are where photosynthesis occurs. The thylakoid membrane, a third inner membrane that creates long folds inside the chloroplast and is bordered by a double membrane, is present inside chloroplasts.

Photosynthesis is very important for the survival of organisms because they get energy from photosynthesis. Life on earth is impossible without this process.

The meaning of the word vital in this passage is "need them to survive". Therefore, option D is correct.

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The velocity of the running back is 8 m/s.

To calculate the velocity of the running back, we can use the work-energy principle. The work-energy principle states that the work done on an object will be equal to the change in its kinetic energy.

Given; Mass of the running back (m); 80 kg

Work done (W); 2560 Joules

We can use the formula for kinetic energy;

KE = 0.5 × m × v²

where KE is the kinetic energy, m is the mass, and v is the velocity of the running back.

According to the work-energy principle, the work done is equal to the change in kinetic energy;

W = KE - KE0

where KE0 is the initial kinetic energy.

Rearranging the formula for kinetic energy, we get;

KE = 0.5 × m × v²

Substituting the given values, we get;

2560 = 0.5 × 80 × v²

Solving for v;

v² = (2 × 2560) / 80

v² = 64

v = √(64)

v = 8 m/s

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Answer:

h=4+85*time - 1/2 32*time^2

16time^2-85*time-106=0

use the quadratic formula to solve for time (notice two solutions, one going up, one going back down).

time=(85+-sqrt(85^2+4*16*106) )/32

Explanation:

Recheck my work just in case I'm not good at this type of class but I wanted to help.

a. At maximum height h, the baseball has zero vertical velocity, so that with initial velocity v we have

\(0^2-v^2 = -2gh \implies h = \dfrac{v^2}{2g}\)

Given that \(v = 30 \frac{\rm m}{\rm s}\), the ball reaches a height of

\(h = \dfrac{\left(30\frac{\rm m}{\rm s}\right)^2}{2g} \approx \boxed{46\,\mathrm m}\)

b. At max height, the baseball's vertical velocity is such that

\(0=v-gt\)

For \(v = 30 \frac{\rm m}{\rm s}\), we find

\(gt=30\dfrac{\rm m}{\rm s} \implies t = \dfrac{30\frac{\rm m}{\rm s}}g \implies t \approx 3.1 s\)

which is half the time it spends in the air, making the total time about 6.1 s.

c. We saw in part (a) that

\(h = \dfrac{v^2}{2g}\)

If we halve the initial speed and replace \(v\) with \(\frac v2\), we get

\(h = \dfrac{\left(\frac v2\right)^2}{2g} = \dfrac14 \cdot \dfrac{v^2}{2g}\)

which means the max height is reduced by a factor of 1/4.

In part (b), we found the time to max height is

\(t = \dfrac{v}{g}\)

and halving the initial speed gives

\(t = \dfrac{\frac v2}g = \dfrac12 \cdot \dfrac{v}{g}\)

That is, the time to max height is reduced by a factor of 2 when the speed is halved, and so the overall time in the air is reduced by a factor of 2.

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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The magnitude of the braking force of the car of mass 1252 kg is 265.98 N.

Force can be defined as the product of mass and acceleration.

To calculate the magnitude of the braking force, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the magnitude of the braking force is 265.98 N.

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Answer:

No, positive charges cannot be liberated by the photoelectric effect.

Explanation:

Answer:

The first law, also called the law of inertia, was pioneered by Galileo. This was quite a conceptual leap because it was not possible in Galileo's time to observe a moving object without at least some frictional forces dragging against the motion. In fact, for over a thousand years before Galileo, educated individuals believed Aristotle's formulation that, wherever there is motion, there is an external force producing that motion.

The second law, $ f(t)=m\,a(t)$ , actually implies the first law, since when $ f(t)=0$ (no applied force), the acceleration $ a(t)$ is zero, implying a constant velocity $ v(t)$ . (The velocity is simply the integral with respect to time of $ a(t)={\dot v}(t)$ .)

Newton's third law implies conservation of momentum [138]. It can also be seen as following from the second law: When one object ``pushes'' a second object at some (massless) point of contact using an applied force, there must be an equal and opposite force from the second object that cancels the applied force. Otherwise, there would be a nonzero net force on a massless point which, by the second law, would accelerate the point of contact by an infinite amount.

Explanation:

The frequency of the object in circular motion is 0.06 Hz.

The formula to calculate the frequency is derived as follows;

The angular speed, ω is related to the frequency, f, as follows;

ω = 2πf

The linear velocity is related to angular velocity as follows:

v = r ω

ω = v/r

where;

v is the linear speed,

r is the radius, and

ω is the angular speed

Hence,

f = v/2πr

f = 7 / (18.7 * 2π)

Frequency, f = 0.06 Hz

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Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved

There is a negative correlation between mass and acceleration.

option B is the correct answer.

The net force applied on an object is the sum of the all the forces acting on an object.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

Mathematically, the Newton's second law of motion is given as;

F = ma

where;

a = F/m

Thus, acceleration and mass are inversely related. That is as the mass of an object increases, the acceleration of the object decreases provided that the applied force remains constant.

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The kinetic energy of the racing car is approximately 849952.4 J joules.

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Convert the speed from kilometers per hour to meters per second since the units of mass and velocity need to be consistent.

We know that 1 km/h = 0.27777 m/s, so:

120 km/h x (0.27777 m/s/km/h) = 33.3336 m/s (rounded to 4 decimal places)

Now we can substitute the values into the formula:

Kinetic Energy = (1/2) × 1530 kg x (33.3336 m/s)²

Kinetic Energy = 849952.4 J

Therefore, the kinetic energy is approximately 849952.4 joules.

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Answer;

1. Accuracy is the closeness with which an instrument approaches the true value of the quantity being measured

2. Precision is a measure of the reproducibility of the measurement

3. Accuracy may be specified in terms of limits of errors.

Answer:

A

Explanation:

may i be marked brainliest?

Statement A correctly characterizes the relationship between water vapor and air. Colder air can hold more water vapor.

Under constant air pressure and water content, the dew point is the temperature at which air must be chilled to become saturated with water vapor.

When temperatures fall below the dew point, moisture capacity decreases and airborne water vapor condenses to create liquid water known as dew.

As the temperature of the air increases the vapor become more and dry. So that older air can hold more water vapor.

Hence,statement A correctly characterizes the relationship between water vapor and air.

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Answer:

The strength of the electric field is \(E=15.66\: N/C\)

Explanation:

Here the electric force is equal to Newton's second law.

\(F_{e}=ma\)

Let's recall that electric force is the electric field times the charge, so we have:

\(qE=ma\)

\(E=\frac{ma}{q}\) (1)

Where:

m is the proton mass

q is the proton charge

a is the acceleration        

Using the equation (1) we have:

\(E=\frac{1.67*10^{-27}1.5x10^{9}}{1.6*10^{-19}}\)

Therefore, the strength of the electric field is \(E=15.66\: N/C\)

I hope it helps you!

a. The magnitude of the electric force that one particle exerts on the other is 1.72 millinewtons (mN). and b. the force is repulsive

To calculate the magnitude of the electric force between two charged particles, we can use Coulomb's Law, which states that the magnitude of the electric force (F) between two charged objects is given by:

F = k * (|q1| * |q2|) / r^2

where k is the electrostatic constant (k = 8.99 x 10^9 N·m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

Given:

q1 = 8.01 nC (nanocoulombs)

q2 = 4.22 nC (nanocoulombs)

r = 1.72 m

Converting the charges to coulombs:

q1 = 8.01 x 10^-9 C

q2 = 4.22 x 10^-9 C

Plugging the values into Coulomb's Law:

F = (8.99 x 10^9 N·m^2/C^2) * ((8.01 x 10^-9 C) * (4.22 x 10^-9 C)) / (1.72 m)^2

Calculating the magnitude of the force:

F ≈ 1.72 x 10^-3 N

Therefore, the magnitude of the electric force that one particle exerts on the other is approximately 1.72 millinewtons (mN).

To determine if the force is attractive or repulsive, we need to consider the signs of the charges. If the charges have opposite signs (one positive and one negative), the force is attractive. If the charges have the same sign (both positive or both negative), the force is repulsive.

In this case, both charges are positive, so the force between them is repulsive. The particles will experience a repelling force due to their like charges, causing them to push away from each other.

The question was incomplete. find the full content below:

Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.  

(a) What is the magnitude (in N) of the electric force that one particle exerts on the other?

(b) Is the force attractive or repulsive?

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Answer:

i think its true

Block y will experience a stronger pull from gravity and fall more quickly than block x since it has more mass than block x is 29.4 md

To complete this task, we will apply Newton's second law. Assume that a block with mass m is moving up.

T-W₁ = m a

W₃ - T = M a

w₃ - w₁ = (m + M) a

g = a = (3m - m) / (3m + m)

a = 2/4 g

a = ½ g

The blocks move at a pace of

v² = v₀² + 2 ½ g x

v = √ g x

b) As work is a scalar, it adds to other quantities.

luminous blocks

W1 = W d = mg

d = -a 3 m hefty block

W2 = 3m g d = W d

the entire project is

W = W₁ + W₂

W = 2 m g d

c) When all external pressures are applied to the centre of mass, they relate to it being

a = ½ g

T = 2m1m2g/(m2 + m1)

= 2x mx3x3mg/ 4m

= 14.7 m

Work done in moving by distance by tension on both masses d

= 2 x 14.7 m x d ( 2 x force x displacement ) ( 2 x force x displacement )

= 29.4 md .

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Answer:

1950cm

Explanation:

You should multiply 1.95 cm by 1000. This will result in the answer.

Tension force? There ay be more than one, but that is all I can currently think of.

Conservation of momentum:

m1*v1+ m2*v2 = (m1+m2) v

mass 1 = m1= 1.95 kg

mass 2 = m2= 0.64 kg

initial velocity 1 = v1= 29 m/s

initial velocity 2 = v2= 7.5 m/s

v= final speed

Replacing:

(1.95*29)+(0.64*7.5) = (1.95+0.64)v

Solve for v

56.55+ 4.8 = 2.59 v

61.35=2.59v

61.35/2.59=v

v= 23.687 m/s