The minimum initial speed that the car must have in order to remain in contact with the circular track at all times is 1.98 m/s.
To calculate the minimum initial speed that the car must have to remain in contact with the circular track at all times, we need to consider the forces acting on the car. At the top of the loop, the car is not applying a force to the track, so the only force acting on the car is the force of gravity. The force of gravity is what provides the centripetal force that keeps the car moving in a circle.
The centripetal force can be calculated using the formula Fc = mv^2 / r, where Fc is the centripetal force, m is the mass of the car, v is the speed of the car, and r is the radius of the loop. In this case, we can assume that the mass of the car is constant and neglect it in our calculations.
At the top of the loop, the centripetal force provided by gravity is equal to the force of gravity itself, which can be calculated using the formula Fg = mg, where m is the mass of the car and g is the acceleration due to gravity. Therefore, we can equate these two forces to get mv^2 / r = mg.
Solving for v, we get v = sqrt(gr), where sqrt is the square root function. Plugging in the given values, we get v = sqrt(9.8 m/s^2 * 0.4 m) = 1.98 m/s.
Therefore, the minimum initial speed that the car must have in order to remain in contact with the circular track at all times is 1.98 m/s.
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What does an increase in the temperature of air indicate? A) The air has less thermal energy. B) The air has more thermal energy. C) The air particles have slowed down. D) The air particles have sped up.
Answer:
B)The air has more thermal energy
Answer:
its B
Explanation:
THATS THE ANSWER TRUST ME
When 120 V is applied across a 20 m long wire, the magnitude of the current density was found to be 2 * 10 ^ 8 * A / (m ^ 2) . The resistivity of this wire is
Answer:
\(\rho=3\times 10^{-8}\ \Omega-m\)
Explanation:
Given that,
Voltage, V = 120 V
The length of the wire, l = 20 m
The current density of the wire, \(\dfrac{I}{A}=2\times 10^8\ A/m^2\)
We need to find the resistivity of this wire. We know that,
\(R=\rho \dfrac{l}{A}\)
Where
\(\rho\) is the resistivity of wire
Also, \(R=\dfrac{V}{I}\)
So,
\(\dfrac{V}{I}=\rho \dfrac{l}{A}\\\\\rho=\dfrac{V}{l\dfrac{I}{A}}\)
Put all the values,
\(\rho=\dfrac{120}{20\times 2\times 10^8}\\\\=3\times 10^{-8}\ \Omega-m\)
So, the resistivity of this wire is equal to \(3\times 10^{-8}\ \Omega-m\).
When distances were carefully measured from the Earth to globular clusters above and below the Milky Way plane (where our view of them is not obscured by interstellar dust and gas), their distribution was found to be
A) spherically symmetric about a point in the constellation Sagittarius and concentrated in that direction.
B) in a relatively flat disk almost perpendicular to the plane of the Galaxy, with a relatively higher density of clusters toward its center.
C) concentrated in the plane of the Milky Way and clustered around the Sun's position, indicating that the Sun is close to the Galaxy's center.
D) uniformly distributed throughout space, with no concentration in any area of the Milky Way.
Answer:
A) Spherically symmetric about a point in the constellation Sagittarius and concentrated in that direction
Explanation:
The globular clusters are present mainly in the direction of Sagittarius with the center of the system of globular cluster being measured as a spherical cluster cloud such that the center of the Milky Way can be taken as being in the Sagittarius constellation
The density of water is 1g/cm³ . If an object with a mass of 100g has a weight of 1 N on Earth, calculate the volume of water displaced by the object
If an object with a mass of 100g has a weight of 1 N on Earth, the volume of water displaced by the object is 100 cm³.
To find the volume of water displaced by the object, take the formula:
Volume = Mass ÷ Density
According to question:
Mass of the object = 100g
Density of water = 1g/cm³
Change the mass to kilograms:
Mass = 100g ÷ 1000 = 0.1kg
By using the formula, it is possible to find the volume of water displaced:
Volume = 0.1kg / 1g/cm³
= 0.1kg / 1g/cm³ × 1000g/1kg × 1cm³/1g
= 0.1 × 1000 cm³
= 100 cm³
Thus, the volume of water displaced by the object is 100 cm³.
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Please someone answer this quickly!! I'll give 20 points for it, I just need the answers :)
The potential energy of the person mass 95 Kg sitting on top of a slid 3 m high is 2795.85 J
How do i determine the potential energy of the person?The following data were obtained from the question:
Mass of person (m) = 95 KgHeight of slid (h) = 3 mAcceleration due to gravity (g) = 9.81 m/s² Potential energy of person (PE) = ?The potential energy of the person can be obtained as follow:
PE = mgh
Inputting the given parameters, we have:
= 95 × 9.81 × 3
= 2795.85 J
Thus, the potential energy of the person is 2795.85 J
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Starting from rest and moving in a straight line, a runner achieves a velocity of 14 m/s in 10 seconds. what is the average acceleration of the runner?
The average acceleration of the runner will be 1.4 m/\(s^{2}\)
An object is said to be accelerated if there is a change in its velocity. The change in the velocity of an object could be an increase or decrease in speed or a change in the direction of motion.
Acceleration is a vector quantity as it has both magnitude and direction. It is also the second derivative of position with respect to time or it is the first derivative of velocity with respect to time.
Average acceleration refers to the rate at which the velocity changes. We divide the change in velocity by an elapsed time to find out the average acceleration of anything.
given
final speed = 14 m/s
initial speed = 0
time taken = 10 seconds
Average acceleration = change in speed / change in time
= final - initial / time
= 14 - 0 / 10 = 1.4 m/\(s^{2}\)
The average acceleration of the runner will be 1.4 m/\(s^{2}\)
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What quantity is the sum of the kinetic energy and all forms of potential
energy in a system?
A cord is wrapped around the rim of a solid uniform wheel 0.280 m in radius and of mass 9.60 kg. a steady horizontal pull of 50.0 n to the right is exerted on the cord, pulling it off tangentially from the wheel. the wheel is mounted on frictionless bearings on a horizontal axle through its center
part a) compute the angular acceleration of the wheel
part b) compute the acceleration of the part of the cord that has already been pulled off the wheel
part c) find the magnitude of the force that the axle exerts on the wheel
part d) find the direction of the force that the axle exerts on the wheel
part e) which of the answers in parts a, b, c, and d would change if the pull were upward instead of horizontal?
The answers are:
a. 31.14 rad/s²
b. 8.72 m/s²
c. 83.73 N
d. 113.96°
e. C and D
The angular acceleration of the wheel and the translational acceleration of the cord depends on the mass and shape of the wheel and the applied.
Given;
Radius of the wheel, r = 0.280 m
Mass of the wheel, m = 9.60 kg
Horizontal pull force, F = 50.0 N
Direction of pull = To the right
Relating to the main wheel axle = Frictionless
Requires:
a. The angular acceleration of the wheel
Moment of inertia of the wheel, I = 1/2(m)(r)²
Therefore;
I = 1/2 X (9.60 kg) X (0.280)² = 0.37632 kgm²
The torque applied, τ = F·r
τ = I·α
Therefore;
F·r = I·α
Which gives;
α = (F X r)/I = (50.0N X 0.280m)/ 0.37632 kgm² = 37.202 rad/s²
The angular acceleration, α ≈ 37.202 rad/s²
b. To compute the acceleration of the part of the cord that has already been pulled off the wheel.
The section of the cord that was pulled out is moving to the right.
Translational acceleration, a = Angular acceleration, α × Radius, r
Therefore;
a ≈ 37.202 rad/s² × 0.280 m ≈ 10.416 m/s²
The acceleration of the part of the cord pulled out, a ≈ 10.416 m/s²
c. To find the magnitude of the force exerted by the axle on the wheel.
Solution:
There are two parts to the force the axle applies to the wheel;Horizontal component, Rₓ, and vertical component,
When the forces are balanced, we have;
∑Fₓ = The horizontal component, Rₓ + The pulling force applied, F = 0
Therefore;
Rₓ = -F = -50.0 N
∑fy = The weight of the wheel, W + The normal reaction, = 0
Therefore;
Ry= -W = -m·g ≈ -9.60 kg × (-1)× (9.81 m/s²) = 94.176 m/s²
The magnitude of the fore from the axle, R, is given as follows;
R = \(\sqrt{R^{2}_{x} + {R^{2}_{y}\) = \(\sqrt{(-50.0 N})^{2} + \sqrt {(94.176N)^{2}\) = 106.626 N
The magnitude of the force exerted by the axle, R ≈ 106.626 N
d. The direction of the force of the axle on the wheel.
Let θ Let be the direction of the fore in relation to the x-horizontal axis's axis.
we have;
tan θ = Ry/Rx = (94.176 m/s²)/(-50.0 N)
Which gives;
θ = arctan ((94.176 m/s²)/(-50.0 N)) = -61.879°
The direction of the force of the axle is, θ ≈-61.879° which is equivalent to 61.87° relative to the negative x-axis and 118.3° relative to the positive x-axis.
e. If the pull where upward instead of horizontal, the changes are;
Rx = 0,
Ry = W-F
tan θ = Ry/Rx
The magnitude and direction of the force, R will change'
Therefore;
The responses that will change are C and D.
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this is life science
What occurs when light bends while passing from one medium to another?
Answer:So the answer is B
Explanation: When the light rays either bend or change their direction while passing from one medium to another it is called refraction of light. The refraction of light takes place when light travels from air into glass, from glass into air, from air into water or from water into air.
The materials that made up the solar nebula can be categorized into these four general types. Rank these materials from left to right based on the temperature at which each would condense into a solid, from highest to lowest. Note: For a substance that does not condense at all, rank it as very low temperature.
From highest to lowest condensation temperature, the four general types of materials that made up the solar nebula are refractory metals and silicates, volatile metals and ices, water, and hydrogen and helium.
Refractory metals and silicates, such as iron, nickel, and silicon, have the highest condensation temperature and would solidify first in the cooling solar nebula. Volatile metals and ices, like zinc and carbon dioxide, have a lower condensation temperature and would condense next. Water has a lower condensation temperature and would come after volatile metals and ices, while hydrogen and helium have the lowest condensation temperature and would not condense until very low temperatures were reached. These materials formed the building blocks for the planets in the solar system.
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How do synthetic fibers differ from natural fibers when viewed under a microscope.
The difference between the natural fibers and synthetic fibers is like synthetic fibers are produced using chemicals while, natural fibers are derived from plants and animals and are appreciated in the textile business for several factors.
What are natural fibers?The fibers that come from natural sources are known as natural fibers. The origins can range from zoological to botanical components. In other words, natural fibers are those that are obtained from plants and animals in their natural state. Wool, silk, hemp, cotton, and linen are a few examples of fabrics that naturally breathe.
What are synthetic fibers?Synthetic fibers are produced through a sequence of chemical processes, as their name suggests. These fibers are produced using a variety of chemical compounds rather than being derived from natural sources.
The creation of tiny molecules known as polymers is the process used to create synthetic, artificial, or man-made fibers. In most cases, raw materials and chemical compounds are used to extract polymers. Nylon, polyester, acrylic, and more are a few examples.
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a 120-v power supple connected to a 10-ohm resistor will produce ____ amps of current
Hello!
a 120-v power supple connected to a 10-ohm resistor will produce 3.464 amps of current
P = 120 V
r = 10Ω
P = r * I²
I² = P ÷ r
I² = 120 ÷ 10
I² = 12
I = √12
I ≈ 3.464
calculate the de broglie wavelength for a proton moving with a speed of 1.1 106 m/s.
To calculate the de Broglie wavelength (λ) for a proton moving with a speed of 1.1 x 10^6 m/s, we can use the de Broglie wavelength equation:
λ = h / p,
where λ is the de Broglie wavelength, h is the Planck's constant (approximately 6.626 x 10^(-34) J·s), and p is the momentum of the proton.
The momentum (p) of a proton can be calculated using the equation:
p = m * v,
where m is the mass of the proton and v is its velocity.
The mass of a proton (m) is approximately 1.67 x 10^(-27) kg.
Substituting the given values into the equations, we have:
p = (1.67 x 10^(-27) kg) * (1.1 x 10^6 m/s),
p ≈ 1.837 x 10^(-21) kg·m/s.
Now, we can calculate the de Broglie wavelength:
λ = (6.626 x 10^(-34) J·s) / (1.837 x 10^(-21) kg·m/s),
λ ≈ 3.602 x 10^(-13) meters.
Therefore, the de Broglie wavelength for a proton moving with a speed of 1.1 x 10^6 m/s is approximately 3.602 x 10^(-13) meters.
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A person performs 100 Joules of work
to push a stroller. How much energy
did this person spend?
The person spent 100 Joules of energy to perform 100 Joules of work in pushing the stroller.
What is law of conservation of energy?The law of conservation of energy states that, energy cannot be created or destroyed, only converted from one form to another.
Energy is a property of objects that enables them to do work. It can take many forms, such as kinetic energy (the energy of motion), potential energy (the energy of position), thermal energy (the energy associated with the temperature of an object), and many others.
Work, on the other hand, is the transfer of energy that occurs when a force is applied to an object and causes it to move a certain distance in the direction of the force.
In the case of the person pushing the stroller, they are applying a force to the stroller to move it forward. This force is causing the stroller to move a certain distance, which is the work being done.
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What is the answer for this question?
Answer:
6 watts
Explanation:
hours against watts
I'm not sure though
which forces are contact forces give one example of each
Answer:
A contact force is any force that requires contact to occur. Contact forces are ubiquitous and are responsible for most visible interactions between macroscopic collections of matter. Pushing a car up a hill or kicking a ball across a room are some of the everyday examples where contact forces are at work.
Q5. Two masses, each 5 kg, are attached
to the two ends of a spring of spring
constant 40 N/m. The masses are pulled
away from each other and the spring gets
stretched by a length 20 cm . Work done
by the spring on each mass, is
Answer:
1/2 KG2
Explanation:
The work done to stretch the spring on each mass with a spring constant of 40 N/m making a displacement of 20 cm or 0.2 m is 0.8 J.
What is spring constant?For an elastic material like a spring, the force applied on it to stretch or compress it to a length x is directly proportional to the length x.
Thus, F = -k x
Here, k is called the proportionality constant or spring constant.
Work done on a spring = 1/2 k x²
Given that, k = 40 N/m.
length x = 20 cm = 0.2 m.
Work done = 1/2 40 N/m × 0.2 m × 0.2 m
= 0.8 J.
Therefore, the work done on the spring is 0.8 J for each masses.
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do you think your real?
Answer: Yes I am alive.
TRUE
FALSE
Butter requires a great deal
of friction to slide on a hot
cookies tray?
Answer:
verdadero
Explanation:
Which graph accurately shows the relationship between kinetic energy and mass as mass increases
Answer:
c
Explanation:
energy doesnt affect to mass of a object
what is a joule in physics?
Explanation:
Joule is unit of work or energy in the International System of Units (SI)
\( \large \mathfrak {Formula}\)
work (joules) = force (newtons) x distance (meters)
\( \large\mathfrak{Invented \: by} \)
James Prescott Joule
The wave oscillation period is 0.5 minutes. Find the length of this wave if its speed is 54 km/h
To find the length of the wave if its speed is 54 km/h, we can use the formula:
Wavelength = Speed / Frequency
where the frequency of the wave is equal to the inverse of the oscillation period. The oscillation period of the wave is 0.5 minutes, so the frequency is 1 / (0.5 minutes) = 2 oscillations/minute.
We can now plug these values into the formula to find the wavelength:
Wavelength = 54 km/h / (2 oscillations/minute)
= 27 km
Therefore, the length of the wave is 27 km
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two windmills stand on a field 456 feet apart. a cow is in the field, 320 feet from one windmill and 210 feet from the other. what is the measure of theta?
The cosine rule is used to determine the values of unknown aides and angles in a triangle
The measure of θ is approximately 117.2°
Reason:
Given parameters are;
The distance between the two windmills, a = 456 feet
The distance between the cow and one of the windmills, b = 320 feet
Distance between the cow and the other windmills, c = 210 feet
Required, the angle θ between b, and c direction
Solution;
By cosine rule, we have;
a² = b² + c² - 2·b·c·cos(θ)
\(cos (\theta) = \dfrac{b^2 + c^2 - a^2}{2 \cdot b \cdot c }\)Which gives;
\(cos (\theta) = \dfrac{320^2 + 210^2 - 456^2}{2 \times 320 \times 210 }\)
\(\theta = arcos \left(\dfrac{320^2 + 210^2 - 456^2}{2 \times 320 \times 210 }\right) \approx 117.2 ^{\circ}\)The measure of θ ≈ 117.2°
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the distance from the center of a lens to the location where parallel rays converge or appear to converge is called the length.
T/F
False. The distance from the center of a lens to the location where parallel rays converge or appear to converge is called the focal length.
What is converge?Converge is a term used to describe the process of two or more entities coming together to form a single, unified whole. In technology, convergence refers to the integration of multiple communication and media technologies into a single device or service. This could include the combination of the Internet, television, radio, and telephone services. It may also refer to the merging of multiple mobile device platforms into a single, unified system. Convergence has become increasingly important and necessary as technology evolves, allowing people to access and use a wide variety of services on a single device.
Therefore, the correct option is False.
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You are asked to determine the identity of an unknown liquid and can measure only one physical property. You hear the liquid and record that the liquid turns into vapor at 100°C.
Which physical property does this demonstrate?
A. Melting point
B. Boiling point
C. Ability to conduct electricity
D. Meltability
The answer is The boiling Point as the transition from liquid to gas occurs at the boiling point.
The actuality that it changes from liquid to vapor indicates that you are working with the substance's boiling point.
The material is pure if its temperatures does not change when it turns phases. Since water turns liquid at 100°C in this situation, water is likely the culprit.
The temperature at which a specific liquid will boil is known as its boiling point. For instance, water reaches its boiling point at 1 atm, or 100 degrees Celsius. The temperature of the liquid, the pressure of the atmosphere, and the pressure of the vapor all affect its boiling point.
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if i were to drop an egg off a cliff, it begins to acceleration toward the ground, until it hits the ground and splattered. is momentum conserved in this situation?
Based on the principle of momentum, the momentum of the egg falling from a cliff and which shatters on hitting the ground is conserved.
What is momentum?Momentum is the product of the mass and the velocity of a compound.
Momentum, p = mass * velocity
Momentum is a vector quantity and its unit is kgm/s.
According to the principle of the conservation of momentum, in a system of colliding bodies, the momentum before the collision and the momentum after collision is conserved or equal.
Therefore, the momentum of the egg in the given scenario is conserved.
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A uniform disk of mass 2.01 kg has a radius of 0.100 m and spins with a frequency of 0.550 rev/s. What is its angular momentum? kg⋅m2/s
Given data
*The given mass of the uniform disk is m = 2.01 kg
*The given radius of the disk is r = 0.100 m
*The given frequency is
\(\omega=0.550\text{ rev/ =(0.550 rev/s\times}\frac{2\pi\text{ rad}}{1\text{ rev}})=3.45\text{ rad/s}\)The formula for the angular momentum is given as
\(\begin{gathered} L=I\omega \\ =\frac{1}{2}mr^2\times\omega \end{gathered}\)Substitute the known values in the above expression as
\(\begin{gathered} L=\frac{1}{2}(2.01)(0.100)^2(3.45) \\ =0.034\text{ kg.m\textasciicircum{}2/s} \end{gathered}\)convert 6000tons into kilograms
pls show workings
thank you
If you are using standard tons, then each ton is 907.18474 kg.
Multiply that and your answer is 5,443,108.44 kg.
If you are using metric tons, then multiply by 1,000.
6,000 * 1,000 = 6,000,000 kg
If a 5 n force is pushing upward on an object what force would need to be applied to create a net force of zero?
Answer:
the foce aplied to make the net force be 0 is 5n force pushing downward on the object becasue it will cancel it out
Explanation: