A car is moving at 60 mi/hr (88 ft/sec) on a straight road when the driver steps on the brake pedal and begins decelerating at a constant rate of 12 ft/sec^2 for 3 seconds. How far did the cargo during this 3-second interval?

Answer:

The closest distance the negative charge gets to the positive charge is given by the expression:

r = (k * q^2) / (m * v^2)

Explanation:

To find the closest distance the negative charge gets to the positive charge, we can analyze the motion of the negative charge under the influence of Coulomb's attraction.

Given that the negative charge is initially moving with a constant velocity and would miss the center of the fixed positive charge by a perpendicular distance of b, we can consider the perpendicular distance b as the impact parameter.

The motion of the negative charge can be treated as a projectile motion with the Coulomb force acting as a centripetal force. As the negative charge approaches the positive charge, the Coulomb force causes it to deviate from its straight-line path and approach the positive charge.

The closest distance the negative charge gets to the positive charge occurs when the centripetal force due to Coulomb's attraction is equal to the gravitational force acting on the negative charge.

Using the equation for Coulomb's force, we have:

k * (q^2) / r^2 = m * (v^2) / r

Simplifying and rearranging the equation, we get:

r = (k * q^2) / (m * v^2)

Note that this expression assumes the motion occurs in a straight line and the interaction is purely Coulombic. In reality, the motion of the negative charge may be more complex due to other forces and factors.

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Answer:

43.58kg

Explanation:

The equation F=ma will help here.

F=ma

523N=m(12m/s^2)

43.58kg=m

When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.

The correct answer to the given question is option C.

Potential energy is the energy stored within an object because of its position or configuration.

In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.

As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.

Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.

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The speed of the  Toyota Corolla would have  been 143.9 mph.

The acceleration of the F-15 can be calculated as follows:

Acceleration = Velocity Change / Time = (Take-off Speed) / Time

where;

Take-off Speed = √(2dg /t²)

Take-off Speed = √(2 x  (270 ft)  x 32.2 ft/s² / (2 s)²)

T  = √(17496) = 131.6 ft/s

Acceleration = Velocity Change / Time

= (131.6 ft/s) / (2 s) = 65.8 ft/s²

We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:

Final Velocity = Initial Velocity + Acceleration x Time

where;

Final Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s

Finally, we can convert the velocity from feet per second to miles per hour:

Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)

= 131.6 ft/s x  (1 hour/3600 s)  x (5280 ft/mile)

= 143.9 mph

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If you were standing on the far side of the moon, you would never be able to see the Earth.

The moon is tidally locked to Earth, which means that the same side of the moon always faces Earth. This is why we only ever see one side of the moon from Earth. Similarly, if you were standing on the far side of the moon, the Earth would always be blocked from view by the moon itself. So, no matter where you stood on the far side of the moon, you would never be able to see the Earth.

In addition, there are no other objects in space that would consistently block the view of the Earth from the far side of the moon. So, the only thing preventing you from seeing the Earth would be the moon itself.

Overall, standing on the far side of the moon would offer a unique and breathtaking view of the universe, but unfortunately, the Earth would not be visible from that vantage point.

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The block rises to a maximum height of 9.98 m above the point of release.

The maximum height above the point of release to which the block rises after it is released from rest can be calculated as follows:

Step 1: Determine the potential energy stored in the spring U = 1/2 kx² Where, U is the potential energy of the spring, k is the force constant, and x is the compression in meters U = 1/2 × 4975 N/m × (0.099 m)²U = 24.52 J

Step 2: The potential energy stored in the spring is converted into kinetic energy, which is then converted into gravitational potential energy.
Thus, U = K.E. = 1/2 mv²Where, K.E. is the kinetic energy of the block, m is the mass of the block, and v is the velocity of the block just after leaving the spring. Rearrange the above formula to calculate the velocity of the block as it leaves the spring: v = √(2U/m)v = √[2(24.52 J)/0.259 kg]v = 5.60 m/s

Step 3: At the maximum height above the point of release, the block has zero kinetic energy and a maximum potential energy. Thus, the gravitational potential energy of the block can be calculated as follows: mgh = U
Where, m is the mass of the block, g is the acceleration due to gravity, h is the maximum height above the point of release, and U is the potential energy stored in the spring. h = U/mg= U/(mg) = (24.52 J)/(0.259 kg × 9.81 m/s²)h = 9.98 m

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The final temperature when 50 ml of water at 80°C is added to 25 ml of water at 25°C is approximately 61.67°C.

To calculate the final temperature, we can use the principle of energy conservation, which states that the total heat lost by one substance is equal to the total heat gained by another substance in a closed system.

First, we can calculate the heat lost by the water at 80°C using the formula:

Q₁ = m₁ * c₁ * ΔT₁

where Q₁ is the heat lost, m₁ is the mass of the water at 80°C, c₁ is the specific heat capacity of water, and ΔT₁ is the change in temperature. Since we have 50 ml of water, we can assume its mass to be 50 grams (as the density of water is approximately 1 g/ml). The specific heat capacity of water is 4.18 J/g°C. Thus:

Q₁ = 50 g * 4.18 J/g°C * (80°C - T)

where T is the final temperature.

Similarly, we can calculate the heat gained by the water at 25°C:

Q₂ = m₂ * c₂ * ΔT₂

where Q₂ is the heat gained, m₂ is the mass of the water at 25°C (25 ml ≈ 25 g), c₂ is the specific heat capacity of water, and ΔT₂ is the change in temperature (T - 25°C).

Since energy is conserved, we can set Q₁ equal to Q₂:

50 g * 4.18 J/g°C * (80°C - T) = 25 g * 4.18 J/g°C * (T - 25°C)

Simplifying the equation, we can solve for T:

50 * (80 - T) = 25 * (T - 25)

4000 - 50T = 25T - 625

75T = 4625

T = 4625 / 75

T ≈ 61.67°C

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a) The thrust on the rocket is 360 Newtons.

b) The time until burnout is 120 seconds.

c) The speed of the rocket at burnout would depend on the velocity it had during the burning phase before the fuel was exhausted.

To find the thrust on the rocket, we can use the concept of momentum. The thrust force is equal to the rate of change of momentum.

Given:

Initial mass of the rocket (m₀) = 30,000 kg

Fuel mass percentage (fuel%) = 80%

Fuel burn rate (dm/dt) = 200 kg/s

Exhaust gas relative speed (v) = 1.8 (m/s)

First, we need to calculate the mass of the fuel:

Fuel mass (m_fuel) = fuel% * m₀ = 0.8 * 30,000 kg = 24,000 kg

The rate of change of momentum (dp/dt) can be calculated as:

dp/dt = (dm/dt) * v

Substituting the given values:

Thrust (F) = (dm/dt) * v = 200 kg/s * 1.8 m/s = 360 N

Therefore, the thrust on the rocket is 360 Newtons.

To find the time until burnout, we can use the concept of mass and fuel burn rate.

Given:

Fuel mass (m_fuel) = 24,000 kg

Fuel burn rate (dm/dt) = 200 kg/s

The time until burnout (t_burnout) can be calculated as:

t_burnout = m_fuel / (dm/dt)

Substituting the given values:

t_burnout = 24,000 kg / 200 kg/s = 120 seconds

Therefore, the time until burnout is 120 seconds.

To find the speed of the rocket at burnout assuming it moves straight upward near the surface of the Earth, we can use the concept of velocity and acceleration.

Given:

Initial mass of the rocket (m₀) = 30,000 kg

Fuel mass (m_fuel) = 24,000 kg

Acceleration due to gravity (g) ≈ 9.8 m/s²

The final mass at burnout (m_final) can be calculated as:

m_final = m₀ - m_fuel

The total force acting on the rocket at burnout is the weight due to gravity:

F_total = m_final * g

Using Newton's second law (F = ma), we can find the acceleration (a):

F_total = m_final * a

Substituting the values:

m_final * g = m_final * a

The acceleration due to gravity and the acceleration of the rocket cancel out, resulting in zero acceleration. Therefore, at burnout, the rocket's speed would be constant, and it would retain the speed it had when the fuel was exhausted.

Hence, the speed of the rocket at burnout would depend on the velocity it had during the burning phase before the fuel was exhausted.

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Answer:bight

Explanation:

The number of units of the fundamental electric charge possessed by a droplet can be determined by dividing the total charge of the droplet by the magnitude of the fundamental charge. Therefore, the droplet possesses 2 units of the fundamental electric charge.

The fundamental electric charge, denoted as e, is the charge of a single electron or proton and has a magnitude of approximately 1.602 x 10^-19 coulombs. To find the number of units of the fundamental electric charge possessed by a droplet, we need to divide the total charge of the droplet by the magnitude of the fundamental charge.

The total charge of the droplet can be determined by measuring the net charge it carries. If the droplet has a positive charge, the total charge will be positive, and if it has a negative charge, the total charge will be negative.

For example, if the droplet has a total charge of +3.204 x 10^-19 coulombs, we can calculate the number of units of the fundamental electric charge by dividing this value by the magnitude of the fundamental charge:

Number of units of fundamental charge = (3.204 x 10^-19 C) / (1.602 x 10^-19 C) = 2.

Therefore, the droplet possesses 2 units of the fundamental electric charge.

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The correct answer is: Berries and leaves are fully grown.

An adaptation is a trait that helps an organism survive in its environment. In the summer, blueberry plants need to grow their berries and leaves to produce food and survive. Therefore, the adaptation of the blueberry plant in the summer is that the berries and leaves are fully grown.

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The magnetic field generated by a current loop is given by the equation:

B = (μ0 * n * I * A) / (2 * R)

where μ0 is the permeability of free space (4π x 10^-7 T·m/A), n is the number of turns, I is the current, A is the area of the loop, and R is the distance from the center of the loop to the point where the magnetic field is measured.

In this case, we want to make a loop with a length of 1.30 m, so the circumference of the loop will be C = 2πr = 1.30 m, where r is the radius of the loop. Solving for r, we get:

r = C / (2π) = 1.30 m / (2π) = 0.2077 m

The area of the loop is given by A = πr^2, so:

A = π(0.2077 m)^2 = 0.1358 m^2

Now we can plug in the values given and solve for the number of turns:

0.700 T = (4π x 10^-7 T·m/A) * n * 1.20 A * 0.1358 m^2 / (2 * 0.2077 m)

Solving for n, we get:

n = (0.700 T * 2 * 0.2077 m) / [(4π x 10^-7 T·m/A) * 1.20 A * 0.1358 m^2]

n = 147.4 turns

Therefore, you need to make a current loop with 147 turns to generate a 0.700 mT magnetic field at the center of the loop using the entire 1.30 m long copper wire.

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Answer:

Chemical property

Explanation:

Science go brrrrrrrrr

The speed of a freely falling object increases by: 32.2 ft/s2 every second.

A freely falling object is an object that falls under the influence of gravity alone, disregarding air resistance or frictional forces. A freely falling object accelerates because of the force of gravity. The acceleration of a freely falling object is approximately 9.8 meters per second squared (m/s2) or 32.2 feet per second squared (ft/s2). This acceleration is referred to as acceleration due to gravity.

Acceleration is the rate of change of velocity with respect to time. The unit of acceleration is meters per second squared (m/s2) or feet per second squared (ft/s2). This unit means that the object's velocity increases by a certain number of meters or feet per second every second.

The acceleration due to gravity is a constant acceleration that all objects experience while falling due to gravity. This acceleration comes from the gravitational force exerted by the Earth on the object. It causes the object to accelerate toward the Earth at a constant rate.

Therefore, the speed of a freely falling object increases by approximately 9.8 m/s2 or 32.2 ft/s2 every second until it reaches its terminal velocity.

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Answer:

Explanation:

Answer:

The answer is C.19.8 m/s because it's their common velocity after the collision of the two cars.

Explanation:

Hello !

look at the attachment above ☝️ and if you have any questions you're welcome.

A controlled burn removes dead vegetation that might otherwise help a wildfire start and spread.

The term controlled burn refers to setting up an area in which the fire is controlled in order to avoid wild fires. These are deliberately set up in order to avoid the bush from burning down.

Let us recall that a wild fire is able to blaze across a large causing damage to a buildings as well as life and other properties in the way of the fire and could cause huge looses including loss of habitat.

Thus, the National Park Service sometimes creates controlled burns to mitigate wildfires because  a controlled burn removes dead vegetation that might otherwise help a wildfire start and spread.

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Answer: the area were the most pressure is at the deep sea trench (the deepest part)

Explanation: because the more on top of you is the more pressure.

Answer:

\(T=9.42Nm\)

Explanation:

From the question we are told that:

Radius \(r= 0.5 m\)

Current \(I= 3.0 A\)

Normal vector \(n=\frac{(2i - j +2k)}{3}\)

Magnetic field \(B= (2i-6j) T\)

Generally the equation for Area is mathematically given by

 \(A=\pi r^2\)

 \(A=3.1415 *0.5^2\)

 \(A=0.7853 m^2\)

Generally the equation for Torque is mathematically given by

 \(T=A(i'*B)\)

Where

 \(i'*B= \begin{bmatrix}2&-1&2\\2&-6&0\end{bmatrix}\)

 \(X\ component\ of\ i'*B= [(-1 * 0)-(2*-6)]\)

 \(X\ component\ of\ i'*B=12\)

Therefore

 \(T=0.7853*12\)

 \(T=9.42Nm\)

Answer:

-7.5

Explanation:

edge 2021

The given problem can be exemplified in the following diagram:

The weight of the bar is concentrated in its center of mass which is located in the middle of the longitude of the bar. We can add the total torques at the point where the pivot touches the bar and we get:

Here we have used momentum counter-clockwise as positive. Since the system is in equilibrium the sum of the torques must be equal to zero:

Now we solve the operations, we will use for the acceleration of gravity 9.8 meters per second squared:

Now we solve for the mass "M" first by subtracting 88.2Nm from both sides:

Now we divide both sides by -1.96:

Solving the operations we get:

Therefore, the mass of the bar is 45 kg.

Answer:    Review your data. ...

   Calculate an average for the different trials of your experiment, if appropriate.

   Make sure to clearly label all tables and graphs. ...

   Place your independent variable on the x-axis of your graph and the dependent variable on the y-axis.

Hope this helps!!

The energy from the potential energy of the car is converted into thermal energy (heat) due to the friction caused by the brakes, which slows down the car.

The kinetic energy of the car remains constant because the speed of the car is being maintained.

Energy is seen as a quantifiable property in physics that may be transferred from an item to carry out work. Thus, we might characterize energy as the capacity to engage in any kind of physical action.

As a result, the simplest way to describe energy is as the capacity for work.

The energy conversions in the problem is as described

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31.64 m/s with velocity fast is it moving 1.8 s after it was thrown vertically downwards at a speed of 14 m/s from the top of a tall building.

V= u + gt= 14 + 9.8×1.8 = 14 + 17.64 = 31.64 m/s

When a body is travelling in a straight line, its estimated "rate of change of displacement in relation to time" is referred to as its velocity.

Speed is a scalar number since it lacks a direction and the value it receives from the distance-to-time ratio simply indicates its magnitude. It doesn't provide any guidance information. Because it always has a direction, velocity is a vector. As a result, when the displacement to time ratio for linear velocity is determined, it provides both the direction and the magnitude.

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The nonconservative work done on the boy, A boy with a mass of 71.2 kg has caught a wave, which gives him an initial speed of 1.6 m/s. He then falls 1.64 m and finishes with a speed of 8.51 m/s. We'll utilize the energy conservation law to calculate the nonconservative work done on him.

The boy's initial kinetic energy is given by 1/2 m v₁² = 1/2 (71.2 kg) (1.6 m/s)² = 91.03 J. The potential energy he has before dropping through a height of 1.64 m is mgh = (71.2 kg) (9.8 m/s²) (1.64 m) = 1151.9 J.When he reaches the bottom, his kinetic energy is 1/2 m v₂² = 1/2 (71.2 kg) (8.51 m/s)² = 2656.36 J.

As a result, the energy conservation law provides us with the following expression:Initial energy + work done on the system = Final energy W_nc = Ef - Ei - W_cW_nc = 2656.36 J - 91.03 J - 1151.9 JW_nc = 1413.43 JTo obtain the answer in kJ, we will convert the value to kilojoules by dividing it by 1000.W_nc = 1413.43 J = 1.41 kJTherefore, 1.41 kJ of nonconservative work was done on the boy.

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Ratio of distances of image and object respectively = ratios of heights of image and objects respectively

This implies

(1.7/600) = (x/1) ........ ( X is largeness of letter on retina)

x= 0.002833333 cm

What is retina?

The retina is the innermost, light-sensitive layer of eye tissue in most vertebrates and some mollusks. The optics of the eye create a focused two-dimensional image of the visual world on the retina. The retina processes that image within the retina, sending nerve impulses along the optic nerve to the visual cortex to produce vision. The retina functions in many ways similar to the film and image sensors in cameras.

The neural retina consists of several layers of neurons connected by synapses and supported by an outer layer of pigment epithelial cells. The main light-sensitive cells in the retina are photoreceptor cells, of which there are two types: rods and cones. Rods work primarily in low light and provide monochromatic vision. Cones function in bright environments, use different opsins to perceive color, and are responsible for sharp vision used for tasks such as reading. A third type of photosensitive cell, the photosensitive ganglion cell, is important in entrainment of circadian rhythms and reflex responses such as the pupillary light reflex.

Therefore, x= 0.002833333 cm

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Answer:

3.94

Explanation:

divide total mass by the number of blocks since they are identical

Answer:

3.94

Explanation:

You want to find the mass of one block. Since we know there is 8 blocks with the same mass, you can divide the total mass by 8 since the mass is equally distributed within the 8 blocks

Answer:

5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps

Explanation:

Answer:

1) The maximum height reached is approximately 39.715 m

2) The time it takes the ball to reach the its highest point is approximately 2.85 s

Explanation:

1) The vertical velocity of the ball, u = 27.9 m/s

The acceleration due gravity, g = 9.8 m/s²

The kinematic equation that gives the height, h, reached by the ball is given as follows;

v² = u² - 2·g·h

Where;

v = The final velocity of the ball = 0 m/s at the maximum height

h = The height reached by the ball = \(h_{max}\) at maximum height

Therefore, by substitution of the known values, we have;

v² = u² - 2·g·h

0² = 27.9² - 2 × 9.8 × \(h_{max}\)

2 × 9.8 × \(h_{max}\) = 27.9²

\(h_{max}\) = 27.9²/(2×9.8) ≈ 39.715

The maximum height reached = \(h_{max}\) ≈ 39.715 m

2) From the kinematic equation of motion, v = u - g·t, we have the time, t, it takes the ball to reach the maximum height given as follows

At maximum height, the final velocity, v = 0 m/s, therefore, we have;

0 = 27.9 - 9.8 × t

9.8 × t = 27.9

t = 27.9/9.8 ≈ 2.85

The time it takes the ball to reach the maximum height = t ≈ 2.85 seconds.