A car moves around a wide turn going 45 mi/hr the whole time. The car has a constant _____.

A.) Speed
B.) Velocity
C.) Direction
D.) Acceleration

Answer:Answer is 66.66666666666667

Explanation:all you have to do is divide 200/3

Answer:

66 seconds

Explanation:

time=distance/speed

200/3=66.6

Answer:

68

Explanation:

now it

Answer:

The velocity of a ball will be "-70.13 m/s".

Explanation:

The given values are:

u = 70 m

t = 0.0 s

g = a = -9.8 m/s²

s = -1 m

v = ?

As we know,

The equation of motion will be:

⇒  \(v^2-u^2=2as\)

On substituting the estimated values, we get

⇒  \(v^2-(70)^2=2\times (-9.8)\times (-1)\)

⇒  \(v^2-4900=19.6\)

⇒  \(v^2=19.6+4900\)

⇒  \(v^2=4919.6\)

⇒  \(v=\sqrt{4919.6}\)

⇒  \(v=70.13 \ m/s\)

In downward direction, it will be:

⇒  \(v=-70.13 \ m/s\)

Answer:

Gravity

Explanation:

Gravity is what causes stars to form. During accretion, gravity pulls matter into a core, which can be a star, planet or black hole.

a. The Sackur-Tetrode equation has the entropy to be  S = NkB [2 + 3[2 - ln(pX³h)]

b.  3S = NkB ln(V / Nλ³  shows the entropy of a gas with distinguishable particles

c.  The quantity 3S = NkB ln(V / Nλ³) is not an extensive quantity because it does not scale linearly with the size of the system.

a)

Entropy in the Sackur-Tetrode equation is denoted by S = NkB [2 + 3[2 - ln(pX3h)],

N = particle count,

kB = Boltzmann constant,

p =  gas's number density,

X = thermal wavelength,

h = Planck's factor.

When we consider two systems, each with a different number of particles and volume, the entropy of the combined system is equal to the sum of the entropies of the individual systems.

b) The entropy is given by 3S = NkB ln(V / Nλ³),

where V =  volume,

N=  total number of particles,

λ=  thermal wavelength.

The Helmholtz free energy (F) is defined as

F_ = U - TS.

IF we  differentiate the Helmholtz free energy with respect to temperature (T), we can obtain the entropy expression 3S = NkB ln(V / Nλ³).

c)  

Because it does not increase linearly with system size, the amount 3S = NkB ln(V / N3) is not a large quantity. In a large quantity, doubling the system's size would also double the quantity's value.

In this our scenario, doubling the system size would not result in a doubling of the entropy. As a result, it is not regarded as a large number.

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Answer:=mgh

Explanation:

The strength of the magnetic field in the center of the system, which is equally spaced from the wires. . B = μ0I/(2πr) for the magnetic field's strength.

And this is where the second important characteristic comes into play. The equivalent surface current density I = dI/ds =B = μ0I/(2πr), which is proportional to the magnetic field Br of the permanent magnet material, may be used to compute the magnetic field of permanent magnets. In this case, the permeability of open space is μ = 4 107 A/Tm.

The magnetic field lines encircle a long, straight wire when it is carrying a current I. You may find the magnetic field direction by circling the wire with your fingers while pointing your right thumb in the direction of the current.

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Answer:

A) Variety of Living Things

Explanation:

Biodiversity is defined as the variety of life in the world or in a particular habitat or ecosystem.

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Answer:

Rotation

Explanation:

i did the test Gl.

The cycle of day and night is a result of Earth’s spinning on its axis, which is Earth’s Rotation.This is further explained below.

Generally, Rotation can be defined as the ability of a body to turn about its axis or its centre.

In conclusion,The full rotation of the earth takes a month

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I think all Rhino species are being lost plz let me know if I am wrong thank u bro I am glad to help any time.

Answer:

Radioactive Decay

Explanation:

Answer:

15.66(s)

Explanation:

3.62+12.3

Answer:

120

Explanation:

KE = (mv^2)/2

= ((0.15)(40)^2)/2

= ((0.15)(1600))/2

= 240/2

No, a 10msun black hole is not larger than a 1msun black hole. The size of a black hole is determined by its mass, and a 10msun black hole is simply ten times more massive than a 1msun black hole.

However, both black holes have a singularity (the point of infinite density) that is infinitely small and surrounded by an event horizon (the point of no return) that expands proportionally to the mass of the black hole. Therefore, both black holes have the same "size" in terms of their event horizon.
1. The term "Msun" represents a unit of mass, specifically the mass of the Sun. So, a 1Msun black hole has the mass of one Sun, while a 10Msun black hole has the mass of 10 Suns.
2. A black hole's size is typically characterized by its event horizon, which is the boundary beyond which nothing, not even light, can escape its gravitational pull.
3. The size of a black hole's event horizon (also known as the Schwarzschild radius) is directly proportional to its mass. Therefore, a black hole with a higher mass will have a larger event horizon.

In summary, a 10Msun black hole has a larger event horizon and is thus larger than a 1Msun black hole.

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Answer:

The force exerted between the two charges is 0.0001248N

Explanation:

we will be using Columb's law to solve this problem.

Columb's law explains that the Force between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Mathematically,

\(F = K\frac{Q_1 \times Q_2}{r^2}\)

WHere K = constant of proportionality = \(8.9875 \times 10^9 N m^2/c^2\)

\(F = 8.9875 \times 10^9 \times\frac{2.5 \times10^{-6} \times 4.5 \times 10^{-7}}{9^2}= 0.0001248N\)

The force exerted between the two charges is 0.0001248N

The movement of charges from one plate to the other in a capacitor is a fundamental process that underlies many electronic devices and applications.

When a capacitor is connected to a circuit, charges begin to flow from one plate to the other until both plates reach the same potential and the capacitor becomes fully charged.

This process involves the movement of electrons, which are negatively charged particles, from one plate to the other.

Initially, the capacitor is uncharged, and the plates have an equal number of positive and negative charges.

When a voltage is applied to the capacitor, electrons begin to flow from the negative plate to the positive plate, creating an electric field between the two plates. This electric field stores energy in the capacitor, which can be released later when the capacitor is discharged.

If the voltage across the capacitor is removed, the capacitor will retain its charge and will discharge slowly over time as the electrons flow back from the negative plate to the positive plate.

This discharge process can be used in various applications, such as in flash photography, where a capacitor is charged rapidly and then discharged quickly to produce a bright flash of light.

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Assuming a flat ground, and  football thrown or dropped from the same height, the horizontally-thrown ball will hit the ground with the same vertical velocity as the dropped ball, but it will have most of its initial horizontal velocity, too. A simple vector addition, guarantees that that the horizontally-thrown ball will have a larger total velocity than the dropped ball.

What is Velocity.

Velocity is the directional velocity of a moving object as an indicator of the rate of change of position observed from a particular frame of reference and measured at a particular time standard.

Therefore, A simple vector addition, guarantees that that the horizontally-thrown ball will have a larger total velocity than the dropped ball.

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The magnetic force will act on the charge carrier in a direction perpendicular to both the magnetic field direction and the velocity direction of the charge carrier.

In this scenario, the magnetic field points along the y-axis in a positive direction, and the charge carrier moves along the z-axis in a negative direction. Since the velocity of the charge carrier is in the same direction as the z-axis, the direction of the magnetic force acting on the charge carrier will be perpendicular to both the y-axis and the z-axis.

To determine the direction of the magnetic force, we can use the right-hand rule. If we point the thumb of our right hand in the direction of the velocity of the charge carrier (i.e., along the negative z-axis), and the fingers in the direction of the magnetic field (i.e., along the positive y-axis), then the direction of the magnetic force will be perpendicular to both and will be directed towards the negative x-axis.

Therefore, the magnetic force acting on the charge carrier will be directed towards the negative x-axis.

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Answer:

An image of the cosmic microwave background radiation, taken by the European Space Agency (ESA)'s Planck satellite in 2013, shows the small variations across the sky (Image credit: ESA/Planck Collaboration) The cosmic microwave background (CMB) is thought to be leftover radiation from the Big Bang, or the time when the universe began

Explanation:

The kinetic energy of the circular disc in initial state is,

\(K^{1r} = \frac{1}{2}I^{t}ω^{ \frac{2}{i} } \)

The initial kinetic energy of the other disc dropped on the first disc is,

\(K^{2r} = \frac{1}{2}I^{b}(0)^{2}\)

\( = > K^{2r} = 0J\)

As both the disc in the final state are moving with the same angular velocity, thus, the net kinetic energy in the final state is,

\(E^{f} = \frac{1}{2}(I^{t} + I^{b})ω^{ \frac{2}{f} }\)

The net kinetic energy in the initial state is,

\(E^{i} = K^{1r} + K^{2r}\)

\( = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} } + 0\)

\( = > E^{i} = \frac{1}{2} I^{t}ω^{ \frac{2}{i} }\)

Thus, the change in the kinetic energy during the change of state is,

\(dE = E^{f} - E^{i}\)

\( = > dE = \frac{1}{2} (I^{t} + I^{b})ω^{ \frac{2}{f} } - \frac{1}{2}I^{t}ω^{ \frac{2}{i} } \)

\( = > dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } \)

This change in value of energy is the energy lost initially rotating the disk to friction.

Hence, the energy lost in the given case is \(dE = \frac{1}{2} I^{t}(ω^{ \frac{2}{f} } - ω^{ \frac{2}{i} }) + \frac{1}{2}I^{b}ω^{ \frac{2}{f} } \)

The energy lost initially by the rotating disk to friction is equal to \(\frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2\)

Given the following data:

At the initial state, the kinetic energy of the circular disc is given by this formula:

\(K.E = \frac{1}{2} I_t\omega_i^2\)

For the second disc, the initial kinetic energy is given by this formula:

\(K.E_2 = \frac{1}{2} I_b\omega_f^{2 }\\\\K.E_2 = \frac{1}{2} I_b(0)^{2 }\\\\K.E_2 = 0\)

At the final state, the discs would move with the same angular velocity and the net kinetic energy is given by this formula:

\(E_f = \frac{1}{2} (I_t + I_b)\omega_f^2\)

For the energy lost:

Also, the change in the kinetic energy is given by this formula:

\(\Delta E = E^f - E^i\\\\\Delta E = \frac{1}{2} (I_t + I_b)\omega_f^2 - \frac{1}{2} I_t\omega_i^2\\\\\Delta E = \frac{1}{2}I_t (\omega_f^2 - \omega_i^2)+\frac{1}{2} I_b\omega_f^2\)

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(a) The rate of change of the potential at P(5,2,6) in the direction of the vector v=i+j−k is (32/√3) in MPa, (b) V changes most rapidly at P in the direction of the gradient vector (∇V) = (24, -2, 10), (c) The maximum rate of change at P is 26.08 in MPa.

(a) Find the rate of change of the potential at point P(5, 2, 6) in the direction of the vector v = i + j - k, we can calculate the dot product between the gradient of the potential and the unit vector in the direction of v.

The gradient of the potential V(x, y, z) is given by ∇V = (∂V/∂x)i + (∂V/∂y)j + (∂V/∂z)k.

Taking partial derivatives of V with respect to x, y, and z:

∂V/∂x = 4x - 4y + yz

∂V/∂y = -4x + 3z

∂V/∂z = xy

Evaluating the partial derivatives at P(5, 2, 6):

∂V/∂x = 4(5) - 4(2) + (2)(6) = 24

∂V/∂y = -4(5) + 3(6) = -2

∂V/∂z = (5)(2) = 10

Now, we can calculate the rate of change at P in the direction of v:

Rate of change = ∇V · (v/|v|)

|v| = √(1^2 + 1^2 + (-1)^2) = √3

Rate of change = (24, -2, 10) · (1/√3, 1/√3, -1/√3)

Rate of change = (24/√3) + (-2/√3) + (10/√3) = (32/√3)

Therefore, the rate of change of the potential at P in the direction of the vector v = i + j - k is (32/√3).

(b) Determine the direction of the maximum change of V at P, we need to find the direction of the gradient ∇V at that point. The gradient vector points in the direction of the steepest increase in the potential.

∇V = (24, -2, 10)

Thus, the direction of maximum change of V at P is (24, -2, 10).

(c) The maximum rate of change at P corresponds to the magnitude of the gradient vector ∇V.

Maximum rate of change = |∇V| = √(24^2 + (-2)^2 + 10^2) = √(576 + 4 + 100) = √680 ≈ 26.08.

The maximum rate of change at P is approximately 26.08.

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Answer:

Swimmer B had the greatest displacement:)

Explanation:

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Answer:

1.) F = 5.3×10^-3 N

2.) Positive y - direction

Explanation:

The parameters given are:

Charge q = 0.0005C

Velocity V = 2.5010 m/s

Magnetic field B = 4.2 T

Magnetic force F = BVqsinØ

F = BVq

since Ø = 90 degree

Substitute all the parameters into the formula

F = 4.2 × 2.5010 × 0.0005

Therefore, the magnetic force on a particle is F = 5.3 × 10^-3 N

2.) According to Fleming's left hand rule, the direction of the magnetic force will be perpendicular to the magnetic field which moving upward of the screen.

Answer:

it’s f=0.0005 x 2.5 x 10^5 x 4.20

F= 525 N

+ y direction (up)

Explanation:

got it right

Answer:

Explanation:

-The hypocenter is the point within the earth where an earthquake rupture starts. The epicenter is the point directly above it at the surface of the Earth. Also commonly termed the focus.

-The location below the earth's surface where the earthquake starts is called the hypocenter, and the location directly above it on the surface of the earth is called the epicenter. Sometimes an earthquake has foreshocks.

Answer:

kelvin is the base unit or SI unit for temperature.

Explanation:

i hope this will help you

Answer:

Temperature.

Explanation:

Answer:

all the resistors are connected in series.

Answer:

the magnitude of the electric field  = 27.1058 V/m

≈ 27 V/m

Explanation:

given

R(radius enclosed) = 12 cm = 0.12 m

ρ(charge density) = 5.0 nC/m³ = 5.0 × 10⁻⁹C/m³

r(radius from the axis) = 15 cm = 0.15 m

using Gauss law, which states that the electric flux through any closed surface is directly proportional to the total electric charge enclosed by this surface.

attached is the calculation of the question, using Gauss law of electrostatics

Answer:

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