a cell of EMF 1.5 volt is connected in series with a resistor of Resistance 3 ohms a high resistance voltmeter connected across the cell registers 0.9 volt calculate the internal resistance of the cell ​

Answer:

The difference in airspeed over the top and bottom of an airplane wing results in a difference in air pressure, which generates lift. The Bernoulli's equation relates the pressure of a fluid (including air) to its velocity and the height of the fluid:

P + 1/2 * rho * v^2 + rho * g * h = constant

where P is the pressure of the fluid, rho is the density of the fluid, v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height of the fluid.

Assuming that the density of air is constant and the height of the wing is negligible compared to the other terms in the equation, we can simplify the equation to:

P + 1/2 * rho * v^2 = constant

The constant in the equation is the same at all points along the wing, since the air is a continuous fluid.

The pressure difference between the top and bottom of the wing can be found by calculating the pressure at the top and bottom of the wing using the simplified Bernoulli's equation, and then taking the difference between the two pressures.

Let P1 be the pressure at the bottom of the wing, where the airspeed is 130 m/s, and P2 be the pressure at the top of the wing, where the airspeed is 170 m/s. Then we have:

P1 + 1/2 * rho * (130 m/s)^2 = P2 + 1/2 * rho * (170 m/s)^2

Simplifying and rearranging, we get:

P1 - P2 = 1/2 * rho * (170 m/s)^2 - 1/2 * rho * (130 m/s)^2

Plugging in the density of air (rho = 1.225 kg/m^3), we get:

P1 - P2 = 1/2 * 1.225 kg/m^3 * (170 m/s)^2 - 1/2 * 1.225 kg/m^3 * (130 m/s)^2

Simplifying and calculating, we get:

P1 - P2 = 377.72 Pa

Therefore, the difference in pressure between the top and bottom of the wing is approximately 377.72 Pa.

Answer:

Electrical energy is caused by moving electric charges called electrons. The faster the charges move, the more electrical energy they carry. As the charges that cause the energy are moving, electrical energy is a form of kinetic energy. Lightning, batteries and even electric eels are examples of electrical energy in action!

Explanation:

The vertical component of the velocity after the given interval of time will be:

B: -9.8 m/s

D: -19.6 m/s

F: -29.4 m/s

H: -39.2 m/s

A projectile can be described as any object upon which the only force is gravity. The projectile travels with a parabolic trajectory because of the influence of gravity. No horizontal forces are acting upon projectiles so there is no horizontal acceleration.

The horizontal velocity of a projectile is constant and the vertical acceleration is caused by gravity. The vertical component of the velocity of a projectile changes by 9.8 m/s each second while the horizontal motion of a projectile is independent of its vertical motion.

Given, the initial horizontal velocity, vₓ = 18 m/s

The initial vertical velocity, Vy = 0 m/s

The time interval = 1 sec

The vertical component of the velocity is calculated as;

\(V_y = V_{0y} -gt\)

\(V_y = 0- (9.8) (1)\\V_y = -9.8 m/s\)

The vertical component when t = 2 sec and horizontal velocity, Vx = 18 m/s

\(V_y = 0- (9.8) (2)\\V_y = -19.6 m/s\)

The vertical component of velocity when t = 3sec:

\(V_y = 0- (9.8) (3)\\V_y = -29.4 m/s\)

The vertical component of velocity when t = 4sec:

\(V_y = 0- (9.8) (4)\\V_y = -39.2 m/s\)

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Here is your soulution Kauruchan

Hence, The two spheres each of mass 10 mg are suspended by a point of threads 0.5 m long .

They are equally charged and repel each other to a distance of 0.20 m . Then the charge of the sphere is

\( (\frac{a}{21} ) \times {10}^{ - 8} \: c \)

The value of a ~ 20C

~

The density of matter in a lead nucleus is 2.82 x 10¹⁷ kg/m³.

Lead nucleus is composed of protons and neutrons. The density of a nucleus is the mass of a nucleus divided by the volume occupied by the nucleus. The volume of a nucleus can be determined using the formula

(4/3)πr³,

where r is the radius of the nucleus. As the diameter of a lead nucleus is given as 14.2 fm, the radius of a nucleus can be calculated as follows:

radius = diameter/2

= 14.2 fm/2

= 7.1 fm

Hence, the volume of a lead nucleus can be calculated as:

(4/3)πr³ = (4/3)π(7.1 fm)³

= 1.57 x 10⁻⁴ fm³

As the mass of a lead nucleus is 3.15 x 10⁻²⁵ kg, the density of matter in a lead nucleus can be calculated as follows:

Density = Mass/Volume

= 3.15 x 10⁻²⁵ kg/1.57 x 10⁻⁴ fm³

= 2.82 x 10¹⁷ kg/m³

The density of matter in a lead nucleus is 2.82 x 10¹⁷ kg/m³.

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Answer:

The answer is "26.208 km"

Explanation:

Given value:

\(\to S= 2.6 \ \frac{m}{s}\\\\\to t= 2.8 \ hours\)

Formula:

\(d= st\\\\d= 2.6 \times 2.8 \times \frac{60 \times 60}{1000}\\\\d= 26.208\ km\)

When a beam of light passes through a pinhole, the light is diffracted. Diffraction occurs when a wave is scattered, or spread out, as it passes an obstacle or an aperture.

When a laser beam is passed through a pinhole, the beam is diffracted and the light is spread out, resulting in a larger beam. This is because the pinhole acts as a diffraction grating and the light waves are scattered in multiple directions, forming an expanded beam.

This is why the investigator found that the beam was spread out, making matters worse.

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Answer:

I think its B but if not then its D

Explanation:

Answer:

b

Explanation:

The minimum gap between the automobiles is 16.9 feet, according to the supplied statement, in order to prevent a collision.

The size or extent of the displacement between two points is referred to as distance. Keep in mind that perhaps the difference between two and indeed the distance travelled between them are not the same. The length of the entire journey taken to go from one point to another is the distance travelled.

For B;

\(\begin{aligned}(\rightarrow) \quad v & =v_0+a_c t \\v_B & =60-12 t \\(\rightrightarrows) & s=s_0+v_0 t+\frac{1}{2} a_c t^2 \\s_B & =d+60 t-\frac{1}{2}(12) t^2\end{aligned}\)

For A;

\(\begin{aligned}& (\stackrel{\rightarrow}{\rightarrow}) \quad v=v_0+a_c t \\& v_A=60-15(t-0.75), \quad[t > 0.75] \\& (\text { 土 }) \quad s=s_0+v_0 t+\frac{1}{2} a_c t^2 \\& \qquad s_A=60(0.75)+60(t-0.75)-\frac{1}{2}(15)(t-0.75)^2, \quad[t > 0.74]\end{aligned}\)

Require \(V_{A} = V_{B}\) the moment of closest approach

60 - 12t = 60 - 15 ( t- 0.75)

t = 3.75 s

The worst case scenario without contact is when \(S_{A} = S_{B}\)

At t = 3.75 s, from eq. (1) and (2),

60(0.75) + 60(3.75 - 0.75) - 7.5(3.75 - 0.75)² = d + 60(3.75) = 6(3.75)²

157.5 = d + 140.62

d = 16.9 ft

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Answer:

Explanation:

\( \sf{Potential Energy ( P.E ) \: = \: 20.8 \: joule}\)

\( \sf{distance \: = 27.6 \: metre}\)

\( \sf{mass = }\) ?

\( \sf{acceleration \: due \: to \: gravity = 9.68 \: {metre \: per \: second}^{2} }\)

Now, let's find the mass:

\( \sf{PE \: = mass \times gravity \: \times \: distance}\)

plug the values

⇒\( \sf{20.8 = m \times 9.8 \times 27.6}\)

Multiply the numbers

⇒\( \sf{20.8 = 270.48 \: m}\)

Swap the sides of the equation

⇒\( \sf{270.48m = 20.8}\)

Divide both sides of the equation by 270.48

⇒\( \sf{ \frac{270.48m}{270.48} = \frac{20.8}{270.48} }\)

Calculate

⇒\( \sf{0.0769}\) kg

Hope I helped!

Best regards!!

Answer:

\(\huge \boxed{\mathrm{0.0769 \ kg}}\)

Explanation:

\(\displaystyle \sf Mass=\frac{Potential \ energy}{Acceleration \ of \ gravity \times Height}\)

\(\displaystyle m=\frac{PE}{gh}\)

\(\mathrm{We \ need \ to \ find \ the \ mass.}\)

\(\displaystyle m=\frac{20.8}{9.8 \times 27.6}\)

\(m= 0.0769\)

Answer:

8.57 m

Explanation:

To solve the problem, we have to decompose the two vectors along the two directions first:Vector A:- x component: Ax = +9.66 m- y compoment: Ay = 0 (the vector lies along the x-axis)Vector B:- x component: - y component: So now we can find the sum of the two vectors by adding the components along each axis:And the magnitude of the sum is given by Pythagorean theorem:

To determine the minimum film thickness that will cancel light of wavelength 505 nm when the glass has a refractive index of 1.62 and TiO2 has an index of refraction of 2.62, we will use the formula for constructive interference:

t = (mλ) / (2n), where t is the thickness of the film, m is the order of interference, λ is the wavelength, and n is the refractive index of the coating material.

For the minimum thickness (m = 0.5), we have:

t = (0.5 * 505 nm) / (2 * 2.62) ≈ 48.09 nm


So, the minimum film thickness that will cancel light of wavelength 505 nm is approximately 48.09 nm.

For part (b), we will find the next three thinnest film thicknesses that would also work:

For m = 1.5, t ≈ (1.5 * 505 nm) / (2 * 2.62) ≈ 144.27 nm

For m = 2.5, t ≈ (2.5 * 505 nm) / (2 * 2.62) ≈ 240.46 nm

For m = 3.5, t ≈ (3.5 * 505 nm) / (2 * 2.62) ≈ 336.64 nm

Thus, the three thinnest alternative film thicknesses that would also cancel light of wavelength 505 nm are approximately 144.27 nm, 240.46 nm, and 336.64 nm.

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Answer:

Wandering Slowly with no pattern

Explanation:

I apologize to those who got it wrong from the first person.

The Earth's magnetic pole is wandering slowly with no pattern. Then the correct option is D.

Magnetic poles are the points near the extremities of the axis of rotation of the Earth or another celestial body where a magnetic needle dips vertically.

At either end of a magnet, the magnetic pole is where the applied magnetic field is strongest. An imaginary basic particle known as a magnetical monopole may be referred to as a magnet's pole. A unique type of magnet is the magnetism poles of celestial bodies.

The north magnetism pole of the earth Today is located where the north arrow is on a path leading downhill.

The magnetic pole is located far away from the geographic pole.

Earth's magnetic pole is defined as wandering slowly with no pattern.

Thus, the correct option is D.

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A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15° to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, the minimum speed at which she can travel without slipping is 13.64 m/s.

To find the minimum speed at which the girl can travel without slipping, we need to consider the forces acting on her and her cycle as they move in a circular track.

The forces acting on the girl and her cycle are the gravitational force (mg), the normal force (N), and the frictional force (f). The frictional force provides the centripetal force necessary to keep the girl moving in a circular path.

The normal force can be resolved into two components: the vertical component (N⊥) and the horizontal component (N∥). The vertical component balances the gravitational force, while the horizontal component provides the centripetal force.

Mass of the girl and cycle (m) = 60 kg

Diameter of the circular track (d) = 60 m

Bank angle (θ) = 15 degrees

Coefficient of friction (μ) = 0.25

Find the normal force components:

N⊥ = mg cos(θ)

N∥ = mg sin(θ)

The frictional force:

f = μN⊥

The frictional force (f) provides the centripetal force required for circular motion:

f = m(v² / r)

Here, v is the velocity and r is the radius of the circular track. The radius is:

r = d / 2

Combining the equations, we have:

μN⊥ = m(v² / r)

Substituting the values we have:

μmg cos(θ) = m(v² / (d / 2))

v² = (μmg cos(θ) / m) * (d / 2)

v² = (μg cos(θ)) * (d / 2)

v = √((μg cos(θ)) * (d / 2))

v = √((0.25 * 9.8 * cos(15)) * (60 / 2))

v ≈ 13.64 m/s

Therefore, the minimum speed at which the girl can travel without slipping is approximately 13.64 m/s.

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By the de Broglie wavelength equation, the speed of proton is 0.47 × \(10^{8}\) m/s.

λ = h / mv

λ = wavelength, given = 8.29 fm

h = plank's constant, given = 6.626 × \(10^{-34}\)

m = mass, given = 1.672 × \(10^{-27}\) kg

v = velocity

Now, v = h / mλ

Put the values in formula,  v = h / mλ

v = 0.47 × \(10^{8}\) m/s

Therefore, the speed of proton is 0.47 × \(10^{8}\) m/s.

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The 90% confidence interval for the true average assembly time for a board is (34.19 minutes, 35.81 minutes).

What is average?
The ratio of a sum of the values in a given set to all the values in the set is the mean value, which is the definition of the average. The average formula has numerous practical uses. If we were asked to determine the average male height throughout India or the average age of the men and women in a group, we would add up all the data and divide it by the total number of data points. In mathematics, the central value of the a set of data is expressed as the average of a list of data.

A) The 90% confidence interval for the true average assembly time for a board is (34.19 minutes, 35.81 minutes).

B) The 90% confidence interval for the true variance of assembly time is (3.42 minutes, 7.06 minutes).

C) The 90% confidence interval for the true standard deviation of assembly time is (1.84 minutes, 2.65 minutes).

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Answer:

the force constant  k = 2.369 N/m

Explanation:

Given that:

A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair.

with period T = 0.500 s and a mass of 0.0150 kg, Then the force constant can be calculated by using the formula:

\(\mathtt{T = 2 \pi \ \sqrt{\dfrac{m}{k} }}\)

where;

T = time period

m = mass

k = force constant.

By making k the subject of the formula; we have:

\(\mathtt{T^2 = 4 \pi^2 (\dfrac{m}{k})}\)

\(\mathtt{k =\dfrac{4 \pi ^2 \ m}{T^2}}\)

replacing our given values , we have:

\(\mathtt{k =\dfrac{4 (3.142) ^2 \ \times 0.0150 }{0.5^2}}\)

\(\mathtt{k =\dfrac{39.49 \ \times 0.0150 }{0.25}}\)

\(\mathtt{k =\dfrac{0.59235 }{0.25}}\)

k = 2.369 N/m

According to the information available in the question, the force constant is 2.37N/m.

Using the relation;

T = 2π√m/k

T = period = 0.500 s

m = mass in kilograms = 0.0150-kg

k = spring constant = ?

Making k the subject of the formula;

k = 4π^2m/T^2

k = 4 × (3.142)^2 ×  0.0150/(0.500 )^2

k = 2.37N/m

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Answer:

At position "B" the northern hemisphere is tilted the most from the earth-sun direction and will experience the shortest hours of daylight, (and also the most indirect sun rays).

Answer:

  (D)  4

Explanation:

The percentage error in each of the contributors to the calculation is 1%. The maximum error in the calculation is approximately the sum of the errors of each contributor, multiplied by the number of times it is a factor in the calculation.

  density = mass/volume

  density = mass/(π(radius^2)(length))

So, mass and length are each a factor once, and radius is a factor twice. Then the total percentage error is approximately 1% +1% +2×1% = 4%.

_____

If you look at the maximum and minimum density, you find they are ...

  {0.0611718, 0.0662668} g/(mm²·cm)

The ratio of the maximum value to the mean of these values is about 1.03998. So, the maximum is 3.998% higher than the "nominal" density.

The error is about 4%.

_____

Additional comment

If you work through the details of the math, you will see that the above-described sum of error percentages is just an approximation. If you need a more exact error estimate, it is best to work with the ranges of the numbers involved, and/or their distributions.

Using numbers with uniformly distributed errors will give different results than with normally distributed errors. When such distributions are involved, you need to carefully define what you mean by a maximum error. (By definition, normal distributions extend to infinity in both directions.) While the central limit theorem tends to apply, the actual shape of the error distribution may not be precisely normal.

Answer:

Explanation:

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Answer:

wire By please mark my answer in brain list

Answer:

Remove wire G, if the wire after it is F. Remove wire A as C is connecting to it already.

Answer:

The frequency will still remain F

Explanation:

Firstly, we should remember that the frequency of a simple harmonic oscillator doesn't depend on the amplitude. Rather, it depends on the spring constant, k, and the mass of the attached weight, m. This means that the change in amplitude will not lead to a corresponding change in frequency.

the frequency is represented by the formula

f = 1/2π * √(k/m),

where

f = frequency of the oscillator

k = spring constant and

m = mass attached to the spring

From the formula above, we can state that the frequency doesn't depend on the amplitude at all, and as such, the amplitude changing from A to 2A, will effect no change in the frequency F.

The weight of the car is 14308 Newtons and the net force acting on it is 230 N. The free body diagram is attached with the answer.

A drag is force that opposes the motion of an object by acting in the direction opposite to its motion.

Given is a car on the freeway that is traveling north at 55 mph on a straight and flat part of the road. The mass of the car is 1460 kg. The engine is pushing the car forward with a force of 760 N. while the drag on the car is 530 N.

PART - A

The free body diagram is attached with the answer. The following equations will help in mathematical analysis.

F[engine] - F[drag] = ma

a = {F[engine] - F[drag]}/m

and

W = N = mg

PART - B

The weight of the car can be calculated as follows -

W = mg = 1460 x 9.8 = 14308 Newton

PART - C

Net force on the car [F] = Force provided by engine {F[E]} - drag force {F[D]}

F = 760 - 530 = 230 N

The direction of force is towards north.

Therefore, the weight of the car is 14308 Newtons and the net force acting on it is 230 N. The free body diagram is attached with the answer.

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Answer: A B C D

Explanation:

The forms of energy that increase as a rocket blasts off are the chemical potential and kinetic energy that are in Option D, as during the launch of a rocket, the chemical potential energy stored in the rocket's fuel is converted into kinetic energy.

When a rocket launches, it uses its engines to burn fuel and produce exhaust gases, and this process releases the chemical potential energy stored in the fuel, which is converted into kinetic energy, as the rocket gains speed and altitude, its kinetic energy increases, but the potential energy of the rocket remains relatively constant during the launch. So during a rocket launch, the chemical potential energy stored in the fuel is converted into kinetic energy as the rocket's engines expel exhaust gases.

Hence, the forms of energy that increase as a rocket blasts off are the chemical potential and kinetic energy that are in Option D.

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The motor could  lift 15 g in a time of 8 seconds 10884 meter.

The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.

Given that motor operates at 200 W.

At time interval of 8 second, it do a work = 200×8 joule = 1600 joule.

Hence,  it lift 15 g in a time of 8 seconds = 1600/(0.015×9.8) meter

= 10884 meter.

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Answer:search this up but put quizzlet at the end it should be there

Explanation:

Answer:

 freezing melting sublimating  x y

 x and

Explanation:

To drop a table of states of matter the best headings must be

table name: matter state

    freezing melting sublimation x y

This order goes from the solid state to the gaseous state, which is obtained by introducing heat into the system

Answer: D on edge

X: Heat Is Absorbed

Y: Heat Is Released

Explanation:

sublimation and melting are both absorbing heat(aka getting warmer)as they change state while freezing and deposition are releasing heat(aka getting colder)as they change state

The half-life of a first-order reaction is a constant that is related to the rate constant for the reaction: t1/2 = 0.693/k.

It is used in life-science laboratories in applications in which lower energy beta emissions are advantageous such as DNA sequencing. P can be used to label nucleotides. It is less energetic than 32P, giving a better resolution.

Phosphorus 33 is an artificial radioactive element. It is produced with a low yield by the neutron bombardment of phosphorus 31 (stable). The phosphorus 33 has a radioactive period of 25.3 days.

Phosphorus-33 atom is the radioactive isotope of phosphorus with relative atomic mass 32.971725, half-life of 25.34 days and nuclear spin (1)/2.

Phosphorus was discovered by the German merchant Hennig Brand in 1669.

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Answer:

Its B- overconfidence

Explanation:

The tendency to have more confidence in judgment and decisions than one should is called Overconfidence

Overconfidence  is a bias in which a person's subjective confidence is his or her judgement is reliably greater then the objective accuracy of those judgments when confidence is relatively high

Hence, The tendency to have more confidence in judgment and decisions than one should is called Overconfidence

correct answer : option B)Overconfidence

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