a certain ore is 27.9'.9% nickel by mass. how many kilograms of this ore would you need to dig up to have 85.0 g85.0 g of nickel?

Answer:

No, it does not demonstrate conservation of matter because there are not the same number of atoms of the products and reactants. For example, the carbon dioxide and water reactants are not represented on the product side of the equation.

Since there are mutations in the lacZ and lacY genes (lacz- and lacy-), only the LacA protein, encoded by the laca+ allele, is functional. Therefore, the phenotype is Lacz- LacY+ LacA+.

Based on the given genotype, the phenotype of the E. coli merodiploid strain in the absence (-) or presence (+) of IPTG can be determined as follows:

IPTG: Lacz- LacY- LacA+

IPTG: Lacz- LacY+ LacA+

In the absence of IPTG, the lac operon is not induced, and the lac repressor protein encoded by the lacl° allele is non-functional. Therefore, it cannot bind to the operator region, allowing the transcription of lacZ, lacY, and lacA genes. However, since there are mutations in the lacZ and lacY genes (lacz- and lacy-), the LacZ and LacY proteins are not produced. The LacA protein, encoded by the laca+ allele, is functional, resulting in the phenotype Lacz- LacY- LacA+.

IPTG: Lacz- LacY+ LacA+

In the presence of IPTG, IPTG acts as an inducer of the lac operon. It binds to the repressor protein encoded by the lacl° allele, causing a conformational change that prevents it from binding to the operator. This allows transcription of the lacZ, lacY, and lacA genes. However, since there are mutations in the lacZ and lacY genes (lacz- and lacy-), only the LacA protein, encoded by the laca+ allele, is functional. Therefore, the phenotype is Lacz- LacY+ LacA+.

So, the correct answer is A. - IPTG: Lacz- LacY- LacA+

IPTG: Lacz- LacY+ LacA+.

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Answer:

C2H6 > CH3OH > H2O

Explanation:

In hexane (C6H14), which is a nonpolar solvent, compounds that are nonpolar or have very low polarity tend to be more soluble. Here's the arrangement of the compounds you provided in order of expected solubility in hexane:

1. C2H6 (ethane) - Ethane is a nonpolar molecule composed of only carbon and hydrogen atoms, making it highly soluble in nonpolar solvents like hexane

2. CH3OH (methanol) - Methanol is a polar molecule due to the presence of the hydroxyl group (-OH). While it has some degree of polarity, it is less soluble in hexane compared to ethane because hexane is a nonpolar solvent.

3. H2O (water) - Water is a highly polar molecule, and hexane is a nonpolar solvent. Polar and nonpolar substances are generally immiscible, meaning they do not mix well. Water is not expected to be soluble in hexane.

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The expected solubility in hexane is C₂H₆ > CH₃OH > H₂O.

What is solubility?

Solubility refers to the ability of a substance, known as the solute, to dissolve in a solvent and form a homogeneous mixture called a solution.

When considering solubility in hexane, it is important to note that hexane is a nonpolar solvent. Substances that are nonpolar or have weak intermolecular forces are generally more soluble in hexane. On the other hand, polar substances or those with strong intermolecular forces tend to be less soluble in hexane.

Based on this information, we can rank the compounds by their expected solubility in hexane:

1.  C₂H₆  (ethane): Ethane is a nonpolar molecule composed of carbon and hydrogen atoms bonded together with nonpolar C-H bonds. It is expected to be highly soluble in hexane because both ethane and hexane are nonpolar substances.

2.  CH₃OH (methanol): Methanol is a polar molecule due to the presence of the polar O-H bond. While hexane is a nonpolar solvent, methanol has some degree of solubility in hexane due to the ability of hexane to dissolve small amounts of polar substances.

3.  H₂O. (water): Water is a highly polar molecule with strong hydrogen bonding. Hexane is unable to break the strong hydrogen bonds in water, making water insoluble in hexane. Water and hexane are immiscible and will separate into two distinct layers when mixed.

Therefore, the expected solubility in hexane, from most soluble to least soluble, is:

C₂H₆  > CH₃OH > H₂O.

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Answer:

Excited State Configuration: 1s^2 2s^2 2p^4 3s^1 are sperated by 13.00 eV.

Answer

%Yield = 87.2%

Explanation

Given:

mass of NH3 reacted = 73 g

mass of H2O produced = 101 g

We know:

molar mass of NH3 = 17,031 g/mol

molar mass of water = 18.01528 g/mol

Required: % Yield

Solution:

The formula used to calculate the percentage yield is:

%Yield = (actual yield/theoretical yield) x 100

The actual yield of H2O produced = 101 g

Now lets calculate the theoretical yield first.

First find the number of moles of NH3, and use stoichiometry to find the theoretical mass of water.

n = m/M n is the moles, m is the mass and M is the molar mass.

n = 73/17,031 g/mol

n = 4.29 mol

Using the stoichiometry, there molar ratio between NH3 and H2O is 4:6

Therefore the moles of H2O = 4.29 x (6/4)

n of H2O = 6.43 mol

The theoretical mass can then be calculated:

m = n x M

m = 6.43 mol x 18.01528 g/mol

m = 115.83 g

%Yield = (101 g/115.83)*100

%Yield = 87.2%

Answer:

Be,Mg,Ra etc

Explanation:

It should be palced in group 2A because as it reacts with chlorine in ratio of 1:2 . It's valancy is 2 and is metal as it react with non metal donating two electrons .

one more thing it fits there orderly

Answer:

Q = 382.5 Kj

Explanation:

Given data:

Mass of block = 10.00 Kg

Initial temperature = 10.0°C

Final temperature = 95.0°C

Specific heat capacity of iron = 0.45 KJ/Kg.°C

Energy given = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 95.0°C - 10.0°C

ΔT = 85.0°C

Q = 10.00 Kg×0.45 KJ/Kg.°C×85.0°C

Q = 382.5 Kj

Answer:

Zinc metals was oxidized ,zinc ions were reduced

Explanation:

The zinc atoms lose electrons and becomes oxidized . And zinc ions gain electrons (becomes reduced)

The redox reaction taking place here, is the zinc metal is oxidized and zinc ions are reduced further by accepting electrons. Hence, option a is correct.

In a redox reaction, one reactant species is oxidized and another one is reduced. Oxidation is the process of loss of one or more electrons to form its higher oxidation state.

Reduction is the process of gaining electrons forming its lower oxidation state. The species which undergoes oxidation is called oxidant and the one reduced is called reductant.

Zn metal have higher negative electrode potential and undergoes oxidation by losing two electrons to form the Zn²⁺ ions. Thus the Zn metal is oxidized.  The Zn²⁺ ions further undergoes reduction to form the metal by gaining electrons.

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If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)

1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).

2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.

It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).

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Answer:

A. Coefficients

Explanation:

that's the number in front of the molecules

Answer:

No

Explanation:

There is only one Nitrogen on the left side while there are 2 on the right. Also there is zero oxygen on the left side and two on the right. The amounts of hydrgen arent equal to each side either.

The most oxygen atoms shared by pairs of neighbouring tetrahedra are found in double chain silicates, which is the most common kind of silicate.

This particular silicate consists of silicon atoms bound to other silicon atoms in a chain with oxygen atoms, with oxygen atoms forming the corners of the tetrahedra. As compared to other forms of silicates, these chains share oxygen atoms with neighbouring chains, leading to a higher percentage of oxygen atoms shared by pairs of adjacent tetrahedra. Due to the lack of connectedness between their tetrahedral units, other silicate types, such as sheet silicates and framework silicates, have a lower percentage of oxygen atoms shared by pairs of neighbouring tetrahedra. Because of this, double chain silicates have a tendency to be more dense and structurally complicated than other silicate kinds.

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Explanation:

NA2SO3

Combination of these three elements forms following compounds.

And the compound that's going to be formed,depends on the ratio of available oxygen and sulphur.

Depends on the ratio of sulfur to oxygen...

sodium sulfate, Na2SO4

sodium sulfite, Na2SO3

sodium thiosulfate, Na2S2O3

ionic bond is present in between SO3 -2 and Na+2

structure of SO3 -2 [take - sign as delta - which here indicates,partial formal charge of oxygen] (image below)

Here,The oxygen is more electronegative.So,2 oxygen atoms drag one Electron from sulphur atom,leaving behind the formal charge of -1 on two oxygen atoms.

The third oxygen forms covalent bond by sharing 2 electrons. (Actually this ion has resonance structure)

This sulphite ion combines with two sodium ions to form two ionic bonds.This happens when sodium, being an alkali metal dontes it's valence electron to oxygen.

SO2

In Sulphur dioxide, Sulphur is bonded to 2 oxygen atoms. Oxygen is more electronegative than Sulphur and thus, shows a fixed valency of 2. As a result each oxygen forms two bonds with the Sulphur atom making its valency 4.

NAHSO4

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Questions & Answers

CBSE

Chemistry

Grade 11

Oxidation State or Oxidation Number

Question

Answers

Related Questions

The oxidation state of sulphur in NaHSO4 ?

A) 0

B) + 2

C) −2

D) + 4

E) + 6

Answer

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72.9K+ Views

Hint: The oxidation state is defined as the charge on the atom. The sum of the oxidation state of an atom in a molecule is equal to the charge on the molecule. The neutral molecules charge less species. It has zero charges.

Complete Solution :

- The oxidation number of an atom is defined as the charge on an atom that appears on the atom on forming an ionic bond. An atom which has higher electronegativity has a negative oxidation state and more electropositive elements have positive oxidation state.

- We are interested in determining the oxidation state of an atom in a molecule. We know that the net charge on a neutral atom or molecule is always equal to zero. Let’s determine the oxidation state of S in the NaHSO4 .

- The oxidation number of alkali metal that is a sodium atom is equal to +1 . Similarly the hydrogen has an +1 oxidation state. Oxygen is an electronegative element. It has an −2 oxidation state. The oxidation states are as listed below:

Element Oxidation state

Na +1

H +1

O −2

We know that the sum of the oxidation state of an atom in a neutral molecule is equal to zero. Then we have,

0 = O.S. of Na + O.S. of H + O.S. of S + 4(O.S. of O)

Let’s substitute the values of oxidation state .we have,

0 = 1 + 1 + O.S. of S + 4(−2)⇒O.S. of S= 8−2 = +6

Therefore the oxidation state of sulphur in NaHSO4 is equal to +6 . So, the correct answer is “Option E”.

H2S

Valency of sulphur is 2 in H2S

Answer:

All particles of matter are always in constant motion. In this case, the particles of the rock possess kinetic energy as they vibrate in place. However, the particles also contain potential energy due to their position and arrangement. This form of stored energy is responsible for keeping the particles bonded together.

Explanation:

Answer: There are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Explanation:

Given: \(M_{1}\) = 0.0023 M,          \(V_{1}\) = ?

\(V_{2}\) = 15.0 mL,           \(M_{2}\) = 0.012 M

Formula used to calculate volume of strontium hydroxide solution is as follows.

\(M_{1}V_{1} = M_{2}V_{2}\)

Substitute the values into above formula as follows.

\(M_{1}V_{1} = M_{2}V_{2}\\0.0023 M \times V_{1} = 0.012 M \times 15.0 mL\\V_{1} = 78.26 mL\)

Thus, we can conclude that there are 78.26 mL of a 0.0023M strontium hydroxide solution are needed to completely react 15.0 mL of 0.012M hydrochloric acid.

Carbon plays a fundamental role in the structure of organic compounds.

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3)6 electrons and neon

In an atom there are levels of energy in the shell and sub shell  

This energy level is expressed in the form of electron configurations.  

The electron configuration Oxygen (atomic number = 8) :

1s²2s²2p⁴

Oxygen will try to achieve stability (according to the octet rule) by binding 2 electrons so that the 2p orbits are filled with 6 electrons, so that the configuration is stable like the noble gases Neon

₁₀Ne = 1s² 2s² 2p⁶

During the cell cycle, compounds called cyclins increase and decrease in a regular pattern. They regulate the stages of cell division and growth.

Cell cycle development is regulated in element by way of the sequential pastime of various cyclins. The cyclins are regulatory subunits that bind, prompt and provide substrate specificity for their catalytic companion serine-threonine kinases, collectively called cyclin-established kinases.

Cyclins are a family of proteins that don't have any enzymatic interest of their personal however spark off CDKs through binding to them.

S cyclins are involved inside the induction of DNA replication and early stages of mitosis. Their stages upward push at the beginning of S phase and fall in early mitosis.

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The nuclear equation for the alpha decay of Uus-294 is

\(^{294}{117} Uus\) →\(^{4}{2}He + ^{290}_{115}Mc\)

To complete the nuclear equation for the alpha decay of Uus-294, we need to determine the missing product.

During alpha decay, the emission of an alpha particle, composed of two protons and two neutrons, leads to the formation of a new nucleus.

The balanced nuclear equation for the alpha decay of Uus-294 can be represented as follows:

\(^{294}{117} Uus\) → \(^{4}{2}He +\)_____(missing product)

In this equation, the atomic number of the missing product must be two less than the atomic number of Uus-294 (117 - 2 = 115), and the mass number of the missing product must be four less than the mass number of Uus-294 (294 - 4 = 290).

Based on this information, the missing product can be identified as:

\(^{290}_{115}Mc\)

Mc stands for Moscovium, which has an atomic number of 115. By subtracting two from the atomic number of Uus, we obtain the atomic number of Mc. The mass number of Mc-290 is obtained by subtracting four from the mass number of Uus-294.

Therefore, the  nuclear equation for the alpha decay of Uus-294 is:

\(^{294}{117} Uus\)→ \(^{4}{2}He + ^{290}_{115}Mc\)

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The complete question is :

Complete this nuclear equation for the alpha decay of Uus-294 by writing a

notation for the missing product:

\(^{204} {117} Uns\)→\(^{4} _{2} He +\)_____

Answer:B is right

Explanation: Al loses electrons and is oxidised, Au gains electron. And is reduced

To solve such this we must know the concept of half cell reaction. Therefore, the correct option is option B that is  Al(s) → A1³⁺(aq) + 3e and  Au(aq) + e \(\rightarrow\)Au(s)

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

Oxidation is loss of electrons and reduction is gain of electrons. The electron transfer from oxidant to reductant. Al loses electrons and is oxidized, Au gains electron. And is reduced.

Therefore, the correct option is option B that is  Al(s) → A1³⁺(aq) + 3e and Au(aq) + e \(\rightarrow\)Au(s)

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Answer:

It’s sodium chloride

Explanation:

Hope that helps

The term molecular mass can only be applied to a(n) covalent compound since compounds do not consist of molecules. the correct term that is applicable to all types of compounds is mass. covalent

The molecular components of a compound offer the smallest integer ratio of the atoms withinside the compound. Different compounds may have identical molecular components. The term "molecular weight" isn't suitable while speaking about ionic compounds that aren't made from personal molecules

An atom and its ion have identical atomic mass due to the fact the mass of the electron that turns an atom into an ion is negligible. The term "molecular weight" won't be suitable due to the fact the components of an ionic compound now no longer describe the composition of an unmarried molecule.

Something like desk salt (NaCl) is a compound due to the fact it's miles made from a couple of elements (sodium and chlorine), however, the bonds that keep NaCl collectively are ionic bonds, so in a molecule There is none. Sodium chloride may be stated to be an ionic compound if desired.

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The hematocrit of the larger individual should be higher than that of the smaller individual.

Hematocrit refers to the percentage of a person's total blood volume that is comprised of red blood cells (RBCs). Hematocrit levels typically differ between males and females. Males have a higher hematocrit level than females.

Red blood cells (RBCs) are the most numerous cells in the blood. They are responsible for transporting oxygen from the lungs to the rest of the body. The hematocrit of the larger individual should be higher than that of the smaller individual. This is because the hematocrit level in the blood is typically higher in individuals who are larger and weigh more.

The reason for this is that larger individuals have a greater blood volume, and so their blood has a higher concentration of red blood cells (RBCs). RBCs contain hemoglobin, which is responsible for carrying oxygen to the body's tissues. Thus, individuals with a higher hematocrit level typically have a greater capacity to transport oxygen to their tissues.

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The coordination geometry of an octahedron is determined by the number of atoms or ions that are bonded to the central atom. In the case of chromium(III) chloride crystals, the chromium atom is surrounded by six chloride ions, which gives it an octahedral coordination geometry.

However, the ratio of chromium to chlorine in the formula of chromium(III) chloride, CrCl3, is not 1:6. The formula indicates that there is one chromium atom for every three chlorine atoms, which would not produce an octahedral coordination geometry if the atoms were bonded directly to each other.

One possible explanation for this discrepancy is that the chromium and chlorine atoms are not bonded directly to each other in the crystal structure.

Instead, the chromium atom may be surrounded by a group of six chloride ions that are bonded to each other, forming an octahedron. This would allow the coordination geometry of the chromium atom to be octahedral even though the ratio of chromium to chlorine atoms in the formula is not 1:6.

Alternatively, the chromium and chlorine atoms may be bonded to each other through intermediate atoms or ions, such as water molecules.

In this case, the coordination geometry of the chromium atom would still be octahedral because it would be bonded to six chlorine atoms, even though the overall ratio of chromium to chlorine atoms in the formula would not be 1:6.

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Answer:

What?

Explanation:

Answer:

alumimum

Explanation:

Aluminum oxidation happens faster than that of steel, because aluminum has a really strong affinity for oxygen. Rather than flaking though, aluminum oxide just forms a hard, whitish-colored surface skin. When all the aluminum atoms have bonded with oxygen the oxidation process stops.

hope this answers your question.

The question is "The concerns over the class of synthetic organic compounds called polybrominated diphenyl ethers (PBDEs) include each of the following EXCEPT:"
The correct answer is "The common use of these compounds as a treatment for children's clothing." The presence of these compounds in human breast milk, the presence of the compounds in aquatic food webs, the exposure to some forms of PBDEs can lead to brain damage, and the effect of the compounds on invertebrates are all concerns associated with PBDEs, but the common use of these compounds as a treatment for children's clothing is not.

The question is incomplete, the complete question is;

Arrange the following ionic compounds in order of decreasing amount of energy released in lattice formation: NaF, MgS, TlN, and CsI.

Answer:

TlN> MgS > NaF > CsI

Explanation:

Recall that lattice energy is the energy evolved when a crystal lattice is formed from its component ions.

The lattice energy depends on the size of the ions. The smaller the sizes of the ions, the larger the lattice energy.

The order of energy released in lattice formation for these compounds is;

TlN> MgS > NaF > CsI

The molarity of NaOH solution is 0.114 M.

Given, Mass of flask and vinegar solution= 25.17 g.Mass of flask= 15.12 gVolume of vinegar solution (in mL)= 10.00 mlInitial volume of NaOH (in mL)= 0.00 mlFinal volume of NaOH (in mL)= 39.00 mlThe Mass of vinegar solution is 10.0503 g.The volume of NaOH used in titration is 39.00 ml.Let's calculate the molarity of the NaOH solution.First, calculate the moles of NaOH used in the reaction. Moles of NaOH = Molarity × Volume of NaOH (in L) Converting volume in mL to L,Volume of NaOH used = 39.00 mL = 39.00/1000 L = 0.0390 LThe molarity of NaOH solution is given by;Molarity of NaOH = Moles of NaOH / Volume of vinegar solution (in L)Converting volume in mL to L,Volume of vinegar solution = 10.00 mL = 10.00/1000 L = 0.0100 LNow, substituting the values; Molarity of NaOH = 0.114 M.

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