A cheetah is running at a speed of 18.0 m/s in a direction of 54° north of west. Find the components of the cheetah's velocity along the following directions.
(a) the velocity component due north
b) the velocity component due west
Answers
The velocity component due north of the cheetah is 14.56 m/s.
The velocity component due west is 10.58 m/s.
Component's of the cheetah's velocity
The component's of the cheetah's velocity is calculated as follows;
velocity component due northVy = V sinθ
Vy = 18 m/s x sin(54)
Vy = 14.56 m/s
velocity component due westVx = V cosθ
Vx = 18 m/s x cos(54)
Vx = 10.58 m/s
Thus, the velocity component due north of the cheetah is 14.56 m/s.
The velocity component due west is 10.58 m/s.
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Related Questions
You are approaching a railroad crossing with no warning devices and are unable to see 400 feet down the tracks in one direction. the speed limit is:______
Answers
Answer: The speed limit is 15 mph when you come within 100 feet of a railroad crossing and you cannot see the tracks for 400 feet in both directions. You may go faster than 15 mph if the crossing is controlled by gates, a warning signal, or a flagman.
Explanation: hope this helps
Answer:69
Explanatioits funnyn:
Are stairs a type of inclined plane?
Answers
Answer:
Inclined planes are simple machines used to make work easier. Ramps, ladders, and staircases are all inclined planes.
Explanation:
Answer:
imma say yes
Explanation:
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × 106 joules
B. 3.4 × 106 joules
C. 5.6 × 106 joules
D. 6.8 × 106 joules
Answers
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\) meters. If the truck's mass is 7,000 kilograms, the work done to reach this distance is 3.3× \(10^6\) joules.
The correct answer is option E.
To calculate the work done by the truck to cover a distance of 5.8 × \(10^4\)meters, we need to use the equation for work:
Work = Force × Distance
In this case, the force can be calculated using Newton's second law:
Force = mass × acceleration
Where:
Acceleration (a) = \(0.0083 meters/second^2\)
Distance (d) = 5.8 ×\(10^4\) meters
Mass (m) = 7,000 kilograms
First, let's calculate the force exerted by the truck:
Force = mass × acceleration = (7,000 kg) ×\((0.0083 meters/second^2)\)= 57.1 Newtons
Next, we can calculate the work done:
Work = Force × Distance = (57.1 N) × (5.8 × 10^4 meters) = 3.3158 × \(10^6\)joules
Rounded to the nearest significant figure, the work done by the truck is approximately 3.3 × \(10^6\) joules.
Therefore, the correct answer is E.
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The question probable may be:
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\)meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × \(10^6\) joules
B. 3.4 ×\(10^6\) joules
C. 5.6 × \(10^6\)joules
D. 6.8 × \(10^6\)joules
E. 3,3 ×\(10^6\) joules
Sound travels faster in air if the air temperature is :_____
a) warm.
b) average.
c) cold.
Answers
Answer: A) warm
Explanation:
The higher the temperature the faster it travels.
In a large tank of liquid, the hydrostatic pressure at a given depth is a function of:
a. depth.
b. surface area.
c. liquid density.
d. Choices a and c are both valid.
Answers
The hydrostatic pressure at a given depth in a large tank of liquid is a function of depth and liquid density. Therefore, choices a and c are both valid.
The hydrostatic pressure at a given depth in a liquid is determined by the weight of the liquid above that depth.
As the depth increases, the weight of the liquid above it increases, resulting in an increase in pressure.
The pressure at a given depth can be calculated using the following formula:
P = ρgh
where P is the pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the depth.
As we can see from the formula, the pressure is directly proportional to the depth and the density of the liquid. The surface area of the tank does not affect the hydrostatic pressure at a given depth.
Therefore, choices a and c are both valid as the hydrostatic pressure at a given depth is a function of depth and liquid density.
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If the rate at which the oceanic ridge is spreading is 5 cm/yr. How much farther (in kilometers) will continents A and B be from each other in one million years? Hint: Speed = Time Dis tan ce , so Distance = Speed × Time. 1 km=1000 m,1 m=100 cm. Show your work. (2)
Answers
In one million years, continents A and B will be 50 kilometers farther apart.
The rate at which the oceanic ridge is spreading is given as 5 cm/yr. To find how much farther continents A and B will be from each other in one million years, we can use the formula Distance = Speed × Time.
First, let's convert the speed from cm/yr to km/yr. Since 1 km = 1000 m and 1 m = 100 cm, we divide the speed by 100,000 to convert cm/yr to km/yr. Therefore, the speed is 5 cm/yr ÷ 100,000 = 0.00005 km/yr.
Next, we multiply the speed by the time (1 million years) to find the distance. Distance = 0.00005 km/yr × 1,000,000 years = 50 km.
Therefore, in one million years, continents A and B will be 50 kilometers farther from each other.
To summarize:
- Convert cm/yr to km/yr by dividing by 100,000.
- Multiply the speed in km/yr by the time (1 million years) to find the distance.
- The continents will be 50 kilometers farther from each other.
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How is speed related to kinetic energy?
Answers
Answer:
K.E. = 1/2mv^2
Explanation:
v is velocity (a vector) not speed (a scalar) but they have the same magnitude
Four forces (1,2,3 and 4) are in the x-y plane and act on an irregularly shaped object
Answers
The statement describes an irregularly shaped object experiencing four forces in the x-y plane, and elaborating on its nature, the magnitude and direction of the forces, and their intended outcome provides more context to the scenario.
The given statement describes a scenario in which an object of irregular shape is subjected to four forces acting in the x-y plane. To rephrase this statement, one could start by stating that there is an object, the shape of which is not uniform or regular, and this object is experiencing the influence of four different forces.
These four forces have been designated as 1, 2, 3, and 4, and all of them are acting within the x-y plane. One way to elaborate on this statement is to provide additional context about the nature of the object, the magnitude and direction of the forces, and the intended outcome of this scenario.
For example, the irregularly shaped object could be a vehicle or a piece of machinery, and the four forces could be the result of external factors such as wind, gravity, or applied forces. The magnitude and direction of each force could be significant in determining the overall motion of the object, and the ultimate outcome could be to cause the object to move in a certain direction or to remain stationary despite the presence of the forces.
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Complete question:
How would you rephrase the statement "Four forces (1,2,3 and 4) are in the x-y plane and act on an irregularly shaped object"?
Two cannons with the same muzzle velocity of 100 m/s fire. One cannon aims at 40 degrees, the other aims at 60 degrees. Which cannon will fire further? You can assume flat ground for both cases.
Answers
Answer:
Below
Explanation:
45 degrees will produce greatest downrange distance ...closer to 45 will win.
40 degree cannon will fire further.
Cannon1 vertical velocity = 100 sin 40 m/s
Vertical speed = vo - at Vertical speed is zero at onehalf of the time in flight (at the apex)
0 = 100 sin 40 - 9.81 t shows t = 6.55 s to max height
total flight time = 2 x 6.55 s = 13.1 s ( up and then down)
Horizontal component = 100 cos 40 m/s
for 13.1 s this would be :
100 cos 40 m/s * 13.1 s = 1004 m downrange
Doing similar for the second cannon (60 °) would result in 883 downrange distance
two pendula are set up so that they just touch when at their lowest position. the pendulum on the left is made from a bowling ball with mass and is released from a height of above its lowest position. it swings down and collides elastically with the second pendulum initially at rest made from a golf ball with mass . what is the approximate maximum height that the golf ball reaches after the collision?
Answers
To answer your question, we need to use the conservation of momentum and conservation of energy principles. Since the collision between the two pendula is elastic, the total momentum and total energy before and after the collision remains the same.
Let's assume that the initial velocity of the bowling ball pendulum is v and the final velocity of both pendula after the collision is v'. According to conservation of momentum,
(m_bowlingball * v) = (m_bowlingball * v') + (m_golfball * v')
where m_bowlingball and m_golfball are the masses of the bowling ball and golf ball pendula respectively.
Similarly, using conservation of energy,
(1/2 * m_bowlingball * v^2) = (1/2 * m_bowlingball * v'^2) + (1/2 * m_golfball * v'^2) + m_golfball * g * h
where g is the acceleration due to gravity and h is the maximum height reached by the golf ball after the collision.
Solving these two equations for v' and h, we get:
v' = (m_bowlingball - m_golfball)/(m_bowlingball + m_golfball) * v
h = (m_bowlingball^2/(m_bowlingball + m_golfball)^2) * (v^2/2g)
Substituting the values given in the problem, we get:
v' = (16/21) * v
h = (256/441) * (v^2/2g)
Therefore, the approximate maximum height that the golf ball reaches after the collision is (256/441) * (v^2/2g), which is approximately 0.58 times the height from which the bowling ball was released.
Note: The exact height reached by the golf ball may vary slightly due to friction and air resistance.
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6) water flowing through a pipe suddenly comes to a section of pipe where the pipe diameter decreases to 93% of its previous value. if the speed of the water in the larger section of the pipe was 36 m/s what is its speed in this smaller section? a) 49 m/s b) 42 m/s c) 31 m/s d) 27 m/s
Answers
The speed of water in a smaller section of a pipe can be determined when the diameter of the pipe decreases from its previous value.
In this case, with a known speed in the larger section and a diameter reduction to 93% of the original size, the speed in the smaller section can be calculated.
The speed of water in a pipe is inversely proportional to the cross-sectional area of the pipe. As the pipe diameter decreases, the cross-sectional area reduces as well. According to the continuity equation, the product of speed and cross-sectional area remains constant. If the diameter decreases to 93% of its previous value, the cross-sectional area decreases to approximately (0.93)^2 = 0.8649 times its original value.
To maintain continuity, the speed of the water in the smaller section will increase inversely proportional to the cross-sectional area reduction. Therefore, the speed in the smaller section is approximately 36 m/s divided by 0.8649, which is approximately 41.62 m/s. Rounding to the nearest option, the answer is (b) 42 m/s.
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A 1.00kg object vibrates at the end of a vertical spring. If the frequency of the vibration is 1.25Hz, what is the spring constant?
Answers
Answer:
61.62 N/m
Explanation:
Applying,
1/F = 2π\(\sqrt{m/k}\).................. Equation 1
Where F = frequency, m = mass of the spring, k = spring constant, π = pie.
make k the subject of the equation
k = m(2πF)²............... Equation 2
From the question,
Given: m = 1.00 kg, F = 1.25 Hz
Constant: π = 3.14
Substitute these values into equation 2
k = 1(2×3.14×1.25)²
k = 61.62 N/m
At t=0, an 850-g mass at rest on the end of a horizontal spring (k = 168 N/m ) is struck by a hammer which gives it an initial speed of 2.20 m/s .
Determine the period of the motion.
Determine the frequency of the motion.
Determine the amplitude.
Determine the maximum acceleration.
Determine the total energy.
Determine the kinetic energy when x=0.40A where A is the amplitude.
Answers
To solve this problem, we can use the principles of simple harmonic motion (SHM) and the equations related to it.
1. Determining the period of the motion:
The period (T) of an object undergoing SHM is the time it takes to complete one full cycle. It can be calculated using the formula:
T = 2π√(m/k)
where m is the mass of the object and k is the spring constant.
Given:
Mass (m) = 850 g = 0.85 kg
Spring constant (k) = 168 N/m
Using the formula, we can calculate the period:
T = 2π√(0.85/168) ≈ 0.782 seconds
Therefore, the period of the motion is approximately 0.782 seconds.
2. Determining the frequency of the motion:
The frequency (f) of an object undergoing SHM is the number of cycles completed per unit of time. It can be calculated as the reciprocal of the period:
f = 1/T
Substituting the calculated value of T:
f = 1/0.782 ≈ 1.28 Hz
Therefore, the frequency of the motion is approximately 1.28 Hz.
3. Determining the amplitude:
The amplitude (A) of the motion is the maximum displacement of the object from its equilibrium position. In this case, it is not directly given. However, we can calculate it using the initial velocity (v) and the angular frequency (ω).
The angular frequency (ω) can be calculated using the formula:
ω = √(k/m)
Substituting the given values:
ω = √(168/0.85) ≈ 17.414 rad/s
The amplitude (A) can be calculated using the initial velocity and angular frequency:
A = v/ω
Given:
Initial velocity (v) = 2.20 m/s
Substituting the values:
A = 2.20/17.414 ≈ 0.126 m
Therefore, the amplitude of the motion is approximately 0.126 m.
4. Determining the maximum acceleration:
The maximum acceleration (amax) of an object undergoing SHM can be calculated using the formula:
amax = ω^2A
Substituting the calculated values:
amax = (17.414)^2 × 0.126 ≈ 30.34 m/s^2
Therefore, the maximum acceleration of the motion is approximately 30.34 m/s^2.
5. Determining the total energy:
The total energy (E) of an object undergoing SHM can be calculated as the sum of its potential energy (PE) and kinetic energy (KE). In SHM, at any point in the motion, the total energy remains constant.
The potential energy (PE) of the system can be calculated using the formula:
PE = 0.5kA^2
Substituting the given values:
PE = 0.5 × 168 × (0.126)^2 ≈ 1.34 J
The kinetic energy (KE) of the system can be calculated using the formula:
KE = 0.5mv^2
Substituting the given values:
KE = 0.5 × 0.85 × (2.20)^2 ≈ 2.042 J
The total energy (E) is the sum of potential energy and kinetic energy:
E = PE + KE = 1.34 + 2.042 ≈ 3.382 J
Therefore, the total energy of the system is approximately 3.382 J.
6. Determining the kinetic energy when x = 0.40A:
The kinetic energy (KE) at a specific displacement (x) from the equilibrium position can be calculated using the formula:
KE = 0.5k(A^2 - x^2)
Given:
x = 0.40A = 0.40 × 0.126 = 0.0504 m
Substituting the given values:
KE = 0.5 × 168 × (0.126^2 - 0.0504^2) ≈ 0.737 J
Therefore, the kinetic energy when x = 0.40A is approximately 0.737 J.
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If the wavelength of a 4. 40 ✕ 102 Hz sound in fresh water is 3. 30 m, what is the speed of sound in water?
Answers
When, the wavelength of a 4. 40 × 102 Hz sound in fresh water will be 3. 30 m. Then, the speed of sound in fresh water is approximately 1452 m/s.
To determine the speed of sound in water, we can use the relationship between frequency, wavelength, and the speed of sound. The formula is;
speed of sound = frequency × wavelength
Given;
Frequency (f) = 4.40 × 10² Hz
Wavelength (λ) = 3.30 m
By substituting the given values into the formula, we can calculate the speed of sound in water;
Speed of sound = 4.40 × 10² Hz × 3.30 m
When we multiply the frequency by the wavelength, we obtain the speed of sound.
Calculating the product, we get;
Speed of sound = 1452 m/s
Therefore, the speed of sound in fresh water will be approximately 1452. m/s.
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A car has a total mechanical energy of 920,500 J. If it goes airborne over a hill at 1.2 m above the ground, while traveling at 18( m)/(s), what is the mass of the car?
(HELP PLEASE I TOLD MY PARTNER IT WAS DONE)
Answers
According to the question the mass of the car is 897.6 kg.
Mass is a fundamental physical property of an object, which is determined by its amount of matter. It is a measure of the quantity of matter contained in an object, and is expressed in units such as kilograms (kg). Mass is also referred to as the inertia of an object, which is the resistance of an object to changes in its velocity when a force is applied to it. Mass is an invariable property of an object, which is independent of its location in space or time. The mass of an object is the same whether it is at rest or in motion. Mass is an intrinsic property of an object, which cannot be changed without changing the basic composition of the object.
The total mechanical energy of the car, 920,500 J, can be expressed as the sum of its kinetic and potential energies. We know the car is going airborne over a hill and we know the height of the hill (1.2 m) and the speed of the car (18 m/s).
K = 0.5 x m x (18 m/s)²
U = m x 9.8 m/s² x 1.2 m
0.5 x m x (18 m/s)² = 920,500 J
m x 9.8 m/s² x 1.2 m = 920,500 J
Solving these two equations, we get m = 897.6 kg.
Therefore, the mass of the car is 897.6 kg.
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Which of the following is one dimensional
A.
acceleration
B.
velocity
C.
both velocity and acceleration
D.
speed
Answers
Answer:
A.
Explanation:
Speed and velocity both require more than one component to be solved but acceleration is independant.
How are defenders on a baseball team positioned ?
Answers
Answer:
1 (pitcher), 2 (catcher), 3 (first baseman), 4 (second baseman), 5 (third baseman), 6 (shortstop), 7 (left fielder) 8 (center fielder), and 9 (right fielder)
Explanation:
There are nine fielding positions in baseball. Each position conventionally has an associated number, for use in scorekeeping by the official score
If net force acting on object is 0, then the force is considered to be..
a. balanced
b. equal in direction
c. unbalanced
d. distance/time
Answers
If net force acting on object is 0, then the force is considered to be balanced (option A).
What is net force?A net force refers to the sum of all the forces acting on an object.
The net force can accelerate a mass. Some other force acts on a body either at rest or motion. The net force is a term used in a system when there is a significant number of forces.
Fnet = F₁ + F₂ + F₃.............+ Fn
When the net force of an object is zero (0), this means that the sum of forces acting on the object is balanced. A balanced forces are forces that are opposite in direction and equal in size.
Therefore, a net force of 0 is a balanced force.
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Danny Diver weighs 500 N and steps off a diving board 10 m above the water. Danny hits the water with kinetic energy of
Answers
Answer:
Danny hits the water with kinetic energy of 5000 J.
Explanation:
Given that,
The Weight of Danny Diver,
F = 500 N
m*g= 500 N
He steps off a diving board 10 m above the water.
h=10 m
when Danny diver hits water he generates the kinetic energy.
We need to find the kinetic energy of the water.
Let kinetic energy is K.
K = m*g*h
Where g is acceleration due to gravity.
that g= 9.8 m/s^2
now substituting the values in above equation
K= (500) * 10
K= 5000 J
Hence,
he hits the water with kinetic energy of 5000 J.
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An object travels for 5 minutes with constant motion. What conclusion can you make about the sum of the forces (total force) acting upon an object? How did you reach this conclusion?
Answers
PLEASE HELP
Obtain expressions in component form for the position vectors having the following polar coordinates.
Answers
After conversion into cartesian coordinates, we can write the position vectors as -
a) → r = 12.4 m , θ = 170° ↔ - 12.21 i + 2.15 j
b) → r = 4 cm , θ = 50° ↔ 2.57 i + 3.06 j
c) → r = 20 inches , θ = 210° ↔ - 17.32 i - 10 j
What are cartesian coordinates?Cartesian coordinates are two-dimensional coordinates which are used to represent a point in X-Y plane. They are, in general, written in the form (x, y), such that x is the horizontal distance of point from origin and y is the vertical distance of point from origin.
Given are the position vectors in polar coordinates of three points in X-Y coordinate system.
It is important to remember the following relations, in order to transform from polar coordinates (r, θ) into cartesian coordinates (x, y) -
x = r cosθ
y = r sinθ
a) → r = 12.4 m , θ = 170°
x = 12.4 x cos (170°) = 12.4 x -0.98480775301 = -12 .21
y = 12.4 x sin (170°) = 12.4 x 0.17364817766 = 2.15
In cartesian form → ( -12.21 i + 2.15 j )
b) → r = 4 cm , θ = 50°
x = 4 x cos (50°) = 4 x 0.64278760968 = 2.57
y = 4 x sin (170°) = 4 x 0.76604444311 = 3.06
In cartesian form → ( 2.57 i + 3.06 j )
c) → r = 20 inches , θ = 210°
x = 20 x cos (210°) = 20 x -0.86602540378 = -17.32
y = 20 x sin (210°) = 20 x -0.5= -10
In cartesian form → ( -17.32 i - 10 j )
Therefore, in two - Dimensional cartesian system, we can write the position vectors as -
a) → r = 12.4 m , θ = 170° ↔ - 12.21 i + 2.15 j
b) → r = 4 cm , θ = 50° ↔ 2.57 i + 3.06 j
c) → r = 20 inches , θ = 210° ↔ - 17.32 i - 10 j
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A football player pushes against another player trying to block him from moving any farther down the field. Which term best describes this example?
Negative work
Positive work
Negative force
Positive force
Answers
Answer:
NEGATIVE
Explanation:
Answer:
negative force
Explanation:
This is so because he needs more force inorder to block the other one.So he won't achieve any good force outcome
what amount of charge can be placed on a capacitor if the area of each plate is 7.3 cm2 ? express your answer using two significant figures.
Answers
The amount of charge that can be placed on a capacitor depends on the capacitance, which is determined by the area of each plate.
The capacitance of a capacitor is given by the formula:
C = ε0 * (A / d)
Where:
C is the capacitance,
ε0 is the permittivity of free space (a constant value),
A is the area of each plate,
d is the separation between the plates.
To determine the amount of charge, we can rearrange the formula as:
Q = C * V
Where:
Q is the amount of charge,
V is the voltage across the capacitor.
Given that the area of each plate is 7.3 cm², we can use this information to calculate the capacitance. However, the question does not provide the voltage or any other information required to calculate the amount of charge accurately. Without knowing the voltage or other relevant parameters, it is not possible to determine the exact amount of charge that can be placed on the capacitor.
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A wooden beam is 6.50 m long and weighs 325 N. It rests on two supports that are 3.00 m apart. Jane weighs 575 N. She stands on the beam in the center and then walks toward one end. How close to the end can she come before the beam begins to tip?
Answers
Suki can go 0.854 meters to the end before the beam starts to tilt.
Beam length: L = 6.5 m
Beam weight: W b = 336 N
Suki's weight is W s = 590 N.
Suki stands in the middle of the steel beam and moves toward the end. Since the beam is supported by two posts that are spaced three meters apart, the distance she may go before the beam starts to lean is determined by how far she moves from the left support.
Thus;
according to formula
Wb × (3/2) = (Ws × x)
where:
Wb= Beam weight
Ws= Suki's weight
Adding the necessary values results in;
336 × 1.5 = 590 × x
x = (336 × 1.5)/590
x = 0.854 m
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The intensity of the distributed lood acting on the beams 25 kN/m.) Determine the magnitude of reaction at Express your answer to three significant figures and include the appropriate units O ? N Value Units Submit Request Answer Figure Part 6 1 of 1 Delane te zand y components of reaction all sing scalar notation Express your answers using three significant figures separated by a comma HV AED vec ?
Answers
The magnitude of reaction at the beam due to the distributed load of 25 kN/m is 625 N.
What is the magnitude of reaction to the distributed load?The magnitude of reaction at the beam can be determined by calculating the total force exerted by the distributed load. In this case, the distributed load is given as 25 kN/m. To find the magnitude of reaction, we multiply the distributed load by the length of the beam.
Therefore, the magnitude of reaction is 25 kN/m multiplied by the length of the beam in meters. By performing the calculation, we obtain the value of 625 N as the magnitude of reaction at the beam due to the distributed load. This represents the total force exerted by the distributed load on the beam.
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If two runners cover the same distance in different amounts of time, how do there speeds compare
Answers
The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always looking for new sources of energy? Use the 2nd law of thermodynamics to answer this question.
Answers
Answer:
The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase
Explanation:
An object that has the ability to do work has_____energy.
A. Magnetic
B kinetic
C potential
D. Electrical
Answers
4. Explain What happens
to water when an object
hits it?
Answers
pressure depend on area
50 points and brainliest for whoever helps
Sciance
Answers
Answer:
P- Waves (Primary waves)
S- Waves (Secondary waves)
L- Waves (Surface waves)
Explanation: