A chemical engineer is responsible for designing a plant that processes 50 tons per day of reactant. what quantities change, what quantities stay the same?

The molecular formula of the compound is C12H14N₃O5.

To determine the molecular formula of the compound, we need to calculate the empirical formula first, which represents the simplest whole-number ratio of atoms in the compound.

Given the masses of carbon, hydrogen, nitrogen, and oxygen in the sample, we can calculate the moles of each element using their molar masses:

Moles of C = 0.900 g / 12.01 g/mol = 0.0749 mol

Moles of H = 0.0751 g / 1.008 g/mol = 0.0745 mol

Moles of N = 0.175 g / 14.01 g/mol = 0.0125 mol

Moles of O = 0.600 g / 16.00 g/mol = 0.0375 mol

Next, we need to find the simplest ratio of the moles by dividing each value by the smallest value:

Moles of C / 0.0125 = 5.992

Moles of H / 0.0125 = 5.960

Moles of N / 0.0125 = 1.000

Moles of O / 0.0125 = 3.000

Rounding these ratios to the nearest whole number, we get a ratio of 6:6:1:3, which corresponds to the empirical formula C6H6N1O3.

Finally, to determine the molecular formula, we divide the given molar mass of the compound (560 g) by the molar mass of the empirical formula (C6H6N1O3):

560 g / (6 * 12.01 g/mol + 6 * 1.008 g/mol + 1 * 14.01 g/mol + 3 * 16.00 g/mol) ≈ 560 g / 194.19 g/mol ≈ 2.88

Since the result is close to 3, we can multiply the empirical formula by 3 to obtain the molecular formula: C6H6N1O3 * 3 = C18H18N3O9.

However, none of the options provided match the calculated molecular formula.

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 The molecular formula for the molar mass of the unknown compound is 560g that consists of 0.900 g of carbon, 0.0751 g of hydrogen, 0.175 g of nitrogen, and 0.600 g of oxygen is C₂₄H₂₄N₄O₁₂ (Option A).

To determine the empirical formula, which involves converting the sample into moles. The moles of each element in the compound are calculated using their respective atomic masses.

The smallest number of moles is 0.0125 moles of nitrogen, which is the limiting reagent. As a result, the empirical formula is:

Therefore, the empirical formula is C₆H₆NO₃.

The empirical formula mass can be calculated by adding the molar masses of each element:

Total mass = 140.13

The molecular formula can be determined by comparing the empirical formula mass and the given molar mass. The molecular formula is the same as the empirical formula when the two values are equal. The ratio of the molecular formula mass to the empirical formula mass is equal to the integer value of n (number of empirical formula units):

n = molar mass/empirical formula mass

n = 560/140.13

n = 4

Therefore, the molecular formula is four times the empirical formula: C₂₄H₂₄N₄O₁₂ (Option A).

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If the pharmacy stocks 35% omeprazole suspension, it required 160 ml of the 35% omeprazole suspension for the dilution.

It is required to apply the idea of dilution equations to determine the quantity of 35% omeprazole suspension required for dilution.

Let C₁ be the concentration of the 8% omeprazole suspension (8%), and let V₁ be the volume of the 0.7 L 8% omeprazole suspension.

Let C₂ be the concentration of the 35% omeprazole suspension, and let V₂ be the volume of the 35% omeprazole suspension that we need to find.

The dilution equation states that the product of the starting volume and concentration (V₁ × C₁) and the end volume and concentration (V₂ × C₂) should be identical.

V₁ × C₁ = V₂ × C₂

Putting the given values:

0.7 L ×  8% = V₂  × 35%

0.056 L = V₂ × 35%

Dividing both sides by 0.35), get:

V₂ = 0.056 L / 0.35

V₂ = 0.16 L

Change 0.16 L to milliliters (ml):

0.16 L × 1000 ml/L = 160 ml

Thus, 160 ml of the 35% omeprazole suspension would be required for the dilution.

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When you mix two liquids, the reaction vessel suddenly feels cold. This observation suggests the temperature change, which is an exothermic reaction, can be felt by the reaction vessel.

The reaction that is occurring in this situation is most likely to be exothermic in nature. A decrease in temperature can occur due to evaporation of the liquid, and thus, the heat absorbed is taken from the environment, causing the vessel to feel cold. The cooling effect might also indicate that an endothermic reaction is occurring. The temperature change in an endothermic reaction is always negative.

As a result, the vessel would feel cold, this effect occurs when two liquids or substances react and absorb heat, resulting in a decrease in temperature. The reaction needs to take in heat from the surrounding environment in order to proceed, so heat is removed from the reaction vessel. This means that the temperature of the reaction vessel may become colder. So therefore Wwhen two liquids are mixed, the temperature change, which is an exothermic reaction, can be felt by the reaction vessel.

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The following observations can be made based on this information:

When two liquids are mixed, the reaction vessel suddenly feels cold.

The following observations can be made based on this information:

Energy is consumed when the two liquids are combined to create a new substance. This change in temperature is caused by an endothermic reaction. The difference in temperature can be explained by the energy absorbed or released during the chemical reaction.Temperature change provides proof that a chemical reaction has occurred. When two chemicals react, the reaction absorbs heat, which causes the temperature in the reaction vessel to drop. The reaction's temperature will rise if heat is produced during the reaction. This change in temperature is caused by an exothermic reaction.

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Answer:

The paper no longer has smooth edges

The paper has not produced gas when torn

The paper has not changed colours

The paper is still paper with the same chemical makeup

Answer:

\(\boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}\)

Explanation:

Given:

Mass of ferous (Fe) produced = 750 gram.

To find:

Mass of water produced= ?

Solution:

Molar mass of Fe is 55.84 gram/mol

Let's find out the number of moles of ferous produced.

\( \small \sf Number \: of \: moles = \frac{Given \: mass \: of \: substance }{Molar \: mass \: of \: substance} \)

Substituting the given data in above formula.

\( \small \sf Number \: of \: moles = \frac{750}{55.84} \)

\( \boxed{\small \sf Number \: of \: moles \: of \: Fe= 13.43 \: moles}\)

Now the given reaction is,

\(Fe_3O_4 + 4H_2 \rightarrow 3Fe + 4H_2O\)

now calculate the number of moles of H2O

\( \sf \: \frac{3}{4} = \frac{13.43}{x} \\ \sf x = \frac{13.43 \times 4}{3} \\ \sf x = 17.90 \: moles\)

\( \small \boxed{\sf number \: of \: moles \: of \: H_2O= 17.90 \: moles}\)

mass of one mole of H2O is 18 gram, so we can calculate mass of 17.90 moles.

\(\small \sf \: Mass \: of \: H_2O = 17.90 \times 18 \\ \boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}\)

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Answer:

The tissues decompose at a slower rate at lower temperatures.

Explanation:

This is my best guess but I think answer is tissue decompose slower rate at low temperature. This is why we in medicine we store specimens at very low temperature so we can do research on it at a later time but they eventually go bad. Low temperature slow down enzymes and proteins thus breakdown is slower rate.

Answer:

Hey mate.....

Explanation:

This is ur answer.....

Hope it helps!

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Answer:Group, in chemistry, a column in the periodic table of the chemical elements. In a group, the chemical elements have atoms with identical valence electron counts and identical valence vacancy counts. ... Groups are numbered from 1 to 18.

Explanation:Hope this helped u may i also get brainlist plz only if u wanna give me brainlist though have an great day!

Answer:

A group is a coulm with elements that share the same number of electons

Explanation:

Explanation:

The separation of gosoline from crude oil by heating until it reaches its boilling point is a separation technique called fractional distillation .It is the separation of a mixture such oil into their respect fraction.

Answer:

The answer is B, Distillation.

Explanation:

Answer:

The unit of Atomic mass is "amu"

Explanation:

Atomic mass unit

Answer:

45 km

Explanation:

To find the distance Tylee walked, multiply her speed by the time.

\(d=10(4.5)\)

\(d =45\)

The distance Tylee walked is 45 kilometers.

I hope this helped :)

Tylee walked 45 km from her parents' farm into town .

Speed can be understood as the measure of  how fast an object is moving.

It is the rate at which an object covers certain distance in fixed amount of time.

It is scalar quantity and its S.I. unit is m/sec .

\(\rm Speed = \dfrac{distance}{time}\)

It is given in the question speed = 10 km/h and time = 4.5 hr

So,

\(\rm Distance = Speed\; \times\;time\)

\(\rm Distance = 10\; \times\;4.5\\\\\rm Distance = 45 \;km\\\)

Therefore Tylee walked 45 km from her parents' farm into town .

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The illustration of Thomson's atom represents a neutral atom. In this case, the total amount of positive charge and the total amount of negative charge must be equal. This means that there are equal numbers of protons and electrons in the atom. This is what makes the atom neutral.

A neutral atom is an atom that has no electrical charge. An atom is neutral because it has the same amount of positively charged protons and negatively charged electrons. The nucleus of an atom contains protons, which are positively charged particles. Electrons, which are negatively charged particles, are located in the atom's electron cloud around the nucleus.

Electrons, protons, and neutrons are the three components of atoms. Electrons are negatively charged, protons are positively charged, and neutrons have no charge. Electrons are found outside the nucleus of the atom and are continually moving at high speeds.

In summary, if the illustration of Thomson's atom represents a neutral atom, then the total amount of positive charge and the total amount of negative charge must be equal. This means that there are equal numbers of protons and electrons in the atom. This is what makes the atom neutral.

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Answer:

Explanation:

Molecule of aluminium fluoride is more polar than molecule of aluminium chloride . It is so because fluorine is more electronegative than chlorine . On Pauling scale , the electronegativity of fluorine is 3.98 whereas that of chlorine is 3.16 . Hence in aluminium fluoride , there is stronger inter molecular bonding because of  more polar nature of molecules .  In aluminium chloride  , there is weaker  inter molecular bonding because of  comparatively  polar nature of molecules . Hence melting point of anhydrous aluminium fluoride is higher than that of anhydrous aluminium chloride .

Answer:

Metals

Explanation:

If the amount of tin deposited is 0.01 mol then 0.01 mol of copper can be deposited.

What is Faraday's second law of electrolysis?

According to Faraday's second law of electrolysis, the masses of ions deposited at the electrodes are inversely proportional to their chemical equivalents when the same amount of power is applied to various electrolytes.

According to the given question:

Two electrolytic cells are connected in series so that the same current flows through both cells for the same length of time.

The amount of tin deposited is 0.01 mol.

By second law of electrolysis,

W1 / W2 = E1 / E2

The same amount of charge is going to both electrolytic cells, and copper and tin have the same charge, so they require the same number of electrons to be discharged.

So, 0.01 mol of Cu can be deposited because the number of equivalents of Cu and SN are same as Cu and Sn carries +2 oxidation state only.

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The new temperature of the gas is 400 â—¦C.

To solve this problem, we can use the Ideal Gas Law, which states that PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Assuming that the pressure is constant in this scenario, we can rewrite the Ideal Gas Law as V/T = constant. This means that the ratio of volume to temperature is constant for a given amount of gas at constant pressure.

We are given that the initial volume is 5 L and the final volume is 10 L. Therefore, the ratio of initial volume to initial temperature is V1/T1 = 5/T1, and the ratio of final volume to final temperature is V2/T2 = 10/T2.

Since the ratio of volume to temperature is constant, we can set these two ratios equal to each other and solve for T2:
5/T1 = 10/T2
T2 = (10/5) x T1
T2 = 2 x 200 â—¦C
T2 = 400 â—¦C

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The rock containing 3 mg 40K. The half-life of 40K is 1.3 billion years. is approximately 3.0448172338 billion years old.

Half-life is a term used in nuclear physics to describe the time it takes for half of the atoms in a sample of a radioactive substance to decay. It is the amount of time required for the quantity of a substance to decrease by half its initial value.

Each radioactive substance has a unique half-life, which can range from fractions of a second to billions of years. The concept of half-life is important in many fields, including nuclear physics, geology, chemistry, and medicine, as it helps scientists understand how long it takes for radioactive materials to decay and how much radiation they emit over time.

The ratio of the remaining 40K to the initial amount of 40K is given by:

(3 mg) / (12 mg) = 0.25

Taking the natural logarithm of both sides of the equation and using the formula for the half-life, we get:

ln(0.25) = -0.693147 * t / (1.3 billion years)

Solving for t, we get:

t = -(1.3 billion years) * ln(0.25) / 0.693147

t ≈ 3.0448172338 billion years

Therefore, the rock is approximately 3.0448172338 billion years old.

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In this  following reaction,  Br2  reduced and Al is oxidized 2Al(s) + 3Br2(g) → 2ABr3(s)

Therefore,option a is correct: Al is oxidized and Br2 is reduced.

In the given reaction, aluminum (Al) is oxidized because it loses electrons and its oxidation state increases from 0 to +3. On the other hand, bromine (Br2) is reduced because it gains electrons and its oxidation state decreases from 0 to -1.

The product formed, aluminum bromide (AlBr3), has an oxidation state of +3 for Al and -1 for Br, which indicates that Al has undergone reduction and Br2 has undergone oxidation.

In the reaction 2Al(s) + 3Br2(g) → 2ABr3(s), aluminum (Al) and bromine (Br2) undergo oxidation-reduction reactions. Al is oxidized because it loses electrons and its oxidation state increases from 0 to +3. This can be seen by comparing the oxidation states of Al in the reactant (0) and product (+3). On the other hand, Br2 is reduced because it gains electrons and its oxidation state decreases from 0 to -1. This can be seen by comparing the oxidation states of Br in the reactant (0) and product (-1).

The product formed, aluminum bromide (AlBr3), has an oxidation state of +3 for Al and -1 for Br. This indicates that Al has undergone reduction and Br2 has undergone oxidation. In other words, Al has gained electrons while Br2 has lost electrons. This type of reaction is known as a redox reaction and it involves the transfer of electrons between reactants.

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In the context of the given options, the most appropriate choice is B. investment, as it aligns with the idea of committing money with the expectation of financial profit.

Money committed to something that is expected to produce a financial profit is called an investment. When you make an investment, you are allocating your funds into assets, projects, or ventures with the expectation of generating returns or profits over time. The goal of investing is to grow your wealth or generate income.

Investments can take various forms, such as stocks, bonds, real estate, mutual funds, or starting a business. Each investment carries a certain level of risk, and the potential for profit depends on factors like market conditions, economic trends, and the specific investment itself.

In contrast to an investment, a debt refers to money borrowed or owed by an individual or entity to another party. While debts can involve financial commitments, they are not necessarily associated with the expectation of generating a financial profit. Debt typically involves repayment of the borrowed amount along with interest or finance charges, which are not directly tied to investment returns.

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Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

The pH value of the resulting solution assume the volume of the solution is not affected by this addition is 3.283.

The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

In this Question, HF is a Weak Acid and RbF is a weak Base - HNO3  is a strong acid.

HF reaction in aqueous medium

HF +  H2O  --------- H3O+  + F -  

RbF +  H2O  ----  Rb+ +  F -

pH (Original)  =  pKa  +  log ( [salt ] / [Acid] )  

We donot need to calculate pH original -which is for the original solution before adding the strong acid.

HF is a weak acid - so in a buffer solution its dissociation is negligible - so it does not affect the H+  ion concentration much.

When a 0.012 mol of HNO3  is added to the buffer solution , it dissociates in H+ and NO-3  .

H+ ions dissociated from the Acid react with F -  and produce HF . As a result the acid concentration will increase to the extent of 0.012 mol  and the salt concentration reduces by the same extent - 0.012 mol.

So the formula for New pH changes to

pH (New)  =  pKa  +  log ( [salt ] - 0.012 mol / [Acid] + 0.012 mol)

Here , 0.012 mol are added to 281 mL solution,

Concentration of HNO3,  M = number of moles / Vol in litres  

                                            =  0.012 mol / 281 mL

                                            =  0.012 mol / 281  / 1000

                                           = [0.012 mol x 1000]  / 281 L  =  0.043 M

As pKa = -log(Ka)  ,  

Given  [salt ] =  0.480 M ,  [Acid] =  0.318 M

                   = - log(Ka) +  log [ (0.480 M - 0.043 M) / (0.318 M + 0.043 M) ]

                        =  - log (6.31 x 10-4 )   +  log ( 0.437 / 0.361)

      pH (New)    =  3.20 + 0.083  = 3.283.

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Complete question:

A biochemist wanted to adjust the pH of 281 mL of a buffer solution composed of 0.318 M HF and 0.480 M RbF (K, = 6.31e - 04) by adding 0.012 moles of HNO3. Determine the pH of the resulting solution: pH number (rtol=0.02, atol=1e-08)

Answer:

a. 5.82km

b. 7.2956cm

Explanation:

An increase in temperature will shift the equilibrium towards the left side of the reaction, which means more H2 and I2 will be formed at the expense of HI.

This is because the reaction is exothermic, which means it releases heat, and Le Chatelier's principle states that a system at equilibrium will shift in a way that counteracts any stress or change in conditions. In this case, an increase in temperature is a stress that the system will try to counteract by producing more of the reactants, H2 and I2, which will consume some of the excess heat.

When the temperature increases in the closed system containing the equilibrium reaction

H2(g) + I2(g) + heat ⇌ 2HI(g),

the equilibrium will shift in the direction that absorbs the added heat. In this case, the endothermic reaction (left to right) absorbs heat. Therefore, increasing the temperature will result in the formation of more HI(g), shifting the equilibrium to the left.

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A. \(1s^2 2s^2 2p^6 3s^2 3p^6\): This electrοn cοnfiguratiοn cοrrespοnds tο the nοble gas cοnfiguratiοn, which is typically οbserved fοr elements in Grοup 18 (Grοup 8A) such as helium (He), neοn (Ne), argοn (Ar), etc.

The electrοn cοnfiguratiοn οf an element describes hοw electrοns are distributed in its atοmic οrbitals. Electrοn cοnfiguratiοns οf atοms fοllοw a standard nοtatiοn in which all electrοn-cοntaining atοmic subshells (with the number οf electrοns they hοld written in superscript) are placed in a sequence. Fοr example, the electrοn cοnfiguratiοn οf sοdium is 1s22s22p63s1.

Tο match the elements with their cοrrespοnding electrοn cοnfiguratiοns οf the mοnatοmic iοns they are mοst likely tο fοrm, we need tο cοnsider the electrοn cοnfiguratiοns οf the iοns cοmmοnly οbserved fοr each element. Here are the matches:

B. \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^1\): This electrοn cοnfiguratiοn cοrrespοnds tο the alkali metal cοnfiguratiοn, which is typically οbserved fοr elements in Grοup 1 (Grοup 1A) such as lithium (Li), sοdium (Na), pοtassium (K), etc.

C. \(1s^2 2s^2 2p^4\): This electrοn cοnfiguratiοn cοrrespοnds tο the halοgen cοnfiguratiοn, which is typically οbserved fοr elements in Grοup 17 (Grοup 7A) such as fluοrine (F), chlοrine (Cl), brοmine (Br), etc.

D. \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2\): This electrοn cοnfiguratiοn cοrrespοnds tο the nοble gas cοnfiguratiοn, which is typically οbserved fοr elements in Grοup 2 (Grοup 2A) such as helium (He), neοn (Ne), argοn (Ar), etc.

E. \(1s^2\): This electrοn cοnfiguratiοn cοrrespοnds tο the hydrοgen iοn (H+), which has lοst its single electrοn tο fοrm a pοsitive iοn.

F. \(1s^2 2s^2 2p^6\): This electrοn cοnfiguratiοn cοrrespοnds tο the nοble gas cοnfiguratiοn, which is typically οbserved fοr elements in Grοup 18 (Grοup 8A) such as helium (He), neοn (Ne), argοn (Ar), etc.

G. \(1s^2 2s^2 2p^6 3s^2 3p^6\): This electrοn cοnfiguratiοn cοrrespοnds tο the nοble gas cοnfiguratiοn, which is typically οbserved fοr elements in Grοup 18 (Grοup 8A) such as helium (He), neοn (Ne), argοn (Ar), etc.

Sο the matches are:

A. Elements in Grοup 18 (Grοup 8A)

B. Elements in Grοup 1 (Grοup 1A)

C. Elements in Grοup 17 (Grοup 7A)

D. Elements in Grοup 2 (Grοup 2A)

E. Hydrοgen iοn (H+)

F. Elements in Grοup 18 (Grοup 8A)

G. Elements in Grοup 18 (Grοup 8A)

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\(\large\underline{\bf\red{Solution:-}}\)

The chemical property deals with the ability of a substance being able to burn is called combustibility [ option b ] .

More to know :-

1) Combustion :-

Combustion is a chemical process in which a substance reacts rapidly with oxygen and gives out heat.

The fuel can be any one of the 3 states of matter that is - solid , liquid & gases .

Examples of combustible substances :-

Solid - Coal

Liquid - Petrol , Disel , etc.

Gas - Hydrogen , Oxygen , etc .

Answer:

combust

Explanation:

did the test