A chemical reaction consumes water at a constant rate. The reaction started at 1:40pm. The mass of water
t
minutes after the reaction starts is
m(t)
grams. You are told
m(0)=48
and
m ′ (t)=−2
all the time. Show work for each part. (a) [2pts] Find the formula for the mass of water
m(t)=
grams (b) [1pts] How many grams of water remained at
1:45pm
? grams (c) [2pts] At what time did the reaction end ? (write an answer like
3:27
to mean 27 minutes past 3 )

Answer:

All are correct

Explanation:

This might be a little deceptive.  The question shows H, O and N which would designate ELEMENTS.

However, all of these can also be considered compounds and molecules as well.  BUT, they are H₂, O₂ and N₂ when they are molecules and compounds.

So it depends on the whether the question is being literal or not.

It's most likely that the circuit B is a series circuit while circuit A is a parallel circuit.

Circuits are basically two or more terminal components and electrical devices that is connected to each other. They can be connected in a series circuit or parallel circuit.

A series circuit is a circuit that connects its components using the same current flows. The current only has one path. Because of that, if one bulb fuses or removed, all the bulbs in the circuit won't light up.

A parallel circuit is a circuit that has multiple paths for the electric current to flow through. That makes the components have a constant voltage across all ends. Because of that, even if one bulb is removed, the other bulbs will stay lighted up.

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The number of mole present in 338 grams silver nitrate, AgNO₃ is 1.988 moles

We can obtain the number of mole present in 338 grams silver nitrate, AgNO₃ as illustrated below:

Number of mole is defined as:

Number of mole = mass / molar mass

Inputting the mass and molar mass of AgNO₃, we have:

Number of mole = mass / molar mass

Number of mole of AgNO₃ = 338 / 170

Number of mole of AgNO₃ = 1.988 moles

Thus, the number of mole of AgNO₃ present is 1.988 moles

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Find the \(pOH\) from \(pH\)

\(pH + pOH =14\\pOH= 14-pH = 14-12.37 = 1.63\)

The \(KSP\) value of \(ca(oh)^{2}\) is

\(ca(oh)^{2} -- > ca^{2} + (aq) +2OH^{-} \\ksp = 4s^{3}\)

The value finally becomes,

\(ksp = 5.15 * x=10^{-5}\)

A saturated solution is one that contains all of the solute that can possibly dissolve in it. The most sodium chloride that may dissolve in \(100 g\) of water at \(20\)°C is \(36.0 g\). Past that point, adding more \(NaCl\) won't cause it to dissolve because the solution is already saturated.

The solution reaches a point when it is saturated. This indicates that if you add more of the substance, it will stop dissolving and instead stay solid. The amount depends on how the solvent and solute interact molecularly.

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Answer:

Negatively charged ions are called anions, and an anion is formed when an atom gains an electron. Thus, the atom has an extra charge of electrons,

Explanation:

so it becomes negatively charged.

Negative ions (or anions) are atoms that have gained electrons.

Electrons have a negative charge so if an atom is getting more of them, it's becoming more negative.

Taking into account the definition of electronic configuration and the Aufbau principle, in an atom with the electron configuration of 1s²2s²2p⁶3s¹, there are 11 electrons.

The electronic configuration of elements is the arrangement of all the electrons of an element in energy levels and sublevels (orbitals).

There are 7 energy levels, numbered from 1 to 7, and in which the electrons are distributed, logically, in order according to their energy level. Electrons with less energy will spin at level 1.

Each level is divided into sublevels. These sublevels into which each level is divided can be up to 4. These 4 sublevels are called: s, p, d, f.

In the s sublevel there can only be a maximum of 2 electrons, in p there can be a maximum of 6 electrons, in the d sublevel 10 electrons and finally in the f sublevel there can be a maximum of 14 electrons.

At level 1 there is only one sublevel, which will be the s. In level 2 there are 2 sublevels, the s and the p. At level 3 there are 3 sublevels s, p and d. And in level 4 there are 4 sublevels, the s, the p, the d and the f.

The Aufbau principle is a principle of atomic physics, which explains how electrons arrange themselves in their orbits around the nucleus of the atom.

This principle states that the filling of these orbitals occurs in order of increasing energy, that is, from orbitals of lower energy to those of higher energy.

The simplest of the sublevels is 1. If you fill the 1s, you can start filling the 2s. Once the 2s sublevel is satisfied, the 2p can start filling, and so on.

In this case, in an atom with the electron configuration of 1s²2s²2p⁶3s¹, there are 2+2+6+1= 11 electrons.

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Answer:

1.) Elements: building blocks of the universe

2.) Atoms: basic blocks of all matter

3.) Molecules: is matter. Made of atoms

Answer:

Explanation:

1.) Elements: building blocks of the universe

2.) Atoms: basic blocks of all matter

3.) Molecules: is matter. Made of atoms

Use scientific notation to to express this quantity: 131. mg

Explanation:

131. mg has 3 SF

131. mg = 1.31 * 100 mg

131. mg = 1.31 * 10^2 mg

Answer: 1.31 * 10^2 mg

The present worth equivalent of these 8 cash flows is $713,196. The present worth equivalent of the 8 cash flows can be calculated by finding the present value of each individual cash flow and summing them up. The cash flows consist of an initial investment of $225,000 in year 1, followed by a gradient series of $90,000 in years 2, 3, and 4, and then a decreasing gradient series of $120,000 in years 5, 6, 7, and 8.

To calculate the present worth, we can use the formula for the present value of a cash flow:

PV = CF / (1 + r)^n

where PV is the present value, CF is the cash flow, r is the interest rate, and n is the time period.

Let's calculate the present worth of each cash flow:

PV1 = $225,000 / (1 + 0.09)^1 = $206,422.01814

PV2 = $90,000 / (1 + 0.09)^2 = $75,402.64076

PV3 = $90,000 / (1 + 0.09)^3 = $68,834.46298

PV4 = $90,000 / (1 + 0.09)^4 = $63,271.72223

PV5 = $120,000 / (1 + 0.09)^5 = $84,600.08664

PV6 = $120,000 / (1 + 0.09)^6 = $77,747.47778

PV7 = $120,000 / (1 + 0.09)^7 = $71,394.17768

PV8 = $120,000 / (1 + 0.09)^8 = $65,522.39315

Now, let's sum up the present values to find the present worth:

Present Worth = PV1 + PV2 + PV3 + PV4 + PV5 + PV6 + PV7 + PV8

             = $206,422.01814 + $75,402.64076 + $68,834.46298 + $63,271.72223 + $84,600.08664 + $77,747.47778 + $71,394.17768 + $65,522.39315

             = $713,195.97936

Therefore, the present worth equivalent of these 8 cash flows is $713,196.

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the present worth equivalent of these 8 cash flows is $1,477,041.

The present worth equivalent of the 8 cash flows can be calculated using the concept of present value. We need to discount each cash flow to its present value using the interest rate of 9% per year.

In year 1, the cash flow is $225,000. To calculate its present value, we divide it by (1 + interest rate)^1, which is (1 + 0.09)^1, resulting in a present value of $206,422.

In years 2, 3, and 4, the cash flow increases by $90,000 each year. To calculate their present values, we divide them by (1 + interest rate)^2, (1 + interest rate)^3, and (1 + interest rate)^4, respectively. The present values for these cash flows are $166,201, $129,402, and $100,888.

In years 5, 6, 7, and 8, the cash flow decreases by $120,000 each year. To calculate their present values, we divide them by (1 + interest rate)^5, (1 + interest rate)^6, (1 + interest rate)^7, and (1 + interest rate)^8, respectively. The present values for these cash flows are $314,027, $281,376, $252,586, and $227,139.

Finally, we add up all the present values to get the present worth equivalent of the 8 cash flows: $206,422 + $166,201 + $129,402 + $100,888 + $314,027 + $281,376 + $252,586 + $227,139 = $1,477,041.

Therefore, the present worth equivalent of these 8 cash flows is $1,477,041.

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To reduce camphor with NaBH4, you can follow these steps:

1. Dissolve the camphor in a suitable solvent such as methanol or ethanol. 2. Prepare a solution of NaBH4 in the same solvent, making sure to handle the reagent with care as it is a strong reducing agent. 3. Slowly add the NaBH4 solution to the camphor solution while stirring continuously. 4. The reaction will proceed quickly, and you should observe the solution becoming cloudy or forming a precipitate. 5. Allow the mixture to stir for a few more minutes to ensure complete reduction of the camphor. 6. After the reaction is complete, you can isolate the product by filtering the mixture and washing it with water or a suitable solvent to remove any impurities.

The reduction of camphor with NaBH4 is a complex chemical reaction that involves several steps and variables, including the choice of solvent, reaction conditions, and the stoichiometry of the reagents. Therefore, it's important to have a good understanding of the chemistry involved and to follow proper safety protocols when working with NaBH4.

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For the n = 5 level of hydrogen, there are five possible subshells. The subshells are labeled using letters: s, p, d, f, and so on.

The number of possible subshells for a given energy level can be determined using the formula 2n², where n represents the principal quantum number.

In this case, since n = 5, we can substitute it into the formula to find the result. Applying the formula, we have 2(5)² = 2(25) = 50. Thus, there are 50 possible orbitals or subshells within the n = 5 level.

However, it's important to note that hydrogen has only one electron, so it can occupy only one orbital at a time. Therefore, while there are 50 possible subshells in theory, only one electron will occupy the n = 5 level of hydrogen.

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To determine the empirical formula, we need to find the simplest whole-number ratio of atoms in the compound.

First, we find the total number of atoms in one molecule of the compound:

16 carbon atoms + 20 hydrogen atoms + 4 oxygen atoms + 0 nitrogen atoms = 40 atoms

Next, we divide each count by the greatest common factor to obtain the simplest whole-number ratio:

16 C atoms ÷ 4 = 4 C atoms

20 H atoms ÷ 4 = 5 H atoms

4 O atoms ÷ 4 = 1 O atom

0 N atoms ÷ 4 = 0 N atoms

Therefore, the empirical formula of the compound is C4H5O.

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\(\\ \sf{:}\longrightarrow 2,4-diethyl-2-methylpentane\)

The following statement is not true about lighteners- " They are used at relatively high levels'.

Skin lighteners are products that are designed and used to bleach the skin from dark spots and pigments. They are usually used to improve one's physical appearance such as blemishes, dark patches and birthmarks.

They work on the skin by reducing or slowly blocking the production of melanin in the skin. The pigment melanin is responsible for the colour it gives to our skin. It also protects our skin from the harmful effects of the sun.

It usually takes few weeks or even three to four months for lighteners to show effective results on continued usage.

Thus, option (a) is correct.

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This problem is providing a mathematical expression which the result should be expressed with the correct significant figures. At the end, the result is 1209.0 because of the following:

In science, the use of significant figures is crucial as long numbers are not necessarily required when reporting a numerical value, for that reason the importance of reporting measurements with the correct number of significant figures.

In the case of additions, we perform the normal operation as the first step:

1204.2 +4.79613 = 1208.99613

Next, we round the result to the least number of decimal places, in this case one because 1204.2 has just one decimal place, unlike the 4.79613 which has five, so that we round the 8 up to 9 and leave a 0 as the only decimal place:

1209.0

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Answer: D

Explanation:

I would say D, because it makes sense for the temperature to decrease with depth because less sunlight means less heat. I'm not sure about the salinity 100% but I think it increases.

(Don't mind me, answering it properly because brainly is being annoying)

Answer:

b)5l x 10kg  c)10kg + 9l   (Not sure for the last 1)

Here's link to the answer:

tinyurl.com/wpazsebu

Answer:

25 g

Explanation:

N/No = (1/2)^t/t1/2

N= amount of radioactive material at time t

No = amount of radioactive material initially present

t= time taken

t1/2 = half life of the radioactive material

Substituting values;

N/800 = (1/2)^80/16

N/800= (1/2)^5

N/800= 1/32

32N = 800

N= 800/32

N= 25 g

Answer:

the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

Explanation:

Given that :

a student dissolves 6.64 g of CoF₂  into 500 mL of water

volume of the solution(water) = 500 mL = 0.50 L

The standard  molar mass of CoF₂ is 96.93 g/mol

number of moles of CoF₂ = mass of CoF₂/molar mass of CoF₂

number of moles of CoF₂ = 6.64 g/96.93 g/mol

number of moles of CoF₂ = 0.0685 mol

The molarity of any given substance is known to be as the number of moles of solute dissolved in one litre of solution.

Thus ;

Molarity of  cobalt(II) fluoride CoF₂ in the resulting solution is = number of moles / Volume in (L)

Molarity of  cobalt(II) fluoride CoF₂  = 0.0685 mol/ 0.50 L

= 0.137  M

Thus ; the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

Vinegar has preservative and antimicrobial properties due to the ability of the active ingredient to cross the membrane as CH₃COOH. Once in the cytoplasm, it becomes Deprotonated.

Vinegar is a natural preservative. It enhances the microbiological safety and extending the life. Production of vinegar is a two step process , where yeasts convert sugars into alcohol, followed by acetobacter, which oxidise alcohol to acetic acid.

Vinegar is a crude acetic acid and possess antimicrobial properties, which kills microorganisms and enhance microbiological safety of food.

Deprotonated simply means the removal of a proton from a chemical compound. The acetic acid in vinegar cross the membrane and become deprotonated, i.e., removal of proton in the cytoplasm which disturbs the normal pH.

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Half life for remaining 5 days is 80. e-0.25 .

Half life period is the time needed by a radioactive substances to transform into a different substance. It is the interval of time required for the one half of the atomic nuclei of a radioactive sample to decay. Half life is calculated by finding the decay constant of a substance then dividing it by 2. Decay constant of a radioactivity is probability of decay per unit time.

Here half life 32P is 5 days.

The concentration of the radioactive isotope is the total amount of radioactivity per unit volume. The expression for calculating concentration of radioactive isotope  at half life is ,

    [A] = [A] e-kt

t1/2= 0.693/K

K= 0.693/ t1/2=0.05days

Now substituting value of K and t in the expression

[A]= [A]e-kt

    = 80 .e-0.25

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Answer:

A: electrons

Explanation:

1) The periodic table could be arranged;

a) in terms of groups and periods

b) In terms of metals and non metals

c)In terms of blocks to which elements belong

d) In terms of reactivity of the elements

2a) Metals are more reactive based on how easily they donate electrons

2b) Non metals are more reactive based on how easily they accept electrons.

In the periodic table we have the arrangement of elements and these elements do not all combine with each other in the same way. We know that the metals are the elements that we see towards the left hand side while the non metals are seen towards the right hand side.

Metals are more reactive if they are able to loose electrons easily while the nonmetals are more reactive if they are able to gain electrons more easily. Thus the loss and gain of electrons is what determines reactivity.

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The colonies on the surface of the pour plate differ from those suspended in the agar in terms of their location and growth pattern.

In a pour plate technique used in microbiology, a diluted microbial sample is mixed with liquefied agar, and the mixture is poured into a petri dish. As the agar solidifies, the microorganisms become trapped within the agar, resulting in two different types of colonies: those on the surface and those suspended in the agar.

Colonies on the surface of the pour plate:

Colonies suspended in the agar:

The colonies on the surface of the pour plate are located on top of the solidified agar, have easier access to oxygen, and may exhibit different characteristics compared to colonies suspended within the agar. Colonies within the agar are dispersed at different depths, may have limited oxygen access, and may appear smaller or less pigmented.

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Answer:

An acid and a base.

Explanation:

An acid and a base, combine to form the products salt and water

That is,

Acid + Base ----> Salt + water.

Answer:

Acid and base

The equation of what happens when iron (III) hydroxide is placed in water is: \(Fe (OH)_3 (s) --- > Fe^{3+} (aq) + 3OH^- (aq)\)

Iron (III) hydroxide is a salt that is sparingly soluble when placed in water. This is unlike many salts that are either soluble or insoluble in water.

Because of the partial solubility of iron (III) hydroxide in water, an equilibrium is created between the salt and its ionic component. The equation is as follows:

\(Fe (OH)_3 (s) < --- > Fe^{3+} (aq) + 3OH^- (aq)\)

In this equilibrium state, a host of factors exist that could shift the equilibrium to the left or to the right. For example, as more and more salt is added to the water, more of the ionic components are formed.

One other factor that could cause a shift in the equilibrium is temperature. The higher the temperature, the higher the solubility and the more the ionic components that are formed.

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The new volume is mathematically given as

V2= 16.12 L

Question Parameters:

A sample of gas has an initial volume of 20 L

and an initial pressure of 2.5 atm.

If the pressure changes to 3.1 atm

Generally, the equation for Pressure   is mathematically given as

P1V1 = P2 V2

2.5 * 20 = 3.1 * V2

V2 = 50/3.1

V2= 16.12 L

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Answer:

The s-block and p-block together are usually considered main-group elements, the d-block corresponds to the transition metals, and the f-block encompasses nearly all of the lanthanides (like lanthanum) and the actinides (like actinium).

Explanation: