The area of the given circle is 616 sq.cm.
The volume of rectangular prism is 416 mm³
What is a circle?A circle is a particular type of ellipse when the eccentricity is zero and both foci are present. The locus of points drawn equally apart from the centre is also referred to as a circle. The radius of a circle is the separation between its centre and its periphery. The circle's diameter, which is equal to twice its radius, is the line that splits the circle into two equal pieces.
What is area of circle?Area of a circle is the region occupied by the circle in a two-dimensional plane. It can be determined easily using a formula, A = πr2, (Pi r-squared) where r is the radius of the circle. The unit of area is the square unit, such as m², cm², etc.
Area of Circle = πr² or πd²/4, square units
where π = 22/7 or 3.14
according to question,
Area = pi times the radius squared
A = pi * r²
A = 22/7 * 14²
A = 22/7 * 196
A = 4,312 / 7
A = 616 sq. cm.
V = l*w*h
To determine the volume, multiply all three dimensions together.
For Connexus users Rectangular prisms and volume quiz part 2:
l * w * h = 8 * 5 * 10.4 = 416
the volume of rectangular prism is 416 mm³
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by considering the curve traced by the parametrisation z(t) = t 2 it3 with −1 ≤ t ≤ 1, show why the condition that z ′ (t) never vanishes is necessary to ensure that smooth curves have no cusps.
To ensure that smooth curves have no cusps, we need to require that z'(t) never vanishes. This condition ensures that the tangent line to the curve changes smoothly and continuously as we move along the curve, without any abrupt changes in direction that would create cusps.
To understand why the condition that z'(t) never vanishes is necessary to ensure that smooth curves have no cusps, we first need to understand what a cusp is. A cusp is a point on a curve where the tangent line changes direction abruptly, creating a sharp point or corner in the curve.
Now, let's consider the curve traced by the parametrization z(t) = t^2it^3 with -1 ≤ t ≤ 1. To determine whether this curve has any cusps, we need to calculate the derivative of z(t) with respect to t:
z'(t) = 2it^3 + 3t^2i
If we set z'(t) equal to zero and solve for t, we get:
2it^3 + 3t^2i = 0
t^2(2i t + 3i) = 0
This equation has two solutions: t = 0 and t = -3/2i. These are the points on the curve where z'(t) vanishes.
At t = 0, the curve passes through the origin, which is a smooth point. However, at t = -3/2i, the curve has a cusp. To see why, we can look at the behavior of z(t) near this point.
As t approaches -3/2i from either side, the magnitude of t^2 increases without bound, while the magnitude of t^3 remains constant. This means that z(t) approaches infinity along a straight line with slope -3/2i. In other words, the curve has a sharp corner or cusp at this point.
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gof)(6)
A. Find f(6)
B. substitute the value of g(x) into the function f(x) in place of x to find the value of f(g(x))
The value of the composite function (g o f)(6) is 3
How to evaluate the composite functionFrom the question, we have the following parameters that can be used in our computation:
f(x) = 2x + 3
g(x) = 1/5x
A. Find f(6)
substitute the known values in the above equation, so, we have the following representation
f(6) = 2 * 6 + 3
So, we have
f(6) = 15
For the function (gof)(6), we have
g(x) = 1/5x
This gives
(g o f)(6) = 1/5 * 15
Evaluate
(g o f)(6) = 3
Hence, the composite function has a solution of 3
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Complete question
Given that f(x) = 2x + 3 and g(x) = 1/5x
Compute (gof)(6)
A. Find f(6)
B. substitute the value of g(x) into the function f(x) in place of x
2) A 100 cubic centimeter (c * m ^ 3) sample of soil has an initial weight of 225.1 gramsIt is oven dried at 105 deg * C to a constant weight of 220.0 gramsThe sample is then with water and has a weight of 234.6 grams. Next, the sample is then allowed to drain by gravity in an environment of 100% humidity and is reweighted at 222.4 grams. Assuming that 1c * m ^ 3 of water = 1 gram at 15.5°C:
a) Calculate the porosity;
b) Calculate the specific yield; 5y / (v/(Le)) c) Calculate the specific retention
d) Calculate the void ratio;
e) Calculate the initial moisture content;
f) Calculate the initial degree of saturation.
For the sample of soil given a) the porosity is 100.4%; b) the specific yield is 12.2%; c) the specific retention is 14.6%; d) the void ratio is 0.5342; e) the initial moisture content is 2.3%; and f) the initial degree of saturation is 41.97%.
a) The porosity of soil can be defined as the ratio of the void space in the soil to the total volume of the soil.
The total volume of the soil = Initial volume of soil = 100 c.m³
Weight of water added to the soil = 234.6 g – 220 g = 14.6 g
Volume of water added to the soil = 14.6 c.m³
Volume of soil occupied by water = Weight of water added to the soil / Density of water = 14.6 / 1 = 14.6 c.m³
Porosity = Void volume / Total volume of soil
Void volume = Volume of water added to the soil + Volume of voids in the soil
Void volume = 14.6 + (Initial volume of soil – Volume of soil occupied by water) = 14.6 + (100 – 14.6) = 100.4 c.m³
Porosity = 100.4 / 100 = 1.004 or 100.4%
Therefore, the porosity of soil is 100.4%.
b) Specific yield can be defined as the ratio of the volume of water that can be removed from the soil due to the gravitational forces to the total volume of the soil.
Specific yield = Volume of water removed / Total volume of soil
Initially, the weight of the oven dried soil is 220 g. After allowing it to drain by gravity, the weight of soil is 222.4 g. Therefore, the weight of water that can be removed by gravity from the soil = 234.6 g – 222.4 g = 12.2 g
Volume of water that can be removed by gravity from the soil = 12.2 c.m³
Specific yield = 12.2 / 100 = 0.122 or 12.2%
Therefore, the specific yield of soil is 12.2%.
c) Specific retention can be defined as the ratio of the volume of water retained by the soil due to the capillary forces to the total volume of the soil.
Specific retention = Volume of water retained / Total volume of soil
Initially, the weight of the oven dried soil is 220 g. After adding water to the soil, the weight of soil is 234.6 g. Therefore, the weight of water retained by the soil = 234.6 g – 220 g = 14.6 g
Volume of water retained by the soil = 14.6 c.m³
Specific retention = 14.6 / 100 = 0.146 or 14.6%
Therefore, the specific retention of soil is 14.6%.
d) Void ratio can be defined as the ratio of the volume of voids in the soil to the volume of solids in the soil.
Void ratio = Volume of voids / Volume of solids
Initially, the weight of the oven dried soil is 220 g. The density of solids in the soil can be calculated as,
Density of soil solids = Weight of oven dried soil / Volume of solids
Density of soil solids = 220 / (100 – (14.6 / 1)) = 2.384 g/c.m³
Volume of voids in the soil = (Density of soil solids / Density of water) × Volume of water added
Volume of voids in the soil = (2.384 / 1) × 14.6 = 34.8256 c.m³
Volume of solids in the soil = Initial volume of soil – Volume of voids in the soil
Volume of solids in the soil = 100 – 34.8256 = 65.1744 c.m³
Void ratio = Volume of voids / Volume of solids
Void ratio = 34.8256 / 65.1744 = 0.5342
Therefore, the void ratio of soil is 0.5342.
e) Initial moisture content can be defined as the ratio of the weight of water in the soil to the weight of oven dried soil.
Initial moisture content = Weight of water / Weight of oven dried soil
Initial weight of soil = 225.1 g
Weight of oven dried soil = 220 g
Therefore, the weight of water in the soil initially = 225.1 – 220 = 5.1 g
Initial moisture content = 5.1 / 220 = 0.023 or 2.3%
Therefore, the initial moisture content of soil is 2.3%.
f) Initial degree of saturation can be defined as the ratio of the volume of water in the soil to the volume of voids in the soil.
Initial degree of saturation = Volume of water / Volume of voids
Volume of water = Weight of water / Density of water
Volume of water = 14.6 / 1 = 14.6 c.m³
Volume of voids in the soil = 34.8256 c.m³
Initial degree of saturation = 14.6 / 34.8256 = 0.4197 or 41.97%
Therefore, the initial degree of saturation of soil is 41.97%.
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the average number of calls that arrived between 8:00 am and 8:10 am during the working days of any month is: select one: a. a population. b. a sample. c. a parameter. d. a statistic.
the average number of calls that arrived between 8:00 am and 8:10 am during the working days of any month is Option(c) a parameter.
What are parameters?A parameter is a special type of mathematical variable. An equation that uses parametric variables that can have multiple values is referred to as a parametric equation. Parameter values are kept constant when using the function. Statisticians use parameters to estimate population characteristics numerically.
Parameters can be used in a variety of ways in real-life scenarios, including in statistics. Parameters are estimations of populations in statistics. The mean and standard deviation are two of the most common statistical parameters. In various statistical tests, these estimates are used to calculate the test statistic.
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Coach Carpenter and Mrs. Dyson each have a KPOP collection. For every five
pieces of BTS merchandise, they have two pieces of merchandise from another
group. If Mrs. Dyson has 38 pieces of BTS merchandise, about how many pieces of
merchandise can you expect her to have from other groups?
Answer:
approx 14 merchandise..........
(a) Find the Fourier transform X (jw) of the signals x(t) given below: i. (t – 2) – 38(t – 3) ii. e-2t u(t) iii. e-3t+12 uſt – 4) (use the result of ii.) iv. e-2|t| cos(t) (b) Find the inverse Fourier transform r(t) of the following functions X(jw): i. e-j3w + e-jów ii. 27 8W - 2) + 210(w + 2) iii. cos(w + 4 7T )
i. The Fourier transform of (t - 2) - 38(t - 3) is [(jw)^2 + 38jw]e^(-2jw). ii. The Fourier transform of e^(-2t)u(t) is 1/(jw + 2). iii. The Fourier transform of e^(-3t+12)u(t-4) can be obtained using the result of ii. as e^(-2t)u(t-4)e^(12jw). iv. The Fourier transform of e^(-2|t|)cos(t) is [(2jw)/(w^2+4)].
i. To find the Fourier transform of (t - 2) - 38(t - 3), we can use the linearity property of the Fourier transform. The Fourier transform of (t - 2) can be found using the time-shifting property, and the Fourier transform of -38(t - 3) can be found by scaling and using the frequency-shifting property. Adding the two transforms together gives [(jw)^2 + 38jw]e^(-2jw).
ii. The function e^(-2t)u(t) is the product of the exponential function e^(-2t) and the unit step function u(t). The Fourier transform of e^(-2t) can be found using the time-shifting property as 1/(jw + 2). The Fourier transform of u(t) is 1/(jw), resulting in the Fourier transform of e^(-2t)u(t) as 1/(jw + 2).
iii. The function e^(-3t+12)u(t-4) can be rewritten as e^(-2t)u(t-4)e^(12jw) using the time-shifting property. From the result of ii., we know the Fourier transform of e^(-2t)u(t-4) is 1/(jw + 2). Multiplying this by e^(12jw) gives the Fourier transform of e^(-3t+12)u(t-4) as e^(-2t)u(t-4)e^(12jw).
iv. To find the Fourier transform of e^(-2|t|)cos(t), we can use the definition of the Fourier transform and apply the properties of the Fourier transform. By splitting the function into even and odd parts, we find that the Fourier transform is [(2jw)/(w^2+4)].
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darcie wants to add the ribbon shown along the diagonal of the rectangular flag she is designing does darcy have enough ribbon explain
Answer:
Step-by-step explanation:
8.5 = √72.25
√72.25 < √74
Which is the better buy? (18 points)
7-pack of T-shirts for $23.02
8-pack of T-shirts for $26.72
Answer: 7 Pack
Step-by-step explanation: Divide each price by the number of shirts :)
Find the general solution of the following differential equation. Primes denote derivatives with respect to x. (x+y)y' = 9x-y The general solution is (Type an implicit general solution in the form F(x,y) = C, where C is an arbitrary constant. Type an expression using x and y as the variables.)
The general solution of the given differential equation is:
(x^2 + y^2) = C, where C is an arbitrary constant.
To solve the given differential equation, we can start by rearranging the terms:
(x+y)y' = 9x - y
Expanding the left-hand side using the product rule, we get:
xy' + y^2 = 9x - y
Next, let's isolate the terms involving y on one side:
y^2 + y = 9x - xy'
Now, we can observe that the left-hand side resembles the derivative of (y^2/2). So, let's take the derivative of both sides with respect to x:
d/dx (y^2/2 + y) = d/dx (9x - xy')
Using the chain rule, the right-hand side can be simplified to:
d/dx (9x - xy') = 9 - y' - xy''
Substituting this back into the equation, we have:
d/dx (y^2/2 + y) = 9 - y' - xy''
Integrating both sides with respect to x, we obtain:
y^2/2 + y = 9x - y'x + g(y),
where g(y) is the constant of integration.
Now, let's rearrange the equation to isolate y':
y'x - y = 9x - y^2/2 - g(y)
Separating the variables and integrating, we get:
∫(1/y^2 - 1/y) dy = ∫(9 - g(y)) dx
Simplifying the left-hand side, we have:
∫(1/y^2 - 1/y) dy = ∫(1/y) dy - ∫(1/y^2) dy
Integrating both sides, we obtain:
-ln|y| + 1/y = 9x - g(y) + h(x),
where h(x) is the constant of integration.
Combining the terms involving y and rearranging, we have:
-y - ln|y| = 9x + h(x) - g(y)
Finally, we can express the general solution in the implicit form:
(x^2 + y^2) = C,
where C = -g(y) + h(x) is the arbitrary constant combining the integration constants.
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Find the product of the three monomials
i. 9ab2 c 5, 2a3b 2 c 2 and 5abc2
ii. xy2, x2 y and xy
iii. 5x5, y2 x 5 and 10xyz
iv. (-4b2 c), (-2bc) and 10c2b
v. Multiply (-5m2n 2) by (-6m3n 5)
The products of the given monomials are
i. 90a⁵b⁵c⁹
ii. x⁴y⁴
iii. 50x¹¹y³z
iv. 80b⁴c⁴
v. 30m⁵n⁷
Product of monomialsFrom the question, we are to determine the products of each of the three monomials
i. 9ab²c⁵, 2a³b²c² and 5abc²
9ab²c⁵ × 2a³b²c² × 5abc²
= 9 × 2 × 5 × a × a³ × a × b² × b² × b × c⁵ × c² × c²
= 90 × a⁵ × b⁵ × c⁹
= 90a⁵b⁵c⁹
ii. xy², x²y and xy
xy² × x²y × xy
= x × x² × x × y² × y × y
= x⁴ × y⁴
= x⁴y⁴
iii. 5x⁵, y²x⁵ and 10xyz
5x⁵ × y²x⁵ × 10xyz
= 5 × 10 × x⁵ × x⁵ × x × y² × y × z
= 50 × x¹¹ × y³ × z
= 50x¹¹y³z
iv. (-4b²c), (-2bc) and 10c²b
(-4b²c) × (-2bc) × 10c²b
= -4b²c × -2bc × 10c²b
= -4 × b² × c × -2 × b × c × 10 × c² × b
= -4 × -2 × 10 × b² × b × b × c × c × c²
= 80 × b⁴ × c⁴
= 80b⁴c⁴
v. Multiply (-5m²n²) by (-6m³n⁵)
(-5m²n²) × (-6m³n⁵)
= -5m²n² × -6m³n⁵
= -5 × m² × n² × -6 × m³ × n⁵
= -5 × -6 × m² × m³ × n² × n⁵
= 30 × m⁵ × n⁷
= 30m⁵n⁷
Hence, the products of the given monomials are
i. 90a⁵b⁵c⁹
ii. x⁴y⁴
iii. 50x¹¹y³z
iv. 80b⁴c⁴
v. 30m⁵n⁷
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the picture below shows the shape of a design painted on the side of a building. The design was formed by combining triangles and rectangles.
What is the area of the wall covered by the design?
Therefore , the solution of the given problem of surface area comes out to be 212 square feet of the wall are therefore covered by the design.
What exactly does an area mean?The total size of the object can be determined by calculating how much room would be required to completely cover its exterior. When choosing a similar product with a cylindrical form, the environment is taken into account. Anything's total dimensions are determined by its surface area. The amount of water that a cuboid can hold depends on the number of sides that link its four trapezoidal shapes.
Here,
We must first determine the area of each individual form before adding them together to determine the portion of the wall that the design covers.
Taking a look at the rectangle first, we can observe that it has the following area:
=> 120 square feet= 10 feet x 12 feet.
=> 40 square feet = (1/2)(10 ft)(8 ft).
Consequently, the two triangles' combined area is:
=> 80 square feet = 2 x 40 square feet.
=> (12 square feet) = (1/2)(6 ft)(4 ft).
The total area of all the shapes is as follows:
=> 212 square feet= 120 square feet, 80 square feet, and 12 square feet.
=> 212 square feet of the wall are therefore covered by the design.
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Answer: the answer is 261 ^2 ft!
Step-by-step explanation:
Covert. 45 mi/h = __ ft/s
Answer:
45 mi/h = 66 feet per second
Logan and Rita each open a savings
account with a deposit of $8,100.
Logan's account pays 5% simple
interest annually. Rita's account pays
5% interest compounded annually. If
Logan and Rita make no deposits or
withdrawals over the next 4 years,
what will be the difference in their
account balances?
A $104. 05
B $113. 22
C $125. 60
D $134. 89
The difference in Logan and Rita's account balances after 4 years will be $113.22. To calculate the difference in their account balances, find the future value of their deposits using the given interest rates.
For Logan's account, which pays simple interest, we can use the formula: Future Value = Principal + (Principal x Rate x Time).
Given:
Principal (P) = $8,100
Rate (R) = 5% = 0.05 (expressed as a decimal)
Time (T) = 4 years
Future Value of Logan's account = 8,100 + (8,100 x 0.05 x 4)
= 8,100 + 1,620
= $9,720
For Rita's account, which pays compound interest annually, we can use the formula: Future Value = Principal x\((1 + Rate)^Time\).
Given:
Principal (P) = $8,100
Rate (R) = 5% = 0.05 (expressed as a decimal)
Time (T) = 4 years
Future Value of Rita's account = 8,100 x \((1 + 0.05)^4\)
= 8,100 x 1.21550625
= $9,833.50
The difference in their account balances = Future Value of Rita's account - Future Value of Logan's account
= 9,833.50 - 9,720
= $113.22
Therefore, the difference in their account balances after 4 years will be $113.22.
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Fill in the missing number. % of 98 = 49
50%
since 98/2 = 49
Thats it
MARK ALL THAT ARE TRUE!! We can use the Normal (Z) table to find probabilities about:
You must choose all five correct statements to get credit.
A. individuals, if the population is Normal
B. individuals, if the population is NOT Normal
C. averages based on small n, if the population is Normal
D. averages based on small n, if the population is NOT Normal
E. averages based on large n, if the population is Normal
F. averages based on large n, if the population is NOT Normal
G. count of successes out of n independent trials
H. sample proportion of successes out of n independent trials, when np and n(1-p) is large enough
Options A , C , E , F , H are true for the statement population that is finding the probability.
Given that,
We have to choose the correct answer for the given statement that is finding the probability.
We know that,
What is probability?Calculating a situation's probability allows us to determine its probability. Many things are difficult to determine with 100% accuracy. We can only anticipate the probability of an event occurring, or how likely it is, using it. A probability can be range 0 and 1, where 0 indicates an impossibility and 1 indicates a certainty. The probability of each event in a sample space is one.
Therefore, Options A , C , E , F , H are true for the statement population that is finding the probability.
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The distribution of retirement age for NFL players is normally distributed with a mean of 33 years old and a standard deviation of about 2 years. What is the percentage of players whose age is less than 31? a 30.85% b 15.87% c 71.2% d 69.15%
The correct answer is b) 15.87%, indicating that approximately 15.87% of NFL players have a retirement age less than 31 years old.
To find the percentage of players whose age is less than 31, we can use the standard normal distribution and z-scores.
First, we need to calculate the z-score for the value 31 using the formula:
z = (x - μ) / σ
where x is the value we want to find the percentage for, μ is the mean, and σ is the standard deviation.
In this case, x = 31, μ = 33, and σ = 2. Plugging these values into the formula, we get:
z = (31 - 33) / 2 = -1
Next, we can look up the cumulative probability associated with the z-score -1 in the standard normal distribution table. The cumulative probability represents the percentage of values that are less than the given z-score.
From the standard normal distribution table, the cumulative probability for z = -1 is approximately 0.1587, which corresponds to 15.87%.
Therefore, the correct answer is b) 15.87%, indicating that approximately 15.87% of NFL players have a retirement age less than 31 years old.
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Curtis estimates that he can run 18 mph. About how many feet per second can Curtis run if there are 5280 feet in a mile?
Answer:26.4 feet per second
Step-by-step explanation:
Answer:
26.4 fps (feet per second)
Step-by-step explanation:
edward has 20 coins made up of quarters and nickels. if he has $3.40 total, how many of each coin does he have?
Edward has 12 coins of the quarter and 8 coins of nickel with him
Total number of coins = 20
The total amount of money = $3.40
Let x represent the number of quarters and y represent the number of nickels
Formulating the equations we get:
x + y = 20-------(1)
0.25x + 0.05y = 3.40
Simplifying by removing the decimals and solving
25x + 5y = 340------(2)
Multiplying equation (1) by 5 and subtracting with equation (2) we get the following:
5x + 5y = 100
25x + 5y = 340
= 20x = 240
x = 12
So, y = 8
So, the number of quarters is 12 and the number of nickels is 8
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In the diagram, if ⊥l⊥m, which statement is NOT correct?
Given,
The diagram of the angles is shown above in the question.
Required
The incorrect statement for the angles.
The angles are of 90 degree as it is given.
So, statement b, c and d is correct.
Here, angles are not perpendicular, sides can be perpenicular to each other.
Hence, statement a is incorrect.
The triangle below has an area of 10 units squared.
Answer:
x = 5 units
Step-by-step explanation:
area = 1/2bh
10 = 1/2(x)4)
2x = 10
x = 5
Answer:
The value of x (which is also the height of this triangle) is x = 5 units.
Step-by-step explanation:
The formula for the area of a triangle of base b and height h is
A = (1/2)(b)(h).
Here A = 10 units² = (1/2)(4 units)(x).
Multiplying both sides by 2 yields 20 units² = (4units)(x), and thus 20 units²
Refer to the figure.
Name a line that intersects the plane containing points Q, N, and P.
a. Line S or RO
b. Line j or MT
c. Line h or RT
d. Line g or PN
Answer:
b. line j or MT
Step-by-step explanation:
as the plane contains the points Q, N, P, R, T also the lines connecting only these points are in the plane, and are not intersecting the plane.
only M is outside of the plane, and so (only) the connecting line MT intersects the plane (at point T).
by the way, the question means the line RQ and not RO, as there is no point O in the graphic.
Define the dummy random variable which takes on the value 1 when the number on first dice is either 1,2 or 3 and takes on the value 0 otherwise. Define a second dummy random variable which takes on the value 1 when the number on the second dice is either 3, 4, 5 or 6 and takes on the value of 0 otherwise. and are independent. True or false
True, the joint probability of Y1 and Y2 taking on the value 1 simultaneously is 1/3.
The first dummy random variable is defined as follows:
Let X be the random variable representing the number on the first dice. Then, the dummy random variable Y1 is defined as:
Y1 = 1 if X is either 1, 2, or 3
Y1 = 0 otherwise
Similarly, the second dummy random variable is defined as:
Let Z be the random variable representing the number on the second dice. Then, the dummy random variable Y2 is defined as:
Y2 = 1 if Z is either 3, 4, 5, or 6
Y2 = 0 otherwise
Since Y1 and Y2 are independent, their joint probability distribution can be computed by multiplying their marginal probabilities.
P(Y1=1, Y2=1) = P(Y1=1) * P(Y2=1)
To compute P(Y1=1), we need to find the probability that X is either 1, 2, or 3. Since each face of a fair dice has an equal probability of appearing, we have:
P(X=1) = P(X=2) = P(X=3) = 1/6
Therefore,
P(Y1=1) = P(X=1 or X=2 or X=3) = P(X=1) + P(X=2) + P(X=3) = 3/6 = 1/2
Similarly, to compute P(Y2=1), we need to find the probability that Z is either 3, 4, 5, or 6. Again, since each face of a fair dice has an equal probability of appearing, we have:
P(Z=3) = P(Z=4) = P(Z=5) = P(Z=6) = 1/6
Therefore,
P(Y2=1) = P(Z=3 or Z=4 or Z=5 or Z=6) = P(Z=3) + P(Z=4) + P(Z=5) + P(Z=6) = 4/6 = 2/3
Thus,
P(Y1=1, Y2=1) = P(Y1=1) * P(Y2=1) = (1/2) * (2/3) = 1/3
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Problems 1- 14, use the rules of differentiation to find the derivative of the function. 1. y = 14; 2. y=x^9+3 tan x; 3. y = 1/x^4-4cos x
1 . y'=0 is the derivative of the function y = 14.
2. y' = 9\(x^8\)+3\(sec^2x\) is the derivative of the function y= \(x^9\)+3tanx
3. y' = \(\frac{-4}{x^5}\) + 4sinx is the derivative of the function y = \(\frac{1}{x^4}\) - 4cos x
1 . The derivative of a constant is always zero.
A constant function is a function whose value does not depend on the input value.
So y = 4 is a constant function, its derivative is always zero.
So the derivative of y=4 is 0
2. The differentiation of \(x^9\)+3tanx is 9\(x^8\)+3\(sec^2x\)
The power rule states that the derivative of x^n (where n is a constant) is nx^(n-1). So the derivative of x^9 is 9x^8.
The derivative of tanx is \(sec^2x\).
And the derivative of 3tanx is 3\(sec^2x\)
So, \(x^9\)+3tanx is differentiated as9\(x^8\)+3\(sec^2x\)
3. The derivative of y = \(\frac{1}{x^4}\) - 4cos x can be found using the power rule and the chain rule.
The power rule states that the derivative of x^n (where n is a constant) is nx^(n-1). In this case, \(\frac{1}{x^4}\) can be rewritten as \(\frac{1}{x^4}\) and the derivative would be -4 \(\frac{1}{x^5}\)
The chain rule states that the derivative of (f(g(x)) is f'(g(x))*g'(x). In this case, the inner function is -4cos x, the derivative of cos x is -sin x and the outer function is , \(\frac{1}{x^4}\) the derivative of that is -4 \(\frac{1}{x^5}\). So the derivative of -4cos x is -4(-sin x)
So the final derivative of y = \(\frac{1}{x^4}\) - 4cos x is \(\frac{-4}{x^5}\) + 4sinx
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2. Solve the following difference equations: (a) \( x_{t+1}=\frac{1}{2} x_{t}+3 \) (b) \( x_{t+1}=-3 x_{t}+4 \)
(a) ( x_{t+1}=\frac{1}{2} x_{t}+3 ), the solution to this difference equation is x_t = 2^t + 3, The difference equations in this problem are both linear difference equations with constant coefficients.
This can be found by solving the equation recursively. For example, the first few terms of the solution are
t | x_t
--- | ---
0 | 3
1 | 7
2 | 15
3 | 31
The general term of the solution can be found by noting that
x_{t+1} = \frac{1}{2} x_t + 3 = \frac{1}{2} (2^t + 3) + 3 = 2^t + 3
(b) ( x_{t+1}=-3 x_{t}+4 )
The solution to this difference equation is
x_t = 4 \cdot \left( \frac{1}{3} \right)^t + 4
This can be found by solving the equation recursively. For example, the first few terms of the solution are
t | x_t
--- | ---
0 | 4
1 | 5
2 | 2
3 | 1
The general term of the solution can be found by noting that
x_{t+1} = -3 x_t + 4 = -3 \left( 4 \cdot \left( \frac{1}{3} \right)^t + 4 \right) + 4 = 4 \cdot \left( \frac{1}{3} \right)^t + 4
The difference equations in this problem are both linear difference equations with constant coefficients. This means that they can be solved using a technique called back substitution.
Back substitution involves solving the equation recursively, starting with the last term and working backwards to the first term.
In the first problem, the equation can be solved recursively as follows:
x_{t+1} = \frac{1}{2} x_t + 3
x_t = \frac{1}{2} x_{t-1} + 3
x_{t-1} = \frac{1}{2} x_{t-2} + 3
...
x_0 = \frac{1}{2} x_{-1} + 3
The general term of the solution can be found by noting that
x_{t+1} = \frac{1}{2} x_t + 3 = \frac{1}{2} (2^t + 3) + 3 = 2^t + 3
The second problem can be solved recursively as follows:
x_{t+1} = -3 x_t + 4
x_t = -3 x_{t-1} + 4
x_{t-1} = -3 x_{t-2} + 4
...
x_0 = -3 x_{-1} + 4
The general term of the solution can be found by noting that
x_{t+1} = -3 x_t + 4 = -3 \left( 4 \cdot \left( \frac{1}{3} \right)^t + 4 \right) + 4 = 4 \cdot \left( \frac{1}{3} \right)^t + 4
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Sunny earns $12 per hour delivering cakes.She worried for x hours this week. Unfortunatly she was charged $15 for a late delivery on tuesday
Answer:
$12x - $15
Step-by-step explanation:
Sunny earns $12 per hour delivering cakes. She worked for x hours this week. Unfortunately, she was charged $15 for a late delivery on Tuesday. How much money did Sunny earn this week?
her total income for the week = income earned - charge
income earned = income per hour x number of hours worked = 12x
total income = 12x - 15
Which of the following describes a situation in which it is safe to employ t-procedures
(a) n1=10, n2=40; both samples are moderately skewed.
(b) n1=10, n2=8; sample 1 is approximately normal, while sample 2 is skewed right.
(c) n1=6, n2=6; both samples are approximately normal.
(d) n1=35, n2=40; both samples are approximately normal, sample 2 has two outliers.
(e) It is safe to use t-procedures in more than one of the situations above.
The situation in which it is safe to employ t-procedures is described by option (c) where both samples are approximately normal.
option (c) is identified as the situation where it is safe to use t-procedures.
t-procedures are appropriate when certain assumptions are met, including the assumption of normality of the population or sample distributions. Option (c) states that both samples are approximately normal, which fulfills this requirement. This means that the data in both samples have a symmetric bell-shaped distribution, allowing t-procedures to be used for hypothesis testing or confidence interval estimation.
Options (a), (b), and (d) describe scenarios where either one or both samples are moderately skewed or contain outliers, which violates the assumption of normality. Skewness and outliers can impact the validity of t-procedures, making them less reliable. Therefore, these options do not fulfill the requirement for safely employing t-procedures.
Option (e) states that it is safe to use t-procedures in more than one of the situations above. However, based on the analysis provided, only option (c) meets the criteria of having both samples approximately normal, making it the only situation where t-procedures can be safely employed.
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Last week the team ran 21 1/2 miles total. this week the track coach had the team run 5 1/2 miles on monday and 4 3/4 miles on tuesday. the next three days the team averaged 6 miles a day
18:10 is equivalent to :5
Answer:
18:10 is equivalent to 9:5
Step-by-step explanation:
half of 18 is 9 and half of 10 is 5
Answer:
9:5
Step-by-step explanation:
18:10 is equivalent to 9:5 because 10 divided by 2 is 5 so you can do the same for 18. You will get 9 which makes it 9:5.
A company expects that the number N(x) of a product sold during a week is related to the amount spent on advertising by the function N(x)=-6x3+180x²+2250x + 13,000, where x (with 0 ≤x≤25) is the amount spent on advertising in thousands of dollars. What is the point of diminishing returns?
The point of diminishing returns is
(Simplify your answer. Type an ordered pair. Do not use commas in the individual coordinates.)
The point of diminishing returns is (20.98, 21247.3).
The point of diminishing returns occurs when the marginal cost of producing an extra unit of output exceeds the marginal revenue generated from selling that unit. Mathematically, it is the point at which the derivative of the production function equals zero and the second derivative is negative.
Given the polynomial function N(x) of degree 3, we can find the point of diminishing returns by finding the critical points where the first derivative equals zero and evaluating the second derivative at those points.
The derivative of N(x) is N'(x) = -18x² + 360x + 2250. To find the critical points, we set N'(x) = 0:
0 = -18x² + 360x + 2250
Dividing by -18 simplifies the equation:
0 = x² - 20x - 125
Using the quadratic formula, we find the solutions to the equation:
x₁,₂ = (20 ± √(20² - 4(1)(-125))) / 2(1)
x₁,₂ = 10 ± 5√5
Thus, the two critical points of N(x) are at x = 10 - 5√5 and x = 10 + 5√5.
To determine the point of diminishing returns, we evaluate the second derivative N''(x) = -36x + 360 at these critical points:
N''(10 - 5√5) = -36(10 - 5√5) + 360 ≈ -264.8
N''(10 + 5√5) = -36(10 + 5√5) + 360 ≈ 144.8
From the evaluations, we find that N''(10 + 5√5) is negative while N''(10 - 5√5) is positive. Therefore, the point of diminishing returns corresponds to x = 10 + 5√5.
To find the corresponding y-coordinate (N(10 + 5√5)), we can substitute the value of x into the original function N(x).
Hence, the point of diminishing returns is approximately (20.98, 21247.3).
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Dustin says the product of 4.5 x 0.8 is equal to 3.6. Which explains whether or not his answer is correct