A cliff diver horizontally runs off a 12 m high cliff at 10 m/s. How far away
does he land?
25.5 m
15.5 m
10.5 m
98.0 m

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

For more such questions on decay rate, click on:

https://brainly.com/question/27542728

#SPJ8

Using the conversion factor that we have seen in the solution, the value obtained is 40.25 kilometers per hours

To convert miles per hour (mph) to kilometers per hour (kph), you need to multiply the speed value in mph by a conversion factor of 1.61, which is the number of kilometers in one mile.

Given that;

1 miles/hour = 1.61 kilometer per hour

25 miles per hour = 25 * 1.61/1

= 40.25 kilometers per hours

Hence the value that we get is 40.25 kilometers per hours

Learn more about miles per hour:https://brainly.com/question/24238048

#SPJ1

The convert unit of  25 miles per hour is equivalent to 40.2335 kilometers per hour

Unit conversion is the process of converting a value expressed in one unit of measurement to another unit of measurement that is equivalent in terms of its value or quantity. This is done by using a conversion factor, which is a numerical factor that relates the two units of measurement.

To convert miles per hour (mph) to kilometers per hour (km/h), we need to multiply the speed in mph by 1.60934, which is the conversion factor from miles to kilometers.

So, to convert 25 mph to km/h:

25 mph × 1.60934 = 40.2335 km/h

Therefore, 25 miles per hour is equivalent to 40.2335 kilometers per hour.

Learn more about convert units below.

https://brainly.com/question/141163

#SPJ1

Answer:

a) Kinetic energy decreases, b) Potential energy increases, c) Mechanical energy stays constant, d) Kinetic energy increases, e) Kinetic energy increases, f) Mechanical energy stays constant.  

Explanation:

a) Let suppose that the skater is a conservative system. If he goes up the hill, gravitational potential energy is increased at the expense of kinetic energy. In a nutshell, his kinetic energy decreases.

b) His potential energy increases.

c) Mechanical energy is the sum of gravitational potential and kinetic energies, since skater is conservative, then mechanical energy stays constant.

d) If he goes down the hill, his kinetic energy is increased at the expense of gravitational potential energy. In a nutshell, his kinetic energy increases.

e) His potential energy decreases.

f) Mechanical energy is the sum of gravitational potential and kinetic energies, since skater is conservative, then mechanical energy stays constant.

Answer:

The answer would be what the other guy said

Explanation:

The time taken by light to go from A to B is approximately 0.000020087 seconds.

The speed of light in a medium is given by:

v = c/n

where c is the speed of light in vacuum and n is the refractive index of the medium.

In medium 1, the speed of light is:

v1 = c/n1 = c/1.33

In medium 2, the speed of light is:

v2 = c/n2 = c/1.51

The distance that light travels in medium 1 is 331 cm, whereas in medium 2, the distance is 151 cm. The time it takes for light to get from point A to point B is the product of the times it takes in mediums 1 and 2.

t = d1/v1 + d2/v2

Substituting the given values, we get:

t = (331 cm)/(c/1.33) + (151 cm)/(c/1.51)

Since the units of speed and distance are not consistent, we need to convert the units to a common unit. We can use meters as the common unit:

t = (3.31 m)/(c/1.33) + (1.51 m)/(c/1.51)

Now, we can use the value of the speed of light in vacuum:

c = 299792458 m/s

Substituting this value, we get:

t = (3.31 m)/((299792458 m/s)/1.33) + (1.51 m)/((299792458 m/s)/1.51)

t = 0.000015065 s + 0.000005022 s

t = 0.000020087 s.

Learn more about  refractive index here:

https://brainly.com/question/30761100

#SPJ1

Answer:

33 mph

Explanation:

My best guess

Answer:

5.8E-3m/s

Explanation:

Using

V= d/t

V= velocity

d= distance

t= time

But d= 2πr

But 180rev= 1min

So 1min/180= 60s/180

So

Vavr= 2π(10m)/180*60

=5.8E-3m/s

The kangaroo that can jump over an object 2.6 m high has:

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Given info:

Applying the maximum height formula and clearing the initial velocity we get:

v₀ = √(y max * (2*g))

v₀ = √( 2.6 m * (2 * 9.8 m/s²))

v₀ = √( 2.6 m * 19.6 m/s²)

v₀ = √50.96 m²/s²

v₀ = 7.138 m/s

Applying the maximum time formula we get:

t max= 7.138 m/s / 9.8 m/s²

t max =0.728 s

Applying  the time of flight formula, we get:

t(of) =2 * t max

t(of) =2 * 0.728 s

t(of) = 1.456 s

Learn more about vertical launch at: brainly.com/question/13962796

#SPJ4

Answer:

Explanation:

This is as a result of Newton's 3rd

Which state's that for every action (force) in nature there is an equal and opposite reaction

Hence when a force of 5N hits the ball the ball will then tend to move with a 5N force

I have observed and experienced behaviors that are learned as a result of environmental influences, and I can furnish examples to support this assertion.

Recycling serves as a noteworthy instance. During my childhood, I acquired the habit of recycling owing to the teachings and guidance of my parents and educators, which became firmly established in me.

Water conservation serves as another illustration. Having experienced repeated droughts in my locale, I developed a sense of awareness about the utilization of water and inculcated practices such as shutting off the tap while brushing my teeth.

My daily habits have been influenced by the environmental elements in my surroundings and have now become ingrained in my routine.

Read more about behaviors here:

https://brainly.com/question/1741474

#SPJ1

the relationship between speed distance and time is Speed=Distance/Time.

what is speed, distance and time?

Speed - The rate at which an object moves along a path is referred to as its speed. It is a scalar quantity.

Distance - It is defined as an object's entire movement without regard for direction.

Time - it is defined as a interval over which the change or event occurs.

relation between speed, distance and time

\(speed = \frac{distance }{time}\)

If the distance is in km and time is in hours, then the speed is km/hr.

If the distance is in m and the time is in seconds, then the speed is m/sec.

the relationship between speed distance and time is Speed=Distance/Time.

To know more about speed, distance and time, check out:

https://brainly.com/question/26046491

#SPJ1

Answer:

(a). The largest value of θ is 71.9°.

(b). The second largest value of θ is 57.7°.

(c). The third largest value of θ is 47.7° .

Explanation:

Given that,

Width of diffraction grating \(w= 19.2\ mm\)

Number of rulings\(N=6010\)

Wavelength = 337 nm

We need to calculate the distance between adjacent rulings

Using formula of distance

\(d=\dfrac{w}{N}\)

Put the value into the formula

\(d=\dfrac{19.2\times10^{-3}}{6010}\)

\(d=3.19\times10^{-6}\ m\)

We need to calculate the value of m

Using formula of constructive interference

\(d \sin\theta=m\lambda\)

\(\sin\theta=\dfrac{m\lambda}{d}\)

Here, m = 0,1,2,3,4......

\(\lambda\)=wavelength

For largest value of  θ

\(\dfrac{m\lambda}{d}>1\)

\(m>\dfrac{d}{\lambda}\)

Put the value into the formula

\(m>\dfrac{3.19\times10^{-6}}{337\times10^{-9}}\)

\(m>9.46\)

\(m = 9\)

(a). We need to calculate the largest value of θ

Using formula of constructive interference

\(\theta=\sin^{-1}(\dfrac{m\lambda}{d})\)

Now, put the value of m in to the formula

\(\theta=\sin^{-1}(\dfrac{9\times337\times10^{-9}}{3.19\times10^{-6}})\)

\(\theta=71.9^{\circ}\)

(b). We need to calculate the second largest value of θ

Using formula of constructive interference

\(\theta=\sin^{-1}(\dfrac{m\lambda}{d})\)

Now, put the value of m in to the formula

\(\theta=\sin^{-1}(\dfrac{8\times337\times10^{-9}}{3.19\times10^{-6}})\)

\(\theta=57.7^{\circ}\)

(c). We need to calculate the third largest value of θ

Using formula of constructive interference

\(\theta=\sin^{-1}(\dfrac{m\lambda}{d})\)

Now, put the value of m in to the formula

\(\theta=\sin^{-1}(\dfrac{7\times337\times10^{-9}}{3.19\times10^{-6}})\)

\(\theta=47.7^{\circ}\)

Hence, (a). The largest value of θ is 71.9°.

(b). The second largest value of θ is 57.7°.

(c). The third largest value of θ is 47.7° .

Answer:

the answer is the formula of acceleration is m/s²

Answer:

Explanation:

Frequency is oscillations per second.

So we have to find the Number of seconds she paced.

2 minutes = 2 X 60

               = 120 seconds

Therefore,

Her frequency = 10 / 120

                       = 1/12 Hertz

Answer:

\(d=2.7m\)

Explanation:

From the question we are told that:

Electric Field strength \(E=8.53 * 10^3 V/m\)

Potential difference is \(V= 23.0 kV\)

Generally the equation for distance is mathematically given by

\(d=\frac{V}{E}\)

\(d=\frac{23.0*10^3}{8.53 * 10^3 V/m}\)

\(d=2.7m\)

Answer:

D

Explanation:

Answer:

The answer is C. Strong Nuclear

Explanation:

I took this test and it was correct!

Answer:

Explanation: Average acceleration = (velocity/distance)

= Convert 1.87 to meters

1.87 / 1000 = 0.00187

(7.49 m/s / 0.00187 m)

= 3987.37 m/s²

The following situations represents a positive displacement:

B. An object moves from a height of 5 meters to a height of 10 meters.

Displacement is a vector quantity that measures the change in position of an object from its initial position to its final position. In this scenario, the positive position is measured vertically upward along the y-axis. Let's analyze each option to determine which one represents a positive displacement:

A. An object moves from a height of 10 meters to a height of 5 meters.

This represents a negative displacement since the object moves downward, opposite to the positive direction along the y-axis.

B. An object moves from a height of 5 meters to a height of 10 meters.

This represents a positive displacement as the object moves upward, in the positive direction along the y-axis.

C. An object remains at a height of 5 meters.

This represents zero displacement since there is no change in the object's position along the y-axis.

D. An object moves from a height of 5 meters to a height of 5 meters.

This also represents zero displacement since the object starts and ends at the same position along the y-axis.

Therefore, the situation that represents a positive displacement is option B, where the object moves from a height of 5 meters to a height of 10 meters.

For more such questions on Displacement, click on:

https://brainly.com/question/14422259

#SPJ8

Position and velocity both have transverse components for motion in polar coordinates. However, acceleration can be expressed as the sum of a radial component and a tangential component, where the tangential component is transverse to the radial direction. Therefore, the answer is Acceleration (Option 3).

An object's acceleration can be defined as the rate at which its velocity changes in relation to the passage of time. Accelerations are vector quantities. The orientation of the net force that is acting on an item is what determines the orientation of the acceleration the object is experiencing.

Particle dynamics studies particle motion and forces. Without a net force, a body has a constant velocity. The net force on a body must be zero to prevent acceleration.

Want to know more about coordinates visit the link which is given below;

https://brainly.com/question/27749090

#SPJ4

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

The work required to pump the water out of the spout is 11,011,392 J.

What is a spout?

A spout is typically a small opening or nozzle through which a fluid (such as water) can flow. The spout may be a part of a container, such as a tank or a pitcher, or it may be a separate attachment, such as a faucet or a sprinkler. The spout is important in the study of fluid dynamics, which is the branch of physics that deals with the motion of fluids and the forces that act on them.

To find the work required to pump the water out of the spout, we need to determine the weight of the water in the tank and the height through which the water needs to be lifted.

The weight of the water in the tank can be found using its volume and weight density. The volume of the tank is given by:

V = a * b * c = 4 m * 4 m * 9 m = 144 \(m^{3}\)

The weight of the water can be found using the:

W = m * g = V * ρ * g

where m is the mass of the water, g is the acceleration due to gravity, and ρ is the weight density of water.

Substituting the given values, we have:

W = V * ρ * g = 144 \(m^{3}\) * 1000 kg/\(m^{3}\) * 9.8 m/\(s^{2}\) = 1,411,200 N

Next, we need to determine the height through which the water needs to be lifted. This is equal to the distance from the spout to the surface of the water in the tank. The height can be found using the Pythagorean theorem since the spout is at a diagonal distance from the base of the tank. The height is given by:

h = sqrt(\(c^{2}\) - \(d^{2}\)) = sqrt(9 \(m^{2}\) - 4 \(m^{2}\)) = 7.81 m

Finally, the work required to pump the water out of the spout is given by:

W = F * d

where F is the force required to lift the water and d is the distance over which the force is applied. The force required to lift the water is equal to its weight, which we calculated earlier. Therefore, we have:

W = F * d = W * h = 1,411,200 N * 7.81 m = 11,011,392 J

Therefore, The amount of work needed to pump the water out of the spout is 11,011,392 joules.

To learn more about spout click here

https://brainly.com/question/1591745

#SPJ1

Answer:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

Explanation:

Answer:

Yes I think... But the joke is it is a walk then.

Answer:

no

Explanation:

because if the fly get its wings cut off its obviously not going to be able to fly

The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.

Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.

There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider

On the number line, we can see the movement as follows

1 0 -1 -2 -3= 4km

Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.

Learn more about displacement here:

https://brainly.com/question/14422259

#SPJ!

Answer:

kinetic energy

Explanation:

It is kinetic energy because it is an energy in motion. In order words it is an energy which the body or object moves.

The horizontal distance travelled by the fish when dropped is 131.25 m.

The time of motion of the fish from the given height is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

h = 0 + ¹/₂gt²

t = √ ( 2h / g )

t = √ ( 2 x 135 / 9.8 )

t = 5.25 seconds

The horizontal distance travelled by the fish when dropped is calculated as;

X = vt

X = 25 m/s  x  5.25 s

X = 131.25 m

Learn more about horizontal distance here: https://brainly.com/question/24784992

#SPJ1

Answer:

Weight of 21 kg is misleading as kg is a unit of mass.

F = m g = 21 kg * 9.8 m/s^2 = 206 Newton's

P(pressure) = Force / Area        definition of pressure

1 cm^2 = 1.0E-4 m^2

200 cm^2 = .02 m^2

P = 206 N / .02 m^2 = 10,300 N/m^2 = 10,300 Pascals

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

Andromeda galaxy is the correct answer.

The characteristics of the scalar product allows to find the angle between the two vectors is:

The scalar product is the product between two vectors whose result is a scalar.

            A . B = |A|  |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

            i.i = j.j = 1

            i.j = 0

            A . B = (4 i - 4j). * -5 i + 7j)

            A . B = - 4 5 - 4 7

            A. B = -48

We look for the modulus of each vector.

           |A| = \(\sqrt{x^2 +y^2 }\)

           |A| = \(\sqrt{4^2 + 4^2}\)  

           |A| = 4 √2

          |B| = \(\sqrt{5^2 +7^2}\)

          |B| = 8.60

We substitute.

            -48 = 4√2  8.60  cos θ

            -48 = 48.66 cos θ

            θ = cos⁻¹   \(\frac{-48}{48.664}\)  

            θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

Learn more about the scalar product here:  brainly.com/question/1550649

The student can use a meterstick and stopwatch to measure the centripetal acceleration.

Acceleration of an object on a circular orbit. Velocity is a vector quantity (that is, it has both magnitude, velocity, and direction), so as an object moves along a circular path, its direction changes constantly, and so does its velocity, causing acceleration. increase. Centripetal acceleration is defined as the property of motion of a body through a circular orbit. An object that moves in a circle and has an acceleration vector pointing to the center of the circle is called centripetal acceleration. Spinning a ball on an overhead string causes it to experience centripetal acceleration.

Learn more about the centripetal acceleration in

https://brainly.com/question/14465119

#SPJ4