A company is Selling price per unit = 1000 $. Fixed cost = 225,000 $ and variable cost per unit = 250 $. Estimating profit 3000 $. Find = BEP 4 إجابتك = Sales value .5 *************** The operating profit at production 2 .....................and selling 500 units The number of unit to obtain on .3 = $ operating profit of 1,500,000 إجابتك إجابتك إجابتك = The number of unit to verify BEP .1 إجابتك

The power developed in the circuit is 56.25 W and the power absorbed by the circuit is also 56.25 W. So, there is no net power transfer in the circuit. Hence, this circuit is a balanced circuit.

The given circuit in the Figure 1 is shown below:Figure 1The voltage v in the middle is common between the two sources, but they have different polarities. We apply KVL around the closed loop of the circuit containing the sources and the resistor to determine the current, iΔ.  -12 + 6iΔ - 2(iΔ+4) + 3 = 0 Simplifying the above equation, 4iΔ = 15iΔ = 15/4 = 3.75 A The current iΔ is flowing in the direction shown in the Figure 1. We can now use Ohm's law to find the voltage across the resistor. vo = iΔ × 4 = 3.75 × 4 = 15 V Total power developed in the circuit can be found by multiplying the total current in the circuit by the voltage v.  PT = (12 - 3) × (3.75 + 2) = 56.25 W where the currents passing through vg1 and vg2 are (12 - v) and v/2 respectively.The power absorbed by the circuit can be found using the current iΔ: PA = (iΔ)² × 4 = (3.75)² × 4 = 56.25 W

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In Stokes flow, the fluid velocity is proportional to the forces acting on the fluid and the fluid is assumed to be viscous and incompressible. The fluid velocity near a rotating sphere in Stokes flow can be determined using the equations of fluid dynamics.

Kinematic reversibility is a property of Stokes flow, which states that the fluid flow is symmetric with respect to time reversal. This means that if the fluid velocity is recorded at a certain time, then the same velocity field will be obtained if time is reversed and the flow is replayed in the reverse direction.

When a sphere is rotating near a wall, the flow of fluid around the sphere creates a velocity field that pushes the sphere away from the wall. This flow can be considered as the fluid being pushed away from the sphere and towards the wall. If the flow is time-reversed, the fluid velocity field would be the same, but the direction of the velocity would be reversed. This means that the fluid would be drawn towards the sphere and away from the wall, pulling the sphere towards the wall.

Therefore, based on the property of kinematic reversibility in Stokes flow, the rotating sphere near a wall will experience a force that could either push it away from the wall or draw it towards the wall, depending on the direction of the flow.

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The approximate average power output is mathematically given as

P=1097.6w

Question Parameters:

Iowa with a 10 m2 swept area and 50 m hub height

Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

Generally, the equation for the average output power  is mathematically given as

\(P=0.5 \phi BAu^3*n\\\)

Where

B= Benz coefficient

n=0.8

Therefore

P=0.5*1*0.8*10*7^3*0.8

P=1097.6w

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What is the approximate average power output of a well-designed modern turbine in Des Moines, Iowa with a 10 m2 swept area and 50 m hub height? Assume 80% of the Betz limit, 80% conversion efficiency, and air density of 1.0 kg/m3. Wind speed is 7 m/s2

By following some steps, you'll be able to select the appropriate course on the OBS and maintain a direct flight from Mercer County Regional Airport to the Minot VORTAC with a "TO" indication. Remember to account for factors like wind correction and magnetic variation when planning your route.

To make a direct flight from Mercer County Regional Airport (Area 3) to the Minot VORTAC (Area 1) with a "TO" indication, you should follow these steps:

1. Obtain the current aviation sectional chart for the flight area. This chart will provide important information like VOR station locations, frequencies, and magnetic variation.

2. Locate Mercer County Regional Airport (Area 3) and Minot VORTAC (Area 1) on the chart.

3. Using a navigation plotter or protractor, determine the magnetic bearing from the departure airport (Mercer County) to the destination VORTAC (Minot). This bearing is the course you'll need to set on the Omnibearing Selector (OBS) to maintain a direct flight path.

4. Before departure, tune your NAV radio to the Minot VORTAC frequency, which can be found on the sectional chart. The DME (Distance Measuring Equipment) will display the distance to the VORTAC.

5. Set the magnetic bearing you determined earlier on the OBS. A "TO" indication will appear on the CDI (Course Deviation Indicator) or HSI (Horizontal Situation Indicator), showing that you're flying towards the Minot VORTAC.

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Answer:

Automation generally means “a process performed without human assistance”, while autonomy implies “satisfactory performance under significant uncertainties in the environment and the ability to compensate for system failures without external intervention [emphasis mine].”

Explanation:

Answer:

a. The rate of loss of entropy from the high-temperature reservoir is 1.2 MJ/s x (1 - 0.35) = 0.78 MJ/s, and the rate of gain of entropy by the low-temperature reservoir is 1.2 MJ/s x 0.35 = 0.42 MJ/s.

b. The work done by the engine is 1.2 MJ/s x 0.35 = 0.42 MW.

c. The total entropy gain of the system is 0.42 MJ/s x (1000 K - 308 K) = 124.8 MJ/s.

d.  = 83 MJ/s

Explanation:

An automobile travels along a straight road at 15.65 m/s through a 11.18 m/s speed zone. A police car observed the automobile. At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile at a constant acceleration of 1.96 m/s2 . The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s2

Find the total time required for the police car  to over take the automobile.

Answer:

15.02 sec

Explanation:

The total time required for the police car to overtake the automobile is related to the distance covered by both  cars which is equal from instant point of abreast.

So; we can say :

\(D_{pursuit} =D_{police}\)

By using the second equation of motion to find the distance S;

\(S= ut + \dfrac{1}{2}at^2\)

\(D_{pursuit} = (15.65 *12 )+(15.65 (t)+ (\dfrac{1}{2}*(-3.05)t^2)\)

\(D_{pursuit} = (187.8)+(15.65 \ t)-0.5*(3.05)t^2)\)

\(D_{pursuit} = (187.8+15.65 \ t-1.525 t^2)\)

\(D_{police} = ut _P + \dfrac{1}{2}at_p^2\)

where ;

u  = 0

\(D_{police} = \dfrac{1}{2}at_p^2\)

\(D_{police} = \dfrac{1}{2}*(1.96)*(t+12)^2\)

\(D_{police} = 0.98*(t+12)^2\)

\(D_{police} = 0.98*(t^2 + 144 + 24t)\)

\(D_{police} = 0.98t^2 + 141.12 + 23.52t\)

Recall that:

\(D_{pursuit} =D_{police}\)

\((187.8+15.65 \ t-1.525 t^2)= 0.98t^2 + 141.12 + 23.52t\)

\((187.8 - 141.12) + (15.65 \ t - 23.52t) -( 1.525 t^2 - 0.98t^2) = 0\)

= 46.68 - 7.85 t -2.505 t² = 0

Solving by using quadratic equation;

t = -6.16 OR  t = 3.02

Since we can only take consideration of the value with a  positive integer only; then t = 3.02 secs

From the question; The motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit;

Therefore ; the total time  required for the police car  to over take the automobile = 12 s + 3.02 s

Total time  required for the police car  to over take the automobile = 15.02 sec

Answer:

Orange signs

Explanation:

Got it right on the test

Answer:

Gasoline is injected directly into the cylinder.

Explanation:

In a direct injection system, the air and gasoline are not pre-mixed. Rather, air comes in using the intake manifold, while the gasoline is injected directly into the cylinder.

In a relational database, the three basic operations used to develop useful sets of data are select, project, and join. The correct option is c.

A relational database is a most commonly digital database based on the relational model of data, as proposed by E. F. Codd in 1970. A system used to maintain relational databases is a relational database management system. Many relational database systems are equipped with the option of using SQL Structured Query Language for querying and updating the database.

A relational model organizes data into one or more tables of columns and rows, with a unique key identifying each row. Rows are also called records or tuples. Columns are also called attributes. Thus, in a relational database, the three basic operations used to develop useful sets of data are select, project, and join.

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Based on the scenario above tech A is wrong and Technician B says the square cut seal acts like self adjustment mechanism is correct.

Note that Square cut seal is entitled in keeping the break fluid behind the piston and also help in  returning the pad to its original position and as such, undergo self adjustment method.

Therefore, we can say that Based on the scenario above tech A is wrong and Technician B says the square cut seal acts like self adjustment mechanism is correct.

See full question below

Technician A says fluid leaks from the caliper dust boot indicates a worn square cut seal.

Technician B says the square cut seal acts like self adjustment mechanism. Who is right? Select the correct

option and click NEXT. A only O B only Both A and B Neither A nor B

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Factory overhead allocated per unit for speedboats is $1,125 per unit and that for bass boats is $1,125 per unit.

a. To determine the total number of budgeted direct labor hours for the year: Direct labor hours Speedboat = Direct labor hours Bass boat = Total direct labor hours Speedboat = Number of units × Direct labor hours per unit SpeedboatTotal direct labor hours Speedboat = 400 × 10Total direct labor hours Speedboat = 4,000Direct labor hours Bass boat = Number of units × Direct labor hours per unit Bass boatTotal direct labor hours Bass boat = 400 × 10Total direct labor hours Bass boat = 4,000Total budgeted direct labor hours = Total direct labor hours Speedboat + Total direct labor hours Bass boatTotal budgeted direct labor hours = 4,000 + 4,000Total budgeted direct labor hours = 8,000Answer: Total number of budgeted direct labor hours for the year is 8,000 direct labor hours.b. The single plantwide factory overhead rate is calculated as follows:Single plantwide factory overhead rate = Total factory overhead / Total budgeted direct labor hoursSingle plantwide factory overhead rate = $900,000 / 8,000Single plantwide factory overhead rate = $112.50Answer: The single plantwide factory overhead rate is $112.50 per direct labor hour.c. Factory overhead allocated per unit for each product using the single plantwide factory overhead rateSpeedboatsFactory overhead allocated per unit = Single plantwide factory overhead rate × Direct labor hours per unitSpeedboatsFactory overhead allocated per unit = $112.50 × 10SpeedboatsFactory overhead allocated per unit = $1,125Bass boatsFactory overhead allocated per unit = Single plantwide factory overhead rate × Direct labor hours per unitBass boatsFactory overhead allocated per unit = $112.50 × 10Bass boatsFactory overhead allocated per unit = $1,125.

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For every unit of heat input into the system, only 38.4% is converted into useful work. This efficiency can be improved by increasing the upper temperature or reducing the condenser pressure, but this may require additional equipment and energy.

The Rankine cycle is a thermodynamic cycle commonly used in power plants to generate electricity. It involves four main components: a boiler, a turbine, a condenser, and a pump. In this scenario, we are given the upper pressure and temperature of the cycle, as well as the pressure at the condenser.

To determine the efficiency of the cycle, we need to use the formula for thermal efficiency, which is (net work output/heat input). In this case, we can assume that the heat input is the energy added to the system in the boiler, and the net work output is the energy generated by the turbine minus the energy required by the pump.

We also need to use the Rankine cycle efficiency formula, which is (1 - T2/T1), where T1 is the temperature at the boiler and T2 is the temperature at the condenser. To find T1, we can use the given upper temperature of 550°C and convert it to Kelvin (823 K). To find T2, we need to use the pressure at the condenser to find the corresponding temperature using a steam table. At 7.5 kPa, the temperature is approximately 41.5°C or 314.5 K.

Using these values, we can calculate the Rankine cycle efficiency to be approximately 38.4%.

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Out of the given function prototypes, the valid function prototype is:

b.int funcTest (int, int, float);

The explanations for each of the given options are as follows:

a. funcTest (int x, int y, float) ();This function prototype is invalid. It misses the function name and the closing parentheses after the float parameter. Correct syntax would be: "return_type function_name (parameter_list);".

b.int funcTest (int, int, float);This function prototype is valid. It uses correct syntax, defines a return type "int" and has a function name "funcTest" followed by three function parameters.

c. int funcTest (int, int Y, float z)This function prototype is valid. It uses correct syntax, defines a return type "int" and has a function name "funcTest" followed by three function parameters. Note that the parameter 'Y' is valid, but it doesn't start with a lowercase letter. It should be 'y'.

d. int functest (int x, int y. float z) {This function prototype is invalid because of a syntax error. The dot in between 'y' and 'float' should be a comma. The correct syntax should be: "int function_name(int parameter1, int parameter2, float parameter3);".

Therefore, the valid function prototype out of the given options is: b.int funcTest (int, int, float);.

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Answer:

Metamorphic manufacturing

Explanation:

I don't know what form of an answer you wanted but I hope this helps :)

Answer:

Here are some characteristics that describe customers who are more likely to have low assets and medium-low debt:

* **Age:** Younger customers are more likely to have lower assets and debt than older customers. This is because they have had less time to accumulate assets and may be carrying more student loan debt.

* **Income:** Customers with lower incomes are more likely to have lower assets and debt than customers with higher incomes. This is because they have less money to save and invest, and may be spending more of their income on necessities.

* **Education:** Customers with less education are more likely to have lower assets and debt than customers with more education. This is because they may have lower-paying jobs and may be less likely to save and invest.

* **Marital status:** Single customers are more likely to have lower assets and debt than married customers. This is because they may have less income and may be spending more of their income on housing and other expenses.

* **Employment status:** Unemployed customers are more likely to have lower assets and debt than employed customers. This is because they may have less income and may be spending more of their income on necessities.

* **Credit score:** Customers with lower credit scores are more likely to have lower assets and debt than customers with higher credit scores. This is because they may have difficulty qualifying for loans and may be paying higher interest rates on debt.

It is important to note that these are just general trends, and there are always exceptions. There are many factors that can affect a customer's assets and debt, including their personal circumstances, financial decisions, and economic conditions.

Explanation:

The acceleration of the man in the boson's chair is 12.54 m/s^2.

To solve this problem, we need to use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object times its acceleration (F = ma). In this case, the force is the tension in the rope, which is equal to the weight of the man (180 lb) plus the force he exerts (50 lb.). Therefore:

F = 180 lb + 50 lb = 230 lb.

We can convert this force to mass units using the conversion factor of 1 lb = 4.45 N (newton's):

F = 230 lb. × 4.45 N/lb. = 1023.5 N

Now we can use Newton's second law to find the acceleration:

a = F/m

where m is the mass of the man. We can use the conversion factor of 1 lb = 0.4536 kg to convert the weight of the man to mass units:

m = 180 lb × 0.4536 kg/lb = 81.65 kg

Therefore:

a = 1023.5 N / 81.65 kg = 12.54 m/s^2

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When you call the substring method on the string "abcdefgh" with the arguments (1, 3), it will return the characters starting at index 1 (inclusive) and ending at index 3 (exclusive). So, the result will be "bc".

Explanation:

1. The substring method is used to extract a portion of a string based on the specified start and end indices.

2. In this case, the start index is 1 and the end index is 3.

3. The start index is inclusive, meaning the character at the start index is included in the substring.

4. The end index is exclusive, meaning the character at the end index is not included in the substring.

5. In the given string "abcdefgh", the character at index 1 is "b" and the character at index 2 is "c".

6. Since the end index is exclusive, the character at index 3 ("d") is not included in the substring.

7. Therefore, the substring extracted using the substring method with the given arguments (1, 3) will be "bc".

8. Thus, "abcdefgh".substring(1, 3) returns "bc".

It's important to pay attention to the index values and the inclusiveness/exclusiveness of the start and end indices when using the substring method to extract substrings from a string.

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The first 5 outputs in the discrete time domain for a unit impulse input and a sampling time of 1 s are: 1, 0, 0, 0, 0.

(i) To derive the open-loop transfer function G(s) of the system, we start with the given information about the single break point and the phase angle. From the phase angle expression, we have:

Phase angle = -tan^(-1)(w)

The magnitude when w << 1 rad/s is 0 dB, which means the gain is unity. Therefore, at low frequencies, the system has unity gain.

We can represent the open-loop transfer function G(s) as follows:

G(s) = K / (s + a)

where K is the gain and a is the break point frequency.

Since the magnitude when w << 1 rad/s is 0 dB, the gain K is equal to 1. The break point frequency a is given as w = 1 rad/s.

Therefore, the open-loop transfer function G(s) is:

G(s) = 1 / (s + 1)

This expression is obtained by considering the given phase angle expression and the magnitude at low frequencies.

(ii) Block diagram for the continuous time domain:

To convert the system from continuous time to time sampled, we need to introduce a sampler and a hold element. The block diagram for the time sampled system is:

The key components in converting the system to a time sampled system are:

1. Sampler: It discretizes the continuous-time input signal into a sequence of samples.

2. Hold: It holds the sampled value for a specific sampling period, producing a constant output during that period.

(iii) To derive the pulsed transfer function for the discrete time domain, we use the bilinear transformation method. The bilinear transformation maps the s-plane to the z-plane using the equation:

s = (2/T) * (z - 1) / (z + 1)

where T is the sampling period.

Substituting s = (2/T) * (z - 1) / (z + 1) into the open-loop transfer function G(s), we get:

G(z) = G(s)|s=(2/T) * (z - 1) / (z + 1)

G(z) = (2/T) * (z + 1) / [(z - 1) + (z + 1)]

Simplifying further, we have:

G(z) = (2/T) * (z + 1) / (2z)

G(z) = (z + 1) / (zT)

(iv) The difference equation for a sampling time of 1 can be obtained by performing inverse Z-transform on the pulsed transfer function G(z). Since the pulsed transfer function is:

G(z) = (z + 1) / (zT)

Taking the inverse Z-transform, we get:

g(n) + g(n-1) = y(n)T

where g(n) represents the system output at discrete time n, y(n) is the input at discrete time n, and T is the sampling period.

(v) Given the sampling time of 1 s and a unit impulse input, the first 5 outputs can be calculated by using the difference equation obtained in part (iv). The initial conditions need to be specified to determine the output sequence.

Assuming g(-1) = 0 (initial condition), the first 5 outputs are:

g(0) + g(-1) = y(0) * T

g(0) + 0 = 1 * 1 = 1

g(1) + g(0) = y(1) * T

g(1) + 1 = 0 * 1 = 0

g(2) + g(1) = y(2) * T

g(2) + 0 = 0 * 1 = 0

g(3) + g(2) = y(3) * T

g(3) + 0 = 0 * 1 = 0

g(4) + g(3) = y(4) * T

g(4) + 0 = 0 * 1 = 0

Therefore, the first 5 outputs in the discrete time domain for a unit impulse input and a sampling time of 1 s are: 1, 0, 0, 0, 0.

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Answer:

\(0.015\ \text{W}\)

Explanation:

\(T_{set}\) = Set temperature = \(70^{\circ}\text{C}\)

\(T_\infty\) = Air temperature = \(50^{\circ}\text{C}\)

A = Surface area = \(30\ \text{mm}^2=30\times 10^{-6}\ \text{m}^2\)

h = Convection heat transfer coefficient = \(25\ \text{W/m}^2\text{K}\)

Heater power is given by

\(P_e=hA(T_{set}-T_\infty)\\\Rightarrow P_e=25\times 30\times 10^{-6}(70-50)\\\Rightarrow P_e=0.015\ \text{W}\)

The required heater power is \(0.015\ \text{W}\)

Answer:

Gap Analysis is the process of discovering discrepancies between two or more sets of data flow diagrams or discrepancies within a single DFD. it might be helpful

To demonstrate that it could be done, the builders chose to utilize concrete rather than the granite specified in the plan. True

For its numerous products, cement received numerous national and international prizes for innovation. They agreed to supply 8,000 barrels of Portland cement to the United States in 1886 as part of one of the largest contracts of their professional lives. This cement was used to build the base of the Statue of Liberty.

The stone construction between the base of the statue and the old, star-shaped battle fort is referred to as the pedestal. It raises the statue and supports her at the same time. Tickets for pedestals provide you entry inside and access to the outside balcony that is located immediately beneath the statue's feet.

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True. The showName() method is a way to create objects based on existing prototypes. Prototypes are essentially blueprints for creating new objects, and they contain all of the shared properties and methods that will be inherited by any objects created from that prototype.

The showName() method specifically allows you to create new objects that inherit the properties and methods of an existing prototype, but also add new properties or methods specific to the new object.

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The productivity index (PI) for this well is 6.9 STB/day/psi.

The Productivity Index (PI) for this well is approximately 6.9 STB/day/psi.What is Productivity Index (PI)?Productivity index (PI) is a performance metric used to assess the capacity of an oil or gas well to produce hydrocarbons. It is a measure of the well's productivity that relates to the pressure drop across the wellbore's reservoir section and the flow rate of fluids (oil, gas, or water) from the reservoir into the wellbore.When the PI value is high, it means the well is very productive. When the PI is low, it means that the well is not very productive.The formula for the Productivity Index (PI) is as follows:PI = (2πkhd)/(μln(r_e/r_w) + s)Where:k = average permeability, mdh = net reservoir thickness, ftμ = fluid viscosity, cpd = drainage area, acr = wellbore radius, fts = skin factorPI Calculation:Given data,Net pay thickness (h) = 75 ftNet to gross ratio = 0.9Porosity (φ) = 6.5%Average permeability, k = 2 md and 15 md in the vertical and horizontal directions, respectivelyRelative permeability (kro) = 0.82Oil viscosity (μ) = 0.55 cpFormation volume factor (Bo) = 1.22 bbl/STBWellbore radius (rw) = 6 in. or 0.5 ftDrainage area (Ad) = 55 acres = (55 × 43560) ft² = 2395800 ft²Well length (L) = 1500 ftSkin value (s) = 0.8Correction factor for wellbore friction = 1.0The first step is to calculate the effective drainage radius (re) using the formula,re = (0.00708 × (φ^2) × (kh/μ))^(1/2)× (kro/Bo) × ln(r_e/r_w)Let's plug in the values of given parameters,re = (0.00708 × (0.065^2) × ((2+15)/2/μ))^(1/2) × 0.82/1.22 × ln(r_e/r_w)re = (0.04226/μ)^(1/2) × ln(r_e/r_w)We know, k = 2 md and 15 md in vertical and horizontal directions. So we use the harmonic average permeability.1/kh = 1/2 + 1/15kh = 2.14 mdUsing μ = 0.55 cp, the effective drainage radius is calculated as,re = 174.86 ftUsing the formula of PI,PI = (2πkh)/[μln(re/rw) + s]PI = (2 × 3.1416 × 2.14 × 1500)/(0.55 × ln(174.86/0.5) + 0.8)PI = 6.9 STB/day/psi.

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The company should go with the out-house treatment option, as it has a lower annual worth value and will result in lower costs over the 11-year period.

GivenDataAn oil refinery finds that it is necessary to treat the waste liquids from a new process before discharging them into a stream. The treatment will cost $40,000 the first year, but process improvements will allow the costs to decline by $4,000 each year.An outside company will process the wastes for the fixed price of $20,000/year throughout the 11 year period, payable at the beginning of each year.MARR = 7%FormulaAnnual Worth (AW) = (P/A, i%, n)Annual Worth (AW) = Present Worth (PW) + Future Worth (FW)Where,P = Initial Cost (Present Worth)A = Capital Recovery Factori = InterestRaten = Life of the ProjectCalculationFirst of all, we calculate the AW of in-house treatment. The cash outflow would be $40,000 in year 0, then $36,000 ($40,000 – $4,000) in year 1, then $32,000 ($36,000 – $4,000) in year 2, and so on until year 10, and the cash inflow would be $0 as there is no salvage value.Annual Worth (AW) = (P/A, i%, n)Present Worth (PW) = $40,000Future Worth (FW) = $0Capital Recovery Factor (CRF) = (i(1 + i)n)/((1 + i)n – 1) = (0.07(1 + 0.07)11)/((1 + 0.07)11 – 1) = 0.122053Annual Worth (AW) = (P/A, i%, n)= ($40,000/0.122053)= $327,814.53Therefore, the AW of in-house treatment is $327,814.53.Now, we calculate the AW of out-house treatment. The cash outflow would be $20,000 in each year from year 0 to year 10, and the cash inflow would be $0 as there is no salvage value.Annual Worth (AW) = (P/A, i%, n)Present Worth (PW) = $20,000Capital Recovery Factor (CRF) = (i(1 + i)n)/((1 + i)n – 1) = (0.07(1 + 0.07)11)/((1 + 0.07)11 – 1) = 0.122053Annual Worth (AW) = (P/A, i%, n)= ($20,000/0.122053)= $163,907.27Therefore, the AW of out-house treatment is $163,907.27. AW in-house treatment = $327,814.53 AW out-house treatment = $163,907.27.

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The LCM of 60 and 90 is 180.

The LCM of 220 and 1400 is 3080.

The LCM of 32, 73, and 11 is 1024.

a. To find the least common multiple of 60 and 90, we can start by listing the multiples of each:

Multiples of 60: 60, 120, 180, 240, 300, 360, 420, 480, 540, 600...
Multiples of 90: 90, 180, 270, 360, 450, 540, 630, 720, 810, 900...

We can see that the first common multiple is 180, and the next one is 360. However, the least common multiple (LCM) is the smallest number that is a multiple of both 60 and 90.

b. To find the LCM of 220 and 1400, we can do the same thing:

Multiples of 220: 220, 440, 660, 880, 1100, 1320, 1540, 1760, 1980, 2200...
Multiples of 1400: 1400, 2800, 4200, 5600, 7000, 8400, 9800, 11200, 12600, 14000...

The first common multiple is 2200, but the LCM is the smallest number that is a multiple of both 220 and 1400.

c. To find the LCM of 32, 73, and 11, we can list their multiples:

Multiples of 32: 32, 64, 96, 128, 160, 192, 224, 256, 288, 320, 352, 384, 416, 448, 480...
Multiples of 73: 73, 146, 219, 292, 365, 438, 511, 584, 657, 730, 803, 876, 949, 1022, 1095...
Multiples of 11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110, 121, 132, 143, 154, 165...

d. To find the LCM of 23, 5, and 7, we can list their multiples:

Multiples of 23: 23, 46, 69, 92, 115, 138, 161, 184, 207, 230, 253, 276, 299, 322, 345...
Multiples of 5: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75...
Multiples of 7: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98, 105...

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Answer:

Explanation:

Galvanic corrosion occurs when two dissimilar metals are immersed in a conductive solution and are electrically connected. One metal (the cathode) is protected, whilst the other (the anode) is corroded. The rate of attack on the anode is accelerated, compared to the rate when the metal is uncoupled.