A company that manufactures vehicle trailers estimates that the monthly profit for selling its midsize trailer is represented by function p, where t is the number of trailers sold. p(t)= -25t^3+625t^2-2500t Use the key features of function p to complete these statements. The company makes a profit when it sells _____trailers. The maximum profit of approximately $____ occurs when it sells approximately____ trailers.

Answer:

-6/5

Step-by-step explanation:

Get y by itself to get the slope. So 18x+15y=90. Move 18x to the other side of the equation. Now you have 15y=-18x+90. Divide both sides by 15 to get y by itself. Now it's y= -18/15x + 6. Reduce -18/15 to the simplest fraction. You have y= -6/5x+6. Any number can replace the 6 in the equation to give you a parallel line...it's the slope that makes it parallel, not the y intercept. So y= -6/5x+10 or y=- -6/5x-1 would satisfy your parallel slope equation.

Answer:

\(\displaystyle -1\frac{1}{5}\)

Step-by-step explanation:

\(\displaystyle 18x + 15y = 90 \hookrightarrow \frac{15y}{15} = \frac{-18x + 90}{15} \\ \\ \boxed{y = -1\frac{1}{5}x + 6}\)

Parallel equations have SIMILAR RATE OF CHANGES [SLOPES], so −1⅕ remains as is.

I am joyous to assist you at any time.

More than once a week: 0.11

Once a week: 0.51

Every other week: 0.26

Every three weeks: 0.05

Less often than every three weeks: 0.07

To make a relative frequency distribution, follow these steps:

Count the number of occurrences of each category in the data. In this case, 11% of the 251 participants responded "more than once a week", so the number of occurrences for this category is 0.11 * 251 = 27.61 (rounded to 28). Similarly, 51% of the participants responded "once a week", so the number of occurrences for this category is 0.51 * 251 = 127.51 (rounded to 128). And so on for the other categories.

Divide the number of occurrences for each category by the total number of participants. In this case, the total number of participants is 251, so the relative frequency for "more than once a week" is 28 / 251 = 0.11. The relative frequency for "once a week" is 128 / 251 = 0.51. And so on for the other categories.

And that's it! These are the relative frequencies for each category in the data.

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18 ans 2,639.064

19 ans 1,437.607

22 ans 7,872.433

23 ans 2,950.190

The two solutions of the equation:

(6x - 12)/3 + 4 = 18/x

Are x = 3 and x = -3

Here we have the following equation:

(6x - 12)/3 + 4 = 18/x

Notice that in the right side we have x on a denominator, then x can not be zero, so x ≠ 0.

Now, let's start by simplifying the left side:

(6x - 12)/3+  4 = 18/x

2x - 4 + 4 = 18/x

2x = 18/x

Now we can multiply both sides by x so we get:

2x^2 = 18

Now divide both sides by 2:

x^2 = 18/2

x^2 = 9

Finally, apply the square root in both sides:

√x^2 = ±√9

x = ±3

The two solutions are x = 3 and x = -3

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Answer:

\(x=\frac{d+c}{a-b}\)

Step-by-step explanation:

The equation is:

a x - c = b x + d

so we subtract b x from both sides to group the terms that contain x on the left:

a x - b x - c = d

add c to both sides to isolate the terms in x on the left:

a x - b x = d + c

extract "x" as common factor on the left:

x (a - b) = d + c

divide both sides by the quantity (a - b) to isolate the "x":

x = (d + c) / (a - b)

or:    \(x=\frac{d+c}{a-b}\)

Answer:

the probability that a randomly selected student received an A, B, or C is approximately 0.769, or about 76.9%.

Step-by-step explanation:

To find the probability that a randomly selected student received an A, B, or C, we need to add up the number of students who received each of these grades and divide by the total number of students in the class.

The total number of students in the class is:

total = A + B + C + D + E = 40 + 40 + 33 + 20 + 14 = 147

The number of students who received an A, B, or C is:

A + B + C = 40 + 40 + 33 = 113

Therefore, the probability that a randomly selected student received an A, B, or C is:

P(A or B or C) = (A + B + C) / total = 113 / 147 ≈ 0.769

So the probability that a randomly selected student received an A, B, or C is approximately 0.769, or about 76.9%.

The maximum and minimum values of the function is solved

Given data ,

We can find the maximum and minimum values of the function by taking the derivative of y with respect to x and setting it equal to zero.

y = (sin x)³ - (sin x)⁶

y' = 3(sin x)² cos x - 6(sin x)⁵ cos x

Setting y' equal to zero:

0 = 3(sin x)² cos x - 6(sin x)⁵ cos x

0 = 3(sin x)² cos x (1 - 2(sin x)³)

sin x = 0 or (sin x)³ = 1/2

If sin x = 0, then x = kπ for any integer k.

If (sin x)³ = 1/2, then sin x = (1/2)^(1/3) ≈ 0.866. This occurs when x = π/3 + 2kπ/3 or x = 5π/3 + 2kπ/3 for any integer k.

To determine whether these values correspond to a maximum or minimum, we can use the second derivative test.

y'' = 6(sin x)³ cos² x - 15(sin x)⁴ cos² x - 9(sin x)⁴ cos x + 6(sin x)⁵ cos x

y'' = 3(sin x)³ cos x (4(sin x)² - 5(sin x)² - 3cos x + 2)

For x = kπ, y'' = 3(0)(-3cos(kπ) + 2) = 6 or -6, depending on the parity of k. This means that these points correspond to a maximum or minimum, respectively.

For x = π/3 + 2kπ/3 or x = 5π/3 + 2kπ/3, y'' = 3(1/2)^(5/3) cos x (4(1/2)^(2/3) - 5(1/2)^(1/3) - 3cos x + 2). This expression is positive for x = π/3 + 2kπ/3 and negative for x = 5π/3 + 2kπ/3, which means that the former correspond to a minimum and the latter to a maximum.

Hence , the maximum value of the function is y = 27/64, which occurs at x = 5π/3 + 2kπ/3, and the minimum value is y = -1/64, which occurs at x = π/3 + 2kπ/3

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Answer:

Step-by-step explanation:

You want the maximum and minimum values of the function ...

  y = sin³(x) -sin⁶(x)

When we substitute sin³(x) = z, we have the quadratic expression ...

  y = z -z² . . . . . a quadratic function

Adding and subtracting 1/4, we can put this in vertex form:

  y = -(z -1/2)² +1/4

This version of the function describes a parabola that opens downward and has a vertex at (z, y) = (1/2, 1/4). The y-value of the vertex represents the maximum value of the function.

The maximum value of y is 1/4.

The sine function is a continuous function with a range of [-1, 1]. Then z will be a continuous function of x, with a similar range. We already know that y describes a function of z that is a parabola opening downward with a line of symmetry at z = 1/2. This means the most negative value of y will be found at z = -1 (the value of z farthest from the line of symmetry). That value of y is ...

  y = (-1) -(-1)² = -1 -1 = -2

The minimum value of y is -2.

__

Additional comment

The range of y is confirmed by a graphing calculator.

<95141404393>

Answer:

845 am

Step-by-step explanation:

Answer:

8:45 Am

Step-by-step explanation:

Answer:

10-(-6), -2-(-18), 2-(-14)

Step-by-step explanation:

The solution to given linear inequality, 6(x1.5) + 30 < 48, is x < 2

From the question, we are to solve the given linear inequality

The given linear inequality is

6(x1.5) + 30 < 48

First, we will write this inequality properly.

The inequality can be properly written as

6(1.5x) + 30 < 48

Now, we will solve the linear inequality

6(1.5x) + 30 < 48

Subtract 30 from both sides of the equation

6(1.5x) + 30 - 30 < 48 - 30

6(1.5x) < 18

Divide both sides of the inequality by 6

6(1.5x)/6 < 18/6

(1.5x) < 3
1.5x < 3

Divide both sides of the inequality by 1.5

1.5x/1.5 < 3/1.5

x < 2

Hence, the solution is x < 2

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Answer:

Step-by-step explanation:

Please find attached the complete solution

Answer:

Perimeter = 10√7 + 2√5 or 30.929

Area = 12

Step-by-step explanation:

Length = 3√7 + 3√5

Width = 2√7 - 2√5

Perimeter of rectangle = 2(length + width) = 2(3√7 + 3√5 + 2√7 - 2√5) = 10√7 + 2√5 or 30.929

Area of rectangle = Length × Width

= (3√7 + 3√5)(2√7 - 2√5)

= 42 - 6√35 + 6√35 - 30

= 12

Answer:

Asriel Dreemurr

Step-by-step explanation:

Answer:

clearly the gay robot

hes my favorite <3

Answer:

Another way to write the expression 3√12 is 6√3.

Given the expression 3√12.

First, we rewrite 12 as 2²×3

3√12 = 3√( 2² × 3 )

Next, we pull terms out from under the radical.

3√12 = 3√( 2² × 3 ) = 3 × (2√ 3 )

Next, we multiply 3 and 2

3 × (2√ 3 ) = 6√3

Therefore, another way to write the expression 3√12 is 6√3.

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Answer:

n = 2

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 30 = n / 2 sqrt(3)

2 sqrt(3) tan 30 = n

2 sqrt(3) * sqrt(3)/3 = n

2 = n

We have to find,

The required value of n.

Now we can,

Use the trigonometric functions.

→ tan(θ) = opp/adj

Let's find the required value of n,

→ tan (θ) = opp/adj

→ tan (30) = n/2√3

→ n = 2√3 × tan (30)

→ n = 2√3 × √3/3

→ n = 2√3 × 1/√3

→ [n = 2]

Thus, the value of n is 2.

Answer:

∠CDF = 48°

Step-by-step explanation:

∠CDE = ∠EDF + ∠CDF

Given that,

∠CDE = 114°

∠EDF = 66°

So, to find the value of ∠CDF, you have to subtract the value of ∠EDF from ∠CDE.

∠CDF = ∠CDE - ∠EDF

∠CDF = 114 - 66

∠CDF = 48°

Answer:

Step-by-step explanation:

HOPE THIS HELPS’

PLZZ MARK BRAINLIEST

Answer: when y= 10 x=30

How is it x= 30 you may ask?

x varies directly as y. This means that:

(x/y) is a constant. Let us call this constant as "k". i.e: x/y=k

for the first one which is x=24 y= 8

24/8= 3

BUT... about y=10?

for y= 10 its the same rule x/y= k in this case we already found K which is 3

*we don't have x so we cant divide anything however we do have  "k" and y so all we have to is multiply so its 10*3= 30*

And that's how x= 30 when y= 10

Note that the table of budget is attached accordingly, and steps 1-4 have been completed. See the table.

4) Since the emergency fund for that month was $200, it means that they are in the short for $105. They can only affod it if they take from their savings.

5) they had a balance of $800 for the month. This is miscellaneous funds. They can make use of this for the trip to NASA. This way, they won't have to touch the savings or entertainment.

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Full Question:
See attached image.

Reflect

4. Analyze Relationships One month, the family must make an

emergency car repair for $305. Are they able to pay for it out of the

fixed emergency fund for that month? If not, how can they afford it?

5. The family wants to make a trip to Houston to visit the NASA Space

Center. What are some ways they can save without using all of the

allotted $160 for entertainment

Answer: 2a < 2b

Step-by-step explanation:

We are given a statement:

a < b and b < c, then 2a ____ 2b

We can use simple numbers that make the statement true.

Where,

a = 2

b = 3

c = 4

Now lets plug it in.

2 < 3 and 3 < 4, then 2(2) ____ 2(3)

and lets simplify:

2 < 3 and 3 < 4, then 4 ____ 6

We can see that 4 is less than 6,

so as a is less than b, 2a is less than 2b.

The only thing changing is the coefficient being multiplied by the variables a and b.

Answer: {(12, 3), (11, 2), (10, 1), (9, 0), (8, 1), (7, 2), (6, 3)}

Step-by-step explanation:

Each value of x corresponds to only one value of y, making the relation a function.

The estimate for when the population will exceed 6371 is t > 20.33. This means that at a time greater than 20.33 units

To estimate when the population will exceed 6371, we can set up the inequality:

p(t) > 6371

where p(t) is the population at time t, as given by the equation \(p(t) = 1950e^{0.16t}\)

Substituting the expression for p(t) into the inequality, we get:

\(1950e^{0.16t} > 6371\)

Next, we can divide both sides of the inequality by 1950 to isolate the exponential term:

\(e^{0.16t} > 6371 / 1950\)

To solve for t, we can take the natural logarithm (ln) of both sides, which will eliminate the exponential term:

\(ln(e^{0.16t} > ln(6371 / 1950)\)

Using the property of logarithms that ln(e^x) = x, we get:

\(0.16t > ln(6371 / 1950)\)

Now, we can divide both sides of the inequality by 0.16 to solve for t:

\(0.16t / 0.16 > ln(6371 / 1950) / 0.16\)

Simplifying, we get:

\(t > ln(6371 / 1950) / 0.16\)

Using a calculator, we can find the approximate value of \(ln(6371 / 1950) / 0.16\), which is approximately 20.33 (rounded to two decimal places).

So, the estimate for when the population will exceed 6371 is t > 20.33. This means that at a time greater than 20.33 units

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Answer:

8,000 :D

Step-by-step explanation:

Answer:

8,000

Step-by-step explanation:

Since the 1 in the hundreds place isn't five or higher we round the number down.

Suppose that So, S1, S2,... is a sequence of subsets of N the following sets is guaranteed to be different from all sets in the sequence is S = {n² | n² & Sn}.

Subsets are a part of the mathematical concept of sets. A set is anything that is wrapped in curly braces, such as "a,b,c,d." If set A is a collection of even integers and set B is composed of the numbers 2, 4, and 6, then set A is the superset of set B and set B is said to be a subset of set A. Review Sets Subset and Superset for further details.

Set A is referred to as a subset of Set B if each element of Set A is also present in Set B. In other words, Set B includes Set A.

As an illustration, if set A has the elements X, Y, and set B contains the elements X, Y, and Z, then set A is the subset of set B.

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If the random number is less than the winning probability of 0.0028, the player wins $20 and we add that to the amount variable.

Otherwise, the player loses $1 and we subtract that from the amount variable.

To simulate this scenario in Python.

Here's a possible implementation:

import random

# Set the seed number

random.seed(77)

# Initialize the starting amount and the number of bets

amount = 18

num_bets = 0

# Loop until the player runs out of money

while amount >= 1:

   # Increment the number of bets

   num_bets += 1

   # Check if the player wins

   if random.random() < 0.0028:

       amount += 20 - 1  # The net earnings are $10

          # Otherwise, the player loses $1

   else:

       amount -= 1

# Report the total number of bets

print(f"Total number of bets: {num_bets}")

In this implementation, we use the random module in Python to simulate the outcome of each bet.

We set the seed number to 77 to ensure that the results are reproducible.

We initialize the starting amount to $18 and the number of bets to 0. We then loop until the player runs out of money (i.e., the amount variable is less than $1).

Inside the loop, we increment the number of bets by 1 and simulate the outcome of the bet using random.

random() which returns a random float between 0 and 1.

If the random number is less than the winning probability of 0.0028, the player wins $20 and we add that to the amount variable.

Otherwise, the player loses $1 and we subtract that from the amount variable.

After the loop ends, we print the total number of bets.

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In the proportion (5x + 1):3 = (2x + 2):7, the value of x is -1/29.

In the proportion (6x):(4x) = 7, there is no value of x that satisfies the proportion.

To find the value of x in the given proportions, let's solve them one by one:

(5x + 1) : 3 = (2x + 2) : 7

To solve this proportion, we can cross-multiply:

7(5x + 1) = 3(2x + 2)

35x + 7 = 6x + 6

Subtracting 6x from both sides and subtracting 7 from both sides:

35x - 6x = 6 - 7

29x = -1

Dividing both sides by 29:

x = -1/29

Therefore, the value of x in the first proportion is -1/29.

(6x) : (4x) = 7

To solve this proportion, we can simplify the left side:

6x / 4x = 7

Dividing both sides by 2x:

3/2 = 7

This equation is not true, as 3/2 is not equal to 7.

Therefore, there is no value of x that satisfies the second proportion.

In summary, the value of x in the proportion (5x + 1) : 3 = (2x + 2) : 7 is -1/29, and there is no value of x that satisfies the proportion (6x) : (4x) = 7.

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