A condition that lifts a parcel of air to form cumulus clouds is
Answer
a. differential heating.
b. mountain barriers.
c. a cold front.
d. All of the above.

Answers

Answer 1

A condition that lifts a parcel of air to form cumulus clouds is  differential heating.

Thus, Differential heating of the land and the water. Water changes temperature more slowly because it has a high specific heat, like the ocean. Land, particularly sandy beaches, has a low specific heat, therefore it warms up faster than water with the same amount of heat.

Our beach towels are blown away by this land-and-water combination, but it is also to blame for more extreme weather like monsoons and thunderstorms and heat.

The typical afternoon thunderstorm might be produced by sea breezes. For instance, the Florida peninsula is bordered by the ocean on both sides. Cool air from the Gulf of Mexico blows inland on the western side as a sea breeze. A sea wind from the Atlantic Ocean causes the same thing to occur on the eastern side and differential heating.

Thus, A condition that lifts a parcel of air to form cumulus clouds is  differential heating.

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Related Questions

When measurements are close to their true values, they are said to be
A. accurate
B. estimated
C. precise
D. standardized

Answers

Answer:

When measurements are close to true

value they are called to be accurate

Explanation:

Answer:

A) accurate

Explanation:

Accuracy refers to how close a measurement is to the true value of what is being measured.

The place below earth's surface where the earthquake begins.
а
focus
fault
en oo
epicenter
P-wave

Answers

Answer:

The position where an earthquake begins below the earths surface is called the hypo center. The point directly above the hypo center is called the epicenter.

Explanation:

www.usga.gov | United States of America Department of Geological Surveys.

The process of sediments being compacted and cemented to form sedimentary rocks is called

Answers

Answer:

Lithification is the answer.

Want in own words please

What determines whether something is solid or liquid or gas

Answers

Answer:

An object could be determined as solid:

-It doesn't change shape easily.

-when lots of heat applied till melting point, it would melt or thaw (basically turn into liquid).

-turn to pieces or bent when enough force applied to it.

-the molecules attached with each other by strong forces, creating strong bonds.

An object could be determined as liquid:

-It changes shaped based on the container.

-when lots of heat applied till boiling point, it would vaporize

-the molecules have weak bonds, creating a lot of spaces.

-when heat extracted from the liquid till freezing point, it would freeze/hardened (turn into solid)

An object could be determined as gas:

-it doesn't have any shape or form.

-if fills in the container.

-if lots of heat applied, its molecules are going to move, vibrate,and transist faster; increasing pressure and volume.

-The molecules have very weak bonds, creating spacious space.

-when the heat are being extracted till certain freezing point, it is going to turn into liquid, then solid.

What forces control the strength of the tides

Answers

Answer:

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996).

Explanation:

I hope this helps.

Answer: gravity is one major force that creates tides

Explanation:

in 1687, sir Isaac newton explained that ocean tides result from the gravitational attraction of the sun and the moon on the oceans of the earth

The function f(x)=−0.0025x2+0.243x+3 models the path of a rocket in feet. Explain how you would use the function to determine the height the rocket was launched from, how far it traveled, and the greatest height it reached. Answer in complete sentences.

Answers

Answer:

The quadratic function models the path of the rocket. When we substitute an x value, we can determine the height in feet of the rocket.

To determine the height it was launched from, we would look at the y-intercept. This represents the starting value, as time = 0 in this point (cannot have negative time).

To determine how far the rocket traveled, we would look at the positive x-intercept of the expression. At this point, height = 0, so we can see the distance from start to finish of the rocket.

To determine the greatest height achieve, we would look at the vertex of the parabola generated from the given function. Using (-b/a, f(-b/a)), we can determine the greatest height achieved.

32. Increasing the amplitude of a sound wave produces a
sound with
1. lower speed
2. higher pitch
3: shorter wavelength
4. greater loudness

Answers

Answer:

4

Explanation:

because amplitude of a sound wave is related to loudness of the sound, so the higher the amplitude, the louder the sound

hope this helps

_____ is a property that determines the amount of current for a given source voltage, whereas a _____ is a device that controls the current in a circuit.Question 21 options:Resistance, resistorResistance, batteryResistor, resistanceBattery, resistance

Answers

Resistance is a property that determines the amount of current for a given source voltage.

A greater resistance results in a lower current whereas a smaller resistance allows a higher current given that voltage is constant.

Resistor is a device and resistance is a property.

Battery is a device that controls the current in a current.

Therefore, the correct answer is

Resistance, battery

A swan is flying at a speed of 17.5m/s. there is wind blowing from the east at 12.5m/s.
a) if the swan pointed due south, what would be the magnitude and direction of its velocity relative to the ground?
b) if the swan wishes to travel south, what would be the magnitude and direction of its velocity relative to the ground?
c) if the swan travels due south as in part b, what will be its displacement after 8.5 hours?

Answers

The swan's velocity relative to the ground, when pointing due south with a speed of 17.5 m/s and wind blowing from the east at 12.5 m/s, is approximately 21.49 m/s at an angle of 35.74 degrees east of south. When the swan wishes to travel south, its velocity relative to the ground matches the wind speed of 12.5 m/s in the opposite direction. After traveling due south for 8.5 hours, the swan's displacement is approximately 106.25 meters.

a) If the swan is pointing due south and flying at a speed of 17.5 m/s while there is a wind blowing from the east at 12.5 m/s, we can calculate the magnitude and direction of its velocity relative to the ground using vector addition.

To find the magnitude, we can use the Pythagorean theorem:

Magnitude = √((17.5 m/s)^2 + (12.5 m/s)^2)

Magnitude = √(306.25 + 156.25)

Magnitude ≈ √462.5 ≈ 21.49 m/s

To find the direction, we can use trigonometry. The wind blowing from the east will create an angle with the south direction. Let's call this angle θ.

tan(θ) = (12.5 m/s) / (17.5 m/s)

θ ≈ tan^(-1)(0.714)

θ ≈ 35.74 degrees

Therefore, the magnitude of the swan's velocity relative to the ground is approximately 21.49 m/s, and its direction is approximately 35.74 degrees east of south.

b) If the swan wishes to travel south, it needs to counteract the effect of the wind blowing from the east. In this case, the swan's velocity relative to the ground needs to be equal to the wind velocity in the opposite direction.

Magnitude = 12.5 m/s (same as the wind speed)

Direction = 180 degrees (opposite direction of the wind)

Therefore, the magnitude of the swan's velocity relative to the ground would be 12.5 m/s, and its direction would be due south.

c) If the swan travels due south as in part b for 8.5 hours, we can calculate its displacement by multiplying the magnitude of its velocity relative to the ground by the time traveled.

Displacement = Magnitude * Time

Displacement = 12.5 m/s * 8.5 hours

Displacement ≈ 106.25 m

Therefore, the swan's displacement after 8.5 hours of traveling due south would be approximately 106.25 meters.

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Final answer:

The swan maintains its speed of 17.5m/s flying due south, unaffected by the eastward wind. If it maintains that speed for 8.5 hours, you need to multiply the speed by the total seconds in 8.5 hours to find its overall displacement.

Explanation:

Given the swan's speed and the wind direction, we can address each part of your question as follows:

In part (a), if the swan is flying due south, the wind coming from the east does not affect the southward speed of the swan. Hence, the magnitude of its velocity remains 17.5 m/s, and the direction is due south unless otherwise affected by another factor, such as wind coming from another direction. The situation in part (b) is effectively the same as part (a). The swan continues to travel at 17.5m/s due south, because the eastward wind has no southward component slowing the swan down. In part (c), to calculate the displacement, we'd need to multiply the swan's speed (17.5 m/s) by the time it travels (8.5 hours converted to seconds, because the speed is given in m/s). This results in the displacement (in meters), not accounting for any effects of the eastward wind.

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A flow chart showing step by step how the body responds to a cold using the words B cells, helper T cells, macrophages, mucus, lymph, cytokines, receptor proteins, antibodies, memory cells and plasma cells

Answers

The body's response to a cold involves various immune cells and processes. Here is a simplified flow chart depicting the step-by-step response:

Initial exposure to a cold virus leads to its entry into the body through the respiratory system. The virus infects the cells lining the respiratory tract, triggering a response from macrophages, which are immune cells that engulf and destroy foreign particles.Macrophages present viral antigens (molecular markers) on their surface and release cytokines, signaling molecules that activate other immune cells.Helper T cells recognize the viral antigens presented by macrophages through their receptor proteins, and they become activated.Activated helper T cells stimulate B cells, another type of immune cell, to produce antibodies specific to the cold virus.B cells differentiate into plasma cells, which secrete large quantities of antibodies into the bloodstream.Antibodies circulate in the body and bind to the cold virus, neutralizing its ability to infect cells.Memory B cells are also generated during this process. These cells "remember" the specific cold virus, enabling a faster and stronger immune response in case of future infections.The antibodies help to remove the virus from the body by marking it for destruction by other immune cells, such as macrophages and natural killer cells. Mucus production increases in the respiratory tract, trapping the cold virus and facilitating its removal from the body. Lymph, a clear fluid containing immune cells and antibodies, carries away the virus and other debris from the infection site.

This flow chart demonstrates the coordinated response of B cells, helper T cells, macrophages, mucus production, lymph, cytokines, receptor proteins, antibodies, memory cells, and plasma cells in combating a cold virus and eventually eliminating it from the body.

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7
How should an Ammeter be connected into a circuit?
(1 Point)
In parallel with the wire
In parallel with the battery
In series

Answers

Answer:

In series

Explanation:

Ammeter is used in electric circuits to measure the amount electric current that passes through the circuit.

Now, as a rule, this ammeter is always connected in series with the wires in the circuit where the current is being measured so that sufficient current can pass through it.

Review the network activity times in months, determine the earliest start and finish times, latest start and finish times, and slack for each activity. Indicate the critical path and the project duration. Your deliverable should include a network diagram and a calculation of the critical path.

Answers

To determine the earliest start and finish times, latest start and finish times, and slack for each activity, we can utilize the network diagram and use forward and backward pass calculation. We can determine the critical path by identifying the longest path in the network diagram where there is no slack. The project duration is the length of the critical path.

Here is the network diagram for the given project: \(\small{\text{(Please see the attached image for the network diagram.)}}\)The calculations for the earliest start and finish times, latest start and finish times, and slack for each activity are shown below:|Activity Duration (Months)|Predecessor|ES|EF|LS|LF|Slack|
|---|---|---|---|---|---|---|---|
|A|2|-|0|2|0|2|0|
|B|3|-|0|3|2|5|2|
|C|5|A|2|7|2|7|0|
|D|4|B|3|7|5|9|2|
|E|3|B|3|6|5|8|2|
|F|6|C, E|7|13|7|13|0|
|G|5|D, F|9|14|13|18|4|The critical path is A-C-F-G, and its length is 13 months.

This means that any delay on these activities will delay the project completion date. Here is the calculation of the critical path: A (2) - C (5) - F (6) - G (5) = 13 months.

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A train A travelled a distance of 150 km in 3 hours, whereas, train 'B"
travelled a distance of 180 km in 4 hours. Which train travelled faster?​

Answers

Answer:

Therefore, Train A is faster with 50km/h and a 5km/h difference

Explanation:

train A

150km/3h = 50km/h

train B

180km/4h = 45km/h

A sound wave traveling in water 144m/s has a wavelength of 0.5m determine the frequency of the wave

Answers

Heya!!

For calculate frequency, lets applicate formula:

                                                       \(\boxed{f=v/\lambda}\)

                                                   Δ   Being   Δ

                                               f = Frequency = ?

                                           v = Velocity = 144 m/s

                                          \(\lambda\) = Wavelenght = 0,5 m

⇒ Let's replace according the formula:

\(\boxed{f = 144\ m/s / 0,5\ m }\)

⇒ Resolving

\(\boxed{f = 288\ Hz}\)

Result:

The frequency of that wave is 288 Hertz

Good Luck!!

Answer:

K Shut up bro

Explanation:

Briefly explain how we can use spectral lines to determine an object's radial motion (toward or away from us). Can we also learn the object's tangential motion (across our line of sight) from its spectral lines

Answers

The spectral lines are spectra in which only a certain wavelength of light is emitted. spectrum can be observed from distant stellar objects.

The definite wavelength spectral lines can be observed from different elements.

Comparing definite wavelengths of emission spectra and spectra of distant stellar objects, we can determine the motion of the stellar body.

If the body is moving, then the Doppler effect plays an effective role by altering the wavelengths of the emission spectra.

Two cases will take place:

First: If the body is moving away, then the wavelength of emission spectra will shift toward red.

Second: If the body is moving towards, then the wavelength of emission spectra will shift toward the blue end.

This phenomenon is only observed in the case of radial movement of the body.

In the case of tangential motion, the Doppler effect won't play a role. so we observe no change in spectral lines.

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in one to two sentences explain how electromagnets move a maglev train​

Answers

Electromagnets are used to create a magnetic field which levitates the train above the track, and then by varying the current in the electromagnets, the train can be propelled forward or slowed down or stopped.

How does magnetic train levitate?

Maglev trains use the principle of electromagnetic suspension to levitate and propel the train. Electromagnets are placed on the underside of the train, and these electromagnets are energized with a current that creates a magnetic field.

This magnetic field interacts with the magnetic field of a conductor in the track, which creates an upward force that levitates the train above the track.

Once the train is levitated, the next step is to propel it forward. The same electromagnets that are used for levitation can be used to propel the train forward.

By varying the current in the electromagnets, the magnetic field created can be made to push or pull the train forward or backward. This process is known as magnetic propulsion or maglev propulsion.

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I'm having a really hard time trying to solve this
A block with mass mb = 1.3 kg is connected by a rope across a 50-cm-diameter, 2.0 kg pulley, as shown in (Figure 1). There is no friction in the axle, but there is friction between the rope and the pulley; the rope doesn't slip and the pulley can be modeled as a solid cylinder. The weight is accelerating upward at 1.2 m/s^2.

What is the tension in the rope on the right side of the pulley?

I'm having a really hard time trying to solve thisA block with mass mb = 1.3 kg is connected by a rope

Answers

Answer:

Approximately \(15.5\; {\rm N}\), assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).

Explanation:

To find the tension in the rope on the right side of the pulley, apply the following steps:

Find the tension that the rope exerts on the block, which is equal to the tension \(T_{\text{left}}\) on the left side of the pulley.Find the torque \(\tau_{\text{left}}\) resulting from the tension \(T_{\text{left}}\) on the left side of the pulley.Find the moment of inertia \(I\) of the pulley and the net torque \(\tau_{\text{net}}\).Add the torque on the left \(\tau_{\text{left}}\) to the net torque \(\tau_{\text{net}}\) to find \(\tau_{\text{right}}\), the torque on the right side of the pulley. Divide \(\tau_{\text{right}}\) by radius of the pulley \(r\) to find the tension on the right side, \(T_{\text{right}}\).


The net force on the block is:

\(F_{\text{net}} = m_{\text{b}} \, a\), where

\(m_{\text{b}} = 1.3\; {\rm kg}\) is the mass of the block, and\(a = 1.2\; {\rm m\cdot s^{-2}}\) is the linear acceleration of the block.

At the same time, the net force on the block can also be expressed as:

\(\begin{aligned}F_{\text{net}} &= T_{\text{left}} - (\text{weight}) \\ &= T_{\text{left}} - m_{\text{b}}\, g \end{aligned}\), where

\(g = 9.81\; {\rm N\cdot kg^{-1}}\) by assumption, and\(T_{\text{left}}\) is the tension the rope exerted on the block. This tension is equal to the tension on the left side of the pulley.

Rearrange and solve for \(T_{\text{left}}\):

\(T_{\text{left}} - m_{\text{b}}\, g = F_{\text{net}} = m_{\text{b}}\, a\).

\(\begin{aligned}T_{\text{left}} &= m_{\text{b}}\, a + m_{\text{b}}\, g \\ &= m_{\text{b}}\, (a + g) \\ &= 1.3\, (1.2 + 9.81)\; {\rm N} \\ &= 14.313\; {\rm N}\end{aligned}\).

Let \(r\) denote the radius of the pulley. It is given that the diameter of the pulley is \(50\; {\rm cm}\). In standard units, the radius of the pulley would be \(r = 25\; {\rm cm} = 0.25\; {\rm m}\).

On the left side of the pulley, tension in the rope exerts a torque of \(\tau_{\text{left}} = T_{\text{left}}\, r\) on the pulley:

\(\begin{aligned}\tau_{\text{left}} &= T_{\text{left}}\, r \\ &= (14.313)\, (0.25)\; {\rm N\cdot m} \\ &= 3.57825\; {\rm N\cdot m} \end{aligned}\).

Under the assumptions, the moment of inertia \(I\) of this cylindrical pulley would be:

\(\begin{aligned} I &= \frac{1}{2}\, m\, r^{2} \end{aligned}\), where

\(m = 2.0\; {\rm kg}\) is the mass of the pulley, and\(r = 0.25\; {\rm m}\) is the radius of the pulley.

\(\begin{aligned} I &= \frac{1}{2}\, m\, r^{2} \\ &= \frac{1}{2}\, (2.0)\, (0.25)^{2}\; {\rm kg \cdot m^{2}} \\ &= 0.0625\; {\rm kg\cdot m^{2}} \end{aligned}\).

Since the rope doesn't slip on the pulley, linear acceleration of the pulley would be equal to that of the rope, \(a = 1.2\; {\rm m\cdot s^{-2}}\). Divide this linear acceleration by the radius of the pulley to find the angular acceleration \(\alpha\) of the pulley:

\(\begin{aligned}\alpha &= \frac{a}{r} \\ &= \frac{1.2}{0.25}\; {\rm s^{-2}} \\ &= 4.8\; {\rm s^{-2}}\end{aligned}\).

Multiply angular acceleration by the moment of inertia to find the net torque \(\tau_{\text{net}}\) on the pulley cylinder:

\(\begin{aligned}\tau_{\text{net}} &= I\, \alpha \\ &= (0.0625)\, (4.8)\; {\rm kg \cdot m^{2}\cdot s^{-2}}\\ &= 0.3\; {\rm kg \cdot m^{2} \cdot s^{-2}} \end{aligned}\).

Note that the net torque of the pulley \(\tau_{\text{net}}\) is in the same direction as \(\tau_{\text{right}}\), but the opposite of \(\tau_{\text{left}}\). Hence:

\(\begin{aligned}\tau_{\text{right}} &= \tau_{\text{net}} + \tau_{\text{left}} \\ &= 0.3\; {\rm N\cdot m} + 3.57825\; {\rm N\cdot m} \\ &= 3.87825\; {\rm N\cdot m}\end{aligned}\).

Divide the torque on the right \(\tau_{\text{right}}\) by radius \(r\) to find the tension in the string on the right \(T_{\text{right}}\):

\(\begin{aligned}T_{\text{right}} &= \frac{\tau_{\text{right}}}{r} \\ &= \frac{3.87825}{0.25}\; {\rm N} \\ &= 15.513\; {\rm N}\end{aligned}\).

Can an automobile with a velocity toward the north simultaneously have an acceleration toward the south? Explain.

Answers

Yes. Velocity and acceleration need not be in the same direction. A car moving north that slows down, for example, accelerates toward the south.

A skateboarder at a skate park rides along the path shown in (Figure 1). hi 0 2.7 m h2 1.0 mPart A If the speed of the skateboarder at point A is v=1.3m/s, what is her speed at point B? Assume that friction is negligible. Express your answer to two significant figures and include appropriate units.

Answers

At a skate park, a skateboarder follows the path shown (Figure 1). At point B, the skateboarder is traveling at a speed of roughly 5.94 m/s.

At point A, the skateboarder has gravitational potential energy and kinetic energy. At point B, the gravitational potential energy is lower, but the total mechanical energy remains the same.

Using the conservation of energy principle:

\(mgh_1 + \frac{1}{2}mv_A^2 = mgh_2 + \frac{1}{2}mv_B^2\)

Since the mass of the skateboarder cancels out, we can rewrite the equation as:

\(gh_1 + \frac{1}{2}v_A^2 = gh_2 + \frac{1}{2}v_B^2\)

Plugging in the given values:

\(2.7 \times 9.8 + \frac{1}{2} \times 1.3^2 = 1.0 \times 9.8 + \frac{1}{2} \times v_B^2\)

Simplifying the equation:

\(26.46 + 0.845 = 9.8 + \frac{1}{2} \cdot v_B^2\)

vB² = (26.46 + 0.845 - 9.8) * 2

vB² = 35.305

Taking the square root of both sides:

vB ≈ 5.94 m/s

Therefore, the speed of the skateboarder at point B is approximately 5.94 m/s.

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a ship is heading due east at 20 mph. the current is flowing southwest at 5 mph. find the actual bearing and speed of the ship

Answers

The problem is related to the relative motion of a ship that is heading towards the east and the current that is flowing towards the southwest.

Let's suppose that the direction of the ship is at an angle of θ° with the East. So, the horizontal component of its velocity will be V cosθ, and the vertical component of its velocity will be V sinθ, where V is the speed of the ship. The direction of the current is flowing southwest, so it is making an angle of 135° with the positive x-axis.

Its horizontal component will be -5 cos45° = -3.5355, and

the vertical component will be 5 cos45° = 3.5355.

The actual horizontal component of velocity = V cosθ - 3.5355

Actual vertical component of velocity = V sinθ + 3.5355

When the ship is moving due East, it means θ = 0°.

Therefore, the actual horizontal velocity will be 20 - 3.5355 = 16.4645 mph, and

the actual vertical velocity will be 0 + 3.5355 = 3.5355 mph.

To find the actual speed of the ship, we will use the Pythagorean theorem;

Actual speed = √(16.4645² + 3.5355²) ≈ 16.87 mph

The angle θ can be calculated using the tangent function; tanθ = 3.5355 / 16.4645 = 0.214, and θ ≈ 12.04°.

The actual bearing is 090° + 12.04° = 102.04°.

The actual bearing of the ship is 102.04°, and the actual speed is 16.87 mph.

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Which object has potential energy?(1 point)
Responses

unlit lightbulb
unlit lightbulb

rock on the ground
rock on the ground

stereo speaker
stereo speaker

can of gasoline

Answers

The object that has potential energy is the can of gasoline.

What is potential energy?

Potential energy is described as the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

The forms of potential energy includes:

Elastic Potential Energy.Electrical (Electromagnetic) Potential Energy.Gravitational Potential Energy.Nuclear Potential Energy.

Potential energy is described as the energy a system has due to position, shape, or configuration.

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plzzzz help I need help ​

plzzzz help I need help

Answers

Answer:

1. It will never run out

2. It’s better for the eviroment

Explanation:

1. Coal is not a renewable source and take along time for it to form so it will soon run out

2. Burning coal releases fossil fums into the air affecting the ozone layer but using solar power dose not release anything into the air

Answer:

Renewable energy works as clean sources of energy, and don't make as much of a detrimental impact on the environment as non-renewable energy. Air pollutants are a product of some non-renewable sources, and it negatively affects the atmosphere, humans, animals, and oceans.

Also, renewable sources won't run out, unlike other sources, as they are finite and will not last forever.

I hope this helped!

A 5V battery is connected to a resistor, 2A of current flows through the resistor. What is the resistance in Ohms

Answers

Answer:

V=IR

5. = 2× RESISTANCE

RESISTANCE=5/2

=2.5 Ohms

A squirrel jumps into the air with a velocity of 4 m/s at an angel of 50 degrees. What is the maximum height reached by the squirrel?

Answers

Answer:

Explanation:

Assuming the squirrel is jumping off the ground, here's what we know but don't really know...

v₀ = 4.0 at 50.0°

So that's not really the velocity we are looking for. We are dealing with a max height problem, which is a y-dimension thing. Therefore, we need the squirrel's upward velocity, which is NOT 4.0 m/s. We find it in the following way:

\(v_{0y}=4.0sin(50.0)\) which gives us that the upward velocity is

v₀ = 3.1 m/s

Moving on here's what we also know:

a = -9.8 m/s/s and

v = 0

Remember that at the very top of the parabolic path, the final velocity is 0. In order to find the max height of the squirrel, we need to know how long it took him to get there. We are using 2 of our 3 one-dimensional equations in this problem. To find time:

v = v₀ + at and filling in:

0 = 3.1 - 9.8t and

-3.1 = -9.8t so

t = .32 seconds.

Now that we know how long it took him to get to the max height, we use that in our next one-dimensional equation:

Δx = \(v_0t+\frac{1}{2}at^2\) and filling in:

Δx = \(3.1(.32)+\frac{1}{2}(-9.8)(.32)^2\) and using the rules for adding and subtracting sig fig's correctly, we can begin to simplify this:

Δx = .99 - .50 so

Δx = .49 meters

A horizontal rope is attached from a truck to a 1475-kg car. As the truck tows the car on a horizontal straight road, the rope will break if the tension is greater than 2551 N. Ignoring friction, what is the maximum possible acceleration of the truck if the rope does not break?

Answers

Given data

*The given mass of the car is m = 1475 kg

*The maximum tension is T = 2551 N

The formula for the maximum possible acceleration of the truck is given by Newton's second law as

\(\begin{gathered} T=ma_{\max } \\ a_{\max }=\frac{T}{m} \end{gathered}\)

Substitute the known values in the above expression as

\(\begin{gathered} a_{\max }=\frac{2551}{1475} \\ =1.72m/s^2 \end{gathered}\)

Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2

2. a. in which principle does simple machine works? ​

Answers

Answer:

A simple machine uses a single applied force to do work against a single load force

Ignoring the friction losses. The work done on the load is equal to the work done with the applied energy. The machine can increase the amount of output power, with a corresponding drop in the distance transported by the load.

light goes from flint glass into ethanol. the angle of refraction in the ethanol is 27.2 ◦ , the index of refraction for flint glass is 1.61, and the index of refraction for ethanol is 1.36. what is the angle of incidence in the glass? answer in units of ◦ .

Answers

The angle of incidence in the glass is approximately 31.8°.

To find the angle of incidence in the glass, we can use Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction:

n1 * sin(angle of incidence) = n2 * sin(angle of refraction)

In this case, n1 is the index of refraction for flint glass (1.61), n2 is the index of refraction for ethanol (1.36), and the angle of refraction in ethanol is 27.2°.

Plugging in these values into Snell's law, we get:

1.61 * sin(angle of incidence) = 1.36 * sin(27.2°)

To find the angle of incidence, we can rearrange the equation:

sin(angle of incidence) = (1.36 * sin(27.2°)) / 1.61

Now, we can solve for the angle of incidence by taking the inverse sine (or arcsine) of both sides:

angle of incidence = arcsin((1.36 * sin(27.2°)) / 1.61)

Calculating this value, the angle of incidence in the glass is approximately 31.8°.

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Select the correct answer.
Jack lives in a society where he has almost no political power. Governmental institutions handle all political, social, and economic affairs.
Which political system is this?
OA. totalitarianism
B. monarchism
C. democracy
D. chiefdom

Answers

Monarchy!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:A or totalitarianism

Explanation: Totalitarianism is an authoritarian form of government in which the ruling party recognizes no limitations whatsoever on its power, including in its citizens' lives or rights

Some characteristics of totalitarianism:

Rule by a single party.

Total control of the military.

Total control over means of communication (such as newspapers, propaganda, etc…)

Police control with the use of terror as a control tactic.

Control of the economy.

What is the internal energy of a substance?

Answers

Answer:

Internal energy is the microscopic energy contained in a substance, given by the random, disordered kinetic energy of the molecules. In addition it includes the potential energy between these molecules, and the nuclear energy contained in the atoms of these molecules

Answer:

Internal energy, in thermodynamics, the property or state function that defines the energy of a substance in the absence of effects due to capillarity and external electric, magnetic, and other fields.

Explanation:

A short horizontal line leads to a small circle, which then has a longer line point up at about 45 degrees. A gap in the horizontal line that led to the circle ends with another small circle and then a short horizontal line segment. In a circuit diagram, what does this symbol represent? a resistor a light bulb a battery a switch. and the answer is D!!!!!!

Answers

Answer:

the answer is D

Explanation:

Answer:

The answer is D

Explanation:

yes

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