A container holds 3.01 grams of
calcium powder for dogs. What is its
weight in centigrams?
Conv
3,010 cg
301 og
30.1 cg
0.0301 og
What is its weight in centigrams

Length (in ft) x Width (in ft) = area in sq. ft

Hope this helps

I'm not good at math so I got this from my notes :)

If it doesn't help then it was worth an attempt...

The solution of the integral by variable change is equal to (1 / 6) · √(2 · x + 3)³ - (3 / 2) · √(2 · x + 3).

In this problem we find the definition of an integral, whose solution must be found by variable change, that is, a kind of algebraic substitution. First, write the complete expression:

∫ [x / √(2 · x + 3)] dx

Second, use algebraic substitution to simplify the expression:

u = 2 · x + 3

x = (u - 3) / 2

dx = du / 2

(1 / 2) ∫  [(u - 3) / (2 · √u)] du

(1 / 4) ∫ [(u - 3) / √u] du

(1 / 4) ∫√u du - (3 / 4) ∫ du / √u

Third, solve the integral:

(1 / 6) · √u³ - (3 / 2) · √u

Fourth, revert the algebraic substitution:

(1 / 6) · √(2 · x + 3)³ - (3 / 2) · √(2 · x + 3)

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Answer:

33cm squared

Step-by-step explanation:

Answer:

33cm

Step-by-step explanation:

The inequality that represents the value of x is (b)  x > 80

from the question, we have the following parameters that can be used in our computation:

The figure

The general rule is that

The larger the side length, the larger the angle opposite it

using the above as a guide, we have the following:

1/8x > 10

So, we have

x > 80

Hence, the inequality is x > 80

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Answer:

116

Step-by-step explanation:

this is the correct answer

The radius of convergence is a-R a+R = 6+12 =18 and 6-12 = -6 for the |6x 12/<78 and diverges if |6x 12| 78.

The set of actual numbers x wherein the collection converges is the c program language period of convergence. If there exists a actual wide variety R such that the collection converges for |x−a|R, then R is the radius of convergence.

The radius of convergence is 1/2 of of the duration of the c program language period of convergence. If the radius of convergence is R then the c program languageperiod of convergence will consist of the open c program languageperiod: (a − R, a + R). To discover the radius of convergence, R, you operate the Ratio Test.

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Answer: is A

Step-by-step explanation:

Answer: kari makes 33 and 51 all together

Step-by-step explanation:

A minimum population size of approximately 7373 to achieve a 99% confidence interval with a margin of error of 3 and a known standard deviation of 100.

To calculate the minimum population size required to achieve a 99% confidence interval with a margin of error of 3 and a known standard deviation of 100, we can use the following formula:

n = [(z-value × SD) / ME]²

Where:

n = the minimum sample size required

z-value = the critical value for the desired confidence level (99% in this case)

SD = the known standard deviation (100 in this case)

ME = the desired margin of error (3 in this case)

First, we need to determine the z-value for a 99% confidence level. Using a standard normal distribution table, we find that the z-value for a 99% confidence level is approximately 2.576.

Substituting the values into the formula, we get:

n = [(2.576 × 100) / 3]²

Simplifying this expression, we get:

n = 7373.08

Therefore, we would need a minimum population size of approximately 7373.

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Answer:

Answer is 268435456

Step-by-step explanation:

use an = a × ^r n-1 to find the sequence

The 15th term of the given geometric progression sequence 1, -4, 16, ... will be 268435456.

A geometric progression is a sequence in which any element after the first is obtained by multiplying the previous element by a constant which is called a common ratio denoted by r.

For example, the sequence 1, 4, 16, 64,… is a geometric sequence with a common ratio of r = 4.

As per the given sequence,

1, -4, 16, ...

First term a = 1

Common ratio r = -4/1 = -4

The nth term is given as ar^(n - 1)

Therefore, the 15th term will be as,

a₁₅ = 1(-4)¹⁵⁻¹

a₁₅ = -4¹⁴ = 268435456

Hence "The 15th term of the given geometric progression sequence 1, -4, 16, ... will be 268435456".

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Answer:

The solution of the inequation \(6\cdot x^{2} \geq 10 + 11\cdot x\) is \(\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)\).

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

\(6\cdot x^{2} \geq 10 + 11\cdot x\)

\(6\cdot x^{2}-11\cdot x -10 \geq 0\)

\(6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0\)

Roots are found by Quadratic Formula:

\(r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}\)

\(r_{1} = \frac{5}{2}\) and \(r_{2} = -\frac{2}{3}\)

Then, the factorized form of the inequation is:

\(6\cdot \left(x-\frac{5}{2}\right)\cdot \left(x+\frac{2}{3} \right)\geq 0\)

By Real Algebra, there are two condition that fulfill the inequation:

a) \(x-\frac{5}{2} \geq 0 \,\wedge\,x+\frac{2}{3}\geq 0\)

\(x \geq \frac{5}{2}\,\wedge\,x \geq-\frac{2}{3}\)

\(x \geq \frac{5}{2}\)

b) \(x-\frac{5}{2} \leq 0 \,\wedge\,x+\frac{2}{3}\leq 0\)

\(x \leq \frac{5}{2}\,\wedge\,x\leq-\frac{2}{3}\)

\(x\leq -\frac{2}{3}\)

The solution of the inequation \(6\cdot x^{2} \geq 10 + 11\cdot x\) is \(\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)\).

Step-by-step explanation:

A 140

its obtuse. Hope this helps :)

Composite Functions for : f [ g (x) ] = 3 g(x) + 7 will be f [ g(x) ] = 3 ( 5x - 5) + 7 = 15x - 8

Common functions typically have a subset of the real numbers as their domain. Any integer from the domain may be used to replace a variable.

The domain of a composite function is determined by another function, not by a collection of numbers. We refer to it as "a result of another function. Example:

If: . f (x) = 3x + 7 . f [g(x)] must be found and simplified. g(x) = 5x - 5. Due to the fact that the domain of this function is a function of another function, f (x) is a simple function or just a function.

Let's make the example I gave previously simpler.

G (x) signifies in f "Replace x with g (x) in the function f (x). The Composite function f [g (x)]

we have : f [ g (x) ] = 3 g(x) + 7 . but . g( x) = 5x - 5

replace x in f[ g(x ) ] . by. 5x - 5 and simplify

f [ g(x) ] = 3 ( 5x - 5) + 7 = 15x - 8 **

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The question seems to be wrong

Evaluating Composite Functions for : f [ g (x) ] = 3 g(x) + 7

Errors:   Both of your upper bounds are wrong

               You subtracted the upper bound from the upper bound

Step-by-step explanation:

605 kg to the nearest 5 kg

lower bound is 602.5 (because it rounds up to 605)

upper bound is 607.4 (because it rounds down to 605)

Note: 607.5 would round up to 610

78 kg rounded to the nearest 1 kg

lower bound is 77.5 (because it rounds up to 78)

upper bound is 78.4 (because it rounds down to 78)

Note: 78.5 would round up to 79

Upper Bound - Lower bound is the maximum weight remaining on the elevator

607.4 - 77.5 = 529.9

529.9 ≤ 530 so YES the elevator is safe.

Answer:

A

Step-by-step explanation:

the answer is a because when it is simplified

Answer:

\(4jkl\)

Step-by-step explanation:

\( \frac{(64 {j}^{4} {k}^{8} {l}^{2}) ^ \frac{1}{2} }{(8 {j}^{3} {k}^{9}) ^{ \frac{1}{3} } } \\ \\ \frac{( {2}^{6} \times {j}^{4} \times {k}^{8} \times {l}^{2} ) ^{ \frac{1}{2} } }{ ({2}^{3} \times {j}^{3} \times {k}^{9}) ^{ \frac{1}{3} } } \\ \\ \frac{ {2}^{6 \times \frac{1}{2} } \times {j}^{4 \times \frac{1}{2} } \times {k}^{8 \times \frac{1}{2} } \times {l}^{2 \times \frac{1}{2} } }{ {2}^{3 \times \frac{1}{3} } \times {j}^{3 \times \frac{1}{3} } \times {k}^{9 \times \frac{1}{3} } } \\ \\ \frac{ {2}^{3} \times {j}^{2} \times {k}^{4} \times l}{2 \times j \times {k}^{3} } \\ \\ {2}^{(3 - 1)} \times {j}^{(2 - 1)} \times {k}^{(4 - 3)} \times l \\ \\ {2}^{2} \times j \times k \times l \\ \\ = 4jkl\)

Hope this helps you.

Let me know if you have any other questions :-):-)

Divide the cost for 4 nights by 4 to get cost per night.

260/4 = 65 per night.

Multiply cost per night by 7:

65 x 7 = 455

It would cost $455 for 7 nights.

The car was sold for 3429.5 cents and the percent discount from the original price is 14.265%.

According to the question,

We have the following information:

Beginning on day one, the owner discounts the price by 5% each day until it sells. On the third day the car sells. And the original price of the model car was $40.

The first day:

40*5/100

200/100

2

The price on the first day = $38

The second day:

38*5/100

190/100

1.9

The price on the second day = 38-1.9

The price on second day = 36.1

The third day:

36.1*5/100

180.5/100

1.805

The price on third day = $34.295 (36.1-1.805)

1 dollar = 100 cents

Price of car in cents = 3429.5 cents

B) Percent discount from the original price:

Let's take it to be x.

40 - (40x/100) = 34.295

-40x/100 = 34.295-40

-40x/100 = -5.705

40x = 570.5

x = 570.5/40

x = 14.265%

Hence, the car was sold for 3429.5 cents and the percent discount from the original price is 14.265%.

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Answer:

1) 2.5

2) 0.16

3) 9

4) 120

5) 48

6) 12,6

7) 54

8) 90

Answer:

y = 19.2

Step-by-step explanation:

We know there is relationship between y and x, so according to the formula \(y = kx\)

k = 12/5

we get one function y = 2.4x

when x = 8, input it into the function,

y = 2.4×8 = 19.2

Answer:

Step-by-step explanation:

n;

Convection; Radiation; Insulation.

PLTS/Gatsby:

Effective participants;

Independent Enquirers.

Compare group 1, 7 and 8 elements.

The BIG question

is… What is the trend in reactivity in the alkali metals, halogens and noble gases

sSHUTSHHHHHHHHHHHHHHUTUPPPPPPPPPPPPP

Answer:

153, 155, 93, 31, 78, 125, 150, 87, 157, 118, 67

Answer:

x=45

Step-by-step explanation:

i hope its right good luck :)

i think im wrong

Hello!

y = 88° (opposite are equal)

z = 180° - 128° = 52° (straight angle = 180°)

x = 180° - 140° = 40° (straight angle = 180°)

Answer:

x=40°

y=88°

z=52°

Step-by-step explanation:

Solution Given:

x+140°=180°

Since the sum of the angle of a linear pair or straight line is 180°.

solving for x.

x=180°-140°

x=40°

\(\hrulefill\)

y°=88°

Since the vertically opposite angle is equal.

therefore, y=88°

\(\hrulefill\)

z+128°=180°

Since the sum of the angle of a linear pair or straight line is 180°.

solving for z.

z=180°-128°

z=52°

The computed mean expenses of the XYZ Corporation based on the given information are 9,911.22.

The mean refers to the average value.

The mean is computed as the quotient that results from dividing the total value of the data set by the number of items in the set.

Name                      Total Sales      Total Expenses

Quezon City            14,950.00             4,933.50

Caloocan City         18,290.00             6,035.70

Marikina City          37,200.00           12,276.00

Cebu City                18,900.00            6,237.00

Davao City             45,000.00          14,850.00

Mandaluyong City 23,000.00           7,590.00

Cavite                     22,000.00          7,260.00

Laguna                    21,000.00          6,930.00

Manila                    66,000.00         21,780.00

Iloilo                       34,000.00          11,220.00

Total                                                  99,112.20

Mean Expenses = 9,911.22 (99,112.20 ÷ 10)

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Answer:

I think it's simple sentence

The correct answer is 3/2. In this case, x = 3/2, and its square, (3/2)^2 = 9/4, is rational. x satisfies the given condition.option (c)

To explain further, we need to understand the properties of rational and irrational numbers.

A rational number can be expressed as a fraction of two integers, while an irrational number cannot be expressed as a fraction and has non-repeating, non-terminating decimal representations.

In the given options, (a) √5102.0 (£) and (b) √2 are both irrational numbers.

Their squares, (√5102.0)^2 and (√2)^2, would also be irrational, violating the given condition. On the other hand, (d) 4/5 is rational, and its square, (4/5)^2 = 16/25, is also rational.

Option (c) 3/2 is rational since it can be expressed as a fraction. Its square, (3/2)^2 = 9/4, is rational as well.

Therefore, (c) 3/2 is the only option where x is rational, but its square is irrational, satisfying the condition mentioned in the question.

In summary, the number x that satisfies the given condition, where x^2 is irrational but x is rational, is (c) 3/2.option (c)

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On solving the given equation, we have - 125 adult tickets and 179= children tickets.

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated by the symbol "equal."

301= 104

6.40 =2.25

4.00=1.75

Suppose the number of adult ticket bought =x

And number of children tickets bought =  (301-x).

equation is

6.40(x) + 4(301-x) = 1504

6.40x + 1204 - 4x = 1504

2.40x = 300

x= 125

125 adult tickets and 179= children tickets.

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The number of dollars Laura should pay at the dinner party is $84.

Given that, the last time Laura hosted a fancy dinner party for her friends, she spent $108 to feed 9 people. This time, there will be only 7 people at the dinner party.

Proportion, in general, is referred to as a part, share, or number considered in comparative relation to a whole. The proportion definition says that when two ratios are equivalent, they are in proportion. It is an equation or statement used to depict that two ratios or fractions are equal.

Let the number of dollars paid by Laura for 7 people be x.

Now, 9:108::7:x

⇒9x=108×7

⇒x=12×7

⇒x=84

Therefore, the number of dollars Laura should pay at the dinner party is $84.

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The length of the segment is 2.4 centimeters.

The scale is 2.4 cm :24 mm.

How to change mm to cm?

One millimeter, or one-thousandth of a meter, is equal to one mm. One centimeter, also known as one hundredth of a meter, is equal to one centimeter.

Accordingly, 1 cm 10 mm. Divide the number of mm by 10 to get the number of cm when converting mm to cm.

Given that length of the segment is 24mm. now we know that,1 mm is equal to 0.1 cm,

So,

\(10 \: mm=1 \: cm \\ or, \: 1 \: mm = \frac{1}{10} \: cm \\ or, 24 \: mm × ( \frac{1}{10} ) = 2.4 \: cm.\)

The scale is 2.4 cm :24 mm.

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