: (a) Convert the hexadecimal number (FAFA.B) 16 into decimal number. (b) Solve the following subtraction in 2's complement form and verify its decimal solution. 01100101 - 11101000 (c) Boolean expression is given as: A +B[AC + (B+C)D (1) Simplify the expression into its simplest Sum-of-Product(SOP) form. (ii) Draw the logic diagram of the expression obtained in part (c)(i). (iii) Provide the Canonical Product-of-Sum(POS) form. (iv) Draw the logic diagram of the expression obtained in part (c)(iii).

Answer:

the police officer cruise each streets precisely once and he enters and exit with the same gate.

Explanation:

NB: kindly check below for the attached picture.

The term ''Euler circuit'' can simply be defined as the graph that shows the edge of K once in a finite way by starting and putting a stop to it at the same vertex.

The term "Hamiltonian Circuit" is also known as the Hamiltonian cycle which is all about a one time visit to the vertex.

Here in this question, the door is the vertex and the road is the edge.

The information needed to detemine a Euler circuit and a Hamilton circuit is;

"the police officer cruise each streets precisely once and he enters and exit with the same gate."

Check attachment for each type of circuit and the differences.

the police officer cruise each streets precisely once and he enters and exit with the same gate.

The relationship between the statements in the source code and the machine instructions that can be executed is also one to many in interpreted languages. True

A physical system known as a machine uses power to exert forces, control movement, and perform an action. The expression is widely used to describe both naturally occurring biological macromolecules, such as molecular machines, and man-made systems that utilise engines or motors. Humans, animals, wind, water, chemical, thermal, electrical energy, and other natural forces can all be used to push machines. Additionally, they have a set of mechanisms that modify the actuator input to generate specific output forces and movements. Mechanical systems, usually referred to as computers and sensors, that monitor activities and plan movement may also be included. Renaissance natural philosophers named the following as the six fundamental mechanisms that move a weight.

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Answer:

a

Explanation:

becasue it is

The type of relay that uses a thermistor to protect motor circuits is called a thermal overload relay. What is a thermal overload relay?A thermal overload relay is a protective gadget that switches off a motor if it overheats.

It guards the motor by tracking the heating of its windings. When an overload situation is detected, the thermal overload relay reacts by tripping a set of contacts to shut down the motor. The thermal overload relay is a control relay with a bimetal strip or a heater element that is sensitive to temperature changes .A thermal overload relay operates based on the principle of thermal memory.

The thermal overload relay's heating component is made up of a heater element and a bimetallic strip. When there is an overload, the heater component heats up the bimetallic strip, causing it to flex and trip the contacts, opening the circuit, and shutting down the motor. The heater component may be replaced or adjusted to fit the motor's current ratings.

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Answer:

a) \(h_c = 0.1599 W/m^2-K\)

b) \(H_{loss} = 5.02 W\)

c) \(T_s = 302 K\)

d) \(\dot{Q} = 25.125 W\)

Explanation:

Non horizontal pipe diameter, d = 25 cm = 0.25 m

Radius, r = 0.25/2 = 0.125 m

Entry temperature, T₁ = 304 + 273 = 577 K

Exit temperature, T₂ = 284 + 273 = 557 K

Ambient temperature, \(T_a = 25^0 C = 298 K\)

Pipe length, L = 10 m

Area, A = 2πrL

A = 2π * 0.125 * 10

A = 7.855 m²

Mass flow rate,

\(\dot{ m} = 4.5 tons/hr\\\dot{m} = \frac{4.5*1000}{3600} = 1.25 kg/sec\)

Rate of heat transfer,

\(\dot{Q} = \dot{m} c_p ( T_1 - T_2)\\\dot{Q} = 1.25 * 1.005 * (577 - 557)\\\dot{Q} = 25.125 W\)

a) To calculate the convection coefficient relationship for heat transfer by convection:

\(\dot{Q} = h_c A (T_1 - T_2)\\25.125 = h_c * 7.855 * (577 - 557)\\h_c = 0.1599 W/m^2 - K\)

Note that we cannot calculate the heat loss by the pipe to the environment without first calculating the surface temperature of the pipe.

c) The surface temperature of the pipe:

Smear coefficient of the pipe, \(k_c = 0.8\)

\(\dot{Q} = k_c A (T_s - T_a)\\25.125 = 0.8 * 7.855 * (T_s - 298)\\T_s = 302 K\)

b) Heat loss from the pipe to the environment:

\(H_{loss} = h_c A(T_s - T_a)\\H_{loss} = 0.1599 * 7.855( 302 - 298)\\H_{loss} = 5.02 W\)

d) The required fan control power is 25.125 W as calculated earlier above

Answer:

the amount of bleed steam required to heat 1 kg of feedwater in this unit is 0.078 kg/s

Explanation:

Given that:

Pressure of the feed water = 7000 kPa

Temperature of the closed feedwater heater = 260 ° C

Pressure of of the turbine = 6000 kPa

Temperature of the turbine = 325 ° C

The  objective is to calculate the amount of bleed steam required to heat 1 kg of feedwater in this unit.

From the table A-4 of saturated water temperature table at temperature  260° C at state 1 ;

Enthalpies:

\(h_1 = h_f = 1134.8 \ kJ/kg\)

From table A-6 superheated water at state 3 ; the value of the enthalpy relating to the pressure of the turbine at 6000 kPa and temperature of 325° C  is obtained by the interpolating the temperature between 300 ° C and 350 ° C

At 300° C; enthalpy = 2885.6 kJ/kg

At 325° C. enthalpy = 3043.9 kJ/kg

Thus;

\(\dfrac{325-300}{350-300}=\dfrac{h_{325^0}-{h_{300^0}}}{{h_{350^0}}- {h_{300^0}}}\)

\(\dfrac{325-300}{350-300}=\dfrac{h_{325^0}-2885.6}{3043.9-2885.6 }}\)

\(\dfrac{25}{50}=\dfrac{h_{325^0}-2885.6}{3043.9-2885.6 }}\)

\(h_{325^0} = 2885.6 + \dfrac{25}{50}({3043.9-2885.6 )\)

\(h_{325^0} = 2885.6 + 0.5({3043.9-2885.6 )\)

\(h_{325^0} =2964.75 \ kJ/kg\)

At pressure  of 7000 kPa at state 6; we obtain the enthalpies corresponding to the pressure at table A-5 of the saturated water pressure tables.

\(h_6 = h_f = 1267.5 \ kJ/kg\)

From state 4 ;we obtain the specific volume corresponding to the pressure of 6000 kPa at table A-5 of the saturated water pressure tables.

\(v_4 = v_f = 0.001319\ m^3 /kg\)

However; the specific work pump can be determined by using the formula;

\(W_p = v_4 (P_5-P_4)\)

where;

\(P_4\) = pressure at state 4

\(P_5\) = pressure at state 5

\(W_p = 0.001319 (7000-6000)\)

\(W_p = 0.001319 (1000)\)

\(W_p =1.319 \ kJ/kg\)

Using the energy balance equation of the closed feedwater heater to calculate the amount of bleed steam required to heat 1 kg of feed water ; we have:

\(E_{in} = E_{out} \\ \\ m_1h_1 +m_3h_3 + m_3W_p = (m_1+m_3)h_6\)

where;

\(m_1 = 1 \ kg\)

Replacing our other value as derived above into the energy balance equation ; we have:

\(1 \times 1134.8 +m_3 \times 2964.75 + m_3 \times 1.319 = (1+m_3)\times 1267.5\)

\(1134.8 + 2966.069 \ m_3 = 1267.5 + 1267.5m_3\)

Collect like terms

\(2966.069 \ m_3- 1267.5m_3 = 1267.5-1134.8\)

\(1698.569 \ m_3 =132.7\)

\(\ m_3 = \dfrac{132.7}{1698.569}\)

\(\mathbf{ m_3 = 0.078 \ kg/s}\)

Hence; the amount of bleed steam required to heat 1 kg of feedwater in this unit is 0.078 kg/s

The components of the reactions are: vertical reaction at point A, horizontal reaction at point A, and reaction at point B. The tension in the cable is the force exerted along the length of the cable.

In this scenario, the bent rod ACDB is supported by a sleeve at point A and a ball-and-socket joint at point B. When analyzing the system, we need to determine the components of the reactions and the tension in the cable.

Firstly, at point A, there are two reaction components: the vertical reaction and the horizontal reaction. The vertical reaction counteracts the weight of the rod and any additional forces acting downward. It ensures equilibrium in the vertical direction. The horizontal reaction, on the other hand, prevents the rod from sliding or moving horizontally. It maintains equilibrium in the horizontal direction.

Secondly, at point B, there is a reaction that allows the rod to rotate or pivot around the ball-and-socket joint. This reaction balances the moment caused by the weight of the rod and any other external moments.

Lastly, the tension in the cable refers to the force exerted along the length of the cable. This tension arises from the need to balance the vertical and horizontal forces acting on the rod. It ensures that the rod remains in a stable position and prevents it from collapsing under its own weight.

To accurately determine the components of the reactions and the tension in the cable, specific calculations and analysis of the forces and moments involved in the system would be required.

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In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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The work done on the gas during this process if the final pressure is 456 kPa is; -82.8 kJ

We are given;

The initial pressure; P₁ = 96 kPa

Final Pressure; P₂ = 456 kPa

The gas is compressed according to;

p = aV + b

where;

a = -1200 kPa/m³

b = 600 kPa

Thus, at initial pressure P₁ = 96 kPa;

96 = -1200V₁ + 600

1200V₁ = 600 - 95

1200V₁ = 505

V₁ = 505/1200

V₁ = 0.42 m³

At Final Pressure P₂ = 456 kPa;

456 = -1200V₂ + 600

1200V₂ = 600 - 456

1200V₂ = 144

V₂ = 144/1200

V₂ = 0.12 m³

Formula for the workdone during the process is;

W_out = ¹/₂(P₁ + P₂)(V₂ - V₁)

W_out = ¹/₂(96 + 456)(0.12 - 0.42)

W_out = -82.8 kJ

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Consider the four sub-cases for each of those three cases two positives, two negatives, one of each . Show that some of those sub-cases are not possible in each case. Then examine each sub-case to see if it indicates overflow.

Two's complement is a mathematical operation that converts a positive binary number with equivalent value reversibly into a negative binary number with equivalent value.

it occurs using the binary digit with the greatest place value to indicate whether the binary number is positive or negative.

Consider each of those three cases' four sub-cases. There are two positives and two negatives, with one of each.

Demonstrate that some of the sub-cases are not feasible in each case. Then, for each sub-case, determine whether it indicates overflow.

Thus, by this it can be proved that in a 2’s complement number system addition overflows if and only if the carry from the sign position does not equal the carry into the sign position.

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The question is incomplete. The complete question is :

The hydrofoil boat has an A-36 steel propeller shaft that is 100 ft long. It is connected to an in-line diesel engine that delivers a maximum power of 2590 hp and causes the shaft to rotate at 1700 rpm . If the outer diameter of the shaft is 8 in. and the wall thickness is \($\frac{3}{8}$\)  in.

A) Determine the maximum shear stress developed in the shaft.

\($\tau_{max}$\) = ?

B) Also, what is the "wind up," or angle of twist in the shaft at full power?

\($ \phi $\) = ?

Solution :

Given :

Angular speed, ω = 1700 rpm

                              \($ = 1700 \frac{\text{rev}}{\text{min}}\left(\frac{2 \pi \text{ rad}}{\text{rev}}\right) \frac{1 \text{ min}}{60 \ \text{s}}$\)

                              \($= 56.67 \pi \text{ rad/s}$\)

Power \($= 2590 \text{ hp} \left( \frac{550 \text{ ft. lb/s}}{1 \text{ hp}}\right)$\)

          = 1424500 ft. lb/s

Torque, \($T = \frac{P}{\omega}$\)

                 \($=\frac{1424500}{56.67 \pi}$\)

                 = 8001.27 lb.ft

A). Therefore, maximum shear stress is given by :

Applying the torsion formula

\($\tau_{max} = \frac{T_c}{J}$\)

        \($=\frac{8001.27 \times 12 \times 4}{\frac{\pi}{2}\left(4^2 - 3.625^4 \right)}$\)

      = 2.93 ksi

B). Angle of twist :

     \($\phi = \frac{TL}{JG}$\)

         \($=\frac{8001.27 \times 12 \times 100 \times 12}{\frac{\pi}{2}\left(4^4 - 3.625^4\right) \times 11 \times 10^3}$\)

         = 0.08002 rad

         = 4.58°

The number of hectares of each crop he should plant are; 250 hectares of Corn, 500 hectares of Wheat and 450 hectares of soybeans

He grows corn, wheat and soya beans on the farm of 1200 hectares. Thus;

C + W + S = 12   ----(1)

It costs $45 per hectare to grow corn, $60 to grow wheat, and $50 to grow soybeans. Thus;

45C + 60W + 50S = 63750  -----(2)

He will grow twice as many hectares of wheat as corn. Thus;

W = 2C    ------(3)

Put 2C for W in eq 1 and eq 2 to get;

C + 2C + S = 1200

3C + S = 1200     -----(4)

45C + 60(2C) + 50S = 63750

45C + 120C + 50S = 63750

165C + 50S = 63750    ------(5)

Solving eq 4 and 5 simultaneosly gives;

C = 250 and W = 500

Thus; S = 1200 - 3(250)

S = 450

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When the process is in control but does not meet specification, it is referred to as a special cause error.

In statistical process control, a process is considered to be in control when it operates within the defined limits and shows only random variations. However, when a process is in control but does not meet the desired specifications, it indicates the presence of a special cause error.

Special cause errors are attributed to specific factors or events that cause the process to deviate from the expected outcome. These errors are typically unpredictable and require investigation and corrective action to bring the process back within the desired specifications.

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Of the three types of hazard controls – engineering, administrative, and personal protective equipment (PPE) – PPE is the last line of defense: True.

OSHA is simply an abbreviation for occupational safety and health administration that was created under the Occupational Safety and Health Act, so as to develop work-safety standards for workers and providing precautionary measures against all workplace hazards.

Generally, there are three types of hazard controls and these include the following:

PPE is an acronym for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which offer protection to different parts of the body while working in a potentially hazardous environment.

Also, some examples of personal protective equipment (PPE) used to protect the different parts of the body are:

According to occupational safety and health administration (OSHA), the use of a faulty personal protective equipment (PPE) should be the last line of defense.

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Complete Question:

Of the three types of hazard controls – engineering, administrative, and personal protective equipment (PPE) – PPE is the last line of defense. True or False?

Answer:

Explanation:

If the museum is running short of funds, and you decide to increase revenue. An increase or decrease in the price of admission into the museum depends on the following:

1. If demand for admission into the museum is elastic there are two possible outcomes

a. An increase in the price of admission leads to a decrease in the quantity demand of admission into the museum

b. A decrease in price of admission into the museum leads to an increase in the quantity demand of admission into the museum.

This follows the law of demand which states that "the higher the price, the lower the quantity demanded and the lower the price, the higher the quantity demanded".

2. If the demand for admission into the museum is inelastic, then an increase in price will lead to an increase in revenue of the museum.

Therefore, before the curator increase the price of admission into the museum, he should first determine the price elasticity of demand of the museum.

In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.

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A heat pump can melt the ice that forms on the outdoor coil by initiating a defrost cycle. This process involves the following steps:

1. The heat pump detects ice build-up on the outdoor coil using temperature sensors.
2. The system's control board activates the defrost cycle when the sensors identify a significant amount of ice.
3. The heat pump reverses its operation, temporarily changing from heating mode to cooling mode. This means that the outdoor coil becomes the condenser, releasing heat instead of absorbing it.
4. The released heat from the outdoor coil melts the ice on its surface.
5. To avoid cooling the indoor space during the defrost cycle, the heat pump's auxiliary heat (usually an electric resistance heater) is activated to maintain the indoor temperature.
6. Once the ice has melted, the heat pump returns to its normal heating mode, and the outdoor coil resumes its function as an evaporator, absorbing heat from the outdoor air.

This defrost cycle ensures that the heat pump operates efficiently and prevents potential damage caused by ice build-up on the outdoor coil.

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A heat pump can melt the ice that forms on the outdoor coil using a defrost cycle.

During normal operation, the outdoor coil of a heat pump absorbs heat from the outside air, and this causes any moisture present in the air to freeze on the coil when the outdoor temperature is below freezing. This can reduce the efficiency of the heat pump and potentially damage the coil.

To prevent this, the heat pump uses a defrost cycle to melt the ice that has formed on the outdoor coil. The defrost cycle is triggered automatically by a temperature sensor, and it works by temporarily reversing the flow of refrigerant through the heat pump. This causes the indoor coil to become the condenser, and it generates heat that is used to melt the ice on the outdoor coil.

Once the ice has melted, the heat pump resumes normal operation, and the cycle continues. Defrost cycles are an essential feature of heat pumps in cold climates, where ice buildup on the outdoor coil can be a common problem.

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Answer: the normal longitudinal strain is most nearly 2.5 x 10⁻⁴ mm/mm

Explanation:

Given the data in the question,

we know that;

Normal longitudinal strain = elongation / original length

so we substitute our values

Normal longitudinal strain = 0.5 mm / (2 m x 1000) mm

= 0.5 mm / 2000 mm

= 2.5 x 10⁻⁴ mm/mm

Therefore the normal longitudinal strain is most nearly 2.5 x 10⁻⁴ mm/mm

The reaction at the beam support is 6300 N, and the moment at the beam support is -25200 N·m (negative sign indicates clockwise moment).

To determine the reactions and moments at the beam supports, we can use the principles of static equilibrium. Let's go through the step-by-step explanation:

Step 1: Identify the Given Information

We are given the following information:

- Load on the beam: F = 500 N/m and Fi = 1600 N/m

- Distance between supports: 4 m

Step 2: Calculate the Total Load on the Beam

To calculate the total load on the beam, we need to find the area under the load curve. In this case, the load is linear, so we can calculate the area of the trapezoid formed by the load curve.

Total load = Area of trapezoid = (0.5 * F + Fi) * distance between supports

Total load = (0.5 * 500 + 1600) * 4

Total load = 6300 N/m

Step 3: Determine the Reaction Forces

Since the beam is in static equilibrium, the sum of the vertical forces must be zero. This allows us to calculate the reaction forces at the beam supports.

Let's assume that the left support experiences a reaction force R1, and the right support experiences a reaction force R2.

ΣFy = 0:

R1 + R2 - Total load = 0

R1 + R2 = Total load

R1 + R2 = 6300 N

Step 4: Determine the Moments at the Beam Supports

To calculate the moments at the beam supports, we can use the principle that the sum of the moments about any point must be zero.

Taking moments about the left support (point A):

ΣMA = 0:

-Total load * distance between supports + R2 * distance between supports - Moment at left support = 0

-6300 * 4 + R2 * 4 - Moment at left support = 0

Moment at left support = -6300 * 4 + R2 * 4

Step 5: Substitute Known Values and Solve

Using the information from step 3, we can substitute the known values into the equation for the moment at the left support and solve for R2.

Moment at left support = -6300 * 4 + R2 * 4

Moment at left support = -25200 + R2 * 4

Since the reaction at the left support is given as 6300 N, we can solve for R2.

6300 = -25200 + R2 * 4

R2 * 4 = 31500

R2 = 7875 N

Therefore, the reaction at the right support is R2 = 7875 N, and the moment at the left support is -25200 N·m.

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A beam and its loeding is shown where F 500 N/m. Fi 1600 N/m 4. 5.00 points Determine the reactions and moments at the beam supports. (Round the reaction to the nearest whole number and the moment to one decimal place.,) The reaction at the beam support is 6300 N The moment at the beam support is kN m.

Both technicians are basically partially correct as per the given situation.

Active wheel-speed sensors are an essential component of braking systems. They detect vehicle rotational wheel speed using a non-contact measurement principle.

Technician A is correct in his assertion that wheel-speed sensors send an alternating current voltage signal to the control module.

The wheel-speed sensors generate an AC voltage signal proportional to the speed of the wheel using a toothed wheel or tone ring.

Technician B is partially correct in that the wheel speed signals generate an alternating current signal voltage by varying a reference voltage received from the control module.

Thus, both technicians are correct.

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Answer:

  a. vehicle color

Explanation:

One might expect that the cost of owning a vehicle would not be a function of its color. There is no reason to believe that a blue car gets better gas mileage than a green car of the same make, model, and equipment. So, the appropriate choice is ...

  a. vehicle color

__

However, vehicle color may play a role in ownership costs if more money is spent on washing a white car than would be spent on a black or beige car. Similarly, a light-colored car may require less use of an air-conditioner in the summer sun than does a dark-colored car, ultimately affecting fuel cost. It isn't always obvious what the features of a vehicle are that contribute to ownership cost.

The components of the reaction force in a ball and socket joint include the horizontal and vertical reaction forces.

A reaction force is an equal but oppositely directed force which forms a pair which the applied or action force.

Tension is a type of force which is present in a string or a rope supporting a body or object.

A ball and socket jont is a type of joint in the body which is able to rotate freely about an axis.

The components of the reaction force in a ball and socket joint include the horizontal and vertical reaction forces.

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Answer:

Explanation:

A. No, "A" will not detect the collision** based on the condition **dprop > l/r.

The condition dprop > l/r refers to the time taken for a signal to propagate across the link (dprop) being greater than the time it takes to transmit a packet (l) divided by the rate of transmission (r). This condition is used to determine if two packets will collide on a shared transmission medium.

However, "A" alone cannot detect collisions based on this condition. The reason is that "A" does not have access to the necessary information such as the propagation delay, packet length, or transmission rate.

Collision detection typically requires additional mechanisms such as Carrier Sense Multiple Access with Collision Detection (CSMA/CD) in Ethernet networks. CSMA/CD allows devices to listen to the transmission medium and detect if there is already ongoing transmission before sending their own packets. If a collision is detected, devices implement collision resolution procedures to handle the collision.

Therefore, "A" alone cannot detect collisions based on the condition dprop > l/r.

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Answer:

The answer "K = 0.0075"

Explanation:

If we try to measure up to 69 kPa of air, find mercury or fluid for gauge.  

While mercury was its largest liquid with a density of 13600 kg / m3 at normal room temperature.  

Let's all measure for 69 kPa that height of the  mercury liquid column.

\(\to P = 69 \ kPa\)

       \(= 69000 Pa \\\\\)

\(\to \rho = 13600 \ \ \frac{kg}{m^3} \\\\\\to g = 9.81 \ \ \frac{m}{s^2} \\\\\)

Formula:

\(\to P=\rho \ gh\)

\(\to 69000 = 13600\times9.81 \times h\\\\\to h= \frac{69000}{13600\times9.81} \\\\\to h= \frac{69000}{133416} \\\\\to h= 0.517179349 \\\\ \to h= 517 \ mm \\\\\)

The right choice for pressure measurements up to 69 kPa is mercury.  

Atmospheric Mercury up to 69 kPa Air 517 mm  

The relationship of Hg to Pa is = 134.22 Pa 1 mm Hg  

Static sensitivity to Pa of mm hg = change of mercury height to Pa:

\(= \frac{\Delta Hg }{ \Delta P }\\\\= \frac{1 }{ 133.3 }\\\\= 0.0075\)

Complete question:

The acceleration of a particle traveling along a straight line is a = 1/4 s^1/2 m/s^2, where s is in meters. If v = 0, s = 1 m when t = 0, determine the particle’s velocity at s = 2 m.

Answer:

The particle’s velocity is 0.781 m/s.

Explanation:

Given;

acceleration of the particle, \(a = \frac{1}{4} s^{\frac{1}{2}} \ m/s^2\) \(= 0.25s^{0.5} \ m/s^2\)

Acceleration is given by;

\(a = \frac{dv}{dt}\\\\a = \frac{dv}{dt} *\frac{ds}{ds} = \frac{ds}{dt}* \frac{dv}{ds}\\\\a = v*\frac{dv}{ds} \\\\ads = vdv\\\\\int\limits^s_1 {a} \, ds = \int\limits^v_0 {v} \, dv\\\\ \int\limits^s_1 {0.25s^{0.5}} \, ds = \int\limits^v_0 {v} \, dv\\\\\frac{1}{6} (s^{1.5} -1^{1.5}) = \frac{v^2}{2} \\\\v^2 = \frac{2}{6} (s^{1.5} -1^{1.5})\\\\v^2 = \frac{1}{3} (s^{1.5} -1^{1.5})\\\\when \ s= 2 m\\\\v^2 = \frac{1}{3} (2^{1.5} -1^{1.5})\\\\v^2 = 0.6095\\\\v = \sqrt{0.6095}\\\\v = 0.781 \ m/s\)

Therefore, the particle’s velocity at s = 2 m, is 0.781 m/s.

Answer:

Valvoline™ ZEREX™ Asian Vehicle has been designed to meet the requirements of Asian manufacturers, which specify a silicate free HOAT formula with a phosphate additive to protect their cooling systems from rust and corrosion. Available in both red and blue formulas to better match your Asian vehicle’s specific requirements.

Explanation:

ZEREX Asian Vehicle Antifreeze/Coolant is specifically formulated to meet the requirements of Asian vehicle manufacturers (Toyota , Lexus , Scion and others) requiring a red, silicate free Hybrid Organic Acid Technology (HOAT) with a phosphate additive.

Answer:poat formulation

Explanation:

Explanation:

I have asked question in my profile please tell me the answer

Answer:

The goal of the software is to observe the software behavior to meet its requirement expectation. In software engineering, validating software might be harder since client's expectation may be vague or unclear.

Explanation:

The Reynolds number for ethyl alcohol is 91,510

Reynolds number (Re) = density×velocity×diameter/viscosity

density of ethyl alcohol = 789kg/m^3, velocity = 5m/s, diameter = 1 in = 0.0254m, viscosity of ethyl alcohol = 0.001095Pa.s

Re = 789×5×0.0254/0.001095 = 91,510

The Reynold Number is a dimensionless quantity used to help predict fluid flow, and Dorothy learned about it through her studies of aeronautical engineering at Langley, where it is used to help with aerodynamic analysis and design.

The Reynold Number is a dimensionless number used in fluid mechanics to help predict flow patterns in a fluid flowing through a pipe or duct. It is defined as the ratio of inertial forces to viscous forces within the fluid, and it is a function of the fluid's velocity, its density, and the viscosity of the fluid.

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