A cord is wrapped around the rim of a solid uniform wheel 0. 280 m in radius and of mass 9. 60 kg. A steady horizontal pull of 50. 0 N to the right is exerted on the cord, pulling it off tangentially from the wheel. The wheel is mounted on frictionless bearings on a horizontal axle through its center

Part A) Compute the angular acceleration of the wheel

Part B) Compute the acceleration of the part of the cord that has already been pulled off the wheel

Part C) Find the magnitude of the force that the axle exerts on the wheel

Part D) Find the direction of the force that the axle exerts on the wheel

Part E) Which of the answers in parts A, B, C, and D would change if the pull were upward instead of horizontal?

Answers

Answer 1

The torque exerted on the wheel is 25 N·m.

The torque exerted on the wheel can be calculated using the formula:

Torque = force x radius

Given that the force applied to the cord is 50 N, and the radius of the wheel is 0.5 meters. Using the formula for torque, we can calculate that the torque exerted on the wheel is equal to the force applied multiplied by the radius of the wheel. We can plug these values into the formula to get:

Torque = 50 N x 0.5 m

Torque = 25 N·m

Therefore, the torque exerted on the wheel is 25 N·m.

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--The complete Question is, If a cord is wrapped around the rim of a solid uniform wheel with a radius of 0.5 meters, and a force of 50 N is applied to the cord, what is the torque exerted on the wheel? Assume no friction or slipping between the cord and the wheel. --


Related Questions

Question 10 of 10
Which is a contact force?
Minerai
O A. Friction slowing down a car
OB. A magnet pulling on a nail
OC. The Sun pulling on Earth
OD. Two electrons repelling each other

Answers

My answer is (A) “the friction slowing down a car

Explanation:

OC the sun pulling on earth

If a wave travels 50 meters south in 3 seconds, what is the velocity of the wave? Express your answer to the nearest whole number.

_________________ meters per second

Answers

The velocity is 17 m/s South.

Answer:

17

Explanation:

A car is driving at 35 m/s. It decides to accelerate at 4.5 m/s2 for 3 seconds. How fast is it now moving?
Please show work even if you are an online student. I know it takes time, but I promise it is worth it.
I have included the units in the answer already. Please only put the number round all answers to 2 decimal places
if possible.
final velocity =
m/s
Blank 1
Next Page
6
? ? ?

Answers

Answer:

48.5

Explanation:

vf = vi + at

vf = 35 + 4.5(3)

vf = 35 + 13.5

vf = 48.5 m/s

What is the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air?

A. 30. 2°F

B. 35. 1°F

C. 40. 4°F

D. 45. 6°F

Answers

The answer to the given question is option C: 40.4°F. Let's see the explanation below.How to find the temperature difference across a properly operating electric furnace?

]We know that the temperature difference across a properly operating electric furnace is given by:ΔT = (Q / (1.08 * CFM))where,Q is the rate of heat input in BTU/hr,1.08 is the factor to convert CFM to lb/min,and CFM is the rate of air flow in cubic feet per minute.So, here,ΔT = (Q / (1.08 * CFM))

Given,The rate of heat input = 10 kW = 34,120 BTU/hrThe rate of air flow = 900 CFMPlugging these values in the above equation, we get:ΔT = (34,120 / (1.08 × 900))ΔT = 40.4°FTherefore, the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air is 40.4°F. Hence, the main answer is option C.

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The temperature difference across the electric furnace is approximately 30.2°F (option A).

To calculate the temperature difference across the electric furnace, we can use the formula:

Temperature difference (ΔT) = Heat (Q) / (Airflow rate * Specific heat capacity * Density)

First, let's convert the power of the electric heater from kilowatts (kW) to watts (W):

10 kW = 10,000 W

Next, we need to determine the specific heat capacity of air. Typically, it is around 0.24 BTU/lb°F.

Since the given airflow rate is in cubic feet per minute (cfm), we need to convert it to pounds per minute (lb/min) using the density of air. The density of air at standard conditions is approximately 0.075 lb/ft³.

Converting 900 cfm to lb/min:

900 cfm * 0.075 lb/ft³ = 67.5 lb/min

Now we can substitute the values into the formula:

ΔT = 10,000 W / (67.5 lb/min * 0.24 BTU/lb°F * 0.075 lb/ft³)

Simplifying the equation:

ΔT = 10,000 W / (67.5 * 0.24 * 0.075) (lb/min * BTU/lb°F * lb/ft³)

Calculating the result:

ΔT ≈ 30.2°F

Therefore, the temperature difference across the electric furnace is approximately 30.2°F, which corresponds to option A.

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____ thermal mass walls help retain captured energy and slowly transfers to the inside.

Answers

Thermal mass walls help retain captured energy and slowly transfer it to the inside by making use of the property of "thermal mass." This property refers to the ability of a material to absorb and store heat energy. Materials with high thermal mass, such as concrete, brick, and stone, can effectively store heat during the day and gradually release it at night.

In the context of building design, thermal mass walls can enhance energy efficiency and maintain comfortable indoor temperatures. When sunlight or other heat sources warm the outer surface of these walls, the heat is absorbed by the high thermal mass materials. Throughout the day, the walls capture and store the heat energy, preventing it from entering the building's interior.

As temperatures drop in the evening, the heat stored within the walls is gradually released into the building, providing a stable and consistent source of warmth. This process helps to maintain comfortable indoor temperatures with less reliance on artificial heating systems, reducing energy consumption and associated costs.

In summary, thermal mass walls contribute to energy efficiency and indoor comfort by effectively capturing, storing, and slowly releasing heat energy. Their high thermal mass properties help to moderate temperature fluctuations, providing a consistent source of warmth in colder periods and reducing the need for additional heating systems.

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A force of F= 45 N is used to drag a crate 3 m across a floor.

A force of F= 45 N is used to drag a crate 3 m across a floor.

Answers

ANSWER:

(a) 108 J

(b) 0 J

(c) 108 J

STEP-BY-STEP EXPLANATION:

(a)

Express the relation between horizontal component of work done and force on the crate:

\(W_h=F_h\cdot d\)

Here Wh is the horizontal component of the work done on the crate and Fh is the horizontal component of force and d is the distance of the crate across the floor.

Replacing:

\(\begin{gathered} W_h=36\cdot3 \\ W_h=108\text{ J} \end{gathered}\)

(b)

Express the relation between vertical component of work done and force on the crate:

\(W_v=F_v\cdot d\)

Here Wv is the vertical component of the work done on the crate and Fv is the vertical component of force and d is the distance of the crate across the floor.

Replacing:

\(\begin{gathered} W_h=27\cdot0 \\ W_h=0\text{ J} \end{gathered}\)

(c)

Express the relation for total work done by the 45 N force:

\(\begin{gathered} W_{\text{total}}=W_h+W_v \\ \text{ replacing} \\ W_{\text{total}}=108+0 \\ W_{\text{total}}=108\text{ J} \end{gathered}\)

Problem 3: Consider two cylindrical objects of the same mass and radius. Object A is a solid cylinder, whereas object B is a hollow cylinder.How fast, in meters per second, is object B moving at the end of the ramp if it rolls down the same ramp?Numeric : A numeric value is expected and not an expression.VR =

Answers

Since object A and object B have the same mass and radius, we can plug in the values for I into the formula for VR and compare the two:

VR_A = √(2gh/((1/2)MR^2))
VR_B = √(2gh/(MR^2))

The speed of object B, a hollow cylinder of the same mass and radius as a solid cylinder, rolling down a ramp can be determined by the formula: VR = √(2gh). Where VR is the velocity of the object at the end of the ramp, g is the acceleration due to gravity, and h is the height of the ramp. Therefore, to get the speed of object B in meters per second, we must first calculate the acceleration due to gravity, then the velocity of the object at the end of the ramp.
The speed of object B at the end of the ramp can be determined using the formula for the velocity of a rolling object: VR = √(2gh/I), where g is the acceleration due to gravity, h is the height of the ramp, and I is the moment of inertia of the object.

For a solid cylinder, the moment of inertia is I = (1/2)MR^2, where M is the mass of the object and R is the radius. For a hollow cylinder, the moment of inertia is I = MR^2.

Since object A and object B have the same mass and radius, we can plug in the values for I into the formula for VR and compare the two:

VR_A = √(2gh/((1/2)MR^2))
VR_B = √(2gh/(MR^2))

Since the moment of inertia for object B is greater than the moment of inertia for object A, the velocity of object B at the end of the ramp will be less than the velocity of object A.

To find the numeric value of the velocity of object B at the end of the ramp, we would need to know the values of g, h, M, and R. Without these values, we cannot provide a numeric answer for the velocity of object B.

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derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire​

Answers

The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

How to explain the expression

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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What is the mass of a ball that is moving at 25 m/s and has 93.75 kg*m/s of momentum ?

Answers

Answer:

m = 3.75 [kg]

Explanation:

We must remember that momentum is defined as the product of mass by Velocity, therefore it can be represented by means of the following equation.

\(P=m*v\)

where:

P = momentum = 93.75 [kg*m/s]

m = mass [kg]

v = velocity = 25 [m/s]

Now replacing, we can clear the mass:

\(P=m*v\\m=P/v\\m=93.75/25\\m=3.75 [kg]\)

If Calcium has 2 valence electrons and Chlorine has 7 valence electrons, how many Cl-1 ions would need to combine with 1 Ca+2 ion?

Answers

Answer:

CALCIUM IDENINE ADEININE AND PHOSPHATE

Explanation:

A wave has a frequency of 900 Hz and a wavelength of 200 m. At what speed is this wave traveling?

Answers

Answer:

The velocity of the wave is, v = 180,000 m/s

Explanation:

Given data,

The frequency of the wave, f = 900 Hz

The wavelength of the wave, λ = 200 m

The formula for the speed of the wave when the frequency and wavelength are known,

                               v = λ x f

Substituting the given values in the above equation,

                               v = 200 m x 900 Hz

                                v = 180000 m/s

Hence, the velocity of the wave is, v = 180,000 m/s

A point charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram. a field of circles labeled b. there is a positively charged particle with a velocity vector pointing 37 degrees north of east labeled v. what is the magnitude of the magnetic force acting on the charge? 6.6 × 10–3 n 4.9 × 10–3 n 4.9 × 103 n 6.6 × 103 n

Answers

The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

What is magnetic force?

Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:

\(\rm F=qvBsin\theta\)

where

The magnitude of the charge   \(q=5.7\ \mu C =5.7\times 10^{-6} \ C\)

The velocity of the charge        \(v=4.5\times 10^5\ \frac{m}{s}\)

The magnitude of the magnetic field   \(3.2\ mT=0.0032\ T\)

The angle between the directions of v and B  \(\theta =90^o-37^o=53^o\)

By substituting the values we will get:

\(F=(5.7\times 10^}-6})(4.5\times 10^5)(0.0032)(Sin53^o)\)

\(F=6.6\times 10^{-3}\ N\)

Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

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Answer:

a - on edge

Explanation:

yes

Que se debe cumplir para que la tabla permanezca en equilibrio Es un balancin con dos niños el primero m1= 45kg el segundo m2=38kg Del centro a la izquierda existe una distancia de 160 CM Hallar la distancia del centro a la derecha

Answers

formula: m1 * d1 = m2 * d2

datos:

m1= 45 kg

d1= 160 cm

m2= 38 kg

d2= x

reemplazamos datos en formula:

45kg * 160cm = 38kg * d2

El 38 pasa al otro lado de la igualdad a dividir:

(45kg * 160cm) / 38 kg = d2

Resolvemos: (kg se cancela con kg, quedando solo los cm)

7200cm / 38 = d2

Resultado:

d2 = 189.5 cm

Respuesta: La condición que se debe cumplir es que la distancia del centro al niño de la derecha sea de 189.5cm

Kelplers 3 laws in your own words

Answers

According to Kepler's first law of planetary motion, planets revolve around the sun such that the sun is always at one of its foci. This law is also known as the law of orbits.

According to Kepler's Second Law of planetary motion, a planet will cover equal amounts of area in an equal period of time if a line is drawn from the sun to the planet. This implies that the planet moves more slowly away from the sun and faster towards it.

According to Kepler's third Law of Planetary Motion, the squares of the orbital periods of the planets are directly proportional to the cubes of their semi-major axes.

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n=Q/e formula of this?

Answers

Answer:

Its not just a mere formula . It tells a hell lot about charges .

q = ne . As you know , q stands for charge and e stands for charge on an electron . As for n , it represents an integer.

This whole q=ne thing represents quantisation of charge. The formula tells us that charge is quantized ( in the form of small packets)

Every body on this small earth has a charge which has to be an integral multiple of ‘e’ . So , we represent charge on a body(q) as

q=ne.

Hence the formula .

I hope you got what I want to say .

Thanks for reading .

What sort of math formula would I use to find a solution to a problem like this, please direct me!
A piece of music with a tempo of 100beats per minute (bpm) has a playing time of 3 minutes. The piece is edited to have a playing time of 120beats per minute.
How long will the edited piece play in minutes?
2 point 0 minutes
4 point 0 minutes
3 point 5 minutes
2.5 minutes

Answers

To listen to the music at a tempo of 110 beats per minute (bpm), it takes Pam approximately 3.6 minutes. Given that Pam uses 5 minutes to listen to the music at a tempo of 80 bpm when she feels unhappy.

We can determine the time it takes for her to listen to the music at a tempo of 110 bpm. We can set up a proportion to find the relationship between the two tempos: 80 bpm / 5 minutes = 110 bpm / x minutes To solve for x, we can cross-multiply:

Rounding to the nearest tenth, it takes Pam approximately 6.9 minutes to listen to the music at a tempo of 110 bpm. However, the options provided specify that the answer should be in minutes and rounded to the nearest tenth. Therefore, the answer would be 3.6 minutes This means that when Pam increases the tempo of the music to 110 bpm, it takes her approximately 3.6 minutes to listen to the entire piece.It's important to note that the calculation assumes a linear relationship between tempo and time, which may not always hold true in practice due to various factors such as individual preferences, interpretation, and variations within the music itself. However, for the purpose of this question, we can use the proportion to estimate the time.

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What is the magnitude BBB of the magnetic field at the location of the charge due to the current-carrying wire

Answers

The magnitude of the magnetic field at the location of the charge due to the current-carrying wire is given as B = μI/2πr.

What is magnetic field?

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.

magnetic field due to the current-carrying wire

The magnitude of the magnetic field at the location of the charge due to the current-carrying wire is calculated as follows;

B = μI/2πr

where;

I is the current in the wirer is the location of the magnetic fieldμ is permeability of free space

Thus, the magnitude of the magnetic field at the location of the charge due to the current-carrying wire is given as B = μI/2πr.

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What is the acceleration of the object?

What is the acceleration of the object?

Answers

a = (v - u)

t

v final velocity

u initial velocity

a = (10 - 40)

12

a = -30/12

a = -5/2 m/s²

This will be the deceleration.

What percentage of maximum heart rate should be the target in doing vigorous-intensity workout?
A. 77% and 93% C. 75% and 90%
B. 77% and 95% D. 77% and 100%​

Answers

Your ideal heart rate for vigorous intensity physical activity should be between 77% and 93% of your maximum heart rate. here option A is correct.

You should feel like you can do the activity for a longer period of time while the intensity is still low. You can educate your body to exercise for extended periods of time in this zone, which is all about increasing your endurance. Active Intensity. In general, you won't be able to speak for more than a few words without pausing to take a breath if you're engaging in vigorous-intensity activities. Running, jogging, or race walking. The American Heart Association recommends working at 70 to 85 percent of your maximal heart rate for a vigorous activity. Running is an example of a rigorous workout. at least 10 mph when cycling. carrying a large bag while moving quickly uphill.

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If the voltage of a circuit is 6V, and the power is 4W, what is its resistance?

Answers

Answer:

9 ohms

Explanation:

P = V²/R

R = v²/p = 6²/4 = 36/4 = 9 ohms.

The resistance is 9 Ohm.

To find the resistance, we need to know about the power in term of resistance and voltage.

What is the value of power in terms of resistance and voltage?We know that power=work/timeElectrostatics work is given as voltage ×charge. So, power=(Voltage×charge)/timeAgain, charge/time is given as current. So, power = Voltage×currentFrom Ohm's law, we know that current=voltage/resistance. So, power= voltage ²/resistance. What is the resistance, if power is 4W and voltage is 6V?Resistance in term of power and voltage is given as Resistance= voltage ²/powerSo, resistance=6²/4=36/4= 9 Ohm

Thus, we can conclude that the resistance is 9 Ohm.

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A force of 900 N pushes a wedge 0.10 m into a log. If the work done on the log is 50 J, what is the efficiency of the wedge?

Answers

Answer:

I'm fairly certain it's 1,800

Explanation:

The efficiency of the wedge with force F=900 N displaces the wedge 0.10 m is 55.55%  or 56%.

What is the efficiency of the machine?

The efficiency of the machine equals the ratio of output energy and input energy. It is also defined as the ratio of work done on a load by the machine to the work done on the effort by the machine.

A load is defined as the weight lifted by the machine. The effort is defined as the force applied to bring the desired change in the load. Work done is defined as the product of force and displacement.

The efficiency, η = Output power / Input power, and the highest efficiency of the machine is equal to one. The efficiency of the machine has no unit. The efficiency η = (Actual work done / Ideal work done) × 100.

From the given,

Force = 900 N

Displacement = 0.1 m

Work done = F × s = 900×0.1 = 90 J

Actual work done = 50 J

Efficiency,η = (50/90) × 100

           η  = 55.55 %

Thus, the efficiency of the wedge is 55.56%.

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which would be the most efficient manner in which to lift a heavy box? turn side to box and lift with one arm grasp box at arms length place one hand under box and one hand on top at arms length face box with elbows bent and arms close to body

Answers

The most efficient manner in which to lift a heavy box is to face the box with elbows bent and arms close to the body.

What is efficiency? Efficiency is the ratio of useful work done by a device to the total energy expended or heat consumed. Efficiency is a measure of the effectiveness with which a device does work.

In order to lift a heavy box, a certain posture must be maintained. Following is the correct way to lift a heavy box:

Face the box with elbows bent and arms close to the body.

Lifting a heavy box with proper posture is important for preventing injury. To lift a heavy box with proper posture, stand as close as possible to the box, feet hip-width apart, and squat down by bending the hips and knees. Once the arms are securely wrapped around the box, use the legs to lift the box off the ground, keeping the back straight and the box as close to the body as possible. This posture prevents the back from rounding, which can cause spinal injuries, and it also enables the arms and legs to work together, distributing the weight of the box more evenly. This posture is the most effective way to lift a heavy box, and it is essential to follow it to avoid injury.

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which has more momentum, a 5000 kg truck moving at 10 km per hour or a 1000 kg car moving at 50 km per hour?

Answers

The car has more momentum than the truck by 13,890 kg*m/s When a 5000 kg truck moves at 10 km per hour or a 1000 kg car moves at 50 km per hour.

To compare the momenta of the truck and car, we need to calculate their respective momenta using the formula:

momentum = mass x velocity

For the truck:

mass = 5000 kg

velocity = 10 km/h = 10,000/3600 m/s = 2.78 m/s

momentum = mass x velocity = 5000 kg x 2.78 m/s = 13,900 kg*m/s

For the car:

mass = 1000 kg

velocity = 50 km/h = 50,000/3600 m/s = 13.89 m/s

momentum = mass x velocity = 1000 kg x 13.89 m/s = 13,890 kg*m/s

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one unusual aspect of dark energy is ____. group of answer choices A) it's made of a material that has not yet been observed in our laboratories. B) it pushes outward on everything in the universe instead of pulling inward as gravity ordinarily does and it's made of a material that has not yet been observed in our laboratories. C) its pushes outward on everything in the universe instead of pulling inward as gravity ordinarily does. D) it exerts no gravitational force. E) it exerts a new kind of fundamental force, never observed before.

Answers

C) It pushes outward on everything in the universe instead of pulling inward as gravity ordinarily does.

Dark energy is a mysterious form of energy that permeates the entire universe, and it acts as a repulsive force, causing the expansion of the universe to accelerate.

Unlike gravity, which pulls objects closer together, dark energy pushes them apart.



Summary: One unusual aspect of dark energy is that it pushes outward on everything in the universe instead of pulling inward as gravity ordinarily does.

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all energy,potential kinetic within a specific system

a)joule

b) total energy

c) potential energy

Answers

Answer:

C

Explanation:

The potential and kinetic energy within a specific system is called the total energy of the system.

Option B is the correct answer.

Potential and Kinetic Energy

The energy of the specific system due to its steady position is defined as the potential energy of the system.

The energy of the system which is stored due to the motion of the system is called the kinetic energy of the system.

The mechanical energy of the system is the total energy within the system including its kinetic and potential energy.

The sum of kinetic and potential energy is known as mechanical energy. An object's mechanical energy is defined as the total energy which is stored during its steady position and stored during the motion of the object.

Hence we can conclude that option B represents the correct answer for the given statement.

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A train is moving west with an initial velocity of 20m/s accelerates at 4m/s for 10 seconds during this time the train moves a distance ​

Answers

Answer:

400m

Explanation:

From Newton's law of motion;

S = ut + 1/2 at2

Where U is initial velocity

a is acceleration

t is velocity hence;

S is distance covered

S = 20×10 + 1/2 × 4×(10)^2

= 200 + 200 = 400m

Anyone know? /——&/&:&:&:!:’dnndndndnd

Anyone know? /&/&:&:&:!:dnndndndnd

Answers

Answer:

Explanation:

1.25 m/s

The answer is 1.25 m/s.

Identical twins Kate and Karen are rowing their boat on a hot Summer afternoon when they decide to go for

a swim. Kate, whose mass is 45 kilograms, jumps off the front of the boat at a speed of 3. 00 m/sec. Karen

jumps off the back at a speed of 4. 00 m/sec. If the 70-kilogram rowboat is moving at 1. 00m/s when the girls

jump, what is the speed of the rowboat after the girls jump?

Answers

Given that identical twins Kate and Karen are rowing their boat on a hot summer afternoon when they decide to go for a swim. Kate, whose mass is 45 kilograms, jumps off the front of the boat at a speed of 3.00 m/sec. Karen jumps off the back at a speed of 4.00 m/sec.

If the 70-kilogram rowboat is moving at 1.00 m/s when the girls jump, then we have to determine the speed of the rowboat after the girls jump.Let V be the speed of the boat after the girls jump.Since there is no external force acting on the boat-girls system, the total momentum of the system will be conserved.Momentum before the jump = Momentum after the jumpInitial momentum = m1v1 + m2v2where m1 is the mass of Kate, m2 is the mass of Karen, v1 is the velocity of Kate and v2 is the velocity of Karen.

Initial momentum of the system before the jump = (45 × 3) + (45 × 4) + (70 × 1) = 585 kg m/sFinal momentum of the system after the jump = (45 × V) + (- 45 × V) + (70 × V) = 70V kg m/sMomentum before the jump = Momentum after the jump585 = 70VV = 585/70V = 8.36 m/sTherefore, the speed of the rowboat after the girls jump is 8.36 m/s.

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Who may perform a post-exposure medical evaluation?

A) A licensed physician


B) An LPN


C) A physician's assistant


D) Your employer

Answers

Answer:a licensed physician

Explanation: taking the osha test now.

A licensed physician is the one to carry out a post-exposure medical evaluation. (Option A)

Post-Exposure Medical Evaluation

Post-exposure Medical Evaluation is any medical evaluation started after exposure to a pathogen in order to prevent the infection from occurring.

Read more on Post-Exposure Medical Evaluation:

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help please, thank you :)

help please, thank you :)

Answers

Stop putting links if she can click on them
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