A cork weigh 2.5 gf in air. When tied to a sinker , the total weight is 20 gf in water. If the sinker alone weighs 25gf in water, find the density of the cork

Answer:

D. 72.9 cm/s towards the wall

Answer:

\(11.3\ \text{g/cm}^3\)

\(7.92\ \text{g/cm}^3\)

\(238.1\ \text{cm}^3\)

Explanation:

8) Volume of lead

\(V=4.5\times 5.2\times 6\\\Rightarrow V=140.4\ \text{cm}^3\)

m = Mass of block = 1587 g

Density is given by

\(\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{1587}{140.4}\\\Rightarrow \rho=11.3\ \text{g/cm}^3\)

Density of lead is \(11.3\ \text{g/cm}^3\)

9) Volume of lead = Volume of water displaced = (49.1-45.5) = 3.6 mL = \(3.6\ \text{cm}^3\)

m = Mass of iron = 28.5 g

Density is given by

\(\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{28.5}{3.6}\\\Rightarrow \rho=7.92\ \text{g/cm}^3\)

The density of iron is \(7.92\ \text{g/cm}^3\)

10) m = Mass of silver = 2500 g

\(\rho\) = Density of silver = \(10.5\ \text{g/cm}^3\)

Volume is given by

\(V=\dfrac{m}{\rho}\\\Rightarrow V=\dfrac{2500}{10.5}\\\Rightarrow V=238.1\ \text{cm}^3\)

The volume of silver is \(238.1\ \text{cm}^3\)

The argon molecules become solid when the temperature decrease from 20C to -190 C.

The changes in arrangement and movement of the particles of the argon occurs as the temperature of the air decreased because the argon gas begins to freeze. The freezing point of argon is -189 Celsius so when the temperature decrease from 20C to -190 C, the argon molecules becomes solid.

So we can conclude that the argon molecules become solid when the temperature decrease from 20C to -190 C.

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Answer:

Original fundamental frequency = 311.111 Hz (Approx)

Explanation:

Given:

Frequency (f) = 560 Hz

3rd harmonic

Used length = 60%

Find:

Original fundamental frequency.

Computation:

Fundamental frequency = Frequency (f) / 3rd harmonic

Fundamental frequency = 560 / 3

Original fundamental frequency = 560 / 3(60%)

Original fundamental frequency = 560 / 1.8

Original fundamental frequency = 311.111 Hz (Approx)

Answer:

473.8miles/hr

Explanation:

Given parameters:

Time of flight  = 4hrs

Distance traveled  = 1895miles

Unknown:

Speed of the plane  = ?

Solution:

Speed is the rate of distance covered per unit of time.

It is expressed as:

        Speed  = \(\frac{distance}{time}\)  

So;

  Speed  = \(\frac{1895}{4}\)   = 473.8miles/hr

Answer:

Explanation:

arc length

el huevo so el cuerpo es calvario y fiebre

Definition: When an object moves in a circular path with uniform speed, the motion is called uniform circular motion.

ac=rv2=ω2r

Answer:

Your balloon has been expanding for 5 hours.

Explanation:

Your balloon has been expanding for 5 hours.

Answer:

RT = 341.62 Ohms

Explanation:

Given the following data;

R1 = 420 Ohms

R2 = 320 Ohms

R3 = 160 Ohms

To find the equivalent resistance;

From the circuit, we can see that R1 and R2 are connected in parallel;

Mathematically, the total equivalent resistance of resistors connected in parallel is given by the formula;

\( RT = \frac {R1*R2}{R1 + R2} \)

Substituting into the formula, we have;

\( RT1 = \frac {420*320}{420 + 320} \)

\( RT1 = \frac {134400}{740} \)

RT1 = 181.62 Ohms

Next, we resolve the resistors to form a series circuit.

RT = RT1 + R3

RT = 160 + 181.62

RT = 341.62 Ohms

a) The width of the first-order bright fringe for 660nm light is 12.3 mm

b)  The width of the first-order bright fringe for 470nm light is 8.85 mm.

c) The distance between the first-order bright fringe for each wavelength is 3.45 mm.

(a) To find the width of the first-order bright fringe for 660nm light, we can use the formula:

w = λL/d

where w is the width of the fringe, λ is the wavelength of the light, L is the distance between the slits and the screen, and d is the distance between the slits.

Substituting the values, we get:

w = (660 x 10^-9 m) x (5.10 m) / 0.270 x 10^-3 m

w = 1.23 x 10^-2 m or 12.3 mm

Therefore, the width of the first-order bright fringe for 660nm light is 12.3 mm.

(b) Similarly, to find the width of the first-order bright fringe for 470nm light, we can use the same formula:

w = λL/d

Substituting the values, we get:

w = (470 x 10^-9 m) x (5.10 m) / 0.270 x 10^-3 m

w = 8.85 x 10^-3 m or 8.85 mm

Therefore, 8.85 mm  is the width of the first-order bright fringe for 470nm light.

(c) The distance between the first-order bright fringe for each wavelength can be found by subtracting the position of the 470nm fringe from the position of the 660nm fringe:

Δx = w660 - w470

Δx = (1.23 x 10^-2 m) - (8.85 x 10^-3 m)

Δx = 3.45 x 10^-3 m or 3.45 mm

Therefore, the distance between the first-order bright fringe for each wavelength is 3.45 mm.

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The amount of work done by the gravitational field of the earth do on the rock is 166.6d (J).

Work is done when energy is transferred from one store to another.

Work is also done when a force causes an object to move.

The amount of work done by the gravitational field of the earth do on the rock is calculated as follows;

W = Fd

where;

W = (mg)d

W = (17 x 9.8)d

W = 166.6d

Thus, the amount of work done by the gravitational field of the earth do on the rock is 166.6d (J).

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The part of the microscope that the objectives are attached to is called the (C) nosepiece.

The nosepiece is a rotating mechanism located below the microscope's body tube. It holds the objectives, which are the lenses responsible for magnifying the specimen. The nosepiece typically has multiple positions, allowing the user to switch between different objective lenses for varying levels of magnification.

This convenient feature eliminates the need to manually remove and replace objectives when changing magnification. By rotating the nosepiece, different objectives can be brought into position above the specimen. This allows for quick and efficient adjustments in magnification without disrupting the viewing process.

Hence, the nosepiece plays a critical role in the microscope's functionality by providing a convenient way to switch between objectives and adjust the magnification level.

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Here is the complete question:

What is the name of the part of the microscope that the objectives are attached to? (Choose the best answer)

A. Ocular

B. Stage

C. Nosepiece

D. Arm

The angle of the first-order maximum (constructive interference) for 450-nm wavelength blue light falling on double slits separated by 0.0500 mm is 10.47 degrees.

The angle of the first-order maximum can be calculated using the formula,

θ = mλ/d

Where θ is the angle

m is the order of the maximum

λ is the wavelength

d is the slit separation.

Plugging in the given values, we get:

θ = 1 * 450 nm / 0.0500 mm

θ = 9000 nm/mm

Converting to degrees, we get:

θ = 9000 nm/mm * (1 rad/1000 nm) * (180°/π rad)

θ = 10.47 degrees

Therefore, the angle of the first-order maximum (constructive interference) for 450-nm wavelength blue light falling on double slits separated by 0.0500 mm is 10.47 degrees.

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Answer:

Friction

Explanation:

In the event that the power is applied toward the path inverse to the bearing of movement, it goes against the movement of the item and henceforth the speed of the article diminishes.

Then, in the event that the thing continues to move one way, grinding will dominate and go about as the moving variable.

So, the moving factor would be friction.

Water has a high specific heat, thus it takes a lot of heat to raise its temperature. This keeps the surroundings from getting overly hot or chilly.

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The net rates of reaction for all components and the expression for instant selectivity are determined. The concentration of P over time in a batch reactor is derived, and the conditions for maximum concentration of P are discussed based on the rate-determining step.

a. The net rate of reaction for component A is given by -11 = -0.025 mol of A/(L.min), as it is a zero order reaction. The net rate of reaction for component P is given by -12 = K2 * Cp = 0.0075 CP mol of P/(L.min), as it is a first order reaction. The net rate of reaction for component B can be calculated by considering the stoichiometry of the two steps.

The instant selectivity is the ratio of the net rate of production of P to the net rate of consumption of A, which can be expressed as selectivity = -12 / -11.

b. Based on material balances for a batch reactor, the rate of change of concentration of P over time (dCp/dt) can be expressed as (dCp/dt) = -2 * (-12) = 0.015 CP mol/(L.min), using the stoichiometry of the reaction.

c. To determine the conditions for maximum concentration of P, we need to consider the rate-determining step. Since the second step is first order, it determines the overall rate of the reaction. To maximize the concentration of P, we need to maximize the rate of the second step. This can be achieved by increasing the concentration of P or the concentration of B while keeping the other reactants at their initial concentrations.

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(A) The pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.
(B) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow

(a) The pressure transients at the mid-point of the pipeline can be calculated using the water hammer equation. Water hammer refers to the sudden changes in pressure and flow rate that occur when there are rapid variations in fluid flow. The equation is given by:

ΔP = (ρ × ΔV × c) / A

Where:

ΔP = Pressure change

ρ = Density of water

ΔV = Change in velocity

c = Wave speed

A = Cross-sectional area of the pipe

First, let's calculate the change in velocity:

ΔV = Q / A

Q = Flow rate = 0.12 m/s

A = π × ((d/2)^2 - ((d-2t)/2)^2)

d = Internal diameter of the pipe = 300 mm = 0.3 m

t = Pipe wall thickness = 5 mm = 0.005 m

Substituting the values:

A = π × ((0.3/2)^2 - ((0.3-2(0.005))/2)^2

A = π × (0.15^2 - 0.1495^2) = 0.0707 m^2

ΔV = 0.12 / 0.0707 = 1.696 m/s

Next, let's calculate the wave speed:

c = √(E / ρ)

E = Young's modulus of steel = 210x10^9 Pa

ρ = Density of water = 1000 kg/m^3

c = √(210x10^9 / 1000) = 4585.9 m/s

Finally, substituting the values into the water hammer equation:

ΔP = (1000 × 1.696 × 4585.9) / 0.0707 = 1,208,277 Pa

Therefore, the pressure transients at the mid-point of the pipeline are approximately 1,208,277 Pa.

(b) Friction in the pipeline affects the calculated pressure transients by increasing the overall resistance to flow. As water moves through the pipe, it encounters frictional forces between the water and the pipe wall. This friction causes a pressure drop along the length of the pipeline.

The presence of friction results in a higher effective wave speed, which affects the calculation of pressure transients. The actual wave speed in the presence of friction can be higher than the wave speed calculated using the Young's modulus of steel alone. This higher effective wave speed leads to a reduced pressure rise during the transient event.

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The correct statement of Newton's Second Law is: An object's acceleration is inversely proportional to its mass and proportional to the net force acting on it.

Newton's Second Law of Motion states that the force acting on an object is directly proportional to the mass of the object and its acceleration. In other words, the greater the force applied to an object, the greater its acceleration, and the greater the object's mass, the less it will accelerate for a given force.

This law is often expressed mathematically as F = ma, where F is the force applied to an object, m is the object's mass, and a is its acceleration.

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Answer:

This is true fact.

Well done bud keep up the hard work at school

true As a non-zero net force

Answer:

The differences that will be observed are;

1) The Sun will become faint and will no longer be yellow but rather appear white and will no longer be visible (become invisible) by unassisted vision as we can see the Sun today

2) The size of the Sun will shrink to a size comparable to the size of the Earth

3) The Sun will cool down and will no longer radiate as much heat

4) The nuclear reactions that generate energy on the Sun's will seize and the and the heat from the Sun will be from residual thermal energy

5) The core, which is the hottest part of the Sun will no longer be hydrogen but carbon and oxygen

Explanation:

mU1 + mU2 = mV1 + mV2

(5 × 6) + (3 × 4) = 5V + 3V

30 + 12 = 8V

42 = 8V

V = 5.25m/s

The velocity of the ball after the collision is 5.25m/s.

While velocity refers to the speed and direction of an object's motion, speed is the rate at which an object moves along a path over time.

The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car traveling north on a highway or a rocket taking flight. The magnitude of the velocity vector's absolute value will always be equal to the motion's speed because it is a scalar.

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No, because water is an insulator and insulators cannot be polarized.

The student's claim that the water droplets become polarized by each sphere, causing some to be positively charged and some to be negatively charged, is incorrect. This is because water is an insulator and insulators cannot be polarized.

Polarization occurs in materials with free charges that can rearrange in response to an electric field. When an electric field is applied to a polarizable material, such as a dielectric, the charges within the material can shift, resulting in the separation of positive and negative charges. However, water is a poor conductor of electricity and does not have freely moving charges that can respond to an electric field in this manner.

In the given scenario, the spheres have charges of +Q and -Q, respectively. While these charges can exert attractive forces on nearby objects, including water droplets, the interaction is not due to polarization of the water droplets. Instead, it is a result of the electric field created by the charged spheres.

It's important to note that even though the water droplets are not polarized, they can still experience attractive forces towards the charged spheres. This attraction is due to the influence of the electric field on the charges within the water droplets.

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1.When the non-sticky sides of the two pieces of tape recording are brought together, they repel each other. This is due to the buildup of electric charge on the  face of the tape recording when it was  hulled off from the flat  face.

2.The pieces didn't change when the tape recording was from different sets.  When two top or two  nethermost pieces of tape recording are brought together, they repel each other.

3.When a top and  nethermost piece of tape recording are brought together, they attract each other. This is  harmonious with the actuality of only two types of charge, positive and negative. The results support the fact that the top and  nethermost pieces of tape recording had  contrary charges.  The top tape recording attracted the arm hair, while the bottom tape recording didn't attract the arm hair. Arm hair is  generally neutral, but it can be  concentrated by the electric field of the charged tape recording.

4.The top tape recording is negatively charged, and it  concentrated the arm hair, which has a positive charge. This redounded in  magnet between the top tape recording and the arm hair.  The pieces of tape recording labeled" T1" and" B2" are  appreciatively charged, while the pieces of tape recording labeled" B1" and" T2" are negatively charged. This can be determined from the  compliances.

5.When the  appreciatively charged tape recording was brought  near to a negatively charged tape recording, they attracted each other. When two  appreciatively charged  videotapes or two negatively charged  videotapes were brought  near together, they repelled each other.  Like charges repel each other,  contrary charges attract each other, and neutral bodies aren't affected by electric fields.  

6.The force of  magnet or aversion between the pieces of tape recording increases as they get  near together and decreases as they move  further  piecemeal. This change happens gradationally, not  snappily.      

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0.02 m/s^2  is the acceleration due to gravity if a 80 g ball is dropped and experiences a force of gravity of -1.96n

F=mg

-1.96=80×g

g=-1.96/80

g=0.02 m/s^2

Acceleration is a vector quantity that describes how quickly an object changes its velocity. An object is said to be accelerating if its velocity is changing. The distance traveled over time is not a constant value, it can be claimed, because accelerating objects are constantly changing their velocity.

For example, a falling object often plummets more quickly. A free-falling item would average a velocity of roughly 5 m/s in the first second, 15 m/s in the second, 25 m/s in the third, 35 m/s in the fourth, etc., if we were to observe it in motion. Our falling object would be descending at an accelerating rate.

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\( \LARGE{ \underline{\underline{ \sf{\pink{Required \: answer:}}}}}\)

Step-by-step Explanation:

Momentum is given by the product of mass and velocity of any object.

We have:

Then, Momentum:

= 0.1 kg × 55 m/s

= 5.5 kg m/s (Ans)

~ \( \large{ \pink{ \sf{FadedElla}}}\)

A movement from Y to Z results from plastic production technology advancements.

What induces motion along the PPC?

If resources are finite and constant, the move along a PPC through one point to the next shows that more of either good can only be generated by giving production up of the second good.

Is there a rise in plastic manufacture globally?

1950 2021: worldwide plastic output. In 2021, the output of plastics on a global scale was projected to reach 390.7 million metric tons, a rise of 4% annually. Since the 1950s, plastics production has exploded. The extraordinary adaptability of this class of materials is what drives their yearly production increases.

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Answer:

A: Scientists agree that the earth's rising temperatures are fueling longer and hotter heat waves, more frequent droughts, heavier rainfall, and more powerful hurricanes.

Explanation:

Explanation:

i will use chainsaw to cut a tree and even if that doesn't work I will use axe to make my work easy.

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have a great day :)

Answer:

The mass=0.169

The height=57.8

The power=1.63 watts

Explanation:

The formula for mass is 2KE/v^2

v=34×34 KE=98 therefore 2*98/34^2=0.169

The formula for height is v^2/2g

v=34*34 therefore 34^2/2*10=57.8

The formula for power is work/time

in which the work is the kinetic energy =98

and time 1*60secs =60 therefore 98/60=1.63watts