a counsellor, new to college was informed that students register an average of 13.6 credits each semester. assume the standard deviation of credits registered is 2.1 credits. the counsellor who wants to check, randomly samples 45 students, collects the credits registered by them this semester and computes sample mean (average).

Answer:

Step-by-step explanation:

\(\dfrac{3+x}3=\dfrac{20}5\\\\3+x = 4\cdot3\\\\x=12-3 \\\\x= 9\)                               \(\dfrac{4+y}4=\dfrac{20}5\\\\4+y= 4\cdot4\\\\y=16-4 \\\\y=12\)

\(\dfrac{3+x+u}3=\dfrac{60}5\\\\3+9+u=12\cdot3\\\\u=36-12 \\\\u=24\)                      \(\dfrac{4+y+v}4=\dfrac{60}5\\\\4+12+v=12\cdot4\\\\v=48-16 \\\\v=32\)

Answer:

0.00375 meters per second,

Step-by-step explanation:

0.00375 meters per second, we know this is the answer because, 4.25*60=255 and 255/11.2=0.00375

The limits are:

1. \(\(\lim _{x \rightarrow 1} \frac{\sqrt{x}-1}{x-1} = \frac{1}{2}\)\)

2. \(\(\lim _{x \rightarrow 1}\left(\frac{1}{x^{2}-1}-\frac{2}{x^{4}-1}\right) = \frac{-1}{2}\)\)

3. \(\(\lim _{h \rightarrow 0} \frac{f(2+h)-f(2)}{h} = \frac{1}{2}\sqrt{2}\)\)

To evaluate the limits provided, we'll analyze each one separately:

1. \(\(\lim _{x \rightarrow 1} \frac{\sqrt{x}-1}{x-1}\)\)

We can simplify this expression by multiplying the numerator and denominator by the conjugate of the numerator, which is \(\sqrt{x} + 1\):

\(\(\lim _{x \rightarrow 1} \frac{\sqrt{x}-1}{x-1} \times \frac{\sqrt{x}+1}{\sqrt{x}+1}\)\\\(\lim _{x \rightarrow 1} \frac{x-1}{(x-1)(\sqrt{x}+1)}\)\\\(\lim _{x \rightarrow 1} \frac{1}{\sqrt{x}+1}\)\\\(\lim _{x \rightarrow 1} \frac{1}{\sqrt{1}+1} = \frac{1}{2}\)\)

Therefore, the value of the limit is \(\(\frac{1}{2}\)\).

2. \(\(\lim _{x \rightarrow 1}\left(\frac{1}{x^{2}-1}-\frac{2}{x^{4}-1}\right)\)\)

To evaluate this limit, we can factor the denominators:

\(\(\lim _{x \rightarrow 1}\left(\frac{1}{(x-1)(x+1)}-\frac{2}{(x^{2}-1)(x^{2}+1)}\right)\)\\\(\lim _{x \rightarrow 1}\left(\frac{1}{(x-1)(x+1)}-\frac{2}{(x-1)(x+1)(x^{2}+1)}\right)\)\\\(\lim _{x \rightarrow 1}\left(\frac{1}{x^{2}+1}-\frac{2}{x^{2}+1}\right)\)\\\(\lim _{x \rightarrow 1}\frac{-1}{x^{2}+1} = \frac{-1}{2}\)\)

Therefore, the value of the limit is \(\(\frac{-1}{2}\)\).

3. If \(\(f(x)=\sqrt{x}\)\), we are asked to find \(\(\lim _{h \rightarrow 0} \frac{f(2+h)-f(2)}{h}\)\).

Plugging in the given function, we have:

\(\(\lim _{h \rightarrow 0} \frac{\sqrt{2+h}-\sqrt{2}}{h}\)\)

To simplify this expression, we can multiply the numerator and denominator by the conjugate of the numerator, which is \(\(\sqrt{2+h}+\sqrt{2}\)\):

\(\(\lim _{h \rightarrow 0} \frac{(\sqrt{2+h}-\sqrt{2})(\sqrt{2+h}+\sqrt{2})}{h(\sqrt{2+h}+\sqrt{2})}\)\\\(\lim _{h \rightarrow 0} \frac{(2+h)-2}{h(\sqrt{2+h}+\sqrt{2})}\)\\\(\lim _{h \rightarrow 0} \frac{h}{h(\sqrt{2+h}+\sqrt{2})}\)\\\(\lim _{h \rightarrow 0} \frac{1}{\sqrt{2+h}+\sqrt{2}}\)\\\(\lim _{h \rightarrow 0} \frac{1}{\sqrt{2+0}+\sqrt{2}} = \frac{1}{2\sqrt{2}} = \frac{1}{2}\sqrt{2}\)\)

Therefore, the value of the limit is \(\(\frac{1}{2}\sqrt{2}\)\).

Complete Question:

1. \(\(\lim _{x \rightarrow 1} \frac{\sqrt{x}-1}{x-1}\)\)

2. \(\(\lim _{x \rightarrow 1}\left(\frac{1}{x^{2}-1}-\frac{2}{x^{4}-1}\right)\)\)

3. If \(\(f(x)=\sqrt{x}\)\), find: \(\(\lim _{h \rightarrow 0} \frac{f(2+h)-f(2)}{h}\)\)

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Answer:

-----------------------------------------------

Let the cost of a 1 kg of apples be x.

Then pear costs x - 1.12 and banana costs x + 2.35.

The total cost is 25.02:

The probability of guessing randomly at least 8 correct answers in a 10 question multiple choice test where each question has 4 choices is 0.0385 or approximately 3.85%.

To find the probability of guessing at least 8 correct answers, we need to use the binomial probability formula:

P(X ≥ k) = 1 - P(X < k)

where

P(X ≥ k) is the probability of getting k or more correct answers

P(X < k) is the probability of getting less than k correct answers

n is the total number of questions in the test = 10

p is the probability of guessing the correct answer = 1/4

q is the probability of guessing the incorrect answer = 3/4

Now, we need to find the probability of getting less than 8 correct answers:

P(X < 8) = Σ P(X = k) for k = 0 to 7

P(X = k) = nCk * p^k * q^(n-k)

where nCk is the binomial coefficient for choosing k items from a set of n items.

P(X < 8) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 7)

P(X = k) = nCk * p^k * q^(n-k)

P(X = 0) = 10C0 * (0.25)⁰ * (0.75)¹⁰ ≈ 0.0563

P(X = 1) = 10C1 * (0.25)¹ * (0.75)⁹ ≈ 0.1875

P(X = 2) = 10C2 * (0.25)² * (0.75)⁸ ≈ 0.2813

P(X = 3) = 10C3 * (0.25)³ * (0.75)⁷ ≈ 0.2503

P(X = 4) = 10C4 * (0.25)⁴ * (0.75)⁶ ≈ 0.1450

P(X = 5) = 10C5 * (0.25)⁵ * (0.75)⁵ ≈ 0.0586

P(X = 6) = 10C6 * (0.25)⁶ * (0.75)⁴ ≈ 0.0161

P(X = 7) = 10C7 * (0.25)⁷ * (0.75)³ ≈ 0.0028

Therefore, P(X < 8) = 0.0563 + 0.1875 + 0.2813 + 0.2503 + 0.1450 + 0.0586 + 0.0161 + 0.0028 ≈ 1.0 - 0.0385 = 0.9615 or approximately 96.15%

The probability of guessing at least 8 correct answers:

P(X ≥ 8) = 1 - P(X < 8) ≈ 1 - 0.9615 = 0.0385 or approximately 3.85%

The problem seems incomplete, it must have been...

"Steve is taking a 10-question multiple choice test where each question has 4 choices. What is the probability that guessing randomly will give him at least 8 correct answers?"

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Answer:

Step-by-step explanation:

17/2=8.5

8.5 x 9=76.5

Answer:

y=-2x

Step-by-step explanation:

y-4=-2(x-(-2))

y-4=-2(x+2)

y-4=-2x-4

y=-2x-4+4

y=-2x

Answer:

third side = 10

I hope it's helps you

Answer:

Step-by-step explanation:

a. 110°

b. 70°

c. 110°

d. 70°

e. 110°

f. 70°

g. 110°

The value of $×$ is 3.14 units

Perimeter is the distance around the edge of a shape. The algebraic sum of the length of each side is the perimeter of that shape. We have formulas available for the various shapes in geometry.

The perimeter of a square is expressed as 4l

The circumference of a circle = 2πr

This means that;

4l = 2πr

4l = 2× 3.142 × 2

4l = 12.57

divide both sides by 4

l = 12.57/4

l = 3.14 units(nearest hundredth)

therefore the value of the side length is 3.14 units

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Answer:

-2/5

Step-by-step explanation:

Exactly the opposite of the sign, opposite of + is negative (-)

a) A and B are independent events.

b) The outcome of each game is independent of the other games so, Rachel's loss = p.

c) The probability of all marbles being red is 4

a) Given that a first marble is red and the second marble is also red, such that

P(1) = P(2) = 0.2, P(3) = P(5) = P(6) = 0.1 and P(4) = 0.3 and die is thrown two times. Also given that:

A1 = red

B1 = red.

So, P(A) = [P(1, 1) + P(2, 2) + P(3, 3) + P(4, 4) + P(5, 5) + P(6, 6)]

= P(1).P(1) + P(2).P(2) + P(3).P(3) + P(4).P(4) + P(5).P(5) + P(6).P(6)

= 0.2 x 0.2 + 0.2 x 0.2 + 0.1 x 0.1 + 0.3 x 0.3 + 0.1 x 0.1 + 0.1 x 0.1

= 0.04 + 0.04 + 0.01 + 0.09 + 0.01 + 0.01 = 0.20

Now, B = [(4, 6), (6, 4), (5, 5), (5, 6), (6, 5), (6, 6)]

P(B) = [P(4).P(6) + P(6).P(4) + P(5).P(5) + P(5).P(6) + P(6).P(5) + P(6).P(6)]

= 0.3 x 0.1 + 0.1 x 0.3 + 0.1 x 0.1 + 0.1 x 0.1 + 0.1 x 0.1 + 0.1 x 0.1

= 0.03 + 0.03 + 0.01 + 0.01 + 0.01 + 0.01 = 0.10

A and B both events will be independent if

P(A ⋂ B) = P(A).P(B) …. (i)

And, here (A ⋂ B) = {(5, 5), (6, 6)}

So, P(A ⋂ B) = P(5, 5) + P(6, 6) = P(5).P(5) + P(6).P(6)

= 0.1 x 0.1 + 0.1 x 0.1 = 0.02

From equation (i) we get,

0.02 = 0.20 x 0.10

0.02 = 0.02

Therefore, we can say that A and B are independent events.

b) We know that the outcome of each game is independent of the other games. Rachel's loss = p. As per the given information, the games in the series are unrelated, indicating the application of the probability multiplication principle.

c) The probability of all marbles being red is 4

Let a be the probability that the first player (ultimately) wins if the two players are tied in wins. Let b be the probability that she wins if she is 1 ahead. And let c be the probability she wins if she is 1 behind. We have the equations

a = rb + 1 - r x c

b = r + 1 - r x a

c = r x a

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Karim and Ali have different conclusions about the closure property for whole numbers and integers because when two whole numbers are subtracted, the result may not be a whole number, but when two integers are subtracted, the result is always an integer. Therefore, integers are closed under subtraction, but whole numbers are not.

Karim and Ali, both  have different conclusions about the closure property for whole numbers and integers because of their definitions.

Whole numbers are defined as all positive integers, including zero. When two whole numbers are subtracted, the result may not be a whole number because the result may be a negative number.

For example, when 3 is subtracted from 2, the result is -1, which is not a whole number.

Integers, on the other hand, are defined as all positive and negative whole numbers, including zero. When two integers are subtracted, the result is always an integer because the result may be a negative or positive number, but it will always be a whole number.

For example, when 3 is subtracted from 2, the result is -1, which is still an integer.

Therefore, Karim and Ali have different conclusions because whole numbers are not closed under subtraction, but integers are closed under subtraction.

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Answer:

V=TTr²h

Step-by-step explanation:

Why?

Because you will v=TT r² h/3

so the answer is

v=TT r² h/3,r É R,h É R

That's my hardwork lick it brainliest and liked my hardwork please

Answer:

24c+37

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

find two points where they line up on the cross sections of the graph

-2, 3

-1, 1

-1 x -2 y

it goes right 1 and down 2

-2/1 or -2

When a graph or a point on the Cartesian plane is symmetric about the origin or with respect to the origin, it means that the graph or point maintains its shape and position when reflected across the origin.

In other words, if you draw a line passing through the origin and the graph or point, the portion of the graph or point on one side of the line will be an exact mirror image of the portion on the other side.

To determine if a graph is symmetric about the origin, we can check if the coordinates of a point on the graph, (x, y), satisfy the condition that (-x, -y) is also on the graph. For example, if the point (2, 3) is on the graph, we can verify that (-2, -3) is also on the graph.

Similarly, for a single point on the Cartesian plane to be symmetric about the origin, its coordinates (x, y) must satisfy the condition that (-x, -y) is also a point on the plane. For instance, if the point (4, -1) is symmetric about the origin, (-4, 1) should also be a point on the plane.

symmetry about the origin in the Cartesian plane refers to maintaining the same shape and position when reflected across the origin. It involves verifying that for every point (x, y) on the graph or plane, (-x, -y) is also a point on the graph or plane.

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Answer:

D. n=3

Step-by-step explanation:

8-2n-6n= –16

Take 8 to the other side

-2n-6n= -16-8

Solve them

-8n = -24

Take -8 to the other side

\(n \: = \frac{ - 24}{ - 8} \)

n = 3

\(\huge\text{Hey there!}\)

\(\huge\textbf{Equation:}\)

\(\mathbf{8 - 2n - 6n = -16}\)

\(\huge\textbf{Solving for the answer:}\)

\(\mathbf{8 - 2n - 6n = -16}\)

\(\huge\textbf{Combine the like terms:}\)

\(\mathbf{(-2n - 6n) + 8 = -16}\)

\(\mathbf{-2n - 6n + 8 = -16}\)

\(\mathbf{-8n + 8 = -16}\)

\(\huge\textbf{Subtract \boxed{\bf 8} to both sides:}\)

\(\mathbf{-8n + 8 - 8 = -16 - 8}\)

\(\huge\textbf{Simplify it:}\)

\(\mathbf{-8n = -16 - 8}\)

\(\mathbf{-8n = -24}\)

\(\huge\textbf{Divide \boxed{\bf -8} to both sides:}\)

\(\mathbf{\dfrac{-8n}{-8} = \dfrac{-24}{-8}}\)

\(\huge\textbf{Simplify it:}\)

\(\mathbf{n = \dfrac{-24}{-8}}\)

\(\mathbf{n = -24 \div -8}\)

\(\mathbf{n = 3}\)

\(\huge\textbf{Therefore, your answer should be:}\)

\(\huge\boxed{\textsf{Option D. \boxed{\frak{n = 3}}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

Answer:

n=5

Step-by-step explanation:

i hope this helps :)

Answer: 0.6763 cm∧2

Step-by-step explanation: Variance is one of the measures of dispersion which is the the second central moment in probability. It is defined as a measure of by how much the values in a data set differs from the mean of the values. Thus it is the average of the squares of the deviations from the mean as this ensures that both the negative and positive deviations do not cancel each other out.

The sample variance would be calculated as follows:

Population size is 7 (5.6 4.9 6.0 5.1 5.5 5.1 7.5)

Mean: Sum of samples / population size ;

(5.6 4.9 6.0 5.1 5.5 5.1 7.5) / 7 = 5.67

Applying the formula for variance: [ Summation (x - mean) ] / population size =( |5.6 - 5.67| + |4.9 - 5.67| + |6.0 - 5.67| + (|5.1 - 5.67|) * 2 + | 5.5 - 5.67| + |7.5 - 5.67|) / 7 = 0.6763 cm^2

The one that has the most circles in a group :D

a) The regression equation for the given data is Overhead Costs = 231,000 + 47.8 × Billable Hours

b) The coefficients of the regression model are b₀ = 231,000 and b₁ = 47.8

a. To develop a simple linear regression model between billable hours and overhead costs, we can use the following formula

Overhead Costs = b₀ + b₁ × Billable Hours

where b₀ is the intercept and b₁ is the slope of the regression line. We can use a statistical software or a spreadsheet program to obtain the regression coefficients. For these data, the regression equation is

Overhead Costs = 231,000 + 47.8 × Billable Hours

b. The coefficients of the regression model are b₀ = 231,000 and b₁ = 47.8. The fixed component of the model (b₀) represents the overhead costs that the consulting firm incurs regardless of the billable hours. This can include expenses such as rent, utilities, salaries, and other fixed costs.

In this case, the fixed component is $231,000, which represents the overhead costs that the firm has to pay even if they do not bill any hours to clients. The slope of the regression line (b₁) represents the change in overhead costs for each additional billable hour. In this case, the slope is 47.8.

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Answer:

y = 1

x = 4

Step-by-step explanation:

x + 3y = 7 → ( 1 )

2x - y = 7 → ( 2 )

First, let us make x the subject in equation ( 1 ).

x = 7 - 3y  → ( 3 )

Let us find the value of y.

For that let us take equation (1) & replace x with ( 7 - 3y ).

2x - y = 7

2 ( 7 - 3y ) - y = 7

Solve the brackets.

14 - 6y - y = 7

Combine like terms.

14 - 7y = 7

Subtract 14 from both sides.

-7y = 7 - 14

-7y = -7

Divide both sides by -7.

y = 1

Let us find value of x

For that let us take equation (3) & replace y with 1.

x = 7 - 3y

x = 7 - 3 × 1

x = 7 - 3

x = 4

The range is all the possible y values, so the set with all the arrows.

Answer: B. {3,9,12}

Answer:

B

Step-by-step explanation:

The range means the y coordinates or output

In this the output are the numbers on the right.

We can also find the answer by eliminating.

Option A could not be the answer because it is only one of the numbers from the range.

Option B is the answer because it includes all the numbers from the range.

Option C and Option D could not be the answer because they include other numbers from the domain (which we are not trying to find).

This is an example here below

Hope this helped!!

Given an angle that is positive, less than 360°, and coterminal with 395° is 35°.

Subtract 360° from 395°.

We know that 1 revolution is equal to 360°.

Therefore, a positive angle that is less than 360° and coterminal with 395° is 35°.

When an angle is less than 360° and shares the same terminal side with another angle that is less than 360°, then the angle is referred to as a coterminal angle.

In other words, the two angles have the same initial side and terminal side but can be either positive or negative.

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Answer:

$15

Step-by-step explanation:

Total distance to be covered = 150km

Fuel efficiency = 6 km per l

150 / 6 = 25

Total fuel cost needed (including existing fuel) = Fuel needed x cost per l fuel

= 25 x 0.6

= 15

Answer:

Step-by-step explanation:

5x+1/3(3x−6)=10

5x+1/3(3x−6)=10

5x+(1/3)(3x)+(1/3)(−6)=10                           (Distribute)

5x+x+−2=10

(5x+x)+(−2)=10                                          (Combine Like Terms)

6x+−2=10

6x−2=10

6x−2+2=10+2

6x=12

6x/6=12/6

x=2