a cylindrical can is to be made to hold 1 liter of oil. find the dimensions (the radius and the height) that will minimize the cost of the metal to manufacture the can.
Answers
Let's start by expressing the cost of the metal to manufacture the can. We assume that the top and bottom of the can are made of a thin material and their cost is negligible compared to the cost of the side.
The surface area of the cylindrical side is given by:
A = 2πrh
The volume of the can is given by:
V = πr^2h
Since the can is to hold 1 liter of oil, we have:
V = 1000 cm^3
Substituting for V, we can write:
r^2h = 1000/π
h = 1000/(πr^2)
Now we can express the cost of the metal as a function of r and h. Let the cost per unit area of the metal be C. Then the cost of the side of the can is:
Cost = C × A
Substituting for A and h, we get:
Cost = C × 2πrh = 2Cπr(1000/(πr^2)) = 2000C/r
To minimize the cost, we differentiate the cost function with respect to r and set the derivative equal to zero:
d(Cost)/dr = -2000C/r^2 = 0
Solving for r, we get:
r = √(2000/C)
Substituting for r in the equation for h, we get:
h = 1000/(πr^2) = 1000/(π(2000/C)) = 0.159 cm
So the dimensions that will minimize the cost of the metal to manufacture the can are:
r = √(2000/C) cm
h = 0.159 cm
Note that we have not been given the value of C, so we cannot calculate the exact values of r and h.
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Related Questions
Which compound is an acid?
a. hydrogen sulfide.
b. water.
c. sodium hydroxide.
d. cannot be determined
Answers
Answer:
a. hydrogen sulfide.
Answer : A
HELP PLS!!!!!!!!!!!!!!!!!!!!! I AM BEGGING YOU THIS IS DUE TOMORROW
( middle school physics)
How does the output work compare to the input work for a machine that has efficiency?
a) equal to 100%
b) less than 100%
2) Pedro and Brittany design a mechanical device that will move desks from one classroom to another on the floor above. They measure the forces and distances and calculate the input and output work. If their calculations show that the input work equals the output work is their calculation correct? Explain.
I would appreciate if you answered this please
Answers
Answer: B) Less than 100%
Explanation:
In this system the mechanical device will move desks on the floor. The floor (unless defined as frictionless) will have some sort of friction resulting in loss in energy. This will reduce the total mechanical energy making it less than 100%.
if we want to see what galaxies looked like at a time close to the beginning of the universe, where should we look?
Answers
Answer: 4 billion years ago
Explanation:
A car that weighs 40,000 N is driving down a hill at a constant velocity. If the car’s momentum is 80,000 kg∙m/s, how fast is the car moving?
Answers
The velocity of the car is equal to 20 m/s.
Given the following data:
Weight of car = 40,000 Newton.Car’s momentum = 80,000 kg∙m/s.Scientific data:
Acceleration due to gravity = 10 \(m/s^2\).To determine the velocity of the car:
How to determine the car's velocity.First of all, we would calculate the mass of the car by using this formula:
\(Weight = mg\\\\40000=m \times 10\\\\m=\frac{40000}{10}\)
Mass, m = 4,000 kg.
For the velocity:
Mathematically, momentum is giving by this formula;
\(Momentum = mass \times velocity\)
Making velocity the subject of formula, we have:
\(Velocity = \frac{Momentum}{Mass}\)
Substituting the given parameters into the formula, we have;
\(Velocity = \frac{80000}{4000}\)
Velocity = 20 m/s.
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two asteroids are 75000 m apart one has a mass of 8 x 10^7 kg if the force of gravity between them is 1.14 what is the mass of the asteroid
3.4 x 10^11 kg
8.3 x 10 ^12 kg
1.2 x 10 ^12 kg
1.2 x 10^10 kg
Answers
Answer:
1.2×10¹² kg
Explanation:
from
\(f = \frac{gm1m2 }{r {}^{2} } \)
\(m2 = \frac{fr {}^{2} }{gm1} \)
\(m2 = \frac{1.14 \times (75000 { )}^{2} }{6.67 \times {10}^{ - 11} \times 8 \times {10}^{7} } \)
HENCE M2= 1.2×10¹²kg
at a minimum, how frequently should an ocular micrometer be calibrated?
Answers
An ocular micrometer is a measuring tool used in microscopy to measure the size of objects under a microscope. Calibration is the process of ensuring that the ocular micrometer is accurate and giving the correct measurements.
What is ocular micrometer?
An ocular micrometer, also known as an eyepiece graticule, is a measuring tool used in microscopy to measure the size of objects viewed through a microscope. It consists of a small, transparent ruler that is placed in the eyepiece of a microscope.
The ruler is etched with fine lines that are used to measure the size of microscopic objects. These lines can be either simple or complex and are usually calibrated to a specific scale, such as millimeters or micrometers. When the microscope is focused on the object, the lines on the ocular micrometer are superimposed onto the image of the object.
An ocular micrometer is a measuring tool used in microscopy to measure the size of objects under a microscope. Calibration is the process of ensuring that the ocular micrometer is accurate and giving the correct measurements.
The frequency of calibration for an ocular micrometer depends on various factors, such as the type and quality of the micrometer, the frequency of use, and the environment in which it is used. However, as a general rule, it is recommended that an ocular micrometer should be calibrated at least once a year.
If the micrometer is used frequently or subjected to harsh environments, it may need to be calibrated more frequently. Additionally, if the micrometer is dropped or damaged, it should be recalibrated before use.
It is important to follow the manufacturer's recommendations and guidelines for the specific type of ocular micrometer being used to ensure accurate measurements.
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The demand for a necessity such as electricity tends to be: inelastic. vertical. unit elastic. D elastic.
Answers
The demand for a necessity such as electricity tends to be inelastic. Here's why:Inelastic demand is when changes in price don't affect the quantity demanded as much.
Necessities such as food, water, and electricity often have an inelastic demand, meaning that when the price of the product increases, the quantity demanded does not decrease as much.Explanation:For example, if the cost of electricity increased by 10%, a household might not be able to decrease its use of electricity as much, such as by 10%. The amount of electricity that a household uses might not be affected by price changes because it's a necessity.A vertical demand curve implies that a change in price results in no change in quantity demanded.
Unit elastic refers to a change in price that results in a proportional change in quantity demanded.D elastic refers to the degree of price sensitivity. Demand is said to be elastic when a price change causes a substantial change in demand.
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NEED HELP ASAP question in picture
Answers
Answer:
B
Explanation:
I don't know how to break it down but I hope this is helpful!
which of the following describes the magnitude of the momentum of the object in the first two straight-line segments shown in the graph as the object moves from point h to point j ?
Answers
The magnitude of the momentum in the first two straight-line segments of the graph remains the same throughout the object's motion from point h to point j.
The magnitude of the momentum of the object in the first two straight-line segments shown in the graph as it moves from point h to point j can be described as **constant**.
In the initial segments of the motion, the graph shows a straight-line portion, indicating that the object's momentum remains constant. This means that the object maintains a consistent magnitude of momentum during this time interval. The momentum of an object is the product of its mass and velocity, and if the velocity remains constant, the momentum will also remain constant. Therefore, the magnitude of the momentum in the first two straight-line segments of the graph remains the same throughout the object's motion from point h to point j.
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Can the switches and bulbs of the room that you stay in be called an electric machine? Switches → input (ON or OFF) and bulbs → (ON or OFF). If so, can switches and bulbs be organized to ADD two numbers like 6 and 4 ? (Do a QMM on this question, i you need) Then attempt the questions below: 1. Decide on at least TWO questions that you need to know to understand the TITLE above (2 marks) 2. If we assume that a switch can represent a number, then ON switch =1 and OFF switch =0. If we have multiple switches we can represent numbers larger than 1. As an output, an OFF bulb can represent 0 output. Since, machines are limited to switches, we need to design a numbering system based on 0's and 1's. How would such a numbering work? (1 mark) 3. To review how binary numbering systems can be used to ADD, Subtract and Multiply numbers, show (using a drawing) how the numbers 6 and 4 can be added using two FOUR switch sets and FOUR bulbs. ( 3 marks) 4. Now once the switches are set to hold 6 and 4 , how can each switch be used to ADD the number and show the output by putting the bulb ON and OFF as needed? To do this, we need to do some logical operations work out how the logical circuits (gates) be used to ADD the TWO numbers given in Question 3. Show and explain this in a drawing. (4 marks)
Answers
Design a numbering system based on 0's and 1's, where each switch represents a binary digit (0 or 1) and combinations of switches represent numbers.
Two questions that need to be known to understand the title:
What defines an electric machine.
How can switches and bulbs be organized to perform mathematical operations like addition.
To design a numbering system based on 0's and 1's:
In a binary numbering system, each switch can represent a binary digit (0 or 1), and the number can be represented by the combination of these digits. For example, if we have four switches, we can represent numbers from 0 to 15 (2^4 - 1).
Adding the numbers 6 and 4 using switches and bulbs:
By representing 6 as 0110 and 4 as 0100 in binary, we can use four switches and bulbs to perform the addition. Each switch represents a binary digit, and the bulbs will display the result of the addition.
Using logical operations and gates to perform addition:
By using logical AND, OR, and XOR gates, we can manipulate the signals from the switches to perform binary addition.
Each gate takes input signals and produces an output based on a specific logical operation. By connecting these gates properly, we can create a circuit that adds the binary numbers and controls the bulbs to indicate the result.
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2. A stone of mass lkg is dropped from height 10m above the ground, and falls speedily under gravity. It's kinetic energy 5m above the ground is equal to
Answers
Answer:
Below
Explanation:
The loss in potential energy (from dropping 5 m) will equal the gain in Kinetic energy
mgh = 1/2 m v^2
m (9.81)(5) = kinetic energy at 5 m <===== you will need to put in the mass
to calculate the value in Joules
009 (part 1 of 2) 10.0 points A gas expands from I to F in the figure. The energy added to the gas by heat is 402 J when the gas goes from I to F along the diagonal path. 0 1 2 3 4 0 1 2 3 4 b b b b I A B F V (liters) P (atm) What is the change in internal energy of the gas? Answer in units of J. 010 (part 2 of 2) 10.0 points How much energy must be added to the gas by heat for the indirect path IAF to give the 2 same change in internal energy? Answer in units of J.
Answers
In the illustration, a gas from I to F. The energy contributed to the gas through heat is 474 J when the gas moves along the diagonal line from I to F.
In physics, what is heat?
In thermodynamics, heat is energy that, in some way besides through labor or the movement of matter, spontaneously flows between a system and the surroundings. Heat transfers naturally from a warmer to a cooler body when an appropriate physical pathway is present.
What category does heat fit into?
Based on this, heat is divided into two categories: hot and cold. We encounter heat energy everywhere, including in icebergs, earthquakes, and our own bodies. There is heat energy in all matter. Heat energy is the only thing that results from the movement of microscopic particles called as atoms, atoms, or ions in fluids, solids, and gases.
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An object with a mass of 20 kg is moving at a speed of 3 m/s. What is the kinetic energy of the object?
Answers
Answer:
\( \huge{ \boxed{ \bold{ \sf{90 \: joule}}}}\)
✑ First , Let's know what kinetic energy is :
⇾ The energy possessed by a body by the virtue of it's motion is called kinetic energy of the body. A flying bird , a moving car , running water , wind , a bullet fired from a gun , an arrow left from a bow , rolling stone etc are some examples of kinetic energy.
The Kinetic energy of a moving body is determined by the formula :
\( \boxed{ \underline{ \sf{KE= \frac{1}{2} m {v}^{2} }}}\)
Here ,
m = mass of the bodyv = velocity of the body--------------------------------------------------------------
☇ Now , Let's solve :
☄ Given :
Mass of the object ( m ) = 20 kgVelocity of the object ( v ) = 3 m/s☄ To find :
Kinetic energy of the object⤿ \( \boxed{ \sf{KE= \frac{1}{2} m {v}^{2} }}\)
Plug the values and simplify :
→ \( \sf{ \frac{1}{2} \times 20 \times {(3)}^{2} }\)
→ \( \sf{ \frac{1}{2} \times 20 \times 9}\)
→ \( \boxed{ \bold{\sf{90 \: joule}}}\)
Hope I helped !
Have a wonderful day ! ツ
~TheAnimeGirl ♡
2. A bowling ball gun is fired horizontally at 248 m/s off a 192 m high cliff.
a. Where does the bowling ball land?
b. Where would a golf ball land? Why? Explain.
C. What is the velocity at impact with the ground? Make sure to include the impact angle.
Answers
To solve this problem, we can use the kinematic equations of motion. Since the bowling ball is fired horizontally, we know that the initial vertical velocity is zero. We can use the equation:
h = vi*t + (1/2)at^2
where h is the initial height of the cliff, vi is the initial vertical velocity (which is zero), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time it takes for the ball to hit the ground.
Solving for t, we get:
t = sqrt(2h / g) = sqrt(2192 / 9.8) = 8.88 s
Where does the bowling ball land?Now that we know the time it takes for the ball to hit the ground, we can use the horizontal velocity to find the distance it travels:
d = v*t = 248 * 8.88 = 2203.24 m
Therefore, the bowling ball lands approximately 2203.24 meters away from the base of the cliff.
A golf ball would land at the same distance as the bowling ball. This is because the distance traveled by a projectile only depends on its initial velocity and the time it spends in the air. Since the golf ball and the bowling ball are fired with the same horizontal velocity, they will travel the same distance before hitting the ground, assuming they are both fired from the same height.
However, the golf ball would take longer to hit the ground because it has a lower initial vertical velocity than the bowling ball, so it would have a longer time of flight.
To find the velocity at impact, we can use the kinematic equation:
v^2 = vi^2 + 2ad
where v is the final velocity (which we want to find), vi is the initial vertical velocity (which is zero), a is the acceleration due to gravity (-9.8 m/s^2), and d is the distance traveled by the ball.
Using the distance found in part a, we get:
v^2 = 2*(-9.8)*2203.24
v = sqrt(2*(-9.8)*2203.24) = 196.67 m/s
The impact angle can be found using trigonometry. The angle theta can be found using the equation:
tan(theta) = opposite / adjacent
where the opposite side is the vertical distance the ball has fallen (which is 192 m) and the adjacent side is the horizontal distance the ball has traveled (which is 2203.24 m).
tan(theta) = 192 / 2203.24
theta = tan^-1(192 / 2203.24) = 5.02 degrees
Therefore, the velocity at impact with the ground is 196.67 m/s at an angle of 5.02 degrees.
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What is the difference between Centrifugal Force And Centripetal Force.
Answers
Answer:
Centripetal force:
This force attracts an object at the center of its circular motion.
Gravitational force attracts the earth and all space bodies towards the sun, at the center of there orbit. So here, the centripetal force for all bodies is gravitational force.
When you start the fan, the tension force in the wings acts as Centeripetal force as the wings are not being flung out.
Note that this force changes it’s name in different Cinerios.
Centrifugal force:
This force acts as if it wants to throw an object from its circular path.
When you spin about your axis, your hands feel like they are being stretched out. This is centrifugal force.
When you spin a rock bounded by a string, you feel like the rock wants to be flung out from its circular path. This is centrifugle force. Here the tension in the string is centripetal force.
Note that this force is not an actual force, it is a pseudo force.
Explanation:
i hope that helps broski
Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in front of A. If the speed of sound in this room is 340m/s will the observer hear a loud sound or a quiet sound?
Answers
Answer:
The observer hears a loud sound
Explanation:
In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.
You first calculate the distance between the observer and the loudspeakers.
The distances are given by:
d1: distance to loudspeaker A = 2.10m
d2: distance to loudspeaker B
\(d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m\)
Next, you calculate the wavelength of the sound waves by using the following formula:
\(\lambda=\frac{v_s}{f}\)
vs: speed of sound = 343 m/s
f: frequency of the waves = 400Hz
λ: wavelength
\(\lambda=\frac{343m/s}{400Hz}=0.8575m\)
Next, you calculate the path difference between the distance from the observer to the loudspeakers:
\(\Delta d=3.827m-2.10m=1.727m\)
You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:
\(\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2\)
Then, there will be a constructive interference, and the sound who the observer hears is loud.
What would be the weight of a 59.1-kg astronaut on a planet twice as massive as Earth and having twice Earth's radius
Answers
Answer:
29.55 kg
Explanation:
force gravity = G m1 m2 / (r^2) now change the mass 1 and the r
= G 2m1 m2 / ( 2r)^2
= 2/4 G m1 m2 / (r^2)
the weight will be 2/4 or 1/2 the original
Describe how the wavelength of a wave changes if the wave slows down but its frequency does not change.
Answers
Answer:
If the wave slows down with no change in frequency, the wavelength decreases.
If the wave slows down with no change in frequency, then the wavelength decreases.
What is a wave?A wave is defined as the disturbance that has the ability to transfer energy from one point to another in a medium.
The properties of a wave are given as;
Wavelength can be defined as the distance that is observed between adjacent points in an identical cycle of a waveform.
Frequency is the number of cycles of a wave that can occur per minute time.
Time period can be defined as the time it takes for a complete cycle of wave to occur.
Wave speed can be defined as the distance a wave travels in a given amount of time.
Amplitude can be defined as the distance from the centre line (or the still position) to the top of a crest or to the bottom of a trough.
When there is a change in the speed of the wave then the length of the wave would decrease.
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What is the centripetal acceleration felt by the passengers of a car moving at 12 m/s along a curve with radius 2.0 m?
a. 3 m/s2
b. 6 m/s2
c. 36 m/s2
d. 72 m/s2
Answers
The centripetal acceleration felt by the passengers of a car moving at 12 m/s along a curve with a radius of 2.0 m is 36 m/s².Option c, 36 m/s², is the correct answer.
How to calculate the centripetal acceleration?Centripetal acceleration is the acceleration experienced by an object moving in a circle or circular path. The formula for calculating centripetal acceleration is given by:ac = v²/r
Where ac is the centripetal acceleration
v is the velocity
r is the radius
To calculate the centripetal acceleration felt by the passengers of a car moving at 12 m/s along a curve with a radius of 2.0 m, we substitute the given values in the formula as shown below:
ac = v²/rac
= (12 m/s)² / 2.0 mac
= 144 m²/s² / 2.0 mac
= 72 mac
= 36 m/s²
Therefore, the centripetal acceleration felt by the passengers of a car moving at 12 m/s along a curve with a radius 2.0 m is 36 m/s².
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How does a concave mirror form an image
A) it bends the light toward a focal point
B) it bends the light away focal point
C) it bounces the light towards a focal point
D) it bounces the light away from a focal point
Answers
Answer:
The correct option is (c) "it bounces the light towards a focal point"
Explanation:
There are two types of spherical mirrors i.e. concave and convex.
A concave mirror is a type of spherical mirror that is curved inwards. For this type of mirror the rays of light are bounced back and converge to the focal point of the mirror.
So, the correct option is (c).
Answer:
c
Explanation:
Urgent!! A plastic rod is charged by rubbing it with a cloth. The cloth and the rod both have a 14.3 mC charge and are placed 20 cm from each other. Calculate the electric force between the rod and the cloth. (Note: k = 8.99 × 10° N • m2 /C2
Answers
The electric force between the rod and the cloth is 4.6 x 10⁷ N.
What is the force between the rod and the cloth?
The electric force between the rod and the cloth is calculated by apply Coulomb's law.
This law states that electric force between two charged bodies is directly proportional to the product of the charges and inversely proportional to the distance between the charged bodies.
Mathematically, this law is given as;
F = kq²/r²
where;
k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²q is the magnitude of the charges = 14.3 mC = 14.3 x 10⁻³ Cr is the distance between the rod and the cloth = 20 cm = 0.2 mSubstitute the given parameters and solve for the electric force between the rod and the cloth as shown below.
F = kq²/r²
F = (8.99 x 10⁹ x 14.3 x 10⁻³ x 14.3 x 10⁻³) / (0.2)²
F = 4.6 x 10⁷ N
Thus, the electric force between the rod and the cloth is determined by applying Coulomb's law.
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What happens to momentum when two objects collide
Answers
Answer:
The sum of momenta of each object before and after collision is equal . Thus when they collide , their momentum will change but its sum will be sane as the sum of the momentum before collision
what makes something bouncy
Answers
Answer: The speed of the object traveling should be met with the opposite reaction, thus making something like a basketball bounce as high as the force applied to the ball, making both surfaces push off each other until kinetic energy ( form of energy that an object or a particle has by reason of its motion) is lost.
When is the average velocity of an object equal to the instantaneous velocity? a. This is always true. b. This is never true. c. This is the case only when the velocity is constant. d. This is the case only when the acceleration is constant. e. This is the case only when the velocity is decreasing at a constant rate.
Answers
When is the average velocity of an object equal to the instantaneous velocity is C. This is the case only when the velocity is constant.
The instantaneous velocity of an object is equal to the average velocity of an object when the velocity is constant or when the acceleration is zero, this is the case only when the velocity is constant. When an object has a constant velocity, the instantaneous velocity of the object is equivalent to the average velocity of the object. This is true because the velocity of the object remains constant over time.
For example, if an object travels at a speed of 20 meters per second for a time period of 5 seconds, then the instantaneous velocity at the end of the 5 seconds is 20 meters per second, and the average velocity of the object over the 5 seconds is also 20 meters per second. This is because the velocity remained constant throughout the entire time period. Therefore, option c is correct, this is the case only when the velocity is constant.
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A falcon is diving at a speed of 30m/s. It accelerates at a rate of 40m/sand reaches a speed of
100m/s. Calculate the distance it travels during its acceleration.
Answers
Answer:
Reasd through the explanartion first :)
Explanation:
Initial velocity, u = 30 m/s
Final velocity, v = 100 m/s
Acceleration, a = 40 m/s²
Distance traveled, s = ?
According to the 3rd equation of motion,
We know that,
v² - u² = 2as
So, putting all the values, we get
⇒ v² - u² = 2as
⇒ (100)² - (30)² = 2 × 40 × s
⇒ 10000 - 900 = 80s
⇒ 9100 = 80s
⇒ 9100/80 = s
⇒ s = 113.75 m.
PLEASE help! I am so desperate LOL
1: A 75.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 20.0 m) and spun at a constant angular velocity of 15.0 rpm (revolutions per minute). He is then slowed and brought to a stop in 2.0 minutes.
(1a) Find the magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity.
(2a) How many g’s is the astronaut experiencing when moving at constant angular velocity?
(3a) Find the torque that is needed to bring the centrifuge to a stop knowing the centrifuge has a mass of 5500.0 kg (ignore all other forces) and the force is applied at the edge of the centrifuge (20.0 m radius). Hint: torque is based on the change of linear velocity.
2: An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion, as shown in this graph.
(2a) What is the period and frequency of the pendulum’s motion?
(2b) How many seconds out of phase with the displacements shown would graphs of the velocity and acceleration be?
(2c) What is the acceleration due to gravity on the surface of the planet in m/s2? Determine the number of g-forces.
Answers
Answer: (1a) The magnitude of the centripetal acceleration is 31.4 m/s^2, and the direction is towards the center of the circular motion.
(2a) The astronaut is experiencing 31.4 m/s^2 / 9.8 m/s^2 = 3.22 g's.
(3a) The torque needed to bring the centrifuge to a stop is (5500.0 kg * 31.4 m/s^2 * 20.0 m) = 3,420,000 N * m.
2:
(2a) The period of the pendulum's motion is 0.20 m / 0.10 m/s = 2.0 seconds, and the frequency is 1 / 2.0 s = 0.50 Hz.
(2b) The graphs of velocity and acceleration would be 0.5 seconds out of phase with the displacements shown.
(2c) The acceleration due to gravity on the surface of the planet is 0.10 m/s^2 / 9.8 m/s^2 = 1.02 g's.
Explanation:
when two or more cars arrive at an intersection at approximately the same time, who goes first?
Answers
When two or more cars arrive at an intersection at approximately the same time, the general rule is that the car on the right has the right of way.
However, if the cars are directly across from each other and there is no clear right or left, then the car that is already in the intersection has the right of way. In situations where there is still confusion, it is always best to proceed with caution and communicate with other drivers to ensure a safe and orderly flow of traffic.
When two or more cars arrive at an intersection at approximately the same time, the question of "who goes first?" depends on several factors.
1. Check for traffic signs or signals: Follow the rules indicated by stop signs, yield signs, or traffic signals to determine the right of way.
2. Right of way at a four-way stop: If it is a four-way stop, the first car to come to a complete stop has the right to proceed. If multiple cars stop at the same time, the car furthest to the right has the right of way.
3. Right of way at a T-intersection: If it is a T-intersection (three-way stop), the car on the through road has priority over the car on the terminating road.
Remember, always prioritize safety and ensure all drivers are aware of their turn before proceeding through the intersection.
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A pendulum makes 50 complete swings in 2 min 40 second . what is time period for 1 complete swing?
Answers
Answer:
3.2 seconds
Explanation:
50 swings = 2 mins 40 secs
= 50 swings = 2 x 60 + 40 secs
= 50 swings = 160 secs
= 1 swing = 160 / 50 secs
= 1 swing -= 3.2 secs
True or False:
Assuming Russia is the same distance from Mt. Saint Helens in Oregon as Brazil, pollutants from a major volcanic eruption at Mt Saint Helens would reach Russia long before they would reach Brazil.
Geostrophic winds blow from east to west at 50 oN latitude.
A persistent high pressure system is more likely at 60 oN than at 30 oN.
In the northern hemisphere, at 15 oN, the predominant winds near the surface, but above the planetary boundary layer, are from the southeast.
Air pollution episodes are associated with high pressure systems because there is a downward flow of air at the center, which inhibits dispersal of pollutants.
Answers
False: Assuming Russia is the same distance from Mt. Saint Helens as Brazil, pollutants from a major volcanic eruption at Mt. Saint Helens would not necessarily reach Russia before reaching Brazil.
True: Geostrophic winds blow from west to east at 50°N latitude, not east to west.False: A persistent high-pressure system is more likely at 30°N than at 60°N. High-pressure systems are commonly associated with subtropical regions, which are typically found around 30°N.
False: In the Northern Hemisphere, at 15°N, the predominant winds near the surface, but above the planetary boundary layer, are from the northeast, not southeast.True: Air pollution episodes can be associated with high-pressure systems because the sinking motion at the center of the high-pressure system inhibits the vertical dispersion of pollutants, leading to their accumulation near the surface.
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A net force acts on a 5 kg object, speeding the object up from 2.0 m/s to 6.0 m/s. Which of the following values indicates the amount of work the net force performs on the object?
a. 20 J
b. 40 J
c. 80 J
d. 90 J
Answers
The following values indicates the amount of work the net force acts on a 5 kg object, speeding the object up from 2.0 m/s to 6.0 m/s that performs on the object = 80 J (option C)
The amount of work performed by the net force on the object can be calculated using the formula:
W = F x d
Where:
W is the work (J)
F is the net force (N) and
d is the displacement of the object (m)
We can also use the formula for kinetic energy to find the amount of work performed.
KE = ½ mv²
The change in kinetic energy of the object is equal to the work done on it.
Initial kinetic energy
= ½ x 5 kg x (2.0 m/s)²
= 10 J
Final kinetic energy
= ½ x 5 kg x (6.0 m/s)²
= 90 J
Hence, the change in kinetic energy (work done) = Final kinetic energy - Initial kinetic energy
= 90 J - 10 J
= 80 J
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