A delivery drone uniformly slowed down from 45 m/s to 23 m/s in a straight line over a 30-minute duration within a 16-kilometer radius of its warehouse. What was the magnitude of its average acceleration?
A. 1.2 x 10^−2 m/s^2
B. 5.3 x 10^−1 m/s^2
C. 7.3 x 10^−1m/s^2
D. 4.4 x 10^1 m/s^2
Answers
Related Questions
A balloon has a volume of 2. 37 liters at 24. 0°c. the balloon is heated to 48. 0°c. calculate the new volume of the balloon.
a. 1. 19 l
b. 2. 19 l
c. 2. 56 l
d. 2. 37 l
e. 4. 74 l
Answers
The new volume of the balloon after being heated to 48.0°C is approximately 2.56 liters. Thus, the correct answer is option c. 2.56 L.
To calculate the new volume of the balloon after it is heated from 24.0°C to 48.0°C, we can use the ideal gas law. The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
First, let's convert the temperatures from Celsius to Kelvin. To convert Celsius to Kelvin, we add 273.15 to the Celsius temperature. So, 24.0°C + 273.15 = 297.15 K, and 48.0°C + 273.15 = 321.15 K.
Since the number of moles and the pressure of the gas are not given, we can assume they are constant. Therefore, we can rewrite the ideal gas law as V₁/T₁ = V₂/T₂, where V₁ is the initial volume, T₁ is the initial temperature, V₂ is the final volume (what we're trying to find), and T₂ is the final temperature.
Plugging in the values, we get V₁/297.15 = V₂/321.15. Rearranging the equation, we have V₂ = (V₁ × T₂) / T₁.
Substituting the given values, we have V₂ = (2.37 L × 321.15 K) / 297.15 K ≈ 2.56 L.
Hence, c is the correct option.
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What does it mean when work is positive?
Answers
1. Initial velocity=0 km/h
Final velocity=24 km/h
Time=3 seconds
2. Initial velocity=0 km/h
Final velocity=35 m/s
Time=5 seconds
3. Initial velocity=20 km/h
Final velocity=60 km/h
Time=10 seconds
4. Initial velocity=50 m/s
Final velocity=150 m/s
Time=5 seconds
What is the acceleration for each problem?
Answers
The accelerations for each problem are:
1. 2.22m/\(s^{2}\)
2. 7m/\(s^{2}\)
3. 1.45m/\(s^{2}\)
4. 20m/\(s^{2}\)
What is acceleration due to gravity?The acceleration which is gained by the object because of gravitational force is called its acceleration due to gravity. Its SI unit is m/\(s^{2}\). Acceleration due to gravity is a vector, which means it has both magnitude and direction. The acceleration due to gravity at the surface of the Earth is represented by letter g. It has standard value defined as 9.80665 m/s2 (32.1740 ft/s2). However, actual acceleration of a body in free fall varies with location.
1. Initial velocity=0 km/h
Final velocity=24 km/h= 6.66m/s
Time=3 seconds
acceleration =\(\frac{6.66-0}{3}\)=2.22m/\(s^{2}\)
2. Initial velocity=0 km/h
Final velocity=35 m/s
Time=5 seconds
acceleration = \(\frac{35-0}{5}\)=7m/\(s^{2}\)
3. Initial velocity=20 km/h=5.55\(m/s^{2}\)
Final velocity=60 km/h= 20m/\(s^{2}\)
Time=10 seconds
acceleration= \(\frac{20-5.55}{10}\)= 1.45m/\(s^{2}\)
4. Initial velocity=50 m/s
Final velocity=150 m/s
Time=5 seconds
acceleration= \(\frac{150-50}{5}\)= 20m/\(s^{2}\)
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Which soil conservation method involves planting different crops in a field
each year to restore nutrients.
Answers
Answer:
Crop rotation is the practice of growing a series of different types of crops in the same area across a sequence of growing seasons. It reduces reliance on one set of nutrients, pest and weed pressure, and the probability of developing resistant pest and weeds
The app claimed it has "Forbidden text"
Answers
Silas sighted Maya in the hallway after his Block 2 Humanities class. They stopped and talked way too long. Recognizing that the Block 3 late bell was going to ring in 17.1 seconds, Silas hurried 50.4 m down the Hall to Mr. Wizeman's English class.
What average
speed must Silas move in order to reach the doorway on time?
Average Speed: ___ m/s
Answers
Silas must move at an average speed of 2.95 m/s to reach Mr. Wizeman's English class on time.
How to find the average speedTo calculate Silas's average speed, we can use the formula:
average speed = distance / time
distance is 50.4 m.
time is 17.1 seconds
Now we can plug in the values:
average speed = distance / time
average speed = 50.4 m / 17.1 s
average speed = 2.95 m/s
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If an object has a mass of 8 kg, what is its approximate weight on Earth?
Answers
Answer:
10^24 kg
Explanation:
Which of these items is roughly the same size as a neutron star?
a. Earth, b. tip of a pencil, c. football field, d. a city, the sun
Answers
The most suitable option from the given choices that is roughly the same size as a neutron star is:
d. a city
Neutron stars are extremely compact and dense objects that form after the core collapse of massive stars during a supernova explosion. They typically have a radius of about 10 kilometers (6.2 miles) or less, which is significantly smaller than the size of Earth, a football field, or the sun.
Comparing a neutron star to the size of a city is a reasonable approximation. While the exact size of a city can vary significantly, there are cities on Earth that have diameters or extents of a few tens of kilometers. This is in the range of the size of a neutron star, making a city a closer approximation in terms of size.
It's worth noting that neutron stars are incredibly dense, packing a mass greater than that of the sun into a much smaller volume. Their size and mass make them fascinating objects in astrophysics and lead to unique physical properties such as intense gravitational forces and strong magnetic fields.
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The mass of a cube is 16cm and the volume is 8cm3. What is the density?
Answers
Answer:
the density is 2
Explanation:
mass divided by volume is density
16 divided by 8 is 2
Please help !!
Which of the following statements regarding orbits is true?
A. A satellite moves in an elliptical orbit with the central body at one
focus
B. The Sun and a planet are at the two foci of an orbit.
c. In an orbit, the satellite and the central body are the two foci of the
ellipse.
D. In an elliptical orbit, there is one focus and the satellite is located
there.
Answers
The true statement about an orbit is that the sun and a planet are at the two foci of an orbit. Hence, option B is correct.
What is an orbit?An orbit is a curved path taken by an object in celestial mechanics, such as the path taken by a planet around a star, a natural satellite around a planet, or an artificial satellite around an object or location in space, such as a planet, moon, asteroid, or Lagrange point.
Ordinarily, the term "orbit" refers to a trajectory that repeats itself periodically, though it can also apply to a non-repeating trajectory. Kepler's principles of planetary motion roughly predict that planets and satellites have elliptic orbits, with the center of mass orbiting at a focal point of the ellipse.
Hence, this concludes that option B is correct.
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why do we daydream during class
Answers
Answer:
Because we wish that a dragon would just destroy school and you can ride your new dragon to starbucks, you'll be famous!!! BUT THEN REALITY SMACKS YOU IN THE FACE WITH A STUPID STACK OF HOMEWORK!!!
Explanation:
I understand how changes at the molecular scale affected the lake’s macro-scale appearance.
Answers
The macro scale look of the lake is determined by water molecules.
What is macro scale appearance?The macro scale refers to the broad scale motion of the gas, while the micro scale refers to individual molecule movements.
The macroscale is defined as geometry on the order of millimeters and beyond, whereas the microscale is concerned with length scales down to the micrometer range.
The biggest circulation patterns in the earth's lower atmosphere are represented by macroscale winds. These wind patterns can endure from days to months and span distances of hundreds to thousands of kilometers.
The jet stream and trade winds are two examples of planetary scale wind patterns.
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Full Question:
Although part of your question is missing, you might be referring to this full question:
How can the change that the molecular scale affect the Lakes Macro scale appearance
What has increased the concentration of atmospheric carbon dioxide (CO2)?
Answers
Answer:
Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.
If the electrons in an atom were stationary, they would be ___ the nucleus
Answers
Answer:
Matter in the universe is made up of atoms, particles if electrons were to be stationary, they would have fallen into the nucleus because of electrostatic force acting on them destroying very existence of an atom we know.
A cylindrical glass that is 10cm high is partially filled with water. You see the glass in two positions. What is the height of the water when the glass is upright
Answers
Answer:
5 cm.
Explanation:
If the glass is located upright, the height of water is about 5 cm because the height of glass is 10 cm and it is partially filled with water and we know that partial means 50 percent of something and here 50 percent of glass is 5 cm. If the glass is slightly bend, so we can't find its right height so the proper height of water is attain if it is placed on flat table and present upright.
Kofi, with mass 42.00 kg, is riding a skateboard with a mass of 2.00 kg and traveling at 1.20 m/s. Kofi jumps off and the skateboard stops dead in its tracks. In what direction and with what velocity did he jump
Answers
He jumped off with a velocity of 1.26 m/s in the same direction as the skateboard .
Conservation of linear momentumAccording to the principle of conservation of linear momentum, the total momentum of a system is constant. Hence;
Total momentum before = (42.00 kg + 2.00 kg) 1.20 m/s = 52.8 Kgm/s
Total momentum after = (42.00 kg × v) + (2.00 kg × 0) = 42.00 v Kgm/s
Applying the law of conservation of linear momentum;
52.8 Kgm/s = 42.00 v Kgm/s
v = 52.8/42.00
v = 1.26 m/s
He jumped off with a velocity of 1.26 m/s in the same direction as the skateboard .
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An object of known mass that can be used to establish uncertainty in measurements made with a balance is best described as a.
Answers
Answer:
standard
Explanation:
we sometimes use weights of known mass to balance with an object of unknown mass to determine that objects weight.
Give a family of set cover problems where the set to be covered has n elements, the minimum set cover is size k = 3, and the greedy algorithm returns a cover of size Ω(log n). That is, you should give a description of a set cover problem that works for a set of values of n that grows to infinity – you might begin, for example, by saying, "Consider the set $X = \{1, 2, ..., 2^b\}$ \text{ for any } $b \geq 10$, and consider subsets of X of the form...", and finish by saying "We have shown that for the example above, the set cover returned by the greedy algorithm is of size b = Ω(log n)." (Your actual wording may differ substantially, of course, but this is the sort of thing we’re looking for.) Explain briefly how to generalize your construction for other (constant) values of k. (You need not give a complete proof of your generalization, but explain the types of changes needed from the case of k = 3.)
Answers
Consider the set X = {1, 2, ..., 2ᵇ} and the subsets of X of the form {1, 2, ..., 2ᶦ} for 0 <= i <= b-1. The greedy algorithm will return a set cover of size b = Ω(log n). To generalize for other values of k, one can consider subsets of X of the form {1, 2, ..., 2ᶦ} for 0 <= i <= bk-2.
Consider the set X = {1, 2, ..., 2ⁿ} and subsets of X of the form S_i = {1, 2ᶦ, 2⁽ᶦ⁺¹⁾, ..., 2⁽ᶦ⁺ᵏ⁻¹⁾} for i = 0, 1, ..., n-k. Let F be the family of all subsets of X that contain at least one of the sets S_i. Then the minimum set cover for F is of size k = 3. However, the greedy algorithm would choose the sets S_0, S_3, S_6, ..., resulting in a cover of size log_2(n/k) = Ω(log n).
To generalize this construction for other constant values of k, we can consider subsets of X of the form S_i = {1, 2ᶦ, 2⁽ᶦ⁺¹⁾, ..., 2⁽ᶦ⁺ᵏ⁻¹⁾} for i = 0, k, 2k, ..., (n/k - 1)k. This would result in a set cover of size k, and the greedy algorithm would choose the sets S_0, S_k, S_2k, ..., resulting in a cover of size log_2(n/k) = Ω(log n), as before. The main change needed is to adjust the indexing of the sets S_i to ensure that each element in X is covered by at least one set.
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Write the answer in scientific notation, using the wanted unit.
(1.26 x 10^4 kg) + (2.5 x 10^6 g)
write the answer in kilograms.
Answers
Answer:
1.51 x 10^4 kg
Explanation:
(1.26 x 10^4 kg) + (2.5 x 10^6 g)
= 12600 kg + 2500000 g
= 12600 kg + (2500000 g / 1000 )
= 12600 kg + 2500 kg
= 15100 kg
= 1.51 x 10^4 kg
a vector has components a x = 10 m and a y = 5.0 m. what is the magnitude of vector ?
Answers
To find the magnitude of a vector with components a_x = 10 m and a_y = 5.0 m, you can follow these steps:
1. Identify the components of the vector: In this case, the components are a_x = 10 m and a_y = 5.0 m.
2. Use the Pythagorean theorem to find the magnitude: The magnitude of a vector can be found using the formula: magnitude = √(a_x²+ a_y²).
3. Plug in the values of the components: magnitude = √((10 m) ²+ (5.0 ²).
4. Calculate the magnitude: magnitude = √(100 m² + 25m ²). = √(125 m²).
5. Simplify the result: magnitude = √(125 m²) = 5√5 m.
So, the magnitude of the vector with components a_x = 10 m and a_y = 5.0 m is 5√5 m.
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using the atomic mass of 235.04393 u for 235u, what is its binding energy per nucleon
Answers
the binding energy per nucleon of 235U is approximately 7.85 x \(10^6\) eV/nucleon.
The atomic mass of 235U is 235.04393 u. This represents the mass of one nucleus of 235U. The mass of 1 mole of 235U is therefore 235.04393 g.
The mass of 1 proton is approximately 1.00728 u and the mass of 1 neutron is approximately 1.00867 u. Therefore, the mass of 1 nucleon is approximately 1.00728 + 1.00867 = 2.01595 u.
The number of nucleons in 1 mole of 235U is equal to Avogadro's number (NA) multiplied by the mass number of 235U, which is 235. Therefore, the number of nucleons in 1 mole of 235U is:
NA x 235 = (6.0221 x \(10^23\)) x 235 = 1.413 x \(10^26\) nucleons
The binding energy of 1 mole of 235U is approximately 1785 x \(10^6\) J/mol. Therefore, the binding energy per nucleon is:
(1785 x\(10^6\) J/mol) / (1.413 x \(10^26\) nucleons) = 1.26 x \(10^-12\) J/nucleon
To express this in electronvolts (eV), we can divide by the elementary charge (1.602 x \(10^-19\) C/eV):
(1.26 x \(10^-12\) J/nucleon) / (1.602 x \(10^-19\) C/eV) = 7.85 x \(10^6\) eV/nucleon
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Which of the following systems have a microscopic property of matter that allows an external magnetic field to cause observable, macroscopic effects on them? Select two we AA plasma, which is classified as a very hot gas of randomly moving positively and negatively charged particles A block of wood, which is composed of particles that are spaced such that the block is classified as having a large density с A pile of iron filings, which are composed of particles such that the iron filings are classified as metal D A container of water, which is composed of particles that are arranged such that the form of matter is classified as a fuld
Answers
The two systems that have a microscopic property of matter that allows an external magnetic field to classified as a very hot gas of randomly moving positively and negatively charged particles and composed of particles that are arranged such that the form of matter is classified as a fuld.
So, the correct answer is A and C.
AA plasma is a state of matter where particles are highly charged and moving randomly. When exposed to a magnetic field, these charged particles can be affected and can result in observable macroscopic effects.
On the other hand, a pile of iron filings is made up of tiny particles that are magnetic and can align themselves with an external magnetic field, leading to visible macroscopic effects such as the formation of patterns. A block of wood and a container of water do not have this microscopic property of being affected by an external magnetic field.
Hence, the correct answer is A and C.
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Which diagram shows the most likely effect when a rock is weathered by water flowing over its entire surface
Answers
Answer:
the answer to this would be D.
Answer: Its D but it might swap to another letter so keep your eye out bud pass this test good luck
Explanation:
Fill The Blank? the tangential speed on the outer edge of a rotating carousel is _______.
Answers
The tangential speed on the outer edge of a rotating carousel is dependent on the carousel's rotational speed and the distance from the center of rotation to the outer edge.
It can be calculated using the formula: tangential speed = radius × angular speed
Where the radius is the distance from the center of rotation to the outer edge, and the angular speed is the rate of rotation measured in radians per second.
The carousel's rotational speed of a carousel refers to the rate at which it completes one full revolution, and it is usually measured in units of revolutions per minute (RPM) or radians per second (rad/s). The faster the carousel rotates, the higher the outer edge's tangential speed. The rotational speed of a carousel can be controlled by adjusting the power source that drives it, such as an electric motor.
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Transverse waves are to radio waves as longitudinal waves are to.
Answers
Question:
A race car slows with an average acceleration of –8.0 m/s2 (negative sign shows deceleration). The car’s initial velocity is 100.0 m/s, how far does it travel in 12.0 seconds? Explain how you arrived at your answer?
Use the equations
Answers
Answer:
\(624\:\mathrm{m}\)
Explanation:
We can use kinematics equation \(\Delta x =v_it+\frac{1}{2}at^2\).
What we're given:
\(v_i\) of 100.0 m/s\(t\) of 12 s\(a\) of -8.0 \(\mathrm{m/s^2}\)Solving for \(\Delta x\):
\(\Delta x=100\cdot 12+\frac{1}{2}\cdot -8\cdot 12^2=\boxed{624\:\mathrm{m}}\)
If a rocket travels 35,200 miles in 2 hours, what is its speed?
Answers
Answer:
Given:
Distance = 35200 miles, time = 2 hr.
So we know = 35200/ 2, = 17600 miles / hr.
35,200/2
= 17,600 miles per hour
compared to the velocity of a 400 hz sound, the velocity of a 200 hz sound through air is
Answers
A sound traveling through air at 200 Hz has the same velocity as one traveling at 400 Hz.
The source determines the frequency of the sound wave. However, the density of the medium and the bulk modulus are the only factors that affect the speed of the sound wave. When compared to the speed of sound at 400 Hz, the speed of sound at 200 Hz is therefore constant.
Air and water have different sound propagation rates. The speed of sound in air is around 343 meters per second under normal circumstances, while the speed of sound in water is approximately 1,480 meters per second. Fundamentally, a compression wave moving through a medium is what makes up normal sound.
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Correct Question:
Compared to the velocity of a 400 Hz sound, the velocity of a 200 Hz sound through air is __________.
PLEASE HELP I WILL GIVE BRAINLYEST!!
Look at the world map shown below.
The picture shows the world map with a horizontal line labeled 'Equator' running across the middle of the map. A dotted line is shown slightly above the equator and parallel to it. This line is labeled 'Tropic of Cancer'. A dotted line is shown slightly below the equator and parallel to it. This line is labeled 'Tropic of Capricorn'. Florida is labeled on the left just above the Tropic of Cancer and Russia is labeled on the right closer to the north pole.
Public Domain
Which statement accurately describes the distribution of sunlight for the regions labeled? (3 points)
Group of answer choices
Florida has shorter seasons because it is more towards the west of the globe.
Russia has a greater number of longitudinal lines, which causes greater temperature differences.
Florida is situated closer to the Tropic of Cancer, which receives more constant and direct rays of the sun.
Russia is situated closer to the North Pole, which is tilted more towards the sun.
Answers
Answer:
Florida is situated closer to the Tropic of Cancer, which receives more constant and direct rays of the sun.
Explanation:
Took the test got it right C
Given an objects momentum and velocity which equation can be used to calculate the objects mass
Answers
an objects momentum is found from
p=mv
so to find m we divide it by v which gives us
p/v=m or m=p/v
option B
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