Answer:
Step-by-step explanation:
Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:
#lbs x $/lb = Total
T
K
Mix
Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:
#lbs x $/lb = Total
T 9
K 13.50
Mix
Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound
#lbs x $/lb = Total
T 9
K 13.50
Mix 50 9.54
Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:
#lbs x $/lb = Total
T x x 9 = 9x
K 50 - x x 13.50 = 675 - 13.50x
Mix 50 x 9.54 = 477
The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:
9x + 675 - 13.5x = 477 and
-4.5x = -198 so
x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.
how many four letter strings can be formed from the letters a,b,c,d,e if the first letter must be a vowel and the last letter must be a consonant?
Number of ways to form four letters strings formed using a, b, c, d, e with the given conditions is equal to 150ways.
As given in the question,
Given letters are a, b, c, d, e has
Number of vowel = 2
Number of consonant= 3
Number of letter strings to be formed = 4
Condition:
First letter must be vowel
Last letter must be consonant
First place filled in 2 ways
Second and Third place filled in 5ways
Last place filled in 3 ways
Total number of ways to form four letters strings
= 2 × 5 × 5 × 3
= 150
Therefore, number of ways to form four letter string is 150 ways.
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b) Su nómina de diciembre, mes en el que percibe una paga extraordinaria.
Answer:
Realmente no sé lo que quieres decir con esto, así que hice lo mejor que pude.
Step-by-step explanation:
Si el período de pago finaliza después del final del año, habrá días adicionales en el pago del próximo año. Esto es importante si un empleado recibió un bono de fin de año significativo, por ejemplo, ya que puede afectar su tasa impositiva. Además, si el año tuvo un período de pago adicional, es posible que los empleados reciban un cheque de pago adicional.
Please help me with this question!!!!!
h = 11.9 cm
cos = adjacent/ hypotenuse
therefore:
cos(24) = h/ 13
rearrange:
h = 13cos(24)
put into calculator:
h = 11.8760...
rounded to one decimal point:
h = 11.9cm
PLEASE HELP!! find the slope of the graph asap!
Answer: I do not understand
Step-by-step explanation:
Please help me, y= ? Answer it below.
(rounding) 17.23. whats the nearest tenth?
Answer:
17.2
Step-by-step explanation:
23 ⇒ Below 5, round down
20 ⇒ Add to decimal
17. 23 ⇒ 17.2 / 17.20
select the symbolic form for each of the following statements. (a) x ≥ 5 p ~ q
b. p ∨ r c. p ∧ q d. q ~ r e. p ∨ q
The symbolic forms for the given statements are: (b) p ∨ r, (c) p ∧ q, (d) q ~ r, and (e) p ∨ q. Statement (a) cannot be expressed symbolically.
(a) x ≥ 5: This statement represents a numerical inequality, and it cannot be expressed symbolically.
(b) p ∨ r: The symbolic form for the statement "p ∨ r" is a logical disjunction, meaning it represents the logical "OR" operation between the propositions p and r.
(c) p ∧ q: The symbolic form for the statement "p ∧ q" is a logical conjunction, indicating the logical "AND" operation between the propositions p and q.
(d) q ~ r: The symbolic form for the statement "q ~ r" is a negation, where the proposition r is negated, represented by the symbol "~".
(e) p ∨ q: The symbolic form for the statement "p ∨ q" is a logical disjunction, indicating the logical "OR" operation between the propositions p and q.
In logic, different symbols are used to represent various logical operations and relationships between propositions. The statements provided have different symbolic forms based on the logical operations they represent.
The "∨" symbol represents logical disjunction (OR), "∧" symbol represents logical conjunction (AND), and "~" symbol represents negation. It is important to understand the symbolic forms to accurately represent and analyze logical statements.
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PLEASE HELP. !!!!!!!!!!
Answer:
the last one bottom right
Step-by-step explanation:
well, did it in my head, but the idea is to calculate it out
(x-8)*(x-8)=50
is just
x²-16x+64=50
to get the 64 down to just 5, we need to subtract 59, on both sides, leaving us with -9 on the righthand side
Find the radius of convergence and the interval of convergence in #19-20: 1 32n 19.) 2n=1(-1)^ (2x - 1)" 20.) Σ=0, -(x + 4)" 1.3.5....(2n-1) 21.) Find the radius of convergence of the series: En=1 3.6.9....(3n) 72 non n+1 ·xn
19. The radius of convergence is infinity, and the interval of convergence is (-∞, ∞).
20. The radius of convergence is infinity, and the interval of convergence is (-∞, ∞).
21. The radius of convergence is 1/24, and the interval of convergence is (-∞, -1/24) ∪ (1/24, ∞).
To determine the radius of convergence and interval of convergence for the given power series, we can use the ratio test.
19.) For the series Σ 2n=1 (-1)^(2n - 1) / 32n:
Using the ratio test, we calculate the limit:
lim (n→∞) |((-1)^(2(n+1) - 1) / 32(n+1)) / ((-1)^(2n - 1) / 32n)|
Simplifying the expression:
lim (n→∞) |-1 / (32(n+1))|
Taking the absolute value and simplifying further:
lim (n→∞) 1 / (32(n+1))
The limit evaluates to 0 as n approaches infinity.
Since the limit is less than 1, the series converges for all values of x. Therefore, the radius of convergence is infinity, and the interval of convergence is (-∞, ∞).
20.) For the series Σ (-(x + 4))^n / (1·3·5·...·(2n - 1)):
Using the ratio test, we calculate the limit:
lim (n→∞) |((-(x + 4))^(n+1) / (1·3·5·...·(2(n+1) - 1))) / ((-(x + 4))^n / (1·3·5·...·(2n - 1)))|
Simplifying the expression:
lim (n→∞) |(-(x + 4))^(n+1) / (2n(2n + 1))|
Taking the absolute value and simplifying further:
lim (n→∞) |-(x + 4) / (2n + 1)|
The limit depends on the value of x. For the series to converge, the absolute value of -(x + 4) / (2n + 1) must be less than 1. This occurs when |x + 4| < 2n + 1.
To determine the interval of convergence, we set the inequality |x + 4| < 2n + 1 to be true:
-2n - 1 < x + 4 < 2n + 1
Simplifying:
-2n - 5 < x < 2n - 3
Since n can take any positive integer value, the interval of convergence depends on x. Therefore, the radius of convergence is infinity, and the interval of convergence is (-∞, ∞).
21.) For the series Σ (3·6·9·...·(3n)) / (72(n+1)·xn):
Using the ratio test, we calculate the limit:
lim (n→∞) |((3·6·9·...·(3(n+1))) / (72(n+2)·x^(n+1))) / ((3·6·9·...·(3n)) / (72(n+1)·xn))|
Simplifying the expression:
lim (n→∞) |(3(n+1)) / (72(n+2)x)|
Taking the absolute value and simplifying further:
lim (n→∞) (3(n+1)) / (72(n+2)|x|)
The limit evaluates to 3 / (72|x|) as n approaches infinity.
For the series to converge, the limit must be less than 1, which implies |x| > 1/24.
Therefore, the radius of convergence is 1/24, and the interval of convergence is (-∞, -1/24) ∪ (1/24, ∞).
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C'D'
is a translation of
CD
. Write the translation rule.
-
Translation is one of the four types of mathematical transformations that may be applied to a function graph.
(x, y) = (x + a, y + b)
Describe translation.In mathematics, a translation is the up, down, left, or right movement of a form. Because the translated shapes appear to be exactly the same size as the original ones, they are consistent with one another. Just one or more routes have been altered. There is no change in the form because it is just being moved from one location to another.
Rule of TranslationWhen the shape is moved towards the left by k units, then replace x with x - k.
When the shape is moved towards the right by k units, then replace x with x + k.
When the shape is moved up by k units, then replace y with y + k.
When the shape is moved down by k units, then replace y with y - k.
Example: What are the new coordinates when the translation (x, y) → (x - 2, y + 3) is applied to the point (2, 5).
Solution:
The coordinates of old point (preimage) are (x, y) = (2, 5). Now, applying the given translation to this point,
x - 2 = 2 - 2 = 0
y + 3 = 5 + 3 = 8
Thus, the coordinates of the translated point (image) are (0, 8).
This was the example of translation.
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HELP ME pls
moe is 8 years older than zach if 20 years ago moe was three times as old as zach what are there present ages
Answer:
34 and 30
Step-by-step explanation:
8 times 3 = 34
and 34-4=30
divide 8 by 2 and you'll get 4
so, 34-4=30
-1 = square root 5x – 9-X
Teresa has a $100 gift card to her favorite restaurant. Each day, she uses her gift card to buy the same lunch for $8.50. Colin has a $75 gift card to the same restaurant. His lunches cost $6 each. For what numbers of lunches will Teresa's gift card balance be greater than Colin's gift card balance?
Answer:
12 lunches.
Step-by-step explanation:
Theresa:
$8.50 * 11 = $93.50 so she can buy 11 lunches with her gift card.
Colin:
$6 * 12 = $72 so he can buy 12 lunches with his gift card.
So Colin can buy one more lunch than Theresa. Therefore, if Theresa buys 12 lunches, she will go over her gift card.
Make x the subject of the formula 6x+a=5
if f(x)= x^3+9x^2-12x-20 and f(-10)=0, then find all of the zeros of f(x) algebraically.
All of the zeros of f(x) algebraically is 3.
What is rational root theorem?
Mathematics has established the rational root theorem, sometimes known as the rational zero theorem. It states that if a polynomial's coefficients are integers, one may discover all rational roots by dividing each constant term factor by each leading coefficient factor.
\($$\begin{aligned}& \text { For } f=x^3+9 x^2-12 x-20 \text { substitute } x \text { with }-10 \\& =(-10)^3+9(-10)^2-12(-10)-20\end{aligned}$$\)
Simplify (-10)^3+9(-10)^2-12(-10)-20: 0
=0
x^3+9 x^2-12 x-20
Use the rational root theorem
=(x+1) \frac{x^3+9 x^2-12 x-20}{x+1}
\(\begin{aligned}& \frac{x^3+9 x^2-12 x-20}{x+1}=x^2+8 x-20 \\& =(x+1)\left(x^2+8 x-20\right)\end{aligned}\)
\(\begin{aligned}& \text { Factor } x^2+8 x-20: \quad(x-2)(x+10) \\& =(x+1)(x-2)(x+10)\end{aligned}\)
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PLEASE HELP WILL GIVE BRAINLIEST!!
Answer:
b. side-angle-side
Step-by-step explanation:
A statistical analysis of 1,000 long-distance telephone calls made by a company indicates that the length of these calls is normally distributed, with a mean of 290 seconds and a standard deviation of 30 seconds. Complete parts (a) through (c).
a. What is the probability that a call lasted less than 230 seconds?
The probability that a call lasted less than
23 seconds is ?
(Round to four decimal places as needed.)
b. What is the probability that a call lasted between 230 and 330 seconds?
The probability that a call lasted between
230 and 330 seconds is
(Round to four decimal places as needed.)
c. What is the probability that a call lasted more than 330 seconds?
The probability that a call lasted more than
330 seconds is
(Round to four decimal places as needed.)
To find the probability of the call lasting less than 230 seconds, we have to find P(X<230). Here X follows normal distribution with mean = 290
The given data: Meanμ = 290 seconds
Standard deviation σ = 30 seconds
Sample size n = 1000a) and
standard deviation = 30.
We get the value of 0.0228, which represents the area left (or below) to z = -2. Therefore, the probability that the call lasted less than 230 seconds is 0.0228 (or 2.28%). By using z-score formula;
Z=(X-μ)/σ
Z=(230-290)/30
= -2P(X<230) is equivalent to P(Z < -2) From z-table,
0.6384 (or 63.84%) P(230330) is equivalent to 1 - P(X<330)Here X follows normal distribution with mean = 290 and standard deviation = 30.From part b,
We already have P(X<330).Therefore, P(X>330) = 1 - 0.9082 = 0.0918, which is equal to 9.18%. Therefore, the probability that the call lasted more than 330 seconds is 0.1356 (or 13.56%).Answer: 0.1356 (or 13.56%). In parts a, b, and c, the final probabilities are rounded off to four decimal places as needed, as per the instructions given. However, these values are derived from the exact probabilities and can be considered accurate up to that point.
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help with my geometry please
Answer:
x = 11
z = 86
Step-by-step explanation:
8x + 6 and 10x-16 are vertical angles
Vertical angles are pairs of angles that are opposite each other and have the same vertex, or point of intersection. They are formed when two lines intersect at a point, and are always congruent, or of equal measure.
To solve this equation, we need to isolate the variable x on one side of the equation. To do this, we can start by subtracting 6 from both sides of the equation:
8x + 6 - 6 = 10x - 16 - 6
8x = 10x - 22
Now we can subtract 8x from both sides of the equation:
8x - 8x = 10x - 22 - 8x
0 = 2x - 22
To solve for x, we can add 22 to both sides of the equation:
0 + 22 = 2x - 22 + 22
22 = 2x
Finally, we can divide both sides of the equation by 2 to find the value of x: 22 / 2 = 2x / 2
x = 11
Therefore, the solution to the equation is x = 11.
Now that we have x, z is a supplementary angle to 8x + 6 (or you could do 10x - 16)
Supplementary angles are pairs of angles that add up to 180 degrees. They are formed when two lines intersect at a point, and the angles formed at the intersection are supplementary.
First plug in x, 8x + 6 = 8(11) + 6 = 88 + 6 = 94
180 - 94 = z
z = 86
In a Stock Dividend Multiple Choice Assets increase, Liabilities decrease. Assets decrease, Liabilities increase. Assets increase, Liabilities increase. Assets decrease, Liabilities decrease. Assets don't change, Liabilities don't change.
In a Stock Dividend Assets don't change, Liabilities don't change.
In a stock dividend scenario, where a company issues additional shares of its own stock to existing shareholders, the impact on the company's balance sheet is as follows:
Assets don't change, Liabilities don't change.
When a company declares a stock dividend, it is essentially distributing a portion of its retained earnings or accumulated profits to its shareholders in the form of additional shares. This means that the company is not receiving any new assets or incurring any new liabilities in the process.
From an accounting perspective, the value of the stock dividend is reflected in the equity section of the balance sheet. The retained earnings account decreases by the value of the dividend, while the common stock or additional paid-in capital account increases by the same value. This adjustment does not affect the company's assets or liabilities.
Therefore, the correct answer is: Assets don't change, Liabilities don't change.
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If t=5pi/3, find the terminal point P(x,y) on the unit circle.
Answer:
\((\frac{1}{2},-\frac{\sqrt[]{3}}{2})\)Explanation:
The given angle:
\(\frac{5\pi}{3}=\frac{5\times180}{3}=300^0\)For an angle in standard position on the unit circle, the location of the terminal point will be:
\(\begin{gathered} (x,y)=(\cos 300^0,\sin 300^0) \\ =(\frac{1}{2},-\frac{\sqrt[]{3}}{2}) \end{gathered}\)Find the area of each circle. Round to the nearest tenth.
Answer:
A≈50.27
Step-by-step explanation:
Using the formulas
A=πr2
d=2r
Solving forA
A=1/ 4πd^2=1/ 4·π·82≈50.26548
Answer:
Area= 50.3cm^2
Step-by-step explanation:
Use the area of a circle formula A= πr²
Then plug in your radius which is half of your diameter.
A=π(4)² = 50.3 cm²
Symbolize and construct proof for the following argument, providing the complete dictionary for each simple sentence, properly written as a syntactically correct sentence (including subject, verb, and object when applicable)
If the cat is ill, either she was fighting or ate too many mice. She was fighting only if she was attacked, and she was attacked only if either the large Siamese or the small Beagle was out. The large Siamese was out only if it was sunny, and the small Beagle was out only if it was warm. It was neither warm nor sunny, but the cat is ill. Therefore, she ate too many mice.
The argument can be symbolized as follows:
1. CI (Cat is ill)
2. FI (She was fighting)
3. AE (She ate too many mice)
4. FI ⟺ A (She was fighting only if she was attacked)
5. A ⟺ (LS ∨ SB) (She was attacked only if either the large Siamese or the small Beagle was out)
6. LS ⟺ S (The large Siamese was out only if it was sunny)
7. SB ⟺ W (The small Beagle was out only if it was warm)
8. ¬W ∧ ¬S (It was neither warm nor sunny)
To prove that she ate too many mice given the provided premises, we need to establish a logical deduction based on the symbols and relationships given.
1. CI (Cat is ill) - Given
2. FI ∨ AE (If the cat is ill, either she was fighting or ate too many mice) - Provided in the first sentence
3. FI ⟺ A (She was fighting only if she was attacked) - Provided in the second sentence
4. A ⟺ (LS ∨ SB) (She was attacked only if either the large Siamese or the small Beagle was out) - Provided in the third sentence
5. LS ⟺ S (The large Siamese was out only if it was sunny) - Provided in the fourth sentence
6. SB ⟺ W (The small Beagle was out only if it was warm) - Provided in the fourth sentence
7. ¬W ∧ ¬S (It was neither warm nor sunny) - Given
Now, we can start constructing the proof by applying logical deductions step by step.
8. ¬(W ∨ S) (De Morgan's Law, from 7)
9. ¬(SB ⟺ W) (Equivalence Law, from 6)
10. ¬(LS ⟺ S) (Equivalence Law, from 5)
11. ¬(A ⟺ (LS ∨ SB)) (Equivalence Law, from 4)
12. ¬(FI ⟺ A) (Equivalence Law, from 3)
13. ¬(FI ∨ AE) (Equivalence Law, from 2)
14. ¬FI ∧ ¬AE (De Morgan's Law, from 13)
15. ¬FI (Simplification, from 14)
16. ¬AE (Simplification, from 14)
17. ¬FI ∧ CI (Conjunction, from 15 and 1)
18. ¬(CI ⟶ ¬FI) (Implication Law, from 17)
19. CI ⟶ ¬FI (Contrapositive, from 18)
Since the negation of FI (not fighting) is true based on the premises, we can conclude that AE (ate too many mice) must be true. Therefore, the final deduction is AE (She ate too many mice).
Thus, the proof establishes that she ate too many mice based on the given premises and logical deductions.
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Jenna sold 63 bracelets at one craft show and 36 and another which expression correctly applies the distributive property to show the total. Umber of brackets she sold
Answer:
C . 63 + 36 = 9(7 + 4)
Step-by-step explanation:
Jenna sold 63 bracelets at one craft fair and 36 bracelets at a second craft fair. Which expression correctly applies the distributive property to show equivalent expressions for the total number of bracelets she sold?
63 + 36 = (3)(21) + (9)(4)
63 + 36 = (7)(9) + (12)(3)
63 + 36 = 9(7 + 4)
63 + 36 = 3(21 + 9)
To “distribute” means to divide something or give a share or part of something.
According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.
To determine the distributive property to show equivalent expression, find the common factors of 63 and 36
63 = 3, 7, 9, 21,
36 = 2, 3, 4, 6, 9, 12, 18,
Common factors of 63 and 36 are 3 and 9
Using 3
3(21 + 12)
Using 9
9(7 + 4)
3(21 + 12) is not one of the options, therefore, 9(7 + 4) is the answer
Option C gives the distributive property
63 + 36 = 9(7 + 4)
63 + 36 = 63 + 36
Which algebraic expression is equivalent to the expression below?
3(5x + 7) - 6(4 - 25)
Answer:
15x+21-24+150
15×+147
Answer:
15x + 147
Step-by-step explanation:
The given algebraic expression to us is ,
⇒ 3(5x + 7) - 6(4 - 25 )
On opening the brackets ,
⇒ 15x + 21 - 24 + 150
⇒ 15x + 147
A computer depreciates (decreases) in value upon purchase. After each
year, the value of the computer decreases by $200. If a computer is
purchased for $2.000. how much will the computer be valued after 6
years?
PLS help
Answer:
800 dollars
Step-by-step explanation:
Answer:
$800
Step-by-step explanation:
First we need to figure out how much the total depreciation is.
200 x 6 = 1,200
2,000 - 1,200 = 800
why we need to adding and subtracting fractions with unlike denominators worksheets
Adding and subtracting fractions with unlike denominators is an important skill for students to master in order to understand basic math concepts.
Unlike denominators are two fractions that have different denominators, such as 1/3 + 1/4. When fractions are added together with unlike denominators, the result is a fraction with a denominator that is a common multiple of the two original denominators.
Worksheets can provide students with the practice and repetition needed to become fluent in this skill.
Worksheets can help to provide context for the concept by explaining the steps involved in solving the problem. This can give students a better understanding of the concepts behind adding and subtracting fractions with unlike denominators and make them more confident in their abilities.
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The amount of money left in Alma's bank account is expressed by the linear equation y = -27x + 577, where x represents the number of weeks and y represents the amount of money left in her account. After how many weeks will Alma have $145 left in her account? 12 weeks 16 weeks 22 weeks 26 weeks
Given:
The linear equation is
\(y=-27x+577\)
where x represents the number of weeks and y represents the amount of money left in Alma's account.
To find:
The number of weeks in which Alma have $145 left in her account.
Solution:
We have,
\(y=-27x+577\)
Substitute y=145, we get
\(145=-27x+577\)
Subtract both sides by 577.
\(145-577=-27x\)
\(-432=-27x\)
Divide both sides by -27.
\(\dfrac{-432}{-27}=\dfrac{-27x}{-27}\)
\(16=x\)
So, the number of required weeks is 16. Therefore, the correct option is B.
Answer:
B
Step-by-step explanation:
Right on edge 2020
what are the conditions in which the approximate doubling time formula works well?
The approximate doubling time formula is used to estimate how long it takes for a population to double based on its growth rate. This formula works well under certain conditions.
Firstly, the population must be growing at a constant rate. Secondly, the growth rate must be exponential, which means that it is proportional to the current population size. Finally, the time period under consideration must be sufficiently short such that other factors that may influence population growth are negligible.
The approximate doubling time formula can be expressed as T = (ln 2) / r, where T is the doubling time, ln is the natural logarithm, and r is the growth rate. This formula estimates the time it takes for a population to double in size under constant exponential growth. This formula is useful for rapidly growing populations and can be used to make projections for future population sizes.
For example, the formula assumes that the population is growing constantly and that the growth rate is proportional to the population size. The formula may not be accurate if the population growth rate changes or is affected by external factors such as migration, disease, or natural disasters.
Thus, the approximate doubling time formula is a useful tool for estimating how long it takes for a population to double under constant exponential growth. This formula works well when the population is growing constantly, the growth rate is proportional to the population size, and the time period under consideration is sufficiently short.
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A farmer goes to the market to sell a box of eggs. A clumsy horse steps on the box of eggs and breaks a lot of them. The horse’s rider offers to pay for all of the eggs in the box and asks the farmer how many eggs there were. The farmer does not remember the exact number, but when she took them out of the box two at a time, there was 1 egg left. The same thing happened when she took them out three, four, five and six eggs at a time, but when she took them out 7 at a time, there were no eggs left
The smallest number of eggs that could have been in the box is 1134
The problem is to find the smallest number of eggs that could have been in the box, given the remainder when taking them out by different numbers. Here are the moves toward tackling it:
Allow n to be the quantity of eggs in the container. Then we have the accompanying arrangement of congruences:
n ≡ 1 (mod 2)
n ≡ 1 (mod 3)
n ≡ 1 (mod 4)
n ≡ 1 (mod 5)
n ≡ 1 (mod 6)
n ≡ 0 (mod 7)
For this problem, we have k = 6 k = 6, a i = {1,1,1,1,1,0} a_i = {1,1,1,1,1,0}, M i = {1260,840,630,504,420,720} M_i = {1260,840,630,504,420,720}, and y i = {−1,−2,−3,-4,-5,-6} y_i = {-1,-2,-3,-4,-5,-6}.
Plugging these values into the formula and simplifying modulo 5040, we get:
n = (−1260 + −1680 + −1890 + −2016 + −2100 + 0) mod 5040
n = (−8946) mod 5040
n = (−3906) mod 5040
n = 1134 mod 5040
Therefore, the smallest number of eggs that could have been in the box is 1134
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consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side length x. (a) determine a formula for the radius r in terms of x .
The formula for the radius r in terms of x . and for the maximum areas is x=2/\(\pi\)+4
Given that,
y forms a circle of radius r
y=2\(\pi\)r
r=y/2\(\pi\)
(2-y)- forms Square Side x
(2-y) = 4x
x=(2-y)/4
Now Sum of Area's=Area of Square +Area of Circle
Sum = \(\pi\)r² + x²
Substitute the r and x values in above equation,
A(y)= y²/4\(\pi\)+(y-2)²/ 16
To maximize Area A(y)
A'(y)= 0
2y/4\(\pi\) + 2(y-2)/16 =0
y/2\(\pi\) + (y-2)/8 =0
y = 2\(\pi\)/\(\pi\)+4
Y max will be max, x to be maximum.
for maximum sum of areas,
x=2/\(\pi\)+4
Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/\(\pi\)+4
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