A dog starts from point A and moves 15m toward the east, then turns 90 degrees south and moves 3m. His displacement is
is the answer for this one 15.3m SE

Answer:

The water particles move in the same direction as the vibrating source of the sound wave.

Explanation:

Answer:

The correct option is B.

Explanation:

Answer:

Atoms

________________

The spheres in this model represent atoms. The correct option is D.

Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.

All matter consists of atoms. Atoms of the same element are the same in size and atoms of different elements are different. Atoms combine in whole-number ratios to form compounds.

And in any model, the atoms are represented as a sphere.

Thus, correct option is D.

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The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer:

100m

Explanation:

Equation of motion for he truck: s=ut

Equation of motion for the car: s=1/2at^2

the second solution gives , s=2u^2/a = 2*10^2/2 = 100m

Classical mechanics describes the motion of objects on a macroscopic scale, while quantum mechanics deals with the behavior of particles on a microscopic scale. Classical mechanics is deterministic, meaning that it predicts precise outcomes based on initial conditions, while quantum mechanics is probabilistic, providing probabilities of different outcomes. Classical mechanics follows the principle of causality, where every effect has a specific cause, whereas quantum mechanics introduces inherent uncertainty and wave-particle duality. Classical mechanics is well-suited for describing everyday objects, while quantum mechanics is necessary to explain the behavior of particles at the atomic and subatomic levels.

~~~Harsha~~~

Answer:

\((a) 189.23 N\), \((b) 47.31 N\) and \((c) 141.92 N\).

Explanation:

Three balls are shown in figure having charge \(q=1.45 \mu C\). The middle ball, \(B\), is positively charged having charge \(+q\), and the remaining two outside balls, \(A\) and \(C\), are negatively charged having charged \(-q\) as shown.

\(AC=20 cm\) and \(AB=BC=10\) cm as B is the mid-point of AC.

Let \(d_1=AC=20\times 10^{-3}m\) and \(d_2=AB=BC=10\times 10^{-3}m\)

From Coulomb's law, the magnitude of the force, \(F\), between two point charges having magnitudes \(q_1 \& q_2\), separated by distance, \(d\), is

\(F=\frac {1}{4\pi\epsilon_0}\frac {q_1q_2}{d^2}\;\cdots (i)\)

where, \(\epsilon_0\) is the permittivity of free space and

\(\frac {1}{4\pi\epsilon_0}=9\times 10^9\) in SI units.

This force is repulsive for the same nature of charges and attractive for the different nature of charges.

Now, Using equations(i),

(a) The magnitude of attraction force between balls A and B is

\(F_{AB}=F_{BC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_2)^2}\)

\(\Rightarrow F_{AB}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(10\times 10^{-3}\right)^2}\)

\(\Rightarrow F_{AB}=189.23 N\)

(a) The magnitude of the repulsive force between balls A and C is

\(F_{AC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_1)^2}\)

\(\Rightarrow F_{AC}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(20\times 10^{-3}\right)^2}\)

\(\Rightarrow F_{AC}=47.31 N\)

(c) The magnitude of the net force, \(F_{net}\), on the outside of the ball is,

\(F_{net}=189.23-47.31 N\)

\(\Rightarrow F_{net}=141.92 N\)

Answer:

(a) Approximately \(0.335\; \rm m\).

(b) Approximately \(1.86\; \rm m\cdot s^{-1}\).

(c) Approximately \(0.707\; \rm m\).

(d) Approximately \(0.228\; \rm m\).

Explanation:

Consider the conversion of energy in this object-spring system.

First diagram: Right before the object came into contact with the spring, the object carries kinetic energy \(\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^2\).

Second diagram: As the object moves towards the position in the third diagram, the spring gains elastic potential energy. At the same time, the object loses energy due to friction.

Third diagram: After the velocity of the object becomes zero, it has moved a distance of \(D\) and compressed the spring by the same distance.

The sum of these two energies should match the initial kinetic energy of the object (before it comes into contact with the spring.) That is:

\(\displaystyle \frac{1}{2}\, m \cdot {v_{i}}^{2} = (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2\).

Assume that \(g = 9.81\; \rm m \cdot s^{-2}\). In the equation above, all symbols other than \(D\) have known values:

Substitute in the known values to obtain an equation for \(D\) (where the unit of \(D\!\) is \(m\).)

\(3.178 = 2.69775\, D + 25\, D^2\).

\(2.69775\, D + 25\, D^2 + 3.178 = 0\).

Simplify and solve for \(D\). Note that \(D > 0\) because the energy lost to friction should be greater than zero.

\(D \approx 0.335\; \rm m\).

The energy of the object-spring system in the third diagram is the same as the elastic potential energy of the spring:

\(\displaystyle \frac{1}{2}\,k\, D^2 \approx 2.81\; \rm J\).

As the object moves to the left, part of that energy will be lost to friction:

\((\mu \cdot m \cdot g) \, D \approx 0.905\; \rm J\).

The rest will become the kinetic energy of that block by the time the block reaches the position in the fourth diagram:

\(2.81\; \rm J - 0.905\; \rm J \approx 1.91\; \rm J\).

Calculate the velocity corresponding to that kinetic energy:

\(\displaystyle v =\sqrt{\frac{2\, (\text{Kinetic Energy})}{m}} \approx 1.86\; \rm m \cdot s^{-1}\).

As the object moves from the position in the fourth diagram to the position in the fifth, all its kinetic energy (\(1.91\; \rm J\)) would be lost to friction.

How far would the object need to move on the surface to lose that much energy to friction? Again, the size of the friction force is \(\mu \cdot m \cdot g\).

\(\displaystyle (\text{Distance Travelled}) = \frac{\text{(Work Done by friction)}}{\text{(Size of the Friction Force)}} \approx0.707\; \rm m\).

Similar to (a), solving (d) involves another quadratic equation about \(D\).

Left-hand side of the equation: kinetic energy of the object (as in the fourth diagram,) \(1.91\; \rm J\).

Right-hand side of the equation: energy lost to friction, plus the gain in the elastic potential energy of the spring.

\(\displaystyle {1.91\; \rm J} \approx (\mu\cdot m \cdot g) \cdot D + \frac{1}{2}\, k \cdot D^2\).

\(25\, D^2 + 2.69775\, D - 1.90811\approx 0\).

Again, \(D > 0\) because the energy lost to friction is greater than zero.

\(D \approx 0.228\; \rm m\).

The energy transferred between the object and the spring as a closed system, therefore, conserved are;

(a) The distance of compression, d ≈ 0.3354 meters

(b) The speed in the un-stretched position wen the object is sliding to the left, v ≈ 1.8623 m/s

(c) The distance where the object comes to rest, D ≈ 0.7071 m

(d) The distance the object will come to rest attached to the spring, D ≈ 0.2278 m

The reason the above values are correct are as follows;

The known parameters are;

Mass of the object, m₁ = 1.10 kg

Coefficient of friction, μ = 0.250

The initial speed of the object, \(v_i\) = 2.60 m/s

Force constant of the spring, K = 50.0 N/m

Distance the spring is compressed by the object = d

(a) Conservation of energy principle

\(Kinetic \ energy = \dfrac{1}{2} \cdot m\cdot v^2\)

Work done = Force × Distance

Friction force, \(F_f\) = W × μ

Weight, W = m·g

Weight = Mass × Acceleration

Energy transferred by object = Work done by spring + Work done by friction

\(Energy \ transferred \ by \ object = Kinetic \ energy = \dfrac{1}{2} \times 1.10\times 2.60^2 = 3.718\)

Energy transferred by object = 3.718 J

\(Work \ done \ by \ spring = \dfrac{1}{2} \cdot k\cdot x^2\)

\(Work \ by \ spring \ to \ bring \ object \ to \ rest, \ W_{spring} = \dfrac{1}{2} \times 50\times d^2\)

\(W_{spring}\) = 25·d²

Work done by friction, \(W_{friction}\) = 1.10×9.81×0.250×d = 2.69775·d

Therefore;

3.718 = 25·d² + 2.69775·d

25·d² + 2.69775·d - 3.718 = 0

Solving gives

The distance of the compression d ≈ 0.3354 m

(b) The energy given by the spring = 25·d²

The work done by friction, \(W_{friction}\) = 2.69775·d

Kinetic energy given to object = 0.55·v²

0.55·v² = 25·d² - 2.69775·d

0.55·v² = 25×0.3354² - 2.69775×0.3354

∴ v = √(3.4682) = 1.8623

The velocity of the object at the un stretched position, v ≈ 1.8623 m/s

(c) The kinetic energy, K.E. of the object on the way left is given as follows;

K.E. = 0.5 × 1.10 kg × 3.4682 m²/s² = 1.90751 J

The work done by friction before object comes to rest = 2.69775·D

\(D = \dfrac{1.90751 \, J}{2.69775 \, N} \approx 0.7071 \, m\)

The distance where the object comes to rest, D ≈ 0.7071 m

(d) The work done on spring, \(W_{spring}\) = 25·D'²

Work done on friction, \(W_{friction}\) = 2.69775·D'

Kinetic energy of object, K.E. ≈ 1.90751 J

K.E. = \(W_{spring}\) + \(W_{friction}\)

1.90751 ≈ 25·D'² + 2.6775·D'

25·D'² + 2.6775·D' - 1.90751 = 0

Solving with a graphing calculator gives;

D' ≈ 0.2278 m

The new value of the distance D = 0.2278 m

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Answer:

b

Explanation:

convert heat energy into mechanical

Answer:

I think it A. Average kinetic energy of

Explanation:

In solids, the molecules are very close together and the attraction between the molecules are great. This causes a substance to have a structure in which the molecules have little freedom to move, as you would see in the case of ice. In the case of a liquid, the molecules are closely spaced, though not as closely spaced as a solid, they have more freedom to move and the intermolecular forces are weaker that that of a solid. Thus a liquid can flow, unlike a solid. Now in a gas, the molecules are sufficiently far apart that there are little to no attractive forces. Because of this a gas can easily be compressed and take the shape of the container.

Now as you heat a solid turning it into a liquid, you increase the kinetic energy of its molecules, moving them further apart until the forces of attraction are reduced to allow it to flow freely. Keep in mind the forces of attraction still exists. Now as you heat a liquid, turning it into a gas, the kinetic energy of the molecules are increased to a point where there are no forces of attraction between the molecules.

The energy required to completely separate the molecules, moving from liquid to gas, is much greater than if you were just to reduce their separation, solid to liquid. Hence the reason why the latent heat of vapourization is greater that the latent heat of fusion.

Given,

Mass of the diver, m=70 kg

Height, h=5.0 m

The potential energy of the person when he was at a height of 5.0 m is

Where g is the acceleration due to gravity.

On substituting the known values,

According to the law of conservation of energy, his potential energy at the beginning will be converted to kinetic energy.

Therefore, the kinetic energy of the diver when he reaches the water is 3430 J

Answer:

1. game

2. game

3. game

4. sports

5. sports

6. game

7. game

8. sports

hope it helps:)

Answer:

1. sports

2. game

3. game

4. sports

5. sports

6. sports

7. game

8. game

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Explanation:

where is the question

I did not understood this question

Answers:

Here are the answers for the U2L9: Temperature & Heat Unit Test

1. Which describes how radiation moves?

  B) Radiation moves from a warmer object to a cooler object

2. Which material most likely gets warmer when places in the Sun?

  C) brown mulch

3. A thermogram of a house shows high amounts of thermal energy around the windows but not around the roof. Which conclusion is best supported by the thermogram?

  C) The windows are not energy efficient, but the roof is.

4. Which best describes convection?

  D) It is driven by temperature differences within a fluid.

5. A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm?

  Any answer you choose is correct on Connexus (look at the screenshot)

6. Convection only occurs in ____.

  B) fluids

7. Conduction involves the transfer of electric charge or ____.

  A) thermal energy

8. A scientist designed a foam container to help keep frozen foods from melting. Which best explains how the foam works?

  D) It reduces the amount of thermal energy that is transferred from the inside to the outside of the container.

9. The diagram shows movement of thermal energy. In which areas of the diagram does conduction occur? (look at the screenshot)

  B) X and Z

10. Nuclear reactions in a reactor produce a lot of thermal energy. That energy then flows and warms up water, which boils and produces steam. The stream then turns turbines that generate electricity. Which statement below can be made about the production of electricity in a nuclear reactor?

  B) Heat flows from the reactor to the water.

11. A stovetop burner on medium reaches 200° C. Which other objects will heat from the burner flow to?

     Any answer you choose is correct on Connexus (look at the screenshot)

12. Heat transfer between two substances is affected by specific heat and the

  D) amount of time and area of physical contact between the substances.

13. Which of these results in kinetic energy of an object?

  B) motion

14. Carmen is heating some water and trying to measure the temperature of water using a Celsius thermometer. Which measurement can she expect once the water begins to boil?

  B) 100° C

15. Which shows the formula for converting from degrees to Celsius to degrees Fahrenheit?

   A) °F = (9/5 × °C) + 32

16. Which of these indicates that a liquid has transferred thermal energy to the air?

  D) The liquid decreases in temperature, and its particles lose kinetic energy.

I took the test ALL of these answers are 100% correct on Connexus (they should be the same for everyone tho)

You're welcome and hope this helps!! :)

Explanation:

No matter where you are in the universe, your mass is always the same: mass is a measure of the amount of matter which makes up an object. Weight, however, changes because it is a measure of the force between an object and body on which an object resides (whether that body is the Earth, the Moon, Mars, et cetera).

Explanation:

Hence, weight of a body will change from one place to another place because the value of g is different in different places. For example, the value of g on moon is 1/6 times of the value of g on earth. As mass is independent of g , so it will not change from place to place.

A line of best fit is a straight line drawn through the most points on a scatter plot, with an equal number of points above and below the line. It is used to investigate the nature of the relationship between two variables. The correct option is d.

A straight line with the best fit is one that minimizes the distance between it and some data.

In a scatter plot of varying data points, the line of best fit is used to express a relationship. It is a result of regression analysis and can be used to forecast indicators and price movements.

It is important to note that your line does not need to pass through any of the points on the plot; it only needs to bisect the area that contains the data points.

Thus, none of the options are correct, the correct one is d.

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Answer:

they were fast ⛷⛷

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Answer:the answer would be C.50N

Explanation:I just took the test

Answer:

50n

Explanation:

The capacitance of the capacitor is 1.7 * 10^-4 F. The capacitance will increase when the voltage is increased.

If we hold the capacitance constant, a higher voltage applied to the capacitor will result in a greater amount of electrical charge stored on the capacitor. Conversely, if we hold the voltage constant, a capacitor with a higher capacitance will be able to store more electrical charge. In other words, the capacitance and the voltage are directly proportional to the amount of electrical charge that can be stored on a capacitor.

We know that;

q = CV

C = q/V

C =  0.0024 C/12 V

C = 1.7 * 10^-4 F

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Answer:

0.159

Explanation:

the formula to find its is 1÷2*gt^2

Answer:

D

Explanation:

v= a t

 = 5.1 * .25 = 1.275 m/s

Answer:

1 km

Explanation:

displacement =velocity ×time

displacement =40m/s ×25s

displacement =1000m equivalent to 1km

The environmental and familial challenges he faces indicate an increased risk of dropping out. Yes. Jacob's background suggests a lot of risk factors is the most accurate response. Here option A is the correct answer.

Jacob's situation presents several risk factors that could increase his likelihood of dropping out of high school. First, living in an economically depressed area can limit access to quality educational resources and opportunities, making it harder for Jacob to thrive academically. The lack of space in his small apartment further compounds the problem, as it becomes challenging for him to concentrate on his homework. The absence of a conducive environment for studying can negatively impact his motivation and ability to complete assignments consistently.

Moreover, Jacob's family dynamics may also contribute to his risk of dropping out. Being raised by a young mother, living with his grandmother, uncle, and little sister in a crowded space could imply limited financial resources and potential disruptions at home. These factors may increase stress levels and make it more difficult for Jacob to prioritize his education and engage in school-related activities effectively.

While race and ethnicity can influence educational outcomes, it is essential to consider the specific circumstances and individual factors in Jacob's life rather than assuming that race alone is the most important determinant.

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Answer:

A) When the insect starts to fall.

Assuming that the little insect can not do anything (he/she does not have wings or anything like that) the only force acting on the insect will be:

Gravitational force: Is the force that pulls down the insect.

Air resistance: As the insect starts to move, the air will try to oppose to that motion.

B) When the insect falls at a constant speed.

This will happen when the air resistance equals in magnitude (but in opposite direction) the gravitational force.

Now the net force is zero, so the insect is not accelerated anymore, which means that the insect moves at a constant speed.

And the fact that the net force is zero does not mean that the gravitational force and the air resistance are "not acting" on the insect, this means that those forces are not having any effect in the dynamics of the insect's motion.

C) When it lands.

When the insect lands, there is a new force that appears, the normal force of the ground that opposes to the movement of the insect through it.

As the insect comes to stop (because he hits the ground) the air resistance does not longer act on it, so now the normal force of the ground is equal in magnitude (but in opposite direction) to the gravitational force, then the net force is zero.

D) When is there a net force acting and in what direction?

The only time that is a net force acting, is when the insect starts to fall, where the gravitational force is accelerating the insect downwards.

E) What force pair is there when the insect lands?

The force pair is the gravitational force, and the reaction, the normal force of the ground.

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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a.

The difference in distance from point S and S' to point D is  seen to be as  1.25 mm.

b. the distance between the two sources is  12.8 mm.

Distance is described as a  a numerical or occasionally qualitative measurement of how far apart objects or points are.

We apply the formula of Δx = d sinθ

Δx=  difference in distance,

d=  distance between the two speakers = 4mm

θ =  angle between the line joining the two speakers and the line from the speakers to the point D, θ = tan^(-1)(1/3) = 18.43°

The distance between the two speakers is given as 4 mm.

Δx = d sinθ

Δx = 4 sin(18.43°)

Δx  = 1.25 mm

(b) we also use

λ = d sinθ

λ= wavelength of the sound waves = 4 mm

θ =  18.43°

d = λ/sinθ

d = (4 mm)/sin(18.43°)

= 12.8 mm

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