A dog walker earns $10 plus $3 per dog. What equation represents this model?

Answer:

Only one triangle is possible.

Step-by-step explanation:

Triangle inequality says that if sum of any two sides of the traingle is greater than the third side, then the triangle is possible.

Here,

,

Therefore, a triangle is possible with the given measurements,

Let us assume there is another triangle with same measurement with same measurements 7 cm, 6 cm, and 9 cm.,

By SSS congruency criteria both the triangles will be congruent.

Thus, all triangles with same measurement will be congruent to each other.

Hence, only one triangle is possible.

Answer:

one

took the quiz on k12 and got it right

Answer:

One third of 24

Step-by-step explanation:

because 3 is a whole number smaller than 4 so the answer would be 3/24 not 4/16.  

The difference between 1.42 and 0.53 is 0.37.

The model can be used to determine the difference between 1.42 and 0.53.

First, we start with 1 whole and 4 tenths (1.4) and represent it in the model. Next, we subtract 5 tenths (0.5) from 4 tenths (0.4). Since we cannot subtract directly, we need to regroup. We can regroup 1 whole into 10 tenths and then regroup 1 tenth into 10 hundredths. Now we have 10 tenths (1) and 40 hundredths (0.4).

Next, we subtract 3 hundredths (0.03) from 40 hundredths (0.4). This can be done directly since the place values match. Subtracting, we get 37 hundredths (0.37).

Therefore, the difference between 1.42 and 0.53 is 0.37.

To summarize, we regrouped to subtract 5 tenths from 4 tenths, and then subtracted 3 hundredths from 40 hundredths. The final answer is 0.37.

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The cosine for 60 degrees is ( 1 / 2 ) and the tangent will be √3.

Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. There are numerous distinctive trigonometric identities that relate to a triangle's side length and angle.

The trigonometric identities for the given image will be calculated as below:-

Cosine value:-

cos60 = Base / Hypotenuse

cos60 = 4 / 8 = 1 /  2

Tangent value:-

tan60 = perpendicular / Base

tan60= 4√3 / 4

tan60 = √3

Therefore, the cosine for 60 degrees is ( 1 / 2 ) and the tangent will be √3.

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Answer:

The smallest of the integers is 7

Step-by-step explanation:

Let the integers be x, y and z

From the question, the integers are consecutive odd integers.

Hence,

If the smallest of the integers is x and the largest is z, then we can write that,

x + 2 = y and

y + 2 = z

Then, x + 2 + 2 = z

∴ x + 4 = z ....... (1)

From the question, four times the smallest decreased by 5 is the same as the largest increased by 12, that is

4x -5 = z + 12 ....... (2)

Put the value of z = x + 4 in equation (1) into equation (2),

We then get

4x - 5 = x + 4 + 12

4x - x = 4 + 12 + 5

3x = 21

x = 7

Hence, the smallest of the integers is 7

The other integers are 9 and 11 ( y= 9 and z = 11)

Answer: There are too lots of results

Step-by-step explanation:

We can make it shorter: 192*n*m=36

n*m=36/192=3/16

...

n and m mustn't be 0 because they can't happen.

Answer:

Step 1, she reversed the values of x. It should have been 4 - (-2) not -2 - 4.

Step-by-step explanation:

Fern made a mistake in writing equation [1] where she wrote  {-2 - 4} in the denominator in place of {4 -(-2)}.

The general equation of a straight line is -

y = mx + c

Where -

[m] is the slope of the line.

[c] is the y - intercept

Given is Fern who is finding the slope of the line that passes through (-2, 8) and (4, 6).

In order to find the slope of the line, the following formula is used -

m = (y₂ - y₁)/(x₂ - x₁)

So, the slope of the line passing through the given points can be calculated using the following steps -

m = (6 - 8)/{4 -(-2)}                       ..[1]

m = -2/6                              

m = -1/3

Fern made mistake in writing equation [1]. She should have written

{4 -(-2)} in the denominator in place of {-2 - 4}

Therefore, fern made a mistake in writing equation [1] where she wrote  {-2 - 4} in the denominator in place of {4 -(-2)}.

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The median price from the given data is 648,303.

To find the median price from the given data, we need to arrange the prices in ascending order and then locate the middle value. If there is an odd number of data points, the median will be the middle value. If there is an even number of data points, the median will be the average of the two middle values.

Let's arrange the data in ascending order:

181,386,243,922,355,008,406,791,542,820,648,303,782,200,845,053,924,494,1,089,774,1,175,704,1,274,928,1,308,954

There are a total of 13 data points, which is an odd number. So, the median price is the middle value.

The middle value is the 7th value:

Median Price = 648,303

Therefore, the median price from the given data is 648,303.

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34 and 49 is  pair of numbers that are relatively prime.

What is relatively prime example?

What do you mean by relatively prime?

34 and 49 is the pair of numbers that are relatively prime.

The numbers have no common prime factors.

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Answer:

D

Step-by-step explanation:

Just did it on T4L

Answer:

5 a^3 c

Step-by-step explanation:

5 • a • a • c • a

There are 3 a's so it becomes a^3

5 a^3 c

The function has the value of its range decrease as the values in its domain increase is equals to \(f(x) = 0.3^ x \). So, option(B) is right one.

The domain of a function is defined as a set of all possible inputs for the function and range of the function is the set of all values that f takes. For example, the domain of f(x)=x² is all reals and range their corresponding values of f(x).

We have a number of functions and we have to check its range decrease as the values in its domain increase.

A) The function is defined as \(f(x) = 3^ x \), As we put values x from reals, x = 0,1,2,3,

=> f(x) = 3⁰, 3¹,3² ,...

so that with increase of input value of x ( domain) the value of range also increase.

B) function is defined, \(g(x) = 3.5^ x \)

As we put values x from reals, x = 0,1,2,3,

=> f(x) = 3.5⁰, 3.5,3.5² ,...

so that with increase of input value of x (domain) the value of range also increase.

C) The function is \(h(x) =0.3^{x}\)

As we put values x from reals, x = 0,1,2,3,

=> f(x) = 0.3⁰, 0.3,0.3² ,...

=> f(x) = 1, 0.3, 0.09,...

so that with increase of input value of x ( domain) the value of range decrease.

D) The function is \(k(x) = \frac{3 ^{x}}{2 } \)

As we put values x from reals, x = 0,1,2,3,

=>\( f(x) = \frac{ {3}^{0}}{2} , \frac{3^{1}}{2}....\)

= 0.5, 1.5,...

so that with increase of input value of x ( domain) the value of range is also increases. Hence, required value is

\(f(x) = 0.3^ x \)

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The function that has the values of its range decrease as the values in its domain increase is the function (C) h(x) = 0.3^x.

To see why, let's take a look at the

other functions:

(A) f(x) = 3^x: As x increases, 3^x also increases, so the range of f(x) increases as the values in its domain increase.

(B) g(x) = 3.5^x: Similarly to (A), as x increases, 3.5^x also increases, so the range of g(x) increases as the values in its domain increase.(D) k(x) = 1/2(3^x): As x increases, 3^x increases, so 1/2(3^x) also increases, although at a slower rate. Therefore, the range of k(x) increases as the values in its domain increase.

However, for (C) h(x) = 0.3^x: As x increases, 0.3^x decreases, approaching zero. Therefore, the range of h(x) decreases as the values in its domain increase.

Thus, the answer is (C) h(x) = 0.3^x.

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Answer:

(-8, -4) U (0, 4)

Step-by-step explanation:

Answer:

Please give Brainliest!

Step-by-step explanation:

The three dimensions are 36ft, 72ft, and 59ft.

9514 1404 393

Answer:

  y -k = m(x -h)

Step-by-step explanation:

To translate a function right by h units, replace x with (x -h).

To translate a function up by k units, replace y with (y -k).

The translated function is ...

  y -k = m(x -h)

_____

Additional comment

You may recognize this as the "point-slope" form of the equation of a line. The "parent function" is the line through the origin with slope m:

  y = mx

The translation above makes it be a line through (h, k) with slope m.

Answer:

B

Step-by-step explanation:

a² + 14a - 51 = 0 ( add 51 to both sides )

a² + 14a = 51

to complete the square

add ( half the coefficient of  the x- term )² to both sides

a² + 2(7)a + 49 = 51 + 49

(a + 7)² = 100 ( take square root of both sides )

a + 7 = ± \(\sqrt{100}\) = ± 10 ( subtract 7 from both sides )

a = - 7 ± 10

then

a = - 7 + 10 = 3

a = - 7 - 10 = - 17

To create an interaction term, we must multiply the variables by each other. The correct answer is d.

When we want to examine the interaction between two variables in a regression model, we create an interaction term by multiplying the variables together. This allows us to capture how the relationship between the variables changes depending on the values of both variables.

For example, let's say we have two variables, X1 and X2, and we want to examine how their interaction affects the outcome variable Y. By creating an interaction term, X1*X2, we can include it as an additional predictor in the regression model. The coefficient of the interaction term will represent the change in the relationship between X1 and Y for each unit change in X2.

Multiplying the variables together helps us capture the combined effect or interaction that cannot be fully explained by the individual variables alone. It allows us to account for the joint influence of the variables and understand how their combined effect affects the outcome of interest.

Therefore, to create the interaction term, we multiply the variables by each other. The correct answer is d.

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Answer

2.5w+4=2u

3. z+6*y

4. 2.5/a=4

Step-by-step explanation:

sorry about the other ones they were confusing hope these are right if not im  so sorry

Answer:

1.5 or 1 ½ pages per min

Step-by-step explanation:

7.5/5=1.5

She reads 1 ½ pages per min

Answer: 1.5 pages per minute

Step-by-step explanation:

Divide the total number of pages she read by 5, the amount of time it took her. So it should look like this: 7.5/5

The answer is 1.5 pages per minute.

To accumulate $2,176,097.00 in his retirement account by age 65, Derek needs to make annual deposits of $5,000.00 starting on his 27th birthday and ending on his 65th birthday, assuming an 8.00% interest rate.

To determine the annual deposits Derek needs to make, we can use the future value of an ordinary annuity formula. First, we calculate the number of years between Derek's 25th and 65th birthdays, which is 65 - 25 = 40 years. Next, we calculate the future value of the retirement account using the given interest rate of 8.00%. Using the formula:

Future Value = Present Value * (1 + interest rate)^number of periods

In this case, the future value is $2,176,097.00, the interest rate is 8.00%, and the number of periods is 40. We can rearrange the formula to solve for the present value:Present Value = Future Value / (1 + interest rate)^number of periods

Substituting the values:Present Value = $2,176,097.00 / (1 + 0.08)^40 = $123,529.31 (rounded to 2 decimal places)

Now, we need to find the annual deposit amount. Since Derek starts making deposits on his 27th birthday and ends on his 65th birthday, he makes deposits for 65 - 27 = 38 years.Annual Deposit = Present Value / ((1 + interest rate)^number of periods - 1)Substituting the values:

Annual Deposit = $123,529.31 / ((1 + 0.08)^38 - 1) = $5,000.00 (rounded to 2 decimal places)Therefore, Derek must make annual deposits of $5,000.00 into his retirement account starting on his 27th birthday and ending on his 65th birthday to accumulate $2,176,097.00 by the time he turns 65.

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Each sample has its own sample mean, and the distribution of sample means is called the sampling distribution. The average weight calculated for each sample set is the average sampling distribution.

The sample mean of sampling distribution, μₓ is 13.6..

We have given that

Sample : number of credits obtained by students

Sample size, n = 45

Sample standard deviations, σ = 2.1

population mean , μ = 13.6

we have to determine the sample mean of collected credits registered by them in this semester.

As we know , For samples of any size taken from a normally distributed population, then the sample mean is normally distributed, with mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size.

so, sample mean μₓ = μ= 13.6

and σ ₓ= σ /√n = 2.1/√45 = 0.372

So, Sample mean of Sampling distribution is 13.6 ..

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Answer:

Zero of the function f(x) is at x = 0

Vertical Asymptotes at x = ±6

Horizontal Asymptotes at y = 0

Step-by-step explanation:

For a given function f(x):

Vertical Asymptotes are obtained at those values of x, where the function f(x) tends to infinity, I.e.,

When x approaches some constant value but the curve moves towards infinity.

Vertical Asymptotes of the given function can be obtained by walking thru the following steps:

Step I

(Factorise the numerator and denominator)

\( \mathsf{ f(x) = \frac{6x}{ {x}^{2} - 36 } }\)

x² - 36 can be factorised into (x + 6)(x - 6)

and, ofcourse, we can write 6x as 6(x - 0)

\( \mathsf{ f(x) = \frac{6(x - 0)}{ (x + 6)(x - 6) } }\)

Step II

(Reduce the fraction to its simplest form by canceling out the common factors)

There aren't any common factors in the numerator and denominator in this case.

Step III

(Look for the values of x which cause the denominator to be zero)

If we put x = 6

denominator becomes 0

Also,

If we substitute x with -6

denominator becomes 0.

The two values of x indicate the two Vertical Asymptotes of the function f(x).

Therefore,

Vertical Asymptotes of the given function f(x) are:

\( \boxed{ \mathsf{x = \pm6}}\)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Horizontal Asymptotes are obtained When x tends to infinity and y approaches some constant value.

I'll be using the concept of limits for this.

\( \mathsf{y = \frac{6x}{ {x}^{2} - 36 } }\)

dividing and multiplying by x² (Yep! so if x becomes infinity 1/ x and 1/ x² all such terms become 0, 'cause 1/ ∞ is 0)

\( \implies \mathsf{y = lim_{x \rightarrow \infty }( \frac{ \frac{6x}{ {x}^{2} } }{ \frac{ {x}^{2} - 36 }{ {x}^{2} } } ) }\)

\( \implies \mathsf{y = lim_{x \rightarrow \infty }( \frac{ \frac{6}{ x } }{ 1- \frac{36 }{ {x}^{2} } } ) }\)

Substitute x with ∞, you get zero/ 1

\( \implies \boxed{\mathsf{y = 0}}\)

So, the horizontal Asymptote of the function is y = 0, that is the x axis

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The values of x that reduces f(x) to zero are called the zeroes of f(x).

Here, only x = 0 acts as the zero of the function.

[NOTE:

__________________

[That's what it's graph looks like. ]

Using a system of equations, it is found that there are 10 baskets that hold 4 meals in the shop.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given by:

There are 25 baskets in the shop, hence:

x + y = 25 -> x = 25 - y

They can hold a total of 70 meals, hence:

2x + 4y = 70

2(25 - y) + 4y = 70

2y = 20

y = 10

There are 10 baskets that hold 4 meals in the shop.

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The statement (D) "If f(c) is differentiable on its domain, then it is also continuous on its domain" must be true.

(A) The statement "Continuous functions are differentiable wherever they are defined" is false. While it is true that differentiable functions are continuous, the converse is not always true. There exist continuous functions that are not differentiable at certain points, such as functions with sharp corners or cusps.

(C) The statement "If f() is differentiable on the interval (0,0), then it must be differentiable everywhere" is false. Differentiability on a specific interval does not imply differentiability everywhere. A function can be differentiable on a particular interval but not differentiable at isolated points or on other intervals.

(D) The statement "If f(c) is differentiable on its domain, then it is also continuous on its domain" is true. Differentiability implies continuity. If a function is differentiable at a point, it must also be continuous at that point. Therefore, if f(c) is differentiable on its domain, it must also be continuous on its domain.

(B) The statement "The product of two differentiable functions is not always differentiable" is false. The product of two differentiable functions is always differentiable. This is known as the product rule in calculus, which states that if two functions are differentiable, then their product is also differentiable.

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the solution to the system of equations is x = 2 and y = 1.

To solve the system of equations by substitution, we will solve one equation for one variable and substitute it into the other equation.

Given the system of equations:

1) y = 6x - 11

2) -2x - 3y = -7

Step 1: Solve equation (1) for y.

  y = 6x - 11

Step 2: Substitute the value of y from equation (1) into equation (2).

  -2x - 3(6x - 11) = -7

Step 3: Simplify and solve for x.

  -2x - 18x + 33 = -7

  -20x + 33 = -7

  -20x = -7 - 33

  -20x = -40

  x = (-40)/(-20)

  x = 2

Step 4: Substitute the value of x into equation (1) to find y.

  y = 6(2) - 11

  y = 12 - 11

  y = 1

Therefore, the solution to the system of equations is x = 2 and y = 1.

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The solution to the system of equations y = 6x - 11 and -2x - 3y = -7 is x = 2 and y = 1. This is achieved by substituting y into the second equation, simplifying, and solving for x, then substituting x back into the first equation to solve for y.

To solve the system of equations y = 6x - 11 and -2x - 3y = -7 by substitution, we start by substituting the equation y = 6x - 11 into the second equation in place of y, giving us -2x - 3(6x - 11) = -7. Next, simplify the equation by distributing the -3 inside the parentheses to get -2x - 18x + 33 = -7. Combine like terms to get -20x + 33 = -7. Subtract 33 from both sides to obtain -20x = -40, and finally, divide by -20 to find x = 2.

Once we find the solution for x, we substitute it back into the first equation y = 6x - 11. Substituting 2 in place of x gives y = 6*2 - 11, which simplifies to y = 1.

Therefore, the solution to the system of equations is x = 2 and y = 1.

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The dimensions of a horizontal cross-section will vary depending on the specific shape or object being considered.

To determine the dimensions of a horizontal cross-section, we need more specific information about the object or shape in question.

A horizontal cross-section refers to a slice or cut made parallel to the horizontal plane.

The dimensions of a horizontal cross-section will depend on the shape or object being sliced. For example, if we have a rectangular prism, a horizontal cross-section would result in a rectangle.

The dimensions of this rectangle would be equal to the dimensions of the corresponding face of the prism.

If we have a cylindrical object, a horizontal cross-section would result in a circle. The dimensions of this circle would be determined by the radius or diameter of the cylinder.

It is essential to provide more information about the shape or object to determine its corresponding horizontal cross-section dimensions.

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The recursive rule for the sequence in the graph is aₙ = aₙ₊₁ + 4

Recursive rule are the rules that continually takes a previous number and changes it to get to a next number.

It gives first term or terms of sequence and describes how term is related to previous term with an equation.

Looking at the graph ,

taking first two point  ,n = 1 and n = 2

At n = 1 , a(n) = 13

At n = 2 , a(n) = 9

so , 9 = 13 - 4

we can write it as,

a₂ = a₁ - 4

Hence , recursive formula for sequence :

aₙ₊₁ = aₙ - 4

bring aₙ to the left

=>  aₙ = aₙ₊₁ + 4 is required recursive formula

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Answer:

122.5 minutes

Step-by-step explanation:

21 hotdigs in 6 min

1 hotdog 3.5 minutes

therefore 35 hotdogs = 122.5 minutes

Answer:

27

Step-by-step explanation:

its 3 times 3 times 3