A farmer plants the same amount every day, adding up to 1 3/4 acres at the end of the year. If the year is 1/2 over, how many acres has the farmer planted?

Answer:

11. The student put 24 as the diameter instead of the radius.

12. 48 pi

Step-by-step explanation:

The formula for the circumference of a circle is c = pi x diameter.

However, the question says that the radius is 24m, not the diameter.

To fix it, all you need to to is double the radius to get 48m for the diameter.

48 x pi = 48 pi

Answer:

Step-by-step explanation:

π = 22/7 or 3.14

Circumference= diameter × 22 / 7

= 2 × radius × 22 / 7

= 2 × 24 × 22/ 7

= 48 × 22 / 7

= 48 / 1 × 22 / 7

= 1056 / 7

= 150.8571428 m

Answer:

im gonna tell you its none promise

The approximate percent decrease in the number of customers from Saturday to Sunday is 33%. Therefore, the answer is option A: 33%

To find the approximate percent decrease in the number of customers from Saturday to Sunday, we first need to calculate the decrease in the number of customers:

Decrease = Saturday customers - Sunday customers

Decrease = 135 - 90

Decrease = 45

The percent decrease can be found by taking the decrease as a percentage of the original value (Saturday customers):

Percent decrease = (Decrease / Saturday customers) x 100%

Percent decrease = (45 / 135) x 100%

Percent decrease = 33.33%

Rounding to the nearest percent, we get that the approximate percent decrease in the number of customers from Saturday to Sunday is 33%. Therefore, the answer is option A: 33%.

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Your question is incomplete, but probably the complete question is :

You work as a cashier in a supermarket. On Saturday, you had 135 customers. On Sunday, you had 90 customers. What is the approximate percent decrease in the number of customers from Saturday to Sunday?

33%

45%

50%

90%

225%

Answer:

Step-by-step explanation:

Substitute the values of x:

P(1) = 6

P(-1) = 2

Substitute a in the previous equation:

Then finding a:

So a = 3, b = 2

The interval of I₁ or I₂ or I₄ is  (2.5 ,10].

The interval of I₁ and I₂ is  [3 , 5.5] .

The interval of I₁ and I₃ is  [5.5]

The interval of I₁ and I₄ is (5.6 , 7]

(a) because the all 3 intervals square measure connected by or which suggests they're going to all embrace the quantity lying from interval one to three and is given by (2.5 ,10].

(b) because the interval square measure connected by and which suggests the common numbers lying in interval one and a couple of and is given by [3 , 5.5] .

(c) because the interval square measure connected by and which suggests the common numbers lying in interval one and three and is given by [5.5]

(d)As the interval square measure connected by and which suggests the common numbers lying in interval one and four and is given by (5.6 , 7] .

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The complete question is given below :

Given the intervals I₁ = (2.5, 5.5], I₂ =[3, 6], I₃=[5.5, 7] and I₄ = (5.5, 10]. Find

(a) I₁ or I₂ or I₄

(b) I₁ and I₂

(c) I₁ and I₃

(d) I₁ and I₄

The requried measure of the angle m∠BCD is 28°.

Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.

Here,
From the figure,
m∠BOD = 2m∠BFD
            = 2 × 76°
            = 152°

OD perpendicular to CE simultaneously OB perpendicular to CA
m∠ODC = m∠OBC = 90°

m∠ODC + m∠OBC + m∠BOD + m∠BCD = 360
90 + 90 + 152 + m∠BCD = 360
m∠BCD = 28°

Thus, the requried measure of the angle m∠BCD is 28°.

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The dollar gains depreciated relative to the pound when the price of pounds in dollars increases, for instance, from $1 = 1 pound to $2 = 1 pound.

Devaluation of a currency can take place in both absolute and relative terms. When the value of one currency declines in relation to the values of other currencies, this is referred to as a relative devaluation. For instance, the British pound sterling may be worth more today than it did yesterday in terms of US dollars.

A currency's value declines when compared to other currencies, which is known as currency depreciation. Political unrest, interest rate differences, weak economic fundamentals, and investor risk aversion are a few examples of the causes of currency devaluation.

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Answer:

y = 3x - 5

Step-by-step explanation:

Find the slope using rise over run (y2 - y1) / (x2 - x1)

Plug in the points:

(13 - 7) / (6 - 4)

6 / 2

= 3

Then, plug this and a point into y = mx + b to solve for b:

y = mx + b

7 = 3(4) + b

7 = 12 + b

-5 = b

Then, plug this and the slope into y = mx + b to get the equation:

y = 3x - 5 will be the equation

Answer:

Step-by-step explanation:

The probability of flipping heads is 20% (or 0.2), the probability of flipping tails is 80% (or 0.8).

It is a branch of mathematics that deals with the occurrence of a random event.

There are four possible outcomes when flipping an unfair coin twice, since each coin flip has two possible outcomes (heads or tails).

We can use H to represent heads and T to represent tails.

The possible outcomes are:

HH (both flips are heads)

HT (first flip is heads, second flip is tails)

TH (first flip is tails, second flip is heads)

TT (both flips are tails)

Each of these outcomes has a certain probability associated with it.

Since the probability of flipping heads is 20% (or 0.2), the probability of flipping tails is 80% (or 0.8).

Hence, the probability of flipping heads is 20% (or 0.2), the probability of flipping tails is 80% (or 0.8).

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Given,

\( \: \)

To Find,

\( \: \)

Solution :

First of all, we'll find the circumference of the circle :

\(\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Circumference_{(circle)} = 2 \pi r}}}}}} \: \: \bigstar \\ \\\)

Now, we'll substitute the required values in the formula :

\(\\ { \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle)} = 2 \times 3.14 \times 3.5}}} \: \: \\ \\\)

\( { \longrightarrow \qquad{ \sf{ \: \: Circumference_{(circle)} = 3.14 \times 7}}} \: \: \\ \\\)

\( { \longrightarrow \qquad{ \sf{ \pmb{ \: Circumference_{(circle)} = 21.98}}}} \: \: \\ \\\)

Therefore,

\( \: \)

Now, we'll find the area of the circle :

\(\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{ \: \: Area_{(circle)} = \pi r^2}}}}}} \: \: \bigstar \\ \\\)

\({ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_{(circle)} = 3.14 \times { \times (3.5)}^{2} }}}}}} \: \: \\ \\\)

\({ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_{(circle)} = 3.14 \times { \times 3.5 \times 3.5 }}}}}}} \: \: \\ \\\)

\({ \longrightarrow \qquad{ {{ { \sf{ \: \: Area_{(circle)} = 3.14 \times 12 .25 }}}}}} \: \: \\ \\\)

\({ \longrightarrow \qquad{ {{\pmb { \sf{ \: \: Area_{(circle)} = 38.465 }}}}}} \: \: \\ \\\)

Therefore,

The given double integral is ∫ ∫ (x² + y²)dx dy, and we need to evaluate it over the region in the positive quadrant where x+y≤1.

To evaluate this double integral, we can first determine the limits of integration for both x and y based on the given region. In the positive quadrant, x and y both range from 0 to 1.

Now, integrating the inner integral with respect to x, we get:

∫ (x² + y²)dx = (1/3)x³ + y²x + C1,

where C1 is the constant of integration.

Next, we integrate the resulting expression with respect to y:

∫ [(1/3)x³ + y²x + C1] dy = (1/3)x³y + (1/3)y³x + C1y + C2,

where C2 is another constant of integration.

Finally, we evaluate this double integral over the given region by substituting the limits of integration:

∫∫ (x² + y²)dx dy = ∫[0 to 1] ∫[0 to 1-x] (x² + y²)dy dx.

Performing the integration, we can find the numerical value of the double integral within the given region.

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Answer:the width =5x-2 hight=6x+1

Step-by-step explanation:

Therefore , the solution of the given problem of expression comes out to be 2x² (2x² - 1 ) / (x⁴ + 1 - 2x²) .

Mathematical operations including addition, subtraction, multiplication, and division are required. They result in the following when combined: An equation, some information, and an arithmetic operator Values, parameters, and operations like adds, omissions, multiplications, and divisions make up a statement of fact. Different phrases and words can be contrasted and compared.

Here,

Given :

=> 2x² / x² -1

=> 2x² / x² -1  *  x² -1 /x² -1

=> 2x²(x²-1) / (x² -1)²

=> 2x⁴ - 2x² / (x⁴ + 1 - 2x²)

=>  2x² (2x² - 1 ) / (x⁴ + 1 - 2x²)

Therefore , the solution of the given problem of expression comes out to be 2x² (2x² - 1 ) / (x⁴ + 1 - 2x²) .

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I would say the one with:

-5m + (-15) <= -80.

As you can see, the diver is going down 5 meters per minute so the slope should be -5.

The diver starts at 15 meter below so it should be -15.

Answer:

its 37

Step-by-step explanation:

Answer:

A. 37

Step-by-step explanation:

Answer:

43 m. Perimeter is all the sides added together.

A solution to the given system of linear inequalities is (-6, -1).

In order to to graph the solution to the given system of inequalities on a coordinate plane, we would use an online graphing calculator to plot the given system of inequalities and then take note of the point of intersection;

2x + 7y ≤ -14     .....equation 1.

-3x + 5y > 5    .....equation 2.

Based on the graph (see attachment), we can logically deduce that the solution to the given system of inequalities is the shaded region below the solid and dashed line, and the point of intersection of the lines on the graph representing each, which is given by the ordered pair (-6, -1).

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Answer:

  False

Step-by-step explanation:

You want to know if it is true that the graph of a rational function cannot cross a horizontal asymptote.

Once a function is on its final approach to an asymptote, it will approach, but not cross, that asymptote.

The function may have a variety of behaviors prior to that point, so may cross the horizontal asymptote one or more times before its final behavior is established.

An example with the asymptote y = 0 is attached.

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Student 1 made measurements with the least variability after performing the natural logarithm transformation on each measurement taken by the four students.

To determine which student made measurements with the least variability, we need to calculate the standard deviation for each student's set of measurements.

First, we calculate the natural logarithm of each measurement for all three students and compute their means

Student 1: ln(6.8), ln(6.3), ln(5.8), ln(5.8), ln(6.8)

Mean = 1.906

Student 2: ln(7.4), ln(3.6), ln(5.8), ln(5.3), ln(7.3)

Mean = 2.924

Student 3: ln(7.4), ln(3.6), ln(5.8), ln(5.3), ln(7.3)

Mean = 2.924

Then, we calculate the sample standard deviation for each student's set of measurements

Student 1: s = 0.367

Student 2: s = 1.592

Student 3: s = 1.592

Therefore, student 1 made measurements with the least variability, as their set of measurements has the smallest standard deviation.

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\((\stackrel{x_1}{-2}~,~\stackrel{y_1}{-14})\qquad (\stackrel{x_2}{h}~,~\stackrel{y_2}{28}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{28}-\stackrel{y1}{(-14)}}}{\underset{run} {\underset{x_2}{h}-\underset{x_1}{(-2)}}} \implies \cfrac{28 +14}{h +2}~~ = ~~\text{\LARGE 6}\implies \cfrac{42}{h+2}=6 \\\\\\ 42=6h+12\implies 30=6h\implies \cfrac{30}{6}=h\implies \boxed{5=h}\)

Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

Step 1

Given;

Required; Find the equation of a line that goes through the point ( 1,- 6 ) and is perpendicular to the line: y = (1 / 8)x - 9

Step 2

For perpendicular lines, the relationship between the slopes is;

The y-intercept is found thus;

Answer; The required equation will be;

:)

Step-by-step explanation:

185 is to 14.8 as x is to 18.5

185/14.8 = x/18.5

x = 185(18.5)/14.8

x = $231.25

Answer:

10. 7 + 4a

11. 7a + 4

12. 12a - 4

13. 14(a - 4)

14. 2a + b

15. 2(a + b)

16. 1/3x - 5

17. 3x/8

18. ab / a+b

Step-by-step explanation:

Let x be the number.

Can't explain, I need to do homework.

Hope this helps :)

Answer:

To solve this problem, we will use the following steps:

Step 1: We know that the amount of time it takes Susan to get from her residence to class averages 50 minutes, with a standard deviation of 5 minutes. So we can use this information to calculate the proportion of Susan's trips to class that would take less than 40 minutes.

Step 2: To calculate the proportion of Susan's trips to class that would take less than 40 minutes, we need to find the z-score for the value of 40 minutes. We can use the following formula to find the z-score:

z = (x - μ) / σ

Where x is the value we are interested in (40 minutes), μ is the mean (50 minutes), and σ is the standard deviation (5 minutes).

z = (40 - 50) / 5 = -2

Step 3: We can use a standard normal table or a calculator to find the proportion of Susan's trips to class that would take less than 40 minutes.

The proportion of Susan's trips to class that would take less than 40 minutes is 0.0228 or 2.28%.

Step 4: To calculate the proportion of Susan's trips to class that would take more than 50 minutes or less than 40 minutes, we need to find the proportion of Susan's trips to class that would take more than 50 minutes and add it to the proportion of Susan's trips to class that would take less than 40 minutes.

Step 5: To find the proportion of Susan's trips to class that would take more than 50 minutes, we need to find the z-score for the value of 50 minutes.

z = (50 - 50) / 5 = 0

Using a standard normal table or a calculator, the proportion of Susan's trips to class that would take more than 50 minutes is 0.5 or 50%.

Step 6: Finally, we can add the proportion of Susan's trips to class that would take more than 50 minutes and the proportion of Susan's trips to class that would take less than 40 minutes to find the proportion of Susan's trips to class that would take more than 50 minutes or less than 40 minutes.

0.50 + 0.0228 = 0.5228 or 52.28%

Final Answer: The proportion of Susan's trips to class that would take more than 50 minutes or less than 40 minutes is 0.5228 or 52.28%.

The curve given by the equation y = (x^2)/(x^4 + 2) has a horizontal asymptote at y = 0 and no vertical asymptote. To make the function f(x) = ax^2 - bx + 3 continuous everywhere, the values of a and b need to satisfy certain conditions.

To find the horizontal asymptote, we consider the behavior of the function as x approaches positive or negative infinity. Since the degree of the denominator is greater than the degree of the numerator, the function approaches 0 as x approaches infinity. Hence, the horizontal asymptote is y = 0.

For vertical asymptotes, we check if there are any values of x that make the denominator equal to zero. In this case, the denominator x^4 + 2 is never equal to zero for any real value of x. Therefore, there are no vertical asymptotes for the given curve.

Moving on to the continuity of f(x), we have two cases: x < 2 and x ≥ 2. For x < 2, f(x) is given by -4, which is a constant. So, it is already continuous for x < 2. For x ≥ 2, f(x) is given by ax^2 - bx + 3. To make f continuous at x = 2, we need the right-hand limit and the value of f(x) at x = 2 to be equal. Taking the limit as x approaches 2 from the left, we find that it equals 4a - 2b + 3. Thus, to ensure continuity, we need 4a - 2b + 3 = -4. The values of a and b can be chosen accordingly to satisfy this equation, and the function will be continuous everywhere.

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The integrating factor for the given differential equation `ty' +(t – 4)y = 1+ t^2` is `I = 1 / t^3`, and the general solution of the given differential equation is `y = t^3 [(ln|t| - 1 / t^2) / 2 + C]` where `C` is the arbitrary constant.

Given differential equation is `ty' +(t – 4)y = 1+ t^2`. We have to find the integrating factor of this differential equation. For this, we follow the below steps:

The differential equation is `ty' +(t – 4)y = 1+ t^2`. To find the integrating factor `I`, we first write the equation in the form:`

y' + p(x) y = q(x)`where

`p(x) = (t - 4) / t` and

`q(x) = (1 + t^2) / t`

The integrating factor `I` is given by:`

I = e^(∫p(x) dx)`

Substituting the values of `p(x)`:

`I = e^(∫[(t - 4) / t] dt)`

On solving the integral, we get:`

I = e^(ln|t| - 4 ln|t|)`

Therefore, the integrating factor is:

`I = e^(-3 ln|t|)

= e^(ln|t^(-3)|)

= 1 / t^3`

We multiply both sides of the differential equation by the integrating factor `1 / t^3`:`

(1 / t^3) ty' + (1 / t^2 - 4 / t^3)

y = (1 / t^3) (1 + t^2)`

On simplifying, we get:`

d / dt [(y / t^3)] = (1 + t^2) / t^3

`Integrating both sides w.r.t `t`:`

y / t^3 = (ln|t| - 1 / t^2) / 2 + C``

y  = t^3 [(ln|t| - 1 / t^2) / 2 + C]`

Therefore, the integrating factor for the given differential equation `ty' +(t – 4)y = 1+ t^2` is `I = 1 / t^3`, and the general solution of the given differential equation is `y = t^3 [(ln|t| - 1 / t^2) / 2 + C]` where `C` is the arbitrary constant.

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Answer:

= 51/110

Step-by-step explanation:

No: of bags with buttons but no zips  = 46

No: of bags that have both buttons and zipz = 110-(46+20+39)  =  5

No: of bags with buttons = 46+ 5 = 51

Total no: of bags = 110

= 51/110

Answer: I hope these two answers help please mark me brainlist

Step-by-step explanation:

Simplifying

z = 6(x + -1h)

Reorder the terms:

z = 6(-1h + x)

z = (-1h * 6 + x * 6)

z = (-6h + 6x)

Solving

z = -6h + 6x

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Simplifying

z = -6h + 6x

or another answer

6(x-h)=z

Distribute 6 through the parentheses

6x-6h=z

Swap the sides of the equation

Z= 6x-6h