Answer:
(a). The change in electric potential energy is 8.3 μJ.
(b). The second particle moves away from the source charge.
Explanation:
Given that,
Charge of first particle = -8.8 nC
Charge of second particle = -4.3 nC
Distance = 0.11 m
They are released and the second particle moves 0.030 m,
(a). We need to calculate the change in electric potential energy
Using formula of potential energy
\(U=\dfrac{Kq_{1}q_{2}}{d}\)
Change in potential energy
\(\Delta U=\dfrac{kq_{1}q_{2}}{d_{2}}-\dfrac{Kq_{1}q_{2}}{d_{1}}\)
Put the value into the formula
\(U=\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.030}-\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.11}\)
\(\Delta U=0.000008256\ J\)
\(\Delta U=8.3\ \mu J\)
(B). We need to find the second particle move toward or away from the source charge
We know that,
Both charges are same, so the second particle will be repul from the source charge.
So, The second particle moves away from the source charge.
Hence, (a). The change in electric potential energy is 8.3 μJ.
(b). The second particle moves away from the source charge.
A stone is thrown vertically upward with a velocity of 96 feet per second from the top of a tower 265 feet high. When will it strike the ground?
The stone will strike the ground after approximately 8 seconds.
To solve this problem, we can use the equation of motion for a freely falling object:
h = v₀t - 1/2gt²
Where h is the height of the object at time t, v₀ is the initial velocity, g is the acceleration due to gravity (32.2 feet per second squared), and t is the time elapsed.
At the highest point of its trajectory, the stone's velocity will be zero. Therefore, we can use the given initial velocity to find the time it takes for the stone to reach its maximum height:
v₀ = 96 feet per second
h = 265 feet
t₁ = v₀/g = 96/32.2 = 2.98 seconds
After this, the stone will fall back to the ground. We can use the same equation of motion to find the time it takes to reach the ground:
h = 0 (ground level)
v₀ = -96 feet per second (negative because it is in the opposite direction of the initial velocity)
t₂ = sqrt(2h/g) = sqrt(2(265)/32.2) = 4.01 seconds
The total time it takes for the stone to strike the ground is the sum of the time it takes to reach the maximum height and the time it takes to fall back to the ground:
t = t₁ + t₂ = 2.98 + 4.01 = 6.99 seconds
Rounding to the nearest whole number, we get that the stone will strike the ground after approximately 8 seconds.
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a 15 N force pushes on an object for 10 seconds. how much momentum did it gain?
Net momentum gained by object due to application of 15N is 150N sec.
Given - Force=15N
time =10 sec
To find - momentum or change in momentum due to application of force.
Concept - We can utilize the concept of Impulse as due to application of force impulse is created that substantiates the role of momentum. Therefore impulse equalizes momentum generated ,
Impulse = Momentum Gained
Mathematically, Impulse =momentum = Force x Time
= 15 x 10
Ans = 150 N sec
Therefore, the momentum will be 150 N
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so i got this paper and it tellin me to put checks under if its metal or non metal and i need to know the properties of metal and non metal :>
Answer:
Explanation:
Metals refers to the natural elements that are hard, shiny, opaque and dense.
Non-metals implies those chemical substances that are soft, non-shiny, transparent and brittle
KEEP IN MIND: Most metals are hard, except sodium. Most non-metals are soft, except diamond.
This table will help you understand it better.
The distance a toy car travels over time is shown in the graph.
Which table best shows the average speed of the toy car at different time intervals?
Answer:
A
Explanation:
0-2 1.0
2-4 0.5
4-6 0
The table of velocity of toy car is drawn below.
What is velocity ?
velocity is defined as rate of change of displacement of the object with respect to rate of change in time. In mathematics It is written as :
\(\begin{aligned}v= \frac{\Delta d}{\Delta t}=\frac{d_{2}-d{1}}{t_{2}-t_1}\end{aligned}\)
considering time interval from t=0 sec to t=2 sec the distance travelled by the toy car is d=0m to d=2m. therefore, the velocity will be :
\(\begin{aligned}v&=\frac{d_{2}-d{1}}{t_{2}-t_1}\\&=\frac{2-0}{2-0}\\&=1 \text{\:m/s}\end{aligned}\)
similarly for interval t = (2sec - 4sec ) and t = (4sec - 6sec) is also calculate and written in table below.
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WILL MARK BRAINLIEST!!
A truck of a mass of 2 tons is traveling north at a speed v=70 km/h collides with a car of mass of 1.2 tons moving south at an equal speed. After collision, both vehicles remain tangled together.
With what speed and in what direction does the wreckage move?
(Would love it if it's solved in the GUESS method, but if not it's okay!)
The final speed of the wreckage after the collision is 17.5 km/h north.
What is the final speed of the wreckage after the collision?
The final speed of the wreckage after the collision is calculated by applying the principle of conservation of linear momentum.
m₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is the mass of the truckm₂ is the mass of the caru₁ is the initial speed of the trucku₂ is the initial speed of the carv is their final speed after the collisionlet north be positive and let south be negative direction
The final speed is calculated as follows;
(2 x 70) - (1.2 x 70) = v ( 2 + 1.2 )
56 = 3.2v
v = 56/3.2
v = 17.5 km/h north
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A crossbow (5.0kg) is sitting loaded with a bolt (m = 0.10kg) on a friction free table. The crossbow is triggered and the bolt (also called an arrow) is launched to the right with a speed of 25 m/s. The velocity of the crossbow as it recoils is _m/s
Answer:
The velocity of the crossbow as it recoils is 5 m/s. This can be calculated using the conservation of momentum. The momentum of the system before the bow was triggered is 0 (since the bow is stationary). After launching the bolt, the momentum of the system is (0.10 kg * 25 m/s), so in order for the momentum of the system to remain constant, the crossbow must recoil with a momentum of (5.0 kg * -5 m/s).
if the volume of cylinder is 1000 cm with 14cm height. Then find the radius of cylinder
Answer:
radius=4.77cm
Explanation:
given
r=? ,h=14 , v=1000
then using the formula
\(r = \sqrt{ \frac{v}{\pi \: h} } \)
= √1000/π•14
=4.77cm
What is the proper unit for gravitational potential energy?Question 16 options:gravitonsjoulesnewtonsmeters
Answer:
Joules
Explanation:
The unit for Energy is Joules, which is equal to kg m²/s².
The gravitational potential energy is calculated as:
\(Ep=\text{mgh}\)Where m is mass (kg), g is gravity (m/s²) and h is the height (m). So, the unit of the potential energy is:
\(kg\cdot\frac{m}{s^2}\cdot m=kg\cdot\frac{m^2}{s^2}=\text{Joules}\)Therefore, the answer is joules.
17. predict the ground state term symbol of si (z=14).
The ground state term symbol of Si (Z=14) is 3P.
To predict the ground state term symbol of Si (Z=14), follow these steps:
1. Identify the electron configuration of Si. Si has 14 electrons, and its electron configuration is 1s² 2s² 2p⁶ 3s² 3p².
2. Focus on the outermost occupied shell, which is the 3p² subshell.
3. Determine the total spin quantum number (S) by adding the spins of the electrons in the 3p² subshell. Since there are two unpaired electrons with a spin of ½ each, the total S is 1 (½ + ½).
4. Calculate the total orbital angular momentum (L) using the orbital quantum number (l) for the 3p² subshell. For the p orbital, l = 1. Since there are two unpaired electrons, the total L is 2 (1 + 1).
5. Determine the term symbol using the values for S and L. The term symbol is given by 2S+1 L, where L is represented by a letter (S, P, D, F, etc.). In this case, the term symbol is 3P.
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the force required to lift a load of 800 Newton by using a Lever having a mechanical advantage of 1.6 is
Answer:force required to lift the load = 500N
Explanation:
Mechanical advantage for a lever is given by the formulae
= force output/force input
or
Mechanical Advantage = Load / Effort
where
Force output / Load= 800 N
mechanical advantage = 1.6
Force input / Effort =??
Force input= Force output /Mechanical advantage
= 800N / 1.6
=500N
OR
Effort = Load/ Mechanical Advantage = 800/ 1.6 = 500N
what happens to kinetic energy as velocity increases
Answer:
\(\huge\purple{\boxed{{\colorbox{black}{Answer \:}}}}\)
What happens to kinetic energy as velocity increases?
Because kinetic energy is proportional to the velocity squared, increases in velocity will have an exponentially greater effect on translational kinetic energy. Doubling the mass of an object will only double its kinetic energy, but doubling the velocity of the object will quadruple its velocity.Explanation:
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When the velocity of an object increases, the kinetic energy of the object increases as well.
What is kinetic energy?The kinetic energy of an object is the energy possessed by the object due to its motion.
The kinetic energy of an object in motion is calculated as follows;
K.E = ¹/₂mv²
where;
v is the velocity of the object.Thus, from the equation above, when the velocity of an object increases, the kinetic energy of the object increases as well.
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During a live action show, an acrobatic performer will fall from heights onto a large foam mat. While these falls would normally injure a person, the performer is unharmed. From the perspective of momentum, what is the best explanation for this?.
The following relationship between impulse and momentum enables for the proper outcome to be determined: The average force Impulse falls as impact time increases.
The impulse, which is connected to the fluctuation in the quantity of movement, is calculated by multiplying the applied force by the time interval. I=F dt =p =m v f - m v0
When I is the impulse, F is the applied force, t is the time, p is the momentum, m is the mass, and v is the body's velocity, all of which are vectors. When the body stops, its speed is zero, and the height of the body affects how quickly it strikes the foam bed. A certain amount of force must be applied in order for someone to be hurt.
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_______ is a space where you can drive without restrictions to your line of sight or intended path of travel
(An open zone) is a space where we can drive without restrictions to our line of sight or intended path of travel.
What is an open zone?There are at least three types of zone we may encounter on the road, which are:
Open zone. The open zone provides a wide, larger open space to drive and we can drive without restriction. We are free to change lanes or move forward without conflict.Closed zone. This path is not available to drive due to some restriction or simply because the space is unavailable in a particular zone.Changing zone. This zone changes from an open to a closed zone. So we have to maintain specific speed limits, visibility, environmental conditions, etc while passing through.Learn more about space management here https://brainly.com/question/28701656
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Four, long, parallel power lines each carry 100-A currents. A cross- sectional diagram of these lines is a square, 20.0 cm on each side. You may want to review (Pages 926-929) For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Magnetic field of two wires. Part A For the case (a) Q Tap image to zoom calculate the magnetic field at the center of the square.
The magnetic field at the center of the square for this case is 0 T (tesla).
To calculate the magnetic field at the center of the square, we will use Ampère's Law, particularly the Biot-Savart Law. Each wire carries a 100-A current, and the distance between each wire and the center of the square is 10 cm (half the side length).
First, let's find the magnetic field due to one wire at the center of the square. The formula for the magnetic field at a perpendicular distance (R) from a long straight wire carrying current (I) is given by:
B = (μ₀ * I) / (2 * π * R)
Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), I is the current (100 A), and R is the distance (0.1 m).
Now, since there are 4 wires, we need to find the total magnetic field at the center of the square. Each wire contributes a magnetic field, but they are not in the same direction. Therefore, we need to find the vector sum of these magnetic fields.
The magnetic fields due to opposite wires have the same magnitude but are in opposite directions. Therefore, the total magnetic field at the center of the square is zero (since the magnetic fields cancel each other out).
So, the magnetic field at the center of the square for this case is 0 T (tesla).
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Which of the following is an example of an electromagnetic wave? (2 points)
Red light
Ocean waves
Sound waves
Earthquakes
Answer:
a
Explanation:
A large crate is pushed across the floor with an effort of 45 Newtons. The box is pushed a distance of 3.5 meters. How much work is done?
Answer:
\(\boxed {\boxed {\sf 157.5 \ Joules }}\)
Explanation:
Work is equal to the product of force and distance.
\(W=F*d\)
The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.
\(F= 45 \ N \\d= 3.5 \ m\)
Substitute the values into the formula.
\(W= 45 \ N * 3.5 \ m\)
Multiply.
\(W= 157.5 \ N*m\)
1 Newton meter is equal to 1 Joule Our answer of 157.5 N*m equals 157.5 J\(W= 157.5 \ J\)
157.5 Joules of work are done on the crate.
Two wires are identical, except that one is aluminum and one is copper. The aluminum wire has a resistance of 0.263Ω. What is the resistance of the copper wire? Take the resistivity of copper to be 1.72 x 10-8 Ω·m, and that of aluminum to be 2.82 x 10-8 Ω·m.
The resistance of the copper wire is 160 Ω
How to solve thisgiven data
the resistivity of Cu is 1.72 x 10^-8the resistivity of Al is 2.82 x 10^-8R=ρ l/S
R is the resistance, ρ resistivity, l length, S cross-sectional area of the wire.R(Al)=0.353 Ω , ρ(Al)=2.82*10^(-8) Ωm
ρ(Cu)=1.72*10^(-8) Ωm
R(Al) * ρ(Al) * l(Al) / S(Al) = R(Cu) * ρ(Cu) * l(Cu) / S(Cu)
Since l(Al) / S(Al) = l(Cu) / S(Cu) ,
we get
R(Al) * ρ(Al) = R(Cu) * ρ(Cu)
R(Cu) = 0.263Ω. * 1.72 / 2.82 =.160 Ω
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A 0. 20-kg baseball is struck with a force of 100 n from a 0. 94-kg baseball bat. What will be the acceleration of the ball and the bat, in that order, while the bat and ball are in contact?.
The acceleration of the baseball is 500 m/s².
A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull.
The mass of the baseball, m = 0.2 kg
The force acting on the baseball is 100 N.
By Newton's second law of motion,
F = ma
Substituting the values in the above equation,
100 N = 0.2 kg × a
a = 100 / 0.2
a = 500 m/s²
The total mass when the baseball and baseball bat are in contact is:
m = 0.2 + 0.94 = 1.14 kg
Then the acceleration will be:
F = ma
100 = 1.14 × a
a = 87.7 m/s²
The acceleration of the ball after the contact is 500 m/s².
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A
heat engine is measured to have 30% efficiency. Is the theoretical
efficiency going to be greater or less than that? Why?
The theoretical efficiency is greater than that of the actual efficiency of the engine. This is because heat engine always produces some waste heat.
The Second Law of Thermodynamics states that a heat engine cannot be 100% efficient. In practice, a heat engine is only 100% efficient when it is operating at about 30-50% efficiency.
If we were to multiply this by 100, we would get the efficiency as a percent: 49%. This is the theoretical maximum efficiency. If we were to actually build an engine, it would be less efficient than the theoretical engine. The theoretical engine that can achieve this theoretical maximum efficiency is called the Carnot Engine.
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please help i give brainest but i need help asap
Answer:
Surface
Explanation:
Rayleigh Waves—surface waves that move in an elliptical motion, producing both a vertical and horizontal component of motion in the direction of wave propagation. Particle motion consists of elliptical motions (generally retrograde elliptical) in the vertical plane and parallel to the direction of propagation.
The moon's diameter is 3.48 106 m, and its mean distance from the earth is 3.85 108 m. The moon is being photographed by a camera whose lens has a focal length of 53.0 mm.
(a) Find the diameter of the moon's image on the slide film.
(b) When the slide is projected onto a screen that is 16.1 m from the lens of the projector (f = 103.4 mm), what is the diameter of the moon's image on the screen?
(a). The object distance (do) is essentially at infinity, the image formed on the slide film is at the focal point of the lens, which means the diameter of the moon's image on the slide film will be equal to the diameter of the lens. Thus, the diameter of the moon's image on the slide film is 53.0 mm.
(b). The diameter of the moon's image on the screen is approximately 44.92 mm.
To solve this problem, we can use the thin lens formula:
1/f = 1/di + 1/do,
where f is the focal length of the lens, di is the image distance, and do is the object distance.
(a) Finding the diameter of the moon's image on the slide film:
Given:
Focal length of the lens (f) = 53.0 mm = 0.053 m
Object distance (do) = Mean distance from the Earth to the Moon = 3.85 × \(10^8\) m
Since the camera forms a real image on the slide film, the image distance (di) is equal to the focal length of the lens (f). Therefore, di = f.
Using the thin lens formula, we can solve for the object distance (do):
1/f = 1/di + 1/do
1/0.053 = 1/0.053 + 1/do
1/do = 1/0.053 - 1/0.053
1/do = 0
do = infinity
(b) Finding the diameter of the moon's image on the screen:
Given:
Focal length of the projector lens (f) = 103.4 mm = 0.1034 m
Image distance (di) = Distance from the lens to the screen = 16.1 m
Using the thin lens formula, we can solve for the object distance (do):
1/f = 1/di + 1/do
1/0.1034 = 1/16.1 + 1/do
1/do = 1/0.1034 - 1/16.1
1/do = 0.0096704 - 0.0621118
1/do = -0.0524414
do = -1/0.0524414 ≈ -19.07 m
Since the object distance (do) is negative, it means the object (moon's image) is located on the same side as the lens. In this case, the diameter of the moon's image on the screen will be given by the formula:
diameter = (di/do) × diameter of the moon's image on the slide film
Plugging in the values:
diameter = (16.1 m) / (-19.07 m) × 53.0 mm
diameter = -0.845 × 53.0 mm
diameter ≈ -44.92 mm
The negative sign indicates an inverted image. However, the magnitude of the diameter is what matters, so the diameter of the moon's image on the screen is approximately 44.92 mm.
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a point charge of 9.00 109 c is located at the origin. how much work is required to bring a positive charge of 3.00 109 c from infi nity to the location x 30.0 cm?
The amount of work required to bring a positive charge of 3.00 109 c from infinity to the location x 30.0 cm can be calculated using the formula W = qV, where W is the work, q is the charge, and V is the potential difference.
The potential difference for this situation is equal to the electric potential at 30.0 cm, which is equal to the electric potential from the 9.00 109 c point charge at the origin.
The work needed is equal to the charge multiplied by the potential difference, so W = qV = (3.00 109 c)(9.00 109 c/30.0 cm) = 9.00 108 c2/cm. This is the amount of work required to bring a positive charge of 3.00 109 c from infinity to the location x 30.0 cm.
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How are the weight and the mass of an object related?
Answer:
The weight and the mass of an object are related because the weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. w=mg
A mixture that forms when one substance dissolves another is called
Answer:
a solution
Explanation: A solution is a homogeneous mixture consisting of a solute dissolved into a solvent .
18. A submerged stone weighs 254 newtons, but out of the water it weighs 1235 newtons. The density of the water is1000 kilograms per cubic meter. The volume of the stone is most nearly(a) 0.100 m^3(b) 0.206 m^3(c) 0.254 m^3(d) 1.24 m^3
ANSWER:
(a) 0.100 m^3
STEP-BY-STEP EXPLANATION:
We have that the force is equal to mass times gravity, therefore, we can calculate the mass, because the difference in force would be the volume of the stone.
Therefore
\(\begin{gathered} F=m\cdot a \\ m=\frac{F}{a} \\ m=\frac{1235-254}{9.8}=100.1\text{ kg} \end{gathered}\)Now, we know that the density is equal to the quotient between the mass and the volume, therefore we can calculate the volume like this:
\(\begin{gathered} d=\frac{m}{v} \\ v=\frac{m}{d} \\ v=\frac{100.1}{1000} \\ v=0.1001\cong0.100m^3 \end{gathered}\)Therefore the volume of the piece is 0.100 cubic meters.
What is the mass of a student who weighs 618 Newton?
Answer:
63.01 kg is the mass of the student whose weight is 618 Newton
Mass of student is 63 kilogram (Approx.)
Given that;
Weight of a student = 618 Newton
Find:
Mass of student
Computation:
We know that;
Gravitational acceleration g = 9.8 m/s²
So,
Mass = Weight / Gravitational acceleration
Mass of student = 618 / 9.8
Mass of student = 63.06
Mass of student = 63 kg (Approx.)
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he total translational kinetic energy of 1.0 mole of diatomic oxygen at 50°C is: The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50°C is 2000 m/s. Note that 1.0 mol of diatomic hydrogen at 50°C has a total translational kinetic energy of 4000 J.
The rms speed of diatomic hydrogen and the total translational kinetic energy of diatomic oxygen. The total translational kinetic energy of 1.0 mole of diatomic oxygen at 50°C can be calculated using the formula:
Total Translational Kinetic Energy = (3/2) * R * T
Where R is the ideal gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin. To convert 50°C to Kelvin, we add 273.15:
T = 50°C + 273.15 = 323.15 K
Now we can substitute the values into the formula:
Total Translational Kinetic Energy = (3/2) * 8.314 J/(mol·K) * 323.15 K
Calculating this expression will give us the total translational kinetic energy of 1.0 mole of diatomic oxygen at 50°C.
Regarding the information about the rms speed of a diatomic hydrogen molecule at 50°C, it states that it is 2000 m/s and that 1.0 mol of diatomic hydrogen at 50°C has a total translational kinetic energy of 4000 J.
It's important to note that the rms speed is related to the average kinetic energy of a gas molecule, but not directly to the total translational kinetic energy of a mole of gas. The total translational kinetic energy takes into account the number of molecules and their individual kinetic energies.
Therefore, we cannot directly compare the given information about the rms speed of diatomic hydrogen and the total translational kinetic energy of diatomic oxygen. They are different properties and cannot be equated or compared in this context.
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Stars give off a tremendous amount of thermal and ________ energy.(1 point) chemical chemical electrical electrical nuclear nuclear radiant radiant
Stars give off a tremendous amount of thermal and nuclear energy. The correct option is C.
Massive amounts of thermal and radioactive energy are released by stars. Thermal radiation that spans the electromagnetic spectrum is produced by the extreme heat produced by nuclear fusion processes at their centers.
The heat, visible light, and other types of electromagnetic radiation that we perceive from stars are all produced by this thermal energy.
Unlike electrical or chemical processes, which are significant on planets like Earth, nuclear fusion is the primary source of energy for stars.
In this process, hydrogen is changed into helium, which releases a tremendous quantity of energy in the form of light and heat.
The luminosity and dynamic processes that characterize the life cycle of stars are maintained through the interaction of thermal and nuclear energy.
Thus, the correct option is C.
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Your question seems incomplete, the probable complete question is:
Stars give off a tremendous amount of thermal and ________ energy.(1 point)
A. chemical
B. electrical.
C. nuclear
D. radiant radiant
how does a thermo flask retain heat
Answer:
A thermo flask has a cork which prevents heat loss by conduction.
It also has vacuum which prevents heat loss by convection.
The speed of light is about 300,000 km/s. It takes approximately 1.3 seconds for light reflected from the moon
to reach Earth. What is the average distance from Earth to the moon?
u have to divide it and u will get the answer