Answers
Considering the Boyle's law, if the pressure is increased to 1.80 atm, the gas will ocuppy a volume of 11.04 L.
Boyle's lawBoyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.
Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Mathematically, Boyle's law states that if the amount of gas and the temperature remain constant, the product of the pressure and the volume always has the same value:
P× V= k
where:
P is the volume.V is the volume.k is the constant.Considering the initial state 1 and the final state 2, it is fulfilled:
P₁× V₁= P₂× V₂
New volumeIn this case, you know:
P₁= 737 torrV₁= 20.5 LP₂= 1.80 atm= 1368 torr (being 1 atm= 760 torr)V₂= ?Replacing in Boyle's law:
737 torr× 20.5 L= 1368 torr× V₂
Solving:
(737 torr× 20.5 L)÷ 1368 torr= V₂
11.04 L= V₂
Finally, the new volume is 11.04 L.
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Related Questions
A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine
Answers
A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine
Explanation:
A load of 20N is lifted through a height of 8m by a machine.If the effort of 80N moves a distance of 6m.Calculate the efficiency percentage of the machine
Answer:

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Join / LoginQuestionIn a lifting machine an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10000 N by a distance of 0.8 m Determine the velocity ratio and mechanical advantage
Determine the velocity ratio and mechanical advantageA
Determine the velocity ratio and mechanical advantageA10 and 35
Determine the velocity ratio and mechanical advantageA10 and 35B
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20Easy
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in App
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolution
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by Toppr
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option is
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8m
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEd
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25
Determine the velocity ratio and mechanical advantageA10 and 35B20 and 35C10 and 25D25 and 20EasyOpen in AppSolutionVerified by TopprCorrect option isD25 and 20Distance moved by effort is 20m,that of load is 0.8mVR=LdEdVR=0.820VR=25the load is 10,000N and effort=500N
MA=effortdloadd
MA=effortdloaddMA=50010000
MA=effortdloaddMA=50010000MA=20
What is the momentum of a 6g bullet moving with a velocity of 1.5 × 10^3 m/s to the east?
Answers
Answer:
Momentum = Mass x Velocity
= 0.006 kg x 1.5 × 10^3 m/s
= 9 kg·m/s (to the east)
c = speed of light = 3.00 × 108 m/s
A gamma ray has a very high frequency of about 1019 s−1. What is the wavelength of the gamma ray?
A.
3.00 × 10−11 m
B.
3.00 × 1027 m
C.
3.33 × 1010 m
D.
3.33 × 10−12 m
URGENT!!!!!!!!!!
Answers
Answer:
The correct answer is option A: 3.00 × 10^(-11) m.
Explanation:
To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:
wavelength = speed of light / frequency
Given:
Speed of light (c) = 3.00 × 10^8 m/s
Frequency (f) = 10^19 s^(-1)
Substituting the values into the equation:
wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))
To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:
wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s
To divide by a fraction, we multiply by its reciprocal:
wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)
Applying the properties of exponents, we can add the exponents when multiplying with the same base:
wavelength = 3.00 × 10^(-11) m
Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.
a. When throwing a ball vertically upward, my hand moves through a distance of about 1.0 m before the ball leaves my hand. The 0.80 kg ball reaches a maximum height of about 20 m above my hand. while the ball is in my hand after the ball leaves my hand
Answers
The required, it experiences a downward force due to gravity and a force due to air resistance.
What is the projectile motion?Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.
Here,
When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.
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When an object is in free fall, ____________________.
Answers
Answer:
Objects that are said to be undergoing free fall, are not encountering a significant force of air resistance; they are falling under the sole influence of gravity.
Explanation:
Under such conditions, all objects will fall with the same rate of acceleration, regardless of their mass.
Which structures are in the cytoplasm? Check all that apply
Cell membrane
Chloroplast
Endoplasmic reticulum
Lysosomes
Cell wall
Nucleus
Vacuoles
Answers
Answer:
nucleus and endoplasmic reticulum. I'm pretty sure the mitochondria is in the cytoplasm too
Answer:
2.chloroplasts
3.endoplasmic reticulum
4.lysosomes
6.nucleus
7.vacuoles
Explanation:
These were the correct answers in my Cell Structure Assignment.
Which is a force that wears away landforms? Select three options.
A. weathering
B. erosion
C. humans
D. clouds
E. light
Answers
In high air pressure the molecules are
A-Warm and moving fast
b-Close together and moving slowly
c-far apart and moving slowly
d-hot and moving rapidly
Answers
How is water vapor formed
Answers
Answer:
Y'now water vapor isn't half bad. It's like a vape but it can't affect your lungs. Anyway, Water vapor is water in gaseous instead of liquid form. It can be formed either through a process of evaporation or sublimation.
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Jibari walks 40.0 meters east in 120.0 seconds. He then walks 30.0 meters west in 60.0 seconds. What is his average velocity for the trip??
Answers
We divide the total distance travelled by the period of time to determine the average speed. By dividing the displacement by the time interval, we can determine the average velocity.
How do you calculate a trip's average speed?Average speed was measured by dividing the overall distances you travelled by the total time, whereas average velocity is determined by dividing your movement (a vectors pointing from the initial position toward your end position) by the whole time.
What is an illustration of average speed?For instance, someone travelling at an average speed over 40 miles split by 10 mins, meaning 1 mile per minute, is travelling twenty miles to the north and afterwards 20 miles south (60 mph).
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A helicopter goes straight up 500m from a landing pad. It then goes north 20m. Then it goes down 452m. a) What is the displacement of the helicopter?
Express as components of a vector.
x-component_____________________
y-component_____________________
b) What is the displacement of the helicopter? Express as a vector (magnitude and direction).
Answer_____________________
Answers
Answer:
a
x-component \(20 \ m\)
y-component \(500 - 452 = 48 \ m\)
b
Magnitude \(d = 52 \ m\)
direction is \(\theta = 67.4^o\)
Explanation:
From the question we are told that
The first vertical distance is \(y_1 = 500 \ m\)
The first horizontal distance is \(x = 20 \ m\)
The second vertical distance is \(y_2 = 452 \ m\)
Generally the displacement is
x-component \(20 \ m\)
y-component \(500 - 452 = 48 \ m\)
Generally the helicopters displacement is mathematically evaluated as
\(d = \sqrt{ x- component ^2 + y- component ^2 }\)
\(d = \sqrt{ 20t ^2 + 48 ^2 }\)
\(d = 52 \ m\)
The direction is the angle the displacement of the helicopter makes with the horizontal which is mathematically evaluated as
\(\theta = tan ^{-1}[ \frac{48}{20}]\)
=> \(\theta = tan ^{-1}[ 2.4 ]\)
=> \(\theta = 67.4^o\)
what are the strengths and weaknesses of the four methods of waste management?
Answers
Answer & Explanation: Waste management are all activities and actions required to manage waste from its inception to its final disposal. There are several methods of managing waste with its strengths and weaknesses. The strengths include;
* It creates employment
* It keeps the environment clean
* The practice is highly lucrative
* It saves the earth and conserves energy
The weaknesses of the methods of waste management includes;
* The sites are often dangerous
* The process is mostly
* There is a need for global buy-in
* The resultant product had a short life
Which direction do longitudinal waves travel?
Answers
Answer:
If the particles of the medium vibrate in a direction parallel to the direction of propagation of the wave, it is called a longitudinal wave. In longitudinal waves, the particle movement is parallel to the direction of wave propagation.
Explanation:
Five gas molegules are choosen at random are found to have speed of 500,600,700, 800 and 900 m/s. Find the rms speed. Is it ghe same as average speed
Answers
Answer:
Explanation:
The rms speed:
Vrms = (500 + 600 + 700 + 800 + 900) / 5 = 700 m/s
What is the cost per month to operate an A.C. 10hours per day whose power is 3kW and 1KWH cost 79francs
Answers
The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.
What is Power?Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.
Cost of operation for 10 hours a day;
Daily consumption = 3kW x 10 hours
Daily Consumption = 30kW
Since 1kWH = 79 francs;
Daily consumption amount = 30 x 79 francs
Daily consumption amount = 2,370 francs
Therefore, the monthly consumption (using 30days) will be;
2,370 francs x 30 = 71,100 francs
In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.
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The purpose of the chiller is to
A. remove heat from the air.
B. cool conditioned air.
C. distribute the refrigerant.
D. cool warmed water.
Answers
The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.
What is a Chiller?This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.
The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.
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"The greater the height of an object, the *BLANK* its gravitational potential energy."
please help thank u!
Answers
Answer:
the greater the height of an object the *greater* its gravitational potential energy
greater
When solving problems involving forces and Newton's laws, the following summary of things to do will start your mind thinking about getting involved in the problem at hand.
When solving problems involving forces and Newton'
Apply these steps
Use the steps outlined above to find the magnitude of the acceleration a of a chair and the magnitude of the normal force FN acting on the chair: Yusef pushes a chair of mass m = 50.0 kg across a carpeted floor with a force Fp (the subscript 'p' here is lowercase and throughout the question) of magnitude Fp = 168 N directed at ? = 35.0 degrees below the horizontal. The magnitude of the kinetic frictional force between the carpet and the chair is Fk= 99.7 N .
Part A
Identify and sketch all the external forces acting on the chair. Because the chair can be represented as a point particle of mass m, draw the forces with their tails centered on the black dot in the middle of the chair. Be certain to draw your forces so that they have the correct orientation.
Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.
Answers
Answer:
Explanation:
There is no acceleration in vertical direction
Fn = mg + Fp sin 35
Frictional force = 99.7 N
Net force in forward direction = Fp cos 35 - 99.7
= 168 cos 35 - 99.7
= 137.61-99.7
= 37.91 N
net acceleration of chair = net force / mass
= 37.91 / 50
= .7582 m / s² .
How are gases and liquids different from each other? A. Gases can change volume, and liquids cannot. O B. Liquids can change volume, and gases cannot. C. Gases can change shape, and liquids cannot. D. Liquids can change shape, and gases cannot.
Answers
Answer:
A.gasses can change volume, and liquids cannot
Explanation:
if you pour a glass of water you don't have to worry about it expanding such that it overflows. however if you air up a ballon you may notice that it becomes lager the warmer it gets and smaller the cooler it gets
anybody from India ?
Answers
Answer:
No,why you say that
Explanation:
Transfer of thermal energy between air molecules in closed room is an example of
conduction
convection
radiation
Answer and I will give you brainiliest
Answers
Answer: Conduction
Explanation: Conduction is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules. Conduction occurs more readily in solids and liquids, where the particles are closer to together, than in gases, where particles are further apart.
A candle is placed in front of a concave mirror as it is shown . State the image characteristics (SALT)
Answers
As a result, the picture behind the mirror is virtual, upright, and enlarged.
What does SALT in concave mirrors stand for?You will find that the properties of an image (SALT) created in a concave mirror depend on the object's position. A) if the item is larger than C. Size, attitude, and location are all important considerations.
The image will be true, but reversed and much reduced. To obtain a crisp flame image, move the burning candle towards the mirror while moving the screen away from it. The size of the inverted picture grows.
Concave mirrors may create both physical and virtual images. A virtual and enlarged picture is produced when the item gets closer to the mirror. When the item is placed further away from the mirror,.
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1c. Using a metric (SI) measuring tape or ruler:
Measure the length L, width Wand height H of the shoebox shaped object and record
them in centimeters plus millimeters. Transform them to decimal format.
height H
Dimensions of shoebox shaped object measured with ruler
Format
length L
width W
In centimeters and
millimeters
28 cm and 6 mm 19 cm and 1 mm
In decimal
centimeters format
(show your work)
9 cm and 5 mm
Lo
Answers
Answer:
Format ______Length ______width ___ height
cm and mm _26cm 6mm _19cm 1mm_9cm 5mm
Decimal ____ 26.6cm _____ 19.1 cm __ 9.5cm
Explanation:
Dimension of shoebox shaped object :
Format ______Length ______width ___ height
cm and mm _26cm 6mm _19cm 1mm_9cm 5mm
Decimal ____ 26.6cm _____ 19.1 cm __ 9.5cm
Recall:
1mm = 0.1cm
For the length :
26cm + 6mm = 26cm+(6*0.1) = 26 + 0.6 = 26.6cm
Width:
19cm + 1mm = 19cm+(1*0.1) = 19 + 0.1 = 19.1cm
Height:
9cm + 5mm = 9cm+(5*0.1) = 9 + 0.5 = 9.5cm
What is a simple circuit?
Answers
Answer:
This is your answer. If I'm right so,
Please mark me as brainliest. thanks!!
Answer:
A simple circuit definition is a closed loop of a conductor that electrons can travel around, usually consisting of a power source (a battery, for example) and an electrical component or device (like a resistor or a light bulb) and conducting wire.
Suppose that a particular artillery piece has a range R = 9880 yards . Find its range in miles. Use the facts that 1mile=5280ft and 3ft=1yard.
Answers
Answer:
R = 9880 yd * 3 ft/yd / 5280 ft/mi = 5.61 mi
If you do it in steps
R = 9880 yd * 3 ft/yd = 29640 ft
R = 29640 ft / 5280 ft/mi = 5.61 mi
Một khối khí hidro bị nén đến thể tích bằng 1/2 lúc đầu khi nhiệt độ không đổi. Nếu vận tốc trung bình của phân tử hidro lúc đầu là V thì vận tốc trung bình sau khi nén là bao nhiêu ?
Answers
answer: what language is this???
Jonny is pushing a 50-kg large package along the dorm room floor with 150 N force. Both the direction of push and the floor are horizontal. While he is pushing the package, it moves in a straight line with constant 0.6 m/s speed. Please ignore air-resistance and make sure to justify your answers to the questions below.
a) (10 points) Write down as much information as you can about the main horizontal forces exerted on the package (names, directions, and if enough information is given, numerical values).
b) (10 points) Write down as much information as you can about the main vertical forces exerted on the package (names, directions, and whenever possible, if enough information is given, numerical values).
c) (5 points) How far did the package move during 3 seconds of pushing? Explain
d) (5 points) What was the package’s acceleration during that time? Explain
2
Answers
a. The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.
b. The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.
c. The package moves 1.8 m
d. The package's acceleration is 0 m/s²
a. The horizontal forcesThe push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.a
Since the direction of push and the floor is horizontal, and first horizontal force acting on the package is the push and its magnitude is 150 N.
Also, a frictional force also acts to oppose the motion of the package.
Since the packge moves at a constant velocity of 0.6 m/s, its acceleration is zero and thus the net force on the package is zero.
Let
F = push force and f = frictional forceSo, F - f = 0
F = f
= 150 N
So, the frictional force is 150 N and opposite to the push.
So, the push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.
b Vertical forces on package
The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.
Since the floor is horizontal, the vertical forces that act on the package are its weight and the normal force due to the ground.
The direction of the weight is downwards while the direction of the normal force is upwards.
Since the floor is horizontal and the package does not move in the vertical direction, the net vertical force is zero.
Let W = weight of package = mg where m = mass of package = 50 kg and g = acceleration due to gravity = 9.8 m/s² and N = normal forceSo, the net force N - W = 0
N = W
= mg
= 50 kg × 9.8 m/s²
= 490 N
So, the weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.
c. Distance package moves
The package moves 1.8 m
Since distance, d = vt where
v = velocity = 0.6 m/s and t = time = 3 sSo, d = vt
= 0.6 m/s × 3 s
= 1.8 m
So, the package moves 1.8 m
d. The package's acceleration
The package's acceleration is 0 m/s²
Since the net force on the package is zero, its acceleration is also zero. Since force, F = ma where
m = mass of package and a = acceleration of packageSince F = 0,
ma = 0
a = 0
So, the package's acceleration is 0 m/s²
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Write the differences between rest and motion
Answers
Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
How does increasing the amount of charge on an object affect the electric force it exerts on another charged
object?
The electric force increases because the amount of charge has an indirect relationship to the force.
The electric force increases because the amount of charge has a direct relationship to the force.
The electric force decreases because the amount of charge has an indirect relationship to the force.
The electric force decreases because the amount of charge has a direct relationship to the force.
Answers
Answer:
the electric force increases because the amount of charge has a direct relationship to the force
Increasing the amount of charge on an object will increase the electric force it exerts on another charged object because the amount of charge has a direct relationship to the force. Therefore, option (B) is correct.
How to calculate the charge on an object?Mathematically, the amount of charge on an object due to the effect of the force that is exerted on it can be calculated by using the formula mentioned below:
F = E×q
Where F is the electric force, E is the energy, and q is the charge.
The electric force between charged particles at rest is known as electrostatic force. The magnitude of the electric force between point charges is directly proportional to the multiplication of the charges and inversely proportional to the distance between them.
Therefore, increasing the amount of charge on an object would increase the electric force because the amount of charge has a direct relationship with the force.
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