A flower basket is hung from the end of a uniform horizontal pole which projects from a wall, as
shown. The pole is supported by a cable attached to a higher point on the wall:
The pole has a mass of 10.0 kg; the flower basket has a mass of 14.0 kg.
a By taking moments about the right hand end of the pole, determine the value of the
tension in the cable T. [5]
b The wall exerts a force R on the pole. Deduce the horizontal component of R.
Answers
The rotational and translational equilibrium conditions allow finding the results for the questions about the forces in the system are;
a) The cable tension is; T = 415.8 N
b) The x component of the wall reaction is: R = 371.8 N
Given parameters
Vase mass m1 = 14.0 kg Beam mass m² = 10.0 kg Beam length x = 1.8 m Height y = 0.9 mTo find
a) The tension of the rope.
b) The x component of the wall reaction.
Newton's second law for linear and rotational movements relate forces and torques are the accelerations of bodies, in the cases where the accelerations are zero, they are called equilibrium conditions:
Transactional ∑ F = 0 Rotational ∑ τ = 0τ = F x r = F r sin θ
Where F is the force, τ the torque, r the position and θ the angle.
In a free-body diagram you have the forces without the details of the bodies. In the attachment we see a diagram of the forces and the reference system for this case.
Let's use trigonometry to break down stress.
Sin θ = \(\frac{T_y}{T}\)
cos θ = \(\frac{T_x}{T}\)
\(T_y\) = T sin θ
Tₓ = T cos θ
Using distance values.
tan θ = \(\frac{y}{x}\)
θ = tan⁺¹ \(\frac{y}{x}\)
θ = tan-1 \(\frac{0.9}{1.8}\)
θ = 26.6º
A) We use the rotational equilibrium condition, they indicate that the turning point is the point of union of the post with the wall, we will take the counterclockwise turns as positive.
W₁ 1.8 + W₂ \(\frac{1.8}{2}\) - \(T_y\) 1.8 = 0
\(T_y=(m_1+\frac{m_2}{2} )\ g\)
\(T_y\) = \((14+ \frac{10}{2} ) \ {9.8\)
\(T_y\) = 186.2 N
\(T_y\) = T sin 26.6
T = \(\frac{T_y}{sin \ 26.6}\)
T = \(\frac{186.2 }{sin \ 26.6}\)
T = 415.8 N
b) Let's apply the translational equilibrium condition for each axis.
x- axis
R - Tₓ = 0
R = T cos tea
R = 415.8 cos 26.6
R = 371.8 N
In conclusion using the rotational and translational equilibrium conditions we can find the results for the questions about the forces in the system are;
a) The cable tension is; T = 415.8 N
b) The x component of the wall reaction is: R = 371.8 N
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Related Questions
QUESTION 5 (Start on a new page.) A block of mass 4 kg starting from rest, at point A, slides down an inclined plane of length 3 m as shown in the diagram below. The plane is inclined by an angle of 30° to the ground. The coefficient of kinetic friction (p) is 0,2 on the inclined plane 5.2 4 kg 5.3 3 m. 30 At the bottom of the inclined plane, at point B, the object slides along a rough horizontal surface experiencing a kinetic frictional force of 19.6 N until it comes to rest at point C 5.1 B State the work-energy theorem in words. Draw a labelled free-body diagram for the block as it slides down the incline. Calculate the: 5.3.1 Kinetic frictional force the block experiences on the incline 5.3.2 Magnitude of the velocity of the block at point B 5.3.3 Distance that the object will slides on the rough horizontal surface until it stops (2) (3) (4) (5) (4) [18]
Answers
1 Therefore, the kinetic frictional force experienced by the block on the incline is 6.784 N.
2 The magnitude of the velocity of the block at point B is approximately 5.11 m/s.
How to calculate the value1. The formula for the kinetic frictional force is given by f = μN, where μ is the coefficient of kinetic friction and N is the normal force. Since the block is on an incline, the normal force can be calculated as N = mg * cos(θ), where θ is the angle of inclination.
N = 4 kg * 9.8 m/s² * cos(30°) = 33.92 N
f = 0.2 * 33.92 N
= 6.784 N
2. Potential energy at point A = mgh, where h is the vertical height of the incline.
Potential energy at point A = 4 kg * 9.8 m/s² * 3 m * sin(30°)
= 58.8 J
The work done by friction is given by W = f * d, where d is the distance traveled along the incline (3 m).
Work done by friction = 6.784 N * 3 m = 20.352 J
Since the work done by friction is negative (opposite to the direction of motion), the total work done on the block is:
Total work = Potential energy at A - Work done by friction
Total work = 58.8 J - 20.352 J = 38.448 J
According to the work-energy theorem, this work done on the block is equal to the change in its kinetic energy. Therefore, we have:
38.448 J = 0.5 * 4 kg * B²
Solving for B, we find:
B = √(38.448 J / (0.5 * 4 kg)) ≈ 5.11 m/s
Therefore, the magnitude of the velocity of the block at point B is approximately 5.11 m/s.
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An Atwood’s machine is set up by suspending two blocks connected by a string of negligible mass over a pulley, as shown above. The blocks are initially held at rest and then released. The acceleration of mass M1 is 4.9 m/s2 downward and M1 = 6 kg. Find the mass of M2.
Answers
The mass of M₂ = 12kg.
What is acceleration of mass?Newton's second law of motion states that an object's acceleration is equal to its mass divided by the net force acting on it, or a = F m. When an object's mass and the net force acting on it are known, this equation for acceleration can be used to determine the object's acceleration.
The formal formulation of Newton's second law is as follows: The acceleration of an object caused by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
F = ma
F = 6×4.9
F = 29.4N.
F = (M₂ - M₁)a
29.4 = (M₂- 6) 4.9
29.4/ 4.9 = M₂- 6
M₂ = 6+6
M₂ = 12kg.
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6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
Answers
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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which of the numbers below correctly describes 1,250 volts?a.0.00125 mvb.0.125 mvc.1.25 mvd.1,250 mv
Answers
1.25 MV is the numbers below correctly describes.
We know, 1000 volts = 1MV
Given, 1250 volts
We have to convert 1250 volts in MV.
1 volt = \(\frac{1}{1000}\) MV
1250 volts = 1.25 MV
Hence, the correct answer is 1.25 MV.
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Which is observed globally: "Earth Day" or "Arbor Day"?
Answers
Answer:
Earth Day is observed globally
Explanation:
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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Be able to list the three compounds that are formed as products of highly exothermic
reactions such as detonating nitrogen-based explosives?
Answers
Answer:
Ammonium perchlorate NH4ClO4
Ammonium Nitrate
Calcium Cyanamide
When detonated, the reaction products are all gases, such as water vapor, nitrogen gas, and oxides of nitrogen.
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An army tank division leaves base and travels 30 miles at [W30*S] and then turns and travels 70 miles at [W10*N]. What is their total displacement from base at the end of the trip?
Answers
The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.
How to calculate the displacement?To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.
We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.
To add vectors, we need to break them down into their horizontal and vertical components.
For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).
For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).
Now we can add these components to get the total displacement:
Horizontal component = -30 + 0 = -30
Vertical component = 0 + 70 = 70
So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.
We can use the Pythagorean theorem to find the magnitude of this vector:
|displacement| = √((-30)² + 70²) ≈ 75.9 miles
And we can use trigonometry to find the direction of this vector:
\(\theta = tan^{-1}\dfrac{70} { -30}\)
θ ≈ -67.4°
So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.
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Question 4 of 10
What is thermodynamics?
A. The movement of matter
B. The flow of fluids
C. The movement of particles
D. The flow of energy, heat, and work
SUBMIT
Answers
Answer:
Explanation:
D.
Thermodynamics is the study of how different types of energy is transferred through the chemical systems
Answer: Thermodynamics is the flow of energy, heat, and work.
Explanation: This is seen in the formula for the first law of thermodynamics, U = Q - W, or “The change of the internal energy of a system (U) is equal to the heat absorbed (Q) minus the work done by that system (W).”
If you keep a gas's temperature constant, how would you increase the volume of the gas?
a
You would change the temperature
b
You would increase the pressure
c
You would decrease the temperature
d
You would decrease the pressure
Answers
when the temperature is kept constant, to increase the volume of the gas, you will decrease the pressure (Option D)
How do I increase the volume at constant temperature?The volume of a gas at constant temperature is explained by the Boyle's law equation which is states as follow:
The volume of a fixed mass of gas is inversely proportional to the pressure at conctant temperature. Mathematically, it is expressed as follow:
P ∝ = 1/V
P = K / V
P₁V₁ = P₂V₂
Where
P₁ and P₂ are initial and new pressure V₁ and V₂ are initial and new volume
From the above formula, we can see that volume and pressure exist in inverse proportionality. This means that when the volume increases, the pressure will decrease and also, when the volume decreases, the presure will increase.
With the above information, we can conclude that the correct answer to the question is: You would decrease the pressure (Option D)
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A current is induced by moving a magnet in and out of a coil of wire. What will happen to the induced current if you move the
magnet twice as fast?
A. Nothing. The induced current will not change.
B. The induced current will decrease
C. The induced current will increase
D. The induced current will change directions
Answers
Answer:
1. The induced current will increase.
2. The ammeter will detect an increase in current, and the compass will detect a stronger magnetic field.
3. the ratio of incoming and outgoing voltages
4. Voltage and electric current are induced.
100%
The induced current will increase.
What are faraday's law? What is Maxwell - Faraday equation?Faraday's law states that the electromotive force around a closed path is equal to the negative of the time rate of change of the magnetic flux enclosed by the path.or
Faraday's law states that the emf is also given by the rate of change of the magnetic flux. Mathematically -\(${\displaystyle {\mathcal {E}}=-{\frac {\mathrm {d} \Phi _{B}}{\mathrm {d} t}}}\)
Maxwell–Faraday equation states that a time-varying magnetic field always accompanies a spatially varying (also possibly time-varying), non-conservative electric field, and vice versa. Mathematically -\($\nabla \times \mathbf {E} =-{\frac {\partial \mathbf {B} }{\partial t}}\)
or
\(${\displaystyle \oint _{\partial \Sigma }\mathbf {E} \cdot \mathrm {d} \mathbf {l} =-\int _{\Sigma }{\frac {\partial \mathbf {B} }{\partial t}}\cdot \mathrm {d} \mathbf {A} }\)
Given is that a current is induced by moving a magnet in and out of a coil of wire.
As the magnet moves twice as fast, then the rate of change of magnetic flux will increase and hence the induced current will increase.
Therefore, we can conclude that the induced current will increase.
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Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 5.00 m above the ground and measure that it hits the ground 0.804 s later. Part APart complete What is the acceleration of gravity near the surface of this planet
Answers
Answer:
g = 15.5 m/s²
Explanation:
In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:
h = Vi t + (0.5)gt²
where,
h = height covered by the wrench = 5 m
Vi = Initial Velocity = 0 m/s
t = Time Taken to hit the ground = 0.804 s
g = acceleration due to gravity near the surface of the planet = ?
Therefore,
5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²
g = (5 m)/(0.3232 s²)
g = 15.5 m/s²
5. You are driving at a constant speed of 35.0 m/s
when you pass a traffic officer on a motorcycle
hidden behind a billboard. One second after your
car passes the billboard, the traffic officer sets out
from the billboard to catch you, accelerating at a
constant rate of 3.0 m/s². How long does it take the
traffic officer to overtake your car?
Answers
The traffic cop needs 23.3 seconds to pass the automobile.
What is the acceleration of a car moving in a straight line at a constant speed?When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.
\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)
\(d = d1 = 35.0 m\)
\(d2 = v2*t + (1/2)at^2\)
\(d2 = (1/2)at^2\)
\(v2*t + (1/2)at^2 = (1/2)at^2\)
\(v2*t = (1/2)at^2\)
Solving for t, we get:
\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)
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Two loudsspeakers emit identical sound waves along the x axis. THe osund at a point on the axis has maximum intensity when the speakers are 40 cm apart. The sound intensity decreases as the distance between the speakers is increased, reaching zero at a separation of 50 cm. If the distance between the speakers continuse to increase, at what separation will the sound intensity again be a maximum?
Answers
Answer: 30 cm.
Solving
The situation described is that of two sources of sound waves that are separated by some distance. The two waves interfere with each other constructively at some points and destructively at others. When they interfere constructively, the amplitude (and intensity) of the sound wave is greater than when they interfere destructively.
When the speakers are 40 cm apart, the waves that they produce are in phase at some points on the axis, leading to constructive interference and a maximum in the intensity of the sound. As the distance between the speakers is increased beyond 40 cm, the points of constructive interference move farther apart, and the intensity of the sound decreases. When the speakers are 50 cm apart, the waves that they produce are exactly out of phase at some points on the axis, leading to complete destructive interference and a minimum in the intensity of the sound.
If the separation between the speakers continues to increase, the points of constructive interference will move closer together again, and the intensity of the sound will increase. The separation between the speakers at which the intensity of the sound will again be a maximum can be found using the following equation:
d = λ/2 + nλ
where d is the separation between the speakers, λ is the wavelength of the sound wave, and n is an integer that represents the number of half-wavelengths between the speakers.
At the maximum, the separation is an even multiple of half the wavelength, so we can use the formula above with n = 1. The wavelength can be found from the distance between the speakers at the minimum, which is 50 cm, and the distance at the maximum, which is 40 cm:
λ = 2(d_max - d_min) = 20 cm
Substituting λ and n into the formula gives:
d = λ/2 + nλ = 10 cm + 20 cm = 30 cm
Therefore, the sound intensity will be a maximum again when the separation between the speakers is 30 cm.
How much work is done by 15 kW engine during 3.5 min? Explain the answer if you can plz
Answers
Answer:
W = 3.15 · 10⁶ J
Explanation:
We know that power is calculated using the formula:
P = W/twhere P = power (W), W = work (J), and t = time (s)We can derive a formula for work using this formula by multiplying t to both sides of the equation.
W = PtLet's convert 15 kW to W.
15 kW → 15,000 WLet's convert 3.5 min to s.
3.5 min → 210 sSubstitute these values into the formula for work and solve for W.
W = Pt W = (15,000 W) · (210 s) W = 3,150,000 J W = 3.15 · 10⁶ JThis is the amount of work done by a 15 kW engine in 3.5 minutes.
Which waves can travel through space?
a. Electromagnetic waves only
b. Mechanical waves only
c. Electromagnetic and mechanical waves
d. Longitudinal and electromagnetic waves
Answers
Answer:
electromagnetic waves only
Explanation:
I just took the test, Hope it helps!
Answer:
A: Electromagnetic waves only
Explanation:
A 15 kg box is pushed with a force of 35 N in the +x direction, and the box accelerates to the right. It does not accelerate up or down
Answers
The box accelerates to the right due to the applied force of 35 N in the +x direction.
Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:
acceleration = net force / mass
acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)
Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.
Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.
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URGENTTTT
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?
Referring to the graph in the section header, what was the runner's velocity during segment D?
Answers
The displacement of the runner according to the graph is obtained as 250 m.
What is the displacement?The term displacement has to do with the distance that is covered in a specified direction. The difference between distance and displacement is that displacement is a vector while distance is a scalar quantity.
Thus we bring the direction into play when we are talking about the displacement of the object. Now we have a graph that shows the displacement of the runner in the vertical axis and then shows the time that is taken in the horizontal axis.
Given the graph as we have it, we can be bale to pick out the following from the graph;
1) Displacement of the runner at 100 s = 500 m
2) Displacement of the runner at 300 s = 750 m
Therefore;
Displacement of the runner between 100 and 300 seconds;
750 m - 500 m = 250 m
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A large tank is filled with water to a depth of 38 m. An opening is located 14 m
above the bottom of the tank. How fast will water emerge from the opening?
Answers
When a large tank is filled with water to a depth of 38 m. An opening is located 14 m above the bottom of the tank then the water would emerge from the opening at a velocity of 21.70 m/s
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.
As total mechanical energy ias s the sum of all the kinetic as well potential energy stored in the system.
ME = KE + PE
The total kinetic energy
KE = 1/2*m*v²
Similarly, the total potential energy
PE = m*g*h
As given in the problem When a large tank is filled with water to a depth of 38 m. An opening is located 14 m above the bottom of the tank
height of the water above the opening
h= 38-14
h= 24 m
The potential energy of water above the opening is getting converted into the kinetic energy
m*g*h = 1/2*m*v²
v = √(2*g*h)
By substituting the respective values of the height and gravity
v = √(2*9.81*24)
v = 21.70 m/s
Thus, when water is poured into a sizable tank until it reaches a 38 m depth. If a hole were to be made at a height of 14 m above the tank's bottom, water would rush out of it at a speed of 21.70 m/s.
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How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
PLEASE HELP!!!
Because of the forces acting on the cart, it will
A: Accelerate to the right
B: Accelerate to the left
C: Accelerate upwards
D: Not accelerate
Answers
Answer:
B. Accelerate to the left
Explanation:
We know that the direction of forces is along the direction of the resultant force. The net force operating on the body, along with the body's direction, is referred to as the resultant force on the body. When the object is at rest or moving at the same speed as the object, the resultant force is zero.
Let us consider the forces on the right side direction as positive and on the left side direction as negative.
From figure, the force along right direction is +50 N, the force along left direction is -150 N.
So we can write
\(F_{right} =+50 N\)
\(F_{left} =-150 N\)
The total or resultant force can be determined as
\(F_{net} =F_{right} +F_{left} =+50-150=-100 N\)
The direction of resultant force is negative, so force will be along left direction. Acceleration of the body is always along direction of force, so the body will accelerate to the left.
Variable Radius Mass (kg) Period (s) 3 2 Radius (m) 1 2 3 3 Tangential speed (m/s) 3.14 3.14 3.14 3.14 3.14 4 Centripetal Force (N) 29.6 14.8 9.87 7.40 5.92 6 www 8 4 10 5 Analysis: Force vs Circle Radius 1. Looking at the Variable Radius table, what can you conclude about the relationship between the centripetal force and radius? What is the functional form of this relationship?
Answers
We can infer from the Variable Radius table that as the radius grows, the centripetal force decreases.
The centripetal force and radius have an inverse connection, which means that as one quantity changes, the other changes proportionally.
The mathematical formula for the functional form of this connection is F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius.
The centripetal force equation, which describes this relationship, is a key idea in comprehending circular motion.
The Variable Radius table reveals that there is an inverse proportionality between the centripetal force and radius. The centripetal force reduces as the radius grows, and vice versa.
The centripetal force equation, F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius, describes this relationship.
The travel of planets around the sun or the movement of cars around a curve are only two examples of how comprehending this relationship is crucial to understanding circular motion.
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At what horizontal velocity would a satellite have to be launched from the top of Mt. Everest to be placed in a circular orbit around the Earth.
Given formula:
GM/R = v^2
G= 6.67 x 10^-11 N.m^2/kg^2
M= 5.98 x 10^24kg
R= 6.38 x 10^3 km
Answers
An orbital projectile should be launched with such a horizontal speed exceeding 8000 m/s. Determine the speed of the a satellite inside an orbit 1000 km, M is 5.98x1024 kg, and R is 6.4x10m. [Ans x 10 = 7.34 m/s].
How far is the top of Mount Everest from outer space?At 328,084 feet, the barrier between earth and space is the highest point you have probably ever gone and is around 11 times greater than Mount Everest. Consider that for a second. If looking at this image doesn't inspire awe in you, perhaps contemplating it in a different way would.
What speed is necessary to send a satellite up at the very least?A: At low earth orbit, an object must travel at a speed of roughly 28,000 km/h (17,500 mph) in order to orbit the Earth. At this speed, the object would be able to leave Earth's atmosphere and keep a steady orbit around it at a height of about 325 km (200 km).
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What is the frequency of this wave
1
2
3
4
Answers
Answer: The answer is 2
Explanation:
I got it wrong by picking 3 and the correct option was 2 on edge
An OP AMP has CMRR = 100 dB and open-loop gain =250000.
Determine the common mode gain ACM
Answers
Answer:
ACM = 2.5
Explanation:
The common mode rejection ratio, is a parameter that is used to measure the ability of an Operational-Amplifier, to reject or eliminate the noises of same polarity. The common mode rejection ratio is given by the following formula:
CMMR = AV/ACM
for the value of CMMR in deciBels (dB), the formula becomes:
CMMR = 20 log(AV/ACM)
where,
CMMR = Common Mode Rejection Ratio = 100 dB
AV = Open Loop Gain = 250000
ACM = Common Mode Gain = ?
Therefore,
100 = 20 log (250000/ACM)
100/20 = log (250000/ACM)
10⁵ = 250000/ACM
ACM = 250000/10⁵
ACM = 2.5
Which of the following is likely to indicate a chemical change ?
Answers
Answer:
A:The dissaperance of a solid stirred in water
The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
Answers
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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Unlike potential energy, kinetic energy cannot —
Answer choices:
a. be heard as sound waves.
b. be stored in atomic bonds.
c. travel in light waves.
d. travel through electrons moving through a wire.
Answers
Answer:Which type of wave vibrates parallel to the direction the energy travels, like a slinky ... ex: Rainbow is composed of different frequencies of visible light ... ex: sledding down a hill - potential energy TRANSFORMS into kinetic energy ... C mechanical. D heat. B Chemical energy is energy stored in the bonds of a chemical ...
Explanation:
A car traveling at 11.6 meters per second crashes into a barrier and stops in 0.287 meters. What force must be exerted on a child of mass 21.2 kilograms to stop him or her in the same time as the car? Answer must be in 3 significant digits.
Answers
The equation to obtain the final speed of car is,
\(v^2=u^2+2as\)Substitute the known values,
\(\begin{gathered} (0m/s)^2=(11.6m/s)^2+2a(0.287\text{ m)} \\ a=\frac{-134.56m^2s^{-2}}{2(0.287\text{ m)}} \\ \approx-234.4m/s^2 \end{gathered}\)The negative sign of acceleration indicates that the car is deaccelerating.
The force required to stop the car is,
\(F=ma\)Substitute the magnitude of known values,
\(\begin{gathered} F=(21.2kg)(234.4m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =4969.28\text{ N} \\ \approx4970\text{ N} \end{gathered}\)Thus, the force required to stop the car is 4970 N.
Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!
Answers
There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.
However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.
Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.
Explanation: