A gas has a volume of 6.00 liters at a temperature of 27° C and a pressure of 1,00 atm. What is the volume of the gas, in liters, at a temperature of 327°C and a
pressure of 3.00 atm?

Answer:

C) 2, 4.

Explanation:

Hello!

In this case, since the sulfur atom has six electrons at its outer shell, it suggests it needs to gain two electrons in order to attain a complete octet, that is why it has 2 paired electrons.

Moreover, since two electrons are paired, then 4 electrons will remain unpaired; therefore the answer would be C) 2, 4.

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The degree of association of AlCl3 into Al2Cl6 is 0.663. The degree of association of AlCl3 into Al2Cl6 can be determined using the ideal gas law and the van't Hoff factor.

Firstly, we need to calculate the number of moles of AlCl3 present in the vessel using the formula n = m/M, where m is the mass of AlCl3 and M is the molar mass of AlCl3.

n = 10.32g / 133.34 g/mol = 0.0774 mol

Next, we can use the ideal gas law equation PV = nRT to calculate the number of moles of particles in the gas phase. Rearranging this equation, we get:

n = PV/RT

where P is the pressure, V is the volume, R is the gas constant and T is the temperature in Kelvin.

n = (1.7 x 10 N/m²) x 1 dm³ / (8.31 J/mol/K x 353 K) = 7.55 x 10⁻⁴ mol

The van't Hoff factor (i) is the ratio of the actual number of particles in solution to the number of formula units dissolved. For a completely dissociated compound, the van't Hoff factor is equal to the number of ions produced. In the case of AlCl3, it undergoes a degree of association to form Al2Cl6, so the van't Hoff factor is less than 1.

We can now use the formula i = 1 + (α - 1)β, where α is the degree of association and β is the number of particles in solution per formula unit. For AlCl3, β = 4 (AlCl3 contains one Al and three Cl atoms), and assuming a degree of association of x, we get:

i = 1 + (x - 1) x 4 = 4x - 3

Substituting the values for n and i into the equation n = iC, where C is the concentration in mol/dm³, we get:

7.55 x 10^-4 mol = (4x - 3) C

Solving for x, we get:

x = 0.663

Therefore, the degree of association of AlCl3 into Al2Cl6 is 0.663.

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Answer:

1.30 mol P

Explanation:

take what is given to you (40.4g). now divide it by the molar mass of the asked element (phosphorus = 30.97g/mol)

40.4g P / 30.97g/mol P = 1.30 mol P

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The balanced chemical equation for the reaction is:

N₂ + 3H₂O → 2NH₃ + O₂

The equation shows that nitrogen gas (N₂) and water (H₂O) react to form ammonia (NH₃) and oxygen gas (O₂). The coefficients in the balanced equation indicate that one molecule of N₂ reacts with three molecules of H₂O to produce two molecules of NH₃ and one molecule of O₂.

The following types of bonds exists between the listed atoms;

A bond is polar covalent when the electronegativity difference between the bonding atoms is above that found in a nonpolar covalent bond.  Now we shall see the types of bonds between these atoms.

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Answer:

it bubbles up and has a chemical reaction also releases co2

Explanation:

Hope it helps <3

Answer:

okay....

Explanation:

technically, fish do not have wings. they are called fins and they are used for the purpose of transportation, just as legs are for humans.

~Ren

Answer:

Pentyl Ethanoate, CH3COOC5H11, which smells like bananas, is produced from the esterification reaction: CH3COOH(aq) +C5H11OH(aq) → CH3COOC5H11(aq) + H … 2O(l) A reaction uses 3.58g of CH3COOH and 4.75g of C5H11OH and has a yield of 45.00%. Determine the mass of ester that foorms

When we convert Bilbo's shire property (i.e 108540 m²) to acres, the result obtained is 26.82 acres

From the question given above, the following data were obtained:

We can convert 108540 m² to acres by doing the following

Conversion scale

4047 m² = 1 acre

Therefore

108540 m² = 108540 / 4047

108540 m² = 26.82 acres

Thus, 108540 m² is equivalent to 26.82 acres

Therefore, we can conclude that Bilbo's shire property in acres is 26.82 acres

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In this case, according to the given information, whereas iron titanate forms in the ilmenite crystal structure that consists of an HCP arrangement, it'd be necessary to use the following equation, in order to figure out the ionic radii ratio of Fe²⁺ to O²⁻ which provides the interstitial site type:

\(\frac{r_{Fe^{2+}}}{r_{O_2^{2-}}}\)

Now, the ionic radii depends on the source that is considered, that is why in this case, we will consider the data reported by Askeland, The Science And Engineering Materials 6th edition for the required radii:

\(r_{Fe^{2+}}=0.074 nm\\\\r_{O_2^{2-}}=0.132 nm\)

Thus, the ratio will be:

\(\frac{0.074nm}{0.132 nm}=0.561\)

Which is within the range of octahedral sites (0.414–0.732).

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Answer:

Explanation:

Conversely, the largest (in terms of mass) fundamental particle we know of is a particle called a top quark, measuring a whopping 172.5 billion electron volts, according to Lincoln.

J.J. Thomson sent a cathode ray between electrically charged metal plate. The aim of the experiment was to find the nature of the particles. The correct option is option D

He lighted the metal plates. A gold foil was subjected to an alpha radiation beam by B. C. In a chamber, he suspended charged oil drops. OD. He produced a cathode ray discharge between two electrically charged metal plates. All atoms include tiny, negatively charged subatomic particles that mimic electrons, as demonstrated by J.J. Thomson's cathode ray tube studies. In Thomson's "plum pudding" atom model, a negatively charged "electon" encircled a positively charged "soup."

He made the decision to attempt to identify the particle's makeup. He sought to calculate their mass and charge by measuring how much they were bent by electrical currents of various intensities because they were too small to have their mass or charge directly ascertained.

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Answer:

Two positive aspects of using methane recapture systems are able to generate significant electricity. Another benefit is that the process of anaerobic digestion creates heat that can be used to warm buildings where animals are kept

Answer:  The correct answer is;

Two positive aspects of using methane recapture systems include lowering the impact on greenhouse gasses and the production of energy. Methane is a very potent greenhouse gas that is contributing to global warming. As a result, the recapturing process reduces the methane impacts of global warming by reclaiming and reusing the gas for other purposes. Recaptured methane can be stored and used to generate electricity or used as fuel to power updated vehicles and other engines on the farm. The overall benefits from this combination are reducing impacts causing global warming and lower the cost of electricity or fuel on the farm.

Explanation:  This answer has been confirmed correct.

A. The number of atoms in  1.15×10⁻⁶ moles of helium is 6.92645×10¹⁷.

B. The number of moles of helium that contains 4.77×10²¹ atoms is 7.9196×10⁻³ moles.

according to the definition of Avogadro's Number.

Avogadro's Number is called the number of particles (usually atoms or molecules) that exist in one mole of any substance. Its value is 6.023×10²³ particles per mole.

You can apply the following rule of three: If 1 mole contains 6.023×10²³ atoms of helium, 1.15×10⁻⁶ moles of helium contains how many atoms?

amount of atoms of atoms= (1.15×10⁻⁶ moles× 6.023×10²³ atoms)÷ 1 mole

amount of atoms of atoms= 6.92645×10¹⁷ moles

Then, there is 6.92645×10¹⁷ atoms.

You can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of helium, then 4.77×10²¹ atoms are contained in how many moles of helium

amount of moles of helium= (4.77×10²¹ atoms × 1 mole)÷ 6.023×10²³ atoms

amount of moles of helium= 7.9196×10⁻³ moles

Finally, there is 7.9196×10⁻³ moles.

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The number of mole of F present in 708.5 grams of F₄C is 32.2 moles

First, we shall determine the mole in 708.5 grams of F₄C. Details below:

Mole = mass / molar mass

Mole of F₄C = 708.5 / 88

Mole of F₄C = 8.05 moles

Finally, we shall determine the number of mole of F in 708.5 grams (i.e 8.05 moles) of F₄C. Details below:

From the chemical formula of F₄C,

1 mole of F₄C contains 4 moles of F.

Therefore,

8.05 moles of F₄C will contain = (8.05 mole × 4 mole) / 1 mole = 32.2 moles of F.

Thus, we can conclude from the above calculation that the number of mole of F present is 32.2 moles

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Answer:

name four agricultural inputs are subsidized by the government

0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Given,

mass = 10g

c = 0.901J/g⁰C

Initial temperature (T₁) = 22⁰C

Final Temperature (T₂) = 55⁰C

Q = mcΔT

= 10 × 0.901 × (55 -22)

= 297.33 J = 0.297 kJ

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Explanation:

1.undetectable to electromagnetic waves

2.hiding an object from an illumination containing diffre t wave lengths become difficult as the object sizes grow.

3. reduce the scattering by two orders.

Electromagnetic waves are unable to detect it. With increasing item sizes, it becomes more challenging to conceal an object from an illumination with various wave lengths. two orders down on the scattering.

Current clocking technology is defined as a hypothetical or made-up stealth technology that makes things like people or spaceships completely or partially invisible to certain electromagnetic (EM) spectrum wavelengths. In a specific frequency band, this gadget renders an object "invisible" to electromagnetic radiation. Obviously, cloaks that operate in the visible spectrum have the most fascinating potential uses.

These metamaterials, according to the researchers, can shield a medium-sized antenna from radio waves over a wide range of bandwidths, resulting in clearer communications. However, as visible light wavelengths are far shorter than radio waves, it is practically difficult to conceal huge things from them, such as the human body. The issue with present designs is that they can only handle a certain amount of bandwidth. Even this "perfect" 3D cloak that was previously exhibited could only conceal items from microwaves.

Thus, electromagnetic waves are unable to detect it. With increasing item sizes, it becomes more challenging to conceal an object from an illumination with various wave lengths. two orders down on the scattering.

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The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.

The position of the image formed is determined using the followimg mirror formula;

\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\)

where;

f = R/2

f = 1.5/2

f = 0.75 m

When the ball and its image is in the same position, u = v

The position of the ball is calculated as;

\(\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m\)

The time taken for the ball to travel the caluclated distance is determined as;

h = ut + ¹/₂gt²

1.5 = 0  + ¹/₂(9.8)t²

1.5 = 4.9t²

t² = 1.5/4.9

t² = 0.306

t = 0.55 s

Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.

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Look for the ones with the same number of protons and different neutrons number

Answer:

6.5

Explanation:

10.0 g of ethanol would require more heat to raise the temperature by 10.0°C Because it has a higher boiling point.

The boiling point of a liquid is the temperature at which the vapour pressure of the liquid becomes equal to the atmospheric pressure of the liquid’s environment. At this temperature, the liquid is converted into a vapour.

The normal boiling point is high for liquids with strong intermolecular attractions and low for liquids with weak intermolecular attractions.

10.0 g of ethanol would require more heat to raise the temperature by 10.0°C because it has a higher boiling point.

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The amount, in mL, of the suspension that should be given to an infant weighing 17 lb will be 1.16 mL

0.8 mL of the liquid contains 80.0 mg of the drug.

The recommended dose is 15 mg per kg of body weight

The infant to be given the drug weighs 17 lb.

First, let's convert the weight of the infant to kg.

1 lb = 453.59 g

17 lb =       453.59 x 17/1

                   = 7711.03 g

1000 g = 1 kg

7711.03 g = 7711.03 x 1/1000

               = 7.711 kg

So, the baby's weight is 7.711 kg.

The drug dose for the baby can thus be calculated as:

15 mg x 7.711 = 115.67 mg

But 0.8 mL of the drug contains only 80.0 mg. How many mL will contain 115.67 mg?

                   0.8 x 115.67/ 80.0 = 1.16 mL

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Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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Answer:

Substance C

Explanation:

Substance C would be the answer because Substance C has a lower attraction level. Because of this, it takes more energy to take out of in order to become a liquid.

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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Explanation:

hope it will help you. Wishing a nice day. enjoy with your answer

The rate of the reaction greatly accelerates when MnO2 is added to a hydrogen peroxide solution. For the breakdown of hydrogen peroxide, manganese dioxide serves as a catalyst.

Hydrogen peroxide breaks down into water and oxygen gas when manganese dioxide is present.

A metal oxide catalyst also facilitates the exothermic breakdown of hydrogen peroxide into water and oxygen (eq 1). (2) Using a catalyst, such as MnO2, lowers the activation energy to around 58 kJ/mol (1) and speeds up the breakdown by more than 1000 times compared to the uncatalyzed reaction.

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Answer:

They study fossils

Explanation:

Fossils are the evidence of past life preserved in rock. They provide a view of billions of years of biological change. By examining an animals fossils, they can discover what it looked like, what it ate, where it lived, and even how it died.