a gaseous mixture contains 414.0 torr h2(g), 394.9 torr n2(g), and 86.1 torr ar(g). calculate the mole fraction, , of each of these gases

Answer:

since you have both the mass and density of the sample, the volume can be derived from both

volume of seawater = \(\frac{5.0}{1.025}\)

                                 = 4.88 ml (3 s.f.)

Answer:

Chemistry provides an excellent foundation for careers in a variety of professions and occupations in academia, government, and industry, and in diverse fields such as environmental sciences, pharmaceuticals, medicine, materials, energy, oceanography, education, health, aerospace, law, and education.

Explanation:

Answer: Hi friend! Sorry if I'm incorrect but Chemistry can prepare you for many careers. Specifically in the scientific area.

Explanation:

If you're studying to get a Chemistry major. I think chemistry shows a way of objectifying and trying to find reasons in order to solve real world application problems. When you think about it chemistry is a guide to showing you current events, such as environment and technological advances.

Answer:

The final temperature will be "12.37°".

Explanation:

The given values are:

mass,

m = 0.125 kg

Initial temperature,

c = 22.0°C

Time,

Δt = 4.5 min

As we know,

⇒  \(q=mc \Delta t\)

On putting the estimated values, we get

⇒     \(=0.125\times 22.0\times 4.5\)

⇒     \(=12.37^{\circ}\)

Answer:

sugar is Soluble in water for the two can be mixed homogeneously to form a Solution

Answer: So, You need to write about Solids Gases and Liquids so do something simple but very smart.....

Explanation:

YOU CAN DO IT!!!

Answer:

B spiracles

Explanation:

These are the tubes connected to the openings in their sides

Insects use tiny openings in their body wall called spiracles to get oxygen. They are also called tracheal tubes. Hence, option B is correct.

An insect's inside functions almost like a sponge. Because a sponge has tiny holes that allow water to enter, it becomes moist. Spiracles are similar to this. They allowed oxygen to enter the bug's body. They then release carbon dioxide.

Insects can open and close their spiracles . This is accomplished through certain muscles . To drive oxygen  through their bodies, insects can also contract their muscles. The oxygen inside them is spread out by doing this.

Stomata is the reparatory organ in plants and gills are the organ in aquatic livings for respiration. In mammals lungs are the respiratory organ. Therefore, option B is correct.

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Answer:

1. true

2. false

Explanation:

PROMISE PROMISE to make the most of the su in the WORLD CUP and chemica are u doing the meetings with

An attractive force that holds the electrons close to the nucleus is the strong nuclear force

definition of nuclear force

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The given water-insoluble compound is discovered to be soluble in 10% NaOH. Out of the given two substances, CH₃(CH₂)₈CH₂-OH is most likely to be the compound.

Option B is correct .

A water-insoluble compound is discovered to be soluble in 10% NaOH. This means that the compound is a weakly acidic or non-acidic compound because it dissolves in a strong base like NaOH.

Only weakly acidic or non-acidic compounds dissolve in a strong base. Alcohols are not acidic, but phenols are acidic. Hence, the given water-insoluble compound is an alcohol. Now, we need to determine which of the given alcohol is soluble in NaOH.

The CH₃(CH₂)₈CH₂-OH alcohol has a long nonpolar alkyl chain. Alcohols with long nonpolar alkyl chains are less soluble in water than alcohols with small alkyl chains.

However, NaOH is a polar solvent. The long nonpolar alkyl chain is not soluble in water but is soluble in NaOH because NaOH is a polar solvent.Therefore, CH₃(CH₂)₈CH₂-OH is most likely to be the compound.

Incomplete question :

A water-insoluble compound is discovered to be soluble in 10% NaOH. Which of the following substances is most likely to be the compound?

a. CH₃CH₂-OH

b. CH₃(CH₂)₈CH2₂-OH

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There would be seven peaks if you could observe them all while considering no decomposition of the ion into smaller fragments.

Each sulfur isotope would give a peak so there are three possible combinations of the hydrogen isotopes:

H-H (m/z = 2), H-D (m/z = 3) and D-D (m/z = 4).

Thus, you will find 4 × 3 = 12 components for the molecular ion.

However, some of these peaks will overlap each other so the stable isotopes of sulfur have masses 32, 33, 34, and 36.

Thus, the expected peaks will be:

32S:m/z=34,35,36

33S:m/z=35,36,37

34S:m/z=36,37,38

36S:m/z=38,39,40

If every peak were visible, you would see seven peaks in total.

They would have m/z = 34, 35, 36, 37, 38, 39, 40.

Isotope peaks are ionic parts of the same chemical equation that are more often than not visible to different adjoining crests inferable to particles of distinctive isotopic compositions.

The number of isotope crests and the relative concentration of each crest depends on the chemical equation of the ionic part and the normal isotopic composition of its constituent components.

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Answer:

Student B because it can be done in natural settings​

Explanation:

Answer:

meter

have a nice holiday

Answer:

The Meter

Explanation:

In the metric system, the meter is the standard measurement of length.

Hope it helped!

Tο make 149.7 g οf CH₄, 9.32 mοles (οr 9.34 mοl, rοunded tο twο decimal places) οf carbοn are required.

Methane has the chemical fοrmula CH₄. Accοrding tο the fοrmula, 1 mοle οf carbοn atοms makes up 1 mοle οf methane.

The reactiοn's chemically balanced equatiοn is as fοllοws:

C + 2H₂ → CH₄

The mοlar mass οf CH₄ (methane) is:

12.01 g/mοl (fοr C) + 4(1.01 g/mοl) = 16.05 g/mοl

1 mοle οf C prοduces 1 mοle οf CH₄

Sο, the number οf mοles οf carbοn required can be calculated as fοllοws:

Mοles οf CH₄ = Mass οf CH₄ / Mοlar mass οf CH₄

Mοles οf CH₄ = 149.7 g / 16.05 g/mοl

Mοles οf CH₄ = 9.32 mοl

An alternative is tο use the quantity οf carbοn needed tο make 149.7 g οf CH₄. We may cοnvert the mass οf CH₄ tο mοles οf carbοn using the mοlar mass οf carbοn (12.01 g/mοl):

Mass οf C = Mass οf CH₄ / (Mοlar mass οf CH₄ / Mοlar mass οf C)

Mass οf C = 149.7 g / (16.05 g/mοl / 12.01 g/mοl)

Mass οf C = 112.28 g

Using the mοlar mass οf carbοn, it is pοssible tο cοnvert the mass intο the number οf mοles οf carbοn:

Mοles οf C = Mass οf C / Mοlar mass οf C

Mοles οf C = 112.28 g / 12.01 g/mοl

Mοles οf C = 9.34 mοl

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To prepare 1.00 L of pH = 12.00 buffer with a total concentration of 0.500 M of dimethylamine and dimethylammonium chloride, you will need  0.495 mol of each component.

The Henderson-Hasselbalch equation for a weak base and its conjugate acid is:

pH = pKa + log([conjugate base]/[acid])

At pH 12.00 and with a pKa of 10.73 for dimethylamine, the conjugate base/acid ratio is:

100 = 10.73 + log([conjugate base]/[acid])

[conjugate base]/[acid] = 100/\(10^(^1^0^.^7^3^)\)

[conjugate base]/[acid] = 99.54

Since the total concentration of the two components is 0.500 M, we have:

[conjugate base] + [acid] = 0.500 M

Substituting [conjugate base]/[acid] = 99.54, we can solve for the concentrations of each component:

[acid] = 0.500 M/(1 + 99.54) = 0.00498 M

[conjugate base] = 0.500 M - 0.00498 M = 0.495 M

The amount in moles of each component required to make 1.00 L of the buffer is then:

moles of dimethylamine = 0.00498 mol/L x 1.00 L = 0.00498 mol

moles of dimethylammonium chloride = 0.495 mol/L x 1.00 L = 0.495 mol

Since we need equal amounts of each component in the buffer, we will use the smaller amount, which is 0.00498 mol. Therefore, we need:

mass of dimethylamine = 0.00498 mol x 45.08 g/mol = 0.224 g

mass of dimethylammonium chloride = 0.00498 mol x 81.05 g/mol = 0.404 g

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To find the final temperature of the combined water, we can use the principle of conservation of energy.The final temperature of the combined water is approximately 150.3°C.

The equation used to calculate the heat exchange is:

Q = mcΔT

Where:

Q is the heat exchanged (in joules)

m is the mass of the water (in grams)

c is the specific heat capacity of water (approximately 4.18 J/g°C)

ΔT is the change in temperature (in °C)

First, let's calculate the heat lost by the hot water:

Q_hot = m_hot * c * ΔT_hot

Where:

m_hot = 96.9 g (mass of hot water)

ΔT_hot = (final temperature - initial temperature of hot water) = (final temperature - 71.1°C)

Next, let's calculate the heat gained by the cold water:

Q_cold = m_cold * c * ΔT_cold

Where:

m_cold = 62.7 g (mass of cold water)

ΔT_cold = (final temperature - initial temperature of cold water) = (final temperature - 27.9°C)

Since the heat lost by the hot water is equal to the heat gained by the cold water, we can set up the equation:

Q_hot = Q_cold

m_hot * c * ΔT_hot = m_cold * c * ΔT_cold

Plugging in the given values:

96.9 g * 4.18 J/g°C * (final temperature - 71.1°C) = 62.7 g * 4.18 J/g°C * (final temperature - 27.9°C)

Simplifying the equation:

404.8892 (final temperature - 71.1) = 261.6066 (final temperature - 27.9)

404.8892 final temperature - 404.8892 * 71.1 = 261.6066 final temperature - 261.6066 * 27.9

404.8892 final temperature - 28772.997 = 261.6066 final temperature - 7290.60714

404.8892 final temperature - 261.6066 final temperature = 28772.997 - 7290.60714

143.2826 final temperature = 21482.38986

final temperature ≈ 21482.38986 / 143.2826

final temperature ≈ 150°C (rounded to the nearest whole number)

Therefore, the final temperature of the combined water is approximately 150°C.

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Answer:

more energy is absorbed when the bonds in the reactants are broken

a. 4.2 x 10⁻¹³ J

b. 6.3 x 10⁻²⁰ J

c. 7 x 10⁻¹⁸ J

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\(\large{\boxed{\bold{E\:=\:h\:.\:f}}}\)

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

a.

\(\tt E=6.626.10^{-34}\times 6.32.10^{20}=4.1876.10^{-13}~J\)

b.

\(\tt E=6.626.10^{-34}\times 9.50.10^{13}=6.2947.10^{-20}~J\)

c.

\(\tt E=6.626.10^{-34}\times 1.05.10^{16}=6.9573.10^{-18}~J\)

Perceived control over a stressful event typically results in a. less reported stress.

When an individual believes they have control over a situation, they tend to feel more empowered and confident in their ability to manage or resolve the stressor. This perception of control allows them to develop effective coping strategies and focus on problem-solving rather than being overwhelmed by the stress. Consequently, this sense of control often leads to a reduction in overall stress levels.

Contrary to options b, c, and d, perceived control does not typically lead to more frustration, less motivation to solve the problem, or increased arousal. Instead, having a sense of control often allows individuals to approach the stressful event in a more positive and proactive manner, ultimately reducing the negative impact of the stressor on their mental and emotional well-being. Thus, fostering a sense of control over stressful events can be a crucial factor in managing stress effectively. So therefore the correct answer is a. less reported stress.

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She knows that the risk factor is not protective and is not very large. Relative risk measures the likelihood of an event occurring in one group compared to another.

In this case, since the risk factor is not protective and not very large, it suggests that the risk of the event happening is higher in the group with the risk factor compared to the group without it.  Based on this understanding, it is likely that Annie's relative risk value would be greater than 1.

This rules out options a. 0.5 and b. 0.2, as they are less than 1. Option c. 2.0 is a possibility since it is greater than 1, but it is not clear whether the relative risk value is "not very large" or just larger than 1. Option d. 1.2 is a safe choice since it is slightly larger than 1 and not very large, making it the most likely answer.

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Answer:

and the question is?

Explanation:

When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

The Baeyer-villiger oxidation would seem to be a chemical reaction that uses peroxy acids using peroxides as the oxidant to transform a ketone into an ester or a lactone from such a cyclic ketone.

The main product produced by the Baeyer-Villiger oxidation of camphor using m-CPBA in buffer conditions could be created as a result of the migration of a tertiary bridgehead carbon as opposed to a methylene group.

By the reaction between 3-methyl-2-butanone with m-CPBA , will form isopropyl acetate and methyl isobutyrate.

It reaction can be shown as:

Therefore, when 3-methyl-2-butanone undergoes a Baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

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Answer:

1/18x(6x-3y+2z)

1/3x-1/6y+1/9z

Explanation:

At the new point in the atmosphere, the volume of the balloon increases to 1.95 L due to the decrease in pressure. The decrease in temperature has no effect on the volume of the balloon.

Atmosphere is the gaseous layer surrounding the earth. It is composed of nitrogen (78%), oxygen (21%), argon (0.9%) and other trace gases. The atmosphere also contains water vapor, which varies in concentration from place to place and time to time. The atmosphere plays a vital role in regulating the earth's climate and is essential for life. It also acts as a barrier to cosmic rays, ultraviolet radiation, and other forms of radiation from outer space. The atmosphere consists of five main layers, the troposphere, stratosphere, mesosphere, thermosphere, and exosphere.

We are given the following values:

P₁ = 1.00 atm (initial pressure)

V₁ = 1.00 L (initial volume)

T₁ = 23.0°C + 273.15 = 296.15 K (initial temperature)

P₂ = 220 torr (final pressure)

T₂ = -31°C + 273.15 = 242.15 K (final temperature)

We need to convert the units to be consistent, so we convert the final pressure to atm:

P₂ = 220 torr / 760 torr/atm ≈ 0.289 atm

Now we can substitute the values into the combined gas law equation:

(1.00 atm × 1.00 L) / (296.15 K) = (0.289 atm × V₂) / (242.15 K)

Simplifying the equation and solving for V₂:

V₂ = (1.00 L×  0.289 atm ×  242.15 K) / (296.15 K)

V₂ ≈ 0.237 L

Therefore, the new volume of the balloon at the new altitude is approximately 0.237 L.

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Answer:

Tungsten

Explanation:

The mass of 3.4 moles of nitric acid (HNO₃) is 214.8432 g.

The molar mass of nitric acid, HNO₃, is determined using its molecular formula. It is calculated using the atomic masses of each of the elements in the formula multiplied by their respective subscripts and added together. The formula mass for HNO₃ is as follows: 1 Hydrogen (H) atom weighs 1.0079 amu, 1 Nitrogen (N) atom weighs 14.0067 amu, and 3 Oxygen (O) atoms each weigh 15.9994 amu.

Using these atomic masses, the formula mass of HNO₃ is calculated as follows:

1(1.0079) + 1(14.0067) + 3(15.9994) = 63.0128 g/mol.

The 3.4 moles of HNO₃ = (3.4 mol) x (63.0128 g/mol)= 214.8432 g

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Answer:

Hehe I don't know spanish -

Explanation: