The maximum speed of her brother as he swings is 5.04777 m/s.
Calculation:
conservation of energy
ΔPE = ΔKE
= mg (h₁-h₂) = 1/2= mv²
= v = √2g (h₁-h₂)
= V = √2x9·8 (0.34 - 1.08)
Vmax = 5.04777 m/s
Forces are influences that can change the movement of an object. A force can cause a mass to accelerate, thus changing its velocity. Forces can also be described intuitively by pushing or pulling. The word "force" has a precise meaning.
At this level, it is appropriate to describe the force as pushing or pulling. A force does not contain or have within an object. A force is applied from one object to another. The idea of force is not limited to animate or inanimate objects.
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The maximum speed of her brother as he swings (her brother sits passively in the swing.) is 1.14 m/s
The gravitational potential energy of the brother increases as he is lifted to a higher height. This increase in gravitational potential energy is converted to kinetic energy (the energy of motion) as the brother swings back down and gains speed. The maximum speed will be reached when all of the gravitational potential energy has been converted to kinetic energy.
The change in gravitational potential energy can be calculated using the formula:
ΔE = mgh
where m is the mass of the brother, g is the acceleration due to gravity (9.8 m/s^2), and h is the change in height.
Plugging in the values, we get:
ΔE = mgh = (50 kg)(9.8 m/s^2)(1.08 m - 0.34 m) = 330.8 kg*m^2/s^2
The maximum kinetic energy of the brother can be calculated using the formula:
E = 1/2 * m * v^2
where m is the mass of the brother, and v is the velocity (speed).
To find the maximum speed, we set the kinetic energy equal to the change in gravitational potential energy and solve for v:
E = 330.8 kgm^2/s^2 = 1/2 * (50 kg) * v^2
v = √(2E/m)
= √(2(330.8 kgm^2/s^2)/(50 kg))
= √(66.16/50)
= √(1.3232)
= 1.14 m/s
Thus, the maximum speed of the brother as he swings is approximately 1.14 m/s.
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Flies could be prey to predator plants, too what plant snacks on this fly?
Answer:
A Venus Fly trap
Explanation:
Insectivorous plants like pitcher plant and venus fly trap snack on flies or insects.
InsectivorousPlants which feed on insects are the insectivorous plants.These plants have special structures like leaves which help in trapping insects.The insects die in the enzymes and acidic juices so produced by the plant. The insects provide nourishment to these plants.
Therefore, insectivorous plants like pitcher plant and venus fly trap snack on flies or insects.
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fiber optic cable is thicker and heavier than unshielded twisted pair. question 10 options: true false
False, Fiber optic cable is thinner and lighter than unshielded twisted pair (UTP) cable.
Fiber optic cables are made up of strands of glass or plastic fibers that transmit data through light pulses. They are immune to electromagnetic interference and can transmit signals over longer distances than UTP cables, which are made up of copper wires.The content loaded Fiber optic cable is used in high-speed internet connections because it can transmit large amounts of data at very high speeds. Additionally, fiber optic cables are more secure than UTP cables because they are much more difficult to tap into without being detected. Therefore, the statement that fiber optic cable is thicker and heavier than UTP cable is false.
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Could someone please help
Answer: Dispersion
Explanation:
Which of the following is not a density-dependent factor limiting a population growth?
a) intra-specific competition
b) switching behavior of a predator
c) a stress syndrome that alters hormone levels
d) a limited number of available nesting site
Answer:A.
i know its a, i did quiz
what factors does the speed of sound depend upon? what are some factors that it does not depend upon?
Not volume or frequency, but wind, temperature, and humidity are factors. In a given medium, all sounds propagate at the same pace.
What do you mean by sound?Sound is a vibration that travels through a medium as a mechanical wave. It is produced by a vibrating body. It can spread via a solid, a liquid, or a gas as the medium.
What does a sound mean in science?Sound is a form of energy created by vibrations. Air molecules nearby move as an item vibrates. These molecules collide with the molecules nearby, causing them to vibrate as well. They then collide with additional surrounding air molecules as a result.
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A wave travels at 295 m/s and has a wavelength of 2.50 m. What is the frequency of the wave?
O 118 Hz
O 292 Hz
O297 Hz
O 738 Hz
Answer:
\(118\; \rm Hz\).
Explanation:
The frequency \(f\) of a wave is equal to the number of wave cycles that go through a point on its path in unit time (where "unit time" is typically equal to one second.)
The wave in this question travels at a speed of \(v= 295\; \rm m\cdot s^{-1}\). In other words, the wave would have traveled \(295\; \rm m\) in each second. Consider a point on the path of this wave. If a peak was initially at that point, in one second that peak would be
How many wave cycles can fit into that \(295\; \rm m\)? The wavelength of this wave\(\lambda = 2.50\; \rm m\) gives the length of one wave cycle. Therefore:
\(\displaystyle \frac{295\;\rm m}{2.50\; \rm m} = 118\).
That is: there are \(118\) wave cycles in \(295\; \rm m\) of this wave.
On the other hand, Because that \(295\; \rm m\) of this wave goes through that point in each second, that \(118\) wave cycles will go through that point in the same amount of time. Hence, the frequency of this wave would be
Because one wave cycle per second is equivalent to one Hertz, the frequency of this wave can be written as:
\(f = 118\; \rm s^{-1} = 118\; \rm Hz\).
The calculations above can be expressed with the formula:
\(\displaystyle f = \frac{v}{\lambda}\),
where
\(v\) represents the speed of this wave, and \(\lambda\) represents the wavelength of this wave.Answer:
118
Explanation:
Explain the operation of a simple circuit made of logic gates
and design the following combinational circuit.
Answer:
A combinational logic circuit is a circuit whose outputs only depend on the current state of its inputs. In mathematical terms, the each output is a function of the inputs. These functions can be described using logic expressions, but is most often (at least initially) using truth tables.
1 A grandfather clock uses energy stored in raised weights. The weights transfer energy to the clock mechanism as they fall. One clock has a 4.5 kg weight that supplies energy to the chimes (which play a few notes every 15 minutes), and two 3.5 kg weights that power the clock and the mechanism that strikes the hours.
For all questions on this sheet,
use g = 10 N/kg
a Calculate how much energy is stored when all three of these weights are raised by 70 cm. b How far does the 4.5 kg weight have to be lifted to store 45 J of energy?
2 The water tank in a house can hold 200 litres of water. The mass of 1 litre of water is 1 kg. The tank is 2 m above the bathroom taps and 5 m above the kitchen taps. The kitchen taps are 1 m above the floor.
a
Calculate the gravitational potential energy (GPE stored in the water in the tank when it is full. State any assumptions made in your answer.
b Calculate the speed at which the water would come out of the bathroom taps and kitchen taps. You
may assume that no energy is transferred due to friction in the pipes.
3 The Victoria Falls in Africa is one of the world's largest waterfalls. Just over 1000 m° of water pass over the falls every second and fall approximately 100 m. 1 m3 of water has a mass of 1000 kg. a What mass of water goes over the falls every second? Give your answer in standard form.
b
Calculate the GPE of 1 kg of water at the top of the falls.
c If all the GPE stored in 1 kg of water is transferred to kinetic energy, calculate the speed of the water as
it reaches the bottom.
d Suggest why the water will not be falling as fast as your answer to part c suggests. e What is the total energy transferred per second as the GP stored in the water falling in one second is
transferred to other energy stores.
f Suggest the ways in which this energy is finally stored.
4 A post driver is used to drive fence posts into the ground. It is a hollow tube with a closed top, and handles on the side. A person fits the driver over a fence post, then lifts it up and lets it drop.
post driver
50 cm
a A post driver has a mass of 10 kg. Calculate the change in GPE stored when the post driver is lifted by 50 cm above the post, as shown in the diagram.
b
Calculate the speed of the driver when the end hits the post.
C
Explain how much extra energy is stored if the post driver is
fence post
lifted by 1 metre instead of only 50 cm.
d Calculate the speed of the post driver after it falls for 1 m. e A new design of post driver has a mass of 15 kg. Suggest one advantage and one disadvantage of this new design.
Extra challenge
5 F The post driver in question 4a stops in
0.5 seconds when it hits the fence post.
a Calculate the force needed to bring the post driver to a stop. (Hint: use your answer to 4b.)
The momentum of a moving object is the product of its mass and its velocity. The force needed to stop a moving object depends on how fast its momentum changes.
force = change in momentum
=
mv - mu
time
t
b What provides this force?
c Explain how your answer might be different it the post were being sunk into very soft ground,
F = force (N)
u = initial velocity (m/s)
te time (s)
m = mass (kg)
v = final velocity (m/s)
1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.
1b) The height of the tank is 2 m.
2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.
3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.
3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.
3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
1a) To calculate the amount of energy stored in the three weights, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
For the 4.5 kg weight:
E = 4.5 x 10 x 0.7 = 31.5 J
For each of the 3.5 kg weight:
E = 3.5 x 10 x 0.7 = 24.5 J
Thus, the total energy stored when all three weights are raised by 70 cm is:
31.5 J + 24.5 J + 24.5 J = 80.5 J
1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:
E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)
To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:
Mass = 200 kg
The height of the tank is 2 m.
Therefore, the gravitational potential energy stored in the water in the tank is:
E = mgh = 200 x 10 x 2 = 4000 J
Assumptions made in the answer:
We have assumed that the tank is full.
2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:
PE = KEPE = mghKE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:
PE = mgh = 200 x 10 x 2 = 4000 J
The potential energy is converted into kinetic energy when the water flows out of the taps.
Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)
3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:
Mass = Volume x Density
Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg
3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:
E = mgh
Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J
3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:
PE = KEP
E = mgh
KE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,
PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:
Power = Energy / Time
Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)
The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
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A motorcycle cop, parked at the side of a highway reading a magazine, is passed by a woman in a red Ferrari 308 GTS doing 120.0 km/h. After a few attempts to get his cycle started, the officer roars off 2.00 s later. At what average rate must he accelerate if 159 km/h is his top speed and he is to catch her just at the state line 3.04 km away?
Answer:
XZXDHF
Explanation:ZDHF
What is ballistic in simple words?.
Ballistics is the study of projectile propulsion, flight, and impact. It is separated into a number of disciplines. The subjects of internal and external ballistics, respectively, are projectile propulsion and flight.
Intermediate ballistics refers to the phase that exists between these two regimes. Ballistics is the study of how projectiles are fired, how they fly, and how they strike a target. It is frequently related to rockets, guided missiles, and projectiles launched from weapons.
The word "ballistic" refers to how an object travels through space. Typically, it refers to projectiles fired by weapons, such as bullets or rockets. Get out of the way if a ballistic missile is headed your way! A ballistic missile is only guided during its initial launch.
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An object of mass 20 g is moving in a horizontal circle of radius 250 cm at a speed of 50 cm/s. What is the centripetal acceleration experienced by the object?
The centripetal acceleration experienced by an object moving in a circle is given by the formula:
a = v²/r
where a is the centripetal acceleration, v is the speed of the object, and r is the radius of the circle.
In this problem, we are given that the object has a mass of 20 g, which we need to convert to kilograms:
m = 20 g = 0.02 kg
We are also given that the object is moving in a horizontal circle of radius 250 cm at a speed of 50 cm/s. We need to convert these measurements to SI units (meters and seconds) to use the formula for centripetal acceleration:
r = 250 cm = 2.5 m
v = 50 cm/s = 0.5 m/s
Now we can calculate the centripetal acceleration:
a = v²/r = (0.5 m/s)² / 2.5 m = 0.1 m/s²
Therefore, the centripetal acceleration experienced by the object is 0.1 m/s².
Planet Force (N) Mass (kg)
A 8.0 0.50
B 30 3.0
C 45 3.0
D 60 6.0
The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the corresponding masses are shown in the data table. Analyze the data and develop a method for comparing the gravitational field strengths on the different planets. Use your method to compare the gravitational field strengths, and report your conclusions.
From the analysis, it can be concluded that planet A has the strongest gravitational field, followed by planet C, and planets B and D have the same gravitational field strength.
The gravitational force acting on various masses is measured on different planets. The table shows the measured values for the forces acting on the corresponding masses:Planet Force (N) Mass (kg)A 8.0 0.50B 30 3.0C 45 3.0D 60 6.0
Method for comparing the gravitational field strengths on the different planets:First, we can use the formula for calculating gravitational force: \(`F = G (m_1m_2 / r^2)`\)where G is the universal gravitational constant `\(6.67 * 10^{-11 }Nm^2/kg^2\), m1 and m2 are the masses of the two objects in kg, and r is the distance between the centers of the objects in meters.
We know that the force is proportional to mass (F = ma). So we can calculate the acceleration due to gravity (g) on each planet by dividing the force by the mass. Therefore, we can use the formula: `g = F / m`.
Comparing the gravitational field strengths on the different planets:We will calculate the acceleration due to gravity (g) on each planet.
For planet A: `
g = F / m
= 8.0 N / 0.50 kg
= 16 \(m/s^2\)`
For planet B: `g = F / m
= 30 N / 3.0 kg
= 10 \(m/s^2\)
For planet C: `g = F / m
= 45 N / 3.0 kg
= 15 \(m/s^2\)
For planet D: `g = F / m
= 60 N / 6.0 kg
= 10 \(m/s^2\)
`So we see that planet A has the strongest gravitational field, followed by planet C, then planet B and planet D have the same gravitational field strength.
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domestic operations fall under which mission areas ssd4
Domestic operations fall under several mission areas, including Homeland Security, Critical Infrastructure Protection, and Community Resilience.
The Homeland Security mission area involves activities that are undertaken to protect the United States and its territories from threats, both foreign and domestic. This includes preventing and responding to terrorist attacks, securing the border, and protecting critical infrastructure. Domestic operations can be an important component of this mission area, as they may involve working with state and local law enforcement agencies to prevent and respond to potential threats.
Critical Infrastructure Protection focuses on safeguarding the essential systems and assets that are necessary for the functioning of our society. These can include everything from power plants and water treatment facilities to financial institutions and transportation networks. Domestic operations may be employed to help ensure the safety and security of these critical assets, through activities such as surveillance, intelligence gathering, and emergency response planning.
Finally, the Community Resilience mission area is concerned with promoting the ability of communities to withstand and recover from all types of hazards and disasters. Domestic operations can play a key role in achieving this goal, by working with local officials and community leaders to develop and implement effective emergency response plans, coordinate resources, and provide support to those in need during times of crisis.
Overall, domestic operations can be an important component of several different mission areas, all of which are focused on ensuring the safety and security of the United States and its citizens. By working together with federal, state, and local partners, these operations can help to mitigate threats, protect critical infrastructure, and promote community resilience in the face of any challenges that may arise.
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How can water boil without heat?
Answer:
Put water at room temperature into a vacuum chamber and begin removing the air. Eventually, the boiling temperature will fall below the water temperature and boiling will begin without heating. Or if you want to be easy but messy, add dry ice to a bowl of water and watch how the water starts to boil.
(ii) Atmospheric pressure on that day is 1.0 x 10^5Pa
Calculate the total pressure at the bottom of the pond
Answer:
Explanation:Force applied by atmosphere = atmospheric pressure × ares of table
F=P×A
F=1.013×\(10^{5}\) ×(2×1)=2.026×\(10^{5}\)N
Find the mass of an object the accelerates at 3.4 m/s2 when a net force of 25.1 N force is applied to it. Answer in units of kg and include all necessary work.
Help Please
Given,
Acceleration of the object = 3.4 m/s²Net force = 25.1 NWe need to find,
Mass of the body = ?Using Newton's first law of motion .
Force = Mass × Acceleration➵ 25.1 = Mass × 3.4
➵ 25.1 ÷ 3.4 = Mass
➵ Mass = 7.38 kg
the reaction to the force in part b is a force of magnitude _____, exerted on the _____ by the _____. its direction is _____.
A. A downward force of magnitude 5 N is exerted on the book by the force of gravity.
B. An upward force of magnitude 5 N is exerted on the book by the table.
C. The reaction to the force in Part B is a force of magnitude 5 N, exerted on the table by the book. Its direction is downward.
According to Newton's third law of motion, the book exerts a force of 5 N on the table in a downward direction, and the table exerts an equal and opposite force of 5 N on the book in an upward direction. The upward force exerted by the table on the book is also 5 N, since the two forces are equal in magnitude and opposite in direction.
The reaction to the upward force exerted by the table on the book is a force of 5 N exerted by the book on the table in a downward direction, again in accordance with Newton's third law. The direction of this force is opposite to that of the upward force exerted by the table on the book.
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--The complete question is, A book weighing 5 N rests on top of a table.
A. A downward force of magnitude 5 N is exerted on the book by the force of
B. An upward force of magnitude _____ is exerted on the _____ by the table.
C. The reaction to the force in Part A is a force of magnitude _____, exerted on the _____ by the _____. Its direction is _____.--
describe the components of soil
Soil is a material composed of five ingredients — minerals, soil organic matter, living organisms, gas, and water. Soil minerals are divided into three size classes — clay, silt, and sand (Figure 1); the percentages of particles in these size classes is called soil texture.Soil contains air, water, and minerals as well as plant and animal matter, both living and dead. These soil components fall into two categories. ... Other, less common minerals include calcium, magnesium, and sulfur. The biotic and abiotic factors in the soil are what make up the soil's composition.
a toy cork gun contains a spring whose spring constant is 18n/m. the spring is compressed 7.47 cm and then used to propel a 9 cork. the cork, leaves the spring from the spring's relaxed length. with what speed, in m/s, does the cork leave the spring?
The cork leaves the spring at a speed of 3.02 m/s.
We can use the conservation of energy to determine the speed at which the cork leaves the spring.
The initial potential energy stored in the spring is converted to the kinetic energy of the cork as it leaves the spring. Neglecting air resistance, the conservation of energy equation is:
(1/2) k x^2 = (1/2) m v^2
where k is the spring constant, x is the distance the spring is compressed, m is the mass of the cork, and v is the speed of the cork as it leaves the spring.
Substituting the given values:
(1/2) * 18 N/m * (7.47 cm / 100 cm/m)^2 = (1/2) * 0.009 kg * v^2
Solving for v:
v^2 = (18 N/m * (7.47 cm / 100 cm/m)^2) / 0.009 kg
v^2 = 9.119 m^2/s^2
Taking the square root of both sides:
v = 3.02 m/s
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.Carbon-14 (14 6C) dating is a method for finding the age of an organic artifact from the quantity of 14 6C it contains. Carbon-14, an unstable isotope of carbon, follows a well-known sequence of decay processes. The decay constants of these processes have been well established, allowing researchers to determine the age of an artifact knowing both the original amount of 14 6C and the current amount.
In the lab, it is relatively easy to measure the activity of a sample and to estimate the mass of carbon in the sample. From these measurements, it is possible to find the age of the sample.
Find the age t of a sample, if the total mass of carbon in the sample is mc, the activity of the sample is A, the current ratioof the mass of 14 6C to the total mass of carbon in the atmosphere is r, and the decay constant of 14 6Cis ?. Assume that, at any time, 14 6C is a negligible fraction of the total mass of carbon and that the measured activity of the sample is purely due to 14 6C. Also assume that the ratio of mass of 14 6C to total carbon mass in the atmosphere (the source of the carbon in the sample) is the same at present and on the day when the number of 14 6C atoms in the sample was set.
Express your answer in terms of the mass ma of a 14 6C atom, mc, A, r, and ?.
t =
An artifact is found in a desert cave. The anthropologists who found this artifact would like to know its age. They find that the present activity of the artifact is 9.25 decays/s and that the mass of carbon in the artifact is 0.100 kg. To find the age of the artifact, they will need to use the following constants:
r=1.2
The decay constant λ, we can substitute them into the equation along with the mass of a 14 6C atom (ma) The value of t = -(mc/λ) * ln(9.25 * ma / (λ * r * mc))
To find the age of the artifact, we can use the equation for the decay of radioactive isotopes:
A = A0 * e^(-λt)
where A is the activity of the sample at the present time, A0 is the initial activity (when the artifact was created), λ is the decay constant, and t is the age of the artifact.
Given that the present activity of the artifact is 9.25 decays/s, we can substitute A with 9.25 in the equation. However, we need to express the decay constant in terms of the ratio of the mass of 14 6C to the total mass of carbon in the atmosphere (r) and the mass (ma) of a 14 6C atom.
The total mass of carbon in the artifact (mc) is given as 0.100 kg, and the ratio of 14 6C to total carbon in the atmosphere (r) is given as 1.2.
Let's assume the number of 14 6C atoms in the artifact when it was created was N0. Since the ratio of the mass of 14 6C to total carbon in the atmosphere is the same at present and when the artifact was created, we have:
(ma * N0) / mc = r
Solving for N0, we get:
N0 = (r * mc) / ma
Now we can rewrite the decay equation as:
A = A0 * e^(-(λ/mc) * t)
Substituting A0 with λ * N0, we have:
9.25 = (λ * N0) * e^(-(λ/mc) * t)
Substituting N0 with (r * mc) / ma, we get:
9.25 = (λ * (r * mc) / ma) * e^(-(λ/mc) * t)
Simplifying the equation, we find:
t = -(mc/λ) * ln(9.25 * ma / (λ * r * mc))
Given the values of mc = 0.100 kg, r = 1.2, and the decay constant λ, you can substitute them into the equation along with the mass of a 14 6C atom (ma) to find the age of the artifact (t).
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If you are inside a car and the car is struck by lightning, it is best to stay inside because the electric field inside the car is ________?
Answer:
Get out if the car
Explanation:
Get out of the car because the car could explode by over eclectic power
get out of the car as fast as possible
I will mark as brainlest
Answer:
Is this science you are talking about
Explanation:
a boy whose mass is 40kg runs up a flight of 30 step each 150 mm in 60 second find the averse power develop expansion explain the anomalous of two of water
The average power developed by the boy during the climb is approximately 29.4 W.
What is power?In physics, the amount of energy transferred or converted per unit time is called power.
total height = number of steps x height of each step
total height = 30 x 0.15 m = 4.5 m
Given, time = 60 s
As power = work done / time
work done = force x distance
force = mass x gravity
mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).
force = 40 kg x 9.81 m/s² = 392.4 N
The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m
work done = force x distance
work done = 392.4 N x 4.5 m = 1765.8 J
power = work done / time
power = 1765.8 J / 60 s
power ≈ 29.4 W
Therefore, the average power developed by the boy during the climb is approximately 29.4 W.
As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.
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From the simulation and the readings that you may have recorded, what do you observe about the relation between period and frequency?
Answer: The speed of the wave appears to be constant. This is because the speed of sound depends only on the properties of the medium, and the medium is the same.
Explanation: The answer is from edmentum. Just letting you know on what not to copy and paste. Change it up.
Suma is driving EAST at 50km/hr
what is sumas speed in m/s
a)180m/s
b) 13.9 m/s
c) 18 m/s
d) 1.39
Answer:
lol b b b b b and b
Explanation:
duuuh its b
a long, straight wire carries a current of 8.60 a. an electron is traveling in the vicinity of the wire. at the instant when the electron is 4.50 cm from the wire and traveling at a speed of 6.00 * 104 m>s directly toward the wire, what are the magnitude and direction (relative to the direction of the current) of the force that the magnetic field of the current exerts on the electron?
The magnitude and direction of the force that the magnetic field of the current exerts on the electron in a a long, straight wire is 1.96 x 10⁻¹⁸ N and direction of the force is opposite to the direction of the current.
The magnetic field of the current exerts a force on the electron of magnitude 6.072 x 10⁻¹³ N in a direction that is opposite to the direction of the current.
where
Current, I = 8.60 A
Distance of electron from wire, r = 4.50 cm = 0.045 m
Velocity of electron, v = 6.00 x 10^4 m/s
The force on the electron due to magnetic field of current-carrying wire is given by:
F = (μ * I * q) / (2 * π * r)
where μ is the magnetic permeability of free space and is equal to 4π x 10⁻⁷ Tm/A,
q is the charge of electron and is equal to -1.6 x 10⁻¹⁹ C, and
r is the distance between the electron and the wire.
Substituting the values, we get:
F = (4π x 10⁻⁷ Tm/A) * (8.60 A) * (-1.6 x 10⁻¹⁹ C) / (2 * π * 0.045 m)
F = -1.96 x 10⁻¹⁸ N.
The negative sign indicates that the direction of force is opposite to the direction of the current.
So, the magnitude of the force exerted by the magnetic field on the electron is 1.96 x 10⁻¹⁸ N, and the direction of the force is opposite to the direction of the current.
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The magnitude of f is 232 newtons and it points at 184o measured counterclockwise from the positive x-axis. what is the y component (in newtons) of f?
By the vector, the force in the y component is -16.18 newtons.
We need to know about vectors to solve this problem. Vector has magnitude and also direction. Force is included in the vector. It can be written as
F = Fx i + Fy j + Fz k
where s is displacement, Fx is force on x-axis, Fy is displacement on y-axis and Fz is displacement on z-axis.
From the question above, we know that
|F| = 232 N
θ = 184⁰
The force on y-axis is
Fy = |F| . sin(θ)
Fy = 232 . sin(184)
Fy = -16.18 newtons
The negative force is caused by the direction of the force.
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A motorcycle skids to a stop on a road.
What is the equal and opposite force for the force of the motorcycle's friction pushing on the road as
described by Newton's third law?
Choose 1 answer:
Normal force of the road pushing up on the motorcycle
B
Earth's force of gravity pulling down on the motorcycle
Friction of the road on the motorcycle in the opposite direction
D
Motorcycle's force of gravity pulling up on the Earth
Answer:
Friction of the road on the motorcycle in the opposite direction
Explanation:
khan academy
What is the velocity of a wave with a frequency of 300 Hz and a wavelength of 0.45 m?
Answer:
velocity= 135m/s
Explanation:
velocity = 300×0.45
= 135m/s²
Which layer of earth is a solid rock?
Answer:
Crust
Explanation: