A grindstone in the shape of a solid disc has a diameter of .52 m in a mass of 50 kg is rotating at 1000 revolutions per minute you press an ax against the rim with a normal force of 160 N assuming it coefficient of friction of .8 how long does it take for the grindstone to come to rest

Answers

Answer 1

A negative sign shows that grindstone has circled clockwise to the way in which it first did. But, the right amount of time, 5.13 secs, is all that matters. Thus the time it takes for the pulverizer to take a step is 5.13 secs.

How do you calculate the friction coefficient?

The resistance frictional force (Fr) divided by normal and perpendicular pressure (N) pushing two objects together yields the friction coefficient (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.The duration is given by t = / 0 ≈ -537.04 rad /104.72 rad/s ≈ -5.13 s.

In Grindstone, how so many levels are there?

Over 250 challenging levels of challenging riddles and perils must be cleared in order to climb the mountain in the hope of accumulating enough grindstones to send your family on a much-needed holiday. Publisher-provided software description.

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Related Questions

Assume you are driving a car at a constant speed of 78.0 km/h. Suddenly you see a deer standing on the highway and you must put on the brakes. Your reaction time (time elapsed between the moment you see the deer and your foot hitting the brakes) is 0.130 sec. The brakes provide an acceleration with a magnitude of 4.6 m/s2, and a direction opposite the initial velocity.
A) Find the distance (in m) the car travels (at 78.0 km/h) during your reaction time.
B) Calculate the total distance (in m) traveled by the car before stopping.

Answers

(a) The distance  the car travels during your reaction time is 2.83 m.

(b) The total distance traveled by the car before stopping is 97.8 m

What is the distance travelled?

To find the distance traveled during the reaction time, we need to find the velocity after the reaction time and then use it to find the distance traveled.

78 km/h = 78,000 m/h ÷ 3600 s/h = 21.67 m/s

After the reaction time, the velocity is equal to the initial velocity plus the acceleration during the reaction time:

v = v₀ + at

v = 21.67 m/s - (4.6 m/s²)(0.130 s)

v = 21.67 m/s - 0.599 m/s

Finally, the distance traveled during the reaction time is given by:

d = v₀t  + ¹/₂at²

d  = 21.67  x 0.130 s    +    ¹/₂(-4.6) x (0.130)²

d = 2.83 m

B) To find the total distance traveled before stopping, we need to find the time it takes for the velocity to reach 0.

The velocity after the reaction time is equal to 21.67 m/s - 0.599 m/s = 21.07 m/s.

Using the equation v = v₀ + at, we can find the time it takes to come to a stop:

t = -v₀ / a

t = -21.07 / -4.6

t = 4.58 s

The total distance traveled can be found using the equation:

d =  v₀t  + ¹/₂at²

d  = 21.67 x 4.58  + ¹/₂(-4.6) x 4.58

d = 97.8 m

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I have a material thats 65 cubic feet totaling 40000 cubic yards. How many dump trucks will it take to haul this material?

Answers

It will take about 2,500 dump trucks to haul the material. Assuming the capacity of the dump truck is 16 cubic yards.

Note: A standard dump truck is between 10 -16 cubic yards.

1 cubic yard = 27 cubic feet.

from the question:

40,000 cubic yards= 65 cubic feet

hence,

Assuming the dump truck capacity is 16 cubic yards

Then,

number of dump trucks = 40,000 cubic yards/16 cubic yards

                                      =2,500

Therefore a dump truck of 16 cubic yards capacity, will need about 2,500 dump trucks to haul the material totaling 40,000 cubic yards.

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the mass of a brick is 4 kg, find the mass of water displaced by it when completely immersed in water.​

Answers

Answer:

The correct answer is = 1.6

Explanation:

Density of water = 1000kg/m³ = d₁

Mass of brick = 4kg = m

Density of brick = 2.5 g/cm³ = 2.5 × 1000 =2500 kg/m³ = d₂

Volume of brick = m/d₂ = 4/2500 =16/10000 = 0.0016 L = v

Buoyant Force = v × d₁ × g          (g= acceleration due to gravity =9.8m/s²)

= 0.0016 × 1000 × 9.8 = 15.68 Newtons

By the Archimedes' Principle, the buoyant force is equal to the weight of the liquid displaced by an object.

Weight of the water displaced=Buoyant Force

=Mass of water displaced × g,

as weight = mass × acceleration due to gravity

15.68= mass of brick × 9.8

15.68/9.8 =Mass of water displaced

1.6 kg = Mass of water displaced

What type of electric current does a power plant generate for use in your home?
А. direct
B. alternating
C. repeating
D. straight​

Answers

Answer:

B........................

!! How much voltage is needed to generate a current of 20 Amps if a line has a resistance of 10 ohms ? How much power does the appliance from question number one give off ? If the appliance runs for 3 minutes , how much energy is used ? Please help me

Answers

Answer:

Power = 4000watts

Energy = 22.22Joules

Explanation:

Power = I²R

I is the current

R is the resistance

t is the time

Given the following

I = 20Amps

R = 10ohms

t = 3miuntes = 180secs

Substitute

P = 20²*10

P = 400*10

P = 4000Watts

Hence the amount of power used is 4000Watts

Energy used = Power/time

Energy used= 4000/180

Energy used = 22.22Joules

Nowton's third law refers to 'action reaction forces*. These forces are
always:

Answers

equal in magnitude but opposite in direction

How much heat has to be added to 1 gallon of water to raise the temperature from
68F to 40C?

Answers

Answer:

The heat needed to raise the temperature of 1 gallon of water from 68°F to 40°C is approximately 28,265 Joules.

Explanation:

A 500 g squirrel with a surface area of 895 cm2 falls from a 5.6-m tree to the ground. Estimate its terminal velocity. (Use the drag coefficient for a horizontal skydiver. Assume that the squirrel can be
approximated as a rectanglar prism with cross-sectional area of width 11.3 cm and length 22.6 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. Give the squirrel's
terminal velocity, not it's velocity as it hits the ground.)
x m/s
What will be the velocity of a 50.0 kg person hitting the ground, assuming no drag contribution in such a short distance?
x m/s

Answers

8.3 m/s is the terminal velocity of the squirrel can be calculated using the equation for terminal velocity and 10.8 m/s is the velocity of a 50.0 kg person hitting the ground.

What is velocity?
Velocity is a measure of the speed of an object's motion in a particular direction. It is a vector quantity, meaning it has both magnitude and direction. Velocity is usually measured in meters per second (m/s).

The terminal velocity of the squirrel can be calculated using the equation for terminal velocity of an object in a fluid, which is given by Vt = (2×m×g)/(ρ×Cd×A). Here, m is the mass of the object, g is the acceleration due to gravity, ρ is the density of the fluid, Cd is the drag coefficient, and A is the reference area of the object. The drag coefficient for a horizontal skydiver is 0.8, and the density of air is 1.225 kg/m^3. Therefore, the terminal velocity of the squirrel can be calculated as Vt = (2×500×9.8)/(1.225×0.8×895) = 8.3 m/s.

The velocity of a 50.0 kg person hitting the ground can be calculated using the equation for the velocity at the end of a fall, which is given by Vf = sqrt(2×g×h). Here, g is the acceleration due to gravity and h is the height of the fall. Therefore, the velocity of the person hitting the ground can be calculated as Vf = sqrt(2×9.8×5.6) = 10.8 m/s.

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calculate power disspated by the element of an electric fire (heater) of resistance 30 ohms when a
current of 10 amps flows in it. if is on for 30 hours in a week determine the energy used. determine the weekly cost of energy if eletricity costs K 13 per unit​

Answers

Answer:

Weekly cost = K 8,190

Explanation:

Given the following data;

Resistance, R = 30 Ohms

Current, I = 10 Amps

Time, t = 30 hours

Cost = K13

I. To find the power dissipated;

Power = current² * resistance

Power = 10² * 30

Power = 100 * 30

Power = 3000 Watts

II. To find the energy consumption;

Energy = power * time

Energy = 3000 * 30

Energy = 90,000 Watt-hour = 90 KWh (1 Kilowatts is equal to 1000 watts).

III. To find the weekly cost;

Daily cost = Energy consumption * cost

Daily cost = 90 * 13

Daily cost = K 1170

Therefore, weekly cost = 1170 * 7

Weekly cost = K 8,190

The temperature of a body is from 200 to 300C.The change of temp at absolute scale is

Answers

Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done?

Answers

The intrepid hero has done 2.332 x Joules of work in pushing the crate.

To ascertain the work done by the traveler, we first need to find the power he applied on the case. As per Newton's subsequent regulation, force is equivalent to mass times speed increase, so the power applied by the traveler on the container is:

Force = mass x speed increase = 220 kg x 2  = 440 N

Then, we really want to work out the distance the case was moved. The pilgrim pushed the box a distance of 5.3 km, or 5,300 m.

At long last, we can compute the work done by the pioneer utilizing the equation:

Work = force x distance = 440 N x 5,300 m = 2.332 x 10^6 Joules

Thusly, the valiant legend has done 2.332 x  Joules of work in pushing the case.

The space pilgrim takes care of business on the case by applying a power that makes it speed up. The work done is equivalent to the power duplicated by the distance over which the power is applied. Involving the recipe for force, F=ma, and the given qualities for mass and speed increase, we can ascertain the power applied. Then, at that point, involving the recipe for work, W=Fd, and the given distance, we can ascertain the work done. The work done by the adventurer is 2.332 x  J.

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A soccer ball is kicked with an initial horizontal velocity of 11 m/s and an initial vertical velocity of 17 m/s.
1)what is the initial speed of the ball?20.25 m/s
2)what is the initial angle 0 of the ball with respect to the ground? 57.09 degrees
3)what is the maximum height the ball goes above the ground? 14.74m
I need help with 4,5 and 6
4)How far from where it was kicked will the ball land?
5) what is the speed of the ball 2.5 second after it was kicked?
6)how high above the ground is the ball 2.5 seconds after it is kicked?

Answers

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

4) To calculate the distance from where the ball was kicked, we need to find the time it takes to reach the ground. We can use the fact that the vertical displacement of the ball is zero at the highest point. Using the formula vf = vi + at, the time it takes to reach maximum height is t = vf / g where g is the acceleration due to gravity which is -9.8 m/s² since it is downward and vf is the final velocity which is 0 because the ball comes to rest at the highest point. t = 17 / 9.8 = 1.73 s. This means the total time for the ball to hit the ground is 2 x 1.73 = 3.46 s. Using the formula for horizontal distance traveled d = vt, we get d = 11 x 3.46 = 38.06 m. So, the distance from where the ball was kicked will be 38.06 meters.5) To calculate the speed of the ball 2.5 seconds after it was kicked, we need to find the horizontal and vertical components of the velocity of the ball at 2.5 seconds. The horizontal component is constant, so it will still be 11 m/s. To find the vertical component, we use the formula vf = vi + at where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. vf = 17 + (-9.8 x 2.5) = -7.5 m/s. Since the ball is moving downward, the velocity is negative. Therefore, the speed of the ball 2.5 seconds after it was kicked is sqrt(11² + (-7.5)²) = 13.82 m/s.6) To calculate how high above the ground is the ball 2.5 seconds after it is kicked, we use the formula for the displacement of an object in the vertical direction y = vi*t + (1/2)*a*t² where vi is initial velocity, a is acceleration due to gravity which is -9.8 m/s² and t is the time which is 2.5 seconds. y = 17*2.5 + (1/2)*(-9.8)*(2.5)² = 21.88 m. So, the ball is 21.88 m above the ground 2.5 seconds after it is kicked.

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A stone is thrown vertically upward with the velocity of 25 m/s. How long day
it take to reach the maximum height? Also calculate the height​

Answers

Answer:

The stone takes 2.55 sec to reach a maximum height of 31.89 m

Explanation:

Vertical Motion

When an object is thrown vertically up with a speed vo, it loses speed because of the effect of the gravity and gains height until the speed is eventually zero. The height attained at that time is called maximum height, and can be calculated as follows:

\(\displaystyle h_m=\frac{v_o^2}{2g}\)

Since vo=25 m/s

\(\displaystyle h_m=\frac{25^2}{2\cdot 9.8}=31.89\ m\)

Also, the time taken to reach the maximum height is calculated by:

\(\displaystyle t_m=\frac{v_o}{g}\)

\(\displaystyle t_m=\frac{25}{9.8}=2.55\ s\)

The stone takes 2.55 sec to reach a maximum height of 31.89 m

Which of the following diagrams involves an upright image?

A convex lens is shown centered at 7 on a ruler that goes from 0 to 14 centimeters. The object is located at 6, and the focal points are at 5.5 and 8.5. The three light rays are shown to form the image located at 4.
A concave mirror is shown with curvature positioned at 8 on a ruler that goes from 0 to 14 centimeters. The object is located at 5, and the focal point is located at 6.5. Two light rays are shown to form the image located at 5.
A convex lens is shown centered at 7 on a ruler that goes from 0 to 14 centimeters. The object is located at 4, and the focal points are at 5.5 and 8.5. The three light rays are shown to form the image located at 10.

Answers

The only diagram that features an upright image is the convex lens one. The image is reversed in all of the other diagrams.

A convex lens is what?

The convex lens, which is relatively thick in the middle and thin at the lower and upper edges, is a lens that converges light rays that travel parallel to its principal axis. Instead of curving inside, the edges are curled outward.

What purposes serve concave lenses?

For the nearsighted, convex lenses are better than concave ones. Nearsightedness is treated with glasses that have concave lenses. Nearsighted individuals have an abnormally lengthy distance between their eye's lens and retina, which prevents them from seeing distant objects.

What distinguishes a convex lens from a concave lens?

A concave lens or diverging lens diverges the light rays, whereas a convex lens or converging lens concentrates the light rays to a particular point. Based on the laws of refraction, a lens is a transparent substance.

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Which of the following diagrams involves an upright image? A convex lens is shown centered at 7 on a

Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k

Answers

The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

To solve this problem

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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Which statement explains why a rubber band analogy is not a perfect comparison for bonds in a substance when considering phase changes?(1 point)

For a phase change from solid to liquid, the bonds break completely and particles can move independently of each other.
For a phase change from solid to liquid, the bonds break completely and particles can move independently of each other.

For a phase change from solid to liquid, the bonds do not break completely and particles can still slide past each other.
For a phase change from solid to liquid, the bonds do not break completely and particles can still slide past each other.

For a phase change from liquid to gas, the bonds break completely and particles can move independently of each other.
For a phase change from liquid to gas, the bonds break completely and particles can move independently of each other.

For a phase change from liquid to gas, the bonds do not break completely and particles can still slide past each other.

Answers

Answer:

For a phase change from solid to liquid, the bonds do not break completely and the particles can still slide past each other

Explanation:

I took the quick check

What are some uses of thermal energy in everyday life?

Choose all that apply.


moving objects

cooking food

heating water

making light bulbs work

Answers

Answer:

b) cooking food

c) heating water

Explanation:

cooking and heating use thermal energy to transfer heat from the source to another object, in the examples provided; the food and the water. on the other hand, moving objects uses kinetic energy and lightbulbs utilize electrical energy.

Answer:

cooking food

heating water

i think making a light bulb work

Explanation:

Electric field lines are used to represent the vector electric field around point charges and charged objects. Which of the following statements are true about electric field lines. Select ALL that apply.

Select all that apply
A. Electric field lines cannot cross.
B. Lines of electric field only originate from positive charges.
C. Field lines point in the direction of the force the electric field creates on an electron.
D. The strength of the electric field is greater in regions where the field lines are closer together.
E. In an electric-field-line drawing with many point charges, the number of field lines originating or terminating on each charge is proportional to the charge. That is, bigger charges have proportionally more field lines. F. The true strength of an electric field at any point can be determined from an electric field representation.​

Answers

Electric field lines are a powerful tool to understand and visualize electric fields. They help to represent the direction and magnitude of the electric field at various points around a charged object.

The following statements are true about electric field lines:

A. Electric field lines cannot cross: This is because at the point where two field lines cross, there would be two directions for the electric field, which is impossible. Hence, the lines do not cross, and this is one of the fundamental characteristics of electric field lines.

B. Lines of electric field only originate from positive charges: Electric field lines originate from positive charges and terminate at negative charges. This is because positive charges repel positive charges and attract negative charges. Therefore, the electric field lines originating from a positive charge terminate at a negative charge.

C. Field lines point in the direction of the force the electric field creates on an electron: Electric field lines point in the direction of the force that would be experienced by a positive charge placed at any point in the field. Electrons, being negatively charged, would experience a force in the opposite direction to the electric field.

D. The strength of the electric field is greater in regions where the field lines are closer together: The density of field lines indicates the strength of the electric field. The closer the lines are, the stronger the field at that point.

E. In an electric-field-line drawing with many point charges, the number of field lines originating or terminating on each charge is proportional to the charge. That is, bigger charges have proportionally more field lines: The number of field lines originating or terminating on each charge is directly proportional to the magnitude of the charge.

F. The true strength of an electric field at any point can be determined from an electric field representation: The strength of the electric field at a point can be determined by the density of electric field lines at that point. However, the actual strength of the field would require quantitative measurements using instruments such as a voltmeter or an electrometer.

In conclusion, electric field lines are an essential tool in understanding the behavior of electric fields. They provide a visual representation of the electric field, its direction, and its strength at various points in space.

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Some students are jumping rope which travels at a speed of 2 m/s. The distance from the top of the swing to the bottom is 2 m. What is the frequency l of the rope

Answers

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Need help with this assignment please

Need help with this assignment please

Answers

Torque is a measure of the turning force applied to an object about a rotational axis. It is calculated as the product of the force applied to the object and the distance from the axis of rotation at which the force is applied.

How to explain the information

Use the equation slope = mod to calculate the unknown mass (mo) for parcels A and C, setting d = 1.0 m, and parcels G and H, setting d = 1.5 m.

Record all data, tables, and four graphs for analysis.

The experiment demonstrates the application of torque in determining unknown masses and provides valuable insights into the concept of torque in physics.

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An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s2. The takeoff speed for this plane will be 65 m/s. All airplanes will start from rest(0m/s). Assuming this minimum acceleration, what is the minimum allowed length for the runway for take off?

Answers

Answer:

x = 704 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f} ^{2} =v_{o} ^{2} +2*a*x\)

where:

Vf = final velocity = 65 [m/s]

Vo = initial velocity = 0 (starts from rest)

a = acceleration = 3 [m/s²]

x = distance [m]

Now replacing we have:

65² = 0 + 2*3*x

4225 = 6*x

x = 704 [m]

Can someone please help me on this, ty!!

Can someone please help me on this, ty!!

Answers

Answer:

the package has probably not arrived due to  mail overloads and packing shortage . mail may be delayed because of external circumstances that change transit times. You can call your local post office to see if your package is there, or wait for your tracking to update to delivered. It will not update to delivered until your mailman actually scans it at your mailbox or door.

Explanation:

A liquid can easily change its shape but a solid cannot because
a. the density of liquid is smaller than that of solid.
b. the forces between the molecules is strong in solid than in liquids.
c. the atoms combine to form bigger molecules in a solid.
d. the average separation between the molecules is larger in solids.​

Answers

Answer:

Explanation:

A liquid can easily change its shape but a solid cannot because:

b. The forces between the molecules is strong in solid than in liquids.

A liquid can easily change its shape but a solid cannot because the forces between the molecules is strong in solid than in liquids. Thus Option b is the answer.

There is some kinds of forces that holds the molecules each other like for example in hydrogen chloride [ HCl ] the relatively positive hydrogen of one molecule is attracted to the negative chlorine of other due to dipole dipole interaction.

Actually structure of any molecule means combination of repulsive and attractive forces which is relatively concerned with charge and electron spin.

Solids have significant intermolecular forces so its difficult to dissociate the bonds and create a new shape , while fluids have insignificant molecular forces due to which its easier to generate new shapes.

So that's why Solids cannot change its shape with that ease as liquids do.

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Help me pls, the lesson is simple machines

Help me pls, the lesson is simple machines

Answers

Answer:

1.pulley,screw,inclined plane

2.using simple machine properly with right way and precautions

Explanation:

3.cuz if they are not used properly they can cause injuries to organs

The first user who answer is correct :)

a single loop of wire with an area of 0.0940 m2 is in a uniform magnetic field that has an initial value of 3.80 t, is perpendicular to the plane of the loop, and is decreasing at a constant rate of 0.190 t/s . for related problem-solving tips and strategies, you may want to view a video tutor solution of emf and current induced in a loop.

Answers

The EMF induced in a single wire loop with an area of 0.0940 m² is in a uniform magnetic field which has an initial value of 3.80 T, is perpendicular to the plane of the loop, and decreases at a constant rate of 0.190 T = 0.34 V. And the current induced in the loop = 0.57 A.

The EMF induced

Induced electromotive force or induced emf is the potential difference at the ends of the coil which will produce an induced electric current.

An induced electric current appears as long as there is a change in magnetic flux.

The equation is:

ε = d∅/dt

We have,

The area of the loop = 0.0940m²

The change in magnetic field with time = (3.80 T - 0.190 T) = 3.61 T

So, the EMF induced:

ε = d∅/dt

=  {(0.0940m²) (3.61)} / 1

= 0.34 V

And the current induced in the loop =

I = ε/R

= 0.34 V / 0.600 Ω

= 0.57 A

The question is incomplete, it should be:

A single loop of wire with an area of 0.0900m2 is in a uniform magnetic field that has an initial value of 3.8 T, is perpendicular to the plane of the loop, and is decreasing at a constant rate of 0.190 T/s.

(a) What emf is induced in this loop?

(b) If the loop has a resistance of 0.600O, find the current induced in the loop.

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Help pleaseee is this correct?​

Help pleaseee is this correct?

Answers

Answer:

Maybe.

Explanation:

An electron and a 0.033 0-kg bullet each have a velocity of magnitude 495 m/s, accurate to within 0.010 0%. Within what lower limit could we determine the position of each object along the direction of the velocity

Answers

Answer:

1.170*10^-3 m

3.23*10^-32 m

Explanation:

To solve this, we apply Heisenberg's uncertainty principle.

the principle states that, "if we know everything about where a particle is located, then we know nothing about its momentum, and vice versa." it also can be interpreted as "if the uncertainty of the position is small, then the uncertainty of the momentum is large, and vice versa"

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

If we make Δx the subject of formula, by rearranging, we have

Δx = h / 4π * m(e).Δv

on substituting the values, we have

for the electron

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 5.67*10^-31

Δx = 1.170*10^-3 m

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.033*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 0.021

Δx = 3.23*10^-32 m

therefore, we can say that the lower limits are 1.170*10^-3 m for the electron and 3.23*10^-32 for the bullet

Mr.lizard limps 40 meters in 8 seconds. What is his speed?

Answers

Mr.Lizard limps 5 meters per sec
So u divid 40/8 which gives u 5

E._____________________

Answers

15-letter words that start with e

electromagnetic

experimentation

electrophoresis

excommunication

extracurricular

ethnomusicology

epichlorohydrin

exemplification

electrodynamics

experimentalism

extralinguistic

electromyograph

electronegative

electrodialysis

ecclesiasticism

encephalography

electrokinetics

electropositive

electroanalysis

enterobacterium

eclaircissement

econometricians

econometrically

ecocatastrophes

ecclesiological

ecclesiologists

echinodermatous

echocardiograms

ecophysiologies

easygoingnesses

egocentricities

eggheadednesses

egregiousnesses

efficaciousness

effortfulnesses

effectualnesses

effectivenesses

egalitarianisms

educationalists

enterobacterial

enterocolitises

enterogastrones

enjoyablenesses

entomologically

entrepreneurial

envenomizations

environmentally

enumerabilities

encephalographs

encephalitogens

encephalopathic

enantiomorphism

enantiomorphous

emulsifications

endoparasitisms

endonucleolytic

endocrinologies

endocrinologist

enfranchisement

electroacoustic

electrification

electrochemical

electroanalyses

electrophoretic

electrophoresed

electrophoreses

electromyograms

electrodialytic

electrodeposits

electrodialyses

electrofishings

elaboratenesses

electrosurgical

electrowinnings

emancipationist

embryologically

employabilities

emotionlessness

extrajudicially

extraordinarily

externalization

extinguishments

extracellularly

exteriorization

externalisation

extensivenesses

extensibilities

extemporisation

extemporization

extendabilities

exquisitenesses

exsanguinations

experimentalist

expensivenesses

expeditiousness

expendabilities

expansivenesses

expressionistic

exponentiations

Expensive hopeeee I helppeddddf

In machines with low efficiency, most of the lost energy is turned into?

a. Light
b. Sound
c. Power
d. Heat

Answers

Answer:

Option (C)

Explanation:

All electric machines are not ideal, therefore they have some losses due to which efficiency being less than 100%.

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