A hawk is flying horizontally at 18.0 m/s in a straight line, 230 m above the ground. A mouse it has been carrying struggles free from its grasp. The hawk continues on its path at the same speed for 2.00 s before attempting to retrieve its prey. To accomplish the retrieval, it dives in a straight line at constant speed and recaptures the mouse 3.00 m above the ground. (a) Assuming no air resistance, find the diving speed (magnitude of the total velocity vector) of the hawk. (b) What angle did the hawk make with the horizontal during its descent? (c) For how long did the mouse "enjoy" free fall?

Answer:75.3 seconds

Explanation:

Using conservation of momentum, the initial momentum of the cannon and the projectile is equal to the final momentum of the cannon and the projectile:

m_cannon * v_cannon = (m_cannon + m_projectile) * v_final

where m_cannon is the mass of the cannon, v_cannon is the initial velocity of the cannon, m_projectile is the mass of the projectile, and v_final is the final velocity of the cannon and projectile together.

Substituting the given values gives:

210 kg * 0 m/s - 1 kg * 610 m/s = (210 kg + 1 kg) * v_final

Solving for v_final gives:

v_final = -1.83 m/s

The negative sign indicates that the cannon and projectile are moving in the opposite direction after the firing.

The time required to bring the cannon to rest can be found using the equation:

F_resistive = m_cannon * a

where F_resistive is the resisting force, m_cannon is the mass of the cannon, and a is the acceleration of the cannon.

Substituting the given values gives:

1,700 N = 210 kg * a

Solving for a gives:

a = 8.10 m/s^2

The time required to bring the cannon to rest can be found using the kinematic equation:

v_final = v_initial + a * t

where v_initial is the initial velocity of the cannon, which is equal to the muzzle velocity of the projectile, and v_final is zero. Solving for t gives:

t = -v_initial / a

Substituting the given values gives:

t = -610 m/s / 8.10 m/s^2 = 75.3 s

Therefore, the time required to bring the cannon to rest is 75.3 seconds.

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The height of the 4 kilograms book with a gravitational potential energy of 98 Joules is approximately 2.5 meters.

Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.

It is expressed as;

U = m × g × h

Given that:

Gravitational potential energy of the book U = 98 Joules

Mass of the book m = 4 kilograms

Acceleration due to gravity g = 9.8 m/s²

Height h = ?

Plug these values into the above formula and solve for height.

U = m × g × h

h = U / ( m × g )

h = 98  / ( 4 × 9.8 )

h = 98/39.2

h = 2.5 meters

Therefore, its height is 2.5 meters.

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Answer: a

Explanation:

Answer: .36 m

Explanation:

The distance that the force is exerted over is equal to 0.3625 meter.

Given the following data:

To calculate the distance that the force is exerted over, we would apply the law of conservation of energy.

According to the law of conservation of energy, the work done by an external force equals the change in kinetic energy for the motion of the tennis ball hit by the racket.

Mathematically, this is given by this expression:

\(Work\;done = \Delta K.E = Fd\)

Where:

Substituting the given parameters into the formula, we have;

\(29 = 80 \times d\\\\d=\frac{29}{80}\)

Distance, d = 0.3625 meter.

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An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.

Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.

Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.

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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.

Given  the Ryerson Campus is at a scale of  1:1000

Then the photographic scale (s) = 1:3000

The focal length of camera (f) = 152mm = 0152m

The format is (k) =  230 x 230mm = 0.23m

the photographic scale (s) = F/H where H is the image height

1/3000 = 0.152 /H Then H = 456m

Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s

(1-0.6) x 0.23/1/3000 = 276mm

Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m

Hence the central points are plotted within the area range in 276m x 483m magnitude.

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A 100kg man jumping off a 10m high building in 10 seconds has a power of 1000 Watts.

When the man jumps off the building, he initially possesses potential energy due to his position above the ground. As he falls, this potential energy is converted into kinetic energy, which is the energy of motion. The work done by the man is equal to the change in potential energy.

The potential energy (PE) can be calculated using the formula PE = mgh, where m represents the mass, g represents the acceleration due to gravity, and h represents the height. In this case, the mass is given as 100kg, the acceleration due to gravity is 10 m/s², and the height is 10m.

Substituting these values into the formula, we get PE = 100kg * 10m/s² * 10m = 10,000 Joules. This means that the work done by the man while jumping off the building is 10,000 Joules.

Power is defined as the rate at which work is done. In this scenario, we divide the work (10,000 Joules) by the time taken (10 seconds) to obtain the power. Therefore, Power = Work/Time = 10,000 J / 10 s = 1000 Watts.

Hence, the power of the 100kg man who jumps off the 10m high building in 10 seconds is calculated to be 1000 Watts. Power represents the rate at which energy is transferred or work is done, indicating how quickly the man transformed potential energy into kinetic energy during the jump.

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Answer:

the vibration of the glass tube creating sound waves within itself.  reason is the rising pitch is that the liquid rise shortens the length of the vibrating area within the tube.

Explanation:

Answer:

\(24.81\ \text{rad/s}^2\)

Explanation:

M = Mass of cylinder = 4.31 kg

R = Radius of cylinder = 0.294 m

m = Mass of bucket = 6.27 kg

g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)

\(\alpha\) = Angular acceleration

a = Acceleration = \(\alpha R\)

I = Moment of inertia of cylinder = \(\dfrac{MR^2}{2}\)

The force balance of the system is

\(mg-T=ma\\\Rightarrow T=m(g-a)\)

For the disk

\(TR=I\alpha\\\Rightarrow m(g-a)R=\dfrac{1}{2}MR^2\alpha\\\Rightarrow \alpha=\dfrac{g}{\dfrac{MR}{2m}+R}\\\Rightarrow \alpha=\dfrac{9.8}{\dfrac{4.31\times 0.294}{2\times 6.27}+0.294}\\\Rightarrow \alpha=24.81\ \text{rad/s}^2\)

The angular acceleration of the pulley is \(24.81\ \text{rad/s}^2\).

The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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Calculate the horizontal component of the velocity. The horizontal component of the velocity is given by:

v_x = v * cos(theta)

where v is the original speed of the arrow and theta is the angle of projection.In this case, v = 2 m/s and theta is unknown. Solving for theta, we get:

theta = arccos(v_x / v)

theta = arccos(2 / 2) = 45 degrees

Calculate the vertical component of the velocity. The vertical component of the velocity is given by:

v_y = v * sin(theta)

In this case, v = 2 m/s and theta = 45 degrees. Solving for v_y, we get:

v_y = 2 * sin(45 degrees) = 1.414 m/s

Calculate the time of flight. The time of flight is given by:

t = 2 * v_y / g

In this case, v_y = 1.414 m/s and g = 10 m/s^2. Solving for t, we get:

t = 2 * 1.414 / 10 = 0.283 seconds

Calculate the height of the arrow. The height of the arrow is given by:

y = v_y * t - 0.5 * g * t^2

In this case, v_y = 1.414 m/s, t = 0.283 seconds, and g = 10 m/s^2. Solving for y, we get:

y = 1.414 * 0.283 - 0.5 * 10 * 0.283^2 = 0.303 meters

Therefore, the angle of projection is 45 degrees and the height of the arrow is 0.303 meters.

The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

In the beginning, I was not familiar to assess assessments of the other students. Ifelt a little bit weird that is it possible to check assignments while having an instructor.I was also a bit frustrated, to be honest, that why do we have to assess thoseassessments. It was kind of extra burden for me. But after few weeks assessingmore assignments, my feeling had changed because I was learning lots of thingsthat were changing my perspectives. I was gaining extra knowledge from my peersin the form of assessments. Yes, I am comfortable with assessing assessments,because I got to learn many vocabularies and making structures of the sentencecorrectly by improving grammatically as I am not a native English speaker. Thus, inthis way, I was learning something new in each and every assessment.

Answer:

below

Explanation:

You will need this equation:

F = G m1 m2 / r^2     G = gravitational constant = 6.6743 x10^-11 m^3/(kg s^2)

Plugging in the values

     6.6743 x 10^-11   *   3.3 * 3.3 / ( .33^2) = 6.67 x 10 ^-9 N

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Answer:

The average energy delivered to a surface is 19.116 W/m².

Explanation:

Given;

maximum electric field, E₀ = 120 v/m

The average energy delivered by the wave to a surface is given by

\(I_{avg} = \frac{c\epsilon_ o E_o^2}{2}\)

where;

c is the speed of light, = 3 x 10⁸ m/s

ε₀ is the permittivity of free space = 8.85 x 10⁻¹² c²/Nm²

\(I_{avg} = \frac{c\epsilon_ o E_o^2}{2} \\\\I_{avg} = \frac{(3*10^8)(8.85*10^{-12})( 120)^2}{2}\\\\ I_{avg} =19.116 \ W/m^2\)

Therefore, the average energy delivered to a surface is 19.116 W/m².

The overall momentum of the ball is 100kgm/s.

The impact on the induced velocity in the propeller plane is most pronounced close to the blade tips. The original blade element momentum theory does not account for the effect of vortices emitted from the blade tips into the slip stream on the induced velocity field. The induced velocity dispersion along the propeller is greatly influenced by these tip vortices, which produce a number of helical structures in the wake. It uses a tip-loss or correction factor, F, to make up for this shortcoming.

\(P= Mv\\\\P=25 * 4\\\\P=100Kgm/s\)

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Based on the image provided and the location of deposition and erosion, it seems that the longshore current is moving towards the right.

Based on the image provided, it appears that the longshore current is traveling towards the right. This can be determined by looking at where deposition and erosion are occurring. Deposition is happening on the right side of the image, where sand is building up and forming a beach. Erosion, on the other hand, is happening on the left side of the image, where the waves are breaking against the cliff face and wearing it away. Longshore currents are generated by waves hitting the shore at an angle, causing the water to move parallel to the shore. In this case, the waves are coming in from the top left of the image and hitting the shore at an angle, which creates a longshore current that moves towards the right. As the water moves along the shore, it picks up sand and sediment and carries it with it. This sand is then deposited on the right side of the image, where the water slows down and loses energy. It's important to note that longshore currents can change direction depending on the direction of the incoming waves and the shape of the shoreline. But based on the image provided and the location of deposition and erosion, it seems that the longshore current is moving towards the right.

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The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer: The half-life is the amount of time it takes for a given isotope to lose half of its radioactivity. If a radioisotope has a half-life of 14 days, half of its atoms will have decayed within 14 days. In 14 more days, half of that remaining half will decay, and so on.

The left hemisphere of the brain is primarily needed in scenario, Solving a complex mathematical problem. Option a is correct.

The brain is divided into two hemispheres, left and right, and they are specialized for different cognitive functions. The left hemisphere of the brain is primarily responsible for language processing, logical reasoning, and analytical thinking. Solving a complex mathematical problem involves logical reasoning, analytical thinking, and the use of language, all of which are primarily controlled by the left hemisphere of the brain.

Mathematical problems often require precise calculations, sequencing of steps, and the use of symbols and formulas, all of which require a strong left-brain function. In contrast, appreciating a work of art, listening to music, and recognizing facial expressions are all more complex perceptual and emotional processes that involve the right hemisphere of the brain. Option a is correct.

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--The complete question is, In which of the following scenarios is the left hemisphere of the brain primarily needed?

a. Solving a complex mathematical problem.

b. Appreciating a work of art

c. Listening to music

d. Recognizing facial expressions.--

Answer:

Newton's theory because he suggested that the greater the distance between objects, the weaker the pull of gravity.

Answer: The answer is Newton’s theory because he suggested that the greater the distance between objects, the weaker the pull of gravity

Explanation: Just took the test i hope this help you enjoy :D

Explanation:

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The value of spring constant (k) is 25 N/m.

Conservation of energy, potential energy of a stretched spring, gravitational potential energy, frequency of oscillation in a spring coupled to a mass, and variation of acceleration due to gravity with altitude are the principles necessary to answer the given problem.

To begin, use energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.

Formula apply

U=mgh

U=1/2kx^2

putting the value of K ,x ,mass and g then

k is 25N/m

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Answer:

distance means the length of any thing that have one starting point mad ending point

displacement means the short distance that move by an object due to help of any force

Answer:

there is examples and defination for distance and displacement

A photon is a tiny energy packet of electromagnetic radiation, also referred to as a light quantum.

1) Ultraviolet radiation is commonly used in sanitizing hospitals because, viruses, methicillin-resistant Staphylococcus aureus, and vancomycin-resistant enterococci are all susceptible to the germicidal effects of UV-C.

2) According to the photon theory, electrons that have been stimulated return to the ground state to create atomic emission spectra. Light or the photon is the energy that is released when electrons drop to a lower energy level.

3) To characterise the atomic characteristics of light, Albert Einstein used Planck's quantum theory.

Planck's hypothesis is supported by Einstein's demonstration that electromagnetic radiation, such as light, has both wave-like and particle-like properties.

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The distance between the glass to have the given heat loss is 2.54 m.

The given parameters:

The area of the glass window is calculated as follows;

\(A = 0.6 \times 0.9\\\\A = 0.54 \ m^2\)

The distance between the glass is calculated as follows;

\(Q = \frac{KA \Delta T}{\Delta x} \\\\\Delta x = \frac{kA \Delta T}{Q} \\\\\Delta x = \frac{0.8 \times 0.54 \times 24 }{4.09} \\\\\Delta x = 2.54 \ m\)

Thus, the distance between the glass to have the given heat loss is 2.54 m.

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I mean if it will be anything the asnwer would be 23^90'200

B. The resistance R of the circuit is determined as 2.0 ohms.

Ohm's Law states that the current flowing in a circuit is directly proportional to the applied potential difference and inversely proportional to the resistance.

V = IR

R = V/I

The slope of the given graph is the resistance of the circuit.

Choosing point (0 A, 0 V) and (4.5 A, 9 V)

R = ΔV/ΔI

R = (9 - 0 ) / (4.5 - 0)

R = 9/4.5

R = 2.0 ohms

Thus, the resistance R of the circuit is determined as 2.0 ohms.

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The time between when the bat emits the sound and when it hears the echo is 0.05 s

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s

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Answer:

0.0491

Explanation: