A heat pump used to heat a house runs about onethird of the time. The house is losing heat at an average rate of 25,000 kJ/h. If the COP of the heat pump is 2.2, determine the power the heat pump draws (kW) when running.
Answers
A heat pump used to heat a house runs about one third of the time. The house is losing heat at an average rate of 25,000 kJ/h. If the COP of the heat pump is 2.2,the power the heat pump draws when running is approximately 3,156.57 kW.
The coefficient of performance (COP) of a heat pump is defined as the ratio of the heat output to the work input. In this case, the COP is given as 2.2, which means that for every unit of work input, the heat pump produces 2.2 units of heat output.
We know that the house is losing heat at an average rate of 25,000 kJ/h. Since the heat pump runs for one-third of the time, we can calculate the heat produced by the heat pump in one hour.
Heat produced by heat pump = COP * Work input
Heat produced by heat pump = 2.2 * Work input
Since the heat produced by the heat pump is equal to the heat lost by the house, we have:
25,000 kJ/h = 2.2 * Work input
Now, we can solve for the work input:
Work input = 25,000 kJ/h / 2.2
Work input ≈ 11,363.64 kJ/h
To determine the power the heat pump draws when running, we need to convert the work input to kilowatts (kW).
1 kilowatt (kW) = 3.6 megajoules per hour (MJ/h)
Work input (kW) = Work input (kJ/h) / 3.6
Work input (kW) ≈ 11,363.64 kJ/h / 3.6
Work input (kW) ≈ 3,156.57 kW
Therefore, the power the heat pump draws when running is approximately 3,156.57 kW.
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Related Questions
I need help with this ASAP.. please and thank you.. I have to get it done
Answers
wettest: january
how long will it take to go in minutes 150 km traveling at 50km/hr?
Answers
Given:
• Distance = 150 km
,• Speed = 50 km/hr
Let's find the time it will take to cover the distance in minutes.
To find the distance, apply the formula:
\(time=\frac{distance}{speed}\)Thus, we have:
\(\text{time}=\frac{150}{50}=3\text{ hours}\)The time in hours is 3 hours.
To convert the time from hours to minutes, we have:
60 minutes = 1 hour
3 hours = 3 x 60 = 180 minutes
Therefore, it time in minutes is 180 minutes.
ANSWER:
180 minutes
a cannon fires a shell that causes a projectile to move down the barrel at a velocity of 600 m/s. what is the speed of the normal shock proceeding down the barrel in front of the projectile and the pressure and temperature experienced by the front face of the projectile? the undisturbed air in the barrel is at 101 kpa and 300k. how fast would the projectile have to be moving down the barrel if the velocity of the shock ahead of the projectile was 3 times the velocity of the projectile?
Answers
If the velocity of the shock ahead of the projectile was 3 times the velocity of the projectile, we can calculate the velocity of the projectile by dividing the velocity of the shock wave by 3.
The speed of the normal shock proceeding down the barrel in front of the projectile can be determined using the equation for the normal shock wave speed, which is given by the square root of the ratio of specific heat capacities multiplied by the product of the pressure ratio and the temperature ratio.
To find the speed of the normal shock wave, we need to calculate the pressure and temperature ratios.
The pressure ratio is the ratio of the pressure behind the shock wave to the undisturbed pressure. In this case, the undisturbed pressure is given as 101 kPa.
The temperature ratio is the ratio of the temperature behind the shock wave to the undisturbed temperature. The undisturbed temperature is given as 300 K.
Since the problem does not provide any information about the pressure and temperature behind the shock wave, we cannot determine the speed of the normal shock wave in front of the projectile.
Regarding the pressure and temperature experienced by the front face of the projectile, we also do not have enough information to calculate them. Without knowing the specific properties of the projectile and the conditions in the barrel, we cannot determine the pressure and temperature at the front face of the projectile.
If the velocity of the shock ahead of the projectile was 3 times the velocity of the projectile, we can calculate the velocity of the projectile by dividing the velocity of the shock wave by 3.
In conclusion, due to the lack of information, we cannot determine the speed of the normal shock wave, or the pressure and temperature experienced by the front face of the projectile.
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Which one of the 4 answers is it?
Answers
A particle moves along the x-axis so that its acceleration at any time t≥0 is given by a(t)=12t−4. At time t=1, the velocity of the particle is v(1)=7 and its position is x(1)=4.
Answers
Given that a particle moves along the x-axis so that its acceleration at any time t0 is given by a(t) = 12t - 4, At time t = 1, the velocity of the particle is v(1) = 7, and its position is x(1) = 4.
To find the velocity and position of the particle, we need to integrate the acceleration, a(t), and then solve the resulting equations for the constants of integration.
To solve for C, we use the fact that v(1) = 7:v(1) = 6(1)^2 - 4(1) + Cv(1)
= 2 + C
Thus, C is 5. Now, we can write the velocity of the particle as:
v(t) = 6t^2 - 4t + 5
To find the position of the particle, we integrate the velocity.
v(t) = dx(t)/dt ⇒ dx(t)
= v(t)dt∫dx(t)
= ∫v(t)dtx(t)
= ∫(6t^2 - 4t + 5)dt
X(t) = 2t^3 - 2t^2 + 5t + K
where K is the constant of integration. To solve for K, we use the fact that
x(1) = 4:X(1)
= 2(1)^3 - 2(1)^2 + 5(1) + KX(1)
= 5 + K
Thus, K = -1.
Now, we can write the position of the particle as:
X(t) = 2t^3 - 2t^2 + 5t - 1
Hence, the velocity of the particle is v(t) = 6t2 - 4t + 5, and the position of the particle is X(t) = 2t3 - 2t2 + 5t - 1.
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Four different balls with different masses (measured in grams) were dropped from the same height on Earth. Assuming no other forces acted on the balls, match each ball with the gravitational force (measured in newtons) it experienced as it fell.gravitational force = 9.8 m/s2
Answers
We will have the following:
1. 143 g = 0.143 kg:
\(F=(0.143kg)(9.8m/s{}^2)\Rightarrow F=1.4014N\)2. 110 g = 0.110 kg:
\(F=(0.110kg)(9.8m/s^2)\Rightarrow F=1.078N\)3. 410 g = 0.410 kg:
\(F=(0.410kg)(9.8m/s^2)\Rightarrow F=4.018N\)4. 46 g = 0.046 kg:
\(F=(0.046kg)(9.8m/s^2)\Rightarrow F=0.4508N\)From this we can see that the given weights do not correspond to any of the values of column B, since the calculations to obtain the values of column B were done using grams, instead of kg, thus those values do not correspond to the unit of force Newtons.
Apply the Pauli exclusion principle to determine the number of electrons that could occupy the quantum states described by the following.
(a)
n = 4,
ℓ = 1,
mℓ = −1
_____ electrons
(b)
n = 4,
ℓ = 3
____ electrons
Answers
The number of electrons that could occupy the quantum states described by n = 4, ℓ = 1, and mℓ = −1 is 2.
(a) The quantum numbers given represent the 4p orbital. According to the Pauli exclusion principle, each orbital can accommodate a maximum of two electrons with opposite spins.
The number of electrons that could occupy the quantum states described by n = 4 and ℓ = 3 is 14.
(b) The quantum numbers given represent the 4f subshell. The number of orbitals in the 4f subshell is 7, and each orbital can accommodate a maximum of 2 electrons with opposite spins.
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A student drops two eggs of equal mass simultaneously from the
same height. Egg A lands on the tile floor and breaks. Egg B
lands intact without bouncing, on a foam pad lying on the floor.
Compared to the magnitude of the impulse on egg A as it lands,
the magnitude of the impulse on egg B as it lands is
Answers
The magnitude of the impulse on egg B as it lands is the same as egg A since both have equal mass and lands with the same speed.
The impulse experienced by each egg is equal to the change in the momentum of the egg as it lands on the floor.
\(J = \Delta mv\)
where;
m is the mass of each egg
v is the velocity of each egg
The final velocity of each egg is the same since they are dropped from the same height.
Thus, the magnitude of the impulse on egg B as it lands is the same as egg A since both have equal mass and lands with the same speed.
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Question 6 of 10
A double-blind study is one in which neither the researchers nor the subjects
know which subjects are receiving the real treatment and which are receiving
the placebo. What is the purpose of this design?
A. It prevents researchers from formulating hypotheses.
B. It postpones the interpretation process.
C. It minimizes bias.
D. It minimizes subject frustration.
SUBMIT
Answers
It reduces bias if In a double-blind study, neither researchers nor the participants are aware of which interpretation method is being used, which patients are receiving the actual treatment, and which
The correct answer is C
What steps comprise the interpretation procedure?taking in the source language, recognising the deep structural meaning, using a contextual/schema screen, formulating/practicing the target language utterance, and creating the interpretation.
What steps does a translator take?An interpreter, as the name implies, converts high-level computer code into code that a machine can understand (machine code) or into a higher-level language that can be quickly executed. The interpreter reads every line of code before converting or directly executing it.
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a race car is traveling at 76 m/s[E] when it slows down at -9m/s^2 for 4 seconds. what is its new velocity?
Answers
Answer:
40 m/s
Explanation:
Between points A and B, the cyclist increases his speed from 2m/s to 5 m/s in a time of 2 seconds. What is the magnitude of his acceleration?
Answers
Answer:
1.5 m/s²
Explanation:
The acceleration can be calculated as the change in velocity over time. So, the magnitude of his acceleration is equal to
\(\begin{gathered} a=\frac{v_B-v_A}{t} \\ \\ a=\frac{5\text{ m/s - 2 m/s}}{2\text{ s}} \\ \\ a=\frac{3\text{ m/s}}{2\text{ s}} \\ \\ a=1.5\text{ m/s}^2 \end{gathered}\)Therefore, the acceleration is 1.5 m/s²
how to calculate displacement
Answers
Velocity = displacement/time
Using the formula above
Displacement = velocity•time
A ball is thrown vertically upward with an initial velocity of 64 feet per second.
Answers
A ball is thrown vertically upward with an initial velocity of 64 feet per second.So, from 0.5 seconds to 3.5 seconds, the ball is at the height of 28 feet above the ground.
What is the straightforward definition of velocity?velocity. . swiftness, quickness, or the speed of motion, activity, or operation A measurement of a body's rate of motion in physics is the rate at which its location changes over time in a specific direction.
What is the definition of velocity using an example?Simply said, velocity is the rate of movement in a specific direction. including the speed of a car driving north on a road or the pace at which a rocket takes off. Since the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.
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two solid brass rods ab and cd are brazed to a brass sleeve ef. determine page 522 the ratio d2/d1 for which the same maximum shearing stress occurs in the rods and in the sleeve.
Answers
The ratio d2/d1 for which the same maximum shearing stress occurs in the rods and in the sleeve is \(\sqrt{((P1*D1^2 + P2*D2^2)/(Ps*D1^2))}\)
To determine the ratio D2/D1 for which the same maximum shearing stress occurs in the rods and in the sleeve, follow these steps:
Let the force acting on the rods be P, the length of the rods be L, and the length of the sleeve be Ls.Calculate the cross-sectional area of rods AB and CD as A1 = π\(D1^2/4\) and A2 = π\(D2^2/4\) respectively.Determine the shearing stress in rods AB and CD as τ1 = P/A1 and τ2 = P/A2 respectively.Calculate the total force transmitted by the sleeve as Ps = P1 + P2.Calculate the cross-sectional area of the sleeve as As = π\((D2^2 - D1^2)/4\).Determine the shearing stress in the sleeve as τs = Ps/As.To have the same maximum shearing stress in both the rods and the sleeve, τ1 = τ2 = τs.Equate the equations for shearing stress and solve for the ratio D2/D1:P1/π\(D1^2/4\) + P2/π\(D2^2/4\) = Ps/π\((D2^2 - D1^2)/4\)Simplify the equation and solve for D2/D1:
\((P1/D1^2) + (P2/D2^2)\) = \(Ps/(D2^2 - D1^2)\)
D2/D1 = \(\sqrt{((P1*D1^2 + P2*D2^2)/(Ps*D1^2))}\)
This step-by-step process will help you determine the ratio D2/D1 for which the same maximum shearing stress occurs in the rods AB and CD and in the sleeve EF.
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A chain has a mass of 10.0 kg. It is hanging freely, at rest, with one end connected to a ceiling hook.
What is the tension at the top of the chain?
What is the tension at the midpoint of the chain?
What is the tension at the bottom of the chain?
Answers
Answer:
Identify the object to be analyzed. For some systems in equilibrium, it may be necessary to consider more than one object. Identify all forces acting on the object. Identify the questions you need to answer. Identify the information given in the problem. In realistic problems, some key information may be implicit in the situation rather than provided explicitly.
Explanation:
Identify the object to be analyzed. For some systems in equilibrium, it may be necessary to consider more than one object. Identify all forces acting on the object. Identify the questions you need to answer. Identify the information given in the problem. In realistic problems, some key information may be implicit in the situation rather than provided explicitly.
A force of - 4.0 N is applied to a 0.5 kg object for 3.0 sec. If the initial velocity of the object was 9.0 m / s, what is its final velocity?
Answers
The final velocity of the object is 6.0 m/s. Using Newton's second law, F = ma, we can find the acceleration experienced by the object.
Rearranging the formula as a = F/m, we get a = (-4.0 N) / (0.5 kg) = -8.0 m/s² (negative because the force is in the opposite direction to the initial velocity).
Next, we use the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Plugging in the values, we have v = 9.0 m/s + (-8.0 m/s²) × 3.0 s = 9.0 m/s - 24.0 m/s = -15.0 m/s.
Since velocity is a vector quantity, the negative sign indicates the direction. Thus, the final velocity is 15.0 m/s in the opposite direction to the initial velocity. Taking the magnitude, the final velocity is 15.0 m/s.
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the interpretation of the wavefunction that describes them as probability amplitudes was developed by:
Answers
The interpretation of the wavefunction that describes them as probability amplitudes was developed by Max Born.
Max Born was one of the renowned physicists known for his splendid work in the field of quantum mechanics.
When the scientists of his time were using the three-dimensional standing wave to describe about the wavelength, he was the person who used probably amplitude to describe a wavefunction.
To describe a wavelength using the probably amplitude, Max Born used and developed the Schrodinger's view of the electron.
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5. A car stops in 20 m. If it has an acceleration of-6m/s?,
how fast was it going before you started slowing down?
Answers
Answer:
15.49 m/s
Explanation:
We know that the stopping distance is ,
=> s = u²/2(-a)
So that ,
=> 20m = u² / 2* 6m/s²
=> u² = 240m²/s²
=> u = √240 m²/s²
=> u = 15.49 m/s
**Edits are welcomed**
If astronomers discovered a new asteroid that occupied the same orbit as jupiter trailing it by about 60°, this asteroid would be categorized as a(n) _____ asteroid.
Answers
If astronomers discovered a new asteroid that occupied the same orbit as Jupiter, trailing it by about 60°, this asteroid would be categorized as a Trojan asteroid.
Trojan asteroids are a type of asteroid that share the same orbit as a planet, with one group of Trojans located about 60° ahead of the planet and the other group located about 60° behind it. These asteroids are named after the Trojan War from Greek mythology.
In the case of the new asteroid discovered, since it is trailing Jupiter by about 60°, it would fall into the category of a trailing Trojan asteroid. It would be one of the many asteroids that have settled into stable positions within Jupiter's orbit. It's important to note that Trojan asteroids are not unique to Jupiter; they can also be found in the orbits of other planets, such as Mars, Uranus, and Neptune. The presence of Trojan asteroids provides valuable insights into the dynamics of the solar system and the formation of planets.
In summary, if astronomers discovered a new asteroid that occupied the same orbit as Jupiter, trailing it by about 60°, this asteroid would be categorized as a trailing Trojan asteroid.
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Elaine went to her outside faucet to fill a 0. 0189m³ bucket with water to wash her car. Water exits with a speed of 0. 61m/s. The radius of the faucet is 0. 0078m. Calculate how long does it take to fill the bucket completely
Answers
The time it will take to fill the bucket completely is 163.3 seconds.
To calculate how long it takes to fill the bucket completely, we can use the equation for volume flow rate:
Q = A * v
Where Q is the volume flow rate, A is the cross-sectional area of the faucet, and v is the speed of the water. We can rearrange this equation to solve for time:
t = V / Q
Where t is the time it takes to fill the bucket, and V is the volume of the bucket.
Plugging in the values given in the question, we get:
A = π * r^2 = π * 0.0078^2 = 0.00019 m^2
v = 0.61 m/s
V = 0.0189 m^3
Substituting these values into the equation for volume flow rate, we get:
Q = 0.00019 m^2 * 0.61 m/s = 0.0001159 m^3/s
Substituting these values into the equation for time, we get:
t = 0.0189 m^3 / 0.0001159 m^3/s = 163.3 s
Therefore, it takes Elaine approximately 163.3 seconds, or 2 minutes and 43 seconds, to fill the bucket completely.
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If you stood on Mars and lifted a 15kg pack,you would be pulling with a force greater than...
Answers
Answer: See answers below.
Explanation: In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
Mercury
Venus
Moon
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
The earth attracts an apple with a force of 15 Newton. taking this as an action force, how much is reaction force? who accepts the reaction force? on which body does a reaction force act?
Answers
Answer:
action = reaction
land accepts
reaction force acts on the apple
Answer:
15 Newton
Explanation:
According to Newton's third law of motion, "Every action has a reaction which is equal in magnitude but opposite in direction" (Right now, we're not talking about direction, so we'll ignore it)
So,
Action Force = Reaction Force
Reaction Force = 15 N
The action force is by the Earth on the Apple, So the reaction force will be by the Apple on the Earth.
1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.
Answers
Answer:
C
Explanation:
because the concave mirror is always inverted
d ) when object is between focus and mirror , image formed is always virtual and erect
What is a Concave mirror ?
A concave mirror has a reflective surface that is curved inward and away from the light source .
a) Incorrect because image can be equal to , smaller then , and bigger then the object
b) and c) Incorrect when object is between focus and mirror , image formed is virtual and erect
d ) Correct option when object is between focus and mirror , image formed is always virtual and erect
e) Incorrect except one case in all other cases nature is real and inverted
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please someone help me understand this question
Answers
\(\\ \sf\longmapsto F=\dfrac{Gm_1m_2}{r^2}\)
m1 and m2 has same units let both be m\(\\ \sf\longmapsto F=\dfrac{Gm^2}{r^2}\)
\(\\ \sf\longmapsto G=\dfrac{Fr^2}{m^2}\)
SI units:-
F=Newton (N)r=metre(m)mass=m=kg\(\\ \sf\longmapsto G=\dfrac{Nm^2}{kg^2}\)
Option C is correct
Describe what is happening to the pressure and volume of the gas in the two diagrams below, assuming that the temperature of the gas does not change.
Answers
The pressure is increasing and accordingly the volume of the gas is decreasing when the temperature of the gas does not changes.
Continuous physical force acting on an object is termed as pressure.
Space occupied by any substance is termed as its volume.
As we know pressure and volume are inversely proportional to each other, this means that if the temperature and amount of any gas in a container is kept constant then the increase in pressure of the gas will cause decrease in the volume of the same gas in the container.
Pressure (P) ∝ \(\frac{1}{Volume (V)}\)
When sign of proportionality '∝' is removed constant 'k' is added to the equation
i.e. P = \(\frac{k}{V}\)
PV = k
So the given picture clearly depicts that the piston is creating pressure on the gas hence the pressure of the gas is increasing and therefore the volume of the gas is decreasing.
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What is the current produced by a 9V battery flowing through a resistance of 2 x 10-4
Q?
Answers
Answer:
.09 cmps
Explanation:
(b) determine the maximum value of the electric field in the sunlight at the earth's location.
Answers
Find the greatest electric field strength in the sun at the earth's position. The highest electric field strength in the sun at the earth's location is 1.056 kV/m.
What is the real name of Earth?It is a frequent fallacy that “Terra” is the worldwide genus of the planet, although in reality Earth doesn't even have an important diplomatic name. The conventional English name of a planet, including in academia, is “Earth”
What that is Earth?Our homeworld Earth is a stony, terrestrial world. It features a substantial and lively surface with mountains, rivers, gorges, plains and much more. Being an ocean planet, Earth is unique. Water covers 70percent of Earth's crust.
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cylinder of mass 0.5 pg and radius of 0.2 m rolls down an 30 degree incline with a length of 2m. find the velocity at the bottom of the ramp
Answers
The velocity of the cylinder at the bottom of the incline is 2.21 m/s.
Given that mass of the cylinder = 0.5 pg
Radius of the cylinder = 0.2 m
Angle of inclination of the plane = 30°
Length of the inclined plane = 2 m.
We have to determine the velocity of the cylinder at the bottom of the incline.
Step 1: Calculate the acceleration of the cylinder.
The acceleration of the cylinder down the inclined plane is given by: a = gsinθ
Here, g = 9.8 m/s² and θ = 30°So, a = 9.8 x sin30° = 4.9 m/s²
Step 2: Calculate the time taken by the cylinder to roll down the incline.
The distance traveled by the cylinder along the incline, s = Lsinθ = 2 sin30° = 1 m
The time taken by the cylinder to roll down the incline is given by: t = sqrt(2s / a) = sqrt(2 x 1 / 4.9) = 0.45 s
Step 3: Calculate the velocity of the cylinder at the bottom of the incline.
The velocity of the cylinder at the bottom of the incline, v = u + at
Here, the initial velocity of the cylinder, u = 0 as it was initially at restv = 0 + 4.9 x 0.45 = 2.21 m/s
So, the velocity of the cylinder at the bottom of the incline is 2.21 m/s.
Therefore, the detailed answer to the given problem is that the velocity of the cylinder at the bottom of the incline is 2.21 m/s.
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A marble accelerates from rest at a constant rate .it travels 36 m in 12.0 sec what’s is it’s final velocity and what was the acceleration
Answers
Answer:
a = 0.50 m/s²
v = 6.0 m/s
Explanation:
Step 1: Given data
Initial velocity (u): 0 m/s (rest)Displacement of the marble (s): 36 mTime elapsed (t): 12.0 sFinal velocity (v): ?Acceleration (a): ?Step 2: Calculate the acceleration
We will use the following suvat equation.
s = u × t + 1/2 × a × t²
s = 0 × 12.0 s + 1/2 × a × (12.0 s)²
36 m = a × 72.0 s²
a = 0.50 m/s²
Step 3: Calculate the final velocity
We will use the following suvat equation.
v = u + a × t
v = 0 + 0.50 m/s² × 12.0 s
v = 6.0 m/s
A cyclist travels from A to B along the arc of a circle of radius 25 m as shown.
0 Calculate the distance travelled by the cyclist.
(ii) Calculate the displacement undergone by the cyclist.
A
4
25 m
12nn41
Answers
The displacement of the cyclist from point A to B is 39.3 m.
Displacement of the cyclist
The displacement of the cyclist is equal to the change between the final position and initial position of the cyclist. This can also be described as the shortest distance between two positions.
From the given image, the displacement of the cyclist from point A to B can be determined by formula for calculating length of arc,
D = (θ/360) x 2πr
D = (90/360) x 2π x 25
D = 39.3 m
Thus, the displacement of the cyclist from point A to B is 39.3 m.
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