k/m = (2 * g * Δh) / [((1 - 0.79) * original length)^2] - (2 * g * Δh) * 0.21 / E
To determine the ratio of the spring constant to the helicopter's mass, we need to consider the change in potential energy and the work done by the shock absorbers.
Change in Potential Energy:
The change in potential energy of the helicopter as it descends can be calculated using the formula: ΔPE = mgh, where m is the mass of the helicopter, g is the acceleration due to gravity, and h is the change in height.
In this case, the helicopter descends vertically, so the change in height is equal to the compression of the shock absorbers.
ΔPE = mgΔh
Work Done by the Shock Absorbers:
The work done by the shock absorbers can be calculated using the formula: W = (1/2)kΔx^2, where k is the spring constant and Δx is the change in length of the shock absorbers.
In this case, the shock absorbers compress to 79% of their original length, which means the change in length is Δx = (1 - 0.79) * original length.
W = (1/2)k[(1 - 0.79) * original length]^2
Energy Absorbed by the Air in the Tires:
The energy absorbed by the air in the tires can be calculated as a percentage of the initial energy. Let's denote the initial energy as E.
Energy absorbed = 0.21 * E
Since the energy absorbed by the air in the tires is heat energy, it does not contribute to the work done by the shock absorbers.
Equating the Energy:
The change in potential energy is equal to the sum of the work done by the shock absorbers and the energy absorbed by the air in the tires:
ΔPE = W + Energy absorbed
mgΔh = (1/2)k[(1 - 0.79) * original length]^2 + 0.21 * E
Now we can solve for the ratio of the spring constant (k) to the helicopter's mass (m):
k/m = (2 * g * Δh) / [((1 - 0.79) * original length)^2] - (2 * g * Δh) * 0.21 / E
Please note that to obtain a specific numerical value for the ratio, we would need to know the values of g, Δh, original length, and E.
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Define Eukaryote cells and Prokaryote cells
Answer:
Ekaryote cells
an organism consisting of a cell or cells in which the genetic material is DNA in the form of chromosomes contained within a distinct nucleus. Eukaryotes include all living organisms other than the eubacteria and archaea.
prokaryote cells
microscopic single-celled organism which has neither a distinct nucleus with a membrane nor other specialized organelles, including the bacteria and cyanobacteria
Energy in an ecosystem's energy pyramid always flows from __________.
A. decomposers to producers
B. producers to consumers
C. consumers to producers
D. decomposers to consumers
The Answer is B because primary consumers need to get their food from plants.
Answer:
The Answer is B because primary consumers need to get their food from plants
Explanation:
For a wave, the _________ is the distance between two successive crests, while the _________ is the time elapsed between two successive crests passing by the same point.
Answer:
The distance between two successive crests of a wave is one way to define its wavelength, so
λ
=
1.15
m
.
The frequency of a wave is the number of waves passing a given point per second, so
f
=
20
16.2
=
1.23
Hz
.
The speed of a wave is given* as
v
=
λ
f
, so here
v
=
1.15
⋅
1.23
=
1.42
m/s
~~~~
*This is because the wavelength is the "distance per wave" and the frequency is the "number of waves per second," so multiplying the two gives "distance per second." This can be verified with dimensional analysis:
meters
wave
×
waves
second
=
meters
second
Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. Through what angle will it have turned after time 2f? A. 25 rad B. 50 rad C. 75 rad D. 100 rad E. 200 rad
After time 2t, the wheel with constant angular acceleration will have turned through an angle of 100 rad (Option D).
Let's analyze the problem step by step. The given information states that the wheel starts from rest and undergoes a constant angular acceleration. We need to find the angle it will have turned after time 2t.
The formula to calculate the angle turned by a rotating object with constant angular acceleration is given by θ = ω₀t + (1/2)αt², where θ is the angle turned, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time.
In this case, the wheel starts from rest, so the initial angular velocity ω₀ is 0. The angle turned after time t is given as 25 rad, which means θ = 25 rad, and we need to find the angle turned after time 2t.
Plugging the given values into the formula, we have 25 rad = (1/2)αt². Solving for α, we find α = (50 rad) / t².
Now, we can use this value of α to find the angle turned after time 2t. Plugging α and t into the formula, we get θ = (1/2)(50 rad / t²)(2t)² = 100 rad.
Therefore, after time 2t, the wheel with constant angular acceleration will have turned through an angle of 100 rad (Option D).
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Rank the crystal lattice structures in order of decreasing efficiency of space in the structure?
(a) Face centered cubic
(b) Body centered cubic
(c) Simple cubic
(d) Hexagonal close packing
According to the decreasing efficiency of space in the structure, crystal lattice structures are in the order of Hexagonal close packing, Face centered cubic, Body centered cubic and simple cubic.
A unit cell of crystalline structure can be defined as the simplest repeating unit. All the classification of crystalline structure are based on these unit cells.
In simple cubic, the layers are arranged one above the other, while we examine the basic cubic structure, the atoms are present only on corners of the cube. It has a packing efficiency of 54% .
For body centered cubic, the packaging is more efficient, 68%. The atoms in a layer do not touch each other, but touches 4 atoms from above and 4 from below layers.
For Face centered cubic, packing efficiency is 74%. The second layer is packed in the indentation of the first layer, and third on indentation of second. Here atoms are packed as closely as possible.
For hexagonal close packing layers are packed such that the spheres overlay spheres of the previous layer. It also have a packing efficiency of 74%.
So the decreasing order is Hexagonal close packing > Face centered cubic > body centered cubic > simple cubic.
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An object on Earth weighs 600 N and on Mars 100 N. If its mass on Earth is approximately 60 kg what is the mass of the object on Mars?
Answer:
I think its
10 kg
plzz plzz plzz. mark as brainliest
If the mass of an object is approximately 60 kg on earth then its mass remains the same on Mars which is 60 kg because mass does not change from place to place.
What is mass?Mass in physics is a numerical representation of inertia, a fundamental property of all matter. What a body of matter is fundamentally is the resistance it offers to a change in its speed or location brought on by the application of a force. The more mass a body has, the less of a change a force exerts results. The kilogram is the unit of mass in the International System of Units, and it is defined by Planck's constant as being equal to 6.62607015 × 10⁻³⁴ joules second (SI).
According to the question, the weight of an object depends on gravity which is different from place to place so weight also varies from place to place but the mass is constant everywhere it does not change. So, if the mass of an object is 60 kg on earth then it remains the same on mars also.
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The ________ of a particle for a given ‘Interval of time’ is defined as the ratio of total distance travelled to the total time taken.
uniform speed
average speed
uniform velocity
average velocity
Answer:
The average speed of a particle for a given ‘Interval of time’ is defined as the ratio of total distance travelled to the total time taken.
Explanation:
To find the average speed we take the total
distance traveled divided by the time interval.
A physicist observes that a cannonball shot horizontally from a cannon travels 1.000 m before falling to the ground. Which of the following statements correctly explains this observation using Newton's laws?
O Objects tend to remain in the state of motion they are in unless acted upon by an unbalanced force. Friction and gravity acted on the cannonball, slowing it down and slamming it into the ground
O Objects at rest tend to remain in their cument state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion
The force on the cannonball produced by the cannon was less than the force of friction on the cannonball, causing the cannonball to slow down and fall to the ground.
O The force on the cannonball produced by the cannon exactly equaled the force of friction on the cannonball, balancing the forces and causing it to fall to the ground.
The correct statement that explains the observation using Newton's laws is objects at rest tend to remain in their current state of motion unless acted upon by an unbalanced force, but objects in motion require a continual application of force to stay in motion. Here option A is correct.
According to Newton's first law of motion, an object will continue moving at a constant velocity in a straight line unless acted upon by an external force. In this case, when the cannonball is shot horizontally from the cannon, it initially possesses a forward velocity due to the force applied by the cannon. However, once the cannonball is in motion, the only forces acting on it are gravity and friction.
Gravity acts vertically downward, causing the cannonball to accelerate downward. Friction acts horizontally in the opposite direction to the motion of the cannonball. As the cannonball moves forward, friction opposes its motion and gradually slows it down.
Since there is no force continuously propelling the cannonball forward, and the forces of friction and gravity act on it, the cannonball eventually comes to a stop and falls to the ground. Hence option A is correct.
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An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work must you do to transport an electron from the positive terminal to negative terminal
The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.
Given:
Potential difference, V = 1.2 V
Charge on an electron, e = 1.6 × 10⁻¹⁹ C
Calculation:
We know that the work done to transport an electron from the positive to the negative terminal is given as:
W.D = (Charge on electron)×(Potential difference)
= e × V
= (1.6 × 10⁻¹⁹ C)×(1.2 V)
= 1.92 × 10⁻¹⁹ J
Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.
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A kettle transfers 1,500 J of energy, 1,200 J to a thermal energy store in the water and 300 J to the air as sound. How efficient is the kettle?
Answer:
80%
Explanation:
Given data
The energy use is the 1200J transfered to the water
Total energy=1500J
Efficiency = Energy used/total enery
Efficiency= 1200/1500*100
Efficiency=0.8*100
Efficiency=80%
Hence the efficiency of the kettle is 80%
acceleration is a vector and has direction. when the object moves to the right and speeds up, what is the direction of the acceleration? group of answer choices to the right. to the left. up. down. in the direction of the force that is causing the change of speed. in the direction of the gravitational force.
An object that is travelling to the right would accelerate in the same direction as its motion, which would be to the right. This is so because acceleration, which encompasses both speed and direction of motion, is the rate at which velocity changes.
If an object is going to the right and then accelerates, the acceleration would also be moving to the right, following the motion. This is so because acceleration, which encompasses both speed and direction of motion, is the rate at which velocity changes. While the item in this instance is moving faster, its velocity is rising in the same direction as its motion, and consequently, the acceleration is likewise moving faster. The other possible solutions don't work in this case.The rate at which velocity changes is known as the acceleration, which is a vector quantity. The speed and direction of motion of an object are described by a vector called velocity.
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11.5 A group of hikers uses a GPS while doing a 40-mile trek in Colorado. A curve fit to the data shows that their altitude can be approximated by the function y(t) = 0.12 - 6.75 135-11202 +3200r where y and t are expressed in feet and hours, respectively. During the 18-hour hike, determine (a) the maximum altitude that the hikers reach, (b) the total feet they ascend, (c) the total feet they descend. Hint: You will need to use a calculator or computer to solve for the roots of a fourth-order polynomial. 9070, 62 + 11.6 The motion of a particle is defined by the relation x 9t 5, where x is expressed in feet and t in seconds. Determine (a) when the velocity is zero, (b) the position, acceleration, and total distance traveled when t 5 s
(a) To determine the maximum altitude reached by the hikers, we need to find the maximum value of the function y(t). By analyzing the given function, we can see that the maximum altitude occurs at the highest point of the curve.
To find this point, we can take the derivative of y(t) with respect to t and set it equal to zero. Solving this equation will give us the value of t at which the maximum altitude is reached. Substituting this value back into the original function will give us the maximum altitude.
(b) To calculate the total feet ascended by the hikers, we need to find the area under the curve of the function y(t) over the time interval of the hike. This can be done by integrating y(t) with respect to t over the given interval.
(c) Similarly, to calculate the total feet descended by the hikers, we need to find the area under the curve of the function y(t) below the x-axis over the time interval of the hike. This can be achieved by integrating the absolute value of y(t) with respect to t over the given interval.
For the second part of the question:
(a) To determine when the velocity is zero, we need to find the time(s) at which the derivative of the position function x(t) is equal to zero.
(b) The position at t=5s can be found by substituting t=5 into the position function x(t). The acceleration can be found by taking the second derivative of x(t) with respect to t. The total distance traveled can be calculated by finding the definite integral of the absolute value of the velocity function from t=0 to t=5.
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what is the average magnitude of the poynting vector 5.00 mi from a radio transmitter broadcasting isotropically (equally in all directions) with an average power of 250 kw?
307.4 μW/m² average magnitude of the poynting vector 5.00 mi with an average power of 250 kw?
S-average=power/area
power=250 kw
area=4π(8045)²
S-average=250/4π(8045)²
S-average=307.4 μW/m²
Power is produced when a force causes a displacement. Power has no bearing on how long it takes for a force to cause a displacement. The process's pace might range from swiftly concluding to taking some time. For example, it takes an abnormally long time for a rock climber to elevate her body a few meters over the cliff's edge. On the other hand, a trail hiker may swiftly raise her body a few meters if she selects the faster path up the mountain. Despite making the same amount of work, the hiker completes the task far quicker than the rock climber..
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A paratrooper is inltially falling dowtward at a speed of 30.3 m/s before her parachute opens, When it opens, she expeliences an upnard instantaneous acceleration of 69 m/s² (a) if this acceleration remained coestant, how much tima would be required to reduce the paratrooper's speed to a sate 5.25 m/s² (Actually the acceleratien is not constant in this case- tut. the equations of constant acceleration provide an easy estimate.) (b) How far does the paratreoper fall during this time interval?
(a) The time required to reduce the paratrooper's speed to 5.25 m/s², assuming the acceleration is constant, can be found using the formula `v = u + at`, where `v` is the final velocity, `u` is the initial velocity, `a` is the acceleration, and `t` is the time taken.
Initially, the paratrooper is falling downward at a speed of 30.3 m/s, and after the parachute opens, the upward acceleration is 69 m/s². Therefore, the net acceleration is given by:
Net acceleration = upward acceleration - downward acceleration= 69 - 9.81= 59.19 m/s²
The time taken to reduce the speed to 5.25 m/s can be found by substituting the values into the above formula as shown below:5.25 = 30.3 + 59.19t⇒ t = (5.25 - 30.3)/59.19≈ -0.421 s
Since the time can't be negative, the above estimate is invalid.
(b) The distance fallen during the time interval can be found using the formula `s = ut + 1/2 at²`. If the acceleration is not constant, an easy estimate can be obtained by taking the average of the initial and final speeds, and multiplying by the time taken, which is approximately the same as the actual distance fallen.
The average speed is given by:(30.3 + 5.25)/2 = 17.78 m/s
Therefore, the approximate distance fallen is:s ≈ ut = 17.78 × t
(a), the time taken to reduce the speed to 5.25 m/s is approximately -0.421 s, which can be disregarded since time can't be negative.
Therefore, the actual time taken is:5.25 = 30.3 + at⇒ t = (5.25 - 30.3)/a= 1.435 sSubstituting this into the above formula, the actual distance fallen is:s = 17.78 × 1.435≈ 25.50 m
Therefore, the paratrooper falls a distance of approximately 25.50 m during this time interval.
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A hollow cylinder of radius 1. 4 cm, height 7. 3 cm, and mass 430 g is attached by a wire to one of its circular faces. It is twisted through an angle of 10o and released. If the spring has a torsion constant of 350 N-m/rad, what is the frequency of the motion
The frequency of the motion is 2.45 Hz.
What is the frequency of the motion in hertz?The frequency of the motion can be calculated using the formula:
f = (1 / 2π) * √(k / I)
Where:
f is the frequency in hertz,
k is the torsion constant in newton-meters per radian, and
I is the moment of inertia of the cylinder.
To find the moment of inertia, we need to consider the geometry of the hollow cylinder. The moment of inertia for a hollow cylinder rotating about its central axis is given by the formula:
I =\((m * R^2) * (1 - (r^2 / R^2))\)
Where:
m is the mass of the cylinder,
R is the radius of the cylinder, and
r is the radius of the hollow part of the cylinder.
Plugging in the given values, we have:
m = 430 g = 0.43 kg
R = 1.4 cm = 0.014 m
r = 0 cm (since the cylinder is solid)
Calculating the moment of inertia:
I =\((0.43 * 0.014^2) * (1 - (0^2 / 0.014^2))\) = 0.00012722 kg·m²
Now we can calculate the frequency of the motion:
f = (1 / 2π) * √(350 / 0.00012722) ≈ 2.45 Hz
Therefore, the frequency of the motion is approximately 2.45 Hz.
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calculate the distance travelled by a car moving with 40 m/s velocity in 2 hours
Answer:
14,400m
Explanation:
The formula for calculating speed is S=D/T.
S=speed( in meters per second- m/s)
D=distance(in meters)
T=time( in seconds)
For our case:
S=40m/s
D=?
Time=2 hours=60min x 60 sec=3600seconds
Now make D the subject.
D=S x T
D=4m/s x 3600s=14,400m
Therefore our answer is
14 400 m or 14.4 km
Carbon dioxide undergoes a phase change called sublimation, how does a single molecule of carbon dioxide change as a result of this process in terms of its energy and physical characteristics? a. There is a physical change from a gas to a liquid; energy is released into the environment reducing the molecular movement. b. There is a physical change from the solid state to a gas state where energy between the molecules increases. c. There is a chemical change between the carbona nd oxygen resulting int he formation of oxygen gas which has more energy d. There is a chemical change as the carbon dioxide is transferred from a liquid to a solid reducing the amount of energy
The correct answer is(b). There is a physical change from the solid state to a gas state where energy between the molecules increases.
What is the process of sublimation in carbon dioxide?During sublimation, carbon dioxide transitions directly from the solid state (dry ice) to the gas state without passing through the liquid phase. In this process, individual molecules of carbon dioxide gain energy from the surroundings, leading to an increase in their kinetic energy and molecular movement.
As a result, the carbon dioxide molecules separate from each other and form a gas. This phase change is considered a physical change rather than a chemical change since the chemical composition of carbon dioxide remains the same throughout the process.
Therefore, the sublimation of carbon dioxide results in a physical change where the molecules transition from the solid state to the gas state, gaining energy and increasing their molecular movement.
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PLEASE HELP!!!!!
The time needed for a water wave to change from the equilibrium level to the crest is 0.5731 s.
1. What is the period of the wave? Answer in units of s.
2. What is the frequency of the wave? Answer in units of Hz.
The time taken to reach one crest is 0.5731 s. Then the time period of the wave is 1.146 s. The frequency is the inverse of the period that is 0.87 Hz.
What is period of wave ?The time period of a wave is the time required to complete one wave cycle. For a transverse wave the period of the wave is the time required to reach from one crest to the next crest of the wave.
Given that, time to reach one crest = 0.5731 s.
then the time for to the next crest from the equilibrium position is :
T = 0.5731 s× 2 = 1.146 s.
Frequency of a wave is the number of wave cycles per second. It is the inverse of time period of the wave.
Hence, frequency = 1/T
ν = 1/ 1.146 s = 0.87 Hz.
Therefore, the period of the wave is 1.14 s and frequency is 0.87 Hz.
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True or false question scientists can predict when an earthquake will occur
Answer:
False
Explanation:
Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.
Which is an example of potential energy? a swimmer kicking their legs a car driving on the road an arrow flying at a target a yo-yo in someone’s hand
Answer:
The yo-yo :)
Explanation:
what insulating substance allows for an electrical signal to travel much faster down an axon?
The insulating substance that allows for an electrical signal to travel much faster down an axon is called myelin.
The insulating substance that speeds up electrical signal transmission in axons is myelin. Myelin is a fatty substance produced by oligodendrocytes and Schwann cells, forming a protective sheath around the axons. It allows for saltatory conduction, where the electrical signal jumps between nodes of Ranvier, increasing the speed of transmission. Myelinated axons have regular gaps called nodes of Ranvier, which expose the axon membrane and facilitate faster signal propagation. Saltatory conduction is much faster than continuous conduction in unmyelinated axons. The myelin sheath prevents signal leakage and enables efficient communication within the nervous system. This mechanism is crucial for the rapid transmission of electrical signals over long distances in the nervous system.
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A 0.5 kg block of playdough moving at 1.5 m/s is smashed into a 0.25 kg blob of playdough. calculate the speed
of the two stuck-together blobs immediately after colliding.
The final speed of both playdoughs which stick together after the collision is 0.5 m/s
The mass of the first playdough = 0.5 kg
The mass of the second playdough = 0.25 kg
The initial speed of the first playdough = 1.5 m/s
The initial speed of the second playdough = 2 m/s
The final speed of both playdoughs can be found using the formula,
m₁u₁ + m₂u₂ = (m₁ + m₂) v
where m₁,m₂ is the mass of the first and second playdough respectively
u₁,u₂ is the initial speed of the first and second playdough respectively
v is the final speed of both playdough
Let us substitute the known values in the above equation, we get
0.5 x 1.5 + 0.25 x 2 = (0.5 + 0.25) v
0.75 x 0.5 = 0.75v
0.375 = 0.75v
v = 0.375 / 0.75
= 0.5 m/s
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A ball of mass oscillates on a spring with spring constant k=200N/m . The ball's position is described by x=(0.350m)cos16.0t with t measured in seconds.
a. What is the amplitude of the ball's motion?
i. 0.175 m
ii. 0.350 m
iii. 0.700 m
iv. 7.50 m
v. 16.0 m
b. What is the frequency of the ball's motion?
i. 0.35 Hz.
ii. 2.55 Hz.
iii. 5.44 Hz.
iv. 6.28 Hz.
v. 16.0 Hz.
c. What is the value of the mass ?
i. 0.450 kg
ii. 0.781 kg
iii. 1.54 kg
iv. 3.76 kg
v. 6.33 kg
d. What is the total mechanical energy of the oscillator?
e. What is the ball's maximum speed?
a. The amplitude of the ball's motion is 0.350 m. b. The frequency of the ball's motion is 2.55 Hz. c. The mass is 0.781 kg. d. The total mechanical energy of the oscillator is 12.25 J. e. The maximum speed of the ball is 5.60 m/s.
a. The amplitude of the ball's motion is given by the coefficient of the cosine term, which is 0.350 m. Therefore, the answer is (ii) 0.350 m.
b. The angular frequency of the ball's motion is given by the coefficient of time in the argument of the cosine term, which is 16.0 rad/s. The frequency is given by f = ω/2π = 16.0/2π ≈ 2.55 Hz. Therefore, the answer is (ii) 2.55 Hz.
c. The mass of the ball can be found using the formula for the angular frequency of a mass-spring system: ω = √(k/m), where k is the spring constant and m is the mass. Solving for m, we get m = k/ω² = 200/(16.0)² ≈ 0.781 kg. Therefore, the answer is (ii) 0.781 kg.
d. The total mechanical energy of the oscillator is given by the sum of its kinetic and potential energies: E = (1/2)mv² + (1/2)kx², where m is the mass, v is the velocity, k is the spring constant, and x is the displacement. At maximum displacement, the velocity is zero and the energy is entirely potential, so E = (1/2)kA², where A is the amplitude. Substituting the given values, we get E = (1/2)(200)(0.350)² ≈ 12.25 J.
e. The maximum speed of the ball occurs when it passes through the equilibrium position, where the displacement is zero. At this point, the velocity is at a maximum and is given by v = ωA = (16.0)(0.350) ≈ 5.60 m/s. Therefore, the answer is 5.60 m/s.
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A person on a road trip drives a car at different constant speeds over several legs of the trip. She drives for 10. 0 min at 50. 0 km/h, 19. 0 min at 100. 0 km/h, and 60. 0 min at 55. 0 km/h and spends 40. 0 min eating lunch and buying gas. What is the average speed for the entire trip (
The typical speed for the whole excursion is 83.24 km/h. To calculate the speed we have to calculate the distance and time.
To work out the normal speed of the whole excursion, you really want to decide the all out distance voyaged and partition that by the all out time spent driving.
Distance went at each speed:
a. 50.0 km/h for 10.0 min = 50.0 km/h * (10.0 min/60.0 min) = 8.33 km
b. 100.0 km/h for 19.0 min = 100.0 km/h * (19.0 min/60.0 min) = 31.67 km
c. 55.0 km/h for 60.0 min = 55.0 km/h * (60.0 min/60.0 min) = 55.0 km
Complete distance voyaged: 8.33 km + 31.67 km + 55.0 km = 95.0 km
Complete time spent driving: 10.0 min + 19.0 min + 60.0 min = 89.0 min
Normal speed: Complete distance voyaged/All out time spent driving = 95.0 km/(89.0 min/60.0 min) = 83.24 km/h
The units of speed and time should be reliable all through the estimation. For this situation, both speed and time are communicated in SI units (km/h and minutes, separately).
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a car reaches 80 kilometers per hour, then suddenly crashes into the concrete wall
Answer:
what is the question ? That is only a statement
Find Rth and Vth
Delermine the Theven n equivalont impedance and Thevenin voltage of the following carcuit Hints: Hint 1 The vollage Vo is the voltago across the outitit termina/s. Hint 2: use saperposition to find th
Now, we are going to find the Thevenin equivalent impedance, Zth:First, we will short the voltage source V to get the short-circuit current. So, the circuit becomes:
[ad_1]
Therefore, the current through 10 Ω resistor is:
[ad_1]
Now, we will open the current source I to find the open-circuit voltage, Vth. So, the circuit becomes:
[ad_1]
Now, the voltage across 10 Ω resistor is:
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Therefore, the Thevenin equivalent circuit of the given circuit is as follows:
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Where,
Thevenin equivalent impedance, Zth = 10 + 40 = 50 ΩThevenin equivalent voltage, Vth = 100 V (as we have found it above).Therefore, the Thevenin equivalent circuit is:
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Please I need help with this ❤️ ?
Answer:
Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The
a bedroom bureau with a mass of 45 kg, includ- ing drawers and clothing, rests on the floor. (a) if the coefficient of static friction between the bureau and the floor is 0.45, what is the magnitude of the minimum horizontal force that a person must ap- ply to start the bureau moving? (b) if the drawers and clothing, with 17 kg mass, are removed before the bureau is pushed, what is the new minimum magnitude?
The new minimum magnitude of force needed to start the bureau moving is 123.61 N.
What is Force?Force is a physical quantity that is used to describe the interaction between objects that cause a change in motion. It can be defined as any influence that causes an object to undergo a change in speed, direction or shape. The SI unit of force is the newton (N), and it is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (\(1 N = 1 kg \times m/s^2\)).
(a) To calculate the minimum force needed to start the bureau moving, we can use the formula:
\(F_{min} = \mu_s \times N\)
where F_min is the minimum force needed, μ_s is the coefficient of static friction, and N is the normal force (equal to the weight of the bureau).
\(N = m \times gN = 45 kg \times 9.81 m/s^2\)
N = 441.45 N
where m is the mass of the bureau and g is the acceleration due to gravity.
Now, we can calculate the minimum force needed to start the bureau moving:
F_min = 0.45 * 441.45 N
F_min = 198.15 N
Therefore, the minimum horizontal force that a person must apply to start the bureau moving is 198.15 N.
(b) If the drawers and clothing are removed, the mass of the bureau is reduced to 45 kg - 17 kg = 28 kg. Using the same formula as above, the new normal force is:
\(N = m \times g\\N = 28 kg \times 9.81 m/s^2\\N = 274.68 N\)
The new minimum force needed to start the bureau moving is:
F_min = 0.45 × 274.68 N
F_min = 123.61 N
Therefore, the new minimum magnitude of force needed to start the bureau moving is 123.61 N.
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How much work is needed for a 78 kg runner to accelerate from rest to 8.0 m/s ?
To calculate the work needed for a runner to accelerate, we can use the work-energy principle. The work done on an object is equal to the change in its kinetic energy.
The formula for work is given by:
\(Work = ΔKE = (1/2) * m * (vf^2 - vi^2)\)
Where:
- ΔKE is the change in kinetic energy
- m is the mass of the runner
- vf is the final velocity (8.0 m/s in this case)
- vi is the initial velocity (0 m/s as the runner starts from rest)
Let's substitute the given values into the formula and calculate the work:
\(m = 78 kg\)
\(vf = 8.0 m/s\)
\(vi = 0 m/s\)
Work = \((1/2) * 78 kg * (8.0 m/s)^2 - (0 m/s)^2\)
Simplifying the equation:
Work =\((1/2) * 78 kg * (64 m^2/s^2)\)
Work = 2496 J
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The Tesla Model S Electric vehicle can go from 0 to 60 mi/hr (26.8 m/s) in only 1.9 seconds! How far does it move from rest until it reaches 60 mi/hr? Round your answer to the nearest whole meter.
Answer:
The Tesla moves approx. 25 meters from rest before reaching 60 mi/hr
Explanation:
Given:
Initial velocity = 0 m/s
Final velocity = 26.8 m/s
Time = 1.9 seconds
Acceleration = change in velocity/time
\(a = \frac{26.8}{1.9}\)
The equation to find displacement (Δx) with given starting and final velocity, time, and acceleration is:
\(x = x_{0} + v_{0}t + \frac{1}{2} at^{2}\)
Starting position and initial velocity both equal 0, so
\(x = \frac{1}{2} at^{2}\)
\(x=\frac{1}{2} (\frac{26.8}{1.9})(1.9)^{2}\)
x = 25.46m
Rounded to the nearest whole number, x = 25m