a helium-filled toy balloon has a gauge pressure of 0.350 atm and a volume of 11.0 liters. how much greater is the internal energy (in j) of the helium in the balloon than it would be at zero gauge pressure?

The pH of the solution is 5.

A solution's pH, which measures how acidic it is, is determined by taking the negative logarithm of the concentration of hydrogen ions (H+) at base 10. The concentration of hydronium ions, or [H3O+], is utilized instead because hydrogen ion concentrations are typically relatively low.

The pH can be calculated using the following formula:

pH = -log[H3O+]

Substituting the given value:

pH = -log(1.00 × 10^-5) = -(-5) = 5

Therefore, the pH of the solution is 5.

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Answer: P2O5 is the empirical formula.

Explanation: When given percentages you can assume that many grams of each atom are in the compound. Then you divide grams by the molar mass of each element, giving you moles. Once you have moles, divide by the smaller molar amount, which should give you 1 mol of Phosphorus and 2.5 mol of Oxygen. Then multiply by 2 in order for both moles to be a whole number. This gets you 2 and 5.

Answer:

45 °C.

Explanation:

From the question given above, the following data were obtained:

Heat (Q) = 1125 J

Mass (M) = 250 g

Final temperature (T₂) = 55 °C

Specific heat capacity (C) = 0.45 J/gºC

Initial temperature (T₁) =?

The initial temperature of the iron can be obtained as illustrated below:

Q = MC(T₂ – T₁)

1125 = 250 × 0.45 (55 – T₁)

1125 = 112.5 (55 – T₁)

Divide both side by 112.5

1125/112.5 = 55 – T₁

10 = 55 – T₁

Collect like terms

10 – 55 = –T₁

–45 = –T₁

Multiply through by –1

45 = T₁

T₁ = 45 °C

Therefore, the initial temperature of the iron is 45 °C

A beam of light has a wavelength of 280 nanometers. The frequency of the light is  1.07 × 10¹⁵ Hz.

the information in the question is given as :

wavelength of beam of light = 280 nm

the relation between the frequency and the wavelength is given as :

F = c / λ

where,

F = frequency of the light

c = speed of light

λ = wavelength of light

speed of light , c is = 3 × 10⁸ m/s

substituting all the value in the formula for the frequency, we get:

F = c / λ

F =  3 × 10⁸  / 280 × 10⁻⁹

F = 0.0107 × 10¹⁷ Hz

F = 1.07 × 10¹⁵ Hz

Thus, A beam of light has a wavelength of 280 nanometers. The frequency of the light is  1.07 × 10¹⁵ Hz.

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Answer:

See the answer below

Explanation:

Read the following passage and identify the error. During germination, the fertilized egg begins to sprout and grow. Each seed contains an embryo, or tiny plant, and it needs the right condition to grow. These conditions include the basic need of water, the correct temperature, and the right location, which is in the soil. Select the statement that corrects the error in the passage. Seeds are fertilized during germination, not before. Basic conditions include wind, not water. The fertilized egg begins to grow and mature, not an embryo. The fertilized seed begins to grow and sprout, not an egg.

A typical seed consists of a fertilized ovule which forms the embryo. Double fertlization ensures that a structure, the endosperm, surrounds and provide nutrition to the embryo while in a state of inactivity.

During germination, the embryo sprouts and grows given the right conditions of moisture, air, temperature, and other factors that may vary from seeds to seeds.

1. The glyoxylate cycle synthesizes glucose from acetyl-CoA under carbon limitation, while the citric acid cycle oxidizes acetyl-CoA for energy production.

2. Citric acid cycle intermediates oxaloacetate and α-ketoglutarate are replenished through anaplerotic reactions, including carboxylation of pyruvate or phosphoenolpyruvate, and transamination of glutamate.

3. Anaplerosis via amino acid metabolism and alternative carbon sources increases citric acid cycle intermediates' concentration.

1. The glyoxylate cycle differs from the citric acid cycle in that it operates in certain organisms (such as plants and bacteria) under conditions of carbon limitation, allowing the net synthesis of glucose from two molecules of acetyl-CoA. In contrast,

the citric acid cycle is a central metabolic pathway occurring in most organisms, involved in the oxidation of acetyl-CoA and energy production.

2. Two citric acid cycle intermediates and the pathways that replenish them are:

Oxaloacetate can be replenished through anaplerotic reactions, such as the carboxylation of pyruvate by pyruvate carboxylase or through the carboxylation of phosphoenolpyruvate by phosphoenolpyruvate carboxylase.

α-Ketoglutarate can be replenished through the transamination of glutamate by glutamate dehydrogenase or through the oxidative decarboxylation of isocitrate by isocitrate dehydrogenase.

3. One process to increase the concentration of citric acid cycle intermediates is through anaplerosis, which refers to the replenishment of depleted intermediates by various pathways,

including amino acid metabolism or by utilizing alternative carbon sources that can be converted into citric acid cycle intermediates through anaplerotic reactions.

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Corona in transmission lines is phenomenon where the surrounding air surrounding the conductors of a power transmission line becomes ionized. It occurrence result in audible noise, losses and power dissipation and radio interference.

In the context of transmission lines, "corona" refers to the phenomenon where the surrounding air surrounding the conductors of a power transmission line becomes ionized. Corona occurs when the electric field strength at the surface of the conductors exceeds the breakdown strength of air, resulting in the ionization of air molecules.

Corona can occur in high-voltage transmission lines when the voltage gradient along the conductor exceeds a certain threshold. It is more likely to occur at higher voltages and in lines with sharp edges or points, such as those found on transmission towers or conductors.

When corona occurs, several effects can be observed:

1. Audible Noise: The ionized air around the conductors produces a characteristic buzzing or crackling sound. This audible noise is often referred to as corona noise and can be heard near high-voltage power lines.

2. Losses and Power Dissipation: The ionization of air in the corona discharge results in power losses. These losses occur due to the energy dissipated in the ionized air and can contribute to a reduction in the overall efficiency of the transmission system.

3. Radio Interference: Corona can generate electromagnetic waves in a wide frequency range, including radio frequencies. These electromagnetic waves can interfere with nearby communication systems, such as radio and television signals, causing disruptions or poor reception.

4. Ozone Generation: The ionization process in corona generates ozone, a form of oxygen. Ozone can have both positive and negative effects. While ozone at ground level is harmful to human health, ozone in the upper atmosphere plays a crucial role in shielding the Earth from harmful ultraviolet (UV) radiation.

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Answer:

c

Explanation:

because the ion are Mobil which mean they are free not combined and carry a charge but when they are combined/ fixed in position they can't carry a charge so therefore can't conduct electricity  :)

Answer:

The post-transition metals cluster to the lower left of this line. Metalloids: The metalloids are boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te) and polonium (Po). They form the staircase that represents the gradual transition from metals to nonmetals.

Explanation: i googled it

The metal that is grouped with metalloids are

A metalloid is a type of element which possesses the characteristics of both the metals and the non-metals.

Metals are those elements that are good conductors of heat and electricity while non-metals are those elements that neither conducts heat nor electricity.

The characteristics of the metalloids listed above are:

Therefore, since these elements share both the properties of metals and non-metals, they are called the metalloids.

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A liquid is allowed to evaporate and leaves no residue. It can not be determined whether it was an element, a compound, or a mixture.

A water vapor molecule stays roughly 10 days in the atmosphere after it has evaporated. Water vapor starts to cool back down as it ascends higher in the atmosphere. The water vapor condenses when it becomes cold enough, turning it back into liquid water. Eventually, individual water droplets will condense to create clouds and precipitation.

It is not possible to determined whether it would be an element, a compound and mixture because the size of the particle will be too less.

A method for separating homogenous mixtures with one or even more dissolved salts is called evaporation. The procedure separates the liquid from the solid components. Usually, the procedure entails heating the combination until there is no more liquid is present.

Therefore, it can not be possible to determined whether it was an element, a compound, or a mixture by evaporation.

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Answer:

71%

Explanation:

The number of moles of Mn3+ are produced in this process is 0.0806 moles

To determine the number of moles of Mn3+ produced in this process, we will use the following terms: current (I), time (t), Faraday's constant (F), and the mole ratio.

1. First, let's calculate the charge (Q) passed through the solution using the formula Q = I × t. Given that the current (I) is 8.64 A, and the time (t) is 15.0 minutes, we have:

Q = 8.64 A × (15.0 × 60) s = 7776 C (We convert time to seconds by multiplying by 60)

2. Now, we need to determine the number of moles of electrons (ne) passed through the solution. We'll use Faraday's constant (F = 96485 C/mol) to do this:

ne = Q / F = 7776 C / 96485 C/mol = 0.0806 mol

3. In the reduction reaction of MnO42- to Mn3+, the mole ratio of electrons to Mn3+ produced is 1:1 (One electron reduces one Mn3+ ion). Therefore, the number of moles of Mn3+ produced is equal to the number of moles of electrons:

n(Mn3+) = ne = 0.0806 mol

Thus, 0.0806 moles of Mn3+ are produced in this process.

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1. The differential equation satisfied by y(t) is:  dy/dt = 0.6 kg/min

The amount of salt in the tank after t minutes can be represented by the function y(t). We need to find the differential equation that y satisfies.
Initially, the tank contains 100 L of pure water, which means there is no salt in the tank. As time passes, a solution with a salt concentration of 0.3 kg/L is added at a rate of 7 L/min. The salt concentration in the tank will increase with the addition of this solution.
At the same time, the solution is drained from the tank at a rate of 5 L/min. This will result in a decrease in the salt concentration in the tank.
To find the differential equation satisfied by y(t), we need to consider the rate of change of salt in the tank.
Rate of change of salt in the tank = Rate of salt added - Rate of salt drained
The rate of salt added is given by the product of the concentration of the solution (0.3 kg/L) and the rate at which the solution is added (7 L/min). So, the rate of salt added = 0.3 kg/L * 7 L/min.

The rate of salt drained is given by the product of the concentration of the solution (0.3 kg/L) and the rate at which the solution is drained (5 L/min). So, the rate of salt drained = 0.3 kg/L * 5 L/min.

Therefore, the differential equation satisfied by y(t) is:
dy/dt = (0.3 kg/L * 7 L/min) - (0.3 kg/L * 5 L/min)

Simplifying the equation:
dy/dt = 2.1 kg/min - 1.5 kg/min
dy/dt = 0.6 kg/min

So, the differential equation satisfied by y(t) is:
dy/dt = 0.6 kg/min

2. The amount of salt in the tank after 40 minutes is 24 kilograms.

To find the amount of salt in the tank after 40 minutes, we can solve the differential equation.

dy/dt = 0.6 kg/min

Integrating both sides with respect to t:
∫dy = ∫0.6 dt

Integrating, we get:
y = 0.6t + C

To find the value of C, we can use the initial condition that the tank initially contains 100 L of pure water, which means there is no salt. So, at t = 0, y = 0.

Substituting these values into the equation:
0 = 0.6(0) + C
C = 0

Therefore, the equation becomes:
y = 0.6t

Now, we can find the amount of salt in the tank after 40 minutes by substituting t = 40 into the equation:
y = 0.6(40)
y = 24 kg


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Answer:

bdnsndmzmkrrbby

Explanation:

hfjdkxkx dnamkynskfkfnd

Answer:

Explanation:

Here, we want to get the mass of carbon (iv) oxide produced

From the question, we have the balanced chemical reaction stating that 2 moles of oxygen molecule produced 1 mole of carbon (iv) oxide molecule

The number of moles of carbon (iv) oxide produced from 7.34 mol oxygen is thus:

1 mole of carbon (iv) oxide contains 44 g

The mass in 3.67 moles will be:

One mole of Pb has the greatest mass and the mass is 207g

We know, that mass = given mole × Molecular weight

According to the given question, we need to find the masses of 1 mole of Na(Sodium), Pb(Lead), Be(Beryllium) and H₂

So,

Mass of Na = 1 × 23 = 23g

Mass of Pb = 1 × 207 = 207g

Mass of Be = 1 × 9 = 9g

Mass of H₂ = 1 × 2 = 2g

Therefore, one mole of Pb (lead) has the greatest mass among the given four elements that are Na, Be and H₂.

The Molar mass of a substance is the mass in grams of one mole of the compound. Pb( lead) is a soft, malleable, ductile and dense metallic element.

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Answer:

The volume of the balloon will decrease.

Explanation:

I had some leftover liquid nitrogen so I tried it in my pool.

The electron has a kinetic energy of 3 KeV. The accuracy rate for locating the electron is one percent.

A negative charges particle known as an electron can either be free or attached to an atom (not bound). One of the three main types of particles within an atom is an electron that is bonded to it; other two are protons and neutrons.

An electrical force maintains electrons in their shells. An atom's protons and electrons are drawn to each other. They both are electrically charged. Electrons have a negative charge (-), while protons have a positive charge (+).

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There are approximately 32.89 grams of sodium in a 120-gram sample of NaHCO3.

The molar mass of NaHCO3 (sodium bicarbonate) can be calculated by adding up the atomic masses of its constituent elements:

NaHCO3 = 1Na + 1H + 1C + 3O

Molar mass of NaHCO3 = 23.0 g/mol + 1.0 g/mol + 12.0 g/mol + (3 × 16.0 g/mol) = 84.0 g/mol

This means that one mole of NaHCO3 has a mass of 84.0 grams.

To determine the number of moles of NaHCO3 in a 120-gram sample, we can use the following equation:

Since the ratio of Na to NaHCO3 is 1:1, there are also 1.43 moles of Na in the sample.

Finally, we can calculate the mass of sodium (Na) in the sample by multiplying the number of moles of Na by its atomic mass:

mass of Na = moles of Na × atomic mass of Na

mass of Na = 1.43 mol × 23.0 g/mol

mass of Na = 32.89 g

Therefore, there are approximately 32.89 grams of sodium in a 120-gram sample of NaHCO3.

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Answer:

Thermal energy is the internal energy of molecules. When we heat an atom then the atoms start to vibrate more rapidly. More is the size of atom, more easily the particles can vibrate. Thus, greater is the size of atom greater will be it is thermal energy.

Whereas particles in a small atom will vibrate with difficulty as less space is available for movement. Therefore, less heat will be enough for collision pf particles. As a result, thermal energy will be less.

Thus, we can conclude that the statement if both objects are at the same temperature, the thermal energy of object A is the same as the thermal energy of object b is false.

Answer:

try c atom i hope this helps!! : )

Explanation:

To calculate the volume of each base required to completely react with 25.00 mL of 0.200 M HCl, we can use the balanced equation and the concept of stoichiometry.

a) 0.100 M NaOH:

The balanced equation for the reaction between HCl and NaOH is:

HCl + NaOH → NaCl + H2O

According to the equation, the molar ratio of HCl to NaOH is 1:1. This means that 1 mole of HCl reacts with 1 mole of NaOH. Using the equation C1V1 = C2V2, we can calculate the volume of NaOH required:

(0.200 M HCl) × (25.00 mL HCl) = (0.100 M NaOH) × (V2 NaOH)

V2 NaOH = (0.200 M HCl) × (25.00 mL HCl) / (0.100 M NaOH)

V2 NaOH = 50.00 mL

Therefore, 50.00 mL of 0.100 M NaOH is required to react completely with 25.00 mL of 0.200 M HCl.

b) 0.0500 M Sr(OH)2:

The balanced equation for the reaction between HCl and Sr(OH)2 is:

2 HCl + Sr(OH)2 → SrCl2 + 2 H2O

According to the equation, the molar ratio of HCl to Sr(OH)2 is 2:1. This means that 2 moles of HCl react with 1 mole of Sr(OH)2. Using the equation C1V1 = C2V2, we can calculate the volume of Sr(OH)2 required:

(0.200 M HCl) × (25.00 mL HCl) = (0.0500 M Sr(OH)2) × (V2 Sr(OH)2)

V2 Sr(OH)2 = (0.200 M HCl) × (25.00 mL HCl) / (0.0500 M Sr(OH)2)

V2 Sr(OH)2 = 100.00 mL

Therefore, 100.00 mL of 0.0500 M Sr(OH)2 is required to react completely with 25.00 mL of 0.200 M HCl.

c) 0.250 M KOH:

The balanced equation for the reaction between HCl and KOH is:

HCl + KOH → KCl + H2O

According to the equation, the molar ratio of HCl to KOH is 1:1. This means that 1 mole of HCl reacts with 1 mole of KOH. Using the equation C1V1 = C2V2, we can calculate the volume of KOH required:

(0.200 M HCl) × (25.00 mL HCl) = (0.250 M KOH) × (V2 KOH)

V2 KOH = (0.200 M HCl) × (25.00 mL HCl) / (0.250 M KOH)

V2 KOH = 20.00 mL

Therefore, 20.00 mL of 0.250 M KOH is required to react completely with 25.00 mL of 0.200 M HCl.

In conclusion, volume of each of the following bases will react completely with 25.00 mL of 0.200 M HCl?

a) 0.100 M NaOH = 50.00 mL of 0.100 M NaOH

b) 0.0500 M Sr(OH)2 =  100.00 mL of 0.

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Answer:

what are the options to the question

Answer:

b and c

Explanation:

just took it on edge :)

Answer:

Alpha decay.

Explanation:

When an element undergoes alpha decay, the resulting daughter nuclei will have a decrease of 4 in the mass number and a decrease of 2 in the atomic number.

In the attached photo, 235 92U undergo alpha decay to produce 231 90Th.

Comparing the mass number and atomic number of 235 92U with that of 231 90Th we can see that the mass of 231 90Th reduced by 4 and the atomic number reduce by 2 indicating that the parent nucleus is undergoing alpha decay.

Answer:

Alpha emission

Explanation:

The alpha particle is akin to a helium nucleus hence it is often referred to as a helium nucleus. The alpha particle has four mass units and a charge if +2.

Alpha emission is one of the emissions undergone by radioactive nuclei. When an atom undergoes alpha emission, it is easy to notice because the mass number of the nucleus decreases by four while its atomic number decreases by two. The daughter nucleus is now found two places behind its parent in the periodic table.

An example of alpha emission is shown below;

23592U→42He+23190Th

Thorium is four mass units less than U-235 and two places behind uranium in the periodic table as explained above.

The water and the solutes leave the capillaries at the arterial end because the blood pressure is the greater than the osmotic pressure at the arterial end.

The blood pressure is the greater than the osmotic pressure at the arterial end and the water molecules  and the solutes leave the capillaries at the arterial end. At the arterial end of capillary, the blood pressure is exceeds the limit of the the osmotic pressure, that will causes the  net movement of the fluid out of the capillary.

Thus, due to the higher blood pressure than the osmotic pressure the solutes and the water leaves the artial end.

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Answer:

this lesson you learned that a chemical symbol is a shorthand way to represent an element and that each element on the periodic table has a unique chemical symbol. Chemical symbols are used to standardize the 'language of chemistry' and to identify elements and atoms in a chemical formula easily.23-Dec-2015

Answer:

Assume that you have a 100.0 g sample, and convert

the percentages to grams.

for C: 60.0% x 100.0 g = 60.0 g C

for H: 13.4% x 100.0 g = 13.4 g H

for O: 26.6% x 100.0 g = 26.6 g O

Explanation:

We can assume that room temperature is 25 °C.

The melting point of a pure substance is the temperature at which it changes state from solid to liquid. The metling point of our substance is -187 °C. Since the room temperature is 25 °C we can say that it won't be solid. At least it will be liquid.

The boiling point of a pure substance is the temperature at which it changes state from liquid to gas. The boiling point of our substance is 42 °C. At room temperature we are under that temperature, so it won't convert into a gas. It will remain as a liquid also.

Since room temperature is between the boiling and melting point of our substance, the physical state is liquid.

Answer: liquid

0.20 M NH₄, and 0.20 M HCI and  0.20 M NH₄, and 0.10 M HF are  combinations  that can be used to make a buffer. Thus option A and C are correct.

A buffer solution is an acid or a base aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa.Its pH changes very little when a small amount of strong acid or base is added to it.

Buffer solutions are used as a means of keeping pH at a nearly constant value in a wide variety of chemical applications. In nature, there are many living systems that use buffering for pH regulation. For example, the bicarbonate buffering system is used to regulate the pH of blood, and bicarbonate also acts as a buffer in the ocean.

As the combination of HCl and NH₄, and NH₄ and HF   are  combinations  that can be used to make a buffer. Thus option A and C are correct.

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Answer:

agua

Explanation:

por que estamos en la planeta