The amplitude of the electric field of the light wave is \({eq}\boxed{5.47 \times 10^4 V/m} {/eq}.\)
The electric field of the light wave refers to the electric vector part of the electromagnetic wave. The amplitude of the electric field of the light wave can be calculated using the formula given below;\({eq}\boxed{E_0 = \sqrt{\frac{2P}{\pi c\epsilon_0 A^2}}} {/eq}\)
Where,\({eq}E_0 {/eq}\) is the amplitude of the electric field of the light wave.\({eq}P {/eq}\) is the power of the light wave. \({eq}c {/eq}\) is the speed of light.\({eq}\epsilon_0 {/eq}\) is the permittivity of the free space. \({eq}A {/eq}\) is the diameter of the laser beam.
We obtain the following by substituting the specified values in the formula:
eq begin aligned\(E_0 &= sqrt\) frac 2 times 2.0 times \(10-3 pi\) times 3 times 10-8 times 8.85 times 10-12 times
\((1.5 times 10-3/2)\) times 2 and equals 5.47 times 10-4 V/m with end alignment and /eq.
As a result, the electric field of the light wave has an amplitude of \(5.47 × 104 V/m x eq\).
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so I'm 6'0 and I'm in high school and I'm really good at football and basketball but I only want to choose one what do yall think
Answer:basketball
Explanation: football is a one way ticket to brain damage
Apply Newton’s second law to calculate the frictional force needed to hold a 15 g pen in your fingers and keep it from falling
Answer:
0.1962N.
Explanation:
Weight is a force, so we use newtons second law which states F=ma. So the weight of a watermelon on earth is 2kg x 9.81m/s², which is 19.62N (newtons). On the moon it weighs 2 x 1.63 which is 3.26N.
The weight of the pen is 0.02 x 9.81, which is 0.1962N. If the pen is not to fall the frictional force needs to be equal to this force,
so the answer is 0.1962N.
(Hope this helps can I pls have brainlist (crown)☺️)
find the weight of an astronaut whose mass is 75 kg on the moon
if you immerse an object into a known mass of water, the measured mass of the water will _____, and will be equal to the mass of the water displaced by the immersed object.
Answer: decrease
Explanation: it does
when the zinc ball on the charged electroscope is illuminated with ultraviolet light, the leaves of the electroscope collapse. was the electroscope charged positive or negative?
Based on the given scenario, we can infer that the electroscope was charged positively.
Electroscope is the device which is used to sense the presence of the electric charge on a body.
It is a simple device consisting of a metal ball that is attached by a conductor to two thin leaves of metal foil protected from air disturbance in a jar.
The image of electroscope is attached below.
We know that, the same charge repulse each other. Thus in the electroscope, when the ball is touched by a charged body, the leaves that normally hang straight down spread apart.
When the zinc ball on the charged electroscope is illuminated with ultraviolet light, the electrons from the zinc ball get excited and jump to the metal leaves, neutralizing the positive charge.
This causes the leaves to collapse, indicating a loss of charge.
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The answer is 84N, but what is the mass and weight calculation?
Answer:
weight= density ×volume× 9.8
mass=density×volume
Explanation:
\(weight = 0.12 \times 0.04 \times 0.04 \times 3.14 \times 13600 \\ \times 9.8 = 80.351 \: n \\ \\ mass = 0.12 \times 0.04 \times 0.4 \times 3.14 \times 13600 = \\ = 8.199 \: kg\)
what is the difference between a 4x100 and a 4x400 relay
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.8 partsimillion (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 990 samples is 5.7 pprm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 1 of 5 : Enter the hypotheses: Answer 2 Points Keyboard shortcuts Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.8parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 990 samples is 5.7ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 2 of 5 : Enter the value of the z test statistic. Round your answer to two decimal places. Our environment is very sensitive to the amount of ozonein the upper atmosphere. The level of ozone normaly found is 5.8partsimillion(ppm).A researcher believes that the current ozone level is at an insufficient kevel. The mean of 990 samples is 5.7ppm. Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 3 of 5 : 5 pecify if the test is one talled or twotalled. Answer 2 Points Keyboard Shortcuts One-Taileditest Two-Tailed Test Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.8 parts/million (pprn). A researcher believes that the current ozone level is at an insufficient level. The mean of 990 samples is 5.7ppm. Assume the standard deviation is: known to be 1.1. Does the data support the claim at the 0.02 fevel? Step 4 of 5 : Enter the decision rule Answerkow to enteryour answer fopens in hewiviouat 2. Points Reject H 0
if z< Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.8 parssimillion (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 990 samples is 5.7 ppmi Assume the standard deviation is known to be 1.1. Does the data support the claim at the 0.02 level? Step 5 of 5 : Enter the condusion. Answer 2 Points Keybosrd Shortcuis Reject Null Hypothesis Fail to Reject NullHypothesis
Hypotheses
Null Hypothesis (H₀): The current ozone level is not significantly different from the normal level of 5.8 ppm.
Alternative Hypothesis (H₁): The current ozone level is significantly lower than the normal level of 5.8 ppm.
Z-test statistic
To calculate the z-test statistic, we use the formula:
z = (sample mean - population mean) / (standard deviation / √sample size)
Given:
Sample mean (x) = 5.7 ppm
Population mean (μ) = 5.8 ppm
Standard deviation (σ) = 1.1
Sample size (n) = 990
Plugging in the values:
z = (5.7 - 5.8) / (1.1 / √990)
z ≈ -2.28
Type of test
This is a one-tailed test. We are interested in whether the ozone level is significantly lower, not higher, than the normal level.
Decision rule
Since the significance level is 0.02, we reject the null hypothesis if the z-test statistic is less than the critical value corresponding to a 0.02 (2%) one-tailed significance level.
Conclusion
The z-test statistic value of -2.28 falls in the critical region and is less than the critical value for a 0.02 (2%) one-tailed test. Therefore, we reject the null hypothesis. The data supports the claim that the current ozone level is significantly lower than the normal level at the 0.02 level.
In summary, the data provides evidence to support the researcher's claim that the current ozone level is insufficient at a significance level of 0.02. The calculated z-test statistic of -2.28 falls in the critical region, leading to the rejection of the null hypothesis.
This suggests that there is a significant difference between the observed sample mean of 5.7 ppm and the expected population mean of 5.8 ppm. The ozone level appears to be lower than normal, warranting further attention and investigation.
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A cannonball is launched horizontally from the top of a 166 m
cliff with an original speed of 35.9 m/s.
Determine the horizontal displacement (in m) of the cannonball.
The horizontal displacement of the cannonball is 65.75 meter.
What is speed?Speed is characterized as the rate at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
original speed: u= 35.9 m/s.
acceleration due to gravity: g = 9.8 m/s².
Initial height of the cannonball = 166 m.
Hence, the horizontal displacement of the cannonball = u²/2g
= 35.9²/(2×9.8) meter
= 65.75 meter.
so, the displacement of the cannonball is 65.75 meter.
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GIVING BRAINLIEST PLEASE HELP!!
-if you answer correctly ill give you brainliest which will give you 20pts-
Answer:
B
Explanation:
inside of a balloon is gas so it has room to move freely
Aniyah is driving down 7th street. She drives 150 meters in 25
seconds. Assuming she does not speed up or slow down, what
is her speed in meters per second?
Answer:
6m/s
Explanation:
formula used; S= d/t
the "7th Street"doesn't matter it's just apart of the scenario. The only thing that matters is the distance and time which we have. the speed in seconds is 6. I had the same question on my phsyics quiz lol.
Suppose a wheel is initially rotating at 10.0 rad/s while undergoing constant angular acceleration reaching a speed of 30.0 rad/s after 20.0 seconds have elapsed. How long after the initial time has the wheel undergone half of the angular displacement that it will have gone through during the entire 20.0 second interval?
a. 10.0 s
b. 12.4 s
c. 14.2 s
d. 15.0 s
The answer is B, according to the textbook but I don't know why
To solve this problem, you can use the equations of motion for rotational motion under constant acceleration:
ωf = ωi + αt --(1)
θ = ωit + 0.5αt^2 --(2)
where ωi is the initial angular velocity, ωf is the final angular velocity, α is the angular acceleration, t is the time elapsed, and θ is the angular displacement.
Using equation (1), we can find the angular acceleration of the wheel:
α = (ωf - ωi)/t
= (30.0 rad/s - 10.0 rad/s)/20.0 s
= 1.0 rad/s^2
Using equation (2), we can find the total angular displacement of the wheel during the 20.0 seconds:
θ = ωit + 0.5αt^2
= 10.0 rad/s × 20.0 s + 0.5 × 1.0 rad/s^2 × (20.0 s)^2
= 400.0 rad
To find the time at which the wheel has undergone half of this angular displacement, we can use equation (2) again:
θ/2 = ωit + 0.5αt^2
Rearranging and solving for t, we get:
t = [(-ωi) ± sqrt(ωi^2 + 2αθ)]/α
Since we are looking for a positive time, we take the positive root:
t = [(-10.0 rad/s) ± sqrt((10.0 rad/s)^2 + 2 × 1.0 rad/s^2 × 400.0 rad)]/1.0 rad/s^2
≈ 12.4 s
Therefore, the answer is B, 12.4 s.
Estimate the total mass of ocean on earth
A 400g mass object at rest is acted on by a 200 N net force for 12 seconds. What is it’s final velocity?
The answer is supposed to be 6000 m/s but I’m not sure how…
Explanation:
do we can say that the first step is finding the acceleration of the object. We do so by saying F = ma
so a = F/m
a = 500 m/s^2
we now have the time, acceleration and initial velocity.
so we can find the final velocity by using one of newtons equations which is: vf = vi + at
so:
vf = 0 + 500 × 12
vf = 6000
note that our initial velocity was zero since the object was initially at rest.
if you still have any doubt dont hesitate to ask for further help.
An object falls from a high building. Ignoring air resistance, what will its velocity be after 6 seconds of falling
Explanation:
Vf=Vi+at
reference frame,take down as positive in y- axis
Data
Vi=0m/s
Vf=?
a=g(9.8m/s2)
t=6s
Vf=0+9.8m/s2*6s
Vf=58.8m/s
The velocity of the object after falling for 6 s from a high building is 58.8 m/s
From the question given above, the following data were obtained:Initial velocity (u) = 0 m/s
Time (t) = 6 s
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?The velocity of the object after falling for 6 s can be obtained as follow:v = u + gtv = 0 + (9.8 × 6)
v = 0 + 58.8
v = 58.8 m/sTherefore, the velocity of the object after falling for 6 s is 58.8 m/s
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3. The total mechanical energy of the object at the highest point compared to its
total mechanical energy at the lowest point is
A. lesser
B. greater
C. equal
D. not related.
The total mechanical energy of the object at the highest point compared to its total mechanical energy at the lowest point is lesser. The correct answer is option A.
The total mechanical energy of an object is the sum of its potential and kinetic energy. When an object moves, it experiences changes in potential and kinetic energy. In simple terms, the total mechanical energy of an object is the energy that it possesses due to its position or motion. In general, when an object moves from its highest to the lowest point, its potential energy is at its maximum value while its kinetic energy is at its minimum value. At the highest point, the object has maximum potential energy and zero kinetic energy. At this point, the total mechanical energy of the object is equal to its potential energy. On the other hand, at the lowest point, the object has maximum kinetic energy and minimum potential energy. At this point, the total mechanical energy of the object is equal to its kinetic energy.Since the total mechanical energy at the highest point is equal to the potential energy only while the total mechanical energy at the lowest point is equal to the kinetic energy only, it is clear that the total mechanical energy at the highest point is lesser than the total mechanical energy at the lowest point. Therefore, the answer to the question is A.For more questions on mechanical energy
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Why Does Elasticity Matter?
Often, a lot of what is covered in courses has little application in the so-called "real world". In this discussion board, you need to post an entry to the discussion board stating why elasticity actually does matter in the everyday lives of businesses and consumers, using an example of a good or service as part of your explanation.
Part I
Using an example of a good or service, you will state why elasticity is applicable in the everyday lives of businesses and consumers. Please be clear in your explanation
Elasticity is of significant importance in the everyday lives of businesses and consumers as it helps them understand and respond to changes in prices and demand for goods or services. By considering elasticity, businesses can make informed decisions regarding pricing strategies, production levels, and resource allocation. Consumers, on the other hand, can assess the impact of price changes on their purchasing decisions and adjust their consumption patterns accordingly.
Elasticity, specifically price elasticity of demand, measures the responsiveness of consumer demand to changes in price. It indicates the percentage change in quantity demanded resulting from a one percent change in price. Understanding price elasticity allows businesses to determine how sensitive consumers are to changes in price and adjust their pricing strategies accordingly.
For example, let's consider the market for gasoline. Gasoline is a highly price-sensitive good, meaning that changes in its price have a significant impact on consumer demand. If the price of gasoline increases, consumers may reduce their consumption and seek alternatives such as carpooling or using public transportation. In this scenario, businesses need to consider the price elasticity of gasoline to predict and respond to changes in consumer behavior. They might lower prices to stimulate demand or introduce more fuel-efficient options to cater to price-conscious consumers.
In conclusion, elasticity matters because it provides valuable insights into the dynamics of supply and demand, enabling businesses and consumers to make informed decisions in response to price changes. By understanding elasticity, businesses can adapt their strategies to maintain competitiveness, while consumers can optimize their purchasing choices based on price sensitivity.
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QUESTION 3 Which of the following statements is not true for a solid conductor in electrostatic equilibrium? a. The excess charge resides solely on the outer surface of the conductor. b. The electric
field inside the conductor is zero. c. The electric potential inside the conductor is constant. d. The electric field just outside the electrostatic equilibrium conductor is perpendicular to its surface.
The excess charge resides solely on the outer surface of the conductor: This statement is true for a solid conductor in electrostatic equilibrium. In electrostatic equilibrium, the excess charge within a conductor redistributes itself on the outer surface of the conductor.
This happens because charges repel each other and seek to minimize their electrostatic potential energy. As a result, the excess charge spreads uniformly over the outer surface of the conductor.
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i need help on this 8th grade knowledge please
The spring of a toy car is wound by pushing the car
backward with an average force of 15 newtons through
a distance of 0.50 meter. How much elastic potential
energy is stored in the car's spring during this process?
The elastic potential energy stored in the car's spring during the process is 3.75 J
Determination of the spring constantFrom the question given above, the following data were obtained:
Force (F) = 15 NExtention (e) = 0.5 mSpring constant (K) =?K = F/e
K = 15 / 0.5
K = 30 N/m
Determination of the potential energySpring constant (K) = 30 N/mExtention (e) = 0.5 mPotential energy (PE) =?PE = ½Ke²
PE = ½ × 30 × 0.5²
PE = 15 × 0.25
PE = 3.75 J
Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J
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7.5 Joules is the amount of elastic potential energy stored in the car's spring during this process.
w=Fd
w=(15)(0.5)
w = 7.5
Help if u understand for a b c
Golf cart is moving 8 metre in 1 second
so, in 10 seconds it moves 8 × 10 = 80 m
a) velocity = 80/10 = 8 m/s
b) acceleration = v - u / t
= 8 - 0 / 10
= 0.8 m/s²
c) the displacement of the graph is increasing
I hope this answer is correct and helpful to you
where would you expect light waves to move faster?
a - in space
b- through an iceberg
c- under the sea
d- on a mountain top
Answer:
a
Explanation:
Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
When filling degenerate orbitals, electrons fill them singly first, with parallel spins. This way of filling orbitals known as.
The Hund's rule states that electrons fill degenerate orbitals with parallel spins when filling them singly first.
What exactly are protons and electrons?A subatomic particle having a negative charge is called an electron. Positively charged subatomic particles include protons. The strong nuclear force holds protons together in the atom's nucleus. A type of subatomic particle without charge is the neutron.
What is an example of an electron?The smallest atom-building block, the electron has a negative charge. A harmless element seems to have an equal amount of both electrons and protons. For instance, the hydrogen atom only has one proton and one electron. In contrast, the uranium atom has 92 protons.
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7. Calculate the force applied on an object if the Pressure exerted is 90 Pascal over an area of 900 cm2.
Answer:
Explanation: pressure = force / area
Rearrange to get: force = pressure x area. 900 cm2 = 0.09 m2
force = 90 x 0.09
= 8.1 N
how much work is being done if you use a 24N force over a distance of 5m
120 Joules is the work done when a force of 20 Newton is used over a distance 5 meters.
What is the amount work done ?Work done is simply the energy transfer that occur when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;
Work done = Force × distance
Given the data in the question;
Force applied = 24 N = 24 kgm/s²Distance = 5mWork done = ?To determine the work done, plug the given values into the formula above.
Work done = Force × distance
Work done = 24 kgm/s² × 5m
Work done = 120 kgm²/s²
Work done = 120 J
Therefore, the amount of work done is 120 J.
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lab number 14: sudden stops hurt newtons first law
Answer:
you want to know newtons first law here.
Explanation:
An object that is at rest stays at rest or stays in motion.
(a) A 10.0 g bullet is fired into a stationary block of wood (n = 5.00 kg). The bullet gets embedded in the wood, and the speed of the wood-and-bullet combination immediately after the collision is measured to be 0.600 m/s. What was the original speed of the bullet? 16) If the block of wood is originally prior to the collision is at rest at the edge of a frictionless table of height 1.00 m, how far away Ihorizontally away from the table's edge does the wood-and-bullet combination land? -. A railroad car of mass 2.50-104 kg is moving at a speed of 4.00 m/s. It collides and couples with three other coupled railroad cars, each of the same mass as the single car and moving in the same direction with an initial speed of 2.00 m/s. (a) What is the speed of the four cars after the collision? (b) How much energy is lost in the collision? Where does this energy go?
The collision is equal to the total momentum after the collision is 3.00 m/s. and The energy lost in the collision is \(E_{lost} = 1.25 \times 10^5 J\)
What is momentum?Momentum is a measure of an object's resistance to changes in its motion due to a force. It is the product of an object's mass and its velocity, and is represented by the equation p = mv, where p is momentum, m is mass, and v is velocity. Momentum is a vector quantity, which means it has both a magnitude and a direction. Momentum can be expressed in terms of an object's speed and direction of motion, as well as its mass.
This is because the momentum of the four cars is conserved, which means the total momentum before the collision is equal to the total momentum after the collision. This gives the equation:
\((2.50 \times 10^4 kg)(4.00 m/s) + (3 x 2.50 \times 10^4 kg)(2.00 m/s) = (4 \times 2.50 \times 10^4 kg)(V)\)
Solving this equation for V gives V = 3.00 m/s.
b) The energy lost in the collision is equal to the difference in kinetic energy before and after the collision, which is given by the equation:
\(E_{lost} = (1/2)(2.50 \times 10^4 kg)(4.00 m/s)^2 - (1/2)(4 \times 2.50 \times 10^4 kg)(3.00 m/s)^2\\E_{lost} = 1.25 \times 10^5 J\)
The energy that is lost in the collision is converted into thermal energy due to the friction of the cars as they collide, as well as sound energy as the collision creates sound waves.
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a. The original speed of the bullet is 300.6 m/s.
b. The horizontal distance travelled by the wood - bullet system is 0.27 m.
c. The speed of the four car after the collision is 1.75 m/s.
d. The energy loss after the collision is -196,875 J.
What is the original speed of the bullet?The original speed of the bullet is calculated as follows;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
u₁ is the initial speed of the bulletu₂ is the initial speed of the woodv is their common velocity after collisionm is the mass0.01u₁ + 5(0) = 0.6(0.01 + 5)
0.01u₁ = 3.006
u₁ = 3.006/0.01
u₁ = 300.6 m/s
The time of motion of the wood is calculated as follows;
t = √(2h/g)
t = √ (2 x 1 / 9.8)
t = 0.45 s
The horizontal distance travelled by the wood - bullet system is calculated s;
X = 0.45 s x 0.6 m/s
X = 0.27 m
The speed of the four car after the collision is calculated as follows;
(2.5 x 10⁴ x 4) + 3(2 x 2.5 x 10⁴) = v (4 x 2.5 x 10⁴)
175,000 = 100,000v
v = 1.75 m/s
The initial kinetic energy of the cars is calculated as;
K.Ei = ¹/₂ x 2.5 x 10⁴ x 4² + 3 (¹/₂ x 2.5 x 10⁴ x 2²)
K.Ei = 350,000 J
The final kinetic energy of the cars;
K.Ef = 4 (¹/₂ x 2.5 x 10⁴ x 1.75²)
K.Ef = 153,125 J
Loss in energy = K.Ef - K.Ei
= 153,125 J - 350,000 J
= -196,875 J
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1) Studies of sunquakes, or helioseismology, have revealed that 1) _______ A) the Sun vibrates only on the surface. B) our mathematical models of the solar interior are fairly accurate. C) ʺsunquakesʺ are caused by similar processes that create earthquakes on the earth. D) the Sun generates energy by nuclear fusion. E) neutrinos from the solar core reach the solar surface easily.
Studies of sunquakes, or helioseismology, have revealed that our mathematical models of the solar interior are fairly accurate. The correct option is (B).
Helioseismology is the study of the Sun's internal structure and dynamics by analyzing its oscillations.
These oscillations, often referred to as sunquakes, are caused by sound waves trapped and bouncing within the Sun. By studying the properties and behavior of these waves, scientists can gain valuable insights into the solar interior.
Through helioseismology, scientists have found that our mathematical models of the Sun's interior, based on principles of physics and stellar evolution, align quite well with the observed data.
The oscillation patterns and frequencies detected from the Sun match the theoretical predictions, providing confidence in our understanding of the Sun's internal structure, composition, and energy generation mechanisms.
A) the Sun vibrates only on the surface.
Helioseismology studies have revealed that the Sun vibrates not only on its surface but throughout its interior as well. Therefore, option A is incorrect.
Overall, helioseismology has contributed significantly to our knowledge of the Sun's dynamics and has validated our mathematical models, making option B the correct answer.
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Một vật có khối lượng 2 kg rơi tự do xuống đất trong khoảng thời gian 0,5 s. Độ biến thiên động lượng của vật trong khoảng thời gian đó là bao nhiêu ? Cho g = 10 m/s2.
Answer: The change in momentum is +20 kg.m/s
Explanation:
To calculate the final velocity of object, we use the first equation of motion:
\(v=u+at\)
where,
v = final velocity
u = initial velocity = 0 m/s
a = acceleration = \(10m/s^2\)
t = time = 0.5 s
Putting values in above equation, we get:
\(v=0+(10\times 0.5)\\\\v=5m/s\)
Momentum is defined as the product of the mass and velocity of an object. It is given by the equation:
\(p=mv\)
where,
p = momentum
m = mass of object = 2 kg
Let the upward velocity be positive and the downward velocity be negative
When the object is dropped, the velocity is downward
v = -5m/s
Initial momentum = \(2kg\times (-5m/s)=-10kg.m/s\)
When the object is bounced back, the velocity is upward
v = +5m/s
Final momentum = \(2kg\times (+5m/s)=10kg.m/s\)
Change in momentum = Final - Inital
Change in momentum = [10 - (-10)] = +20 kg.m/s
Hence, the change in momentum is +20 kg.m/s