Answer:
The inner diameter is 57.3 cm
Explanation:
The inner diameter of the hollow spherical iron shell can be found using the weight of the sphere (\(W_{s}\)) and the weight of the water displaced (\(W_{w}\)):
\( W_{s} = W_{w} \)
\( m_{s}*g = m_{w}*g \)
\( D_{s}*V_{s} = D_{w}*V_{w} \)
Where D is the density and V is the volume
\( D_{s}*\frac{4}{3}\pi*(\frac{d_{o}^{3} - d_{i}^{3}}{2^{3}}) = \frac{4}{3}\pi*(\frac{d_{o}}{2})^{3} \)
Where \(d_{o}\) is the outer diameter and \(d_{i}\) is the inner diameter
\( D_{s}*(d_{o}^{3} - d_{i}^{3}) = d_{o}^{3} \)
\( D_{s}*d_{i}^{3} = d_{o}^{3}(D_{s} - 1) \)
\( 7.87*d_{i}^{3} = 60.0^{3}(7.87 - 1) \)
\( d_{i} = 57.3 cm \)
Therefore, the inner diameter is 57.3 cm.
I hope it helps you!
What happens to a positive charge due to a negative charge? And what happens to two charges that are positive?
We have the next diagram
When the signs are opposite, the charges experience an attractive force
When the both charge is positive the force is the force is repulsion
Pls help need answers
The angular diameter of Mars in radians and in arc minutes and the evaluation of the capability of human eyes to resolve Mars of diameter 6.8 × 10³ km, located 5.5 × 10⁷ km away are as follows;
(d) The angular diameter of Mars is 1.23\(\overline{63}\) × 10⁻⁴ rad
(e) The angular diameter in arc minutes is about 0.425 arc minute.
Optical aid is required for humans to resolve Mars.What is an angular diameter?The angular diameter is an apparent dimension used to describe the size of a circular object, observed from a specified point of view or location.
The diameter of Mars = 6,800 km
The closest distance between Mars and Earth when Mars gets closest to Earth = 55,000,000 km
(d) The angular diameter of Mars can be obtained by finding the vertex angle formed by the diameter of Mars and the ray from the observer on Earth to the left and right extremities of Mars using the trigonometric ratio of tangent as follows;
Angular diameter = 2 × arctan((6,800/2)/55,000,000) = 0.000123636363 radians
The angular diameter of Mars as observed from Earth is 1.23\(\overline{63}\) × 10⁻⁴ radians
(e) 1 radians = 3437.75 arc minute
0.000123636363 radians = 0.000123636363 × 3437.75 arc minute
0.000123636363 × 3437.75 ≈ 0.425
Therefore;
0.000123636363 radians ≈ 0.425 arc minute
The specified level of detail that the human eye can resolve is one arc minute (1')
The apparent angular diameter of Mars, which is about 0.425 arc minute is lesser than the angular limit of detail of one arc minute that the eye can resolve, therefore, humans can not resolve Mars without optical aid.
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A 85 kg skydiver parachutes from a stationary helicopter at a height of 1,200 m above the ground. After the
skydiver reaches a predetermined speed, the parachute opens, slowing the skydiver down. With the parachute
open, the skydiver reaches a terminal velocity of 3.5 m/s.
Calculate the work done by air resistance during the descent from the height of the helicopter to the ground.
The work done by air resistance during the descent from the height of the helicopter to the ground is 520.2 J.
Acceleration of the skydiver
The acceleration of the skydiver is calculated as follows;
v² = u² + 2as
v² = 0 + 2as
v² = 2as
a = (v²)/(2s
a = (3.5²)/(2 x 1200)
a = 0.0051 m/s²
Work done by air resistanceW = Fd
W = (ma)d
W = (85 x 0.0051) x 1200
W = 520.2 J
Thus, the work done by air resistance during the descent from the height of the helicopter to the ground is 520.2 J.
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A 0.450-kg ice puck, moving east with a speed of 5.34 m/s , has a head-on collision with a 0.990-kg puck initially at rest. Assume that the collision is perfectly elastic.1. What is the speed of the 0.450-kg puck after the collision?2. What is the direction of the velocity of the 0.450-kg puck after the collision?3. What ise the speed of the 0.990-kg puck after the collision?4. What is the direction of the velocity of the 0.990-kg puck after the collision?
(1) -2.0025m/s.
(2) It moves west.
(3) 3.3375m/s.
(4) It moves east.
Explanation:
Assuming the collision occurred in an isolated system. This means that total momentum of the system of pucks is conserved. Since no external forces are acting on these pucks, the momentum of the pucks before collision is equal to the momentum of the pucks after collision. i.e
(p₁)₀ + (p₂)₀ = (p₁)₁ + (p₂)₁ -------------(i)
Where;
(p₁)₀ = momentum of the 0.45kg puck before collision
(p₂)₀ = momentum of the 0.990kg puck before collision
(p₁)₁ = momentum of the 0.45kg puck after collision
(p₂)₁ = momentum of the 0.990kg puck after collision
But;
(p₁)₀ = m₁ u₁
[m₁ = mass of the 0.45kg, u₁ = speed of the 0.45kg before collision]
(p₂)₀ = m₂u₂
[m₂ = mass of the 0.990kg, u₂ = speed of the 0.990kg before collision]
(p₁)₁ = m₁v₁
[m₁ = mass of the 0.45kg, v₁ = speed of the 0.45kg after collision]
(p₂)₁ = m₂v₂
[m₂ = mass of the 0.990kg, v₂ = speed of the 0.990kg after collision]
Equation (i) then becomes;
m₁ u₁ + m₂u₂ = m₁v₁ + m₂v₂ ----------------(ii)
From the question:
m₁ = 0.450kg
u₁ = +5.34m/s [Taking east direction as positive]
m₂ = 0.990kg
u₂ = 0m/s [since the second puck is initially at rest]
Substitute these values into equation (ii)
(0.450 x 5.34) + (0.990 x 0) = 0.45 v₁ + 0.990 v₂
2.403 + 0 = 0.45 v₁ + 0.990 v₂
2.403 = 0.45 v₁ + 0.990 v₂ ------------------(iii)
Also, since the collision is perfectly elastic, it means that the kinetic energy is conserved. i.e the total kinetic energy before collision is equal to the total kinetic energy after collision.
=> \(\frac{1}{2}\)m₁ u²₁ + \(\frac{1}{2}\)m₂u²₂ = \(\frac{1}{2}\)m₁v²₁ + \(\frac{1}{2}\)m₂v²₂
Substitute the necessary values into the above equation:
[\(\frac{1}{2}\) x 0.45 x 5.34²] + [0] = [\(\frac{1}{2}\) x 0.45 x v²₁] + [\(\frac{1}{2}\) x 0.990 x v²₂]
[6.41601] = [0.225 x v²₁] + [0.495 x v²₂] ------------------(iv)
Now let's solve equations (iii) and (iv) simultaneously
2.403 = 0.45 v₁ + 0.990 v₂
6.41601 = 0.225 x v²₁ + 0.495 x v²₂
let
v₁ = x
v₂ = y
2.403 = 0.45 x + 0.990 y ------------(5)
6.41601 = 0.225 x² + 0.495 y² -------------(6)
From equation (5), make x subject of the formula
2.403 = 0.45x + 0.990y
0.45x = 2.403 - 0.990y [divide through by 0.45]
x = 5.34 - 2.2y ----------------(m)
Substitute x into equation (6)
6.41601 = 0.225 (5.34 - 2.2y)² + 0.495 y² [expand bracket]
6.41601 = 0.225 [28.5156 - 23.496y + 4.84y²] + 0.495 y² [remove bracket]
6.41601 = 6.41601 - 5.2866y + 1.089y² + 0.495 y²
1.584y² - 5.2866y = 0
y(1.584y - 5.2866) = 0
y = 0 or 1.584y - 5.2866 = 0
y = 0 or 1.584y = 5.2866
y = 0 or y = 3.3375
Since y = v₂ cannot be zero because the puck will definitely move after collision, the second value of y = 3.3375 is considered.
Substitute this value into equation (m)
x = 5.34 - 2.2y
x = 5.34 - 2.2(3.3375)
x = 5.34 - 7.3425
x = -2.0025
Therefore,
x = v₁ = -2.0025m/s
y = v₂ = 3.3375m/s
(1) From the analyses above, the speed of the 0.450kg puck after collision is -2.0025m/s.
(2) Since the speed is negative, it shows that the 0.45kg puck moves opposite the direction at which it was moving before collision. It moves west.
(3) The speed of the 0.990kg puck after collision is 3.3375m/s.
(4) Since the speed is positive, it shows that the 0.990kg puck moves east. Remember that east has been taking as the positive direction.
The speed of a bus increases uniformly from
15 ms- to 60 ms in 20 seconds. Calculate
a. the average speed,
b. the acceleration,
C. the distance travelled during the entire
period The speed of a bus increases uniformly from
15 ms- to 60 ms in 20 seconds. Calculate
a. the average speed,
b. the acceleration,
C. the distance travelled during the entire
period
Explanation:
a. For constant acceleration:
v_avg = ½ (v + v₀)
v_avg = ½ (60 m/s + 15 m/s)
v_avg = 37.5 m/s
b. a = (v − v₀) / t
a = (60 m/s − 15 m/s) / 20 s
a = 2.25 m/s²
c. x = v_avg t
x = (37.5 m/s) (20 s)
x = 750 m
The lowest point in Death Valley is 85 m below sea level. The summit of nearby Mt. Whitney has an elevation of 4420 m above sea level.
The difference in the elevation is 4505 meters.
What is the difference in the elevation?A geographic location's elevation is its height above or below a fixed reference point, most commonly a reference geoid, which is a mathematical model of the Earth's sea level as an equipotential gravitational surface.
Elevations are classified into four types: front elevation, side elevation, rear elevation, and split elevation.
In this case, the lowest point in Death Valley is 85 m below sea level. The summit of nearby Mt. Whitney has an elevation of 4420 m above sea level. The difference will be:
= Highest point - Lowest point
= 4420 - (-85)
= 4420 + 85
= 4505 m
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Complete question
The lowest point in Death Valley is 85 m below sea level. The summit of nearby Mt. Whitney has an elevation of 4420 m above sea level. What is the difference in the elevation?
what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
A basin surrounding a drain has the shape of a circular cone opening upward, having everywhere an angle of 35.0° with the horizontal. A 25.0-g ice cube is set sliding around the cone without friction in a horizontal circle of radius R. (a) Find the speed the ice cube must have as a function of R. (b) Is any piece of data unnecessary for the solution? Suppose R is made two times larger. (c) Will the required speed increase, decrease, or stay constant? If it changes, by what factor? (d) Will the time required for each revolution increase, decrease, or stay constant? If it changes, by what factor? (e) Do the answers to parts (c) and (d) seem contradictory? Explain.
According to the information we can infer that the decrease in speed is offset by the increase in radius.
How to calculate the speed the ice cube must have as a function of R?To calculate the speed the ice cube we have to consider that the gravitational force on the ice cube is balanced by the normal force provided by the cone. So, the speed of the ice cube must be such that the centripetal force equals the gravitational force.
In this case, to find the speed of the ice cube let M be the mass of the ice cube and r be the radius of the circular path. The gravitational force on the ice cube is given by Fg = Mg, where:
g = acceleration due to gravity.
The centripetal force is given by Fc = Mv^2/r, where:
v = speed of the ice cube
Setting Fg = Fc, we get:
Mg = Mv^2/rSolving for v, we get:
v = sqrt(gr)
Is any piece of data unnecessary for the solution?No piece of data is unnecessary for the solution.
Will the required speed increase, decrease, or sttay constant?According to the information, when R is made two times larger, the required speed will decrease. For example:
From part (a), v is proportional to the square root of R. Therefore, if R is doubled, v will be multiplied by the square root of 2, which is approximately 1.414.
Will the time required for each revolution increase, decrease, or stay constant?To know if the time required for each revolution will increase, decrease or stay constant we have to consider that shen R is made two times larger, the time required for each revolution will increase. To see this, note that the period T of the circular motion is given by:
T = 2πr/v
Do the answers to part C and D seem contradictory?According to the information, the answers to parts (c) and (d) are not contradictory because the decrease in speed is offset by the increase in radius, resulting in a longer period of revolution. The net effect is that the ice cube will travel the same distance in each revolution, so the total time required for one complete revolution will remain constant.
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lesson 14: bisect it cool down: going both ways again explain the difference between these 2 statements: given figure where segment is congruent to segment , prove that: 1. if ray is the angle bisector of angle , and is the midpoint of segment , then ray passes through . 2. if is the midpoint of segment , and ray bisects angle .
Make a section of a line AB = 5 cm. 2. Draw two arcs, one above and one below AB, with a radius of any bigger than 2.5 cm and with the compass set at A bisects.
A straight line drawn from a triangle's vertex to its opposite side that divides an angle into two equal or congruent angles is called an angle bisector. Triangle Angle Bisector Theorems The internal and exterior angle bisector theorems and their contrapositions are shown in the table below.
A line is divided into two equal halves by a bisector. Therefore, when we refer to the perpendicular bisector of a line segment AB, we mean that it bisects or divides AB into two equal halves.
A line is an angle bisector.
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A bubble of air has a diameter of 1 mm when it is 0.5 m under the surface of water ( coefficient of surface tension 0.073 N/m). Find the gauge pressure inside the bubble.
The gauge pressure inside the bubble. is -101310.4 Pa.
The negative sign shows that the pressure inside the bubble is lower than the atmospheric pressure. Hence, the bubble will rise to the surface of the water.
How do we calculate?We apply Laplace's law to find the absolute pressure inside the bubble:
ΔP = 2γ/r
where ΔP is the pressure difference across the curved surface of the bubble, γ is the coefficient of surface tension of water, and r is the radius of curvature of the bubble.
r = 0.5 mm = 0.0005 m
Substituting the given values, we have:
ΔP = 2 × 0.073 N/m ÷ 0.0005 m
ΔP = 14.6 × 10^(-3) Pa
The atmospheric pressure at sea level is approximately 101325 Pa. Therefore, the gauge pressure inside the bubble is:
P_gauge = ΔP - P_atm
P_gauge = 14.6 × 10^(-3) Pa - 101325 Pa
P_gauge = -101310.4 Pa
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A free falling asteroid is experiencing a force of gravity of 903 newtons. How much work, in joules, does gravity do on the asteroid over a distance of 126 meters?
Answer:
Workdone = 113778 Joules
Explanation:
Given the following data;
Force = 903N
Distance = 126m
To find the workdone;
Workdone = force * distance
Substituting into the equation, we have
Workdone = 903 * 126
Workdone = 113778 Joules
Therefore, the amount of work, in joules, the gravity did on the asteroid is 113778.
can someone answer these physical science questions please
1. The kinetic energy would be the same for the both balls.
2) As the ball gains potential energy, its speed will decrease.
What is kinetic energy?Kinetic energy is the energy possessed by an object due to its motion. The amount of kinetic energy an object has is dependent on its mass and velocity. An object with a greater mass and a higher velocity will have a higher kinetic energy than an object with a smaller mass and lower velocity.
The increase in the potential energy as the ball reaches the maximum height would imply that the ball would become stationary for some time and the speed will decrease.
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A train car with a mass of 10kg and speed of 10 m/s is traveling to the right. Another train car with a mass of 20kg is moving to the left at -40 m/s. After the collision, the 10 kg train car is now moving at -20 m/s and we need to find the Velocity of the 20 kg train car.
When two particles collide and the masses of the particles are given, as well as the initial and final velocity of one particle and one of the velocities of the second particle, then the remaining velocity of the second particle is given by the expression:
\(v_2^{\prime}=\frac{m_1v_1+m_2v_2-m_1v_1}{m_2}\)Which can be deduced from the Law of Conservation of Linear Momentum.
In the given problem, the initial and final velocities of the train car with mass 10kg are given, as well as the initial velocity of the 20kg car:
\(\begin{gathered} m_1=10kg \\ v_1=10\frac{m}{s} \\ v_1^{\prime}=-20\frac{m}{s} \\ \\ m_2=20kg \\ v_2=-40\frac{m}{s} \\ v_2^{\prime}=\text{ unknown} \end{gathered}\)Replace those values into the given equation to find v₂':
\(\begin{gathered} v_2^{\prime}=\frac{(10kg)(10\frac{m}{s})+(20kg)(-40\frac{m}{s})-(10kg)(-20\frac{m}{s})}{20kg} \\ \\ \Rightarrow v_2^{\prime}=-25\frac{m}{s} \end{gathered}\)Therefore, the velocity of the 20kg train car after the collision, is: -25 m/s.
According to Ohm’s law, which combination of units is the same as the unit for resistance? volt ÷ ampere ampere × volt volt + ampere ampere ÷ volt
Answer:
volt ÷ ampere
Explanation:
The mathematical form of Ohms law is given by :
V = IR
Where V is voltage
I is current
R is resistance
\(R=\dfrac{V}{I}\)
The unit of voltage is volt and that of current is ampere
Unit of resistance :
\(R=\dfrac{\text{volt}}{\text{ampere}}\)
So, volt ÷ ampere is the same as the unit of resistance. Hence, the correct option is (a).
Answer:
The answer is: volt ÷ ampere
Explanation:
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What is the net force of particle q1
The net force on particle 1 or charge 1 is determined as 32.73 N.
What is the net force on particle1?The net force acting on charge 1 is calculated by applying Coulomb's law as shown below;
Force due to charge 2;
F12 = (9 x 10⁹ x 5.16 x 10⁻⁶ x 8.99 x 10⁻⁶)/ (0.22²)
F12 = 8.625 N
Force due to charge 3;
F12 = (9 x 10⁹ x 89.9 x 10⁻⁶ x 8.99 x 10⁻⁶)/ (0.55²)
F12 = 24.1 N
The net force on charge 1 is calculated as;
F (net) = 8.625 N + 24.1 N
F (net) = 32.73 N
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The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is (a) the speed of the roller coaster at the top of the loop (in m/s) if the radius of curvature there is 13.0 m and the downward acceleration of the car is 1.50 g, and (b) the minimum speed necessary for the coaster to complete the loop without falling off the track?
the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s
the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.
Explanation to the Roller Coaster Speed Calculation(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).
So, we can rearrange the equation to solve for v: v = sqrt(ar)
Plugging in the values, we get: v = sqrt(1.5g * 13m)
v = sqrt(22.5 * 9.8)
v = sqrt(219.5)
v = 14.8 m/s
(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).
So, we can rearrange the equation to solve for v: v = sqrt(ar)
Plugging in the values, we get: v = sqrt(g * 13m)
v = sqrt(9.8 * 13m)
v = sqrt(127.4)
v = 11.3 m/s
So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.
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In hiking, what fitness component is required of you
Which of the following is NOT true about the mass of an object?
A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.
Answer:
B) Mass is a measurement of force
Explanation:
Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.
poem on physical education and the importance of participating in physical education?
Answer:
AS USUAL SHE DID NOT TAKE PART
I’ll never forget what’s her name
A PE teacher and ogre she became
For I was such a sickly child
it really made this ogre wild
Held in my hand a medical certificate
exempted from all things physical
with Rheumatic Fever and St Vitus’ Dance
for me to take part ~ there was no chance
Instead I assisted the Deputy Head
with clerical duties I helped him instead
But clearly this really annoyed her
As she gave me her evil stare
She appeared to be looking right through me
No words were spoken ~ was I even there
Each and every year she wrote
inside my school report
A snide remark that ended with
“as usual she did not take part”
For I was told such illnesses
Could leave me with a weakened heart
And so upon Doctor’s orders
in PE I was not to take part
I can still see her face
As she filled me with fear
No compassionate words
from her lips I could hear
Whilst illnesses kept me off school for a year
It’s time I let go of this nasty so and so
For she left planet Earth a long time ago
And my heart ~ it still beats
I’m so glad to be here
With a smile on my face
I have no one to fear
Answer:
Explanation:
Physical education is important because it keeps you healthy and living longer
what is one way to increase the momentum of an object
1 . decrease aerodynamics
2. decrease velocity
3. increase friction
4. increase force
Explanation:
Momentum = mv so the most likely way to increase an object's momentum would be to increase its velocity
A ball is launched from the surface of a planet. Air resistance and other frictional forces are neglected. The graph shows the position of the ball every 0.20 s.
a. Use this graph to determine:
I. The components of the initial velocity of the ball
II. The angle to the horizontal the ball was launched at
III. The acceleration of free fall on this planet.
b. Make a copy of the graph and draw two arrows to represent the velocity and the acceleration vectors of the ball at t = 1.0 s.
c. The ball is now launched under identical conditions from the surface of a different planet where the acceleration due to gravity is twice as large. Draw the path of the ball on your graph.
The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.
What are the velocities ?Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.
What is time ?Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.
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TRUE or FALSE: You maintain a healthy body composition by balancing your food intake with your exercise
Answer:
Summary: Nutrition and exercise are critical for improving body composition. Keeping your calories, fiber and protein in check is a good first step. All exercise can help with fat loss, but weight training is the best way to increase muscle mass.
Explanation:
Answer: TRUE
Explanation:
A watermelon seed has the following coordinates: x = -7.1 m, y = 5.6 m, and z = 0 m. Find its position vector as (a) a magnitude and (b)
an angle relative to the positive direction of the x axis. If the seed is moved to the xyz coordinates (4.7 m, Om, O m), what is its
displacement as (c) a magnitude and (d) an angle relative to the positive direction of the x axis? Put the angles in the range (-180°, 180°]
Who has so much time to measure the fμcking seeds?
A system absorbs 1500J of heat energy from its surroundings. Determine the change in the internal energy of the system when: (i) system performs 2200J of work on the surroundings (ii) the surroundings perform 2200J of work on the system
(a) When the system does work on the surroundings, the change in the internal energy is - 700 J.
(b) When the surroundings performs work on the system, the change in the internal energy is 3,700 J.
What is the change in the internal energy of the system?
The change in the internal energy of the system is determined by applying the first law of thermodynamics as shown below.
Mathematically, the formula for first law of thermodynamics is given as;
ΔU = Q ± W
where;
ΔU is the change in the internal energy of the systemQ is the heat gain or loss of the systemW is the work done by or done on the systemWhen the system does work on the surroundings, the equation is given as;
ΔU = Q - W
ΔU = 1500 J - 2200 J
ΔU = -700 J
When the surroundings performs work on the system, the equation is given as;
ΔU = Q + W
ΔU = 1500 J + 2200 J
ΔU = 3,700 J
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2 cards with different masses are both moving to the right. The mass and initial velocity of each card are shown in the diagram below the carts that collide and stick together into the boxes show drag and drop the. Speed in direction of the stock together carts after collision.
The speed of the carts after collision will depend on their combined mass and initial velocity.
The collision between the two carts with different masses will result in the formation of a single object with a combined mass. The speed of the resulting object will depend on the momentum of the individual carts before the collision, which is determined by their mass and initial velocity.
The conservation of momentum principle states that the total momentum of the system before the collision is equal to the total momentum of the system after the collision. Therefore, the speed of the resulting object will be determined by the combined mass of the carts and their initial velocity before the collision.
The heavier cart will contribute more to the combined mass, and its initial velocity will have a greater impact on the resulting speed.
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A contestant in a winter games event pulls a 36.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in Figure 4.29(b). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03.
Figure 4.29
(a) Calculate the minimum force F he must exert to get the block moving.
40.873
(b) What is its acceleration once it starts to move, if that force is maintained?
m/s2
(a) The minimum force F he must exert to get the block moving is 38.9 N.
(b) The acceleration of the block is 0.79 m/s².
Minimum force to be applied
The minimum force F he must exert to get the block moving is calculated as follows;
Fcosθ = μ(s)Fₙ
Fcosθ = μ(s)mg
where;
μ(s) is coefficient of static frictionm is mass of the blockg is acceleration due to gravityF = [0.1(36)(9.8)] / [(cos(25)]
F = 38.9 N
Acceleration of the blockF(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32
a = F(net)/m
a = 28.32/36
a = 0.79 m/s²
Thus, the minimum force F he must exert to get the block moving is 38.9 N.
The acceleration of the block is 0.79 m/s².
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Convert from scientific notation to standard form
9.512 x 10-8
Answer:
0.00000009512
Explanation:
Scientific notation is a very useful and abbreviated way of writing quantities that are very large or small. It consists of placing the number with an integer and multiplying by an exponent to arrive at the same number.
let's pass the number 9,512 10⁻⁸ to decimal notation
9,512 / 10⁸ = 9,512 / 100000000
0.00000009512
As we see writing this number, it is very easy to make mistakes
the very act of observing a particle has a dramatic effect on its behaviour why do you think this is the case
Answer:
Explanation:
In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.
So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.
List two methods that can be used to reduce the effect of friction.
To reduce the firction between two objects or surfaces we can use the following methods:
• Make the surfaces or objects smoother. This comes from the fact that if the material is rougher then it will produce more friction while if the material is smoother the friction will decrease.
,• Lubricate the objects or surface. A lubricant can reduce the friction between two objects or surface.
,• Reduce the contact between the object or surfaces. The more contact there is the more friction it will make; that's why we use round wheels.
explain why the ray does not bend when it enters the semi circular glass block
The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.
Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.
Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.
Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.
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