a hot-air balloon can lift a weight of 6453 n (counting the balloon itself). the density of the air outside the balloon is 1.205 kg/m3. the density of the hot air inside the balloon is 0.9671 kg/m3. what is the volume of the balloon? (in m^3)

Answer:

Work Required = Potential Energy increase

PE = W H        where W is weight fo body and H the increase in height

P = PE / t - Work / time       definition of power

PE2 / PE1 = W H2 / W H1 = H2 / H1

Power 2 / Power 1 = (H2 / t) = (H1 / t)  = V2 / V1 = 3

Note that the distance lifted does not depend on the power because power is defined as work / time

Answer:

Explanation:

Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Momentum = Mass (M) * Velocity(V)

BEFORE COLLISION

Momentum of 0.25kg body moving at 1.0m/s = 0.25*1 = 0.25kgm/s

Momentum of 0.15kg body moving at 0.0m/s(body at rest) = 0kgm/s

AFTER COLLISION

Momentum of 0.25kg body moving at x m/s = 0.25* x= 0.25x kgm/s

x is the final velocity of the 0.25kg ball

Momentum of 0.15kg body moving at 0.75m/s(body at rest) =

0.15 * 0.75kgm/s = 0.1125 kgm/s

Using the law of conservation of momentum;

0.25+0 = 0.25x + 0.1125

0.25x = 0.25-0.1125

0.25x = 0.1375

x = 0.1375/0.25

x = 0.55m/s

Since the 0.15 kg ball moves off to the right after collision, the 0.25 kg ball will move at 0.55 m/s towards the right

1. The phone is moving with a velocity of 20.77 m/s before racking into pieces

2. The time taken for the ball to come back to their hand is 0.82 s

3. The maximum height reached by the batarang is 49.03 m

4. The cliff is 1016.06 m high

5. The object is moving with a velocity of –8.6 m/s after 2 s

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 22)

v² = 431.2

Take the square root of both side

v = √431.2

v = 20.77 m/s

We'll begin obtaining the time taken to reach the maximum height. This is illustrated below:

v = u – gt (since the ball is going against gravity)

0 = 4 – (9.8 × t)

0 = 4 – 9.8t

Collect like terms

0 – 4 = –9.8t

–4 = –9.8t

Divide both side by –9.8

t = –4 / –9.8

t = 0.41 s

Finally, we shall determine the time for the entire trip

T = 2t

T = 2 × 0.41

T = 0.82 s

v² = u² – 2gh (since the ball is going against gravity)

0² = 31² – (2 × 9.8 × h)

0 = 961 – 19.6h

Collect like terms

0 – 961 = –19.6h

–961 = –19.6h

Divide both side by –19.6

h = –961 / –19.6

h = 49.03 m

h = ½gt²

h = ½ × 9.8 × 14.4²

h = 4.9 × 207.36

h = 1016.06 m

v = u – gt (since the ball is going against gravity)

v = 11 – (9.8 × 2)

v = 11 – 19.6

v = –8.6 m/s

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Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

Sampling is the process of selecting a subset of individuals or items from a larger population in order to gather information or make inferences about the whole population. This method allows researchers to collect data from a smaller group, which is more efficient and cost-effective than collecting data from the entire population.

Sampling is a crucial process in research because it helps ensure that the data collected is representative of the population and reduces the potential for bias. There are several types of sampling methods, including random sampling, stratified sampling, and convenience sampling. The choice of sampling method depends on the research question, the population being studied, and the resources available to the researcher. The accuracy of the data obtained from a sample depends on the sample size and the sampling method used. A larger sample size is generally more representative of the population and reduces the margin of error, while a smaller sample size may be more susceptible to sampling bias.

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Answer:

0.125 J

Explanation:

E = ½ kx²

E = ½ (25 N/m) (0.10 m)²

E = 0.125 J

The stored elastic potential energy from the given equation is equal to 0.5 J.

When an elastic object, such a spring or a stretched rubber band, is displaced from its equilibrium state, it stores energy called elastic potential energy.

Given:

Spring constant, k = 25 Nm⁻¹

Distance, s = 10 cm

From the given equation

E = (0.5) × k × e²

Substitute values:

Ee = (0.5) ×  k × e²

Ee = (0.5) ×  25 ×  (0.1)²

Ee = 0.5 J

Hence, the stored elastic potential energy from the given equation is equal to 0.5 J.

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Explanation:

Pressure = Height * Density * acc. due to gravity

P = 2 * 680 * 9.8 = 13, 328 Pa

Answer:

13328pa

Explanation:

p = hgd

h = height = 200cm = 2m

g = 9.8m/s²

d = density = 680kg/m³

p = pressure

p = 2 x 9.8 x 680 = 13328pa

Answer:

(a) The kinetic energy of a 1.10 g particle with a speed of 0.800 c can be calculated using the equation KE = (1/2)mv^2, where m is the mass of the particle and v is its velocity. In this case, the mass of the particle is 1.10 g and the velocity is 0.800 c, so the kinetic energy would be:

KE = (1/2) * (1.10 * 10^-3 kg) * (0.800 * 3 * 10^8 m/s)^2

(b) The rest energy of a particle is the energy it has when it is at rest. According to the equation E=mc^2, where E is the energy, m is the mass, and c is the speed of light. In this case, the rest energy would be:

E = (1.10 * 10^-3 kg) * (3 * 10^8 m/s)^2

(c) The total energy of a particle is the sum of its kinetic energy and rest energy. Thus,

Total energy= kinetic energy + rest energy

The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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Cloud-to-cloud lightning makes up 60 % of all lightning.

Cloud-to-cloud lightning is a type of lightning that occurs within a single thunderstorm cloud, between two different thunderstorm clouds or between a thunderstorm cloud and the air near the ground. It is also known as intra-cloud lightning.

This type of lightning is responsible for creating the beautiful light shows that we often see during thunderstorms, but it can also be dangerous and cause damage to electrical equipment.
In terms of its frequency compared to other types of lightning, cloud-to-cloud lightning makes up a significant portion of all lightning strikes.

However, it is difficult to determine an exact percentage because lightning is a complex and unpredictable phenomenon. Studies have shown that cloud-to-cloud lightning accounts for around 60% of all lightning strikes worldwide.
This high percentage can be attributed to the fact that thunderstorm clouds often contain multiple charged regions, which can create the conditions necessary for cloud-to-cloud lightning.

While cloud-to-cloud lightning may not be the most well-known type of lightning, it plays an important role in the overall frequency and impact of lightning strikes worldwide.

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1. The height of the image is 0.287 m.

2. The wavelength of the light is 563 nm.

1. The image distance, denoted as `i`, is determined by the lens formula: `1/f = 1/o + 1/i`, where `f` represents the focal length, `o` is the object distance, and `i` represents the image distance. Given `f = 28.3 cm` and `o = 1.78 m`, we need to convert the object distance from meters to centimeters: `o = 1.78 m = 178 cm`. Therefore, the image distance is calculated as follows:

i = (1/f - 1/o)^-1 = (1/28.3 - 1/178)^-1 = 24.53 cm.

The image height, denoted as `h'`, can be determined using the object height `h` and the magnification `m` relationship: `h' = m * h`. The magnification `m` is given by `m = -i/o`, where the negative sign indicates an inverted image. Thus,

m = -i/o = -(24.53 cm)/(178 cm) = -0.138.

The image height `h'` is obtained by multiplying `h` by `m`: `h' = m * h`, where `h = 2.08 m`. Therefore,

h' = (-0.138) * 2.08 = -0.287 m.

The negative sign signifies an inverted image. Hence, the height of the image is determined as `0.287 m`, and it is inverted.

2. Bright fringes are observed at angles `theta` satisfying the condition `d sin theta = m lambda`, where `d` represents the spacing between two slits, `m` is an integer indicating the fringe order, and `lambda` denotes the wavelength of light. In this case, given `d = 1/20 mm` and `m = 1`, the angle `theta` corresponding to the first bright fringe is given by `tan theta = x/L`, where `x` represents the separation between two fringes, and `L` is the distance from the grating to the screen. With `x = 27.2 mm` and `L = 2.41 m`, we can calculate:

tan theta = (27.2 mm)/(2.41 m) = 0.01126.

Therefore, `sin theta = tan theta = 0.01126`.

Consequently, the wavelength `lambda` is determined using the formula `lambda = d sin theta / m`, where `d = 1/20 x 10^-3 m`, `sin theta = 0.01126`, and `m = 1`:

lambda = (1/20 x 10^-3 m) x 0.01126 / 1 = 5.63 x 10^-7 m = 563 nm.

In summary:

1. The height of the image is 0.287 m.

2. The wavelength of the light is 563 nm.

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Answer:

The net displacement is

\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)

\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)

Explanation:

Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement

Given data

A = 15 m

B = 25 m

Angle between the vectors A and B is θ = 30°

The net displacement is

\(R= \sqrt{A^2+B^2+2AB \cos \theta}\)

\(=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m\)

A liter of molten lead and a liter of apple juice have the same volume but not the same mass Particle. No, a liter of molten lead does not have the same volume or mass as a liter of apple juice.

Molten lead is a dense and heavy metal, while apple juice is a liquid made mostly of water with a much lower density. Density is the amount of mass per unit of volume, and since lead is much denser than apple juice, a liter of molten lead will weigh much more and take up less space than a liter of apple juice. In fact, a liter of molten lead will weigh about 11 times more than a liter of apple juice.

A liter is a unit of volume, so one liter of any substance, whether it's molten lead or apple juice, will have the same volume. However, mass is a different property, dependent on the density of the substance. Molten lead has a much higher density than apple juice, meaning it has more mass per unit volume.

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Answer:

i think its A. orange.

Explanation:

Answer:

They do this by joining pieces of different Rock sequences together from different places in the whole world.

Explanation:

Geologic columns are basically an arrangement of rock layers whereby the newest rocks are at the top while the oldest rocks will be at the bottom. Thus, it is like a timescale that's used to find the age of rock formation on the earth around the world.

Liquid containers are necessary to store liquids or other fluids, and are manufactured using various materials. These materials have unique properties and physical characteristics to meet the diverse requirements of different fluids and their storage conditions. Two of the materials used to make liquid containers are covalently bonded and metal.

1) Covalently bonded materials:Covalent bonds are strong bonds formed between atoms by sharing electrons. Covalently bonded materials are non-metallic materials that use a covalent bond between atoms to form the material. Examples of covalently bonded materials that can be used to manufacture liquid containers include:

- Polyethylene Terephthalate (PET): PET is a plastic material used to make water bottles and soft drink bottles. PET is lightweight and unbreakable, making it ideal for shipping and storing liquids.

- Polypropylene (PP): PP is a popular plastic material that is lightweight, durable, and resistant to chemical reactions. PP is used to make containers that store harsh chemicals and strong acids, as well as food containers, such as yogurt cups and margarine tubs.

In conclusion, there are many materials available that can be used to manufacture liquid containers, including covalently bonded materials and metals. The choice of material used depends on the type of liquid being stored and the storage conditions.

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Early morning clouds will change to partly cloudy sky later in the day temperature . High 52F. SW winds 10 to 20 mph.

Except for the Mediterranean region, where pleasant winters and scorching summers are more common, France typically experiences moderate winters and mild summers. The usual winter ranges from 32 to 46 degrees Fahrenheit, while the typical summer ranges from 61 to 75 degrees.

Maximum daily temperatures in July ranged from 20°C to 43°C (68°F to 109°F). The range of daily lows in July is 45°F to 66°F (7°C to 19°C).

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The electric motor's efficiency is 51.06%.

The majority of electric motors are made to operate between 50% and 100% of rated load. Typically, maximum efficiency is within 75% of rated load. Hence, the allowable load range for a 10-horsepower (hp) motor is between 5 and 10 hp; its peak efficiency is at 7.5 hp. Below roughly 50% load, a motor's efficiency tends to decline significantly.

To calculate the effort required to raise the object, use the formula:

Work = Force x Distance

= m x g x h (where m is the mass of the object, g is the acceleration due to gravity, and h is the height lifted)

= 34 kg x 9.81 m/s² x 11 m

= 3,769.34 J

The energy consumed by the electric motor is given as 7.4 kJ.

Therefore, the input power is:

Input power = Energy consumed / time taken

= 7.4 kJ / t

Efficiency=(Output power/Input power) x 100%

Output power = Work done/time taken

= 3,769.34 J / t

As a result, the electric motor's efficiency is:

Efficiency=(Output power/Input power)x 100%

= [(3,769.34 J / t) / (7.4 kJ / t)] x 100%

= 51.06%.

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Answer:

B. They travel at different speeds through the Earth.

Explanation:

The true statements about exomoons are:

A. Exomoons are likely to exist

D. Exomoons have been used as locations within science fiction stories

C. Exomoons must be only made of ice

A. Exomoons are likely to exist: It is believed that exomoons could exist in planetary systems beyond our own. While the detection and confirmation of exomoons remains a challenge, their existence is considered plausible based on the understanding of moon formation and the prevalence of exoplanets.

D. Exomoons have been used as locations within science fiction stories: Exomoons, being a fascinating concept, have captured the imagination of science fiction writers. They have been depicted in various stories and movies as intriguing and potentially habitable worlds.

E. Exomoons are moons that orbit exoplanets: An exomoon refers to a moon that orbits an exoplanet, which is a planet outside our solar system. Just like moons in our own solar system, exomoons are expected to orbit exoplanets, providing additional complexity and dynamics to the planetary systems.

C. Exomoons must be only made of ice: This statement is not true. Exomoons can be composed of various materials depending on their formation and composition. While some exomoons could have icy surfaces or subsurface oceans, others may be rocky or have diverse compositions.

It is important to note that our understanding of exomoons is still limited, and further research and observations are required to confirm their existence and study their characteristics.

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The acceleration of the block is 6.4 m/s².

To calculate the acceleration of the block, we need to consider the forces acting on it.

The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.

The frictional force opposing the motion is 8 N.

The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).

The net force is the difference between the applied force and the frictional force:

40 N - 8 N = 32 N.

Now, we can plug the values into Newton's second law:

32 N = 5 kg × a.

Solving for the acceleration (a), we get

a = 32 N / 5 kg

a = 6.4 m/s².

Therefore, the acceleration of the block is 6.4 m/s².

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Answer:750

Explanation:

The statement Cars already on the freeway do not have the right-of-way to cars merging onto the freeway is False.

The right-of-way is the right of a pedestrian, vehicle, or ship has to move ahead or proceed with precedence over others in a particular situation or place.

The right-of-way of car already on the freeway precedes those of other cars merging onto the freeway.

In conclusion, the right-of-way is a legal right as to who has precedence in a particular situation or place.

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Answer:

false

Explanation:

Answer:

Time taken for car to stop = 0.89 seconds (Approx.)

Explanation:

Given:

Mass of car = 1100 kg

Speed of car = 15 m/s

Impact force = 185,000 N

Find:

Time taken for car to stop

Computation:

Change in momentum of car = M(v) - M(u)

Change in momentum of car = 1100(0) - 1100(15)

Change in momentum of car = -16,500

Time taken for car to stop = I Change in momentum of car I / Impact force

Time taken for car to stop = I-16,500I / 185,000

Time taken for car to stop = 0.89 seconds (Approx.)

The time it takes for the car to stop will be 0.89 sec. Due to the external resistive force, the car will stop after some time.

The momentum is defined as the product of mass and the velocity of the body. It is denoted by the letter P. It occurs due to the applied force. Its unit is Kg m/s².

The change in the momentum of the car is given as;

\(\rm \triangle P = m(V-U) \\\\ \triangle P = 1100(0-5) \\\\ \rm \triangle P =-16,500 Kgm/s\)

The time taken for a car to stop will be;

\(I \triangle p= F\triangle t \\\\ \rm t = \frac{\triangle p }{F} \\\\ \rm t = \frac{|-16500|}{18500} \\\\ \rm t =0.89 \ sec\)

Hence the time it takes for the car to stop is 0.89 sec.

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Answer:

d=1/2 (a)(t^2)

D = distance

A = acceleration

T = time

acceleration due to gravity is 32 ft/second

so, d=1/2 (32)(5^2)

d=16(25)

d=400

Explanation:

Answer:

400 ft.

Explanation:

D= 1/2 gt^2

=1/2(-32 ft/sec^2)(5 sec^2)

= -(1/2)(32)(25) ft

D= -400 ft, down

0.45 kJ/kg/°C is the specific heat of the object when the temperature of a 50 kg block increases by 15°C when337,500 J of thermal energy are added to the block.

Heat = mass × specific heat × change in temperature

q = m C ΔT

Given:

q = 337500 J

m = 50 kg

ΔT = 15°C

now, place values

337500 J = (50 kg) C (15°C)

C = 450 J/kg/°C

Specific heat is usually recorded in J/g/°C or kJ/kg/°C.  Converting:

C = 0.45 J/g/°C = 0.45 kJ/kg/°C

the amount of heat needed to increase a substance's temperature by one degree Celsius in one gram, also known as specific heat. Typically, calories or joules per gram per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gram per degree Celsius.

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Answer:

C- Frequency

Explanation:

Answer:

A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it.[1] The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.[2][3]

The boundary of the region from which no escape is possible is called the event horizon. Although the event horizon has an enormous effect on the fate and circumstances of an object crossing it, according to general relativity it has no locally detectable features.[4] In many ways, a black hole acts like an ideal black body, as it reflects no light.[5][6] Moreover, quantum field theory in curved spacetime predicts that event horizons emit Hawking radiation, with the same spectrum as a black body of a temperature inversely proportional to its mass. This temperature is on the order of billionths of a kelvin for black holes of stellar mass, making it essentially impossible to observe directly.

Objects whose gravitational fields are too strong for light to escape were first considered in the 18th century by John Michell and Pierre-Simon Laplace.[7] The first modern solution of general relativity that would characterize a black hole was found by Karl Schwarzschild in 1916, although its interpretation as a region of space from which nothing can escape was first published by David Finkelstein in 1958. Black holes were long considered a mathematical curiosity; it was not until the 1960s that theoretical work showed they were a generic prediction of general relativity. The discovery of neutron stars by Jocelyn Bell Burnell in 1967 sparked interest in gravitationally collapsed compact objects as a possible astrophysical reality.

Black holes of stellar mass are expected to form when very massive stars collapse at the end of their life cycle. After a black hole has formed, it can continue to grow by absorbing mass from its surroundings. By absorbing other stars and merging with other black holes, supermassive black holes of millions of solar masses (M☉) may form. There is consensus that supermassive black holes exist in the centers of most galaxies.

The presence of a black hole can be inferred through its interaction with other matter and with electromagnetic radiation such as visible light. Matter that falls onto a black hole can form an external accretion disk heated by friction, forming quasars, some of the brightest objects in the universe. Stars passing too close to a supermassive black hole can be shred into streamers that shine very brightly before being "swallowed."[8] If there are other stars orbiting a black hole, their orbits can be used to determine the black hole's mass and location. Such observations can be used to exclude possible alternatives such as neutron stars. In this way, astronomers have identified numerous stellar black hole candidates in binary systems, and established that the radio source known as Sagittarius A*, at the core of the Milky Way galaxy, contains a supermassive black hole of about 4.3 million solar masses.

On 11 February 2016, the LIGO Scientific Collaboration and the Virgo collaboration announced the first direct detection of gravitational waves, which also represented the first observation of a black hole merger.[9] As of December 2018, eleven gravitational wave events have been observed that originated from ten merging black holes (along with one binary neutron star merger).[10][11] On 10 April 2019, the first direct image of a black hole and its vicinity was published, following observations made by the Event Horizon Telescope in 2017 of the supermassive black hole in Messier 87's galactic centre.[12][13][14]

Blackness of space with black marked as center of donut of orange and red gases

The supermassive black hole at the core of supergiant elliptical galaxy Messier 87, with a mass about 7 billion times that of the Sun,[15] as depicted in the first false-colour image in radio waves released by the Event Horizon Telescope (10 April 2019).[16][12][17][18] Visible are the crescent-shaped emission ring and central shadow,[19] which are gravitationally magnified views of the black hole's photon ring and the photon capture zone of its event horizon. The crescent shape arises from the black hole's rotation and relativistic beaming; the shadow is about 2.6 times the diameter of the event horizon.[12]

Schwarzschild black hole

Simulation of gravitational lensing by a black hole, which distorts the image of a galaxy in the background

Gas cloud being ripped apart by black hole at the centre of the Milky Way (observations from 2006, 2010 and 2013 are shown in blue, green and red, respectively).[20]

The electric field's strength can be determined using the equation E = k | Q | r 2 E = k | Q | r 2. The charge's sign, which in this instance is negative, determines the direction of the electric field.

The force per charge applied to the test charge can be used to determine the electric field's strength. Its definition gives birth to the common metric units for electric field strength. The units of an electric field would be force units divided by charge units as an electric field is defined as a force per charge. The electric field's strength can be determined using the equation E = k | Q | r 2 E = k | Q | r 2.

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The electric field's strength can be determined using the equation E = k | Q | r 2 E = k | Q | r 2. The charge's sign, which in this instance is negative, determines the direction of the electric field.

To gauge the strength of the electric field, apply a force per charge to the test charge. The standard metric units for electric field strength were created as a result of its specification. Since the definition of an electric field is a force per charge, the units of an electric field would be force units divided by charge units. Equation can be used to determine the magnitude of the electric field. E = k | Q | r 2 E = k | Q | r 2.

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