(a) if the maximum accelerationthat is tolerable for passengers in asubway train is 1.34 m/s2and subwaystations are located 806 m apart, whatis the maximum speed a subway traincan attain between stations?

A stone thrown from the top of a tall building follows a parabolic path due to the effects of gravity on its motion. The correct answer is D.

A stone thrown from the top of a tall building follows a parabolic path. This is because the stone is initially moving in a straight line, but it is also being pulled downward by gravity. As a result, the stone follows a curved path that is shaped like a parabola.  In mathematical terms, the path of the stone can be described by a quadratic equation, which is a type of equation that produces a parabolic graph. The equation for the path of the stone will include terms for the initial velocity of the stone, the acceleration due to gravity, and the initial height of the stone.

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Answer:

2+ charge

Explanation:  The alkaline earth metals have two valence electrons in their highest-energy orbitals (ns2). They are smaller than the alkali metals of the same period, and therefore have higher ionization energies. In most cases, the alkaline earth metals are ionized to form a 2+ charge

Hope this helps, have a great day :)

Answer:

15 kg ball

Explanation:

Answer:

0.00025 kilometers

Explanation:

divide the length value by 1e+6

Answer:

250 mm = 0.00025 km.

Explanation:

250 mm equal 0.00025 km

Conversion details

To convert mm to km use the following formula:

1 mm equals 0.000001 km

So, to convert 250 mm to km, multiply 0.000001 by 250 i.e.,

250 mm = 0.000001 * 250 km = 0.00025 km

(hope this helps can i plz have brainlist :D hehe)

Hi there!

We can use the work-energy theorem and apply it to this situation.

At the top of the ramp, the ball only has gravitational potential energy, and at the bottom of the ramp, the ball has BOTH translational and rotational kinetic energy.

We must use the following equations:
\(GPE = mgh \\KE_T = \frac{1}{2}mv^2\\\\KE_R = \frac{1}{2}I \omega^2\)

m = mass of sphere (kg)
g = acceleration due to gravity (m/s²)

h = height of ramp (m)

v = final velocity (m/s)
I = Moment of Inertia (kgm²)

ω = angular velocity (rad/sec)

Since:
\(E_i = E_f\\\\mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega ^2\)

In order to make things easier, since the ball is not slipping, we can relate angular velocity to translational velocity:
\(\omega = \frac{v}{r}\)

Also, recall the equation for the moment of inertia for a solid sphere:
\(I = \frac{2}{5}mr^2\)

We can use these to simply our equation:
\(KE_R = \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = \frac{1}{5}mv^2\)

Now, we can rewrite the equation and solve for 'v'.

\(mgh = \frac{1}{2}mv^2 + \frac{1}{5}mv^2\\\\mgh = \frac{7}{10}mv^2\\\\v = \sqrt{\frac{10gh}{7}} = \sqrt{\frac{10(9.8)(2.2 - 1.87)}{7}} = 2.149\frac{m}{s}\)

a)

We can begin by solving for the time taken for the ball to land on the ground. The ball only has a horizontal velocity, so this is essentially a free-fall situation. Use the rearranged kinematic equation:
\(t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.87)}{9.8}} = .6178 s\)

Now, use the following equation to solve for horizontal distance given horizontal velocity and time:
\(d_x = v_x t\\\\d_x = 2.149 * .6178 = \boxed{1.328 m}\)

b)
We can use the previously-stated relationship between translational and angular velocity to solve for the angular velocity.

\(\omega = \frac{v}{r}\)
It is given that the diameter is 0.14 m, so the radius is 1/2th the diameter, or 0.07 m.

Solve for the angular velocity:
\(\omega = \frac{2.149}{0.07} = 30.706 \frac{rad}{sec}}\)

Using the above fall time and dimensional analysis to convert from rad/sec to revolutions, we can solve for the # of revolutions made by the ball:
\(\frac{30.706rad}{sec} * .6178 sec * \frac{1 rev}{2\pi rad} = \boxed{3.019 rev}\)

The answer is yes

They are isotopes.

The energy released in the β⁻ decay of ⁹⁹Mo is zero.

To calculate the energy released in the β⁻ decay of ⁹⁹Mo, we need to determine the change in mass (Δm) and then use the equation E = Δm * c², where c is the speed of light.

In this case: mass of ⁹⁹Mo (m) = 98.907711 u

Mass of ⁹⁹Mo in kg = 98.907711 u * (1.66 × 10⁻²⁷ kg/u) ≈ 1.64 × 10⁻²⁵ kg

Next, we determine the mass of the decay product, which is ⁹⁹Tc (technetium). The mass of ⁹⁹Tc is approximately 99 u.

Mass of ⁹⁹Tc in kg ≈ 99 u * (1.66 × 10⁻²⁷ kg/u) ≈ 1.64 × 10⁻²⁵ kg

Now we can calculate the change in mass:

Δm = (Mass of ⁹⁹Mo in kg) - (Mass of ⁹⁹Tc in kg)

Δm ≈ (1.64 × 10⁻²⁵ kg) - (1.64 × 10⁻²⁵ kg) = 0

Since Δm is zero, it means that there is no change in mass during the β⁻ decay of ⁹⁹Mo.

Finally, we can calculate the energy released:

E = Δm * c² = 0 * (3.00 × 10⁸ m/s)² = 0

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A battery-operated power tool, such as a cordless drill, converts electrical energy stored in the battery into mechanical energy through the use of a motor.

The battery, typically a lithium-ion or nickel-cadmium type, supplies the necessary voltage and current to the motor. As electricity flows through the motor's coils, it generates a magnetic field that interacts with permanent magnets, creating rotational force (torque) to turn the drill bit or drive a screw. The conversion of electrical energy to mechanical energy allows for enhanced portability and convenience, eliminating the need for a power cord and enabling users to work in a wide range of locations. Cordless drills often come with variable speed settings and torque adjustments, providing greater versatility and control for various tasks.

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Answer:

The work done on the block by the force of gravity is 392.4 J. The work done by the normal force is zero. The work done by the net force is equal to the change in kinetic energy of the block. At the end of the slide, the block has a kinetic energy of (1/2)mv^2, where v is the speed of the block.

Explanation:

Answer:

Due to waves.

Explanation:

The can merely moves up and down because the movement of the waves that propagate away from the disturbance caused by the boat. The Can has low density due to low mass and high volume which allow the can to float on the surface of water after prevent it from the drowning. The wave moves the can up and down but prevent it from going deep inside the water so we can say that the can moves due to movement of waves in water.

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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The 100 Ω and 50 Ω have been joined in series and their combination is joined in parallel with 75 Ω, in the given picture. The circuit diagram shown below.

A circuit diagram uses electrical symbols to show the various components of an electrical circuit graphically or visually. There is a lot of resistance in the voltmeter.

For the design (circuit design), fabrication (like PCB layout), and maintenance of electrical and electronic equipment, circuit diagrams are utilized. When illustrating Boolean algebraic expressions, circuit diagrams are helpful in the field of computer science.

We may create parallel and series circuits, which are two different sorts of circuits. Wires connect the various parts of a circuit. If there are no branches, the circuit is in series. If there are branches, the circuit is parallel.

Consider the 100 Ω and 50 Ω have been joined in series and their combination is joined in parallel with 75 Ω.

The circuit diagram drawing is as follows:

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The complete question is as follows:

Draw a circuit diagram for the circuit of Figure P23.1.

It will take 2 seconds to reach 30 m/s north.

Below are the parameter given from the question :

Initial velocity U = 20 m/s

Final velocity V = 30 m/s

Acceleration a = 5 m/s

Time t = ?

The equation of linear motion to use is:

V = U + at

Substitute all the parameter to the equation above.

30 = 20 + 5t

Collect the like term

5t = 30 - 20

5t = 10

t = 10/5

t = 2 s

Therefore, It will take 2 seconds to reach 30 m/s north.

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There is evidence to suggest that Mars may have been more Earth-like in the past because of the presence of water on its surface.

The presence of water is a key component in the search for life, as it is essential for the development and sustenance of life as we know it. The discovery of potential past habitable environments on Mars suggests that there may have been conditions suitable for the development of life.

Additionally, Mars has a similar geological history to Earth, with evidence of plate tectonics, volcanic activity, and other geological processes. This suggests that the planet may have had a similar composition and structure to Earth in its early history.

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An annular solar eclipse happens when the Moon is in its first or last quarter phase, further from Earth than usual due to its irregular orbit, and appears smaller than the Sun.

The Moon must pass exactly in front of the Sun during the alignment, but it must not entirely obscure it. To do this, the Sun, Moon, and Earth must precisely line up to form a straight line known as a syzygy. The viewer must also be situated within the Moon's shadow's path on Earth. These circumstances work together to create an annular solar eclipse, in which the Moon appears as a black disc encircled by a dazzling ring of sunlight.

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Answer:

c

Explanation:

tell me if im write

Answer:

positive acceleration: releasing an object from a height - acceleration due to the force of gravity, the speed of the object will increase as it falls

negative acceleration: applying breaks on the tires to slow down the car - deceleration due to frictional forces

These are Some climates

Tropical.

Dry.

Temperate.

Continental.

Polar.

And these are some biomes

aquatic, grassland, forest, desert, and tundra,

Answer:

You can charge capacitor to any potential as long as charging voltage is less than rated voltage value of the capacitor. The voltage across a capacitor is limited by the dielectric strength of the insulating material times its thickness.

Answer:

20 cm

Explanation:

Given that a ball is released from a vertical height of 20 cm. It rolls down a "perfectly frictionless" ramp and up a similar ramp. What vertical height on the second ramp will the ball reach before it starts to roll back down?

Since it is perfectly frictionless, the Kinetic energy in which the ball is rolling will be equal to the potential energy at the edge of the ramp.

Therefore, the ball will reach 20 cm before it starts to roll back down.

The wavelength of the light falling on the slits is approximately 493 nanometers when adjacent bright fringes are separated by 2.10 mm.

To find the wavelength of the light falling on the slits, we can use the formula for the interference pattern in a double-slit experiment:

λ = (d * D) / y

where λ is the wavelength of the light, d is the separation between the slits, D is the distance between the slits and the screen, and y is the separation between adjacent bright fringes on the screen.

Given:

Separation between the slits (d) = 0.610 mm = 0.610 × 10^(-3) m

Distance between the slits and the screen (D) = 1.70 m

Separation between adjacent bright fringes (y) = 2.10 mm = 2.10 × 10^(-3) m

Substituting these values into the formula, we can solve for the wavelength (λ):

λ = (0.610 × 10^(-3) * 1.70) / (2.10 × 10^(-3))

λ = (1.037 × 10^(-3)) / (2.10 × 10^(-3))

λ = 0.4933 m

To convert the wavelength to nanometers, we multiply by 10^9:

λ = 0.4933 × 10^9 nm

λ ≈ 493 nm

Therefore, the wavelength of the light falling on the slits is approximately 493 nanometers.

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The force that the floor of the elevator exerts on the 52-kg passenger in this case is approximately 510 N upward.

To determine the force that the floor of the elevator exerts on a 52-kg passenger, you'll need to consider the forces acting on the passenger and the elevator's motion. If the elevator is moving at a constant speed or is stationary, the net force acting on the passenger is zero, meaning the forces balance each other out.
In this scenario, the force of gravity pulls the passenger downward, which can be calculated using the equation F_gravity = m * g, where m is the mass (52 kg) and g is the acceleration due to gravity (approximately 9.81 m/s²).
F_gravity = 52 kg * 9.81 m/s² ≈ 510 N (rounded to the nearest whole number)
The floor of the elevator must exert an equal and opposite force, called the normal force, to counteract the force of gravity. Therefore, the force that the floor of the elevator exerts on the 52-kg passenger in this case is approximately 510 N upward. Note that if the elevator is accelerating, the normal force would be different and can be calculated using Newton's second law, F = m * a, where a is the acceleration of the elevator.

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Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \(\frac{moles}{L}\).

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

\(Molarity=\frac{number of moles}{volume}\)

Molarity is expressed in units \(\frac{moles}{L}\).

In this case, you have:

Replacing in the definition of molarity:

\(Molarity=\frac{0.7143 moles}{0.28 L}\)

Solving:

Molarity= 2.5510 \(\frac{moles}{L}\)

Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \(\frac{moles}{L}\).

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An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The  pressure at the point on the wing is  \(P = 6.96 * 10^4 N/m^2\).

To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.

The equation is as follows:

P + 1/2 * ρ * \(V^2\) = constant

where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.

Given:

\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)

ρ = \(0.909 kg/m^3\) (density of the fluid)

\(V_1 = 42 m/s\) (velocity of the airplane)

\(V_2 = 88 m/s\) (velocity at the point on the wing)

To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:

\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\)  * ρ * \(V_2^2\)

Substituting the given values:

\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)

Simplifying the equation:

\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)

7.01 × 10^4 + 804.906 = P + 3526.242

\(P + 4329.148 = 7.01 *10^4\)

\(P = 7.01 * 10^4 - 4329.148\)

\(P = 6.96 * 10^4 N/m^2\)

Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)

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The-ratio of their gravitational potential energy is \(1:2\). The unit of measurement for any and all types of energy, which would include kinetic and potential energy, is kilograms per square second, or kg*m2/s2 (J).

Height \(H_{1} = h\)

Height \(F_{2} = 2h\)

Mass of body 1 = m

Mass of body 2 = m

Gravitational potential energy of body  \(1 = mgH 1 =mgh\)

Gravitational potential energy of Body 2 \(= mgH 2 =mg(2h)\).

Ratio of gravitational potential energies

\(=\frac{mgh}{mg (2h)} =\frac{mgh}{2mgh} =\frac{1}{2} = 1:2\)

What Unit of Measurement Is Potential Energy in?

Due to the fact that energy and work quantify identical types of force, the Joule is indeed the proven scientific measurement device for either of those.

How do you calculate kinetic energy?

K E = 1 2 m v 2 is the formula for kinetic energy. When m denotes the body's weight as well as v denotes its velocity, KE stands for kinetic energy.

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Answer:

d

Explanation:

Answer:true

Explanation:

Given what we know, we can confirm that when a light wave is refracted, it changes direction.

Refraction is a term used to explain and describe the change in direction of a light wave as it passes through a medium. This change in direction is caused by the change in speed of the light wave entering a new medium.

Therefore, we can confirm that when a light wave is refracted, it changes direction.

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The data displayed the expected relationship between the centripetal force and angular speed of the rotation. Increasing the angular speed led to a proportional increase in the centripetal force, indicating a direct relationship between the two variables.

This relationship was supported by the experimental evidence obtained in the investigation. When the mass was changed while keeping the radius constant, the centripetal force increased as the mass increased.

Similarly, when the radius was changed while keeping the mass constant, the centripetal force increased as the radius increased. These observations demonstrate that both mass and radius have a direct effect on the required centripetal force to maintain a certain angular speed.

In the experiment, the relationship between centripetal force and angular speed was confirmed. As the angular speed increased, the centripetal force also increased proportionally. This relationship was evident through the data collected during the investigation. When the mass was altered while maintaining a constant radius, an increase in mass resulted in a corresponding increase in the required centripetal force. Likewise, when the radius was modified while keeping the mass constant, an increase in radius led to a greater centripetal force.

These experimental observations support the notion that both mass and radius directly influence the amount of force required to achieve a specific angular speed.

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