please help much appreciated!
The equation of the inequality graph with dashed line
y > 2x - 4The equation of the inequality graph with solid line
y ≥ -x + 4How to derive the equationsUsing the slope intercept form of the straight line which is of the form
y = mx + c
The slope, m is the ratio of the change in the output to the change in the input. This is given by the formula
m = (y₀ - y₁) / (x₀ - x₁)
Slope calculation using the points (0, -4) and (2, 0)
m = (-4 - 0) / (0 - 2)
m = 2
y intercept, c from the graph
c = -4
applying inequality representations
shading above the line is greater than and dotted lines means it does not have equal to
hence y > 2x - 4
for the solid line graph
the slope, m calculating using the points on the graph (0, 4) and (4, 0)
m = (4 - 0) / (0 - 4)
m = (4) / (-4)
m = -1
y intercept, c from the graph
c = 4
The equation of the line is y = -x + 4
Solid lines indicate an equality in the inequality, while shading over the line indicates a greater than
hence y ≥ -x + 4
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Kara and six of her friends are playing miniature golf.
If it costs $42 for all of them to play a round of golf,
how much does each round cost per person?
Answer:
Step-by-step explanation:
it cost 6 dollars because you would divide 42÷7 and you would get 6 you would divide the price between the 7 people and you would get
Write the equation of the line that passes through the points (-3, -7) and (-3,-4) put your answer in fully reduced point slope form unless it is a vertical or horizontal line
Answer:
It is an undefined line which means a vertical line.
Step-by-step explanation:
Using the point-slope formula y2-y1 divided by x2-x1, you would get -4-(-7)/-3-(-3) which the answer would be 3/0. If zero is at the bottom of the fraction, the line would be undefined.
Solve 2x + 3y = C, for y
Answer:
y= \(\frac{c-2x}{3}\)
Step-by-step explanation:
2x+3y=C
isolate y
3y=C-2x
y= \(\frac{c-2x}{3}\)
how do u put x-2y=2 into slope intercept form , show your work.
Answer:
y = -x - 1
Step-by-step explanation:
-2y=-x+2
y—x-1
What is the quotient of 4 and 2 over 3Division sign2 over 3 ? (1 point)
The quotient of (4 ÷ 2) ÷ (3 ÷ 2/3) is equal to 4.
To simplify the given expression, we need to perform the division operations following the order of operations.
First, let's simplify the division (3 ÷ 2/3). When dividing by a fraction, we can multiply by the reciprocal of the fraction. The reciprocal of 2/3 is 3/2, so the expression becomes (3 ÷ 2/3) = 3 * (3/2) = 9/2.
Now, we can simplify the division (4 ÷ 2) ÷ (9/2). Dividing 4 by 2 gives us 2, and dividing 2 by 9/2 is equivalent to multiplying by the reciprocal of 9/2, which is 2/9. Thus, (4 ÷ 2) ÷ (9/2) = 2 ÷ (9/2) = 2 * (2/9) = 4/9.
Therefore, the quotient of (4 ÷ 2) ÷ (3 ÷ 2/3) is equal to 4/9.
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Question3: A random sample of 10 students contains the following data, in hours, for time spent
studying in the week before final exams. Sample mean is 45 and sample standard deviation is 10.5409.
Assume that the population distribution is normal. Test, at the 5% significance level, the null hypothesis
that the population mean is 40 hours against the alternative that it is higher.
At the 5% significance level, we have sufficient evidence to conclude that the population mean is higher than 40 hours.
To test the null hypothesis that the population mean is 40 hours against the alternative that it is higher, we can perform a one-sample t-test.
The null hypothesis (H₀): μ = 40 (population mean is 40 hours)
The alternative hypothesis (H₁): μ > 40 (population mean is higher than 40 hours)
Given a sample of 10 students, the sample mean (x') is 45 hours and the sample standard deviation (s) is 10.5409.
Using the t-test, we calculate the test statistic t:
t = (x' - μ₀) / (s / √n)
Where x' is the sample mean, μ₀ is the null hypothesis population mean (40), s is the sample standard deviation, and n is the sample size (10).
Plugging in the values, we get:
t = (45 - 40) / (10.5409 / √10)
t ≈ 2.38
Next, we determine the critical value or the p-value associated with a significance level of 5%. For a one-tailed test (since we are testing if the mean is higher), the critical value is tc = t(α,n-1), where α is the significance level and n-1 is the degrees of freedom.
At a significance level of 5%, with 9 degrees of freedom (n-1), the critical value is tc = 1.833 (obtained from a t-table or statistical software).
Since the calculated t-value (2.38) is greater than the critical value (1.833), we reject the null hypothesis.
Therefore, at the 5% significance level, we have sufficient evidence to conclude that the population mean is higher than 40 hours based on the given sample data.
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In the figure, angle A measures 41° and angle D measures 32°. What is the measurement of angle E?
A. 88°
B. 90°
C. 99°
D. 100°
Answer:C
Step-by-step explanation:
interior angles of a triangle, when added, = 180
so < A + < B + < C = 180
41 + 90 + < C = 180
131 + < C = 180
< C = 180 - 131
< C = 49
< C + < D + < E = 180.....because when added they form a line
49 + 32 + < E = 180
81 + < E = 180
< E = 180 - 81
< E = 99 <======
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Your car gets about 20 miles per gallon. You are planning to drive to see your friends
who live about 850 miles away. How many gallons of gas will you need to purchase to make the trip to see your friends and to return home?
Can someone explain step by step how to do this
You would need to purchase approximately 85 gallons of gas to make the trip to see your friends and return home.
To determine the number of gallons of gas needed for the trip to see your friends and return home, you can follow these step-by-step calculations:
Calculate the total distance of the round trip:
Since the distance to your friends' place is 850 miles, the round trip would be twice that distance, which is 850 miles × 2 = 1700 miles.
Determine the number of gallons of gas required:
Divide the total distance of the round trip by the car's mileage per gallon. In this case, since your car gets about 20 miles per gallon, you would divide 1700 miles by 20 miles per gallon:
1700 miles ÷ 20 miles per gallon = 85 gallons.
Therefore, you would need to purchase approximately 85 gallons of gas to make the trip to see your friends and return home.
It's important to note that this calculation assumes a constant fuel efficiency of 20 miles per gallon throughout the entire trip. In reality, factors such as driving conditions, speed, and traffic may affect the actual mileage you achieve.
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will give brainliest answer
Solve for x. Round your answers to two decimal places.
2x2 + 6x = 4
x = −0.56 and x = 3.56
x = 0.56 and x = −3.56
x = −0.40 and x = 2.90
x = 0.40 and x = −2.90
please give brainliest
Answer:
To solve the equation 2x^2 + 6x = 4, we can rearrange it to the quadratic form and then solve for x.
2x^2 + 6x - 4 = 0
To find the solutions, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For the given equation, a = 2, b = 6, and c = -4. Substituting these values into the quadratic formula, we get:
x = (-6 ± √(6^2 - 4(2)(-4))) / (2(2))
x = (-6 ± √(36 + 32)) / 4
x = (-6 ± √68) / 4
x = (-6 ± 2√17) / 4
x = -3/2 ± √17/2
Rounding to two decimal places, we get:
x ≈ -0.56 and x ≈ 1.56
Therefore, the correct answer is:
x = −0.56 and x = 1.56
Answer The question in the picture *MATH* DUE NOW PLEASE HELP ME ,I WILL BRAINELIST
Answer:
sorry i really don't know :(
Use the fundamental identities to find the value of the trigonometric function. Find cot 8, given that csc 0 = - and is in quadrant III. A7-√33 33 B) -√33 4√33 D) √33
To find the value of cot 8, we can use the fundamental trigonometric identity: cot(theta) = 1 / tan(theta).
Since we know that csc(0) = -sqrt(33) and it is in quadrant III, we can determine the value of sin(0) and cos(0) using the Pythagorean identity: sin^2(theta) + cos^2(theta) = 1.
In quadrant III, sine is negative, so sin(0) = -sqrt(33).
Using the Pythagorean identity, we can calculate cos(0):
sin^2(0) + cos^2(0) = 1
(-sqrt(33))^2 + cos^2(0) = 1
33 + cos^2(0) = 1
cos^2(0) = 1 - 33
cos^2(0) = -32
Since cosine is positive in quadrant III, we take the positive square root:
cos(0) = sqrt(-32) = sqrt(32)i = 4sqrt(2)i
Now, we can find the value of tan(0) using the definition: tan(theta) = sin(theta) / cos(theta):
tan(0) = sin(0) / cos(0)
tan(0) = (-sqrt(33)) / (4sqrt(2)i)
tan(0) = -sqrt(33) / (4sqrt(2)i) * (sqrt(2)/sqrt(2))
tan(0) = -sqrt(33) * sqrt(2) / (4sqrt(2)i * sqrt(2))
tan(0) = -sqrt(66) / (4i)
tan(0) = -sqrt(66) / 4i
Finally, we can find cot(8) using the reciprocal property:
cot(8) = 1 / tan(8)
cot(8) = 1 / (-sqrt(66) / 4i)
cot(8) = 1 * (-4i) / (-sqrt(66))
cot(8) = 4i / sqrt(66)
Therefore, the value of cot 8 is 4i / sqrt(66).
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Pls answer this question it is due in 60 seconds
CMR for the first and MRC for the second
JUST TRUST YOU DON'T HAVE TIME
In the month of March the Digby Corporation received and delivered orders of 152,000 units at a price of $15.00 for revenue of $2.280mil for their product Dixie. Digby uses the accrual method of accounting and offers 30 day credit terms. By the end of May Digby had collected payments of $2.280mil for the March deliveries. How much of the collected $2.280mil should Digby show on the March 31st income statement and how much on the May 31st income statement?
Select 1:
A) $2.280mil in March;
$0 in May
B) $1.140mil in March;
$1.140mil in May
C) $0.752mil in March;
$1.528mil in May
D) $0 in March;
$2.280mil in May
Digby Corporation should show $0 on the March 31st income statement and $2.280 million on the May 31st income statement.
Digby Corporation uses the accrual method of accounting, which means revenue is recognized when it is earned, regardless of when the payment is received. In this case, the revenue of $2.280 million was earned in March when the deliveries were made, even though the payments were collected later.
On the March 31st income statement, Digby should not show any of the collected $2.280 million since the payments were not received by that date. The income statement for March will only reflect the revenue earned and any expenses incurred during that month.
On the May 31st income statement, Digby should show the full $2.280 million as revenue since the payments were collected by that date. The income statement for May will reflect the revenue earned in March, as well as any additional revenue and expenses for the month of May.
Therefore, the correct answer is:
D) $0 in March;
$2.280 million in May.
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The Root cause analysis uses one of the following techniques: o Rule of 72 o Marginal Analysis o Bayesian Thinking o Ishikawa diagram
The Root Cause Analysis technique used to identify the underlying causes of a problem is the Ishikawa diagram. It is a graphical tool also known as the Fishbone diagram or Cause and Effect diagram. The other techniques mentioned, such as the Rule of 72, Marginal Analysis, and Bayesian Thinking, are not specifically associated with Root Cause Analysis.
Root Cause Analysis is a systematic approach used to identify the fundamental reasons or factors that contribute to a problem or an undesirable outcome. It aims to go beyond addressing symptoms and focuses on understanding and resolving the root causes. The Ishikawa diagram is a commonly used technique in Root Cause Analysis. It visually displays the potential causes of a problem by organizing them into different categories, such as people, process, equipment, materials, and environment. This diagram helps to identify possible causes and facilitates the investigation of relationships between different factors. On the other hand, the Rule of 72 is a mathematical formula used to estimate the doubling time or the time it takes for an investment or value to double based on compound interest. Marginal Analysis is an economic concept that involves examining the additional costs and benefits associated with producing or consuming one more unit of a good or service. Bayesian Thinking is a statistical approach that combines prior knowledge or beliefs with observed data to update and refine probability estimates. In the context of Root Cause Analysis, the Ishikawa diagram is the technique commonly used to visually analyze and identify the root causes of a problem.
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!!!! PLEASE ANSWER ASAP !!!! WILL GIVE BRAINLIEST !!!!
bill is traveling to the museum 42 miles away from his house. on bill's map, his house and the museum are 7 inches apart. what is the scale factor used on bill's map?
Answer:
42÷7=6. that's all. that's my answer. but ask others
Shannon’s bicycle travels 50 feet for every 3 pedal turns. How many pedal turns are needed to travel
one mile (1 mile = 5,280 feet)?
Answer:
316.8
Step-by-step explanation:
take 5280, divide it by 50, and muliply by three.
Your camera determines the focal distance required for your picture to be in focus using the lens equation, 1−1=1, where the focal distance to the object from the lens(D)is related to the focal length (F)and the distance from the lens to the film (S).If an object is placed 8 cm from a lens with a focal length of 4 cm, how far from the lens is the image (film) formed?
If an object is placed 8 cm from a lens with a focal length of 4 cm, the image is 8 cm from the lens
Let the focal length be represented by f
Let the distance between the object and the lens be represented by u
Let the distance between the image and the lens be v
The focal length, f = 4 cm
The distance between the object and the lens, u = 8cm
The distance between the image and the lens, v = ?
The relationship between the focal length (f), distance between the object and the lens (u), and the distance between the image and the lens (v) is given below:
\(\frac{1}{u} + \frac{1}{v} = \frac{1}{f}\)
Substitute f = 4, and u = 8 into the equation above:
\(\frac{1}{8} + \frac{1}{v} = \frac{1}{4} \\\\\frac{1}{v} = \frac{1}{4} - \frac{1}{8}\\\\\frac{1}{v} = \frac{2-1}{8}\\\\\frac{1}{v} = \frac{1}{8}\\\\v = 8\)
Therefore, the image is 8 cm from the lens
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A student spends $48 on school supplies at a store where the sales tax rate is 7%.
What is the sales tax on the supplies in dollars and cents?
Suppose that 10% of all students at a local college have tattoos. Suppose that a simple random sample of 10 students is obtained. What are the probabilities that (a) none of the 10 students have a tattoo, (b) the first student chosen has a tattoo, but the rest do not, and (c) exactly one student has a tattoo?
The probability of none of the 10 students having a tattoo is 0.3486784401, the probability of the first student chosen having a tattoo and the rest not having one is 0.03162277660, and the probability of exactly one student having a tattoo is 0.3162277660.
(a) P(none of the 10 students have a tattoo)
= P(no tattoos) = P(no tattoos in the first student) * P(no tattoos in the second student) * ... * P(no tattoos in the tenth student)
= 0.9 * 0.9 * ... * 0.9 = 0.9^10
= 0.3486784401
(b) P(first student chosen has a tattoo, but the rest do not)
= P(tattoo in the first student) * P(no tattoos in the second student) * ... * P(no tattoos in the tenth student)
= 0.1 * 0.9 * 0.9 * ... * 0.9 = 0.1 * 0.9^9
= 0.03162277660
(c) P(exactly one student has a tattoo)
= P(tattoo in the first student and no tattoos in the others) + P(no tattoos in the first student and tattoo in the second student) + ... + P(no tattoos in the first nine students and tattoo in the tenth student)
= 10 * 0.1 * 0.9^9
= 0.3162277660
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Solve for b.
-7b-12=-61
Answer:
the answer is b=7
b = − 7 b − 12 = − 61 = = − 61
Step-by-step explanation:
mark me brainliest
pls and ty
1) Simplify. 2x^(-2)
Using the above property, the expression of the problem is simplified as follows:
\(2\cdot x^{-2}=2\cdot\frac{1}{x^2}=\frac{2}{x^2}\)Solve the system of equations.
y = 6x + 13
y = 2x + 1
Answer:
x=-3. y=-5
Step-by-step explanation:
Equating both equations,
6x + 13 = 2x + 1
6x - 2x = 1 - 13
4x = -12
x = -3
Plug in the value of x in the given first equation,
y = 6* (-3) + 13 = -18 + 13 = -5
Answer:
{y,x} = {-5,-3}
Step-by-step explanation:
System of Linear Equations entered
y - 6x = 13
y - 2x = 1
Graphic Representation of the Equations
-6x + y = 13 -2x + y = 1 (attached)
Solve by Substitution
y = 2x + 1
(2x+1) - 6x = 13
- 4x = 12
4x = - 12
x = - 3
y = 2x+1
x = -3
y = 2(-3)+1 = -5 (final answer)
hope it helps you!
[amc10b.2011.7] the sum of two angles of a triangle is $\frac{6}{5}$ of a right angle, and one of these two angles is $30^{\circ}$ larger than the other. what is the degree measure of the largest angle in the triangle?
The degree measure of the largest angle is 72° in the triangle.
We have, The sum of two angles of a triangle is 6/5 of a right angle.
One of these two angles is 30° larger than the other.
Let A and B be the two angles of the triangle such that A = B + 30°.
We know that the sum of three angles in a triangle is 180°.
⇒ A + B + C = 180°
⇒ B + 30° + B + C = 180°
⇒ 2B + C = 150°
We also know that the sum of two angles of a triangle is 6/5 of a right angle.
⇒ A + B = 6/5 × 90°
⇒ B + 30° + B = 108°
⇒ 2B = 78°
⇒ B = 39°
C = 150° - 2B ⇒ 72°
A = B + 30° ⇒ 39° + 30° ⇒ 69°
Therefore, the degree measure of the largest angle in the triangle is 72°.
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The acceleration function in (m/s²) and the initial velocity are given for a particle moving along a line. Find a) the velocity at time t, and b) the distance traveled during the given time interval: a(t) = 2t+3, v(0) = -4, 0≤t≤3(a) Find the velocity at time t.(b) Find the distance traveled during the given time interval.
a) The velocity at time t can be calculated using function v(t) = t² + 3t - 4.
b) The distance traveled during the time interval [0, 3] is approximately 30.5 meters.
To find the velocity function v(t), we need to integrate the acceleration function a(t) with respect to time:
a(t) = 2t + 3
∫a(t) dt = ∫(2t + 3) dt
v(t) = ∫(2t + 3) dt = t² + 3t + C
We need to find the constant C using the initial velocity v(0) = -4:
v(0) = 0² + 3(0) + C = C = -4
So the velocity function is:
v(t) = t² + 3t - 4
To find the distance traveled during the time interval [0, 3], we need to integrate the absolute value of the velocity function:
d(t) = ∫|v(t)| dt = ∫|t² + 3t - 4| dt
The velocity changes sign at t = -4 and t = 1, so we need to break the integral into three parts:
d(t) = ∫(-t² - 3t + 4) dt for 0 ≤ t ≤ 1
+ ∫(t² + 3t - 4) dt for 1 ≤ t ≤ 3
+ ∫(-t² - 3t + 4) dt for -4 ≤ t ≤ 0
Evaluating each integral, we get:
d(t) = [-1/3t³ - 3/2t² + 4t] for 0 ≤ t ≤ 1
+ [1/3t³ + 3/2t² - 4t + 11] for 1 ≤ t ≤ 3
+ [1/3t³ + 3/2t² + 4t] for -4 ≤ t ≤ 0
Now we can calculate the distance traveled by subtracting the distance traveled in the negative time interval from the distance traveled in the positive time interval:
d(3) - d(0) = [1/33³ + 3/23² - 43 + 11] - [-1/30³ - 3/20² + 40]
= 30.5
So the distance traveled during the time interval [0, 3] is approximately 30.5 meters.
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write twelve thousand twelve hundred and twelve in numbers
Answer:
12, 120,012
Step-by-step explanation:
Please help.How do I find the length of x?
Since the area of B is 9 times the area of A, we know that the sides of B are √9= 3 times the length of the sides of A.
That's how.
It is roughly 8100 miles to fly from California to Australia. If it takes the airplane 15 hours to reach its destination of Australia, what was the average speed of the airplane in feet per hour?
Answer:
540 miles an hour or 2,851,200 Feet an hour
Step-by-step explanation:
36. Exactly 9 years ago, Welham purchased a house with a $326,500, 20-year, monthly payment mortgage.
The fixed interest rate on his loan was 4.25% p.a. If Welham made all required payments for the last 8
years (i.e., for the first 96 payment periods of the loan), what is the remaining balance on his loan today?
To calculate the remaining balance on Welham's loan today, we need to determine the outstanding principal after 96 payment periods.
First, we calculate the monthly interest rate by dividing the annual interest rate by 12:
r = 4.25% / 12 = 0.04208333
Next, we calculate the number of remaining payment periods:
n = 20 years * 12 months/year - 96 payment periods = 144 - 96 = 48 payment periods
Using the formula for the monthly payment on a fixed-rate mortgage, we can calculate the monthly payment amount:
P = $326,500
r = 0.04208333
n = 20 years * 12 months/year = 240 payment periods
monthly payment = P * (r * (1 + r)^n) / ((1 + r)^n - 1)
After calculating the monthly payment amount, we can use the remaining balance formula for a fixed-rate mortgage:
remaining balance = monthly payment * ((1 + r)^n - (1 + r)^p) / r
where p is the number of payments made (96 payment periods in this case).
Substituting the values into the formula, we can calculate the remaining balance on the loan today.
Please note that the exact calculations require precise values for the interest rate and the number of remaining payment periods. Make sure to use the actual values provided in the problem statement to obtain an accurate result.
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Find the area of the region between y=x^1/2 and y=x^1/5 for 0<=x<=1.
area =
The area of the region between y=x^(1/2) and y=x^(1/5) for 0<=x<=1 is 1/6 square units.
To find the area between the two curves y=x^(1/2) and y=x^(1/5) for 0<=x<=1, we will use the definite integral.
Step 1: Identify the bounds of integration. Since the question specifies 0<=x<=1, these are our bounds.
Step 2: Determine the difference between the two functions. Subtract the smaller function from the larger one: (x^(1/2)) - (x^(1/5)).
Step 3: Set up the integral. We will integrate the difference of the two functions with respect to x, from 0 to 1.
area = ∫(x^(1/2) - x^(1/5)) dx from 0 to 1
Step 4: Evaluate the integral. Using the power rule for integration, we get:
area = (2/3 * x^(3/2) - 5/6 * x^(6/5)) evaluated from 0 to 1
Step 5: Substitute the bounds and find the area.
area = [(2/3 * (1)^(3/2) - 5/6 * (1)^(6/5)) - (2/3 * (0)^(3/2) - 5/6 * (0)^(6/5))]
area = (2/3 - 5/6)
area = 1/6
The area of the region between y=x^(1/2) and y=x^(1/5) for 0<=x<=1 is 1/6 square units.
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