A jogger runs 300m due west and then turns and runs 500m due south. what is her total displacement

Parallel pennies distance that must be had to make a 1.80 pf capacitor is 0.0154 mm.

To determine, we need to use the formula for the capacitance of a parallel plate capacitor.

                                                                         C = εA/d

where C is the capacitance, ε is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.
Given that the capacitance is 1.80 pf and the radius of the penny is 1.0 cm, we can plug these values into the formula and solve for d:
1.80 pf = (8.85 × 10⁻¹² F/m)(π × (1.0 cm)²)/d

        d = (8.85 × 10⁻¹² F/m)(π × (1.0 cm)²)/(1.80 pf)

        d = 0.0000154 m

Therefore, the parallel pennies would have to be 0.0000154 m, or 0.0154 mm, apart to make a 1.80 pf capacitor.

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The required speed of the electron is calculated to be 0.73% of the speed of light.

De Broglie wavelength is given as 3.31 × 10⁻¹⁰ m.

The de Broglie wavelength λ is given by the following formula,

λ = h/p ---(1)

where,

h is planck's constant (6.626 × 10⁻³⁴ m²kg/s)

p is momentum of the atom

p can be written as,

p = me × v ---(2)

where,

me is mass of electron (9.11 × 10⁻³¹ kg)

v is velocity of the electron

Using (2) in (1), we have,

λ = h/(me × v)

To find out the velocity of electron, we have to make v as subject.

v = h/(me × λ) = (6.626 × 10⁻³⁴)/(9.11 × 10⁻³¹ × 3.31 × 10⁻¹⁰) = 0.219 × 10⁻³⁴ × 10⁴¹ = 0.219 × 10⁷ m/s = 2.19 × 10⁶ m/s

According to calculations, the electron moving relative to the speed of light as,

⇒ v/c × 100 = (2.19 × 10⁶)/(3 × 10⁸) × 100 = 0.73 %

The needed electron speed is therefore 0.73% of the speed of light.

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Answer:

1.27551m

Explanation:

This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.

Thus, we get:

\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)

We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)

One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.

\(KE_{initial} = PE_{final}\)

Plugging in:

\(\frac{1}{2}*30*5^2 = 30*9.8*h\)

Solving for h, we get 1.27551m

To determine the fracture stress of the rebar, we need to use the formula for stress, which is stress = force/area. We know that the load applied to the rebar is 31,000 lbs, but we need to determine the cross-sectional area of the rebar to calculate the fracture stress.

Assuming a standard size for the rebar, we can use the formula for the area of a circle to calculate its cross-sectional area. The formula for the area of a circle is A = πr^2, where A is the area and r is the radius of the circle.

If we assume a radius of 0.5 inches for the rebar, the cross-sectional area would be A = π(0.5)^2 = 0.785 square inches.

Now we can calculate the fracture stress by dividing the load by the cross-sectional area: stress = 31,000 lbs / 0.785 in^2 = 39,490 psi.

Therefore, the fracture stress of the rebar is approximately 39,490 psi. This means that if the stress applied to the rebar exceeds this value, it will break.

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The measurement that is closest to 1×10^-2 m is the width of a student's finger.

In mathematics, scientific notations are used to express very small or very large values that will occupy a lot of space on paper when written in full.

The length of a football field and height of a school teacher are far larger than the value, 1×10^-2 m. Also, the diameter of an atom is quite smaller than this value.

It then follows that, the measurement that is closest to 1×10^-2 m is the width of a student's finger.

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Answer:

B my brother say that it was

(a) The image distance is approximately 5.10 cm.

(b) The object distance is approximately 1.9659 cm.

To solve the problem, we can use the lens formula, which relates the object distance (u), image distance (v), and focal length (f) of a lens:

1/f = 1/v - 1/u

Given:

Focal length (f) = -3.20 cm (negative sign indicates a diverging lens)

Image distance (v) = 5.10 cm

(a) Finding the image distance (v):

We know that the focal length (f) and image distance (v) are given. Plugging these values into the lens formula, we can solve for the object distance (u).

1/f = 1/v - 1/u

Substituting the given values:

1/(-3.20 cm) = 1/(5.10 cm) - 1/u

Simplifying:

-0.3125 cm^(-1) = 0.1961 cm^(-1) - 1/u

Rearranging the equation:

1/u = 0.1961 cm^(-1) + 0.3125 cm^(-1)

1/u = 0.5086 cm^(-1)

Taking the reciprocal:

u = 1 / (0.5086 cm^(-1))

u = 1.9659 cm

Therefore, the object distance is approximately 1.9659 cm.

(b) Finding the object distance (u):

We have already found the object distance (u) in the previous step.

Object distance (u) ≈ 1.9659 cm.

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Answer: Differences: Solids have particles that are tightly packed and they form a pattern. In this case, they move and vibrate in place. On the other hand, liquid particles are close together but they have an irregular arrangement. The spaces between the particles allow them to move freely.

Explanation:

Particles in solids are arranged in a pattern and are closely packed. In this instance, they remain stationary and vibrate. However, despite being close together, liquid particle arrangements are asymmetrical. The particles can travel freely because of the voids between them and the similarity is both solid and liquid has some shape, but gas does the random movement in the container.

In solid the particles are tightly packed with each other, so there will be no such movement by the particles it means that there the particles have very less kinetic energy. Solids have definite shape and size, and they are incompressible in nature, and they are tough and rigid as well.

In liquid the particles are lightly packed with each other due to which there is some movement in the particles it means that the particles have some kinetic energy. The liquids are compressible in nature. They do not have a specific shape, but they can take the shape of a container where it is filled.

Liquids are fluid in nature.

In gases, there is so much of  distance between particles due to which the particles do random movement, and they have high kinetic energy. They do not have any shape and size, but they are highly compressible as compared to solid and liquid. They also take the shape of the container where they filled.

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If F = 37 N, the static frictional force between the block and the table and the minimum force required to move it must be equal.

It is the force that regulates itself. The value of static friction varies from zero to the smallest force required to initiate motion. The formula for determining static friction is as follows: Normal Force divided by the static friction coefficient is static friction.

Although the maximum static friction will rise, the frictional force will always be the same as the weight in mg because friction cannot accelerate an object. Because FrN can take any value less than N to balance the weight, this is the case.

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Answer:

During a thunderstorm, lightning is seen first and thunder is heard later on because light travels faster than sound. If you see a lightning flash but cannot hear any thunder, the thunderstorm is most likely be quite far away from you.

If Frank leaves Gainesville at 7:30 am, the time he should arrive in Tampa is 12.00 pm after spending 4 hours 30 minutes on the road.

The average speed of an object is the ratio of total distance to total time of motion.

V = total distance/total time

For Frank to be in Tampa by noon, he must spend atleast 4 hours 30 minutes on the road.

18.3 mph = d/4.5 h

d = 82.35 miles

The distance between Gainesville  and Tampa is 82.35 miles.

Thus, we can conclude that, if Frank leaves Gainesville at 7:30 am, the time he should arrive in Tampa is 12.00 pm after spending 4 hours 30 minutes on the road.

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Voyager 2 passed closer to the southern magnetic pole of Uranus.

During its flyby of Uranus in 1986. This was determined by the measurements taken by the spacecraft's instruments, which detected the magnetic field of Uranus and allowed scientists to map its magnetic structure.

The spacecraft's trajectory and the data collected indicated that Voyager 2 passed nearer to the southern magnetic pole than the northern one. This encounter provided valuable insights into the magnetic field and overall magnetosphere of Uranus, contributing to our understanding of the planet's unique characteristics and the dynamics of its magnetic environment.

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Answer:

Hai quả cầu nhỏ hoàn toàn giống nhau, mang điện tích q1, q2 đặt trong chân không cách nhau 20cm thì hút nhau F = 5×10^-5. đặt vào giữa hai quả cầu tấm thủy tinh dày 5 cm có hằng số điện môi là 4. tính lực tác dụng giữa hai quả cầu

To solve this problem, we need to use the formula for calculating the current in an AC circuit that contains a resistor and a capacitor in series. The formula is:

I = V/Z

where I is the current, V is the voltage, and Z is the impedance of the circuit, which is given by:

Z = sqrt(R^2 + (1/ωC)^2)

where R is the resistance, C is the capacitance, and ω is the angular frequency, which is equal to 2πf, where f is the frequency in hertz.

Using the given values, we can calculate the current in the circuit as follows:

R = 3.45 kΩ = 3450 Ω

C = 1 μF = 1 × 10^-6 F

f = 50 Hz

ω = 2πf = 2π × 50 = 314.16 rad/s

Z = sqrt((3450)^2 + (1/(314.16 × 1 × 10^-6))^2) = 109.12 Ω

I = V/Z = 115/109.12 = 1.054 A (to three significant figures)

Therefore, the rms current in the circuit is 1.054 A.

To calculate the average power consumed by the circuit, we can use the formula:

Pavg = Irms^2R

where R is the resistance of the circuit.

Pavg = (1.054)^2 × 3450 = 3,809 W (to three significant figures)

Therefore, the average power consumed by the circuit is 3,809 W.

To find the phase angle between the current and the voltage, we can use the formula:

tan(θ) = 1/(ωCR)

θ = tan^-1(1/(314.16 × 1 × 10^-6 × 3450)) = 0.025 radians (to three significant figures)

Therefore, the phase angle between the current and the voltage is 0.025 radians.

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Answer:

led would be the best for decorations

Explanation:

Answer:

10

Explanation:

you have to divide 25 and 50 the multiply 2

Unless a light ray comes into contact with a surface or enters a different material, it travels in a​ straight line.

When light enters a medium with a different speed or transitions from a fast to a slow medium, refraction occurs. According to Snell's law, if a light ray is incident ordinarily on the surfaces, then deviating from the normal will always lengthen the travel time.

Theoretically, sine (angle of incidence)*index of refraction of the incident media = sine (angle of refraction)*index of refraction of the refractive medium

Sine (0)=0 because the angle of incidence is 0 degrees.

As a result, the light ray will travel straight.

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The factor that leads to interference between waves is similar wave amplitudes. So, the correct option is b.

Constructive interference occurs when the crests of one wave overlap the crests of the other wave, causing an increase in wave amplitude. Destructive interference occurs when the crests of one wave overlap the troughs of the other wave, causing a decrease in wave amplitude. To set up a clear interference pattern, two conditions must be met: The sources of the waves must be coherent, which means they emit identical waves with a constant phase difference. The waves should be monochromatic - they should be of a single wavelength.

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Answer:

Similar wave amplitudes

Explanation:

I got it right on the test.

Answer:

A proposed answer to a s scientific problem is a hypothesis.

The position of the object is the property that distinguishes the potential energy from kinetic energy.

What is potential energy?

The potential energy of a body or system is due to the position of the different components.

\(U = mgh\)

Where,

\(m\) - mass

\(g\) - graviatational acceleration

\(h\) - height

The kinetic energy of a body is due to its motion. It can be given as,

\(KE = \dfrac 12 mv^2\)

Where,

\(v\)- velocity

Since both potential energy and kinetic energy depend upon the mass, power, can perform work.

Therefore, the position of the object is the property that distinguishes the potential energy from kinetic energy.

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Answer:

Explanation:

F = ma, so filling in:

15000 = 30000a and

a = .50 m/s/s

The acceleration of a train is 0.50 \(m/s^{2}\).

Acceleration is the rate of change of the velocity of an object with respect to time.

F = ma

a = F/m

a = 15000/30000

a = 0.50 \(m/s^{2}\)

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In order to calculate a planet's orbital period, we must know the dimensions of its orbit. The correct answer is C.

To calculate a planet's orbital period, we need to know the dimensions of its orbit, specifically the semi-major axis. The semi-major axis is the average distance between the planet and its parent star (assuming a circular or nearly circular orbit). The orbital period of a planet is determined by its distance from the star and the mass of the star.

The tilt of the planet's axis (option A) affects the planet's seasons but does not directly impact its orbital period. The radius of the planet (option B) is not directly related to its orbital period either. The velocity of the planet (option D) can vary along its orbit, but it is not sufficient on its own to calculate the orbital period. Hence the correct answer is C.

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The phenomenon in hearing that is analogous to spatial frequency channels in vision is critical bands. Hence, the correct option is A: Critical bands.

Critical bands are regions of the audible frequency range in which a complex sound is divided into individual, discrete frequency bands by the human auditory system.

For instance, when different frequencies in a complex sound, such as a musical instrument or a human voice, are picked up by the ear, they are sent to the brain via various channels that respond to specific frequencies.

These channels are referred to as critical bands. The frequency range of these bands varies depending on the loudness of the sound.

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The cue ball's final velocity is 0.453 m/s, or 0.90 m/s.

The pace at which an item goes in one direction is known as its velocity. As the velocity of a car driving northward on a highway or the pace at which a rocket takes off. The vector quantity velocity (v), denoted by the formula v = s/t, quantifies deformation (or shift in position, s), over change in time (t).

The displacement that such an object or particles experiences with regards to time is expressed vectorially as velocity. The meters per second (m/s) is the accepted unit of velocity profile (sometimes known as speed).

Let "v" represent the ball's ultimate speed.

Apply the law of linear momentum conservation.

Total initial momentum is = Total final momentum

=(0.17 x 1.3) + (0.16 x 0) = (0.17 x v) + (0.16 x 0.90)

0.221 = 0.17v + 0.144

0.17 v = 0.221 - 0.144

v = (0.077) / (0.17)

v = 0.453 m/s

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Answer:

WP LA æ WI all all Eduardo whatever Cincinnati quips I was just wondering if you want to be a good day

\(a_avg = (22 m/s - 4 m/s) / 3 s = 18 m/s / 3 s = 6 m/s^2,\) Therefore, the average acceleration of the roller coaster car is \(6 m/s^2\).

Newton's first law states that each change in velocity (a change in either magnitude or direction) must have a cause. The law of inertia is another name for this rule. An external force called friction slows down an object.

a_avg = (v_f - v_i) / t

So, the average acceleration is:

a_avg = (22 m/s - 4 m/s) / 3 s

= 18 m/s / 3 s

\(= 6 m/s^2\)

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To determine the greatest distance you can be from the base camp at the end of the third displacement, regardless of direction, we need more specific information about the magnitudes and directions of the displacements.

Displacement is a vector quantity that has both magnitude and direction. The distance covered during multiple displacements depends on the individual magnitudes and directions of each displacement. Without specific values, it is not possible to determine the exact greatest distance from the base camp.

If you provide the magnitudes and directions of the three displacements, I can help you calculate the total distance and determine the maximum possible distance from the base camp at the end of the third displacement.

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Answer:

5 years worth of work (aka all of the homework i currently have)

Answer:

a)   τ₁ = 660 N m,  b)  τ’= 686 N m,  c)    F = 623.6 N

Explanation:

a) For this exercise let's use the concepts of torque and rotational balance.

For this we set a reference system at the base and assuming that the counterclockwise rotations are positive

where the force F = 600 N, the distance to the axis is x = 1.1 m, the mass of the system m = 70g and the weight is placed at the point of the center of  gravity x_{cm} = -1.0 m

The torque at the front is

          τ₁ = F x

          τ₁ = 600 1.1

          τ₁ = 660 N m

b) let's write the rotational equilibrium condition

           ∑ τ = 0

           τ'- W x_{cm} = 0

           τ ’= mg x_{cm}

            τ’= 70 9.8 1.0

            τ’= 686 N m

c) the greatest force Matt can apply

           τ’= F x

           F = τ’/ x

           F = 686 / 1.1

           F = 623.6 N