A landscaper plants 1,923 rose bushes in rows with 15 rose bushes in each row. How many rows of rose bushes does the landscaper plant to fit all the rose bushes? *
HELP ASAP

a) 4x + 2x = 6x - 4

= 6x = 6x - 4

cannot be solved further.

b) 3(2x + 4) = 2(2x - 4)

= 6x + 12 = 4x - 4

(bring the numbers and variables on one side)

= 6x + 4x = 12 - 4

10x = 8

x = 8/10 = 4/5

can be solved.

c) 5(x - 3) = 5x - 3

= 5x - 15 = 5x - 3

= (bring the variables and numbers on one side)

5x + 5x = -15 - 3

= 10x = -18

x = -18/10 = 9/5

can be solved

d) 2x = 2x + 4

= 2x + 2x = 4

= 4x = 4

x = 4/4 OR 1.

a. The median number of calls = 55

b. The first and third quartiles, Q1 = 48 and Q3 = 66

c. The first decile and the ninth decile, D1 = 45 and D9 = 71.

d. The 33rd percentile = 52.5

To answer the questions, let's first organize the data in ascending order:

38 40 41 45 48 48 50 50 51 51 52 52 53 54 55 55 55 56 56 57 59 59 59 62 62 62 63 64 65 66 66 67 67 69 69 71 77 78 79 79

(a) The median is the middle value of a dataset when arranged in ascending order.

Since we have 40 observations, the median is the value at the 20th position.

In this case, the median is the 55th visit.

(b) The quartiles divide the data into four equal parts.

To find the first quartile (Q1), we need to locate the position of the 25th percentile, which is 40 * (25/100) = 10.

The first quartile is the value at the 10th position, which is 48.

To find the third quartile (Q3), we need to locate the position of the 75th percentile, which is 40 * (75/100) = 30.

The third quartile is the value at the 30th position, which is 66.

Therefore, Q1 = 48 and Q3 = 66.

(c) The deciles divide the data into ten equal parts.

To find the first decile (D1), we need to locate the position of the 10th percentile, which is 40 * (10/100) = 4.

The first decile is the value at the 4th position, which is 45.

To find the ninth decile (D9), we need to locate the position of the 90th percentile, which is 40 * (90/100) = 36.

The ninth decile is the value at the 36th position, which is 71.

Therefore, D1 = 45 and D9 = 71.

(d) To find the 33rd percentile, we need to locate the position of the 33rd percentile, which is 40 * (33/100) = 13.2 (rounded to 13). The 33rd percentile is the value at the 13th position.

Since the value at the 13th position is between 52 and 53, we can calculate the percentile using interpolation:

Lower value: 52

Upper value: 53

Position: 13

Percentage: (13 - 12) / (13 - 12 + 1) = 1 / 2 = 0.5

33rd percentile = Lower value + (Percentage * (Upper value - Lower value))

                = 52 + (0.5 * (53 - 52))

                = 52.5

Therefore, the 33rd percentile is 52.5.

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Answer:

The answer is true.

Step-by-step explanation:

Because we are working on negative integers and if a negative number is leaning more to the right on a number line it is bigger.

We can use Lagrange multipliers to find the distance from the plane x + y + z = 0 to the center of the sphere S, which is given by the point (5,7,9).

Let f(x,y,z) be the distance between the point (x,y,z) and (5,7,9), which is given by the formula:

f(x,y,z) = √[(x-5)² + (y-7)² + (z-9)²]

Let g(x,y,z) be the equation of the plane x + y + z = 0, which can be rewritten as:

g(x,y,z) = x + y + z

We want to minimize f(x,y,z) subject to the constraint g(x,y,z) = 0, which means we need to solve the system of equations:

∇f = λ∇g

g(x,y,z) = 0

where ∇f and ∇g are the gradient vectors of f and g, respectively, and λ is a Lagrange multiplier.

Taking the partial derivatives of f and g, we have:

∂f/∂x = (x-5)/√[(x-5)² + (y-7)² + (z-9)²]

∂f/∂y = (y-7)/√[(x-5)² + (y-7)² + (z-9)²]

∂f/∂z = (z-9)/√[(x-5)² + (y-7)² + (z-9)²]

∂g/∂x = 1

∂g/∂y = 1

∂g/∂z = 1

Setting ∇f = λ∇g, we get the following system of equations:

(x-5)/√[(x-5)² + (y-7)² + (z-9)²] = λ

(y-7)/√[(x-5)² + (y-7)² + (z-9)²] = λ

(z-9)/√[(x-5)² + (y-7)² + (z-9)²] = λ

x + y + z = 0

Squaring the first three equations and adding them up, we get:

(x-5)² + (y-7)² + (z-9)² = λ²[(x-5)² + (y-7)² + (z-9)²]

Simplifying, we get:

(1-λ²)x² + (1-λ²)y² + (1-λ²)z² - 10x - 14y - 18z + 135 = 0

This is a quadratic form in x, y, and z, which can be diagonalized using a rotation of coordinates. The diagonalization yields:

(1-λ²)(x'-5)² + (1-λ²)(y'-7)² + (1-λ²)(z'-9)² = 135 - 25λ²

where (x',y',z') are the new coordinates obtained by the rotation. The minimum value of λ is achieved when the right-hand side of the above equation is minimized, which occurs when λ = ±1. Therefore, the distance between the plane x+y+z=0 and the center of the sphere S is given by:

d = √[(x'-5)² + (y'-7)² + (z'-9)²]

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There are 13 different colors available for the top stripe, 5 colors available for the middle stripe, and 8 colors available for the bottom stripe. To determine the total number of color possibilities or combinations, we need to multiply the number of options for each stripe.

For the top stripe, Rosie has 13 different colors to choose from. For the middle stripe, she has 5 different colors to choose from. And for the bottom stripe, she has 8 different colors to choose from.

To find the total number of combinations, we multiply the number of options for each stripe together:

13 colors for the top stripe × 5 colors for the middle stripe × 8 colors for the bottom stripe = 520 total color possibilities.

Therefore, Rosie has a total of 520 color possibilities for her flag design.

Rosie has 13 options for the top stripe, 5 options for the middle stripe, and 8 options for the bottom stripe. By multiplying these numbers together, we find that there are 520 total color possibilities for her flag design.

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The length of the two pieces is = 3 - 3B yards

The length of piece one (A) = 3 - 2B

The length of piece two ( second piece) = B

Therefore the total length of the two pieces( T) is =

length of piece one (A) + length of piece two ( second piece).

That is,

T = 3 - 2B + B

T = 3 - 3B

Therefore the length of the two pieces is = 3 - 3B yards

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The optimal solution is Z = -74, X = 4, Y = 2.

Maximize Z = 20X + 3Y

Subject to:

A1: 2X + Y + S1 = 10

R2: 3X + 3Y + S2 = 18

R3: 2X + 4Y + S3 = 20

X = 0, Y ≥ 0

The initial tableau for the simplex method is given below.

The column labels represent the variables, and the row labels represent the equations and slack variables. The bottom row (RHS) represents the right-hand side values of the equations.

To find the optimal solution, we'll perform the simplex method iterations:

Iteration 1:

Pivot column: Y (the most negative coefficient in the Z row)

Pivot row: S2 (smallest positive ratio of RHS to coefficient in the pivot column)

Performing row operations:

Divide row S2 by 3 to make the pivot element (coefficient of Y) equal to 1.

Row S2 = Row S2 / 3

Row S2: 1 | 1 | 0 | 1/3 | 0 | 6

Eliminate other elements in the pivot column:

Row Z = Row Z - (3 * Row S2)

Row S1 = Row S1 - (1 * Row S2)

Row S3 = Row S3 - (0 * Row S2)

Row Z: 20 | 0 | 0 | -3 | 0 | -18

Row S1: 1 | 0 | 1 | -1/3 | 0 | 4

Row S3: 2 | 1 | 0 | -2/3 | 1 | 14

Iteration 2:

Pivot column: X (the most negative coefficient in the Z row)

Pivot row: S1 (smallest positive ratio of RHS to coefficient in the pivot column)

Performing row operations:

Divide row S1 by 1 to make the pivot element (coefficient of X) equal to 1.

Row S1 = Row S1 / 1

Row S1: 1 | 0 | 1 | -1/3 | 0 | 4

Eliminate other elements in the pivot column:

Row Z = Row Z - (20 * Row S1)

Row S2 = Row S2 - (0 * Row S1)

Row S3 = Row S3 - (2 * Row S1)

Row Z: 0 | 0 | -20 | -2/3 | 0 | -74

Row S2: 1 | 1 | 0 | 1/3 | 0 | 6

Row S3: 0 | 1 | -2 | -2/3 | 1 | 6

Since there are no negative coefficients in the Z row, we have reached the optimal solution.

Final Solution:

Z = -74 (maximum value of the objective function)

X = 4

Y = 2

S1 = 0

S2 = 6

S3 = 6

Therefore, the maximum value of Z is -74, and the optimal values for X and Y are 4 and 2, respectively. The slack variables S1, S2, and S3 are all zero, indicating that all the constraints are satisfied as equalities.

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To answer this question, we need to know the median and upper quartile of the data set. Once we have these values, we can determine what percentage of the data falls to the right of the median and to the left of the upper quartile.
Let's say the median of the data set is 50 and the upper quartile is 75. To find the percentage of measurements to the right of the median, we need to look at the data values that are greater than 50 and divide that number by the total number of measurements. Let's say there are 40 data values greater than 50 and a total of 100 measurements.

Then, the percentage of measurements to the right of the median would be:

(40/100) x 100% = 40%

To find the percentage of measurements to the left of the upper quartile, we need to look at the data values that are less than or equal to 75 and divide that number by the total number of measurements. Let's say there are 60 data values less than or equal to 75 and a total of 100 measurements. Then, the percentage of measurements to the left of the upper quartile would be:

(60/100) x 100% = 60%


Your answer:
1. 40% of the measurements lie to the right of the median.
2. 60% of the measurements lie to the left of the upper quartile (Q3).

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Answer:

3/2

Step-by-step explanation:

\(A'B'=6, AB=4\)

The scale factor is the ratio of the lengths of a pair of corresponding sides. (image to preimage).

Thus, the scale factor is \(6/4=3/2\).

Answer:

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

16 times 13 = 208

208 divid by 26 is 8

Answer:

8

Step-by-step explanation:

area = 16ft*13ft= 208ft^2

1 bag = 26 ft^2

208 ft^2/ 26ft^2 = 8 bags

brainliest please

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input.

The collection of all potential inputs for a function is its domain. For instance, the domain of f(x)=x2 and g(x)=1/x are all real integers with the exception of x=0.

Think about the function y = f. (x). The range of the function is the range of all the y values, from least to maximum. Substitute all possible values of x into the provided expression of y to see whether it is positive, negative, or equal to other values.

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Answer:

32

Brainiest plz?  :)

Answer:

23696

Step-by-step explanation:

\(Step1\1\\We\ know\ that:\)

↓

\(P=15000\)
\(r=6.75\)%
\(n=1\)
\(t=7\)

\(Step\ 2:\ Formulate\ and\ substitute:\)

                                \(P=15000\)
                                \(r=6.75\)%

\(Substitute\)                                  \(into\ formula\)

                                \(n=1\)
                                \(t=7\)

\(F=P\ast(1+r/n)^{nt}\)

\(F=15000\bullet(1+6.75\bullet\frac{1}{100})^7\)

\(Step\ 3:Evaluate\)

\(Evaluate\ the\ equation/expression:\)

\(23695.53098\)

\(Step\ 4:\ Find\ the\ value\)

\(Find\ the\ closest\ integer\ to\ 23695.53098:\)

\(23696\ YOUR\ ANSWER\)

I hope this helps you

:)

To minimize the overall number of coins the value would be V mod (100 + 50 + 25 + 10 + 5) so option d is correct choice.

           
This function returns the remainder when the V value is divided by the total value of the largest coin denomination available (100) plus the four next largest coin denominations (50, 25, 10, 5). As a result, a number of changes that cannot be implemented using only the largest denominations of coins must be implemented using smaller denominations, including pennies.


A legitimate capability would consider the value of the various coin sections and use that data to decide the most effective method for rolling out the improvement with the fewest coins possible.

The capability would almost certainly include division and modulus activities to compute the remainder of the value of V when partitioned by the value of each coin group.

The result of the capability would be the number of pennies required to complete the exchange, as pennies are the smallest denomination of coin that anyone could hope to find.


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The expressions that could represent the length and width are (x - 2) units and (x - 7) units respectively.

To find the expressions that represent the length and width of the rectangle, we need to factor the given expression.

x² - 9x + 14 = (x - 2)(x - 7)

The length and width of the rectangle are represented by two factors of the expression.


To find the length and width of the rectangle, we need to understand the formula for the area of a rectangle, which is length multiplied by width. The given expression x²-9x+14 represents the area of the rectangle. To find the expressions that represent the length and width, we need to factor the given expression.

We can do this by finding two numbers that multiply to 14 and add up to -9. These numbers are -2 and -7. Therefore, we can factor the given expression as (x - 2)(x - 7). From this, we can see that the length of the rectangle is represented by the factor (x - 2) units and the width is represented by the factor (x - 7) units.

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Answer:

a

Step-by-step explanation:

First, let find the first five terms using the recursive formula:

Then:

Now,

a1 = 2

For a2 :

a2= 4

For a3:

a3 = 8

For a4:

a4 = 16

For a5:

a5 = 32

Therefore, the five first terms are 2,4,8,16,32.

Now, the common ratio is 2.

The explicit formula hast the next form:

where d is the common ratio.

Replace using a1=2 and d=2

Therefore, the explicit formula is given by:

The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.

The first three prime numbers are 2, 3, and 5. The first three composite numbers are 4, 6, and 8. In order for a number to be divisible by all six of these numbers, it must be divisible by their least common multiple (LCM).

The LCM of 2, 3, 5, 4, 6, and 8 is 120. Therefore, the smallest three-digit number divisible by the first three prime numbers and the first three composite numbers is 120.

Here is a more detailed explanation of how to calculate the LCM:

Find the prime factorization of each number.

Find the highest power of each prime factor.

Multiply the prime factors together, using the highest power for each factor.

The highest power of 2 that appears in any of the prime factorizations is 2^3.

The highest power of 3 that appears in any of the prime factorizations is 3^1.

The highest power of 5 that appears in any of the prime factorizations is 5^1.

Therefore, the LCM of 2, 3, 5, 4, 6, and 8 is 2^3 * 3^1 * 5^1 = 120.

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Answer:

612

Step-by-step explanation:

you multiply 27 x 12 and 24 x 12, and add up the products, and you get 612

Answer: 612 Treats

Work: To find out how many treats he baked, you do 27 x 12 and 24 x 12. After doing so, you get 324 and 288. Add those up, and you get 612.

I hope this helps, and Happy Holidays! :)

The confidence interval is used to estimate the average age of all Pokémon players. Option(a) is correct.

A confidence interval displays the probability that a parameter will fall between two values close to the mean. Confidence intervals express the degree of certainty or unpredictability of a sampling technique.

The importance of a proposed (hypothesized) relationship between population statistics (parameters) and their corresponding sample estimators is examined using a hypothesis test, a statistical inference technique.

We employ confidence intervals whenever we want to estimate any parameters.

To Calculate the estimated mean we use the confidence interval formula

(X bar ± Z*σ/√n)

So option (a) is correct.

Therefore confidence interval is used to estimate the average age of all Pokémon players.

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5p-2p-3p=-4+4

Solving, we have 0 = 0. It indicates the value of p must be any value.

The sampling method used by the marketing manager of a supermarket to obtain information about the ages of its customers is "Simple Random Sampling".

Simple Random Sampling method involves selecting a sample of n observations from a population of size N in a way that each individual has an equal chance of being selected at any stage during the sampling process. This method ensures that the sample represents the population as closely as possible.

In this case, the marketing manager selects 100 customers randomly at each store location over the next two weeks. This sampling method ensures that each customer has an equal chance of being selected, and it is a cost-effective method as it does not require expensive equipment to perform.

Additionally, the sampling method eliminates bias from the selection process as every customer has an equal chance of being selected at any stage of the sampling process. Hence, the sampling method used by the marketing manager of a supermarket to obtain information about the ages of its customers is Simple Random Sampling.

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Answer:

2 units

Step-by-step explanation:

From one crest (high point) to the next crest  point is one period....

  this covers 2 units on this graph

Answer:

See below

Step-by-step explanation:

\(2(x+5)-3 =15\)

Using the distributive property in the LHS we get

\(2x+10-3 =15\)

\(2x+7=15\)

Now add -7 both sides. So we have the subtraction property of equality.

\(2x+7+(-7)=15+(-7) \text{ This is what I meant for add}\)  

\(2x+7-7=15-7\)

\(2x=8\)

Now divide both sides by 2. So we have the division property of equality

\(\dfrac{2x}{2} =\dfrac{8}{2}\)

\(x=4\)

The TQ is a chord, PR is a secant line and WU is a tangent line.

Circle is a two dimensional figure which consist of set of all the points which are at equal distance from a point which is fixed called the center of the circle.

A chord of a circle is the line segment joining two points on the circle.

Line segments TQ and QV are chords.

TV is also a chord, which is the diameter.

A secant line is a line which intersects the circle at two different points.

Line PR is a secant line which intersects the circle at T and Q.

A tangent line is a line which intersects the circle at exactly one point.

Line WU is a tangent line which intersects the circle at V.

Hence the chords in the given figure are TQ and QV, secant line is PR and tangent line is WU.

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The conversion of a fraction number with denominator 5 and numerator 2 , 2/5 in decimals is equals to the 0.4 value.

A decimal number can be defined as a number whose whole number part and fractional part are separated by a decimal point. Writing 2/5 as a decimal number by converting the denominator to powers of 10. We multiply the numerator and denominator by a number so that the denominator is a power of 10.

2/5 = (2 × 2) / (5 × 2) = 4/10

Now move the decimal point to the left as many places as there are zeros in the denominator, which is a power of 10.

The decimal moved one place to the left because the denominator was 10. Therefore, 4/10 = 0.4. Hence, required value is 0.4.

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