A large research organization wants to recruit graduate secretaries/typists from two commercial institutes. The personnel manager of the organization gave a typing test to 35 graduating students from each of the commercial institutes and observed that the mean of the first group was 65 words per minute with a S1 = 15. The mean of the second group was 70 words per minute with S2 = 10. Using a 1% level of significance, can we say there is a significant difference between the mean scores of the graduates in the two commercial institutes?

The z score associated with the highest 10% is closest to: option (c) 1.28

-To find the z score associated with the highest 10%, first determine the percentage that corresponds to the lower 90%, since the z score table typically represents the area to the left of the z score.

- Look up the 0.90 (90%) in a standard normal distribution  (z score) table, which will give you the corresponding z score.

-The z score closest to 0.90 in the table is 1.28, which corresponds to the highest 10% of values.

Therefore, the z score associated with the highest 10% is closest to 1.28.

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A line spectrum refers to a type of spectrum where light is emitted at specific, discrete frequencies. A continuous spectrum, on the other hand, refers to a type of spectrum where light is emitted at all frequencies within a given range.

A line spectrum refers to a type of spectrum where light is emitted at specific, discrete frequencies. The light is emitted in a pattern of individual lines, hence the name "line spectrum." Hot gases or plasmas often produce this type of spectrum, and the lines represent specific energies of electrons in the gas.

An example of a line spectrum is the Hydrogen spectrum, which consists of a series of distinct lines of different colours that correspond to different energies of the electrons in a hydrogen atom.

A continuous spectrum, on the other hand, refers to a type of spectrum where light is emitted at all frequencies within a given range. The light is emitted in a smooth, continuous manner, hence the name "continuous spectrum." This type of spectrum is often produced by hot solid objects, such as the sun, and it represents a continuous range of energies.

An example of a continuous spectrum is the spectrum of light emitted by the sun, which spans a wide range of frequencies and has a smooth, continuous appearance.

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The percent of the games that was lost is 26.7%.

Percentage is the ratio of two numbers expressed as a number out of 100. The sign that is used to represent percentage is %.

Percentage of the games lost = (number of games lost / total number of games) x 100

Number of games lost = total number of games - number of games won

75 - 55 = 20

Percentage of the games lost = (20 / 75) x 100 = 26.7%

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Answer:

V=15

Step-by-step explanation:

You have to make V the subject of the formula. Start by multiplying both sides of the problem by three to get rid of it on the left and multiply it to 8 on the right. Then carry 9 over to the answer on the right side and make sure tp change the sign to subtraction. Then carry out the operation and you have the answer.

3 (v+9/3)=(8)3

v+9=24

v=24-9

v=15

The energy required to bend a microtubule of length 20 cm into an arc of radius 10 cm can be calculated using the persistence length of the microtubule.

The persistence length is a measure of the stiffness of a polymer, and for a microtubule with a persistence length of 2 mm, the energy required can be determined. In the case of bending a microtubule, the energy can be expressed in units of kBT (Boltzmann constant times temperature).

To calculate the energy, we can consider the microtubule as a flexible rod with a persistence length of 2 mm. The energy required to bend the rod into an arc can be approximated using the worm-like chain model, which describes the behavior of flexible polymers. The energy can be calculated using the formula:

\(\[E = \frac{{k_BT L^2}}{{2P}} \left(1 - \sqrt{1 - \frac{{4PR}}{{L^2}}} \right)\]\)

where E is the energy, \(k_B\) is the Boltzmann constant, T is the temperature, L is the length of the microtubule, P is the persistence length, and R is the radius of the arc. Plugging in the values (\(k_B = 1.38 \times 10^{-23} J/K\), T = temperature in Kelvin, L = 20 cm = 0.2 m, P = 2 mm = 0.002 m, R = 10 cm = 0.1 m), we can calculate the energy in units of kBT.

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Answer:

he answer is 140 minutes to plant 14 saplings.

Step-by-step explanation:

30 divided by 3=10

so it takes 10 minutes to plant one sapling.

10x14=140 so this is how you get your answer. im 99% sure

Answer:

100.8÷3.6=28

he grew the plant for 28 days

Answer:

Percentage error is 0.0024 %

Step-by-step explanation:

Initial average distance between Earth and moon = 384467 km  

Distance measure by the scientist = 384476 km

Total variation in the distance calculation = 384476 – 384467 = 9 km.

Now we can find the percentage by dividing the variation in distance from the initial measurement and then multiply with hundred.

Percentage error = ( 9 /  384467 ) × 100 = 0.0024 %

Step-by-step explanation:

x^2-6x-6x+36=0

x(x-6)-6(x-6)=0

(x-6)(x-6)=0

x=6

Answer:

D

Step-by-step explanation:

In order to calculate the time it will take for Andrew to settle the loan, we can use the formula for compound interest. So, it will take Andrew approximately 5.22 years to settle the loan.

The formula is given as A = P(1 + r/n)^(nt), Where: A = the final amount, P = the principal (initial amount borrowed), R = the annual interest rate, N = the number of times the interest is compounded in a year, T = the time in years.

We know that Andrew borrowed R200 000 from a bank at an annual interest rate of 5.25% compounded quarterly and that he will make repayments of R6 000 at the end of every 3 months.

Since the first repayment will be made 3 months from now, we can consider that the initial loan repayment is made at time t = 0. This means that we need to calculate the value of t when the total amount repaid is equal to the initial amount borrowed.

Using the formula for compound interest: A = P(1 + r/n)^(nt), We can calculate the quarterly interest rate:r = (5.25/100)/4 = 0.013125We also know that the quarterly repayment amount is R6 000, so the amount borrowed minus the first repayment is the present value of the loan: P = R200 000 - R6 000 = R194 000

We can now substitute these values into the formula and solve for t: R194 000(1 + 0.013125/4)^(4t) = R200 000(1 + 0.013125/4)^(4t-1) + R6 000(1 + 0.013125/4)^(4t-2) + R6 000(1 + 0.013125/4)^(4t-3) + R6 000(1 + 0.013125/4)^(4t)

Rearranging the terms gives us: R194 000(1 + 0.013125/4)^(4t) - R6 000(1 + 0.013125/4)^(4t-1) - R6 000(1 + 0.013125/4)^(4t-2) - R6 000(1 + 0.013125/4)^(4t-3) - R200 000(1 + 0.013125/4)^(4t) = 0

Using trial and error, we can solve this equation to find that t = 5.22 years (rounded to 2 decimal places). Therefore, it will take Andrew approximately 5.22 years to settle the loan.

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Answer:

y = -2x-3

Step-by-step explanation:

Answer:

1.

\(C.\\sin(N)=\frac{\sqrt{3} }{2}\)

2.

\(x=82.1\)

3.

x = 18°

Step-by-step explanation:

1. The sine ratio is sin(θ) = opposite/hypotenuse, where θ is the reference angle.  When N is the reference angle, we see that side OP with a measure of 5√3 units is the opposite side and side NP with a measure of 10 units is the hypotenuse.

Thus, we can find plug everything into the sine ratio and simplify:

\(sin(N)=\frac{5\sqrt{3} }{10} \\\\sin(N)=\frac{\sqrt{3} }{2}\)

2. We can use the tangent ratio to solve for x, which is tan (θ) = opposite/adjacent.  If we allow the 75° to be our reference angle, we see that the side measuring x units is the opposite side and the side measuring 22 units is the adjacent side.  Thus, we can plug everything into the ratio and solve for x or the measure of the opposite side:

\(tan(75)=\frac{x}{22}\\ \\22*tan(75)=x\\\\82.10511777=x\\\\82.1=x\)

3. Since we're now solving for an angle, we must using inverse trigonometry.  We can use the inverse of the tangent ratio, whose equation is tan^-1 (opposite/adjacent) = θ.  We see that when the x° is the reference angle, the side measuring 11 units is the opposite and the side measuring 33 units is the adjacent side.  Now we can do the inverse trig to find the measure of x:

\(tan^-^1(\frac{11}{33})=x\\ 18.43494882=x\\18=x\)

The median element of a dataset is the middle element of the dataset.

There are 3 runs above and below the sample median

What is the median of a data set ?

The median of a data set is the value that falls in the middle, indicating that 50% of the data points have values that are lower or equal to the median and 50% of the data points have values that are higher or equal to the median. When working with a small data collection, you must first count the number of data points (n) and organize them in ascending order.

The information is given as:

Observations  1      2       3      4     5     6

Defects           10     18    13    15     9     12

In ascending order, the information is represented as:

Defects           9   10   12   13   15   18

Observations  5    1     6    3     4    2

The total number of observations is:

n=5+1+6+3+4+2 = 21

The median element is calculated as:

Median = (n+1)/2 th

Substitute 21 for n

Median = (21+1)/2 th

Median = 11th

The 11th element is 12.

So, the median is:

median = 12

Considering the given information;

Observations  1      2       3      4     5     6

Defects           10     18    13    15     9     12

The defects greater than the median (i.e. 12) are above (A) the median, while the defects less than the median are below (B)

So, we have:

Observations  1      2       3      4     5     6

Defects           10     18    13    15     9     12

Status               B     A       A     A    B      -

Next, we take a count of the number of times the status changes, i.e. from B to A, from A to B, from A or B to -

The count is 3.

Hence, there are 3 runs above and below the sample median

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Answer:

x = pm - pn

Step-by-step explanation:

m = n + \(\frac{x}{p}\)  Subtract n from both sides

m - n = n - n + \(\frac{x}{p}\)

m-n = \(\frac{x}{p}\)   Multiply both sides by p

p(m - n) = (\(\frac{p}{1}\)) \(\frac{x}{p}\)          \(\frac{p}{1}\) means the same as p

pm - pn = x             Distribute the p

x = pm - pn

Answer:

2x - 2y + 11

Step-by-step explanation:

Step One: Collecting Terms

2x - 2y + 8 + 3

Answer: 2x - 2y + 11

Answer:

Step-by-step explanation:

number 2) 0

Answer:

5/8-2/8=3/8 I hope this helped!

The sum of all the entries of a matrix whose null space consists of all linear combinations of vectors is zero.

To find the sum of all the entries of a matrix whose null space consists of all linear combinations of vectors, follow these steps:

Therefore, the sum of all the entries of a matrix whose null space consists of all linear combinations of vectors is zero.

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The value of the constant k for the function to be a probability density function on the interval (0, 9) is k = 1/18.

To find the value of the constant k such that the function \(f(x) = k\sqrt{x}\) is a probability density function on the interval  (0, 9), you need to make sure that the total probability is equal to 1. This means that the integral of f(x) from 0 to 9 must be equal to 1.

Step 1: Write the integral for the function f(x) from 0 to 9.
∫(0 to 9) k√x dx

Step 2: Find the antiderivative of k√x with respect to x.
Antiderivative of \(k\sqrt{x} =\frac{2}{3} k x^{\frac{3}{2} }\)

Step 3: Evaluate the antiderivative at the limits 0 and 9.
((2/3)k(9)^(3/2)) - ((2/3)k(0)^(3/2)) = (2/3)k(27) - 0 = (2/3)k(27)

Step 4: Set the integral equal to 1 and solve for k.
(2/3)k(27) = 1
k = 1 / (2/3 * 27) = 1 / 18

So, the value of the constant k for the function to be a probability density function on the interval (0, 9) is k = 1/18.

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Answer:

You are correct!!

It would be (-infinity, infinity) :)

Cⁿ₁ is always positive, then the second term has negative sign.

What does binomial expansion mean?

Theorem that states that any power of a binomial (a + b) can be expanded as a specific sum of products (aibj), such as (a + b)2 = a2 + 2ab + b2.

The i-th term of the binomial expansion \((x- y)^{n}\)

Ti = nCi - 1 . (x)ⁿ+¹⁺i  . (-y)i - 1

For any n, when i=2,

T₂ = nC₂₋₁  . xⁿ⁺¹⁻² . (-y)²⁻¹  = -Cⁿ₁ xⁿ⁻¹ . y

Given that is consistently positive, the second term has a negative sign.

Cn1 is consistently positive, and the second term is always negative.

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Step-by-step explanation:

(B) 12 Inches is the answer because perimeter (P) =4l =4×3=12

Answer:

The mean of the numbers are 1

Answer:

1

Step-by-step explanation:

4+0+-3+8+-2+-1=6

6/6=1

We know that the height of the rectangular shape is BC=AD= 4 feet and the the area is A=29.2 ft^2. Since the area of our rectangle is given by

we get

By moving the number 4 to the left hand side, we have

which also is the lenght of one side of our parallelogram.

Now, the area of our parallelogram is given by

where the base is given by segment DC=7.3 ft and the height FG=2 BC. Then, we get

by substituting our previous result and BC=4 ft, we obtain

Then, the answer is 58.4 ft^2

The linear equation of the plane through the origin and the points (5, 4, 2) and (3, -1, 1) is 6x + 1y - 17z = 0.

To find the linear equation of the plane through the origin and the points (5, 4, 2) and (3, -1, 1), you need to find a normal vector to the plane by taking the cross product of the position vectors of the two given points.

Position vector of point A(5, 4, 2): a = <5, 4, 2>
Position vector of point B(3, -1, 1): b = <3, -1, 1>

The cross product of a and b (normal vector to the plane): n = a × b
n = <(4*1 - 2*-1), (2*3 - 5*1), (5*-1 - 3*4)>
n = <4+2, 6-5, -5-12>
n = <6, 1, -17>

Now, the equation of the plane with normal vector n = <6, 1, -17> and passing through the origin (0, 0, 0) is given by: 6x + 1y - 17z = 0

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Answer:

-10x +25

Step-by-step explanation:

–5(2x – 5)

Distribute

-5 * 2x - (-5) * 5

-10x +25

Answer:

-10x + 25

Step-by-step explanation:

-5(2x - 5)

Distribute the expression

-5(2x) + 5(5)

Multiply

-10x + 25

The expression cannot be simplified further

Hope this helps :)

a. To approximate the given quantity using Taylor polynomials with n=3, we need to use the formula for the Taylor polynomial of degree n:

Pn(x) = f(a) + f'(a)(x-a) + (1/2!)f''(a)(x-a)^2 + (1/3!)f'''(a)(x-a)^3 + ... + (1/n!)f^(n)(a)(x-a)^n
where f(x) = sinh(x), a = 0. The derivatives of sinh(x) are:
f'(x) = cosh(x), f''(x) = sinh(x), f'''(x) = cosh(x), and so on.
Therefore, the Taylor polynomial of degree 3 for sinh(x) centered at a = 0 is:
P3(x) = x + (1/2!)(x)^3
To approximate sinh(0.24), we substitute x = 0.24 into the formula above:
P3(0.24) = 0.24 + (1/2!)(0.24)^3 = 0.240008
b. To compute the absolute error in the approximation assuming the exact value is given by a calculator, we need to subtract the actual value of sinh(0.24) from the approximation we obtained in part a:
Error = |P3(0.24) - sinh(0.24)| = |0.240008 - 0.241663| = 0.001655
Therefore, the absolute error in the approximation is 0.001655.
To approximate sinh(0.17), we use the same formula and substitute x = 0.17:
P3(0.17) = 0.17 + (1/2!)(0.17)^3 = 0.170005
To compute the absolute error in this case, we subtract the actual value of sinh(0.17) from the approximation we obtained:
Error = |P3(0.17) - sinh(0.17)| = |0.170005 - 0.17031| = 0.000305
Therefore, the absolute error in the approximation for sinh(0.17) is 0.000305.

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In the year 2002 the exports of Chinese's automobile parts will $5.3 billion.

The exponential function for the given export of Chinese's automobile parts is-

5.3 = 1.8208 e^0.3387x

5.3/1.8208 = e^0.3387x

Taking ln both sides-

ln(5.3/1.8208) = ln e^0.3387x

ln(5.3/1.8208) = 0.3387x

Further simplifying

x = ln(5.3/1.8208)/0.3387

x =  3.15

x ≈ 3 year ad some months

Add 3 years to 1998 to get the required year.

Year = 1998 + 3

Year = 2001 and months

Year = 2002

Thus, in the year 2002 the exports of Chinese's automobile parts will $5.3 billion.

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The correct question is-

The value of China's exports of automobiles and parts (in billions of dollars) is approximately f(x) = 1.8208e^.3387x, where x = 0 corresponds to 1998.

In what year did/will the exports reach $5.3 billion?

An Experiment is repeated 10 times compared to just 3 times, the results from the 10 repetitions would generally be considered more reliable.

True.

In general, conducting an experiment multiple times increases the reliability of the results. The more times an experiment is repeated, the greater the opportunity to collect data and observe patterns or trends. This allows for a more robust analysis and reduces the impact of random variations or errors that may occur in a single trial.

When an experiment is repeated multiple times, it helps to reduce the effects of outliers or anomalies that may occur in a single trial. By averaging the results over multiple repetitions, the overall outcome tends to be more representative and reliable.

In the context of statistical analysis, increasing the sample size (number of repetitions) can lead to more precise estimates of parameters and reduce the margin of error. It provides a better understanding of the underlying phenomenon being studied and allows for more confident conclusions.

Therefore, if an experiment is repeated 10 times compared to just 3 times, the results from the 10 repetitions would generally be considered more reliable. The larger sample size provides a stronger basis for drawing conclusions and making inferences about the population or phenomenon under study.

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Answer:

Bus 18 is more consistent than Bus 47 based on the IQR, which is smaller for Bus 18 (16) compared to Bus 47 (24), indicating less spread of data between the 25th and 75th percentiles.

Step-by-step explanation:

Answer: The correct option regarding which bus has the least spread among the travel times is given as follows:

Bus 14, with an IQR of 6.

How to obtain the measures of spread?

First, we consider the dot plot, which shows the number of times that each observation appears in the data set.

Then we consider the interquartile range, which gives the difference between the third quartile and the first quartile of the data set.

The interquartile range is a better measure of spread compared to the range of a data set, as it does not consider outliers.

For groups of 15 students, we have that:

The first half is composed of the first seven students, hence the first quartile is the fourth dot, which is the median of the first half.

The second half is composed of the last seven students, hence the first quartile is the eleventh dot, which is the median of the first half.

The quartiles for Bus 14 are given as follows:

Q1 = 12.

Q3 = 18.

Hence the IQR is of:

IQR = Q3 - Q1 = 18 - 12 = 6.

The quartiles for Bus 18 are given as follows:

Q1 = 9.

Q3 = 16.

Hence the IQR is of:

IQR = Q3 - Q1 = 16 - 9 = 7.

Step-by-step explanation: