A large truck and a small car are moving at the same speed. The truck has a greater kinetic energy because its _________ is greater

The mass of the the object, given that the same force acted upon it to accelerate at 2 m/s² is 34 Kg

First, we shall determine the force. This can be obtained as follow:

Force (F) = mass (m) × acceleration (a)

Force = 4 × 17

Force = 68 N

Finally, we shall determine the mass of the object that will accelerate at 2 m/s² when the force of 68 N is applied to it. Details below:

Force = mass × acceleration

68 = mass × 2

Divide both sides by 2

Mass = 68 / 2

Mass = 34 Kg

Thus, from the above calculation, we can conclude that the mass is 34 Kg

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Answer:

It's true

Explanation:

Because the ship is mafe up of aluminium, which is a light metal.

Answer:

False

Explanation:

Took The Quiz

Answer:\(3.6\ kW\)

Explanation:

Given

Power Supplied \(\(P_{input}=4\ kW\)\)

Efficiency of the motor \(\neta =90\%\)

and \(\neta =\dfrac{\text{Power output}}{\text{Power input}}\)

\(\Rightarrow 0.9=\dfrac{P_{out}}{4}\)

\(\Rightarrow P=0.9\times 4\)

\(\Rightarrow P=3.6\ kW\)

So, vacuum cleaner delivers a power of \(3.6\ kW\)

Answer:

For parallel plate capacitor ,the capacitance C=dAϵ0

Area, A=ϵ0Cd=8.85×10−121×10−3=1.13×108m2

Pls Check This Answer Is correct or not

actually i am not sure

Answer:

I = 27kg.mi/h

Explanation:

In order to calculate the impulse of the ball, you use the following formula:

\(I=m\Delta v\)  \(=m(v-v_o)\)      (1)

m: mass of the ball = 0.3kg

v: speed of the ball after the bat hit it = 60mi/h

vo: speed of the ball before the bat hit it = 30mi/h

You replace the values of all parameters in the equation (1):

\(I=(0.3kg)(60mi/h-(-30mi/h))=27kg\frac{mi}{h}\)

where the minus sign of the initial velocity means that the motion of the ball is opposite to the final direction of such a motion.

The imulpse of the ball is 27 kg.miles/hour

The stones needed to be dropped from the same height. The light stone is moving quicker than the hefty stone just as it touches the ground. The light stone is taller when it is first placed than the heavy stone is.

Energy is the ability to carry out work. Potential, kinetic, thermal, electrical, chemical, nuclear, and other forms may all exist for it.

There are numerous types of energy. Examples of these include: electromagnetic energy, chemical energy, nuclear or atomic energy, mechanical energy, gravitational energy, electrical energy, sound energy, and so on. Each form can be changed or transformed into the others.

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Answer:

The effects of the thin atmosphere are that the surface of the planet is going to be much hotter and not only that but also more radioactive than a planet with a thicker atmosphere. The thick atmosphere on other planets prevents a lot of radiation from going straight to the surface of the planet.

Explanation:

Answer:

Energy =  1.5032*10^(-10) Joules

Explanation:

By Einstein's relativistic energy equation, we know that the energy of a given particle is given by:

Energy = rest energy + kinetic energy.

            = m*c^2  + (γ - 1)*mc^2

Where γ depends on the velocity of the particle.

But if the proton is at rest, then the kinetic energy is zero, and γ = 1

Then the energy is just given by:

Energy = m*c^2

Where we know that:

mass of a proton = 1.67*10^(-27) kg

speed of light = c = 2.9979*10^(8) m/s

Replacing these in the energy equation, we get:

Energy = ( 1.6726*10^(-27) kg)*( 2.9979*10^(8) m/s)^2

Energy = 1.5032*10^(-10) kg*m^2/s^2

Energy =  1.5032*10^(-10) J

As the collision is elastic,  u₁ + u₂ = v₁ + v₂ must be satisfied.

According to the law of momentum conservation, momentum is never created nor destroyed inside a problem domain.

Before collision,

velocity of body A = u₁ velocity of body B = u₂

After collision,

velocity of body A = v₁ velocity of body B = v₂

Hence, according to  law of momentum conservation

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

As the collision is elastic, total kinetic energy is also conserved.

1/2m₁u₁² + 1/2m₂u₂² = 1/2m₁v₁² + 1/2m₂v₂²

This two equation satisfy that:

u₁ + u₂ = v₁ + v₂

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As mass increases, the following which is found to be always true is a corresponding increase in the inertia and is therefore denoted as option C.

This is defined as the property of a body to resist changes in velocity or motion. Such feature is characterized by the body having the tendency to remain at rest or in uniform motion unless an external force acts on it.

When mass increase, inertia also increases due to the large amount of force which is needed to change the direction or motion of a body in this scenario. On the other hand, when mass decreases, there is a corresponding decrease in the inertia which is present in a given body over a period of time.

This is therefore the reason why mass of a body is directly proportional to its inertia and makes it the most appropriate choice.

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The planet that a Martian is on is Earth.

The formula to calculate the period from a simple pendulum

T = 2π × √(L ÷ g)

T ÷ 2π = √(L ÷ g)

(T ÷ 2π)² = L ÷ g

T² ÷ 4π² = L ÷ g

L = (T² × g) ÷ 4π²

Compare from pendulum on Mars and another planet

L₁ = L₂

(T₁² × g₁) ÷ 4π² = (T₂² × g₂) ÷ 4π²

T₁² × g₁ = T₂² × g₂

1.5² × 0.38g = 0.92² × g₂

2.25 × 0.38g = 0.8464 × g₂

0.855g = 0.8464 × g₂

g₂ = 0.855g ÷ 0.8464

g₂ = 1.0101g

g₂ = 1.0101 × 9.8

g₂ = 9.89

The other planet is Earth.

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The distance travelled by the plane in the first second of its run is 5m.

Velocity is defined as the rate of change of a body’s position with respect to time. Velocity is basically speeding in a specific direction. It is a vector quantity, which means we need both magnitude (speed) and direction to define velocity. If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.

From the question;

velocity (acceleration) = 5m/s2

distance = 1800m

so, to find the distance travelled in the first second;

time = 1 second

using the formula; \(velocity = \frac{displacement}{time}\)

therefore; displacement = velocity x time

displacement = 5 x 1

displacement = 5m

In conclusion, the plane travelled 5m in the first second of its run.

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A force-directed or force-based graph is a sort of layout that is frequently used in a number of application domains, including network visualization, big graph visualization, knowledge representation, system management, and mesh visualization. The connections between the objects in a network are visualized using it.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

Probably copper wire

Explanation:

I took the class and that's the only one that sounds right but I'm pretty dum lol

Answer:

We are given the trajectory of a projectile:

y=H+xtan(θ)−g2u2x2(1+tan2(θ)),

where H is the initial height, g is the (positive) gravitational constant and u is the initial speed. Since we are looking for the maximum range we set y=0 (i.e. the projectile is on the ground). If we let L=u2/g, then

H+xtan(θ)−12Lx2(1+tan2(θ))=0

Differentiate both sides with respect to θ.

dxdθtan(θ)+xsec2(θ)−[1Lxdxdθ(1+tan2(θ))+12Lx2(2tan(θ)sec2(θ))]=0

Solving for dxdθ yields

dxdθ=xsec2(θ)[xLtan(θ)−1]tan(θ)−xL(1+tan2(θ))

This derivative is 0 when tan(θ)=Lx and hence this corresponds to a critical number θ for the range of the projectile. We should now show that the x value it corresponds to is a maximum, but I'll just assume that's the case. It pretty obvious in the setting of the problem. Finally, we replace tan(θ) with Lx in the second equation from the top and solve for x.

H+L−12Lx2−L2=0.

This leads immediately to x=L2+2LH−−−−−−−−√. The angle θ can now be found easily.

Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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Answer:

Given :  

m 1 =0.5 kg        

u 1 =0 m/s                    

m 2=0.005 kg      

u 2=200 m/s              

Let the velocity acquired by the block after the collision be V.

Using conservation of linear momentum before and after the collision :    P i =P f

​∴    m1u 1 +m 2u 2=(m 1+m 2 )V

OR    

0.5×0+0.005×200=(0.5+0.005)V              

⟹V≈1.9  m/s

Answer:

V= 1.9  m/s

Explanation:

I did the test

Hope this helps :)

Distance between two lines of grating is 4.85*10^-4 cm.

The act of bending light around corners where it spreads out and illuminates regions is known as the diffraction of light.

A optical element known as a diffraction grating splits light into numerous beams that move in various directions. The directions, as well as diffraction angles of these beams, depending on the wavelength of the incident light, the angle at which the wave strikes, and the distance or spacing between consecutive diffracting elements.

The distance between the two grating lines is calculated by taking the reciprocal of the grating value which is provided.

Distance between two lines of grating is, 1/2060 = 4.85*10^-4 cm.

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To determine the height from which a person was shot based on the distance traveled by a blood drop, we can use projectile motion calculations considering the vertical component and apply the equations for the time of flight and vertical distance traveled.

To determine how high up the person was shot, we can use the properties of a projectile motion and the dimensions of the blood drop.

First, convert the distance from feet to meters, as it is a more commonly used unit in physics calculations. 5.1 feet is approximately 1.55 meters.

The blood drop is assumed to follow a parabolic trajectory, where its horizontal and vertical motion are independent. We can focus on the vertical component to determine the height.

The horizontal distance traveled by the blood drop is not relevant to calculating the height.

The vertical distance traveled by the blood drop can be calculated using the equation:

d = ut + (1/2)gt^2

Where:

d is the vertical distance traveled (height),

u is the initial vertical velocity (0 since the drop starts at rest),

t is the time of flight,

g is the acceleration due to gravity (approximately 9.8 m/s^2).

Rearranging the equation, we have:

t = sqrt((2d)/g)

The time of flight can be found using the measured distance, as the horizontal and vertical motion take place simultaneously:

t = distance / horizontal velocity

The horizontal velocity is the horizontal distance divided by the time of flight, which is 1.55 meters divided by the time of flight.

Substitute the time of flight from step 5 into the equation from step 6 and solve for the horizontal velocity.

Now, we know the horizontal velocity, and we can calculate the time it takes for the blood drop to travel from the person to the landing point, which is the horizontal distance divided by the horizontal velocity.

Finally, we can use the time of flight obtained in step 8 and substitute it back into the equation from step 5 to calculate the height.

Please note that this calculation assumes ideal projectile motion without considering factors like air resistance or other variables that may affect the trajectory. Additionally, the size of a single blood drop may not accurately reflect the height from which a person was shot. It is important to consult medical professionals and forensic experts for accurate analysis and interpretation of crime scene evidence.

Therefore, We can use projectile motion calculations with the vertical component and apply the equations for time of flight and vertical distance travelled to determine the height from which a person was shot based on the distance travelled by a blood drop.

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#Case -1

If Pulling force is less than frictional force the object won't move .

#Case-2

If Pulling force is greater than frictional force then object will be .

In order to calculate friction force you need Limiting friction first .

\(\\ \sf\longmapsto F_L=\mu sN\)

Or

\(\\ \sf\longmapsto F_L=\mu smg\)

If metal is required to cast the cubical metal box, it would require 784cm3 of solid static electricity iron.

Unbalanced electric charge on such a material's surface is known as static electricity. In contrast for dynamic (moving) electricity, which takes the shape of electric currents, static electricity is defined as being fixed or immovable. A typical atom is neutral, meaning it has an equal number of protons and electrons.

Although static electricity does not directly endanger human life, it can nonetheless shock us and, if we were on an elevated surface, might inflict serious injuries.

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Athletes training for the 100-meter dash will mostly rely on phosphocreatine for this event's rapid energy.

Numerous creatine kinases catalyze the reversible phosphorylation of creatine, which includes both the forward and backward reactions. It is used to detect tissue injury when creatine kinase (CK-MB, creatine kinase myocardial band) is present in blood plasma.

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Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Work done on an object depends on the distance and force but independent of time.

Work is the product of force and the distance move in the direction of the force. It is measured in Joule.

If you use more force to move an object, there will be more amount of work because Work done = force x distance.

More force will give more about of work.

If you lift a 20 N object faster, you will experience the same amount of work because work is independent of time.

If you raise an object a shorter height, there will be less work done since work depends on the distance move in the direction of the force.

If you move a lighter object, you will experience a less work done because the weight of the object will reduce the work done

If you move an object farther, there will be more work to be done because of the increase in distance.

Therefore, Work done on an object depends on the distance and force but independent of time.

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The scientific symbol are matched with their respective unit of measurement as follows:

The amount of work that is required for each situation is given by:

A force (F) can be defined as a push or pull of an object, which typically causes a change of motion (acceleration), especially due to the interaction of the object with another. Also, force (F) is measured in Newton (N).

The work done (W) by an object is calculated by multiplying the force acting on it by the perpendicular distance covered by the object. Thus, work done (W) and energy (E) have the same unit i.e Joules (J).

In this exercise, you're required to match the scientific symbol with their respective unit of measurement and this is represented as follows:

The amount of work that is required for each situation is given by:

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Answer: 7260,39

Explanation:

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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