a light horizontal spring has a spring constant of 143 n/m. a 3.24 kg block is pressed against one end of the spring, compressing the spring 0.136 m. after the block is released, the block moves 0.246 m to the right before coming to rest. the acceleration of gravity is 9.81 m/s 2 . what is the coefficient of kinetic friction between the horizontal surface and the block?

Answer:

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Answer:

The two wires exert the same force on each other.

Explanation:

Mira will observe that varying the current in wire 1 affects the force per unit length on wire 1.

When the wires are kept as far apart as possible and the current in wire 2 is set to a constant value of 5 A, varying the current in wire 1 will affect the force per unit length on wire 1.

According to Ampere's law, the magnetic field created by a current-carrying wire is directly proportional to the current passing through the wire. When the current in wire 1 is varied, it will create a magnetic field around wire 1.

If the current in wire 1 is increased, the magnetic field around wire 1 will also increase. As a result, the force per unit length on wire 1 will increase. Mira will observe a stronger force acting on wire 1 as the current in wire 1 is increased.

On the other hand, if the current in wire 1 is decreased, the magnetic field around wire 1 will weaken, leading to a decrease in the force per unit length on wire 1. Mira will observe a weaker force acting on wire 1 as the current in wire 1 is decreased.

Therefore, Mira will observe that varying the current in wire 1 affects the force per unit length on wire 1, with an increase in current leading to a stronger force and a decrease in current resulting in a weaker force.

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Answer:

\(\boxed {\boxed {\sf 400 \ J}}\)

Explanation:

Work is a force that causes the displacement of an object. It is the product of force and displacement.

\(W=Fd\)

The force is 40 Newtons and the displacement is 10 meters.

Substitute the values into the formula.

\(W= 40 \ N * 10 \ m\)

Multiply.

\(W= 400 \ N*m\)

Convert the units. 1 Newton meter is equal to 1 Joule, so our answer is equal to 400 Joules.

\(W= 400 \ J\)

400 Joules of work was done to move the block.

Answer:

400 J

Explanation:

This is the correct answer for k12

Answer:

C. 199.9 s

Explanation:

3 minutes = 3×60 = 180 seconds.

the turtle moves in that time 180×10 = 1800 cm.

in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).

the rabbit moves with 10×10cm/s = 100cm/s.

the rabbit needs therefore 1800/100 = 18 seconds for the

1800 cm.

at that time the turtle has added another 18×10 = 180 cm.

for which the rabbit needs 180/100 = 1.8 seconds.

during that time the turtle has added 1.8×10 = 18 cm.

and so on.

in formal mathematics this looks like this :

1800 + 10x = 100x

after x seconds of the rabbit running both will have run the same distance, and it is a tie.

1800 = 90x

x = 20 seconds

so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm

and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.

but our question tells us that the turtle won by 10 cm.

so, the race was over a little bit before these 200 seconds (for a tie).

this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).

the rabbit would have needed 10/100 seconds for these 10 cm.

as speed = distance/time

we need to divide distance by speed

distance/1 / distance/time

to get time.

so,

10cm/1 / 100cm/s = 10s/100 = 1/10 s

so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).

the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).

and so, the race was 199.9 s long.

The induced drag coefficient of the Supermarine Spitfire with its original elliptical wing is given as 0.001109. If the wing is replaced by a tapered wing with a taper ratio of 0.4, we can determine the new induced drag coefficient and the percentage increase.

Based on the given graph, we can observe that a taper ratio of 0.4 corresponds to an induced drag coefficient of approximately 0.00054. Therefore, the induced drag coefficient for the Spitfire with a tapered wing would be approximately 0.00054.

To calculate the percentage increase, we can use the formula:

Percentage Increase = (New Value - Original Value) / Original Value * 100

Using this formula, the percentage increase in the induced drag coefficient would be:

Percentage Increase = (0.00054 - 0.001109) / 0.001109 * 100 ≈ -51.03%

Therefore, the induced drag coefficient with the tapered wing decreases by approximately 51.03% compared to the original elliptical wing configuration.

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Answer:

x = 15√3m , y = 3.75m

Explanation:

According to the question ,

And we need to find out ,

As we know that , at any time t , the horizontal displacement (x) is given by ,

\(\longrightarrow\) x = u cos\(\theta\)t

\(\longrightarrow\) x = 20 * cos30° * 1.5 m

\(\longrightarrow\)x = 20 * √3/2 * 3/2 m

\(\longrightarrow\) x = 15√3 m .

\(\rule{200}2\)

For finding the vertical distance , let's find range first .

\(\longrightarrow\) R = u²sin2\(\theta\)/g

\(\longrightarrow\) R = (20)² * sin60° / 10 m

\(\longrightarrow\)R = 400 * √3/10 *2

\(\longrightarrow\)R = 20√3 m

Now we can find the vertical displacement as ,

\(\longrightarrow\) y = xtan\(\theta\) ( 1 - x/R)

\(\longrightarrow\)y = 15√3 *1/√3 ( 1-15√3/20√3)m

\(\longrightarrow\)y = 15( 1 - 3/4)m

\(\longrightarrow\)y = 15 * 1/4m

\(\longrightarrow\) y = 3.75 m

The average acceleration of the egg while falling can be calculated using the equation a = (v - u)/t, where v is the final velocity, u is the initial velocity and t is time.

a) A = (11.0 m/s) / (1.12 s) = 9.82 m/s^2

b) A = (0 m/s) / (0.131 s) = 0 m/s^2

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The current that would pass through the 30 ohms resistor is 2 A.

Electric current is the rate of flow of electric charge round a conductor.

To calculate the electric current that would pass through the 30 ohms resistor, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The current that would pass through the 30 ohms resistor is 2 A.

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The skateboard will travel a distance of 20 * 1^2 - 40 * 1 = 400 feet before it stops moving.

a.The differential equation can be solved using separation of variables. First, we move the constant k to the right-hand side of the equation:

dv/dt = -kv^(3/2)

Then, we divide both sides of the equation by v^(3/2):

v^(-3/2) dv = -k dt

We can now integrate both sides of the equation:

int v^(-3/2) dv = int -k dt

The left-hand side of the equation can be integrated using the power rule:

int v^(-3/2) dv = -2/3 v^(1/2)

The right-hand side of the equation can be integrated using the constant of integration C:

int -k dt = -kt + C

Combining the two sides of the equation, we get:

-2/3 v^(1/2) = -kt + C

We can now solve for the constant of integration C. We are given that the initial velocity of the skateboard is 100 ft/min, so we can set t = 0 and v = 100 in the equation:

-2/3 * 100^(1/2) = -k * 0 + c

Simplifying the left-hand side of the equation, we get -20. This means that the constant of integration C = -20.

Therefore, the final solution for the velocity of the skateboard isv^(1/2) = 20t - 20

b. To find the position of the skateboard, we need to integrate the velocity equation. The integral of v^(1/2) is 2v^(3/2), so the position of the skateboard is given by:

x = 2 * int v^(1/2) dv = 2 int (20t - 20) dv

The integral of 20t - 20 is 10t^2 - 20t, so the position of the skateboard is:

x = 20t^2 - 40t

c. The skateboard will only travel a finite distance because the velocity of the skateboard will eventually approach zero as t approaches infinity. This means that the skateboard will eventually stop moving, and its position will be finite.

The skateboard will travel a distance of 400 feet before it stops moving. This can be found by setting the velocity equation equal to zero and solving for t:

v^(1/2) = 20t - 20

0 = 20t - 20

20 = 20t

1 = t

Therefore, the skateboard will travel a distance of 20 * 1^2 - 40 * 1 = 400 feet before it stops moving.

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\(\\ \tt\longmapsto Acceleration=\dfrac{v-u}{t}\)

\(\\ \tt\longmapsto Acceleration=\dfrac{95-5}{10}\)

\(\\ \tt\longmapsto Acceleration=\dfrac{90}{10}\)

\(\\ \tt\longmapsto Acceleration=9m/s^2\)

Answer:

The spring constant will be "1333.33 N/m".

Explanation:

The given values are:

Mass,

m = 1.2 kg

Displacement compression,

x = 0.15 m

Block's velocity,

\(v_i=5 \ m/s\)

As we know,

⇒  \(E_i=E_f\)

or,

⇒  \(K_i+v_i=K_f+v_f\)

⇒  \(\frac{1}{2}mv_i^2+0=0+ \frac{1}{2}Kx^2\)

So,

⇒  \(K=\frac{mv_i^2}{x_2}\)

On substituting the values, we get

⇒       \(=\frac{1.2\times 5\times 5}{0.15\times 0.15}\)

⇒       \(=\frac{30}{0.0225}\)

⇒       \(=1333.33 \ N/m\)

The normal force at point C is the force exerted perpendicular to the beam. Since the beam is in equilibrium, the sum of all forces in the vertical direction is equal to zero. Therefore, the normal force at point C will be equal in magnitude and opposite in direction to the total vertical force acting on the beam.

2. Shear force: The shear force at point C is the force acting parallel to the beam, causing it to shear or slide. To determine the shear force at point C, we need to consider the forces acting on either side of point C and take the sign convention into account. If we take the left side of point C, the shear force will be positive if it acts in the upward direction and negative if it acts in the downward direction. Similarly, if we take the right side of point C, the shear force will be positive if it acts in the downward direction and negative if it acts in the upward direction. We need to sum up the vertical forces on either side of point C and determine the difference to find the shear force at point C.

3. Moment: The moment at point C is the turning effect caused by the forces acting on either side of point C. To determine the moment at point C, we need to consider the forces acting on either side of point C and their perpendicular distances from point C. Again, we need to take the sign convention into account. Clockwise moments are considered positive, while counterclockwise moments are considered negative. We need to calculate the moments caused by the forces on either side of point C and determine the algebraic sum to find the moment at point C.

By applying these steps, we can determine the normal force, shear force, and moment at point C.

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The interaction of an attracting or repulsive force between two charged bodies is referred to as an electric force.

This force is comparable to other forces in that it strikes and affects a specific item, and it is simple to illustrate using Newton's law of motion. One of the forces acting on other bodies is the electric force.

Electric force is the interaction of any two charged bodies that is either repellant or attracting. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. The list of additional forces that apply to objects includes the electric force.

The electrostatic force between the two electrons is one of repulsion since electrons are negatively charged and items with like charges repel one another.

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Answer: B  6.2 Hz

Explanation:  Equation for waves v = λf.

Frequency = speed / wavelength    f = v/λ

   f = 74 m/s / 12 m = 6.166... Hz

Answer:

Rounding is necessary: the answer is 6.2 Hz

Explanation:

Answer:

Independent Variable

Explanation:

The variables that are plotted on X-axis, the horizontal line of the graph are termed as independent variables. The variables plotted on Y-axis which is vertical side of the graph are dependent variables.

The difference in power for two people carrying the boxes up the ramp is 30 W.

Given the following data:

W = 40.0 N is the weight of a box.

The ramp's length is L = 2.00 m.

The platform height is h = 1.0 m.

t = 2.0 s is the time interval for the first person.

t' = 4.0 s is the time interval for the other person.

Power is the rate at which energy is used. The expression for the Power is given in the given question as,

P = W×(L+h)/t

Assume that you are solving for the first person.

P₁ = W(L+h)/t₁.................................................................. (1)

Substitute the following values into equation (1):

P₁ = 40(2+1)/2

P₁ = 20(3) (3)

P₁ = 60 W.

Regarding the second person,

P₂ = W(L+h)/t₂..................................................................... (2)

Fill in the blanks in equation (2) as follows:

P₂ = 40(2+1)/4

P₂ = 10*(3) *3)

P₂ = 30 W

Obtaining the difference in power as

P = P₁ - P₂

P = 60-30

P = 30 W

As a result, we can conclude that the difference in power for two people carrying the boxes up the ramp is 30 W.

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Answer: The object moves with constant velocity

Explanation:

In this velocity vs time graph we're dealing with Ap physics or regents physics. If we look at the slope we can see it is constant or not changing. Even so lets check the other answers and prove them wrong

The objects speed increases: This is wrong because the line shows a steady 5m/s with no change

The object is in free fall: If the object was in freefall the speed would be increasing as a result of acceleration due to gravity

The object moves with a constant speed: This seems to be the case since the slope or line doesn't change at all

The object stays at rest: Can't be right because the object is at a speed of 5m/s so we know its moving at least

The objects speed decreases: Again the line isn't going up or down so we can't say speed increases or decreases

Answer:

Not sure but, I think C

Hopefully this helps

The friction factor of the ice is M = 0.0102. The resistive friction force (Fr) defined either by ordinary or perpendicular force (N) pushing the particles close yields the coefficient of friction (fr), a numerical value.

The formula fr = Fr/N serves as a representation of it. By figuring out the greatest frictional force, someone can employ the frictional coefficient calculation to calculate the least force necessary to get an item going on a ground.

The item will advance whenever a force given to it that is larger than just the frictional force; as force is measured in newtons, as well as typical, which is a force, newtons are additionally utilized to measure normal. It's going to be cancelled out by the two military units. This coefficient of friction does not have a unit. It is a dimensionally and unitlessly empty quantity.

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The moment of inertia of the stick when it is pivoted about its midpoint is (1/6)ML². The answer choice is (B).

When the stick is pivoted about its midpoint, we can split it into two equal pieces of mass M/2 and length L/2, each with a moment of inertia of:

I₁ = (1/3)(M/2)(L/2)² = (1/12)ML²

The parallel axis theorem tells us that the moment of inertia of the whole stick about its midpoint is equal to the sum of the moments of inertia of the two pieces plus the moment of inertia of the stick as if it were a point mass at its center of mass:

I₂ = 2I₁ + (1/12)M(L/2)²

I₂ = (2/12)ML² + (1/48)ML²

I₂ = (1/6)ML²

Option B is correct.

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Howdy,

B. Thermal and light.

Answer:

D is correct

Explanation:

(a) If you are adding them: Yes, two quantities being added must have the same dimensions. When adding quantities, it is essential that they have the same units to ensure that the operation is mathematically meaningful.

(b) If you are multiplying them: No, two quantities being multiplied do not need to have the same dimensions. Multiplication is valid between quantities of different dimensions. The resulting unit of the product will depend on the units of the individual quantities being multiplied.

(c) If you are subtracting them: Yes, two quantities being subtracted must have the same dimensions. Subtraction requires the quantities to have the same units to ensure that the operation is mathematically valid.

(d) If you are dividing them: No, two quantities being divided do not need to have the same dimensions. Division is valid between quantities of different dimensions. The resulting unit of the quotient will depend on the units of the numerator and denominator.

(e) If you are equating them: Yes, two quantities being equated must have the same dimensions. Equating quantities means that they are equal in magnitude and unit, so their dimensions must match.

In summary, the requirement for the same dimensions varies depending on the operation performed between the quantities. Addition and subtraction require the same dimensions, while multiplication, division, and equation do not have this requirement.

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The airline will need to have at least 167 passengers on each flight to break even.

To calculate the number of passengers needed to break even, we need to consider the total costs and the revenue generated per flight.

The total cost per flight consists of the fixed costs (£25,000) and the variable costs (£75 per passenger). The revenue per flight is determined by the ticket price (£225) multiplied by the number of passengers.

Let's denote the number of passengers as 'P'. The total cost per flight is given by:

Total Cost = Fixed Costs + (Variable Cost per Passenger * Number of Passengers)

Total Cost = £25,000 + (£75 * P)

The revenue per flight is given by:

Revenue = Ticket Price * Number of Passengers

Revenue = £225 * P

To break even, the total cost should equal the revenue:

£25,000 + (£75 * P) = £225 * P

Now, we can solve this equation for P to find the number of passengers needed to break even:

£25,000 + (£75 * P) = £225 * P

£25,000 = £225 * P - £75 * P

£25,000 = £150 * P

P = £25,000 / £150

P ≈ 166.67

Since the number of passengers must be a whole number, we round up to the nearest whole number:

P = 167

The airline will need at least 167 passengers on each flight to break even. However, since the maximum capacity of the aircraft is 200 passengers, the airline will need to fill the aircraft to its maximum capacity to break even on each flight.

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Answer:

Magnetic field lines exit out of the North pole . Magnetic field lines enter into the South pole. Magnetic field lines travel around a bar magnet in closed loops.

Explanation:

Magnetic field lines shows the direction of a magnetic force and how it acts, it gives the direction of the magnetic field at that point in time.

For a bar magnetic, the magnetic field lines runs from the north pole to the south pole, i.e. it exits the north pole and enters into the south pole. This magnetic field lines also go through the magnet forming closed loops without ends.

Answer:

Magnetic field lines exit out of the

✔ north pole

.

Magnetic field lines enter into the

✔ south pole

.

Magnetic field lines travel around a bar magnet in

✔ a closed loop

.

Explanation:

Answer:

B C A D

Explanation:

...match it accordingly